The pH at the equivalence point in the titration of 50.0 ml of 0.300 M CH₃COOH with 0.3 M NaOH is approximately 4.68.
To calculate the pH at the equivalence point, we need to determine the concentration of acetate ion (CH₃COO⁻) and hydronium ion (H³O⁺) at this point.
At the start of the titration, the initial concentration of acetic acid is 0.300 M and the initial concentration of hydronium ion is the same.
Let's say that x moles of NaOH are added to the solution. This will lead to the formation of x moles of acetate ion (CH³COO⁻) and x moles of hydroxide ion (OH⁻).
The final concentration of acetic acid will be (0.300 M - x M) and the final concentration of hydronium ion will be (x M).
The ionization constant (Ka) for acetic acid can be used to determine the concentration of acetate ion and hydronium ion in the solution. The equation for the ionization of acetic acid is:
CH₃COOH + H₂O ↔ CH₃COO⁻ + H₃O⁺
Ka = [CH₃COO⁻][H₃O⁺] / [CH₃COOH]
At the equivalence point, [CH₃COOH] = (0.300 M - x M), [CH₃COO⁻] = x M, and [H₃O⁺] = x M. Substituting these values into the equation for Ka, we get:
1.8 x 10⁻⁵ = (x)(x) / (0.300 - x)
Solving for x, we get:
x = 2.1 x 10⁻⁵ M
The pH at the equivalence point is equal to the negative log of the hydronium ion concentration:
pH = -log[H₃O⁺] = -log(2.1 x 10⁻⁵) = 4.68
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2) The current in a metallic conductor is a flow of A) Negatively charged electrons B) Negatively charged protons C) Positively charged electrons Positively charged protons D)
Answer:
c.Positively charged electrons
which of the following are not colligative properties? group of answer choices freezing point depression temperature change density enthalpy of formation boiling point elevation vapor-pressure lowering
Enthalpy of formation is not a colligative property. Colligative properties are physical properties of a solution that depend on the concentration of solute particles in the solution, but not on their chemical identity.
Examples of colligative properties include freezing point depression, boiling point elevation, and vapor pressure lowering.
Enthalpy of formation, on the other hand, is the energy change associated with the formation of a substance from its constituent elements in their standard states. It is a thermodynamic quantity and is not dependent on the concentration of solute particles in a solution. Hence, the enthalpy of formation is not a colligative property.
Freezing point depression and boiling point elevation are two of the most important colligative properties. Freezing point depression occurs when the freezing point of a solvent decreases in the presence of a solute. Boiling point elevation occurs when the boiling point of a solvent increases in the presence of a solute.
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which has a higher tensile strength? group of answer choices butyl rubber spider silk kevlar polyethylene
Kevlar has the highest tensile strength of the choices with a tensile strength of 8.3 GPa, followed by spider silk with a tensile strength of 4.5 GPa.
What is tensile strength ?Tensile strength is the maximum amount of tensile stress that a material can take before failing or breaking. It is the maximum amount of force that a material can withstand when being stretched or pulled. It is measured in units of force per unit area, such as pounds per square inch (psi) or megapascals (MPa). Tensile strength is an important property of materials because it tells us how much force a material can withstand before it breaks.
Butyl rubber and polyethylene both have a tensile strength of around 0.5 GPa.
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Why are foods that have a high pH pressure processed?
a. the higher pressure helps tenderize and make them edible
b. their low acidity makes them more prone to microbial growth
c. the shorter processing time preserves more of their nutrients
d. all of the above
is O2 a reactant or product or chemical reaction or microorganism or plant structure.
O2 is a reactant in chemical reactions, meaning that it is the substance that is involved in the process of producing new products.
It can also be a product in certain types of reactions. O2 is a molecule composed of two oxygen atoms, and it is essential for life as it is a byproduct of photosynthesis. In chemical reactions, O2 is highly reactive, often forming bonds with other elements and molecules. This is due to its low ionization energy and high electronegativity. When O2 is involved in a reaction, the reaction often requires a large amount of energy to initiate, but the products have lower energy than the reactants, releasing energy in the process. O2 is also an important component of respiration in most organisms, allowing them to produce energy from the breakdown of organic molecules. In general, O2 is an essential element in most processes involving energy production, as it is involved in numerous oxidation-reduction reactions.
