density dependent population growth in scetion 5.9, we introduced a model for population growth. our model predicts that a population of organisms will grow according to the differential equation:

one eigenvalue and two linearly independent eigenvectors of A ={2 2 2 } are [ 1, 2 ]

1st step:

Lambda I

here I is identity matrix.

As our matrix is 2X2 , so we will take I= [ 1  0, 0  1]

consider lambda is represented as $

so $I matrix will be [$  0, 0  $]

2nd Step:

A - Lambda I

i.e .[2  2, 2] - [0, 0  $]

=> [2-$   2,  2$]

3rd Step:

Det [A-$I]

i.e. [(2-$)(4-$) - (-2)(-4)]  = 0

=>8-2$-4$+$²-8

=>$²-6$

4th Step:

Det [A-$I]=0

i.e. $²-6$ =0

$($-6)=0

i.e. $ =0, & $ =6  (eigen values)

5th Step

put these eigen values in [A-$I] matrix

i.e if we put $ =0

we get [2  -2, -4  4]

consider this matrix as B

then

B X⁻= 0⁻    (⁻ is a bar sign notation)

[2  -2, -4  4] [x₁  x₂] =[0 0]

by row reduction

-2R₁+ R₂ -> R₂

so  

2X₁-2X₂=0

X₁=X₂

ie eigen vector will be [0 0]

now consider

i.e if we put $ =6

we get [-4  -2, -4  -2]

consider this matrix as B

then

B X⁻= 0⁻    (⁻ is a bar sign notation)

[-4  -2, -4  -2] [x₁  x₂] =[0 0]

by row reduction

R₁- R₂ -> R₂

so  

-4X₁-2X₂=0

2X₁=X₂

if we put X₁=1

x₂=2

So eigen vector will be

[1  2]

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The amount of the commission earned by Zachary on the $635 sale is $196.85.

A commission is a percentage of a sale earned by a sales person.

Given that;

Since commission is a percentage of a sale earned

Commission amount = sale price × commission

Plug in the given values and simplify

Commission amount = $635 × 31%

Note that; 31% is the same as 31/100

Commission amount = $635 × 31/100

Commission amount = $635 × 0.31

Multiply $635 and 0.31

Commission amount = $196.85

Therefore, the amount of commission is $196.85.

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The standard equation of a line is expressed as y = mx + b

m is the slope

b is the y-intercept

Given the equation y = 2x - 2

If x = -2

y = 2(-2) - 2

y = -4-2

y = -6

If x  = 4

y = 2(4) - 2

y = 8-2

y = 6

This shows that the point (-2, -6) and (4, 6 )must be on the line graph. FInd the graph attached below.

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The equation 5x = x + 3 has 1 solution.

The solution to the equation 5x = x + 3 is x = 3.

The 5x factored out will be 5x(4x+3)

What is the Greatest Common Factor?

The greatest common factor, which is the product of two or more numbers, is the largest number (GCF). A natural number is created by dividing them by the biggest number (factor). There are a few factors that both share once all the number's factors have been identified. The greatest common factor is the one with the largest number among the common factors. The highest common factor is another name for the GCF (HCF)

The factors of 20x2 (all the values that will divide into 20x2:  

1, 2, 4, 5, 10, 20, x, 2x, 4x, 5x, 10x, 20x, x2, 2x2, 4x2, 10x2, 20x2

The factors of 15x:

 1, 3, 5, 15, x, 3x, 5x, 15x

The greatest ("largest") one that is common ("in both lists"):

5x

So, with the 5x factored out:    5x(4x+3)

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The full question

Factor out the greatest common factor.

20x2 + 15x

Answer:

[tex]\displaystyle{\text{possible rational roots} = \pm 1, \pm \dfrac{1}{2}, \pm 3, \pm \dfrac{3}{2}, \pm 9, \pm \dfrac{9}{2}, \pm 27, \pm \dfrac{27}{2}}[/tex]

Step-by-step explanation:

Rational Root theorem is when we divide the factors of last term by the factors of first term:

[tex]\displaystyle{\text{possible rational roots} = \dfrac{\text{factors of the coefficient of last term (constant)}}{\text{factors of lead coefficient (coefficient of first term)}}}[/tex]

Our constant (last term) is -27. The factors of -27 can be ±1, ±3, ±9, ±27

Our lead coefficient is 2. The factors of 2 can be ±1 and ±2.

