Create a simple program that calls a function call gradeCalculated, in the main area the user is asked to enter their grade from 0-100. (Python)

Answer:

Print Area

Explanation:

First, I'll assume Donte is making use of a spreadsheet application (Microsoft Office Excel, to be precise).

From the given options, only "Print Area" fits the given description in the question.

The print area feature of the Excel software allows users to print all or selected workbook.

To print a selection section, Donte needs to follow the steps below.

Go to File -> Print.

At this stage, Donte will have the option to set the print features he needs.

Under settings, he needs to select "Print Selection"; this will enable him Print sections of the entire workbook.

Refer to attachment for further explanation

Answer:

C. print area

Explanation:

Answer:

The body of water that is most likely to be a marine ecosystem would be an estuary.

Explanation:

An estuary is a widened, often funnel-shaped mouth of a river, where fresh river water and salt sea water are mixed and thus brackish water is created, and where tidal differences can be observed. When a river flows as a system of branches, it is called a delta.

Estuaries often have a great natural value. They typically consist of swallows and salt marshes that are very rich in invertebrates and thus have a great attraction for birds, among other things.

Answer:

Explanation:

public class ItemToPurchase {

private String itemName ;

private int itemPrice;

private int itemQuantity;

public ItemToPurchase(){

itemName = "none";

itemPrice = 0;

itemQuantity = 0;

}

public String getName() {

return itemName;

}

public void setName(String itemName) {

this.itemName = itemName;

}

public int getPrice() {

return itemPrice;

}

public void setPrice(int itemPrice) {

this.itemPrice = itemPrice;

}

public int getQuantity() {

return itemQuantity;

}

public void setQuantity(int itemQuantity) {

this.itemQuantity = itemQuantity;

}

}

ShoppingCartPrinter.java

import java.util.Scanner;

public class ShoppingCartPrinter {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

ItemToPurchase item1 = new ItemToPurchase();

ItemToPurchase item2 = new ItemToPurchase();

System.out.println("Item 1");

System.out.print("Enter the item name: ");

String name1 = scan.nextLine();

System.out.print("Enter the item price: ");

int price1 = scan.nextInt();

System.out.print("Enter the item quantity: ");

int quantity1 = scan.nextInt();

item1.setName(name1);

item1.setPrice(price1);

item1.setQuantity(quantity1);

scan.nextLine();

System.out.println("Item 2");

System.out.print("Enter the item name: ");

String name2 = scan.nextLine();

System.out.print("Enter the item price: ");

int price2 = scan.nextInt();

System.out.print("Enter the item quantity: ");

int quantity2 = scan.nextInt();

item2.setName(name2);

item2.setPrice(price2);

item2.setQuantity(quantity2);

System.out.println("TOTAL COST");

int item1Total = item1.getPrice() * item1.getQuantity();

int item2Total = item2.getPrice() * item2.getQuantity();

System.out.println(item1.getName()+" "+item1.getQuantity()+" for $"+item1.getPrice()+" = $"+item1Total);

System.out.println(item2.getName()+" "+item2.getQuantity()+" for $"+item2.getPrice()+" = $"+item2Total);

System.out.println();

System.out.println("Total: $"+(item1Total + item2Total));

ItemToPurchase.java

======================================================

package brainly;

//Class header definition for class ItemToPurchase

public class ItemToPurchase {

   //Write the private fields

   private String itemName;

   private int itemPrice;

   private int itemQuantity;

   //Create the default constructor

   //And initialize all the fields to their respective initial values

   public ItemToPurchase(){

       this.itemName = "none";

       this.itemPrice = 0;

       this.itemQuantity = 0;

   }

   //Create the accessor methods as follows:

   public String getItemName() {

       return itemName;

   }

   public void setItemName(String itemName) {

       this.itemName = itemName;

   }

   public int getItemPrice() {

       return itemPrice;

   }

   public void setItemPrice(int itemPrice) {

       this.itemPrice = itemPrice;

   }

   public int getItemQuantity() {

       return itemQuantity;

   }

   public void setItemQuantity(int itemQuantity) {

       this.itemQuantity = itemQuantity;

   }

}     // End of class definition

=======================================================

ShoppingCartPrinter.java

=======================================================

package brainly;

