Describe and explain your observations using the law of conservation of charge and the properties of the conductors.

The measure of the angle EFD = 34°. That is option A.

The radii of the given circle are CE and CD.

The measure of the given angle of the arc is = 68°

But the central angle of an intercepted arc measure the double of the inscribed angle by the same arc.

Therefore, the measure of angle of an intercepted arc is 68/2 = 34°

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Answer:

34

Explanation:

edge 2023

i. The work done by the load is load x distance moved by load.

ii. The work done by effort is effort applied x distance moved by effort.

iii. The mechanical advantage of the simple machine is Load/effort.

iv. The velocity ratio of the simple machine is 2.

v. The efficiency of the machine is M.A/V.R x 100%.

The work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;

Work done by the load = load x distance moved by load

The work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;

Work done by effort = effort applied x distance moved by effort

M.A = Load/Effort

V.R = distance moved by effort / distance moved by load

V.R  = 30 cm/15 cm

V.R = 2

E = (M.A/V.R) x 100%

Thus, the work done by the load is load x distance moved by load.

The work done by effort is effort applied x distance moved by effort.

The mechanical advantage of the simple machine is Load/effort.

The velocity ratio of the simple machine is 2.

The efficiency of the machine is M.A/V.R x 100%.

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The correct option  is D.

The three lowest-pitch tones generated by this pipe have wavelengths of = 2 L, L, 2 L/3

Measuring a wave's size from one peak to the next is all that is required. The wavelength is only the separation between the crests of the successive waves, if one thinks of a sound wave as being similar to a water wave.

The length of a pipe with an opening at either end and a length l is given by:

[tex]l=\frac{n \lambda}{2}[/tex]

or

[tex]\lambda=\frac{2 l}{n}[/tex]

Initial pitch tone: n = 1.

[tex]\lambda_{1}=2 l[/tex]

The first pitch tone has n = 2

[tex]\begin{aligned}\lambda_{2} &=\frac{2 l}{2} \\\lambda_{2} &=l\end{aligned}[/tex]

The initial pitch tone has n = 3.

[tex]\begin{aligned}&\lambda_{3}=\frac{2 l}{3} \\&\lambda_{3}=\frac{2 l}{3}\end{aligned}[/tex]

The three lowest-pitch tones generated by this pipe have wavelengths of 2 L, L, and 2 L/3, respectively.

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I understand that the question you are looking for is :

Consider a pipe of length L that is open at both ends. What are the wavelengths of the three lowest-pitch tones produced by this pipe?

Answer

A. 2L, L, L/2

B. 2L, L, L/2

C. 4L, 2L, L

D. 2L, L, 2L/3

E. 4L, 4L/3, 4L/5

The membrane is depolarized compared to the resting membrane potential.

Through conformational changes from closed, nonconducting states to an open, current-conducting state, membrane depolarization activates sodium channels. Na+ channels open slowly and change from an open state to a nonconducting, rapidly inactivated state as a result of delayed openings, which contribute to the declining fraction of INa induced by prolonged depolarization. Additionally, sodium channels can move swiftly from the closed state to the fast-inactivated state. When the membrane is depolarized, inactivated channels are prevented from opening.

The distribution of channels between the closed and slow-inactivated states, however, limits the number of excitable sodium channels as a function of the membrane potential since slow inactivation acts at greater negative potentials than fast inactivation.

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Clouds of gas in space

A protostar resembles a star, but its core is still too cool for fusion to occur. The protostar's heating as it contracts is the only source of brightness. The light that protostars release is typically blocked by dust, making them challenging to study in the visible spectrum.

By the time a protostar is produced, the cloud has flattened and a protostellar disk is spinning around it. The cloud starts spinning as it collapses. These disks occasionally form planetary systems and are thought to slow the protostar's rotation. The protostar produces a powerful magnetic field as it revolves.

Additionally, a strong protostellar wind—a movement of particles into space—is produced by the magnetic field. A lot of protostars also release gas into space in the form of fast-moving streams or jets.

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Galaxy M33 is classified as a Triangulum normal spiral.

The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms.

This spiral galaxy is located in the triangle shaped constellation earning a pet name as triangular galaxy. This galaxy star formation rate is ten times higher than average found in Andromeda galaxy.  It has relatively bright apparent. This galaxy was given by Charles Messier and he classified it as Triangulum normal spiral.

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A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for 800 secs.

Newtons 3 law whilst one object exerts pressure on any other object, the second object exerts a force on the first item this is identical in significance, but opposite in course; for each movement, there is an identical, but opposite response; referred to as the law of action-reaction.