Hence:

[tex]\displaystyle{\text{possible rational roots} = \dfrac{\pm 1, \pm 3, \pm 9, \pm 27}{\pm 1, \pm 2}}\\\\\displaystyle{\text{possible rational roots} = \pm 1, \pm \dfrac{1}{2}, \pm 3, \pm \dfrac{3}{2}, \pm 9, \pm \dfrac{9}{2}, \pm 27, \pm \dfrac{27}{2}}[/tex]

All of these are possible roots, meaning that not all of them are real roots of the equation, just a possibility.

The function is defined by m(x)=f(x)/2g(x) is m′(5))=[tex]\sqrt[3]{3/2}[/tex] on graph.

A function is a relation that is "well-behaved," by which we mean that, given a starting point, we know the exact one ending spot to go to; given an x-value, we get only and precisely one corresponding y-value. As a result, even though all functions are relations [since they pair information], not all relations are functions. Family members who behave well are a subset of all your relations, just as well-behaved functions are a subset of all mathematical relations.)

f(x)=2x+3,XE[-1,2]

-2/3x+25/3, XE[2,8]

g(x)=√x^2−x+3 XE

m′(5))=[tex]\sqrt[3]{3/2}[/tex]

The thing to notice here is that f(x) is expressed differentially in different domain.

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The area in a square meter is 5$. We can equate the two expressions for the length of the edge of the square and solve for x:

$4x - 15 = 20 - 3x$

$7x = 35$

$x = 5$

The length of one edge of the square is 5 meters, so the area of the square is $5^2 = 25$ square meters. Therefore 5$ is the solution for the $4x-15$ and  20 - 3x$ equation. 15 and 3 will exchange their places to form 7$ and 35$ and 5$ is the end result of the problem that is given.

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A real estate agent has 17 properties that she shows,  the probability of selling no more than 3 properties in one week is 0.0464 or 4.64%.

There are only two possible outcomes for each attribute. Selling one home does not affect the likelihood of selling another. Therefore, to answer this query, we employ the binomial probability distribution.

Binomial probability distribution

The probability of precisely x successes on n repeated trials is known as a binomial probability, and X can only have two possible outcomes.

[tex]P(X=x) = C_{n} , x.P^x.(1-P)^{n-x}[/tex]

Given by the following formula.

[tex]C_{n} , x = \frac{n!}{x! (n-x)!}[/tex]

And p is the probability of X happening.

n = 17

P = 0.4

P(X≤3) = P(X=0) + P(X=1) + P(X=2) + P(X=3)

In which,

[tex]P(X=x) = C_{n} , x.P^x.(1-P)^{n-x}[/tex]

[tex]P(X=x) = C_{n} , x.P^x.(1-P)^{n-x}\\P(X=0) = C_{17} ,0.(0.4)^0.(0.6)^{17} = 0.0002\\P(X=1) = C_{17} ,1.(0.4)^1.(0.6)^{16}=0.0019\\P(X=2) = C_{17} ,2.(0.4)^2.(0.6)^{15}=0.0102\\P(X=3) = C_{17} ,3.(0.4)^3.(0.6)^{14}=0.0341[/tex]

P(X≤3) = P(X=0) + P(X=1) + P(X=2) + P(X=3) = 0.0002 + 0.0019 + 0.0102 + 0.0341  = 0.0464

Therefore probability of selling no more than 3 properties in one week is 0.0464 or 4.64%.

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So the initial value of x was 11142.86 when divided by 1/6, then divided by 1/13, and finally divided by 1,000.

An algebraic equation, also known as a polynomial equation, is a mathematical equation of the form P=0, where P is a polynomial with coefficients in some field, most commonly the field of rational numbers. In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign.

Here,

Let's call the original value of x as X. Then, we can write the following equation:

X - X/6 - X/13 = 1000

Expanding the first two terms on the left-hand side:

X - X/6 - X/13 = 1000

7X/78 = 1000

X = 78 * 1000 / 7

X = 11142.85714

So, the original value of x was 11142.86 when x is taken away by 1/6, then taken away by 1/13 and left with 1,000.