//import the Scanner class

import java.util.Scanner;

//Class header definition for class ShoppingCartPrinter

public class ShoppingCartPrinter {

   public static void main(String[] args) {

       //Create an object of the Scanner class

       Scanner scnr = new Scanner(System.in);

       //prompt the user to enter the name of first item

       System.out.println("Item 1: Enter the item name");

       //Store the input in a String variable

       String firstItemName = scnr.nextLine();

       //Prompt the user to enter the price of the first item

       System.out.println("Enter the item price");

       //Store the input in an int variable

       int firstItemPrice = scnr.nextInt();

       //Prompt the user to enter the quantity of the first item

       System.out.println("Enter the item quantity");

       //Store the input in an int variable

       int firstItemQuantity = scnr.nextInt();

       //Call the scnr.nextLine() method to allow user enter the

       // second item

       scnr.nextLine();

       //Prompt the user to enter the name of the second item

       System.out.println("Item 2: Enter the item name");

       //Store the input in a String variable

       String secondItemName = scnr.nextLine();

       //Prompt the user to enter the price of the second item

       System.out.println("Enter the item price");

       //Store the input in an int variable

       int secondItemPrice = scnr.nextInt();

       //Prompt the user to enter the quantity of the second item

       System.out.println("Enter the item quantity");

       //Store the input in an int variable

       int secondItemQuantity = scnr.nextInt();

       //Create the first object using the first item

       ItemToPurchase item1 = new ItemToPurchase();

       //Create the second object using the second item

       ItemToPurchase item2 = new ItemToPurchase();

       //Get the total cost of the first item

       int totalcostofitem1 = firstItemPrice * firstItemQuantity;

       //Get the total cost of the second item

       int totalcostofitem2 = secondItemPrice * secondItemQuantity;

       //Calculate total cost of the two items

       int total = totalcostofitem1 + totalcostofitem2;        

       //Print out the result.

       System.out.println("Total: $" + total);

   }

}

=======================================================

=======================================================

>> Item 1: Enter the item name

Chocolate Chips

>> Enter the item price

3

>> Enter the item quantity

1

>> Item 2: Enter the item name

Bottled Water

>> Enter the item price

1

>>Enter the item quantity

10

>>Total: $13

======================================================

The above code has been written in Java and it contains comments explaining every line of the code. Please go through the comments carefully.

The actual lines of code are written in bold face to distinguish them from comments.

Also, in the sample output, the user inputs are written in bold face.

Answer:

A program in C++ was written to prompts the user to enter the area of the flat cardboard.

Explanation:

Solution:

The C++ code:

#include <iostream>

#include <iomanip>

#include <cmath>

using namespace std;

double min(double,double);

void max(double,double,double&,double&);

int main()

{double area,length,width=.001,vol,height,maxLen,mWidth,maxHeight,maxVolume=-1;

cout<<setprecision(3)<<fixed<<showpoint;

cout<<"Enter the area of the flat cardboard: ";

cin>>area;

while(width<=area)

{length=area/width;

max(length,width,vol,height);

if(vol>maxVolume)

{maxLen=length;

mWidth=width;

maxHeight=height;

maxVolume=vol;

}

width+=.001;

}

cout<<"dimensions of card to maximize the cardboard box which has a volume "

<<maxVolume<<endl;

cout<<"Length: "<<maxLen<<"\nWidth: "<<maxLen<<endl;

cout<<"dimensions of the cardboard box\n";

cout<<"Length: "<<maxLen-2*maxHeight<<"\nWidth: "

<<mWidth-2*maxHeight<<"\nHeight: "<<maxHeight<<endl;

return 0;

}

void max(double l,double w,double& max, double& maxside)

{double vol,ht;

maxside=min(l,w);

ht=.001;

max=-1;

while(maxside>ht*2)

{vol=(l-ht*2)*(w-ht*2)*ht;

if(vol>max)

{max=vol;

maxside=ht;

}

ht+=.001;

}

}

double min(double l,double w)

{if(l<w)

return l;

return w;

}

Note:  Kindly find the output code below

/*

Output for the code:

