The percent yield for the reaction is 84.6%.
To calculate the percent yield for the reaction, we first need to determine the theoretical yield of CO₂ based on the balanced chemical equation for the reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
From the equation, we can see that for every mole of C₃H₈ , 3 moles of CO₂ are produced. So, to determine the theoretical yield of CO2, we need to first convert the mass of C₃H₈ to moles and then multiply that by the stoichiometric ratio for CO₂.
The molar mass of C₃H₈ is 44.1 g/mol, so:
3.66 g C₃H₈ / 44.1 g/mol = 0.083 mol C₃H₈
Using the stoichiometry of the reaction, we can now calculate the theoretical yield of CO₂:
0.083 mol C₃H₈ × 3 mol CO₂ / 1 mol C₃H₈ = 0.25 mol CO₂
And the theoretical mass of CO₂:
0.25 mol CO₂ × 44.01 g/mol = 11.0025 g CO₂
Finally, the percent yield of the reaction can be calculated as:
9.31 g CO₂ / 11.0025 g CO₂ × 100% = 84.6%
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Charlotte is driving at 60.2 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for
3.91 s. How far has Charlotte traveled in feet during this time?
Charlotte, driving at 60.2 mi/h, would travel approximately 344 feet during the 3.91 seconds that she looked at her phone.
Explanation:To find out how far Charlotte traveled, we can first convert her speed to feet per second since we're given the time she looked at her phone in seconds. We know that 1 mile is approximately 5280 feet, so Charlotte's speed in feet per second is 60.2 miles per hour multiplied by 5280 feet over 3600 seconds (the number of seconds in an hour). This comes out to be approximately 88 feet per second.
Therefore, in the 3.91 seconds that Charlotte looked at her phone, she would've traveled 88 feet per second times 3.91 seconds, which equals roughly 344 feet.
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The pressure, volume and temperature of a gaseous sample are 0. 753 atm, 1. 68 liters, and 2°C, respectively.
Determine the number of moles of gas in the sample
as per ideal Gas Law equation, we can calculate the number of moles to be 0.0292 moles.
The number of moles of a gas can be calculated using the Ideal Gas Law equation, PV = nRT,
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
For the given sample, the pressure, volume, and temperature are 0.753 atm, 1.68 liters, and 2°C respectively.
By converting the temperature to Kelvin and plugging the values into the Ideal Gas Law equation, we can calculate the number of moles to be 0.0292 moles.
Number of moles = PV / RT
= 0.753 * 1.68 / (0.0821 * (275 + 2))
= 0.0292 moles.
+ the number of moles to be 0.0292 moles.
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what percent of the global atmosphere is carbon dioxide (co2)? lab 5 and other subsequent labs have an emphasis on co2.
The percentage of the global atmosphere is the carbon dioxide that CO₂ is 0.04 %.
The CO₂ that is carbon dioxide makes up the only about 0.04% of the atmosphere, and the water vapor can vary the range from the 0 to 4%. The water vapor is the concentrated lower in atmosphere. The higher will be the greenhouse gas, the more effective will be the trapping heat from the Earth’s surface.
The burning of fossil fuels will affects the concentration of the CO₂ in the earth atmosphere. Before the industrial revolution, the amount of the carbon dioxide in the earth atmosphere was about the 288 ppm.
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GIVING BRAINLIEST TO WHOEVER GETS IT RIGHT
Identify the choice that best completes the statement or answers the question. The following paragraph contains an error. Read the entire passage. Then select the option that corrects the error. Most people know that bats can find their way in the dark using echolocation. Bats make a series of high-pitched squeaks. Based on the way these sound waves diffract off objects around it, a bat can form a mental picture of its surroundings. Fewer people realize that humans can also learn to echolocate. A man named Daniel Kish can ride his bike even though he lost his vision at the age of one! Mr. Kish makes a sharp clicking sound with his tongue. By listening to the echoes of the click, he can easily navigate his surroundings.
