The output by the equation and energy required for friction is 160,000 J. Efficiency is 0.267 or 26.7% and this efficiency can be improved by friction reduction.
What should be the method to calculate the output, friction and efficiency?The weight of the water pushed and the height it is lifted can be multiplied to determine the beneficial work done by the pump. The volume of water in the tank multiplied by its density yields the weight of the water therein. The tank's total volume, which can be determined by multiplying the tank's cross-sectional area by its height, is equal to half of the amount of water in the tank (8 m). The water therefore weighs:
Volume is calculated as cross-sectional area times height (2 m x 8 m = 16 m3).
Weight is equal to volume times density, or 16 m3 times a density of 1000 kg/m3 equals 16,000 kg.
Useful work=Weight x Height = 16,000 kg x 10 m = 160,000 J for useful work.
A proportion of the useful work can be used to estimate the amount of energy needed for friction. This proportion is influenced by the pump's design, the water's viscosity, and other elements. The energy needed for friction can be computed using a 10% friction loss as follows:
Frictional energy equals 0.1 x 160,000 J, or 16,000 J.
The ratio of the pump's useful work to its energy input can be used to calculate the pump's efficiency. The energy input can be estimated as the motor's power (1 kW) times how long it runs for (10 minutes, or 600 seconds). So, the efficiency can be determined as follows: Energy input is calculated as follows: 1 kW x 600 sec = 600,000
Efficiency is calculated as follows: 160,000 J of useful work per 600,000 J of energy input, or 26.7%.
The friction loss can be decreased, the pump's design can be improved to reduce energy losses, or the motor's power can be increased to increase the pump's efficiency. As the beneficial work performed by the pump is directly proportional to the height the water is lifted, increasing the height the water is lifted is another alternative.
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Compute the density in g/cm³ of a piece of metal that has a mass of 0.470 kg and a volume of 77 cm³.
X g/cm³
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The density of the metal is determined as 6.1 g / cm³.
What is the density of the metal?
The density of the metal is defined as the ratio of the mass per unit volume of the metal.
Mathematically, the formula for density is given as;
ρ = m / V
where;
m is the mass of the metalV is the volume of the metalThe density of the metal is calculated as follows;
ρ = ( 0.47 kg x 1000 g/kg ) / ( 77 cm³ )
ρ = 6.1 g / cm³
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find an expression for the magnitude of the electric field that enables the block to remain at rest.
To keep the block at rest, an electric field with a magnitude equal to the gravitational force divided by the block's charge is required.
What is magnitude?A physical quantity's magnitude can be used to gauge its size or strength, such as in the case of a vector. The term "magnitude" in the context of an electric field refers to the field's amplitude.
The "equilibrium electric field" is the electric field needed to hold an object still. A force will be applied to a charged object in an electric field, either in the direction of or away from the source of the field. The net force must be zero in order to maintain the item at rest, which necessitates counteracting the electric field's force with another force.
E = k * q / d2, where k is the Coulomb constant, q is the charge on the object, and d is the separation between the item and the field source, can be used to calculate the size of the electric field necessary for equilibrium. According to this equation, the electric field is inversely proportional to the square of the distance between the item and the field source and directly proportional to the charge on the object.
As a result, if an object is charged and placed in an electric field, the size of the field needed to keep the object at rest will depend on the object's charge and the distance between it and the field source.
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An expression for the magnitude of the electric field that enables the block to remain at rest is:
[tex]\mathrm{ E = \dfrac{m \times g\times sin(\theta) }{q} }[/tex]
What is magnitude?A physical quantity's magnitude can be used tο gauge its size or strength, such as in the case of a vector
The "equilibrium electric field" is the electric field needed to hold an object still. A force will be applied to a charged object in an electric field, either in the directiοn of or away from the source of the field. The net force must be zero in order to maintain the item at rest, which necessitates cοunteracting the electric field's fοrce with another force.