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lim (x → a) f(x) = ∞ , The limit does not exist and is neither ∞ nor - ∞

The vertical line test is used to verify function. That is, a graph must have a unique y value for it to be referred to as a function for a certain (unique) value of x. If for a particular x, and y values are coming it means it is not a function. If it crosses y-axis twice it means for a particular x value , two different value of y will exist. And that is not possible for a function

From the graph, we know that limit at point a is:

lim (x→a) f(x) exists if and only if

lim (x →a⁺) f(x) = lim (x→a⁻) f(x) and ≠ ∞

∴ right hand side limit = left hand side limit

lim (x →a⁺) f(x) = - ∞

lim (x →a⁻) f(x) = - ∞

∴ lim (x → a) f(x) = ∞

thus, option B is the correct answer.

The limit does not exist and is neither ∞ nor - ∞

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The value of f(7) is 31

Now, According to the question:

First fundamental theorem of integral calculus states that “Let f be a continuous function on the closed interval [a, b] and let A (x) be the area function. Then A′(x) = f (x), for all x ∈ [a, b]”.

"Information available from the question"

If f(3) = 15, f ' is continuous, and 7 f '(x) dx 3 = 16,

Since ∀x,  f'(x) = f(x) , f is a primitive function of f'.

Therefore,

[tex]=\int\limits^7_3f' {x} \, dx = f(x)|^7_3[/tex]

= f(7) - f(3)

= f(7) - 15 = 16

by the fundamental theorem of calculus (part 2) (because f' is continuous and thus integrable).

= f(7) = 16 + 15

=> f(7) = 31

Hence, The value of f(7) is 31

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Answer:

23%

Step-by-step explanation:

Without additional information, it is impossible to determine the probability that the toy is not cool.

Without additional information, it is impossible to determine the probability that the toy is not cool. This is because the color of the toy does not provide any information about its coolness. For example, a red toy could be a cool action figure or a boring stuffed animal. Therefore, the color of the toy does not provide any insight into its coolness, and thus any probability assigned to the toy being not cool would be purely speculative and not based on any information. In order to determine the probability that the toy is not cool, we would need additional information, such as what the toy is, what its features are, or who makes it.

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Answer:

0.02777777778 or 1/36

Step-by-step explanation:

1/9 divided by 4 = 0.02777777778 or 1/36

Answer:

16 per 4 tickets so that 4 a ticket so multiply 4 bye 1000 to get 4000

Step-by-step explanation:

Answer:

$4000 because the amount it costs is larger than the quantity, so the price will be more.

Step-by-step explanation:

Hope it helps! =D

The scale factor of the dilation is given by the equation s = 2.5

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the triangle be represented as RST

Let the dilated triangle be represented as R'S'T'

Now , the coordinates of ΔRST is

The coordinate of R = R ( 0 , 4 )

The coordinate of S = S ( 2 , 4 )

The coordinate of T = T ( 2 , 2 )

And , the coordinates of ΔR'S'T' is

The coordinate of R' = R' ( 0 , 10 )

The coordinate of S = S ( 5 , 10 )

The coordinate of T = T ( 5 , 5 )

So , the dilation scale factor is given by coordinate of R' / coordinate of R

Substituting the values in the equation , we get

Scale factor s = 10/4

Scale factor s = 5/2

Scale factor s = 2.5

Hence , the dilation scale factor is 2.5

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This is an equation is e⁻¹³⁸ˣ - 5e⁻¹³⁹ × 81y + z = 6

In mathematics, a tangent is a line that touches a curve at a single point and has the same slope as the curve at that point. The tangent can be thought of as an approximation of the curve at the point where it touches it.

The concept of the tangent is used in calculus and other branches of mathematics to study the properties of curves and to analyze their behavior. The derivative of a function at a point is defined as the slope of the tangent to the curve of the function at that point. The derivative is a fundamental concept in calculus and is used to study the rate of change of a function, the optimization of functions, and to solve problems in many different fields.

To find the equation of the tangent plane to the surface z = e^(x - y^5) at the point (3, 3, 6), we need to find the normal vector of the surface at that point, and use that to find the equation of the plane.