Enter the area of the flat cardboard: 23

dimensions of card to maximize the cardboard box which has a volume 0.023

Length: 4.796

Width: 4.796

dimensions of the cardboard box

Length: 4.794

Width: 4.794

Height: 0.001

*/

Answer:

well, idc

Explanation:

Answer:

Check the explanation

Explanation:

1.

void func(void){

int a,b,c; /*definition 1*/

/////* a,b,c for definition 1 are visible */

//// d, e are not visible

while(...){

int b, c, d; /* definition 2*/

////*

a from definition 1 is visible

b, c, d from definition 2 are visible

*/ ///

while(...){

int c, d, e;/* definition 3*/

////*

a from definition 1 is visible

b from definition 2 is visible

c, d, e from definition 3 are visible

*/ ///

}

////*

a from definition 1 is visible

b, c, d from definition 2 are visible

e not visible

*////

}

/////* a,b,c for definition 1 are visible */

///// d, e are not visible

}

Answer:Backspace

Explanation:

If you want to delete words you use the backspace button.

Answer:

Backspace

Explanation:

Answer:An electronic device for storing and processing data, typically in binary form

Explanation:

Answer:

a.

Explanation:

The option that correctly declares an array is int array.

This is a term that connote a regular system or arrangement. Here,  numbers or letters are said to be arranged in rows and columns.

In computing, An array is a term that describe memory locations box having the same name. All data in an array is said to  be of the same data type.

Learn more about array from

https://brainly.com/question/26104158

Answer:

The TCP socket state will be as 'Closed'.

Explanation:

TCP seems to be a framework that describes how well a web discussion can be established and maintained through which software applications could access information.

The accompanying is the finished status whenever the connection is suspended by TCP:

CLOSE-WAIT:

This means that the end destination had already chosen to take a similar requirement from the 'remote endpoint.'

CLOSING:

This indicates the position for the cancellation of server access verification from either the faraway TCP.

LAS-ACK:

This indicates the view for approval including its extermination previously sent through the cell tower TCP.

TIME-WAIT:

This symbolizes a lengthy delay for all the remote to accept verification of its cancellation request.

CLOSED:

This means that there is no link region or anything like that.

Answer:

The code implements a recursive function by decrementing number  by 1 from 10 to 4 recursively from the stack and add an extra space 2 using  the macro function

Explanation:

Solution

The  code implements a recursive function by decrementing number  by 1 from 10 to 4 recursively from the stack and add an extra space 2 using  the macro function mwritespace

The first number is printed after the code executes is 9

Code to be used:

Include Irvine32.inc

INCLUDE Macros.inc               ;Include macros for space

.code

main proc

  push 4                   ;Push 4 to the stack

  push 10                   ;Push 10 to the stack

  call rcrsn                   ;call the function  

  exit

  ;invoke ExitProcess,0           ;After return from the function

                      ;call exit function

  main ENDP               ;end the main

  rcrsn PROC               ;define the function

      push ebp               ;push the ebp into stack

      mov ebp,esp           ;set ebp as frame pointer

      mov eax,[ebp + 12]       ;This is for second parameter

      mov ebx,[ebp + 8]       ;This is for first parameter

      cmp eax,ebx           ;compare the registers

      jl recurse           ;jump to another function  

      jmp quit               ;call quit

      recurse:               ;Implement another function  

      inc eax               ;increment count value

      push eax               ;push the eax value into stack

      push ebx               ;push ebx into stack

      call rcrsn           ;call above function

      mov eax,[ebp + 12]       ;This is for second parameter

      call WriteDec           ;write the value on the screen

      mWritespace 2           ;Space macro print 2 spaces

                      ;pause the screen

      quit:               ;Implement quit function

      pop ebp               ;pop the pointer value from the stack

      ret 8               ;clean up the stack  

 rcrsn ENDP          

end main

#!/bin/bash

usage() {

       echo "Usage: $0 [ -f outfile ] name password" 1>&2

       exit 1

}

while getopts "f:" o; do

       case "${o}" in

       f)

               filename=${OPTARG}

           ;;

       *)

               usage

           ;;

   esac

done

shift $((OPTIND-1))

name=$1

password=$2

if [ -z "$password" ] ; then

       usage

fi

set -x

if [ -z "$filename" ] ; then

       useradd -p `crypt $password` $name

else

       useradd -p `crypt $password` $name > $filename

fi

Answer:

honestly i dont know but I used to have computer programming classes on java and I'd get all my answers from repl.it forums. Wist you best of luck!!

