Danielle took an iron nail and wrapped thin copper wire around it, then connected the ends of the copper wire to a battery. Which two forces can Danielle's device produce?

A. electrical force and frictional force

B. electrical force and magnetic force

C. frictional force and gravitational force

D. magnetic force and gravitational force

Answers

Answer 1

Answer:

It's B (electrical force and magnetic force) I just took the test.

Answer 2

The two forces can Danielle's device produce will be an electrical force and magnetic force. Daniel forms a coil resulting in both forces.

What is electric force?

Electric Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force. it is the ratio of voltage to the distance between them.

Danielle took an iron nail and wrapped thin copper wire around it, then connected the ends of the copper wire to a battery.

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil.

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

The two forces can Danielle's device produce will be an electrical force and magnetic force. Daniel forms a coil resulting in both forces.

Hence option B is correct.

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Related Questions

A circular ferris wheel that revolves at a constant rate once every 30 seconds. The
radius of the ferris wheel is 10 m. What is the normal force of the ferris wheel on a 10
kg toddler at the very bottom of the ferris wheel?

Answers

The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.

Centripetal force of the Ferris wheel

The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is calculated as follows;

Fn = Fc + mg

Fn = mω²r + mg

Fn = m(ω²r + g)

where;

ω is the angular speed = 1 rev/30 s = 2π/30 s = 0.21 rad/s

Fn = 10(0.21² x 10  + 9.8)

Fn = 102.41 N

Thus, the normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.

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What was made first? The color orange or the food orange? it's not on my test I just want to know.

Answers

Answer:

the fruit was made before the color

Answer:

I think the color because I lowkey think the food Orange was named after the color bc ofc it was Orange.

Explanation:

Part I: Friction Parabola Track 1. Click Reset and observe the energy bars as the skater moves back and forth. As the skater descends his kinetic energy (green) ____________ and his potential energy (blue)_________. The total energy bar_____________. 2. Considering the bottom of the parabola as a reference line, measure the maximum height (h) the skater climb. h

Answers

As the skater descends his kinetic energy increases and his potential energy decreases. The total energy remains constant.

What is energy?

Energy is the ability to do work. Types of energy are potential, kinetic, thermal and so on.

Potential energy is the energy stored in an object due to its position relative to another object. Kinetic energy is the energy due to the motion of an object.

As the skater descends his kinetic energy increases and his potential energy decreases. The total energy remains constant.

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explain why it is dangerous to jump from a fast moving train

Answers

Answer:

When you jump off a train, you jump off a certain height and your downwards (vertical) velocity is zero. But your forward (horizontal) velocity is not. You will hit the ground on split second with your horizontal velocity practically the same as the train.

Explanation:

you be in serious injury.

Help me real quick someone

Answers

Explanation:

10 ......

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A photovoltaic panel of dimension 2 m × 4 m is installed on the roof of a home. The panel is irradiated with a solar flux of GS = 700 W/m2 , oriented normal to the top panel surface. The absorptivity of the panel to the solar irradiation is αS = 0.83, and the efficiency of conversion of the absorbed flux to electrical power is η = P/αSGSA = 0.553 − 0.001 K−1 Tp, where Tp is the panel temperature expressed in kelvins and A is the solar panel area. Determine the electrical power generated for (a) a still summer day, in which Tsur = T[infinity] = 35°C, h = 10 W/m2 ⋅K, and (b) a breezy winter day, for which Tsur = T[infinity] = −15°C, h = 30 W/m2 ⋅K. The panel emissivity is ε = 0.90

Answers

Answer:

(a) the electrical power generated for still summer day is 1013.032 W

(b)the electrical power generated for a breezy winter day is 1270.763 W

Explanation:

Given;

Area of panel = 2 m × 4 m, = 8m²

solar flux  GS = 700 W/m²

absorptivity of the panel, αS = 0.83

efficiency of conversion, η = P/αSGSA = 0.553 − 0.001 K⁻¹ Tp

panel emissivity , ε = 0.90

Apply energy balance equation to determine he electrical power generated;  

transferred energy + generated energy = 0

(radiation + convection) +  generated energy = 0

[tex][\alpha_sG_s-\epsilon \alpha(T_p^4-T_s^4)]-h(T_p-T_\infty) - \eta \alpha_s G_s = 0[/tex]