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CH4 (g) + H2O(g) → CO(g) + 3H2 (g) What is the volume of steam, H2O(g), needed to completely react with 53.50L of methane gas at a constant pressure and temperature? What is the volume of carbon monoxide, CO, produced? What is the volume of Hydrogen gas, H2, produced? What is the total volume of gas produced?
To solve this problem, we need to use stoichiometry to relate the volume of methane to the volumes of steam, carbon monoxide, and hydrogen produced.
The balanced chemical equation is:
CH4 (g) + H2O(g) → CO(g) + 3H2 (g)
The stoichiometric ratio of steam to methane is 1:1, so the volume of steam needed is also 53.50 L.
To determine the volumes of carbon monoxide and hydrogen gas produced, we need to use the stoichiometric coefficients in the balanced equation. For every 1 mole of methane consumed, 1 mole of steam is consumed, 1 mole of carbon monoxide is produced, and 3 moles of hydrogen gas are produced.
First, we need to convert the volume of methane gas to moles using the ideal gas law:
PV = nRT
n = PV/RT
n = (1 atm) x (53.50 L) / [(0.08206 L·atm/mol·K) x (298 K)]
n = 2.189 mol
Therefore, 2.189 moles of methane react with 2.189 moles of steam to produce 2.189 moles of carbon monoxide and 6.567 moles of hydrogen gas.
To convert the moles of each gas to volume, we use the ideal gas law again:
V = nRT/P
For carbon monoxide:
n = 2.189 mol
R = 0.08206 L·atm/mol·K
T = 298 K
P = 1 atm
V = (2.189 mol) x (0.08206 L·atm/mol·K) x (298 K) / (1 atm)
V = 53.68 L
For hydrogen gas:
n = 6.567 mol
R = 0.08206 L·atm/mol·K
T = 298 K
P = 1 atm
V = (6.567 mol) x (0.08206 L·atm/mol·K) x (298 K) / (1 atm)
V = 160.76 L
The total volume of gas produced is the sum of the volumes of carbon monoxide and hydrogen gas:
53.68 L + 160.76 L = 214.44 L
Therefore, the volume of steam needed is 53.50 L, the volume of carbon monoxide produced is 53.68 L, the volume of hydrogen gas produced is 160.76 L, and the total volume of gas produced is 214.44 L.
Answer: 185.5 L.
Explanation: To solve this question, we need to use the stoichiometry of the chemical reaction to determine the amounts of each gas produced. The balanced chemical equation is:
CH4 (g) + H2O(g) → CO(g) + 3H2(g)
According to the stoichiometry of the reaction, 1 mole of methane reacts with 1 mole of water to produce 1 mole of carbon monoxide and 3 moles of hydrogen. Therefore, we can use the ideal gas law to calculate the volumes of each gas produced.
Given that the initial volume of methane gas is 53.50 L, we can first calculate the number of moles of methane present using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Since the pressure and temperature are constant, we can write:
n = PV/RT
where R = 0.08206 L atm/K mol is the gas constant.
n(CH4) = (1 atm)(53.50 L)/(0.08206 L atm/K mol)(298 K) = 2.23 mol
This means that 2.23 moles of methane react with 2.23 moles of water to produce 2.23 moles of carbon monoxide and 6.69 moles of hydrogen.
To determine the volume of water needed to react with all the methane, we can use the stoichiometry of the reaction again:
1 mol CH4 reacts with 1 mol H2O
Therefore, the number of moles of water required is also 2.23 mol. We can calculate the volume of water using the ideal gas law:
n(H2O) = PV/RT
V(H2O) = n(H2O)RT/P = (2.23 mol)(0.08206 L atm/K mol)(298 K)/(1 atm) = 46.4 L
Therefore, the volume of steam required to react with all the methane is 46.4 L.
Next, we can use the stoichiometry of the reaction to calculate the volumes of carbon monoxide and hydrogen produced:
1 mol CH4 produces 1 mol CO
1 mol CH4 produces 3 mol H2
Therefore, the number of moles of carbon monoxide and hydrogen produced are also 2.23 mol and 6.69 mol, respectively. We can calculate their volumes using the ideal gas law:
V(CO) = n(CO)RT/P = (2.23 mol)(0.08206 L atm/K mol)(298 K)/(1 atm) = 46.4 L
V(H2) = n(H2)RT/P = (6.69 mol)(0.08206 L atm/K mol)(298 K)/(1 atm) = 139.1 L
Therefore, the volume of carbon monoxide produced is 46.4 L and the volume of hydrogen produced is 139.1 L.
