Determine the Oxidation number of the indicated element in each of the following substances: Mn in KMnO4 S in SO2 C in COCl2 P in PF4 O in K2O2

Answer:

1) Heat

Explanation:

Heat Transfer: The movement of heat from a warmer object to a colder one

Answer: A) 1

Explanation:

Lithium is the third element of the periodic table with atomic number of 3. The atomic number is equal to the number of electrons for a neutral atom and thus there are 3 electrons in Lithium.

The electronic configuration of Lithium (Li) is [tex]1s^22s^1[/tex]. Thus it can gain one electron to complete its octet and attain stability. Thus it can form one bond with other atoms.

Example: Lithium can form one bond with flourine to form LiF by losing one electron to form [tex]Li^+[/tex].

The actual value is greater than the theoretical value

Given

Reaction

Sb2S3 + 3Fe --> 2Sb + 3FeS

0.022 mol Sb2S3

0.08mol Sb

Required

The percent yield

Solution

Percent yield is the comparison of the amount of product obtained from a reaction(actual) with the amount you calculated (theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

Theoretical yield of Sb : 2/1 x 0.022 mol = 0.044 moles

In the question, there seems to be an error, because the actual yield value(0.08=?) should be smaller than the theoretical yield(0.044)

Answer:

69

Explanation:

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1.28 moles of aluminum bromide (AlBr₃) has a mass of 341.35 g.

We want to convert 1.28 moles of aluminum bromide (AlBr₃) to grams. We will need first to calculate its molar mass.

The molar mass is the sum of the total mass in grams of all the atoms that make up a mole of a particular molecule.

M(AlBr₃) = M(Al) + 3 M(Br) = 26.98 g/mol + 3 × 79.90 g/mol =

= 266.68 g/mol

1.28 mol × 266.68 g/mol = 341.35 g

1.28 moles of aluminum bromide (AlBr₃) has a mass of 341.35 g.

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Explanation:

203.31                brainliest

Answer:

203.31g when rounded to 2 decimal places.

Answer:

Air masses are also identified based on whether they form over land or over water. Maritime air masses form over water and are humid. Continental air masses form over land and are dry. ... One that forms over the Indian Ocean is called a maritime tropical air mass and is warm and humid

The type of air mass that forms in an area is determined by the location and nature of the water and land.

Air mass may be characterized as a huge volume of air that is present in the atmosphere which possesses a uniform temperature and moisture. This attribute is generally classified on the basis of latitude and continental or maritime source regions.

For example, Maritime air masses construct over water and are significantly humid. While continental air masses construct over land and are significantly dry. That is why air masses are characterized by the temperature and humidity of the given region.

Therefore, the type of air mass that forms in an area is determined by the location and nature of the water and land along with the temperature and humidity of the given region.

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Answer:

Yes, because it follows the octet rule.

Explanation:

The Lewis is correct

because it follows the octet rule.

And

The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas.

Answer:

Neither accurate nor precise

Explanation:

The measurements shown on the table are neither accurate nor precise in value.

Accuracy is the nearness of the measured value to the true value.

Precision is the ability to reproduce a result.

Answer:

2.8 x10^-4

Explanation:

Answer:

14 days.

Explanation:

If today were October 7 and we observed a waxing gibbous moon, that is, a moon with an illumination greater than a first quarter but less than a full moon, we would have to wait 14 days to see a waning crescent moon, which would be a moon with a visibility less than the last quarter but greater than a new moon.

Answer:  In one mole of carbon, we get 12g of carbon

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Answer:

C. Ill only

Explanation:

Motion can be defined as a change in location with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, displacement etc.

A reference point is an object or location from which the movement of another object is determined.

Thus, a point on a map is considered to be a reference point because it represents the starting point of an object or person in motion.

Answer:

dominant and recessive

Explanation:

Answer:

longitudinal

Explanation:

A prime meridian is the meridian (a line of longitude) in a geographic coordinate system at which longitude is defined to be 0°. Together, a prime meridian and its anti-meridian (the 180th meridian in a 360°-system) form a great circle. This great circle divides a spheroid into two hemispheres.

The given question is incomplete. The complete question is:

Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Answer:   0.0484 g

Explanation:

[tex]Q=I\times t[/tex]

where Q= quantity of electricity in coloumbs

I = current in amperes = 0.920 A

t= time in seconds = 47.0 sec

[tex]Q=0.920A\times 47.0s=43.24C[/tex]

[tex]AgNO_3\rightarrow Ag^++NO_3^-[/tex]

[tex]Ag^++e^-\rightarrow Ag[/tex]

96500 Coloumb of electricity electrolyzes 1 mole of Ag

43.24 C of electricity deposits =[tex]\frac{1}{96500}\times 43.24=0.00045moles[/tex] of Ag

[tex]\text{ mass of Ag}={\text{no of moles}\times {\text{Molar mass}}=0.00045mol\times 108g=0.0484g[/tex]

Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g

Answer:

have similar properties

Explanation:

Elements in a column of the periodic table have similar chemical properties.