According to this equation, the electric field is inversely proportional to the square οf the distance between the item and the field source and directly proportional to the charge on the οbject.
As with a typical inclined plane problem, we need tο find the compοnent of the gravitational fοrce parallel to the incline.
That is
[tex]\mathrm{ m \times g\times sin(\theta) }[/tex]
For the blοck to remain stationary, we set this equal to the coulοmb force
[tex]\mathrm{ qE = m \times g\times sin(\theta) }[/tex]
since E is parallel to the incline,
sοlving for E, we find the answer tο part a:
[tex]\mathrm{ E = \dfrac{m \times g\times sin(\theta) }{q} }[/tex]
Thus, an expression fοr the magnitude οf the electric field that enables the block tο remain at rest is:
[tex]\mathrm{ E = \dfrac{m \times g\times sin(\theta) }{q} }[/tex]
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true/false. relationship between the strength of the attractions between particles and the number of particles you expect to be in the gas phase at a given temperature.
Consider the point charges arranged at the corners and at the center of a square, as depicted in the figure. 1. Find the magnitude of the electric field, in newtons per coulomb, at the location of qa in the figure, given that qb= qc = qd = 5.6 nC, q = -1.3 nC, and the square is 6 cm on a side.
The magnitude of the electric field, in newtons per coulomb, at the location of qa in the figure is 32737.87 N/C.
What is electric field?
An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field.
When charge is present in any form, every point in space has an electric field associated with it. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
[tex]$$The $\mathrm{x}$ component of $\vec{E}_q$ is given as:$$\begin{aligned}\vec{E}_{q, x} & =E_q \cos 45^{\circ} \hat{x} \\& =k \frac{\left|-1.1 \times 10^{-9}\right|}{1.25 \times 10^{-3}} \times \frac{1}{\sqrt{2}} \hat{x}\end{aligned}$$And its y component is given as:$$\begin{aligned}\vec{E}_{q, y} & =-E_q \sin 45^{\circ} \hat{y} \\& =-k \frac{\left|-1.1 \times 10^{-9}\right|}{1.25 \times 10^{-3}} \times \frac{1}{\sqrt{2}} \hat{y}\end{aligned}$$[/tex]
[tex]$$Therefore, the net electric field at the location of $q_a$ is given as:$$\begin{aligned}\vec{E} & =\vec{E}_b+\vec{E}_c+\vec{E}_{d, x}+\vec{E}_{d, y}+\vec{E}_{q, x}+\vec{E}_{q, y} \end{aligned}[/tex]
[tex]& =k \times 10^{-9} \times\left(\left(-\frac{5.9}{(0.05)^2}-\frac{5.9}{\sqrt{2} \times 5 \times 10^{-3}}+[/tex] [tex]\frac{1.1}{\sqrt{2} \times 1.25 \times 10^{-3}}\right) \hat{x}+\left(\frac{5.9}{(0.05)^2}+\frac{5.9}{\sqrt{2} \times 5 \times 10^{-3}}-\frac{1.1}{\sqrt{2} \times 1.25 \times 10^{-3}}\right) \hat{y}\right) \end{aligned}[/tex]
[tex]\begin{aligned}& =\left(9 \times 10^9\right) \times 10^{-9} \times(-2572.13 \hat{x}+2572.13 \hat{y}) \\& =23149.17 \times(-\hat{x}+\hat{y}) \mathrm{N} / \mathrm{C}\end{aligned}[/tex]
[tex]$And its magnitude is given by:$$\begin{aligned}|\vec{E}| & =23149.17 \times \sqrt{1^2+1^2} \\& =23149.17 \times \sqrt{2} \\& =32737.87 \mathrm{~N} / \mathrm{C}\end{aligned}$$[/tex]
Thus, the magnitude of the electric field, in newtons per coulomb, at the location of qa in the figure is 32737.87 N/C.