The total volume of gas produced is the sum of the volumes of carbon monoxide and hydrogen:
V(total) = V(CO) + V(H2) = 46.4 L + 139.1 L = 185.5 L
Therefore, the total volume of gas produced is 185.5 L.
Text me for any other issues.
I need help please!!!!!!!!!!
The number of moles is 257143 moles
How many liters are in one mole?The volume of one mole of a gas at a given temperature and pressure depends on the specific gas and the conditions.
However, under standard conditions of temperature and pressure (STP), one mole of any ideal gas occupies a volume of 22.4 liters.
This value is known as the molar volume of an ideal gas at STP and is a useful conversion factor in many chemistry problems involving gases.
We know that;
1 mole = 22.4 L
x moles = 5.76 * 10^6 L
x = 257143 moles
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the ratio of effusion of an unknown diatomic gas to oxygen is 0.50:1. what is molar mass of the unknown gas?
The molar mass of the unknown gas is 8.05 g/mol.
The ratio of effusion of an unknown gas to oxygen is 0.50:1, which means that the effusion rate of the unknown gas is half that of oxygen. Effusion is the process by which a gas escapes through a tiny hole into a vacuum, and the rate of effusion is directly proportional to the square root of the gas' molar mass. So, we can use this relationship to calculate the molar mass of the unknown gas.
Let's assume that the molar mass of oxygen is 32 g/mol. Then, the square root of the molar mass of oxygen is √32 = 5.66. If the effusion rate of the unknown gas is half that of oxygen, then the square root of its molar mass is 0.5 * 5.66 = 2.83. Taking the square of 2.83 gives us 8.05, which is the molar mass of the unknown gas.
Therefore, the molar mass of the unknown gas is 8.05 g/mol.
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EXPERIMENT: DEMONSTRATING POLAR PROPERTIES
These supplies are needed:
acetate (overhead transparency material) strip and tissue paper
vinyl strip and woolen cloth
slow, steady stream of water from a faucet
Follow these directions and answer these questions.
1. Rub the acetate strip with the tissue paper.
2. Bring the strip near a slow stream of running water.
What happened when the strip was brought near the stream?
From your ideas about charges on acetate and vinyl strips, predict what will happen if a charged vinyl strip is brought near the slow stream of water. (Review Unit 4.)
3. Test your hypothesis. Rub a vinyl strip with a woolen cloth.
4. Bring the charged strip near a slow stream of water.
Now analyze your prediction.
a. Was your prediction correct?
b. If not, propose a reason for the difference.
Analyze the shape of H2O.
a. What is the shape of the H2O molecule?
b. Is it symmetrical?
c. Does this mean that the H2O molecule is polar or nonpolar?
Analyze the bonds of CCl4.
a. What is the shape of the CCl4 molecule?
b. Is it symmetrical?
c. Does this mean that the CCl4 molecule is polar or nonpolar?
Assume that the water stream is replaced by a stream of CCl4. Predict what would happen in each case.
a. charged acetate strip:
b. charged vinyl strip:
c. Explain your predictions.
Chemists have found that charged acetate and vinyl strips have no effect on a stream of CCl4. Does this fact match your prediction?
Develop a model or picture of water, H2O, and carbon tetrachloride, CCl4, that would account for observations with the charged strips for the two compounds.
PLEASE GIVE ME LEGIT ANSWER!
A. The actual outcome of the experiment will depend on the specific details of the charges on the strips and the stream of water. However, in general, a charged strip will experience a force when brought near a stream of running water due to the interaction between the electric field of the strip and the movement of the charged water molecules.
What are the responses to other questions?b. If the prediction was incorrect, it could be due to a number of factors, such as the magnitude of the charge on the strip, the size of the stream, and the distance between the strip and the stream. Additionally, other factors such as the properties of the air and the presence of other substances in the water could also affect the outcome.
a. The shape of the H2O molecule is bent or angular.
b. Is it symmetrical?