A periodic column is also called a group or family.

Elements in the same group has the same number of valence electrons.

Therefore, they will combine chemically the same way.

This is not so for the periods on the periodic table.

Answer:

0.00246kg

Explanation:

1g = $40.63

$100 = $100/40.63 = 2.46g

2.46/1000 g = 0.00246kg

Answer:

1. Nucleotides

2. Amino acids

3. Monosaccharides

Explanation:

There are four major biological polymers in nature namely: carbohydrate (polysaccharides), lipids, proteins and nucleic acids. These polymers are formed from smaller units called MONOMERS, which are linked together via chemical bonds. The monomeric units of the polymers are listed below:

- Carbohydrates or polysaccharides are polymers of monomers called MONOSACCHARIDES linked by glycosidic bonds.

- Nucleic acids are polymers of monomers called NUCLEOTIDES linked by phosphodiester bonds.

- Proteins are polymers of monomers called AMINO ACIDS linked by peptide bonds.

Answer:

b

Explanation:

I did this quiz and i think a got it right i also looked up my answer to make sure it was right good luck on quiz :)

Answer:

Percent by mass is 69.42% Fe

Explanation:

If the molar mass is 159.69 grams per mol, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first. We will calculate the amu of Iron and divide that by the total molar mass of Fe2O3.. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

Fe2 = 2(55.845) = 111.69

111.69/159.69 = 0.69941762164

0.69941762164 * 100 = 69.42% Fe

The study of chemicals is called chemistry.

The correct answer to the question is Percent by mass is 69.42% Fe

If the molar mass is 159.69 grams per mole, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first.

We will calculate the AMU of Iron and divide that by the total molar mass of Fe2O3. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

[tex]Fe2 = 2(55.845) = 111.69\\\\\\frac{111.69}{159.69} = 0.69941762164\\\\0.69941762164 * 100 = 69.42% Fe[/tex]

Hence, the correct option answer is 69.42.

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Answer:

1=a 2=d i think

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 856.8648 \ grams \ of \ K_2CO_3}}[/tex]

Explanation:

To convert from moles to grams, we must find the molar mass.

1. Molar Mass

First, identify the elements in the compound. K₂CO₃ It has potassium, carbon, and oxygen. Find these elements and their masses on the Periodic Table.

Note the subscript of 2 after K and 3 after O. We must multiply oxygen's molar mass by 2, then oxygen's by 3, and add carbon.

2. Convert Moles to Grams

Use the molar mass as a fraction.

[tex]\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}[/tex]

Multiply by the given number of moles: 6.2

[tex]6.2 \ mol \ K_2CO_3 *\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}[/tex]

[tex]6.2 *\frac {138.204 \ g \ K_2CO_3}{1 }[/tex]

[tex]6.2 * {138.204 \ g \ K_2CO_3}[/tex]

[tex]856.8648 \ g \ K_2CO_3[/tex]

There are 856.8648 grams of potassium carbonate in 6.2 moles.

Answer:

gains 2 electrons. In order for the new ionic compound to form a a neutral compound, the oxygens must gain 6 electrons

Answer:

C

Explanation:

because you got to share

1.83 × 10⁻⁷ mol Au

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

3.60 × 10⁻⁵ g Au (Gold)

Step 2: Identify Conversions

Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

Answer:

5.61 * 10²¹ molecules

Explanation:

You have 1.25 g of malic acid, C4H.Os, an acid found in apples and other fruits. How many molecules of the acid do you have?

Solution:

A molecule is the group of two or more atoms held together by chemical bonds.

The number of molecules is calculated using the formula:

number of molecules in a substance = number of moles of substance * Avogadro constant

Avogadro constant = 6.02 * 10²³ mol⁻¹

number of moles = mass / molar mass

Given that mass = 1.25 g

molar mass of malic acid (C₄H₆O₅) = (12 * 4) + (1 * 6) + (16 * 5) = 48 + 6 + 80 = 134 g/mol

number of moles = mass / molar mass = 1.25 g / 134 g/mol = 0.0093 mol

Recall that: number of molecules in a substance = number of moles of substance * Avogadro constant

number of molecules in a substance = 0.0093 mol * 6.02 * 10²³ mol⁻¹ = 5.61 * 10²¹ molecules

Answer: The enantiomeric excess ee is 50%

Explanation:

Given that;

compound A = 75%, B = 25%

ee = ?

so

ee = [( A - B) / ( A + B)] × 100

= [( 75 - 25) / ( 75 + 25)] × 100

= [50 / 100] × 100

= 0.5 × 100

= 50%

Therefore enantiomeric excess ee is 50%