A. Mr kishs use of echolocation would be limited due to absorption of sound waves
B. Mr kish actually navigates through the use of radar waves, not echolocation
C. in echolocation, bats listen to the way sound waves refract, not diffract
D. In echolocation, bats listen to the way sound waves reflect, not diffract
Answer:C
Explanation: Done by reading and is best answer option.
What is the IUPAC name of NABH4
I’m pretty sure it’s Sodium borohydride
In the following acid-base reaction,
OH- is the
CH3NH2(g) + H2O(1)
→
CH3NH3(aq) + OH¯(aq)
Conjugate base
Acid
Conjugate acid
The base in the following chemical interaction is CH3NH2, which is methyl amine. It creates its conjugate acid, the methyl ammonium ion, when it receives a proton.
How is the conjugate base discovered?The conjugate base's formula is the acid's formula less one hydrogen. The base that reacts changes into its conjugate acid. The conjugate acid's formula is the base's formula adds one hydrogen ion.
Is ch3oh a base for Bronsted-Lowry?Because it is categorized as both a Lewis acid and a Bronsted-Lowry acid, methanol. It will become a Bronsted-Lowry acid as a result of the proton donation, and the methanol will also take electrons as a result.
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n the formation of ammonia from the reaction of hydrogen and nitrogen . 1. a. hydrogen gains electrons and is reduced. 2. b. hydrogen loses electrons and is reduced. 3. c. hydrogen gains electrons and is oxidized. 4. hydrogen loses an electron and is oxidized. 5. none of the above
In the formation of ammonia from the reaction of hydrogen and nitrogen, hydrogen gains electrons and is reduced.
Reduction is a chemical process in which a substance gains electrons and its oxidation state decreases. This can be contrasted with oxidation, in which a substance loses electrons and its oxidation state increases. In the formation of ammonia from the reaction of hydrogen and nitrogen, hydrogen gains electrons and is reduced, while nitrogen is oxidized. During the reaction, hydrogen atoms donate electrons to nitrogen atoms, forming a covalent bond and producing ammonia. The electrons that are donated by the hydrogen atoms result in an increase in the number of electrons in the hydrogen atoms, which is what makes them reduced. This reaction provides a clear example of how the concepts of reduction and oxidation are related and how they can occur simultaneously in a single chemical reaction.
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simple bread recipe calls for
g of flour, 8 g of salt, 1 g of yeast, 400
and 0.3 L of water. The recipe
produces 1 loaf of bread. The data
table shows the amounts of
each ingredient you have. Identify the
limiting reagent. What is the
theoretical yield, assuming you could
make partial loaves? How many
whole loaves of bread can you actually
make? What is the percent
yield? How much of each ingredient do
you have left over?
We would produce a loaf of bread, the limiting reagent is water and the percent yield is 30%
What is the limiting reagent?The limiting reagent, also known as the limiting reactant, is the reactant that determines the maximum amount of product that can be formed in a chemical reaction. It is the reactant that is completely consumed first and therefore determines the amount of product that can be formed.
Since we have 0.3 g of the water, the theoretical yield would now be;
0.3 g/1 g * 100/1
= 30 %
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a flask contains four gases: ch4, o2, c2h5, and n2. when the stopper is removed, which gas will diffuse the fastest? responses c2h5 uppercase c subscript 2 end subscript uppercase h subscript 5 end subscript o2 uppercase o subscript 2 end subscript ch4 uppercase c h subscript 4 end subscript n2
The gas that will diffuse the fastest is O2 (oxygen). Gases diffuse from areas of high concentration to areas of low concentration. Oxygen has a relatively small molecular size compared to the other gases.
So, it is more likely to move quickly through the container and escape through the opening. Methane (CH4) and Ethane (C2H5) are larger, and thus will diffuse slower than oxygen.
Nitrogen (N2) is an even larger gas, and it will diffuse the slowest of all the gases in the flask.
Methane is a chemical composite with the chemical formula CH₄. It is a group-14 hydride, the simplest alkane, and the main basic of natural gas.
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Comparing the grams of each reactant needed to the number of grams actually used in the lab, the limiting reaction is _______ and the excess reaction is _________.