Answer:

it is two by five credit limit

Answer:

Your answer is A Tamera’s credit limit is most likely higher than Rupert’s, and her interest rate is most likely lower.

Explanation:

I got it right on the test and I hope this answer helps

Answer:

Following are the code to this question:

import java.util.*; //import package for user input

public class Main //defining main class

{

public static double sumMajorDiagonal(double [][] m) //defining method sumMajorDiagonal

{

double sum = 0; //defining double variable sum

int i, j; //defining integer variable  

for(i = 0; i <m.length; i++) //defining loop to count row

{

for(j = 0; j < m.length; j++) //defining loop to count column  

{

if(i == j) //defining condition to value of i is equal to j

{

sum=sum+ m[i][j]; //add diagonal value in sum variable

}

}

}

return sum; //return sum

}

public static void main(String args[]) //defining main method

{

int n,i,j; //defining integer variable    

System.out.print("Enter the dimension value: "); //print message

Scanner ox = new Scanner(System.in); //creating Scanner class object for user input

n = Integer.parseInt(ox.nextLine()); //input value and convert value into integer

double m[][] = new double[n][n]; //defining 2D array

for(i = 0; i < m.length; i++)

{

String t = ox.nextLine(); // providing space value

String a[] = t.split(" "); // split value

for(j = 0; j < a.length; j++) //defining loop to count array value

{

double val = Double.parseDouble(a[j]); //store value in val variable

m[i][j] = val; //assign val in to array

}

}

double d_sum = sumMajorDiagonal(m); //call method store its return value in d_sum variable

System.out.println("diagonal matrix sum: "+ d_sum); //print sum

}

}

output:

Enter the dimension value: 3

1 2 3

1 2 3

1 2 4

diagonal matrix sum: 7.0

Explanation:

Program description:

Answer:

The program goes as follows  

Comments are used to explain difficult lines

#include<iostream>

#include<fstream>

#include<sstream>

#include<string>

using namespace std;

int main()

{

//Declare String to accept file name

string nm;

//Prompt user for file name

cout<<"Enter File Name: ";

getline(cin,nm);

//Create File

ofstream Myfile(nm.c_str());

//Prompt user for 4 names of movies

string movie;

for(int i = 1;i<5;i++)

{

 cout<<"Please enter a movie title #"<<i<<": ";

 cin>>movie;

 //Write to file, the names of each movies

 Myfile<<movie<<endl;

}

Myfile.close(); // Close file

//Create an Array for four elements

string myArr[4];

//Prepare to read from file to array

ifstream file(nm.c_str());

//Open File

if(file.is_open())

{

 for(int i =0;i<4;i++)

 {

  //Read each line of the file to array (line by line)

  file>>myArr[i];

 }

}

file.close(); // Close file

//Create a reverseOrder.txt file

nm = "reverseOrder.txt";

//Prepare to read into file

ofstream Myfile2(nm.c_str());

for(int j = 3;j>=0;j--)

{

 //Read each line of the file to reverseOrder.txt (line by line)

 Myfile2<<myArr[j]<<endl;

}

Myfile2.close(); //Close File

return 0;

}

See attached for .cpp program file

Answer:

Quick sort and Merge sort supports parallelism

Explanation:

When we talk about parallelism, we are referring to the idea of breaking down a problem into a number of many subproblems after which we combine the solutions of these subproblems into a single solution. Here we allocate these subtasks to the multicore processors where each core gets assigned each of the subtasks are assigned to a core according to its ability or functionality. After each of the core are through with its evaluation, all their results are collated and combined to come up with a full rounded and complete solution to the given problem.

If we take a look at sorting algorithms such as selection sort, bubble sort and insertion sort, we will find out that these algorithms cant be simulated on a multicore processor efficiently because they are sequential algorithms.

On the other hand, we have sorting algorithms that can easily be simulated in a multicore processor since they can divide the given problem into subproblems to solve after which the solutions can be combined together to arrive at or come up with a complete solution to the problem. This algorithms includes Quick sort and Merge sort, they make use of Divide and Conquer paradigm.