No, the H2O molecule is not symmetrical.
c. Does this mean that the H2O molecule is polar or nonpolar?
The bent shape of the H2O molecule means that it is a polar molecule.
a. What is the shape of the CCl4 molecule?
The shape of the CCl4 molecule is tetrahedral.
b. Is it symmetrical?
Yes, the CCl4 molecule is symmetrical.
c. Does this mean that the CCl4 molecule is polar or nonpolar?
The symmetrical shape of the CCl4 molecule means that it is a nonpolar molecule.
a. charged acetate strip:
If a charged acetate strip were brought near a stream of CCl4, it is likely that the strip would experience no effect, as CCl4 is a nonpolar molecule and does not have a significant electric field.
b. charged vinyl strip:
If a charged vinyl strip were brought near a stream of CCl4, it is likely that the strip would experience no effect, as CCl4 is a nonpolar molecule and does not have a significant electric field.
c. Explain your predictions.
The lack of an effect in both cases is due to the nonpolar nature of CCl4, which means that it does not have a significant electric field. Since a charged strip experiences a force due to the interaction between its electric field and the electric field of a surrounding material, a nonpolar material like CCl4 will not produce a significant effect on a charged strip.
Chemists have found that charged acetate and vinyl strips have no effect on a stream of CCl4. Does this fact match your prediction?
Yes, this fact matches the prediction, as CCl4 is a nonpolar molecule and does not have a significant electric field that would interact with the charged acetate or vinyl strips.
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the conformation of the backbone of a polypeptide is described completely by the angle(s) of rotation about which bond(s)?
The conformation of a polypeptide's backbone is described by the angles of rotation about the peptide bonds.
The most common type of conformation is an alpha helix, in which the peptide bond rotates at an angle of approximately 100 to 120 degrees in a clockwise direction. This arrangement of the peptide bond contributes to an increase in the stability of the polypeptide, as the bonds form hydrogen bonds between the amino acids. This arrangement also allows for more efficient folding of the polypeptide, allowing for better functionality of the proteins involved. To calculate the angle of rotation for a given polypeptide, the bond length, bond angle, and torsional angle must all be known. First, the bond length must be determined from the x-ray data.
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if you were to look at a solution of k3po4 (aq) and see all the molecules and ions, what specific molecules and ions would you see? of those, which would make up most of the solution? which would make up the least amount of the solution?
If you were to look at a solution of K₃PO₄ (aq), you would see the following molecules and ions: Potassium ions (K+), Phosphate ions (PO₄³⁻) and Water molecules (H₂O).
Among these species, the phosphate ions (PO₄³⁻) would make up the least amount of the solution, as they are negatively charged and are counterbalanced by the positively charged potassium ions (K⁺). On the other hand, the water molecules (H₂O) would make up the majority of the solution, as they are not charged and are neutral.
Tripotassium phosphate, also known as tribasic potassium phosphate is a water-soluble salt having chemical formula K₃PO₄.(H₂O)x. Tripotassium phosphate is produced by the neutralization of the phosphoric acid.
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what is the temperautre of a system in a thermal equilibrium with another system made up of water and steam at 1 atm of pressure?
The temperature of a system in thermal equilibrium with another system made up of water and steam at 1 atm of pressure would be 100 degrees Celsius (or 373 Kelvin). This is the boiling point of water at 1 atm of pressure and is the temperature at which water and steam coexist in equilibrium.
Thermal equilibrium is a state in which two or more objects at different temperatures are placed in thermal contact, and as a result of this, they eventually reach a common temperature. In other words, thermal equilibrium is the state in which no net heat flow occurs between the objects. The common temperature they reach depends on the specific heat capacities and masses of the objects and the initial temperatures of each.
For example, if a hot piece of metal and a cold piece of metal are placed in thermal contact, heat will flow from the hot piece of metal to the cold piece of metal until both pieces reach the same temperature. Once this occurs, the two pieces are said to be in thermal equilibrium.
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a compound has the empirical formula bnh2. if its molecular weight is 80.52 amu, what is its molecular formula?
So, the molecular formula of the compound is:
BNH2 * 5 = B5NH10
What is molecular formula?
The molecular formula of a compound is the chemical formula that specifies the number and type of atoms present in one molecule of the compound. The molecular formula gives the exact number of each type of atom in a molecule and can be used to distinguish between isomers (compounds with the same molecular formula but different arrangements of atoms).