Answer:
The limiting reactant is the reactant that is completely consumed first in a chemical reaction and the excess reactant is the reactant that remains after the limiting reactant is used up.
a pot contains 9 l of brine at a concentration of 110 g/l. how much of the water should be boiled off to increase the concentration to 220 g/l?
4.95 liters of water need to be boiled off to increase the concentration of the brine to 220 g/l.
When the solution will boil, only the solvent will be converted to gas. The solute remains in the solution, so its amount does not change but the concentration does.
The total amount of the solute = 110 g/l * 9 l = 990 g
Inorder concentration = 220 g/l
The amount of the water that should be boiled off = 990 g / (220 / 110)
= 990 g / 2
= 4.95 liters
So, 4.95 liters of water need to be boiled off to increase the concentration of the brine to 220 g/l.
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openstax college physics what would this frequency become if the person's breathing passage were filled with carbon dioxide instead of air? assume the same temperature dependence for carbon dioxide as for air.
The speed of sound in a given medium, which depends on the medium's temperature, pressure, and density, determines the frequency of a sound wave inside.
The frequency of a wave is the number of times its cycles occur in a unit of time. It is typically expressed in Hertz (Hz), which stands for one cycle per second, in physics. A wave's apparent pitch depends on its frequency; higher frequency waves produce higher pitches, and lower frequency waves produce lower pitches. Frequency is a key idea in several branches of physics, such as electromagnetism and optics, where it relates to the energy of waves and the colour of light, respectively. The periodic motion of objects and the behaviour of oscillating systems are both connected to frequency in mechanics. Additionally, it is employed in the research of sound waves and the creation of music.
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9.9 kg of r-134a at 300 kpa fills a rigid container whose volume is 14 l. determine the temperature and total enthalpy in the container. the container is now heated until the pressure is 600 kpa. determine the temperature and total enthalpy when the heating is completed. use data from the refrigerant tables.
the temperature and total enthalpy after the heating is can be found by using the conservation of energy principle and the first law of thermodynamics.
To determine the temperature and total enthalpy in a container filled with 9.9 kg of R-134a at 300 kPa and a volume of 14 L, and then to find the temperature and total enthalpy after the pressure has been increased to 600 kPa, we need to use the refrigerant tables to look up the thermodynamic properties of R-134a.
The first step is to find the specific volume, internal energy, and enthalpy of R-134a at the initial state (300 kPa and a temperature to be determined).
Next, we can use the ideal gas law to find the temperature of R-134a at the initial state:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of refrigerant, R is the gas constant, and T is the temperature.
The number of moles can be found using the mass and molecular weight of R-134a:
n = m/M
where m is the mass of R-134a and M is its molecular weight.
Using the refrigerant tables, we can find the specific volume, internal energy, and enthalpy of R-134a at the final state (600 kPa and a temperature to be determined).
With this information, we can calculate the change in internal energy and enthalpy during the process of heating the container.
Finally, the final temperature and total enthalpy can be found by using the conservation of energy principle and the first law of thermodynamics.
This is a complex calculation that requires a good understanding of thermodynamics and the use of refrigerant tables. If you need more detailed information or have specific data, please provide it and I will do my best to assist you.
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the child is receiving d10ns with 20 meq kcl infusing at 100 ml/hr. a new 1,000- ml fluid bag was hung at 0700. at 0800 the iv infiltrated and was restarted at 1000. at 1100 the iv rate was decreased to 50 ml/hr until 1900. calculate the total iv intake from 0700 to 1900.
The following formula can be used to determine the total IV intake between 7:00 and 9:00. Thus, 600 cc of IV fluid total were administered between 7:00 and 1:00.
Total IV intake is the total volume of fluid injected into a person's circulation via an intravenous (IV) line. Typically, the IV line is put into a vein in the arm or hand, and the fluid, which may contain nutrients, electrolytes, and drugs, is then given directly into the bloodstream. Tracking the overall IV intake is crucial, particularly in healthcare settings, since it ensures that patients are receiving the right amount of fluid and minerals to preserve their health. A range of medical disorders, such as dehydration, malnutrition, and some medical procedures, may require the insertion of an IV line. It is crucial to carefully monitor the total IV intake to prevent consequences like fluid overload.