You can use the equal formulation d = rt because of this distance equals the price instance's time. To solve for speed or rate use the components for pace, s = d/t this means that pace equals distance divided by way of time. To clear up for time use the components for time, t = d/s this means that time equals distance divided by way of velocity.

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Explanation:

Step I: 1 day means 24 hours * 60 minutes * 60 seconds.

So 1 day have 86400 seconds.

Step I:

Now,

To calculate the travel distance 20,000m/s* 84600 is 1728000000m

Step Ill:

Now convert the meter in kilometer

Because 1 km = 1000 m

So, = 1728000000/1000 = 172800OKm

The thick cloud cover of Venus makes it difficulty in visibility  because of impenetrable in visible light which has made it tough for astronomers to measure the length of the planet's day . Whereas Mars have clear atmosphere which do not hinder visibility

The most important reason of why is it difficult to measure the length of the day on Venus is tougher than in mars is that Mars' atmosphere is generally clear because of which their is no visibility issue on mars but due to the thick cloud covering of Venus makes it impenetrable in visible light , due which visibility is not that clear  and it become tough to observe the length of the day on Venus.

Mars is much larger than Venus in size which makes easier to observe

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B. The amount of work done by the worker on the wheelbarrow is 250 J.

The amount of work done by the worker on the wheelbarrow is calculated as follows;

W = Fd

where;

W = 50 x 5

W = 250 J

Thus, the amount of work done by the worker on the wheelbarrow is 250 J.

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1. E is a vector pointing to the right.

2. E is a vector pointing to the left.

3. E is a vector pointing to the right.

4. E is a vector pointing to the left

A vector is an object that has both a magnitude and a direction

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Answer:

Solids

Explanation:

Solids, liquids, and gases all have mass.

Answer:

Explanation:

v = 30m/s, u = 6m/s, t = 6s

Change in velocity = v(final velocity) - u (initial velocity)

v-u = 30-6 = 24m/s

acceleration = (v-u)/t

(24m/s)/6s = 4m/s^2

The orbital speed of the satellite is 7.35*10^3 m/s.

What is orbital speed?

The speed of the satellite in its orbit is termed the orbital speed.

The orbital speed is given by the formula,

[tex]v=\sqrt{\frac{GM}{r}}[/tex]

where G is the universal gravitational constant, M is the mass of the planet and r is the distance of the satellite from the center of the planet.

Here the distance of the satellite from the center of the planet is the sum of the planet's radius and the height attained by the satellite above the ground. So

r=6370 + 1000

r=7370 km

Given the mass of the planet is 5.97*10^24 kg and the value of the gravitational constant is 6.67*10^(-11) N m^2 kg^(-2), substitute these values in the formula of the orbital speed.

Note: 1 km=1000 m

[tex]v=\sqrt{\frac{6.67\times10^{-11}\text{ N m}^2\text{kg}^{-2}\times5.97\times10^{24} \text{ kg}}{7370 \text{ km}}} \\ v=\sqrt{\frac{6.67\times10^{-11}\text{ N m}^2\text{kg}^{-2}\times5.97\times10^{24} \text{ kg}}{7370\times 1000 \text{ m}}} \\ v= 7.35\times 10^3 \text{ m/s}[/tex]

Hence the orbital velocity of the satellite is 7.35*10^3 m/s.

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The time lapse between when the bat emits the sound and when it hears the echo is 0.05 s.

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

Time (t) =?

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

t = 0.05 s

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s.

A bat emits a sound wave and carefully listens to the echoes that return to it. The returning information is processed by the bat's brain in the same way that we processed our shouting sound with a stopwatch and calculator. The bat's brain determines the distance of an object by measuring how long it takes for a noise to return.

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Correction question:

A bat emits a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away. How much time elapses between when the bat emits the sound and when it hears the echo? (Unit = s)

The initial temperature of the metal was 94.24⁰C.

The initial temperature of the metal is calculated as follows;

Q = mcΔθ

where;

Δθ = Q/mc

Δθ = (3,300) / (0.854 x 150)

Δθ = 25.76⁰C

Δθ = T₂ - T₁

T₁ = T₂ - Δθ

T₁ = 120 - 25.76

T₁ = 94.24⁰C

Thus, the initial temperature of the metal was 94.24⁰C.

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A. What can happen to energy in a system is that it can be converted.

The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

The energy of a system can be converted from one form to another.

Thus, what can happen to energy in a system is that it can be converted.