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A parachute is used to decelerate a skydiver from an initial velocity of vo = 83 m/s to a velocity of vf = 9 m/s. The deceleration produced by the parachute is a = (-0.0302) m/s2. Determine the distance in [m], As, required to reach its final speed. As = number (3 significant figures) [m]
The distance required to be covered by the skydiver to reach the final speed is found to be 378.22m.
The deceleration produced by the parachute is -0.0302m/s². The final and the initial velocity of the skydiver are 9m/s and 83m/s respectively.
Now, we know the equation of motion,
V² - U² = 2as
Where,
V and U are the final and the initial velocity,
a is the net acceleration,
s is the distance covered by the parachute.
Now, putting all the values,
(9)²-(83)² = 2(-0.0320)s
s = 378.22 m.
So, distance that should be travelled by the skydiver is 378.22m.
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A 5.0 Ω, 10.0 Ω, 12.0 Ω, and 16.0 Ω resistor are connected in series to a 120 V voltage source. What is the current of the circuit?
A) 2.8 A
B) 4.4 A
C) 44 mA
C) 28 mA
Answer:
2.8 A
Explanation:
since the resistances are in series, the net resistance will be,
R = R1 + R2 + R3 + .....
R = ( 5+10+12+16)Ω
R = 43Ω
From Ohm's law,
V = iR
120 = i * 43
i = 120/43 A
i = 2.8A
1. An object was launched from the ground to the top of a building at a
distance of 65 m from its foot on a horizontal plane at an angle of 60
degrees. Using SOHCAHTOA, find the height of the building the
projectile was launched to from the ground.
Using SOH,CAH,TOA, we can calculate the height of the building by taking the sine of the launch angle (60°) and the distance traveled (65 m). The height of the building is 56.9 m.
What is SOH,CAH,TOA?SOH,CAH,TOA stands for Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse and Tangent = Opposite/Adjacent. This is a set of trigonometric ratios that can be used to solve for angles and lengths of sides of a right triangle. It is used when the angle and length of two sides of a right triangle are known, but the length of the third side needs to be calculated.
Calculation using SOH, CAH, TOA
The distance from the ground to the top of the building is 65 m and the angle is 60 degrees. the height (h) of the building.has to be found
Using the trigonometric ratio of Sine, calculate the height of the building:
Sin(60°) = Opposite/Hypotenuse
h/65 = sin(60°)
h = 65sin(60°)
h = 65(0.866)
h = 56.59 m
Therefore, the height of the building the projectile was launched to from the ground is 56.59 m.
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assuming you start at the top of the ramp that is 10 m tall with velocity of 10 m/s and your car has a mass of 1000 kg, what is your pe g
The gravitational potential energy of the car at the top of the ramp is 98,000 Joules.
How to calculate the potential energy?The gravitational potential energy (PE) of an object of mass m at ground level h is given by
PE = mgh
where g is the acceleration due to gravity, approximately 9.8 m/s^2 near the surface.
In this case, the car has a mass of 1000 kg and a height of 10 m above the ground. Therefore, the gravitational potential energy (PEg) is:
PEg = mgh = 1000kg * 9.8m/s^2 * 10m = 98,000J
Therefore, the gravitational potential energy of the car at the top of the ramp is 98,000 Joules.
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what concept in the video of the Big Bang Theory show which demonstrated operant conditioning that is incorrect?
Answer:
getting chocolate is a positive reinforcement
Explanation:
suppose that the apparatus used in the demonstration is placed on a moving cart. the cart moves with a constant acceleration a, and the spring is activated when the cart crosses point p. which ball will hit the ground first?a. Ball A and Ball B hit the ground simultaneously b. Ball Ac. Ball B
The ball will hit the ground first if the cart moves with a constant acceleration a, and the spring is activated when the cart crosses point P as Ball A and Ball B hit the ground simultaneously.
Thus, the correct option is A.
