Consider two circular swimming pools. Pool A has a radius of 44 feet, and Pool B has a diameter of 27. 02 meters. Complete the description for which pool has a greater circumference. Round to the nearest hundredth for each circumference.
1 foot = 0. 305 meters.
,question,
The diameter of Pool A is what meters. The diameter of Pool B v is greater, and the meters. Circumference is what by what meters​

Answers

Answer 1

Pool A has a diameter of approximately 88 feet, and Pool B has a diameter of approximately 27.02 meters. The circumference of Pool A is greater than the circumference of Pool B by approximately 77.22 meters.

In summary, Pool A has a diameter of approximately 88 feet, while Pool B has a diameter of approximately 27.02 meters. The circumference of Pool A is greater than the circumference of Pool B by approximately 77.22 meters.
The diameter of a circle is twice the radius. Since the radius of Pool A is given as 44 feet, the diameter of Pool A would be (2 * 44) = 88 feet.
To compare Pool A and Pool B in the same unit, we need to convert the diameter of Pool B from meters to feet. Given that 1 meter is equal to 3.281 feet, the diameter of Pool B in feet would be (27.02 * 3.281) = 88.63 feet (rounded to the nearest hundredth).
The circumference of a circle can be calculated using the formula C = 2πr, where r is the radius. For Pool A, the circumference would be (2 * 3.14159 * 44) = 276.46 feet (rounded to the nearest hundredth).
For Pool B, the circumference would be (2 * 3.14159 * 88.63) = 556.80 feet (rounded to the nearest hundredth).
Comparing the circumferences, we find that the circumference of Pool A is greater than the circumference of Pool B by approximately (556.80 - 276.46) = 280.34 feet (rounded to the nearest hundredth), which is equivalent to approximately 85.34 meters.
Therefore, the circumference of Pool A is greater than the circumference of Pool B by approximately 77.22 meters.

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9514 1404 393

Answer:

  y = 2x +5

Step-by-step explanation:

We can use the slope formula to find the slope of AB, which is the same as the slope of the parallel line. Then, we can use the point-slope equation for a line to find the desired equation.

  m = (y2 -y1)/(x2 -x1)

  m = (-8 -2)/(-1 -4) = -10/-5 = 2

__

  y -y1 = m(x -x1) . .  point-slope form of equation for a line

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Evaluate y + (x2 + y) when x = 0.4, y = 3, z =

Answers

Answer:

6.16 is the answer

Step-by-step explanation:

3 + (.4^2 + 3)

3 + 3.16

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A running race follows a triangular course. The first leg of the race is in a straight line, covering 4.4km. Runners turn an angle of 79 deg for the second leg, and then turn again 77 deg to head back to the start line to finish the race. What is the length of the entire race, to the nearest tenth of a kilometer?

Answers

Answer:

The length of the entire race is 9,5km

Step-by-step explanation:

Required

Determine the length of the race.

To aid my explanation, I have added an attachment which shows the triangular course.

From the attachment, we have:

A as the starting point and the following measurement;

[tex]\angle B = 11^{\circ[/tex]

[tex]\angle C = 13^{\circ} + 79^{\circ} = 92^{\circ[/tex]

[tex]\angle A + \angle B + \angle C = 180^{\circ}[/tex]

[tex]\angle A = 180^{\circ} - (\angle B + \angle C )[/tex]

[tex]\angle A = 180^{\circ} - (11^{\circ}+92^{\circ})[/tex]

[tex]\angle A = 77^{\circ}[/tex]

[tex]\angle B = 11^{\circ[/tex]

[tex]\angle C = 92^{\circ[/tex]

[tex]c = 4.4km[/tex]

Apply sine rule

[tex]\frac{a}{sin\ A} = \frac{b}{sin\ B} = \frac{c}{sin\ C}[/tex]

[tex]\frac{a}{sin\ 77^{\circ}} = \frac{b}{sin\ 11^{\circ}} = \frac{4.4}{sin\ 92^{\circ}}[/tex]

[tex]\frac{a}{sin\ 77^{\circ}} = \frac{b}{sin\ 11^{\circ}} = \frac{4.4}{0.9994}[/tex]

[tex]\frac{a}{sin\ 77^{\circ}} = \frac{b}{sin\ 11^{\circ}} = 4.403[/tex]

Split to solve for a and b

[tex]\frac{a}{sin\ 77^{\circ}} =4.403[/tex]

[tex]\frac{b}{sin\ 11^{\circ}} = 4.403[/tex]

Make a the subject

[tex]\frac{a}{sin\ 77^{\circ}} =4.403[/tex]

[tex]a = 4.403 * sin(77^{\circ})[/tex]

[tex]a = 4.403 * 0.9744[/tex]

[tex]a = 4.3km[/tex]

Make b the subject

[tex]\frac{b}{sin\ 11^{\circ}} = 4.403[/tex]

[tex]b = 4.403 * sin(11^{\circ})[/tex]

[tex]b = 4.403 * 0.1908[/tex]

[tex]b = 0.8km[/tex]

The length of the race is:

[tex]Length = a + b + c[/tex]

[tex]Length = 4.3km + 0.8km + 4.4km[/tex]

[tex]Length = 9.5km[/tex]

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

sin(45°)=height/30

height=30sin(45°)

h=30×√2/2=15√2≈21.213(21ft to the nearest whole)

The height should be 21 ft.

Given that,

A 30 ft water slide forms a 45 degree angle with their surface of the water.

Based on the above information, the calculation is as follows:

[tex]sin(45^{\circ})=height\div 30\\\\height =30sin(45^{\circ})\\=30\times \sqrt 2\div 2\\\\=15\sqrt 2[/tex]

≈21.213

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Step-by-step explanation:

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Step-by-step explanation:


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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Answers

B
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Answer:

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Step-by-step explanation:

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Answers

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(-1,1)

Step-by-step explanation:

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Answers

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Inductive

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Step-by-step explanation:

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