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When 16.68 grams of methane (CH4) are burned (see equation below), how many moles of oxygen gas (O2) will be used? Please round your answer to two digits after the decimal point and don't forget units and substance!
CH4 + 2 O2 --> CO2 + 2 H2O
Please help me with this! thank you a bunch in advance!!
When 16.68 grams of methane (CH4) are burned. Therefore, 2.06moles of oxygen gas will be used.
What is mole?A mole is merely a measuring unit. In reality, it is one of the International System of Units' seven foundation units (SI). When basically determines are insufficient, new units are created.
Chemical reactions frequently occur at levels that use grams would be inappropriate, but using actual figures of atoms/molecules/ions could also be misleading. As a result, scientists devised the moles to bridge the divide between extremely small and extremely huge numbers.
CH[tex]_4[/tex] + 2 O[tex]_2[/tex] [tex]\rightarrow[/tex]CO[tex]_2[/tex]+ 2 H[tex]_2[/tex]O
moles of methane = 16.68 /16.04=1.03moles
the mole ratio between methane and oxygen is 1:2
mole of oxygen = 2×1.03=2.06moles
Therefore, 2.06moles of oxygen gas will be used.
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what is the concentration of every ion present in solution made by mixing 25ml of 3m solution of aluminum
The concentration of aluminum ions in the solution made by mixing 25ml of 3M Al solution is determined by the amount of solute present in a given amount of the solvent.
What are aluminum ions?Aluminum ions are positively charged atoms of aluminum that have lost one or more electrons. These ions are important components in many chemical reactions, and they are also used in a variety of industries, such as in the production of aluminum products.
The aluminum ion concentration in the solution formed by combining 25ml of 3M Al solution will be 3M. This is because the amount of solute (in this example, Al) present in a given amount of solvent determines the concentration of the solution (in this case, 25ml of the solution). Because the concentration of the solution is 3M, the concentration of aluminum ions in the solution is also 3M.
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if 5 half-lives have gone by and you have .03125 grams of an unstable parent substance, how many grams of stable daughter product should you have?
Answer:
Explanation:
The amount of daughter product that should be present after 5 half-lives depends on the specific radioactive decay process involved and the initial amount of the parent substance. In general, after each half-life, the amount of the parent substance decreases by half, and the corresponding amount of the daughter product increases by half.
In this case, with 5 half-lives gone by, the amount of the parent substance should have decreased by a factor of 2^5 = 32. Hence, the amount of the parent substance should be .03125/32 = 0.0009765625 grams.
Since the amount of daughter product is proportional to the amount of the parent substance that decays, the amount of daughter product should be 0.0009765625 * 32 = 0.03125 grams.
given that a sample of air is made up of nitrogen, oxygen, and argon in the mole fractions , , and , what is the density of air at standard temperature and pressure?
The density of air is1.293 kg/m³
What is density?
this can be defined as the ratio of the mass of a body and its volume.
The S.I unit of density is kg/m³
D = m/v.......(1)
D = density, m = mass, v = volume
(i) Mass of one mole of N₂ = 28 g
Therefore, mass of 0.78 mole of N₂ = 28×0.78 = 21.84 g.
(ii) Mass of one mole of O₂ = 32 g
Therefore, mass of 0.21 mole of O₂ = 32×0.21 = 6.72 g
(iii) Mass of one mole of Ar = 40 g
Therefore mass of 0.01 mole of Ar = 0.01×40 = 0.4 g
m = 21.84 + 6.72 + 0.4 = 28.96 g
One mole of every gas at standard temperature and pressure = 22.4 dm³
Therefore,
(i) volume of 0.78 mole of N₂ = 22.4×0.78 = 17.47 dm³
(ii) volume of 0.21 mole of O₂ = 0.21×22.4 = 4.704 dm³
(iii) volume of 0.01 mole of Ar = 0.01×22.4 = 0.224 dm³
Therefore,
v = 17.47+4.704+0.224
v = 22.398 dm³
Substituting the value of v and m into equation (1)
D = 28.96/22.398
D = 1.293 g/dm³
D = 1.293 kg/m³
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how do the physical properties of ionic solids, in general, differ from the properties of molecular solids? give an example of each to illustrate your discussion.