The molecular formula of a compound can be found by determining its empirical formula and then finding the multiple of the empirical formula that gives the correct molecular weight.
The empirical formula of a compound is the simplest whole number ratio of atoms in the molecule. In this case, the empirical formula of the compound is BNH2.
To find the molecular formula, we need to determine the molecular weight of the compound and divide it by the molecular weight of the empirical formula:
80.52 g/mol / (10.81 g/mol + 1.01 g/mol + 2 x 1.01 g/mol) = 80.52 g/mol / 14.84 g/mol = 5.44
Since the molecular weight must be a whole number, the ratio must be a whole number as well. In this case, the ratio is close to 5, so the molecular formula of the compound is likely to be 5 times the empirical formula.
So, the molecular formula of the compound is:
BNH2 * 5 = B5NH10
This means that the compound contains 5 boron atoms, 10 nitrogen atoms, and 10 hydrogen atoms.
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Why does a lump of cotton wool shrink in water?
Answer: Sufficient volume of air is present in lump of cotton wool. then dipped in water, this air goes out due to which the cotton lump shrunk.
yes
if you were to take 5.70 l of the buffer in part a and add 200.00 ml of 1.50 m hcl, what would the new ph be? (2 points)
The new pH of the solution after adding 200.00 mL of 1.50 M HCl to 5.70 L of the buffer in part A would be approximately 2.43.
pH is calculated by taking the negative logarithm of the hydrogen ion concentration in the solution. The hydrogen ion concentration for the solution after adding the HCl can be calculated using the Henderson-Hasselbalch equation, which states that pH = pKa + log([A-]/[HA]). In this case, the pKa of the buffer is 4.76 and the initial [A-]/[HA] ratio is 0.20.
After adding the HCl, the [A-]/[HA] ratio will decrease to 0.0166, giving a new pH of 2.43.
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a tlc of my product gives a rf of 0.37 using a 5:3 hexanes/ethyl acetate eluent. what would happen to the rf if the eluent was changed to 3:1 hexanes/ethyl acetate?
RF value will increase if the eluent was changed to 3:1 hexanes/ethyl acetate.
Explain about Rf value?
RF value (or Retention Factor) is a measure of a compound's retention time in a chromatographic process. It is calculated by dividing the retention time of a compound by the retention time of a reference compound (typically a known standard). RF values are used to compare the retention times of compounds within a given chromatographic system. They are also used to identify unknown compounds by comparing their retention time to a database of known compounds.
The change in the eluent composition will affect the retention factor (RF) of the product in the thin-layer chromatography (TLC) analysis. In general, a change in the eluent composition from 5:3 hexanes/ethyl acetate to 3:1 hexanes/ethyl acetate will result in a change in the RF value. It's difficult to predict exactly how the RF value will change without conducting the experiment, but it's possible that the RF value will increase with the new eluent. This is because increasing the concentration of hexanes and decreasing the concentration of ethyl acetate will result in a more nonpolar solvent, which may result in a stronger partitioning of the product into the solvent and a longer distance traveled up the TLC plate.
Therefore, the RF value will increase.
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the density of solid cu is 8.96 g/cm3. how many atoms are present per cubic centimeter (cm3) of cu?
Solid cu has an 8.96 g/cm3 density. Per cubic centimeter (cm3) of cu, there are 3.61*10⁻⁸ atoms.
Molar mass of Cu = 63.546 gm/mol
according to avogadro's law, 1 mol of a substance contains 6.022*10²³ atom
thus, 63.546 gm Cu contains 6.022*10²³ atom
density of Cu = 8.96g/cm³ that mean 1 cm3 contain 8.96 gm Cu
we have to calculate 63.546 gm Cu containing 6.022*10²³ atom then 8.96 gm Cu contains how many atom calculations are given as below.
63.546/8.96 = 6.022*10²³?