[tex][\alpha_sG_s-\epsilon \alpha(T_p^4-T_s^4)]-h(T_p-T_\infty) - (0.553-0.001T_p)\alpha_s G_s[/tex]

(a) the electrical power generated for still summer day

[tex]T_s = T_{\infty} = 35 ^oC = 308 \ k[/tex]

[tex][0.83*700-0.9*5.67*10^{-8}(T_p_1^4-308^4)]-10(T_p_1-308) - (0.553-0.001T_p_1)0.83*700 = 0\\\\3798.94-5.103*10^{-8}T_p_1^4 - 9.419T_p_1 = 0\\\\Apply \ \ iteration \ method \ to \ solve \ for \ T_p_1\\\\T_p_1 = 335.05 \ k[/tex]

[tex]P = \eta \alpha_s G_s A = (0.553-0.001 T_p_1)\alpha_s G_s A \\\\P = (0.553-0.001 *335.05)0.83*700*8 \\\\P = 1013.032 \ W[/tex]

(b)the electrical power generated for a breezy winter day

[tex]T_s = T_{\infty} = -15 ^oC = 258 \ k[/tex]

[tex][0.83*700-0.9*5.67*10^{-8}(T_p_2^4-258^4)]-10(T_p_2-258) - (0.553-0.001T_p_2)0.83*700 = 0\\\\8225.81-5.103*10^{-8}T_p_2^4 - 29.419T_p_2 = 0\\\\Apply \ \ iteration \ method \ to \ solve \ for \ T_p_2\\\\T_p_2 = 279.6 \ k[/tex]

[tex]P = \eta \alpha_s G_s A = (0.553-0.001 T_p_2)\alpha_s G_s A \\\\P = (0.553-0.001 *279.6)0.83*700*8 \\\\P = 1270.763 \ W[/tex]

4. Brian stands at the edge of a cliff and throws a stone horizontally over the edge with a
speed of 18 m/s. The cliff is 50 m above a flat, horizontal beach: (2 pts each)
a. How long does it take for the stone to reach the bottom of the cliff?
b. What is the range of the stone?
5. A student shot a basketball at an initial velocity of 25 m/s at an angle of 30 degrees with
respect to the horizontal: (2 pts eac)
a. What is the vertical component of the initial velocity?
b. What is the maximum height reached by the arrow?
6. A fireman stands 50 m away from a burning building and directs a stream of water from
ground level at an angle of 30° above the horizontal. If the speed of the stream as it
leaves the hose is 40 m/s: (2 pts each)
a. How long will it take for the stream to reach the building?
b. At what height will the water strike the building?

Answers

Answer:A).3.16 s B).56.92

A).12.5m/s

B).7.81m

Explanation:

Example Compute the capacitance of a parallel-plate capacitor with plates 10cm by 20cm, separation of 5mm, and a mica dielectric.​

Answers

Answer:

Explanation:

Mica dielectric constant (k) is approximately 3. The distance between the plates is 5 mm = [tex]5\times10^{-3}[/tex] m = d and the area of each plate is[tex]A = 0.1\times 0.2=2\times 10^{-2} m^{2}[/tex]. So, the capacitance of that capacitor is:

[tex]C=\frac{\epsilon_{0}kA}{d}=\frac{(8.85\times10^{-12})(3)(2\times10^{-2}}{5\times10^{-3}}=10.62\times10^{-11} =1.062\times10^{-10} F[/tex]

or approximately 0.106 nF.

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the instantaneous velocity of the particle when t=1.0 s?

Answers

Answer:

pls first attach the fig.

The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.

What do you mean by average speed ?

The term average speed is defined as the total distance traveled by the object in a particular time interval.

In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.

       v = Δ x / Δt

Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

Therefore,

v =  2.0 - ( - 2.0 ) / 4.0 - 1.0

v = 1.33 m / s          

Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.

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Your question is incomplete, most probably your question was

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?

Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.

a 1000 kg car traveling at 70 m/s takes 3 m to stop under full braking. the same car under similar road conditions, traveling at 140 m/ s takes how long to stop under full braking?

Answers

Answer:

0.21 SECONDS

Explanation:

THE CAR TRAVELS AT A SPEED OF 140M/S AND A DISTANCE AS THE PREVIOUS = 3M THEREFOR S=D/T, T=D/S= 3/140= 0.12 SEC

A gold wire carries a current of 76.2 mA.