Ionic solids and molecular solids have distinct differences in their physical properties due to the nature of their constituent particles.
Ionic solids are composed of positively and negatively charged ions, held together by strong electrostatic forces. They are typically hard and brittle, with high melting and boiling points. Ionic solids are poor conductors of electricity in the solid state, but they are good conductors in the molten state or in aqueous solution.
An example of an ionic solid is sodium chloride (NaCl), which is a white crystalline solid with a high melting point of 801 °C.
Molecular solids, on the other hand, are composed of neutral molecules held together by weak intermolecular forces such as van der Waals forces or hydrogen bonds. They tend to be soft and have low melting and boiling points. Molecular solids are poor conductors of electricity in both the solid and liquid state.
An example of a molecular solid is iodine (I2), which is a black crystalline solid with a low melting point of 114.5 °C.
In summary, ionic solids are characterized by their high melting and boiling points, brittleness, and poor electrical conductivity in the solid state, while molecular solids are characterized by their low melting and boiling points, softness, and poor electrical conductivity in both the solid and liquid state.
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what occurs when ice melts? responses a physical change a physical change an atomic compound is newly formed. an atomic compound is newly formed. a nuclear change a nuclear change a chemical change
When ice melts a physical change occur. The correct answer is A.
The capacity to flow gives an ice cube the ability to alter shape as it melts. Its makeup stays the same, though. One instance of a physical change is melting. A physical change is when a sample of matter experiences a change in some of its qualities but not in its identity.
A reversible change in the substance's or object's physical characteristics can be referred to as the physical change. It is a physical change when ice melts. Water (H₂O) appears to alter when it turns from a liquid state to a solid state (ice). However, this shift is just physical, as the constituent molecules still consist of 11.19% hydrogen and 88.81% oxygen by mass.
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What do we do with the extra 0.24 days each year upon the completion of Earth's revolution?
A. Every year on New Year's Day we get an extra 4 hours added to our day.
B. Nothing is done with them and our yearly calendar always has 365 days.
C. Every 4 years they are put together and we add one day to our yearly calendar.
D. We move our clocks back an hour in the fall and ahead an hour in the spring.
Answer:
C. Every 4 years they are put together and we add one day to our yearly calendar.
Answer:C. Every 4 years they are put together and we add one day to our yearly calendar (leap year).
Explanation:
Help what is the answer?
The specific heat of mercury calculated from her data is 0.13 J/g°C.
Specific heat is a measure of how much energy is required to heat a substance. This is the amount of energy (in joules) required to heat 1 gram of a substance by 1°C. Different substances have different specific heats.
To answer this question, use the heat slaughter formula:
Q =mCΔT
In the question:
Heat energy: Q = 30.1 J
Mass of mercury: m = 12.5 g
T1 = 21.2
T2 = 39.6°C
Temperature:
ΔT = T2 –T1
∆T = 39.6 – 21.2
∆T = 18.4°C
The specific heat of mercury is?
Q =mCΔT
C = Q/mΔT
C = 30.1/12.5 x 18.4
C =30.1/230
C = 0.13 J/g°C
So, the specific heat of mercury is 0.13 J/g°C.
Question:
In the laboratory a student finds that it takes 30.1 Joules to increase the temperature of 12.5 grams of liquid mercury from 21.2 to 39.6 degrees Celsius.
The specific heat of mercury calculated from her data is_____J/g°C.
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what is the freezing point of a solution formed by dissolving 0.75 moles naphthalene in 2.0 kg benzene g
The freezing point of a solution is dependent on the concentration of solute particles in the solvent. The presence of solute particles in a solvent decreases its ability to freeze, and as a result, the freezing point of the solution is lowered.So, the freezing point of the solution would be lower than that of pure benzene by 1.91 °C.
