Step 1 of 7: The class width of the data given s 50.
Step 2 of 7: The frequency in 3rd class is 5
Step 3 of 7: Lower class boundary for the second class is 1228.5.
Step 4 of 7: Upper class boundary for the 3rd class is 1328.5
Step 5 of 7: The midpoint of the first class is 1203.5
Step 6 of 7: The relative frequency of the second class is 0.0476
Step 7 of 7: The cumulative frequency of the 5th class is 15.
As per the data given:
the following data representing the price of plasma televisions (in dollars).
1467, 1281, 1342, 1429, 1313, 1357, 1448, 1385, 1304, 1291, 1406, 1410, 1307, 1422, 1264, 1454, 1191, 1191, 1372, 1461, 1447.
Class Relative Cumulative
Class Frequency Boundaries Midpoint Frequency Frequency
1179−1228 2 1178.5 - 1228.5 1203.5 0.0952 2
1229−1278 1 1228.5 - 1278.5 1253.5 0.0476 3
1279−1328 5 1278.5 - 1328.5 1303.5 0.2381 8
1329−1378 3 1328.5 - 1378.5 1353.5 0.1429 11
1379−1428 4 1378.5 - 1428.5 1403.5 0.1905 15
1429−1478 6 1428.5 - 1478.5 1453.5 0.2857 21
Step 1 of 7: Determine the class width of the data given.
The class width is the difference between the upper or lower class limits of consecutive classes. All classes should have the same class width. In this case, class width equals to the difference between the lower limits of the first two classes.
w = 1229 - 1179 = 50
Step 2 of 7: Determine frequency in 3rd class
The 3rd class is 1279−1328 and the frequency in 3rd class is 5
Step 3 of 7: Determine the lower class boundary for the second class
The 2nd class is 1229−1278 and the class boundary is 1228.5 - 1278.5
Lower class boundary for the second class is 1228.5.
Step 4 of 7: Determine the upper class boundary for the 3rd class
The 3rd class is 1279−1328 and the class boundary is 1278.5 - 1328.5
Upper class boundary for the 3rd class is 1328.5
Step 5 of 7: Identify the midpoint of the first class
The 1st class is 1179−1228 and the midpoint of the first class is 1203.5
Step 6 of 7: Calculate the relative frequency of the second class.
The 2nd class is 1229−1278 and the relative frequency of the second class is 0.0476
Step 7 of 7: Compute the cumulative frequency of the 5th class
The 5th class is 1379−1428 and the cumulative frequency of the 5th class is 15.
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Evaluate sec2 (pi/5) - tan2 (pi/5).
The value of sec2(pi/5) - tan2(pi/5) is equals to 1.
What is trigonometric identity ?
A trigonometric identity is a mathematical equation that relates the values of trigonometric functions of an angle. These identities are true for all values of the angle for which both sides of the equation are defined.
We can use the trigonometric identities to simplify this expression. Recall that:
sec(x) = 1/cos(x)
tan(x) = sin(x)/cos(x)
sin2(x) + cos2(x) = 1
Using these identities, we can rewrite the expression as:
sec2(pi/5) - tan2(pi/5)
= (1/cos2(pi/5)) - (sin2(pi/5)/cos2(pi/5))
= (1 - sin2(pi/5))/cos2(pi/5)
= cos2(pi/5)/cos2(pi/5) (using the identity sin2(x) + cos2(x) = 1)
= 1
Therefore, sec2(pi/5) - tan2(pi/5) = 1.
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thhis is my question
Both items have different rate of change, m₁ = -2, m₂ = -1/2, Item 1 is steeper.
Correct option is C.
What is slope?The slope of a line is defined as the change in y coordinate with respect to the change in x coordinate of that line. The net change in y coordinate is Δy, while the net change in the x coordinate is Δx. So the change in y coordinate with respect to the change in x coordinate can be written as,
m = Δy/Δx
where,m is the slope
Slope of line denotes rate of change and steepness.
Given,
A) a line with y-intercept (0,0) and passes through point (-2 , 4).
slope of the line
= (y₂ - y₁)/(x₂ - x₁)
= (4 - 0)/(-2 - 0)
= 4/-2
m₁ = -2
B) In the graph, line passes through (2, -1) and (-2 , 1 )
slope of the line
= (y₂ - y₁)/(x₂ - x₁)
= (1 - -1)/(-2 - 2)
= 2/-4
m₂ = -1/2
Hence, by the calculation
Items have different rate of change, Item 1 is steeper.