The normal vector can be found using the gradient of the surface, which is given by the partial derivatives of the function:

∇f = ∇(e^(x - y^5)) = (e^(x - y^5), -5e^(x - y^5)y^4, 1)

Evaluating this at the point (3, 3, 6), we get:

∇f(3, 3, 6) = (e^(3 - 3^5), -5e^(3 - 3^5)3^4, 1) = (e^-138, -5e^-138 * 81, 1)

So the normal vector of the surface at the point (3, 3, 6) is (e^-138, -5e^-138 * 81, 1).

To find the equation of the tangent plane, we need to find a point on the plane, and use that along with the normal vector. We already know that the point (3, 3, 6) is on the surface, so we can use that as a point on the plane.

Using the point-normal form of a plane, the equation of the tangent plane is given by:

ax + by + cz = d

Where (a, b, c) is the normal vector and (x⁰, y⁰, z⁰) is a point on the plane.

Substituting the values, we get:

e⁻¹³⁸ˣ - 5e⁻¹³⁹ × 81y + z = 6

This is the equation of the tangent plane to the surface z = e^(x - y^5) at the point (3, 3, 6).

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The point on a line where it crosses the y-axis is known as the y-intercept. To put it another way, it is the value of y when x is equal to 0. This can sometimes have real significance for the model that the line offers, but it can also have no significance. In this section, we will see examples of both categories.

The y-intercept can frequently be used as a beginning point when the line in question represents a group of data or observations.

The formula m = r(SDy/SDx) can be used to get the slope of a least squares regression.

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I = (1/12) ML² is a common way to write the moment of inertia of a rod whose axis passes through its center and has mass (M) and length (L).

Therefore,

When the rod's axis passes through the end of the rod, the moment of inertia can also be stated using a different formula. In this instance, we apply I = 13 ML².

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The median lies outside the span of the box is always false.

Boxplots are particularly helpful for immediately determining a collection of data's location, dispersion, symmetry, or skewness as well as for comparing these characteristics between two or more data sets. Building a boxplot is straightforward.

A box and whisker plot, often known as a box plot, shows a data set's five-number summary. The minimum, first quartile, median, third quartile, and maximum make up the five-number summary.

In a box plot, we draw a box from the first quartile to the third quartile. A vertical line goes through the box at the median. The whiskers go from each quartile to the minimum or maximum.

Thus, The median lies outside the span of the box is always false.

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The correct option regarding the range of the function graphed in this problem is given as follows:

−4 ≤ y ≤ 2.

The range of a function is the set that contains all the output values that can be assumed by the function.

Hence, on the graph, the range of the function is given by the values of y assumed by the graph of the function.

The minimum and maximum values of y are given as follows:

As the function is continuous, the range is given as follows:

−4 ≤ y ≤ 2.

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The tangent line to the parabola y = x² at the point (6, 36) is (0.141, 1.68)

The equation of the tangent line at the point (6, 36) can be found using the derivative of the function and the point-slope form of a line:

f(x) = x²

f'(x) = 2x

y = f'(x) * (x - 6) + 36

Substituting f'(x) = 2x,

y = 2x * (x - 6) + 36

Now, we can find a unit vector that is parallel to this line by finding a non-zero multiple of the direction vector of the line, which is (1, 2x), and normalizing it.

To normalize, we divide by the magnitude, which is sqrt(1^2 + (2x)^2) = sqrt(1 + 4x^2).

Let's use x = 6:

y = 2 * 6 * (x - 6) + 36

y = 72

So, the direction vector is (1, 12) and its magnitude is sqrt(1 + 144) = sqrt(145) = 7.07.

The unit vector that is parallel to the tangent line is (1/7.07, 12/7.07) = (0.141, 1.68).

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The correct answer is option 1. In a continuous probability distribution, the random variable can take on an infinite number of values within a given range.

This range is typically represented by the interval between two points on the number line, such as 0 and 100. The probability of a particular value occurring is defined as the area under the curve of the probability density function for that distribution, rather than a single value.

Option 2, "may have a probability greater than 1.00" is incorrect as probabilities are always between 0 and 1, inclusive.

Option 3, "has a limited number of values" is incorrect as, by definition, continuous random variables can take on an infinite number of values.

Option 4, "is discrete" is incorrect as a continuous random variable is not limited to a finite or countable number of values.

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Population, Statistic, sample, Variable, data, parameter are the correct matching vocabulary words.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

The correct matching of the vocabulary words and the examples given of the web administrator's process are:

Population - All the days that the website has been in existence.