What is constant acceleration?Аccelerаtion is the rаte of chаnge in velocity, which is а vector, therefore, chаnges in this quаntity cаn influence its mаgnitude аnd/or direction. Аlthough аccelerаtion cаn be null, positive, or negаtive, it is, often, misunderstood аs а synonym for speeding up. This is true when аccelerаtion is positive for а strаight-line motion. In this type of motion, а negаtive аccelerаtion meаns thаt the object is slowing down, аnd а null аccelerаtion meаns thаt the speed does not chаnge.
Thus, when the cart moves with a constant acceleration a, and the spring is activated when the cart crosses point P, Ball A and Ball B hit the ground simultaneously.
Your question is incomplete, but most probably your full question can be seen in the Attachment.
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suppose that vehicles taking a particular freeway exit can turn right (r), turn left (l), or go straight (s). consider observing the direction for each of three successive vehicles.
the direction for each of three successive vehicles. A = {RRR,LLL,SSS} , B = {RLS, RSL, LSR, LRS, SRL, SLR} C = {RRS, RRL, RSR, RLR, LRR, SRR}
What is the best definition of direction?Direction is defined as the path that something takes, the path that must be taken to reach a specific place, the way in which something is starting to develop or the way you are facing. An example of direction is when you go right instead of left.
What is direction in a sentence?the course or path on which something is moving or pointing. The army attacked from three different directions. Down the road, he could see a bus coming from the opposite direction. The wind changed direction and started blowing in faces.
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Three blocks in contact with each other are pushed across a rough horizontal surface by 63 N force as shown. The acceleration of gravity is 9.8 m/s 2 kg kg 2.5 kg K = 0.1 If the coefficient of kinetic friction between each of the blocks and the surface is 0.1, find the magnitude of the force exerted on the 9 kg block by the 2.5 kg block_ Answer in units of N.
The 2.5 kg block pulls on the 9 kg block with an 87.2 N force.
Newton's Third Law, often known as the law of action and reaction, can be used to determine the force that the 2.5 kg block exerts on the 9 kg block. The force applied to the 9 kg block is equivalent to, but applied in the opposite direction from, the force applied to the 2.5 kg block. Since they are in touch, the force of friction operating on the 9 kg block is equal to the force of friction acting on the 2.5 kg block.
Calculating the friction force is as simple as multiplying the normal force, or weight of the object, by the coefficient of friction:
Step 1: Determine the normal force or weight of the object. The weight of a 9 kg object can be calculated as 9 kg x 9.8 N/kg = 87.2 N.
Step 2: Determine the coefficient of friction. In this case, the coefficient of friction is 0.1.
Step 3: Calculate the friction force by multiplying the normal force by the coefficient of friction.
Friction force = Normal force x Coefficient of friction
= 87.2 N x 0.1 = 8.72 N.
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an investor is building a hydropower station. it's 5 megawatt capacity and utility is paying 26 cents per kilowatt hour. how much revenue will the hydropower station make per year? PLEASE TRY TO SOLVE
Answer:
1,300dollars
Explanation:
5megawatt= 5*10^6watts=5,000,000W
26cents/1000watts (10^3=kilo)
total amount=26cents/1000watts*5,000,000W
=130000cents
=1300 dollars
Might be wrong but you can try this
a motorized pulley lifts an object of mass m at a constant velocity v. assuming that all frictional forces are abscent, find average power
The vertical component of acceleration at time tm can be determined by taking the second derivative of the vertical position vector with respect to time.
What is velocity?Velocity is a vector quantity that measures the rate and direction of change in an object's position. It is typically expressed in units of meters per second (m/s). Velocity is equal to the distance traveled divided by the time it takes to travel that distance. Velocity is also related to acceleration, which is the rate of change of velocity.