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Someone help me with these math problems
1. Two lines are MT and UW. 2. Two segments are SX and SY. 3. A pair of congruent angles is ∠QNT and ∠QNM. 4. Four right angles are ∠QNT and ∠QNM. ∠TNY and ∠MNY.
What are obtuse vertical angles?Angles that are both vertical and obtuse are known as obtuse vertical angles. In order to comprehend what obtuse vertical angles are, we must first learn the definitions of each of these kinds of angles.
Angles that cross one other at the junction of two lines are known as vertical angles. There is always an equal amount of vertical angles.
With these definitions, we get that obtuse vertical angles are angles that are in front of one another at the intersection between two lines, and both of which share a comparable measure that is between 90° and 180°.
From the given figure we observe that:
1. Two lines are MT and UW.
2. Two segments are SX and SY.
3. A pair of congruent angles is ∠QNT and ∠QNM.
4. Four right angles are ∠QNT and ∠QNM. ∠TNY and ∠MNY.
5. Two pairs of obtuse vertical angles ∠MSW and ∠UST. ∠VNT and ∠PNM.
6. Two pairs of adjacent supplementary angles are ∠MSW and ∠WST. ∠WNM and WNT.
7. Two pair of complementary angles are ∠TNP and ∠PNY. ∠QNW and ∠WNM.
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What is 32/34 in simplest form
Answer:
Step-by-step explanation:16/17
Answer:
16/17 is the simplest form
Using Company A's calling plan, the cost of an overseas phone call is a $0.95 connection fee plus 33 cents
per minute. If the total cost of the call is $11.84, how long is the phone call?
minutes
The total duration of the phone call was 33 minutes.
Given that, by using Company A's calling plan, the cost of an overseas phone call is a $0.95 connection fee plus 33 cents per minute. If the total cost of the call is $11.84 and we have to calculate the time how long was the phone call.
Let the number of minutes a phone call held be x.
Now, we will be representing the above given information in terms of linear equation and then solve for the value of x which will give us the number of minutes the phone call held.
[tex]Total[/tex] [tex]cost=[/tex] $[tex]0.95[/tex] [tex]+[/tex] $[tex]0.33x[/tex]
$[tex]11.84=[/tex] $[tex]0.95[/tex] [tex]+[/tex] $[tex]0.33x[/tex]
[tex]11.84=0.95+0.33x[/tex]
[tex]11.84-0.95=0.33x[/tex]
[tex]0.3=0.33x[/tex]
[tex]\frac{0.3}{0.33}=x[/tex]
[tex]33=x[/tex]
Therefore, the call will go 33 minutes long.
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Find x, y, and z such that x³+y³+z³=k, for each k from one to 100.
Answer:
The answer is:-
Step-by-step explanation:
x^3+y^3+z^3=k
xyz^9=k
xyz/9=k
xyz=9k
Hence, k=9 and, x, y and z are 1.
Please tell me the answer and explain how
The value of x is 60.
We can use the fact that the opposite angles of a parallelogram are equal to find the value of x. Angle BCD is therefore equal to angle ABD, and angle CBD is equal to angle CAD.
Based on the given angles, we can construct two equations:
Angle ABD + angle CBD = 100 (because angle BCD = angle ABD) Angle ABD + angle ACD = 80 (because angle CAD = angle CBD)
When we substitute the given values, we get:
x + 40 = 100 x + 20 = 80
When we solve for x in both equations, we get:
x = 60 x = 60.
We can be confident that our answer is correct because both equations give us the same value for x. As a result, the value of x is 60.
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The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two time periods of an equal length. It is known that the mean number of occurrences in ten minutes is 5.3. (please show work)
1. Refer to Exhibit 2. The random variable x satisfies which of the following probability distributions?
a. normal b. Poisson c. binomial d. Not enough information is given to answer this question.
2. Refer to Exhibit 2. The probability that there are 8 occurrences in ten minutes is
a. .0241 b. .0771 c. .1126 d. .9107
3. Refer to Exhibit 2. The probability that there are less than 3 occurrences is
a. .0659 b. .0948 c. .1016 d. .1239
The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.