The freezing point depression of a solution can be calculated using the equation:
ΔTf = Kf x molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of solute particles in the solution expressed in moles per kilogram of solvent.
In this case, the solvent is benzene and its freezing point depression constant, Kf, is 5.12 °C/m. The molality of the solution can be calculated as follows:
molality = moles of solute / kilograms of solvent
= 0.75 moles / 2.0 kg
= 0.375 moles/kg
Substituting these values into the equation, we get:
ΔTf = 5.12 °C/m x 0.375 moles/kg
= 1.91 °C
So,the freezing point of the solution is 1.91 °C.
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how many grams of NaCl would dissolve in water to make a 50 M solution with 500 mL final volume
Mass of NaCl that would dissolve in water to make a 50 M solution with 500 mL final volume is 1460 grams
To make a 50 M solution of sodium chloride (NaCl), the number of moles of NaCl required can be calculated using the formula:
moles of solute = concentration (M) x volume (L)
where volume is in liters. In this case, the concentration is 50 M and the volume is 0.5 L (500 mL).
moles of NaCl = 50 M x 0.5 L = 25 moles
Since the molecular weight of NaCl is 58.44 grams/mole, the mass of NaCl required can be calculated by multiplying the number of moles by its molecular weight:
mass = moles x molecular weight
mass of NaCl = 25 moles x 58.44 grams/mole = 1460 grams
So, 1460 grams of NaCl would dissolve in water to make a 50 M solution with a final volume of 500 mL.
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an acidic water sample initially contains 2 mg/l of iron(iii). how much iron precipitates out if the ph is raised to 3? assume the temperature is 25oc
The amount of iron that precipitates out if the ph is raised to 3 assuming the temperature is 25 will be depending on the solubility product constant of iron(III) hydroxide.
The amount of iron(III) that precipitates out when the pH of an acidic water sample is raised to 3 depends on the solubility product constant (Ksp) of iron(III) hydroxide. At 25°C, the Ksp of Fe(OH)3 is 1.26 x 10^-39. When the pH of the water sample is raised to 3, the concentration of hydroxide ions increases, which can lead to the precipitation of iron(III) hydroxide if the concentration exceeds the solubility limit defined by the Ksp. The exact amount of iron(III) that precipitates out can be calculated using an equilibrium expression and the Ksp, but without more information about the initial conditions and changes in concentration, it is not possible to determine the exact amount of iron that precipitates.
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how many moles and how many grams of kmno4 are needed to carry out this reaction on 11.4 grams of kno2
0.0451 moles of KMnO4 and 7.18 grams of KMnO4 are required to produce 11.4 grams of KNO3.
The chemical equation for the reaction is
5 KNO₂ + 2KMnO₄ + 3 H₂SO₄ →5 KNO₃ + K₂SO₄ + MnSO₄ + 3 H₂O
From the equation, we see that for every 5 moles of KMnO2, 5 moles of KNO3 are produced, and for every 2 moles of KMnO4, 5 moles of KNO3 are produced.
Determine the number of moles of KNO3 produced, which can be calculated from the mass of KNO3 (11.4 g) and its molar mass (101.1 g/mol):
11.4 g KNO3 / 101.1 g/mol = 0.1129 moles KNO3
Since 5 moles of KMnO2 produce 5 moles of KNO3, 2 moles of KMnO4 produce 5 moles of KNO3.
This means that for every 0.1129 moles of KNO3, 0.1129 moles / (5/2) = 0.0451 moles of KMnO4 are required.
Convert the number of moles of KMnO4 to mass by multiplying by its molar mass (158.0 g/mol):
0.0451 moles KMnO4 * 158.0 g/mol = 7.18 g KMnO4
How do you convert moles to mass?
Multiply the molecular weight by the number of moles for the substance. The molecular weight is the number of grams per mole for the substance and gives the conversion factor for moles to grams for that particular substance.
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you are conducting the acetophenetidin reaction and just finished your hot gravity filtration. you notice that you have some activated carbon in your filtrate solution. what is the best way to address this problem?
Use a fresh funnel and fresh filter paper to repeat the hot gravity filtration.