At time tm, the vertical component of acceleration for the module would be the derivative of the vertical velocity vector with respect to time, which is the change in vertical velocity over time. This can be calculated by taking the second derivative of the vertical position vector with respect to time. Since the position vector is a function of time, the acceleration can be determined by taking the second derivative of the position vector with respect to time, which is defined as the rate of change of the velocity with respect to time. Therefore, the vertical component of acceleration at time tm can be determined by taking the second derivative of the vertical position vector with respect to time.
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suppose that two runners run a 100-meter dash, but the first runner reaches maximum speed more quickly than the second runner. both runners maintain constant speed once they have reached their maximum speed and cross the finish line at the same time. which runner has the larger maximum speed
The runner who reaches their maximum speed more quickly has the larger maximum speed. In a 100-meter dash, reaching maximum speed more quickly generally indicates a higher level of acceleration, which is related to maximum speed.
The runner who reaches their maximum speed more slowly may have a longer time to build up speed, but once both runners have reached their maximum speed, they are both running at the same speed.
So, the runner who reached maximum speed more quickly will have had a higher maximum speed.
Speed is known as the rate of change of position of an object in any direction. Speed is calculated as the ratio of distance to the time in which the distance was covered.
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put the parts or regions of the neuron in order from the direction of where a stimulus is first received to where a response stimulus is conducted.
In sequence from the position of where a stimulation is initially absorbed to whether a reply stimulus is conducted, dendrites, cell body and soma, axon hillock, axon, and synaptic terminal sections or areas of the neuron.
Describe dendrites.Dendrites are extensions made to receive messages from nearby cells. They appear to have a tree-like shape because they produce projections that are activated by numerous other neurons and carry the electromagnetic gradient to the neurone.
What are the functions of dendrites?Dendrites receive impulses from numerous other neurons and pass them on to the nerve cell. If a neuron is sufficiently active, it will emit an electrical impulses, an electrical impulse that excites additional neurons. Huge networks of these neurons are set up, and they communicate among themselves in order to create ideas and actions.
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A thin layer of liquid with thickness h has a laminar velocity profile of u=Uo(2yh−y2h2) where Uo is the surface velocity and y is the distance from the wall along the thickness of the liquid. If the liquid thickness is 0.5 in and the flow rate per foot of channel is 1.25 gal/min, determine the surface velocity Uo
The surface velocity is approximately 2.07 m/s.
The average velocity of the liquid flow per unit depth,
Q/A = 1.25 [gal/min]/[1 ft x 0.5 in x (1/12) ft/in] = 10 [ft/min]
where Q is the flow rate and A is the cross-sectional area of the channel.
Use the laminar velocity profile to determine the velocity at the center of the channel (y=0),
u(y=0) = Uo(2(0) - 0^2)/(2h) = 0
Since there is no slip at the wall, the velocity at y=h/2,
u(y=h/2) = Uo(2(h/2) - (h/2)^2)/(h)
= Uo(2-h/2)
= 2Uo - Uh/2
Equating this to the average velocity,
2Uo - Uh/2 = 10 [ft/min]
Solving for Uo = (10 + Uh/2)/2
Uh = Ahu(y=h/2) = AhUo(2-h/2)/(h) = A*Uo(2-h/2)
Substituting A = 1 [ft^2] and h = 0.5 [in] = 0.042 [ft], we get:
Uh = Uo(2-0.042/2) = 0.979Uo
Uo = (10 + 0.979Uo/2)/2
Uo = 6.8 [ft/min] or 2.07 [m/s]
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A ball is thrown straight up. It reaches its highest point and then falls back. Which of the following is the correct statement?(a) Throughout its motion, the ball's velocity is zero(b) At the highest point in its motion, the ball's acceleration is zero(c) At the highest point in its motion, the ball's velocity is zero(d) Throughout its motion, the ball's acceleration is zero(e) At the highest point in its motion, the ball's velocity and acceleration.
The correct statement is (c): At the highest point in its motion, the ball's velocity is zero.