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The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:

In an atom, an electron is known to be attracted to a given nucleus by the use of "electromagnetic force".

Note that  similar to a baseball, the faster the electron is said to go, the farther away from the nucleus it is known to be seen. Therefore, the electrons in an atom are known to be in a state where they are moving a lot and very fast, so they are said to be far away from their nucleus.

Note also that energy difference between what we call consecutive levels tends to often decreases as well as increases.

Therefore, The distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n because:

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See full question below

Consider the hydrogen atom. How does the distance between adjacent orbits in a hydrogen atom vary with increasing values of the orbital number n?

The distance difference between adjacent orbit radii varies with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii increases with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii remains constant with increasing values of the principal quantum number.

The distance difference between adjacent orbit radii decreases with increasing values of the principal quantum number.

length of V-50 = 49mm

length of V-1 = 49/50mm

= 0.98mm

so,

minor measurement = (M-1) - (V-1)

= 1mm -0.98mm

= 0.02mm

☆ Therefore,

The minor measurement of the vernier scale is 0.02mm.

☆...hope this helps...☆

_♡_mashi_♡_

Answer:

The direction of the net force is at a tangent to the circle.

The change in the object’s gravitational potential energy is 2.11 J.

ΔP.E = mg(hf - hi)

where;

ΔP.E = 0.54 x 9.8(1.1 - 0.7)

ΔP.E = 2.11 J

Thus, the change in the object’s gravitational potential energy is 2.11 J.

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Answer:

350x^2

Explanation:

I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.

noob anyways I can't get u vape because first reason I lost ur money and second I felt bad for losing ur and I will not on yourself as I am thinking of a number my number is a multiple of 6.What other numbers must my number is a multiple of 6.What other numbers

For vibrational motion, the amplitude denotes the maximum displacement from the equilibrium position.

What is vibrational motion?

The motion in which there are some vibrations about the fixed position called mean position is termed vibrational motion. For example, the motion of a wave on the string has perpendicular vibration.

What is amplitude?

The amplitude is defined as the maximum displacement of the vibration from its mean position. For vibrational motion, the mean position is the equilibrium position. So amplitude is the term that denotes the maximum displacement from the equilibrium position. For example, the displacement of the string wave from its equilibrium position is the amplitude of the string wave.

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Explanation:

a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.

If you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

A dust cap is a gently curved dome mounted either in concave or convex orientation over the central hole of most loudspeaker diaphragms.

Thus, if you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

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D. The energy transfer he is experiencing is Gravitational potential to kinetic.

The bungee jumper possesses gravitational potential energy due to his position above the ground level (on a bridge).

As he starts accelerating towards a lake below, his gravitational potential energy will be converted into kinetic energy.

Thus, the energy transfer he is experiencing is Gravitational potential to kinetic.

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Answer:

a = v^2 / R        where a is the centripetal acceleration and R the radius

v = 2 π R N / t        where (N / t) is the revolutions / sec giving distance / time

a = 4 g         horizontal acceleration

4 g = (2 π R N / t)^2 / R = 4 π^2 * R * (N / t)^2

(N / t)^2 = g / (π^2 * R)

N / t = 1 /  π * (g / R)^1/2 = .318 * (9.80 m / s^2 / 8 m)^1/2  = .352 / sec

1. The time taken to discharge to 2 V is 2×10⁻⁹ s

2. The time taken to discharge to 1 V is 5×10⁻¹⁰ s

The energy stored in a capacitor is given by

E = ½CV²

But

E = Pt

Thus,

Pt = ½CV²

Where

With the formula (Pt = ½CV²), we can determine the time in each case. Detail below:

Data obtained from the question include:

Pt = ½CV²

100 × t = ½ × 1×10⁻⁷ × 2²

Divide both sides by 100

t = (½ × 1×10⁻⁷ × 2²) / 100

t = 2×10⁻⁹ s

Thus, the time required to discharge to 2 V is 2×10⁻⁹ s

Data obtained from the question include:

Pt = ½CV²

100 × t = ½ × 1×10⁻⁷ × 1²

Divide both sides by 100

t = (½ × 1×10⁻⁷ × 1²) / 100

t = 5×10⁻¹⁰ s

Thus, the time required to discharge to 1 V is 5×10⁻¹⁰ s

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Among the given objects, the largest one is dwarf elliptical, then ultra-compact dwarf and then globular clusters. Thus, option a is correct.

To find the correct answer, we need to know about the galaxies.

Thus, we can conclude that, option a is correct.

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