Statistic - The average number of visitors per day for the 42 days that the administrator tracked.

Sample - The 42 randomly selected days that the administrator tracked.

Variable - The number of visitors that the website receives on a given day.

Data - The list of visitor counts for the 42 days that were tracked.

Parameter - The average number of visitors per day that have come to the website since it was created.

Hence, Population, Statistic, sample, Variable, data, parameter are the correct matching vocabulary words.

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The 4 in 64.723 has a value that is 10 times greater than the value of the 4 in 9.048.

The values of the 4 in 64.723 and 9.048 are not directly comparable because they represent different places in the number and have different values as a result.

In 64.723, the 4 is the hundredths place, which means it represents 0.04. In this case, the value of the 4 is 0.04.

In 9.048, the 4 is the thousandths place, which means it represents 0.004. In this case, the value of the 4 is 0.004.

To compare the two values of 4, we can divide the value in 64.723 by the value in 9.048:

0.04 / 0.004 = 10

So the value of the 4 in 64.723 is 10 times the value of the 4 in 9.048. This means that the 4 in 64.723 has a value that is 10 times greater than the value of the 4 in 9.048.

Therefore, the 4 in 64.723 has a value that is 10 times greater than the value of the 4 in 9.048.

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The 4 in 64.723 has a value that is 10 times greater than the value of the 4 in 9.048.

The values of the 4 in 64.723 and 9.048 are not directly comparable because they represent different places in the number and have different values as a result.

In 64.723, the 4 is the hundredth place, which means it represents 0.04. In this case, the value of the 4 is 0.04.

In 9.048, the 4 is the thousandths place, which means it represents 0.004. In this case, the value of the 4 is 0.004.

To compare the two values of 4, we can divide the value in 64.723 by the value in 9.048:

0.04 / 0.004 = 10

So the value of the 4 in 64.723 is 10 times the value of the 4 in 9.048. This means that the 4 in 64.723 has a value that is 10 times greater than the value of the 4 in 9.048.

Therefore, the 4 in 64.723 has a value that is 10 times greater than the value of the 4 in 9.048.

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The answer to these questions is "7," but before we get there, let's define the instantaneous rate and its further computation.

A rate at a specific time is called an immediate rate.The negative ball of the reactant concentration curve with respect to time t is calculated by calculating the pitch of the product amounting with respect to time t.

Given:

at X = 3

y = 21 according to the graph.

In light of this, given that X = 3 and the instantaneous rate of changes,

that is half.

Consequently, y/x = 21/3 = 7 is the instantaneous rate of change.

The final response is "7," as a result.

The answer to these questions is "7," but before we get there, let's define the instantaneous rate and its further computation.

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It appears that for any ax + b, a combination of ax + b and 2a+d equals 1. This can be proven by setting P(x) = -ax - b and Q(x) = 2a+d.

(a) No combination of 2x + 5 and 3 can equal 1.

Let P(x) and Q(x) be two integer polynomials such that P(x)·(2x + 5) + Q(x)·3 = 1.

This can be written as P(x)·2x + P(x)·5 + Q(x)·3 = 1.

Rearranging, we get P(x)·2x + (P(x)·5 + Q(x)·3) = 0

This implies that P(x)·2x = -(P(x)·5 + Q(x)·3).

Since both P(x) and Q(x) are integer polynomials, it follows that P(x)·2x and (P(x)·5 + Q(x)·3) are both integers.

However, this is impossible since the left hand side is an even integer, while the right hand side is an odd integer.

Therefore, no combination of 2x + 5 and 3 can equal 1.

(b) A combination of 2x + 5 and 4 that equals 1 is P(x) = -2x - 5 and Q(x) = 4.

(c) No combination of 15x+9 and 25 equals 1. However, a combination of 15x+9 and 20 equals 1. This can be seen by setting P(x) = -15x - 9 and Q(x) = 20.

(d) Some examples of ax + b and d combinations that equal 1 are:

2x + 5 and 4

3x + 4 and 7

4x + 3 and 9

5x + 2 and 11

It appears that for any ax + b, a combination of ax + b and 2a+d equals 1. This can be proven by setting P(x) = -ax - b and Q(x) = 2a+d.

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Answer Px1 and px2 is the same

Step-by-step explanation: