Convert:
1) 2kg into gram
2) 5200m into km
3) 20cm into m

Complete Question:

The Statue of Liberty is made of copper that has turned green because it has undergone a change. What can be said about this change?

Group of answer choices.

A. The change is a physical change because the copper in the statue is still there.

B. The change is a physical change because a new chemical is formed on the outside of the statue.

C. The change is not a physical change because the color of the statue has changed.

D. The change is not a physical change because a new chemical is formed on the outside of the statue.

Answer:

D. The change is not a physical change because a new chemical is formed on the outside of the statue.

Explanation:

A physical change can be defined as a type of change that only affects the physical form of a chemical substance (matter) without having any effect on its chemical properties. Thus, a physical change would only affect the physical appearance and properties of a chemical substance (matter) but not its chemical properties.

This ultimately implies that, a physical change result in a change of matter from one form or phase (liquid, solid or gas) to another without a corresponding change in chemical composition.

Additionally, a physical change is a type of change that involves an increase or decrease in the volume of a physical object (object). Also, this change can be reversed to the original state under certain conditions.

Since the Statue of Liberty which is made of copper turned green, the change is not a physical change because a new chemical is formed on the outside of the statue.

Answer: Quarks

Explanation:

Quarks are the elementary particles that make up protons and neutrons. If you want to be more specific, there's six types, but overall, it's just quarks.

[tex]c_{water} = 2.25\times 10^{8}m/s[/tex]

Explanation:

The speed of light in any medium is given by

[tex]c = \lambda \nu[/tex]

where [tex]\lambda[/tex] is the wavelength and [tex]\nu[/tex] is the frequency. In water,

[tex]c_{water} = \lambda_{water} \nu[/tex]

[tex]\:\:\:\:\:\:\:\:= (3.75\times 10^{-7}\:m)(6\times 10^{14})\:Hz[/tex]

[tex]\:\:\:\:\:\:\:\:= 2.25\times 10^{8}\:m/s[/tex]

Answer:

we neglect the time data

Answer:

what I think in my opinion is B

Answer:

If the resistors are in parallel they must all experience the same voltage drop.

R * I = V

8 * 3 = 24 V    (if i is 3 amps)

24V / 4 ohm = 6 amps

24V / 16 ohm = 1.5 amps

Answer: reciever is going to be going the momentum which is 90 times 6.7, so defensive back who is 103 KG and standing still therefore has no momentum, so the collision is 6.7 m/s against the defense

Explanation:

zero momentum

newton's 1st law of motion, when something is acted upon by an unbalanced force.

Question: A ship anchored at sea is rocked by waves that have crests 100 m apart the waves travel at 70m/S, at what frequency do the waves reach the ship?

Answer:

0.7 Hz

Explanation:

Applying,

v = λf............... Equation 1

Where v = velocity of the wave, f = frequency fo the wave, λ = wavelength of the wave

make f the subject of the equation

f = v/λ................. Equation 2

From the question,

Given: v = 70 m/s, λ = 100 m ( distance between successive crest)

Substitute these values into equation 2

f = 70/100

f = 0.7 Hz

Hence the frequency at which the wave reach the ship is 0.7 Hz

Answer:

yes

Explanation:

The gases and dust particles thrown into the atmosphere during volcanic eruptions have influences on climate. ... Volcanoes have also caused global warming over millions of years during times in Earth's history when extreme amounts of volcanism occurred, releasing greenhouse gases into the atmosphere.

Answer:

Water

Explanation:

Given the specific heat of oxygen is 918J/kg °C and the specific heat of water is 4181 J/kg °C.

Consider 1Kg mass of each substance.

Now 1 Kg of oxygen needs 918 J of energy to raise its temperature by 1 °C

Also, 1 Kg of water needs 4181 J of energy to raise its temperature by 1 °C.

Clearly water requires more energy when compared to oxygen.

Basically, specific heat capacity is the amount of energy required to raise the temperature of a 1 kg body by 1 °C.