Answer:

The third point i.e " Use an alternating least squares (ALS) algorithm to create a collaborative filtering solution" is the correct answer .

Explanation:

The Alternating Less Squares  is the different approach that main objective to enhancing the loss function.The Alternating Less Squares process divided the matrix into the two factors for optimizing the loss .The divided of two factor matrix is known as item matrix or the user matrix.

Answer:

The final tables in 3NF are as follows.

Project( ProjectNbr, ProjectName)

Employee( EmployeeNbr, EmployeeName, JobClass)

Job( JobClass, HourlyRate)

ProjectBilling( ProjectNbr, EmployeeNbr, HoursBilled)

Explanation:

The given table is given below.

ProjectBilling( ProjectNbr, ProjectName, EmployeeNbr, EmployeeName, JobClass, HourlyRate, HoursBilled)  

ProjectNbr -> ProjectName

EmployeeNbr -> EmployeeName  

JobClass -> HourlyRate

ProjectNbr, EmployeeNbr -> HoursBilled

1NF

1. All the fields in the given table contain only a single value. The table is in 1NF.

2NF

2. New tables are formed based on the given functional dependencies.

Project( ProjectNbr, ProjectName)

Employee( EmployeeNbr, EmployeeName)

Job( JobClass, HourlyRate)

ProjectBilling( ProjectNbr, EmployeeNbr, HoursBilled)

3. Every table is assigned a primary key which are as follows.

ProjectNbr is the primary key for Project table.

EmployeeNbr is the primary key for Project table.

JobClass is the primary key for Project table.

(ProjectNbr, EmployeeNbr) is the composite primary key for the ProjectBilling table.

4. The tables which are related to each other are linked via primary key and foreign key.

5. In the ProjectBilling table, the composite primary key, ProjectNbr, EmployeeNbr is composed of the primary keys of the Project and Employee tables, i.e., ProjectNbr and EmployeeNbr respectively.

6. Job table is related to Employee table. Hence, primary key of Job table, JobClass, is introduced as foreign key in Employee table.

Employee( EmployeeNbr, EmployeeName, JobClass)

7. Partial dependency arises when composite primary key exists and non-prime attributes (columns other than the primary key) depend on a part of the primary key, i.e., partial primary key.

In the ProjectBilling table, no partial dependency exists.

8. All the tables are in 2NF as given below.

Project( ProjectNbr, ProjectName)

Employee( EmployeeNbr, EmployeeName, JobClass)

Job( JobClass, HourlyRate)

ProjectBilling( ProjectNbr, EmployeeNbr, HoursBilled)

3NF

9. All the tables are in 2NF.

10. In every table, all non-prime attribute depend only on the primary key.

11. No transitive dependency exists, i.e., all non-prime attributes do not depend on other non-prime attributes.

12. Hence, all the conditions are satisfied and the tables are in 3NF.

Answer:

False.

Explanation:

The correct option is false that is to say the arrangement is not true. So, let us check one or two things about the RSA System.

The RSA system simply refer to as a cryptosystem that was first established in the year 1973 but was later developed in the year 1977 by Ron Rivest, Adi Shamir and Leonard Adleman.

The main use of the RSA system is for encryption of messages. It is known as a public key cryptography algorithm.

The way the algorithm should have been arranged is;

(1). Randomly select two large prime numbers p and q, which always must bekept secret.

(2). Determine the product n = pq, known as public modulus.

(3). Select an integer number E, known as the public exponent, such that (p 1)and E have no common divisors, and (q 1) and E have no commondivisors.

(4). Determine the private exponent, D, such that (ED 1) is exactly divisible by both (p 1) and (q 1). In other words, given E, we choose D such that the integer remainder when ED is divided by (p1)(q 1) is 1.

(5). Release publicly the public key, which is the pair of numbers n and E, K =(n, E). Keep secret the private key, K = (n, D).

Therefore, The way it should have been arranged in the question should have been;

(1) , (4), (2), (3 ) and ( 5).

Answer:

We made use of the dynamic programming method to solve a linear-time algorithm which is given below in the explanation section.

