Consider three widely separated galaxies in an expanding universe. Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?

Answer:

The speed of the ball when it hits the ground is 102.1 m/s

Explanation:

Given;

initial velocity of ball, u = 25 m/s

distance traveled by the ball = height of the building = h = 500 m

when the ball hits the ground, the final velocity, v = ?

The final velocity of the ball is given by;

v² = u² + 2gh

where;

g is acceleration due to gravity = 9.8 m/s²

v² = (25)² + 2(9.8)(500)

v² = 10425

v = √10425

v = 102.1 m/s

Therefore, the speed of the ball when it hits the ground is 102.1 m/s

Answer:

Albert Einstein was from Germany he was born theoritical physicist, from childhood only he loved mechanical toys, he was highly gifted in Mathematics, He was a world citizen and a scientific genius too. His contribution were:

1) he developed the theory of relativity

2) he also discovered the process of nuclear fission

3)he developed the quantum theory of specific heat

4)theory of stimulated emission, on which laser device technology is based

5) law of photoelectric effect

hope it helped you :)

hi olivia hope this helps you

Answer:

Explanation:

λ = hc/¢

Where

h = the Plank constant 6.63 x 10-34 Is

C = 3.0×10^8

¢= 1.96eV

= (6.63×10^-34Js)×(3×10^8)÷( 1.96eV) × 1eV/1.6×10^-19J

= (1.989×10^-25)÷( 1.96eV)×1eV/1.6×10^-19J

= 6.342×10^-7m

B) maximum kinetic energy

= K=hf−ϕ ........1

ϕ = hc

Where

​ h = constant 6.63 x 10^-34Js

ϕ= 1.96eV

Recall

λ =425×10^-9m

f = frequency in Hz

f = c / λ

C = 3.0×10^8

f = 3.0×10^8 / 425×10^-9m

f = 0.000705Hz

From equation 1

K = (6.63 x 10^-34Js×0.000705Hz )- 6.63 x 10^-34Js×3.0×10^8

= 4.68×10^-37 - 1.989×10^-25

= - 1.98×10^-25J

Answer:

4 times that of nitrogen gas, N2.

Explanation:

Let R1 be the rate of diffusion of nitrogen gas, N2.

Let R2 be the rate of diffusion of Hydrogen gas, H2.

Let M1 be the molar mass N2

Let M2 be the molar mass of H2.

Next, we shall determine the molar mass of N2 and H2.

This is illustrated below below:

Molar mass of N2 (M1) = 2 x 14 = 28 g/mol

Molar mass of H2 (M2) = 2 x 1 = 2 g/mol

Finally, we shall determine the rate of diffusion of Hydrogen gas, H2 as follow:

R1/R2 = √(M2/M1)

M1 = 28

M2 = 2

R1/R2 = √(M2/M1)

R1/R2 = √(2/28)

R1/R2 = √(1/14)

R1/R2 = 0.27

Cross multiply

R1 = R2 × 0.27

Divide both side by 0.27

R2 = R1/0.27

R2 = R1 × 1/0.27

R2 = R1 × 4

R2 = 4R1

Therefore, the rate of diffusion of H2 (R2) is 4 times that of N2 (R1)

Explanation:

KE = ½ mv²

KE = ½ (70 kg) (5.0 m/s)²

KE = 875 J

Answer:

t = 10.02 minutes

Explanation:

It is given that,

Speed of bus, v = 216 km/h

Distance to be traveled by the bus, d = 36 km

We need to find the time taken by the bus to cover the distance. Let the time is t.

Speed = distance/time

[tex]t=\dfrac{d}{v}\\\\t=\dfrac{36\ km}{216\ km/h}\\\\t=0.167\ h[/tex]

or

t = 10.02 minutes

So, 10.02 minutes is taken by the bus.

Answer:

The magnitude of the electric field at the center of curvature of the arc is 3.87 N/C

Explanation:

Please see the attachments below

Assuming the cannonball is fired horizontally, its horizontal velocity stays at a constant 76 m/s. At the point it hits the ground, it has a speed of 89 m/s, so if its vertical velocity at that moment is [tex]v_y[/tex], we have

[tex]89\dfrac{\rm m}{\rm s}=\sqrt{\left(76\dfrac{\rm m}{\rm s}\right)^2+{v_y}^2}\implies{v_y}^2\approx2145\dfrac{\mathrm m^2}{\mathrm s^2}[/tex]

(taking the negative square root because we take the downward direction to be negative)

Recall that

[tex]{v_f}^2-{v_i}^2=2a\Delta x[/tex]

where [tex]v_i[/tex] and [tex]v_f[/tex] are the initial and final velocities, respectively; [tex]a[/tex] is the acceleration; and [tex]\Delta x[/tex] is the change in position of a body. In the cannonball's case, it starts with 0 vertical velocity and is subject to a downward acceleration with magnitude [tex]g=9.80\frac{\rm m}{\mathrm s^2}[/tex]. So we have

[tex]2145\dfrac{\mathrm m^2}{\mathrm s^2}-0=-2g\Delta y\implies\Delta y\approx-109.44\,\mathrm m[/tex]

(which is negative because we take the cannonball's starting position at the top of the cliff to be the origin) so the cliff is about 109 m high.

Answer:

Let:

r= radius= 3cm= 0.03m

∅1= initial temperature= 30°C

∅2= final temperature= 100°C

∆∅= change in temperature= ∅2 - ∅1= 70°C

L.E.= linear expansivity= 0.000019k^-1

¥= 3L.E.= volume expansivity= 3(0.000019)= 0.000057k^-1

The initial volume of the metal sphere= 4/3(πr³)

= 4/3(π×0.03³)

= 4(π×0.03²×0.01)

= 4(3.142×0.0003×0.01)

= 4(0.000009426)

= 0.000037704

= 3.7704 × 10^-5m³

¥= V2 - V1/V1∆∅

V2= ¥V1∆∅ + V1

= (1.5044 × 10^-7) + (3.7704×10^-5)

= 0.00003785

= 3.785 × 10^-5m³

Therefore, the initial and final volume of the metre sphere are 3.7704 × 10^-5 and 3.785 × 10^-5 respectively.

The force of friction depends on the area of contact between the two surfaces. As the area of contact is less in the case of rolling than in the case of sliding that's why rolling friction is less than the sliding friction. More the contact area more the friction.

Answer:

The right approach will be Option C "Group 12".

Explanation:

Some other options in question are not relevant to something like the given scenario. Because then the option here is just the right one.

Answer:

option C group 12

Explanation:

i did the test

Answer:

false

Explanation:

because they does'nt Work for anything, are like they are not there

Answer:

False

Explanation:

The rules for significant figures are:

A zero before a decimal point is only significant if there's a non-zero digit before it.

For example, in the number 10.5, the zero is significant, because it is between significant digits.

But in the number 0.5, the zero is not significant.

Answer:

Capacitor

Explanation:

Capacitor ; A capacitor is a passive two-terminal electrical component that can store energy in an electric field electrostatically. It works as a small rechargeable battery that stores electricity. However, unlike a battery, it can charge and discharge in the split of a second. Capacitors are widely used to build different types of electronic circuits.

Answer:

0.0238 centimetre

Explanation:

multiply the length value by 100

Answer:

the orbital speed of umbriel is 16,800 km/h

Explanation:

The computation of the orbital speed is shown below

According to the question the Data provided in the question

Uranus mass = 8.68 × 10^25 kg

Distance = 2.66 × 10^8 m

Based on the above information, the orbital speed of Umbriel is

[tex]V = \sqrt{\frac{GM}{R} } \\\\ = \sqrt{\frac{((6.673e-11)(8.68e25)}{2.66e8} }[/tex]

V = 4666 m/s

= 16,800 km/h

Hence, the orbital speed of umbriel is 16,800 km/h

Therefore it can be calculated by applying the above formula

Answer: 4665

Explanation: I got it right after on acellus

Explanation:

Airplanes have more kinetic energy because their bigger. A bug is a living thing well a airplane is not so it (the airplane) has all these machines and engines to make it go faster.

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]

v is image distance

[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm[/tex]

If h' is the height of the image. Magnification is given by :

[tex]m=\dfrac{h'}{h}=\dfrac{v}{u}[/tex]

[tex]h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm[/tex]

So, the height of the image of the candle is 20 cm.

Answer:

The correct answer is H ÷ ¹/₂T

Explanation:

The formula for velocity is distance covered ÷ time.

Neglecting air resistance;

If the ball's time of overall time flight is T, the time it will take for the second half/return trip is ¹/₂T.

If the ball's maximum height above its released point is H, the height will also be the distance it covered for the second part of the trip since the student caught the ball in the exact same place the ball was thrown. Hence, the distance for the second half of the trip will be H.

Since velocity = distance/time

The average velocity during the second half of the trip will be = H ÷ ¹/₂T

Answer:

15.13m

Explanation:

change 15m to cm

1m=100cm

15m times 100=1500cm

add 1500+13 = 1513cm

in metres it will be 15.13m

Multiple of a unit of measure are found by multiplying the unit by an unteger larger than one

The total distance the tortoise walked in meters is 15.13 m

Reason:

Known parameter are;

The distance west the tortoise travels = 15 meters

The further distance west the tortoise walks = 13 cm = 0.13 m

Required:

The total (distance) in meters she has walked

Solution:

The total distance the tortoise walked in meters = 15 m + 0.13 m = 15.13 m

Learn more about multiples of units of measurement here:

https://brainly.com/question/1643372

she needs to tie back her hair

Answer:140 m

Explanation:

Displacement = 290-150= 140 m

Answer:

[tex]\Large \boxed{3}[/tex]

Explanation:

Info given;

∵ 40 meters east in 5 seconds

∵ 100 meters west in 15 seconds

=> [tex](100 -40)[/tex]

=> Divided by;

=> [tex](5 + 15)[/tex]

=> [tex]3 m/s[/tex]

Answer; 3 m/s

(Average velocity is; 3 m/s )

Answer:

Explanation:The average human adult has more than 5 liters (6 quarts) of blood in his or her body. Blood carries oxygen and nutrients to living cells and takes away their waste products. It also delivers immune cells to fight infections and contains platelets that can form a plug in a damaged blood vessel to prevent blood loss

Answer:

F = 7.21 N

Explanation:

There are two methods to find the magnitude of F.

The first method is the analytical one and the second one is the geometrical one.

The easiest is the geometrical one.

We will start with it

■■■■■■■■■■■■■■■■■■■■■■■■■■

● Method 1:

The geometrical method

The grain remains in equilibrum under the action of 3 forces.

The 3 forces must give if joined together a close path.

There are 3 forces so the resulting shape is a triangle. (Picture 1)

● Al Kashi theorem:

We will use Al Kashi theorem (law of cosine) to find the magnitude of F.

● F^2 = b^2 + c^2 + 2bc×cosA

● F^2 = 10^2 + 4^2 + 2×10×4 × cos(37°)

● F^2 = 52.1

● F = 7.21 N

■■■■■■■■■■■■■■■■■■■■■■■■■■

● method 2 (analytical one)

This method is based on projecting each vector on the x and y axis.

Since the grain remains in equilibrum the relation between the vectors is:

● Vector F + Vector 1 + Vector 2 = Null vector

Vector one is the one with 4 N magnitude and 2 is the 10 one.

Project each vector following the x-axis and the y-axis and add them together.

(Picture 2)

● x-axis

F1 is the 4 N force and F2 is the 10 N one

● Fx + F1x + F2x = 0

● Fx -4 + 10 × cos(37°) = 0

F1x is negative since it goes toward the negatives numbers. It is parallel to the x-axis that's why we have put directly the magnitude

Fx2 is not parallel to the x-axis that's why we have expressed it using the cosine relation. (Picture 3)

● Fx -4 + 10 × cos(37°) = 0

● Fx = 4 -10 × cos(37°)

● Fx = -4 after rounding to the nearest unit

● y-axis

● Fy + F1y + F2y = 0

● Fy + 0 + sin(37°) × 10 = 0

F1y equals 0 since when projecting the vector's head and tail, both were in the same point. In other words the direction of the vector was perpendicular to the y-axis.

F2y is'nt parallel to the y-axis. That's why we have expressed it using the sine.

● Fy + sin(37°)×10 =0

● Fy = -10×sin(37°)

● Fy = -6 after rounding it to the nearers unit

Notice that F, Fx and Fy are creating a right triangle.(picture 4)

● The Pythagorian theorem

● F^2 = Fx^2 + Fy^2

● F^2 = (-4)^2 + (-6)^2

● F^2 = 16+36

● F^2 = 52

● F^2 = 7.21 N

That's the same result we got using the first method.

Answer:

F = 7.21 N

Explanation:

horizontal sum of forces = ∑h = 10 cos(37) - 4 = 3.98 N

vertical sum of forces = ∑v = 10 cos(90-37) = 6.02 N

therefore, the resultant F² = ∑h² + ∑v²

F = sqrt (3.98² + 6.02²)

F = 7.21 N

'Doing work' is a way of transferring energy from one object to another, energy is transferred when a force moves through a distance.

If i explain with formula

Work done (J) = Energy transferred (J)

So more energy, more work done bc u transferred more energy to move the object and doing the work. and if you only use a little of energy, the work done also only a little.

Work affect energy between objects so it can cause a change in the form of energy by transferring energy.

According to work energy theorem, the work done on an object is directly proportional to the change in the average kinetic energy of the body.

Thus, we can conclude that work affect energy between objects so it can cause a change in the form of energy by transferring energy.

Learn more here: https://brainly.com/question/10063455

Answer:

The weight of the wrench on the Moon is approximately 0.8555 N

Explanation:

On Earth, the acceleration of gravity at sea level is 9.8 m/s^2

then if the wrench weights 5.24 N that means that its mass according to Newton's second law is:

[tex]F = m \, a\\m=\frac{F}{a} \\m=\frac{5.24}{9.8} \, kg\\m=0.5347[/tex]

Now we can use the wrench's mass to find its weight on the Moon, knowing that the acceleration due to gravity there is 1.6 m/s^2:

[tex]W=m\,g\\W=(0.5347) \,(1.6) \,N\\W=0.8555\,\,N[/tex]

Answer:

Explanation:

0.8555

Answer:

The answer is C 0.0

Explanation:

Because its sitting still on the ground.

Answer:

0.0j

Explanation:

Answer:

2.481 mm

Explanation:

Given that

Distance between the slits, d = 0.275 mm = 2.75*10^-4 m

Wavelength of the lamp, λ = 546.1 nm

Distance between slit and the screen, L = 1.25 m

To solve this question, we would be applying the formula for Young's double slit fringes, from the path difference equal to a whole number of wavelengths.

mλ = dy/L

The question states that we should find the distance from the centre to the 1st order bright fringe, thus, m = 1

Now, we apply all these values into the question

1 * 546.1*10^-9 = (2.75*10^-4 * y) / 1.25

1.25 * 1 * 546.1*10^-9 = 2.75*10^-4 * y

6.825*10^-7 = 2.75*10^-4 * y

y = 6.825*10^-7 / 2.75*10^-4

y = 0.002481 m or 2.481 mm