This is due to the fact that when anything is thrown straight up, it has a starting velocity and then accelerates as it descends towards the Earth. Its velocity is equal to zero as it reaches its highest point (due to the gravitational pull of the Earth). The ball's acceleration varies continuously as it travels because it accelerates towards the Earth when it is travelling upward and decelerates when it is travelling downward.
The ball is briefly at rest, and the only force acting on it is the gravitational pull of the Earth, therefore at its fastest point in motion, the acceleration is equal to zero.
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if a 12 V battery is connected to the circuit shown, and R1 and R2 are EACH 2 ohm resistors; what must be the resistance of R4 be if R3 is 4 ohms and the total current is 2 amp?
Answer:
Explanation:
First find the total resistance of the combination circuit:
R = V/I = 12 V / 2 A = 6 Ω
6Ω = R1 + R2 + 1/(1/R3 + 1/R4)
6Ω = 2Ω + 2Ω + 1/(1/4 + 1/R4)
2Ω = 1/(1/4Ω + 1/R4)
2Ω(1/4Ω + 1/R4) = 1
(1/4 + 1/R4) = 1/2
1/R4 = 1/4
R4 = 4Ω
Note: R1 and R2 are in series, so you just add them together. But R3 and R4 are in parallel, so Req = 1/R3 + 1/R4
Suppose the activity of a sample of radioactive material was 100, B, q,100Bq at the start. What would you divide 100, B, q,100Bq by to obtain the activity at:
n half-lives after the start?
please get back quick its due in form tomorrow
After n half-lives, its radioactivity will be 100× [tex]2^{-n}[/tex] Bq.
What is radioactivity?A characteristic of some forms of matter known as radioactivity is the spontaneous emission of energy and subatomic particles. In essence, it is a characteristic of particular atomic nuclei.
The radioactivity of the material is 100 Bq, that means, the radioactivity of the material is 1000 disintegration per second.
the relation between radioactivity and half-life is : A = A₀ 2^-n
Hence, after n half-lives, its radioactivity will be = 100 × 2^-n Bq.
Therefore, after n half-lives, its radioactivity will be 100× [tex]2^{-n}[/tex] Bq.
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Select the correct answer from each drop-down menu. What procedure is necessary when a person does not have a heartbeat? Martin, a caregiver, finds five-year-old Jessa unconscious and not breathing, Martin performs CPR balance Jessa's body fluids start Jessa's lungs manually circulate Jessa's blood and keep oxygen flowing Reset Next to help
Answer:
need points srr
Explanation:
Examine the following scenarios or questions, and determine whether science can be used to investigate them or not. You aren't being asked to decide whether or not the scenarios or questions ARE TRUE, only whether science can be used to investigate them. 1) Are the immigration laws of Canada better than those of the United States? 2) Can bacteria learn? 3) A Russian mystic claims he can move physical objects with his mind, but any attempts to monitor his actions with recording equipment interfere with the ability. 4) A truck driver is roused from sleepiness while driving, and narrowly avoids a head-on collision. He knows that his guardian angel saved his life by waking him up. 1) if I have a liter of cornflakes, am I measuring its volume, its mass, or its length? 2) If I have a meter of cornflakes, am I measuring its volume, its mass, or its length? 3) You see a measurement of 320s. Is this a measurement of temperature, duration, or computer storage capacity?
Explanation:
the Newsweek shadow STD test like that card imperial how was
The measured total pressure for each trial is the sum of the vapor pressure of the liquid and the pressure due to any air trapped in the flask (see equation 1 in the introduction) a) What happens to the air pressure in higher temperature flasks? Explain in terms of molecular motion. b) Calculate corrected air pressures for any of the trials that were not performed at the same temperature as the atmospheric pressure data. Hint: P1/T1 = P2/T2
As the temperature of the flask increases, the molecules in the air become more energetic, resulting in an increase in air pressure.