(a) Find the number of electrons that flow past a given point in the wire in 10.4 minutes.
[Answer] electrons

b)In what direction do the electrons travel with respect to the current?
o opposite direction
o same direction
o The magnitude is zero.

Answers

#a

Time=10.4min=10.4(60s)=624sCurrent=76.2mA=76.2×10^{-3}A=I

Now

Charge=Q

[tex]\\ \tt\Rrightarrow Q=\dfrac{I}{t}[/tex]

[tex]\\ \tt\Rrightarrow Q=\dfrac{76.2\times 10^{-3}}{624}[/tex]

[tex]\\ \tt\Rrightarrow Q=0.122\times 10^{-3}[/tex]

[tex]\\ \tt\Rrightarrow Q=122\times 10^{-6}C[/tex]

[tex]\\ \tt\Rrightarrow Q=122\mu C[/tex]

#b

Same direction

The force that keeps objects moving in a circle is called centripetal force. A. True B. False​

Answers

Answer:

true

Explanation:

look it up

hope this helped u ;)

Answer:

True

Explanation:

Took The Test

Gravity is a force that acts upon a ball after it is thrown

true

false​

Answers

Answer:

true.

Explanation:

The forces on a thrown ball after it leaves the thrower's hand are the force of gravity .

Question 1: What is the before image showing?

Question 2: What is the after image showing?

Answers

Answer:

the after image is showing precipitation. i dont know what the before image is though.

Explanation:

the tip of the nail is sharp.why?​

Answers

Answer:

To minimize area which in turn increases pressure

if an astronaut weighs 981 N on Earth and only 160 N on the Moon, then what is his mass on the Moon?

Answers

Answer:

if an astronaut weighs 981 N on Earth and only 160 N on the Moon, then what is his mass on the Moon?

ANSWER 256n

The mass of the astronaut on the moon as compared to the earth will be  [tex]M_m=97.85\ lg[/tex]

What will be the mass?

The mass of any substance or body is defined as how much quantity of matter is present.

Now it is given in the question:

Weight of the astronaut on earth  [tex]W_E=981\ N[/tex]

Weight of the astronaut on earth  [tex]W_M=160\ N[/tex]

The mass of the astronaut on the moon will be calculated as:

Weight on the moon will be  given as:

[tex]W_M=M_M\times g_m[/tex]

Weight on the earth will be given as:

[tex]W_E=M_E\times g_e[/tex]

The ratio of the gravity of the earth to the moon is given as

[tex]\dfrac{g_e}{g_m} =\dfrac{9.81}{1.62} =6[/tex]

The mass of the earth will be calculated as

[tex]W_E=M_E\times ge[/tex]

[tex]M_E=\dfrac{981}{9.81} =100\ kg[/tex]

Now taking the ratio of the weight of the earth to the moon :

[tex]\dfrac{W_E}{W_M} =\dfrac{M_E\times g_e}{M_M\times g_m}[/tex]

[tex]M_M= \dfrac{W_M\times M_E}{W_E} \times \dfrac{g_e}{g_m}[/tex]

Now by putting the value in the formula we get;

[tex]M_M=\dfrac{160\times 100}{981} \times 6=97.85\ kg[/tex]

Thus the mass of the astronaut on the moon as compared to the earth will be  [tex]M_m=97.85\ lg[/tex]

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How do you write numbers in
scientific notation? Explain
with an example.

Answers

Answer:

3.34x10*5

Explanation:

this is just a example.

take 3 sig.fig

A 50 kg student who is capable of generating 700 watts of power climbs a set of stairs that is 6.5 m high. Calculate the amount of work that the student needs to do in order to climb the stairs.​

Answers

the amount of work that the student needs to do in order to climb the stairs is 3185 J

What is work?

Work can be defined as the product of force and distance.

To calculate the amount of work that the student needs to do in order to climb the stairs, we use the formula below

Formula:

W = mgh............ Equation 1

Where:

W = Work done by the student in order to climb the stairs.m = mass of the studentg = acceleration due to gravityh = height of the student

From the question,

given:

m = 50 kgg = 9.8 m/s²h = 6.5 m

Substitute these values into equation 1

W = 50(9.8)(6.5)W = 3185 J

Hence, the amount of work that the student needs to do in order to climb the stairs is 3185 J.

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Can u please explain the force of gravity in this

Answers

Answer:

gravity is a natural phenomenon in which objects with mass,energy,light are attracted to one another

hi how are you toady



what does it mean????