? = 6.022*10²³*8.96/63.546
=8.494*10²² atom
1 cubic centimeter of Cu contains 8.494*10²² atom
Cu adopts FCC unit cell so contains 4 atoms in each unit cell
one cubic centimeter contains 8.494*10²² atom
therefore one cubic centimeter contains 8.494*10²²/4 =2.1235*10²² unit cell
2.1235*10²²unit cell have volume 1 cm³then 1 unit cell have volume 1/2.1235*10²² =4.72*10⁻²³ cm3
Edge = (4.72*10⁻²³ cm³)1/3 =3.61*10⁻⁸cm
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Methane gas (CH4) effuses 3. 4 times faster than an unknown gas. Determine the molar mass of the unknown gas. Show your work or explain your answer, giving specific values used to determine the answer
The molar mass of the unknown gas is 184.96 g/mol.
Graham's law of diffusion states that "the rate of diffusion of a gas is inversely proportional to the square root of the molar mass".
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
Rate of unknown gas (R₁) = R
Rate of CH₄ (R₂) = 3.4R
Molar mass of CH₄ (M₂) = 16 g/mol
Molar mass of unknown gas (M₁) =?
The molar mass of the unknown gas can be obtained as follow:
R₁/R₂ = √(M₂/M₁)
R / 3.4R = √(16 / M₁)
1 / 3.4 = √(16 / M₁)
Squaring both sides
(1 / 3.4)² = 16 / M₁
Cross multiplying
(1 / 3.4)² × M₁ = 16
Dividing both sides by (1 / 3.4)²
M₁ = 16 / (1 / 3.4)²
M₁ = 184.96 g/mol
Hence, the molar mass of the unknown gas is 184.96 g/mol.
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statement is true about these substances? they have exactly the same mass. they have different numbers of particles. they have the same number of atoms. they have different masses.
The statement "they have exactly the same mass" is true about these substances.
Mass is a measure of the b of matter in an object and can be determined by measuring its weight or using a balance. Two substances with the same mass will have the same number of atoms or particles if they are composed of the same b, although their arrangement of atoms or particles may be different. For example, two samples of water, one in the form of a liquid and the other in the form of a solid (ice), have the same number of water b but are in different states of matter due to differences in their arrangement of molecules. This difference in arrangement of particles does not affect the mass of the substances as mass is a scalar quantity and is not dependent on the arrangement of particles.
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Titanium (IV) chloride reacts with solid magnesium to produce magnesium chloride and solid titanium via a single displacement reaction. How many grams of magnesium chloride are produced if 50g TiCI is completely reacted?
According to the stoichiometry of the reaction taking place between titanium (IV) chloride and magnesium chloride , 50.197 g of magnesium chloride are produced if 50 g TiCI is completely reacted.
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.In the given reaction, 189.67 g titanium (IV) chloride gives 190.42 g magnesium chloride, thus 50 g titanium (IV) chloride will give 50×190.42/189.67= 50.197 g
Thus,50.197 g of magnesium chloride are produced if 50 g TiCI is completely reacted.
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Two oxides of sulphur A and B analysed and the result obtained shows that in oxide A 3.50g of sulphur combined with 6.05g of oxygen and in oxide B 2.80g of sulphur combined with 2.80g of oxygen show that this results illustrate the law of multiple proportion. Write their formulae
The results illustrate the law of multiple proportions since the oxygen atoms in A and B are in simple multiple ratios.
The formula of the oxides is SO₃ and SO₂ respectively.
What are the masses of sulfur and oxygen in A and B?Mass of sulfur in A = 3.50 g
Moles of sulfur in A = 3.50/32
Moles of sulfur in A = 0.11 moles
Mass of oxygen in A = 6.05 g
Moles of oxygen in A = 6.05/16
Moles of oxygen in A = 0.38
The mole ratio of sulfur to oxygen = 0.11 : 0.38
The mole ratio of sulfur to oxygen = 1 : 3
The formula of oxide = SO₃
Mass of sulfur in B = 2.80 g
Moles of sulfur in B = 2.80/32
Moles of sulfur in B = 0.088 moles
Mass of oxygen in B = 2.80 g
Moles of oxygen in B = 2.80/16
Moles of oxygen in B = 0.175
The mole ratio of sulfur to oxygen = 0.088 : 0.175
The mole ratio of sulfur to oxygen = 1 : 2
The formula of oxide = SO₂
The oxygen atoms in A and B are in simple multiple ratio.
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which bond occur after the second step of the pyruvate dehydrogenase reaction
After the second stage of something like the pyruvate dehydrogenase process, thioester bonds form.