The best way to address this problem is to perform a cold gravity filtration. This will allow the activated carbon to settle at the bottom of the container, making it easier to filter out. After the cold gravity filtration, you may also want to consider running the solution through a filter paper to remove any remaining activated carbon particles. Recrystallization is accomplished using hot gravity filtration. It is specifically used to clean the sample of any insoluble contaminants. The stemless funnel is ideal for this method because it prevents crystallization on the stem of the funnel (since stemless).
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Nitrogen gas, N2, reacts with hydrogen gas, H2 to form ammonia, NH3.
3 H2(g)+ N2(g) → 2 NH3(g)
If 5.40 L of ammonia gas is collected at 25.60 °C and 761.0 mmHg, how many grams of nitrogen gas are consumed? The molar mass of nitrogen gas is 28.0134 g/mol.
Ammonia has a molar mass of 17 g/mol. Ammonia weighs 68 grammes, or 17g/mol. 68g=4moles From 241 = 2 moles of nitrogen and 243 = 6 moles of hydrogen, 4 moles of ammonia will be produced. Nitrogen and hydrogen have molar weights of 28 g/mol and 2 g/mol, respectively. 56 grammes are equivalent to 2 moles of nitrogen, or 228. 6 moles of hydrogen are equivalent to 12 grammes (62).
From 50.0 grammes of the nitrogen gas 3h2 N2 --> 2nh3, how many grammes of ammonia are produced?
We need to determine how many moles of nitrogen there are in this 50 g of nitrogen gas. We would generate 1.792=3.58 moles of ammonia from this point. 3.58 mol; 17.031 gmol; 61 g of NH3
42 grammes of nitrogen may be converted into how many grammes of ammonia?
b The mass of N and H in the ammonia molecule, NH3, is equal to 14 + 3 1 = 17. The amount of H needed to react with 14 g of N is 3 g. Hence, the mass of H needed to react with 42 g of N is equal to 3/14 42 = 9 g.
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a compound has the empirical formula c2h4s. its molecular weight is 120 g/mol. identify the molecular
The molecular formula of the compound with empirical formula C2H4S and molecular weight of 120 g/mol is C6H12S2.
The empirical formula represents the simplest ratio of atoms in a compound. It is determined from the elemental analysis of the compound. The molecular weight of the compound is the sum of the atomic weights of all the atoms in the molecular formula. To find the molecular formula, the molecular weight is used to determine the number of atoms in the empirical formula.
In this case, the molecular weight of 120 g/mol can be used to find the molecular formula by dividing the molecular weight by the empirical formula weight. The empirical formula weight of C2H4S is 40 g/mol, which means that the molecular formula must have a weight of three times the empirical formula weight, or 120 g/mol.
This leads to the molecular formula of C6H12S2, which has a molecular weight of 120 g/mol.
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CoCl2 + F2 ⟶ CoF2 + Cl2
How many moles of fluorine are required to produce 291g of chlorine?
How many grams of cobalt (II) fluoride are produced from 291 g of F2 with excess cobalt (II) chloride ?
One mole of fluorine gas gives one mole of chlorine gas. Hence, 291 g of chlorine gas is produced by 155 g of fluorine gas. 38 g of F₂ gives 66 g of cobalt fluoride. Hence, 291 g will give 505 g of cobalt fluoride.
What is cobalt fluoride ?Cobalt fluoride is an ionic compound formed by the combination between cobalt metal and chlorine gas.
As per the given reaction, one mole of F₂ gives, one mole of Cl₂.
molecular mass of F₂ = 38 g/mol
molecular mass of Cl₂= 71 g.
hence, mass of F₂ needed to produce 291 g of Cl₂ is:
(291 g × 38 g)/71 g = 155 g.
38 g of F₂ gives 66 g of CoF₂.
molar mass of CoF₂ = 66 g/mol.
Hence, mass of cobalt fluoride produced by 291 g of fluorine is :
(291 × 66)/38 g = 505.4 g
Therefore, 291 g of F₂ will produce 505 g of cobalt fluoride.
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