Given the total pressure measured for the each trail = vapor pressure of liquid + pressure due to any air trapped in the flask.
a) The pressure of the gas rises because the molecules collide with the container walls more frequently as a result of the faster collisions between the molecules and the walls. This is because the molecules are moving faster and collide more often with the walls of the flask, creating a greater force.
b) To calculate the corrected air pressure, the ideal gas law can be used (P1/T1 = P2/T2). The atmospheric pressure (P1) and temperature (T1) must be known for the trial and the temperature (T2) of the flask must be known. The corrected air pressure (P2) can then be calculated.
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body a of mass 4m moving with speech u colldes with another body b of mass 2m, at rest the collisn on and elastic nature. after collision the fracyion of energy lost by the colding body a is
a.1/9
b.8/9
c.4/9
d.5/9
The fraction of energy lost by the colliding body is 8/9.
In an elastic collision, the total kinetic energy of the system before the collision is equal to the total kinetic energy of the system after the collision.
Before the collision, the total kinetic energy of the system is given by:
[tex]K1 = 0.5 * m1 * u^2[/tex]
After the collision, the total kinetic energy of the system is given by:
[tex]K2 = 0.5 * m_{1} * v_{1} ^2 + 0.5 * m_{2} * v_{2}^2[/tex]
where m1 is the mass of body A, u is its initial velocity, v1 is its final velocity, m2 is the mass of body B, and v2 is its final velocity.
Conservation of momentum also applies in this case. The momentum of the system before the collision is equal to the momentum of the system after the collision.
Before the collision, the momentum of the system is given by:
[tex]p_{1} = m_{1} * u[/tex]
After the collision, the momentum of the system is given by:
[tex]p_{2} = m_{1} * v_{1} + m_{2} * v_{2}[/tex]
From the conservation of momentum, we have:
[tex]m_{1} * u = m_{1} * v_{} + m_{2} * v_{2}[/tex]
Solving for v1 and v2, we find:
[tex]v_{1} = u * (m_{1} - m_{2}) / (m_{1} + m_{2})[/tex]
[tex]v_{2} = 2 * u * m_{1} / (m_{1} + m_{2})[/tex]
Substituting these values into the equation for K2, we find:
[tex]K_{2} = 0.5 * m_{1} * u^2 * (m_{1} - m_{2})^2 / (m_{1} + m_{2})^2[/tex]
The fraction of energy lost by body A is given by:
[tex](K_{1} - K_{2}) / K_{1} = 1 - K_{2} / K_{1}[/tex]
= [tex]1 - 0.5 * m_{1} * u^2 * (m_{1} - m_{2})^2 / (m_{1} + m_{2})^2 / (0.5 * m_{1} * u^2)[/tex]
= [tex]1 - (m_{1} - m_{2})^2 / (m_{1} + m_{2})^2[/tex]
= 1 - (4 - 2)^2 / (4 + 2)^2
= 1 - (2)^2 / (6)^2
= 1 - 4/36 = 1 - 1/9 = 8/9
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Which of the following statements are true regarding the similarities between heat and work?
-both heat and work are path functions
-both heat and work can cross the boundary of a system
-both heat and work are associated with a process
-both heat and work are associated with a thermodynamic state
-systems possess energy including heat and work
Heat and work are path functions because their values depend on the path taken from the initial to the final state of a system.
What is Heat?Heat is a form of energy that is transferred from one object to another due to a difference in temperature. Heat is a form of kinetic energy, the energy of motion, and can be transferred from one object to another by conduction, convection, and radiation.
Both heat and work can cross the boundary of a system, as energy transfer in the form of heat or work can occur when a system interacts with its surroundings.
Heat and work are associated with a process, which is a change in the state of a system from one thermodynamic state to another.
Heat and work are also associated with a thermodynamic state, as the amount of heat and work exchanged between a system and its surroundings is determined by the thermodynamic state of the system.