What part does the thioester play?Thioesters have a significant impact on metabolism. Particularly in the case of metabolism of fatty acids. Acetyl CoA, the major metabolite, seems to be a thioester that would be primarily created by the oxidative cleavage of dopamine or by the breakdown of fatty acids.
Why does a thioester react so strongly?For instance, a thiolate (RS-) is just a weaker bases and better donating group than an alcoxide, making a thioester more sensitive than an ester (RO-). Remember from paragraph 6 that a thiol's pKa is approximately 10, whereas an alcohol's pKa is 15 or higher this means that a larger conjugate acid results in a lesser conjugate base.
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Remember it!
Determine the statement that accurately explains the
endothermic and exothermic reactions.
4
O Endothermic reactions absorb heat
energy while exothermic reactions
release heat energy.
O Exothermic reactions absorb heat
energy while endothermic reactions
release heat energy.
O Endothermic and exothermic reactions
absorb thermal energy.
O Endothermic and exothermic reactions
release thermal energy.
REM
The prefix exo-
applied to a che
mean energy
re
Statement-1 is the correct answer that is Endothermic reactions absorb heat energy while exothermic reactions release heat energy.
How can we distinguish between exothermic and endothermic processes?
Chemical reactions that release energy are referred to as exothermic. More energy is produced than is needed to break the bonds between the reactants when bonds are formed in the byproducts of exothermic processes.
Chemical processes that either use or absorb energy are referred to as endothermic. In endothermic reactions, more energy is absorbed when bonds in the reactants are broken than is released when new bonds are formed in the products. Since an isothermic chemical reaction uses exactly as much energy as it produces, there is no net energy change.
Therefore, the first statement is the right response.
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explain why the density of the metal has a high inheirt percetenage of error than the value for the liquid
The density of the metal has the high inherit percentage of error than the value for the liquid because the possibility error in measuring the volume of the solid is more than the liquid.
The density is expressed as follows :
Density = mass / volume
The volume of the solid cannot be measure directly. The volume of the solid can be measured by immersing the solid in to the liquid and then we measure the volume of the liquid displaced. The possibility error in measuring the volume of the solid, especially when the shape of the solid is irregular, is more than the liquid.
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If I perform this reaction with 25 grams of iron 3 phosphate and an excess of sodium sulfate how many grams of iron 3 sulfate can I make
This reaction with 25 grams of iron 3 phosphate and an excess of sodium sulfate, 33.190 grams of iron 3 sulfate.
What do you mean by stoichiometry ?The term Stoichiometry is defined as a section of chemistry that involves using relationships between reactants and products in a chemical reaction to determine desired quantitative data.
Step 1.
In any stoichiometry question is to find the molecular weights of the compounds involved:
FePO4 = 55.845+ 30.974 + 16*4
= 150.819 g/mol
Fe2(SO4)3 = 55.845*2 + (32.065+16*4)*3
= 399.885 g/mol
Step 2.
To find the number of moles of your reactant, FePO4:
grams of substance/molecular weight of substance= moles of substance
25g/150.819g/mol= 0.166 moles of FePO4
So, think about the proportion of how many moles of your reactant there are for each mole of your product. In this case, there are 2 moles of FePO4 for every 1 mole of Fe2(SO4)3.
0.166 mole FePO4 * 1 mole Fe2(SO4)3/ 2 moles of FePO4
= .083 mole of Fe2(SO4)
Now, multiply the number of moles of your product by its molecular weight:
0.083 moles of Fe2(SO4)3 × 399.885 g/mol
= 33.190 grams of Fe2(SO4)3
Thus, 33.190 grams of iron 3 sulfate.
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One mole of O2 has approximately the same mass as one mole of
One mole of O2 has approximately the same mass as one mole of methanol.
Mole and mass of substancesRecall that: mole = mass/molar mass, hence, mass = mole x molar mass.
O2 has a molar mass of 32 g/mol
Using the above equation, the mass of one mole of O2 will be:
Mass of 1 mole O2 = 1 x 32 = 32 grams
Methanol has a molar mass of 32 g/mol.
Mass of 1 mole [tex]CH_3OH[/tex] = 1 x 32 = 32 grams.
In other words, 1 mole of O2 will have approximately the same mass as 1 mole of CH3OH.
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How many moles of HCI are needed to produce 2.5 moles of KCI?