Answer:

The beta decay takes place.

Explanation:

The reaction of radioactivity of carbon 14 to nitrogen 14 is

There is a beta decay.  

The reaction is

[tex]C_{6}^{14}\rightarrow N_{7}^{14}+\beta _{-1}^{0}+ energy[/tex]

Here some energy is released in form of neutrino.

Answer:

Explanation:

Although there is absolutely NO regard for significant digits, I can help you with this, nonetheless.

The equation for Potential Energy is PE = mgh. We have everything but the height of the ball. We have to solve for that using a one-dimensional motion equation:

v² = v₀² + 2aΔx, where Δx is our displacement (the height we need for PE). Filling in and keeping in mind that at the max height of parabolic travel, the final velocity of the object is 0:

0 = (21.5)² + 2(-9.8)Δx and

0 = 462.25 - 19.6Δx and

-462.25 = -19.6Δx so

Δx = 23.58 m. Using this as the h in our PE equation:

PE = .19(9.8)(23.58) so

PE = 43.9 J, choice C.

Answer:

ssooeorkgogogoogkrorooror

Explanation:

Answer:Magnesium and OXYGENNNN

Explanation:

Magnesium Oxide is still technically Magnesium

Answer:

The answer is below

Explanation:

i) Since the length of the second clock (radius) is 14 cm = 0.14 m, the distance covered by the second hand in one revelution is:

Distance covered = 2πr = 2π(0.14) = 0.88 m

The time taking to complete one revolution = 60 seconds, hence;

Speed = distance covered in one revolution / time take o complete a revolution

Speed = 0.88 m / 60 s = 0.0147 m/s

ii) Distance covered in 150 s = speed * 150 s = 0.0147 * 150 = 2.2 m

iii) Displacement in 150 seconds = distance from initial position to final position

At 150 s, the hand has covered 2 revolutions and moved 30 s. Hence:

Displacement in 150 seconds = speed * 30 s = 0.0147 * 30 = 0.44 m

Answer:

200kg is the answer to the question

Answer:

[tex]I=1.9A[/tex]

Explanation:

From the question we are told that:

Meter distance [tex]d=0.0525[/tex]

Magnetic field [tex]B=7.14*19^{-6}T[/tex]

Generally the equation for Magnetic field B is mathematically given by

 [tex]B =\frac{\mu *I }{2* \pi r}[/tex]

 [tex]7.14*19^{-6}T =\frac{ 1.26 *10^{-6} *I }{2* 3.142*0.0525}[/tex]

Where

Constant[tex]\mu=1.26 *10^{-6}[/tex]

 [tex]I=1.9A[/tex]

Therefore

The Current through the wire is

 [tex]I=1.9A[/tex]

Answer: 1.87

Explanation:

acellus

Answer:

Explanation:

We don't need the mass of the car in the equation to solve for final velocity, since the values given for the acceleration and the time it took to accelerate to that velocity are given. The equation we need is the one for acceleration, which is

[tex]a=\frac{v_f-v_0}{t}[/tex] We are solving for final velocity, we know the initial velocity is 0 (starting from rest), and the time to complete this acceleration (10 m/s/s) is 3 seconds:

[tex]10=\frac{v_f-0}{3}[/tex] which is the same thing as saying

[tex]10=\frac{v}{3}[/tex] so

v = 30 m/s

Answer:

The correct option is (b).

Explanation:

Given that,

The height of the object, h = 15 cm

Object distance, u = -44 cm

Image distance, v = -14 cm

We need to find the focal length of the lens. Using the lens formula.

[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{f}=\dfrac{1}{(-14)}-\dfrac{1}{(-44)}\\\\f=-20.53\ cm[/tex]

So, the focal length of the lens (-20.53 cm).

Answer:

The mass of air in the box is 0.78 grams.

Explanation:

A litre equals a cubic decimetre. By definition of density ([tex]\rho[/tex]), in grams per litre, we calculate the mass of air inside the cube ([tex]m[/tex]), in grams:

[tex]m = \rho \cdot V[/tex] (1)

Where [tex]V[/tex] is the volume occupied by air within the cube, in litres.