Explanation:

Solution

(1) By making use of the  dynamic programming, we can solve the problem in linear time.

Now,

We consider a linear number of sub-problems, each of which can be solved using previously solved sub-problems in constant time, this giving a running time of O(n)

Let G[t] represent the sum of a maximum sum contiguous sub-sequence ending exactly at index t

Thus, given that:

G[t+1] = max{G[t] + A[t+1] ,A[t+1] } (for all   1<=t<= n-1)

Then,

G[0] = A[0].

Using the above recurrence relation, we can compute the sum of the optimal sub sequence for array A, which would just be the maximum over G[i] for 0 <= i<= n-1.

However, we are required to output the starting and ending indices of an optimal sub-sequence, we would use another array V where V[i] would store the starting index for a maximum sum contiguous sub sequence ending at index i.

Now the algorithm would be:

Create arrays G and V each of size n.

G[0] = A[0];

V[0] = 0;

max = G[0];

max_start = 0, max_end = 0;

For i going from 1 to n-1:

// We know that G[i] = max { G[i-1] + A[i], A[i] .

If ( G[i-1] > 0)

G[i] = G[i-1] + A[i];

V[i] = V[i-1];

Else

G[i] = A[i];

V[i] = i;

If ( G[i] > max)

max_start = V[i];

max_end = i;

max = G[i];

EndFor.

Output max_start and max_end.

The above algorithm takes O(n) time .

Answer:

C. Maximal Flow Method

Explanation:

When it comes to optimization theory, Maximal Flow Method or problems have to do with finding a possible or viable flow through a flow network that obtains the maximum potential flow rate. The maximum flow problem can be viewed as an exceptional case of more complex and complicated network flow problems, such as that of the circulation problem.

Answer:

?

Explanation:

?

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

Answer:

see explaination

Explanation:

If I am to select I will select the strategy Impute the missing values . Because rather than deleting and all the other strategies. This is the best option because, this is an optional field as described there is no need for such accurate information about salary.

If we want to maintain this field we can just fill the value by identifying the similar records which is the other customers who is visiting the same no of times and fill that.

Answer:

dude what r u doin

Explanation:

Answer:

Explanation:

.Car can Travel a m miles tank on a gas

2.For N distance there are n+1 adjacent gas stations.

Output Conditions:

Tacoma will fill the gas station while going.

Tijuana will fill up gas for the return trip

3.Dynamic self Reduction Algorithm

Start

if(n==0)

Tacoma is a gas station number 0;

else

Tijuana is a gas station n+1;

stop

Answer:

The reason is due to proprietary design of the Operating System (OS) which require a virtualization software to blanket or "disguise" the hardware (processor) borderlines of the computer onto which it is to be installed.

Explanation:

An Apple system that has the RISC processor and system architecture which has an operating system made entirely for the Apple system architecture

If the above Apple OS is to be installed on a windows computer, then the procedure to setup up the OS has to be the same as that used when on an Apple system, hence, due to the different processors and components of both systems, a virtualization will be be needed to be provided by a Virtual box, Parallels desktop or other virtualization software.

Answer:

A  C++ program was used in writing a function in merging ( vector a, vector b)   or that will merge the two vectors into one new one and return the merged vector.

Explanation:

Solution

THE CODE:

#include <iostream>

#include <vector>

using namespace std;

vector<int> merge(vector<int> a, vector<int> b) {

   vector<int> vec;

   int i = 0, j = 0;

   while(i < a.size() || j < b.size()) {

       if(i >= a.size() || (j < b.size() && b[j] < a[i])) {

           if(vec.empty() || vec[vec.size()-1] != b[j])

               vec.push_back(b[j]);

           j++;

       } else {

           if(vec.empty() || vec[vec.size()-1] != a[i])

               vec.push_back(a[i]);

           i++;

       }

   }

   return vec;

}

int main() {

   vector<int> v1 = {2, 4, 6, 8};

   vector<int> v2 = {1, 3, 7, 10, 13};

   vector<int> vec = merge(v1, v2);

   for(int i = 0; i < vec.size(); ++i) {

       cout << vec[i] << " ";

   }

   cout << endl;

   return 0;

}