The reaction for the production of potassium chloride from hydrochloric acid and potassium hydroxide is:
HCl + KOH → KCl + H2O
From the reaction, it takes 1 mole of HCl to produce 1 mole of KCl.
So, to produce 2.5 moles of KCl, we would need 2.5 moles of HCl.
What is a reaction?In chemistry, a reaction is a process by which one or more compounds change into one or more other ones. Chemical bonds between atoms or molecules are often broken and new ones are generated as a result of this transition. Energy can be released or absorbed during reactions, which can happen naturally or be produced by a number of factors like heating, cooling, adding a catalyst, or being exposed to light.
In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products. In contrast to the reactants, the products have diverse properties. Physical changes, which include state transitions like ice melting to water and water evaporating to vapor, are different from chemical processes.
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A rugby team spend a number of hours training each week. 35% is spent on fitness and
this lasts for 7 hours and 21 minutes. How long do the team spend training each week?
The total time for the training is 21 hours.
How long does the team train?We can see that what we have here is a percentage of the total time that the team can spent as a part of the training that they have to pass through and this is what we are going to use to carry out the calculation that we have in the case of this problem.
Hence we can see that;
Total time that is spent = x
The percentage of the time that is spent of fitness = 35%
The allotted time for fitness is 441 minutes
Thus we have that;
35/100 * x = 441
x = 441 * 100/35
x = 1260 minutes or 21 hours
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a solution consists of 18.8 g of ammonia (nh3), 129.2 g water, and has a volume of 156 ml. calculate the weight percent of nh3, the molality of nh3, the mole fraction of nh3, and the molarity of nh3 in the solution.
A solution of 18.8 g of ammonia (nh3), 129.2 g water, which has a volume of 156 ml ha s weight percent 12.76%, mole fraction 0.131, and molarity 7.05 mol/L.
First, we'll calculate the number of moles of ammonia (NH3) in the solution:
moles of NH3 = mass of NH3 / molecular mass of NH3
moles of NH3 = 18.8 g / 17.03 g/mol = 1.10 mol
Next, we'll find the weight percent of NH3 in the solution:
weight percent of NH3 = (mass of NH3 / total mass of solution) x 100
total mass of solution = mass of NH3 + mass of water
total mass of solution = 18.8 g + 129.2 g = 148.0 g
weight percent of NH3 = (18.8 g / 148.0 g) x 100 = 12.76%
Next, we'll find the molality of NH3 in the solution:
molality = moles of solute / mass of solvent (in kilograms)
mass of solvent (water) = 129.2 g
mass of solvent in kilograms = 129.2 g / 1000 g/kg = 0.1292 kg
molality = 1.10 mol / 0.1292 kg = 8.51 mol/kg
Next, we'll find the mole fraction of NH3 in the solution:
mole fraction of NH3 = moles of NH3 / (moles of NH3 + moles of water)
moles of water = 129.2 g / 18.015 g/mol = 7.16 mol
mole fraction of NH3 = 1.10 mol / (1.10 mol + 7.16 mol) = 0.131
Finally, we'll find the molarity of NH3 in the solution:
molarity = moles of solute / volume of solution (in liters)
volume of solution = 156 ml
volume of solution in liters = 156 ml / 1000 ml/L = 0.156 L
molarity = 1.10 mol / 0.156 L = 7.05 mol/L
So, the weight percent of NH3 in the solution is 12.76%, the molality of NH3 is 8.51 mol/kg, the mole fraction of NH3 is 0.131, and the molarity of NH3 is 7.05 mol/L.
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A block has the following dimensions: length of 2.50 cm. width of
1.00 cm and height of 2.00 cm. The mass of the block is 150.0
grams. Calculate the density of the density of the block
If a block has the following dimensions: length of 2.50 cm. width of
1.00 cm and height of 2.00 cm. The density of the density of the block is: 30.0 g/cm^3.
How to find the density of the block?The volume of the block can be calculated by multiplying the length, width and height:
V = 2.50 cm x 1.00 cm x 2.00 cm = 5.00 cm^3
The density of the block can then be calculated by dividing the mass by the volume:
Density = mass/volume
Density = 150.0 g / 5.00 cm^3
Density = 30.0 g/cm^3
Therefore the density is 30.0 g/cm^3.
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