Answers

Answer:

Am doing well am fine thank you

my day was good i really did do nun but start on my essay

What happens when one side of the tug of war rope has a large net force than the other

Answers

Answer:

When one side of the tug-of-war rope has a larger net force than the other side then the basket in the middle will be pulled to whichever side has a larger net force.

Explanation:

When one side of the tug-of-war rope has a larger net force than the other side then the basket in the middle will be pulled to whichever side has a larger net force.

PLEASE HELP ME!!!!!!!!!!
IT'S REALLY EASY I'M JUST STUPID

Explain what happens to the particles in a substance during a physical change.

Answers

Answer:

nothing lol

Explanation:

nothing changes in a physical change, particles stay the same unless a chemical change happens

A ball rolls 12m in 2.0s. What is the ball’s average velocity?

Answers

Answer:

6 m/s

Explanation:

12m / 2s = 6 m/s

Hope that's the answer you seek.

A block-spring system oscillates on a frictionless horizontal surface. The time needed for the block to complete one cycle is 0.1 sec. Determine the time needed for the block to travel from -A/2 to A/2, where A is the amplitude of motion.​

Answers

The time required for the block to travel or complete it's half-cycle is 0.05s

Data;

time = 0.1sdistance = -A/2 to A/2Amplitude of a Simple Harmonic Motion

This is the maximum displacement of a body from it's mean position.

Assuming a system start from its mean position i.e mean initial position and go to A/2 towards right and then back to his mean position after going through -A/2 then it is said to have completed one cycle. If the block oscillate only between -A/2 to A/2 then it will complete half cycle then it's time period will be 0.05 sec.

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The wavelength of a wave is less than
450 nanometers. Which color would this wave most likely appear
?

Answers

Answer:-

[tex]\longrightarrow \sf Indigo [/tex]

Solution:-

The color and their corresponding wavelength ranges are given in the table below.

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf colour & \bf wavelength\\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf red & \sf 650 - 700 \\ \\ \sf orange & \sf 600 - 650 \\ \\ \sf yellow & \sf \: 580 - 600 \\ \\ \sf green & \sf 550 - 580 \\ \\ \sf cyan & \sf 500 -550 \\ \\ \sf \: blue& \sf450 - 500\\ \\ \sf indigo & \sf 425- 450\\ \\ \sf violet & \sf 380 - 425 \end{array}} \\ \end{gathered}\end{gathered}[/tex]

After observing the table, we can predict that wave is most likely appear Indigo.

Note- The wavelengths boundaries between the colours are not very sharp and they form a continuous spectrum.

The direction of force of Earth's magnetic field is from the geographic South
Pole to the geographic North Pole. Where is Earth's magnetic north pole?
A. Near Earth's center
B. Near Earth's equator
C. Near Earth's North Pole
D. Near Earth's South Pole

Answers

Answer:d

Explanation:

Answer:

D

Explanation:

Furthermore, the magnetic pole near earth's geographic north pole is actually the south magnetic pole. When it comes to magnets, opposites attract. This fact means that the north end of a magnet in a compass is attracted to the south magnetic pole, which lies close to the geographic north pole.

The blood pressure of human body is greater at the feet than at the brain. why?give reason​

Answers

Answer:

Gravity stronger closer to the core of the earth

Explanation:

The gravity applied to the feet is stronger than to the upper part of the body for example the brain because of the distance it is between the body part and the core of the earth where the gravity force is pulling towards. Even though the difference between the gravity force between the brain and the feet is minimal it is still a greater force at the feet than at the brain

can someone tell me if my answer correct?

Answers

Answer:

yes

Explanation:

yes to my best known knowledge I am thinking that your answer is correct

Does The stretched string of an archer’s bow has kinetic energy in it.

Answers

Answer:

The ball has potential energy just like the Longbow has when it is stretched. The other aspect of energy that the bow portrays is kinetic energy. Kinetic energy is the energy of motion. When the string is released, the potential energy is converted to kinetic energy in movement of the arrow

Explanation:

Answer:

It has potential energy not kinetic

Explanation:

A car is uniformly accelerated at a rate of 2 m/sec2 for 12 sec. If the original speed of the car is 36 m/sec, what is its final speed?

Answers

Answer:

60m/s

Explanation:

v=u+at

v=36+(2×12)

v=36+24

v=60m/s

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