If we know that [tex]V = 0.6\,L[/tex] and [tex]\rho = 1.3\,\frac{g}{L}[/tex], then the mass of air is:

[tex]m = \left(1.3\,\frac{g}{L} \right)\cdot (0.6\,L)[/tex]

[tex]m = 0.78\,g[/tex]

The mass of air in the box is 0.78 grams.

Answer:

ANO BA TO?(;-;)

Explanation:

miss the rage??

Answer:

Dynamo

Explanation:

Dynamo started to rotate which is known as kinetic energy.When dynamo is in running it produces electricity.dynamo specially used for generating electricity.

Answer: Load carrying heavy vehicles have large number of wheels in order to reduce pressure on the contact patch on road. With large number of wheels, it becomes easy to distribute the entire pressure of loads in an even manner.

Explanation:

Answer:

Q=21600C

Explanation:

Q=It.

Data

I=12A

t=30min

convert time from minutes to second

t=60*30

=1800s

Q=?

Q=It

=(12A)*(1800s)

Q=21600C

Answer:

there it is fella u were right with ur answer

Solution :

The angular acceleration, [tex]$\alpha$[/tex] is obtained from the equation of the [tex]$\text{Newton's second law}$[/tex] of rotational motion,

Thus,

[tex]$\tau = F \times d$[/tex]

or [tex]$\tau = I \times \alpha$[/tex]

where [tex]$\tau$[/tex] is torque, F is force, d is moment arm distance, I is the moment of inertia

Thus, [tex]$\alpha=\frac{(F\times d)}{I}$[/tex]

Now if the force and the moment arm distance are constant, then the [tex]\text{angular acceleration is inversely proportional to the moment of inertia.}[/tex]

That is when, F = d = constant, then  [tex]$\alpha \propto \frac{1}{I}$[/tex] .

Thus, moment of inertia, I is proportional to mass of the bar.

The mass is less for the bar in case (1) in comparison with that with the bar in case (2) due to the holes that is made in the bar.

Therefore, the bar in case (1), has less moment of inertia and a greater angular acceleration.

Answer:

The magnitude of the emf induced in the loop is 2.4 × 10⁻⁵ V

Explanation:

The magnitude of the induced emf of a loop moving relative to a wire is given as follows;

The given parameters are;

I = 50 A, a = 50 cm, and b = 6.0 cm

The constant rate of change of x, v = 20 cm/s

Motional emf formula

The magnetic field due to the straight wire, B = μ₀·i/(2·π·x)

The flux given by the rectangular loop, Ф = BA =  μ₀·i/(2·π·x) × a × b

Therefore, we get;

[tex]e = \dfrac{-d\phi}{dt} = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \dfrac{d}{dt} \left (\dfrac{1}{x} \right ) = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \left (\dfrac{1}{x^2} \right ) \dfrac{dx}{dt}[/tex]

[tex]\because \dfrac{dx}{dt} = v[/tex]

Therefore;

[tex]e = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \left (\dfrac{1}{x^2} \right ) \dfrac{dx}{dt} = \dfrac{-\mu_0 \cdot i \cdot a\cdot b}{2 \cdot \pi} \times \left (\dfrac{1}{x^2} \right ) \times v \left(\because \dfrac{dx}{dt} = v \right)[/tex]

μ₀ = 4·π × 10⁻⁷ H/m

We get;

[tex]e = \dfrac{4\cdot \pi \times 10^{-7} \, H/m\times50 \, A \times 0.5 \, m\times 0.06 \, m}{2 \cdot \pi} \times \left (\dfrac{1}{(0.05 \, m)^2} \right ) \times 0.2 \ m/s = 2.4 \times 10^{-5} \, V[/tex]

The induced emf, e = 2.4 × 10⁻⁵ V

Explanation:

answer is in the picture above