Finally, systems possess energy in the form of heat and work, which can be exchanged between a system and its environment.
Therefore, all the given option is correct
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Starting with an energy balance on a rectangular volume element, derive the one- dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation.
The transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation can be derived from the energy balance equation for a rectangular volume element.
Consider a plane wall with constant thermal conductivity, k, and no heat generation. Let's assume that the wall is at temperature T at time t and T + ΔT at time t + Δt. The energy balance equation for a rectangular volume element of the wall can be expressed as:
ΔQ/Δt = -kA(ΔT/Δx), where
ΔQ/Δt is the rate of heat transfer into the volume element k is the thermal conductivityA is the cross-sectional area of the wallΔT/Δx is the temperature gradient across the wall.Rearranging the equation:
ΔT/Δt = -(k/A)(ΔT/Δx)
The above equation represents the one-dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation.
This equation can be further simplified by using the thermal diffusivity, α, which is defined as:
α = k / (ρCp) where,
ρ is the density of the material Cp is the specific heat capacity.Substituting α into the equation:
ΔT/Δt = -α(ΔT/Δx^2)
This is the final form of the one-dimensional transient heat conduction equation for a plane wall with constant thermal conductivity and no heat generation.
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Find the average velocity of the cat if she ran +110 meters in 50 seconds. Round to two decimal places, and include both magnitude and direction.
A substance with stronger molecular attraction will evaporate at a higher/lower temperature because it requires more/less energy to be ADDED to overcome attraction between the molecules.
A phase change occurs when the kinetic energy increases/decrease enough so that the attraction between molecules pulls them together.
A substance with weaker molecular attraction will freeze at a higher/lower temperature because it requires more/less energy to be TAKEN OUT before the attraction pulls the molecules together.
Select the correct words in each sentence. :)
A substance with stronger molecular attraction will evaporate at a higher temperature because it requires more energy to be ADDED to overcome attraction between the molecules.
What is phase change?A phase change is when matter shifts from one state (solid, liquid, gas, or plasma) to another. These transitions take place when the system receives enough energy or loses enough energy, as well as when the pressure on the system is altered.
A phase change occurs when the kinetic energy decreases enough so that the attraction between molecules pulls them together.
A substance with weaker molecular attraction will freeze at a higher temperature because it requires more energy to be TAKEN OUT before the attraction pulls the molecules together.
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Assuming all of the resistors have the same resistance, which of the following correctly ranks the equivalent resistance of the circuits shown?
A. b < d < c < a
B. d < b < a < c
C. a < c < d < b
D. c > a > d > b
E. a = b = c = d
The correct answer is (A) b < d < c < a.
How to determine the equivalent resistance of the circuit?we need to consider the placement of the resistors.
In circuits a, b and c, resistors are connected in series. The corresponding resistance of resistors combined in series is the sum of the particular resistances. So the equivalent resistance for these circuits is:
a) 3R + R + 3R = 7R
b) R + R + 3R + 3R = 8R
c) 3R + R + R + 3R = 8R
In circuit d, resistors are connected in parallel. The equivalent resistance of resistors connected in parallel is given by the formula
1/request = 1/R + 1/R + 1/R = 3/R
Therefore Req = R/3. Comparing the values of the equivalent resistors reveals the following:
b < d < c < a
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I know the answer but can someone please, please explain?
Two blocks are on a frictionless surface and have the same mass m. Block 2 is initially
at rest. Block 1 moves to the left with speed 4v. Block 1 collides elastically with block 2.
What is the final speed of block 1?
The answer is 0 and I cannot for the life of me figure out why.
Answer:
Explanation:
The only explanation I can think of is this:
Block 1 is moving to the left and strikes Block 2, which is at rest. 100% of the momentum of Block 1 transfers to Block 2. So Block 2 now moves to the left at 4 m/s (you didn't specify a unit) and Block 1 comes to a complete stop and is now at rest.