Given,
The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two time periods of an equal length. It is known that the mean number of occurrences in ten minutes is 5.3.
1) A Poisson distribution characterizes the random variable x that is provided.
2) Having 8 occurrences in 10 minutes is likely based on the following formula:
P(X = 8) = (e^(-5.3) * 5.3^8) / 8! = 0.0241 (rounded to four decimal places) (rounded to four decimal places)
Consequently,
(a) 0.0241 is the correct response.
3) The likelihood that there are fewer than 3 occurrences is as follows:
P(X 3) = P(X = 0), P(X = 1), and P(X = 2) = (e(-5.3) * 5.30), (e(-5.3) * 5.31), and (e(-5.3) * 5.32), respectively, / 0!, / 1/1, and / 2/ respectively, / 2! = 0.0659 (rounded to four decimal places)
Accordingly,
(a) 0.0659 is the correct response.
The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.
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The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.
Given,
The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two time periods of equal length. It is known that the mean number of occurrences in ten minutes is 5.3.
1) A Poisson distribution characterizes the random variable x that is provided.
2) Having 8 occurrences in 10 minutes is likely based on the following formula:
P(X = 8) = ([tex]e^(-5.3)[/tex] * [tex]5.3^8[/tex]) / 8! = 0.0241 (rounded to four decimal places) (rounded to four decimal places)
Consequently,
(a) 0.0241 is the correct response.
3) The likelihood that there are fewer than 3 occurrences is as follows:
P(X 3) = P(X = 0), P(X = 1), and
P(X = 2) = ([tex]e(-5.3)[/tex]* 5.30), ([tex]e(-5.3)[/tex]* 5.31), and ([tex]e(-5.3)[/tex] * 5.32),
respectively, / 0!, / 1/1, and / 2/ respectively, / 2! = 0.0659 (rounded to four decimal places)
Accordingly,
(a) 0.0659 is the correct response.
The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.
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A new battery’s voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries will be independently selected and tested until two acceptable ones have been found. Suppose that 90% of all batteries have acceptable voltages. Let Y denote the number of batteries that must be tested.
a. What is p(2), that isP ( Y = 2), ?
b. What is p(3)? [Hint: There are two different outcomes that result inY = 3 .]
c. To have Y=5, what must be true of the fifth battery selected? List the four outcomes for which Y= 5 and then determine p(5).
d. Use the pattern in your answers for parts (a)–(c) to obtain a general formula for p(y).
a) Probability, P(y = 2) = P(AA) is equals to the 0.81.
b) Probability, P(y = 3), is equals to the 0.162.
c) For P(y=5), 5ᵗʰ battery must be an A. four outcome for which Y= 5 , probability is equals to the 0.00324.
d) General formula for p(y) is P(y)= (y-1)(0.1)⁽ʸ⁻²⁾(0.9)².
A new battery’s voltage may be acceptable (A) or unacceptable (U). Assume that 90% of all batteries have acceptable voltages. So, probability of acceptance = 0.90 and
probability of unacceptance = 1 - 0.9 = 0.1
Let the number of batteries that must be tested be "Y". A particular flashlight requires two batteries, that is batteries will be independently selected.
a) For P(y = 2), both the batteries must be acceptable. Hence probability, P(y = 2)
= P(AA) = 0.90× 0.90 = 0.81
b)For P(y = 3 ) = P(AUA) + P(UAA)
=0.9× 0.1×0.9 + 0.1× 0.9× 0.9 = 0.162
C) For any(Y = n), nᵗʰ batterry should be acceptable, as search for two acceptable batteries will complete once second acceptable battery gets selected. Hence for P(y=5), 5ᵗʰ battery must be an A. four outcome for which Y
= 5 are (AUUUA) ,(UAUUA),(UUAUA),(UUUAA)
P(y=5) = P(AUUUA) + P(UAUUA) + P(UUAUA) + P(UUUAA)
= 4× 0.9² × 0.1³
= 0.00324
d) From above probabilities we conclude, the general formula for p(y) is p(y) =(y- 1)(0.1)⁽ʸ⁻²⁾(0.9)².
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Help will be greatly appreciated :}
Answer:
4.5 mm
Step-by-step explanation:
You want the length of AB in similar triangles ACE and BCD, given BD is parallel to AE, and AC=36 mm, ED=9 mm, EC=72 mm.
ProportionCorresponding segments in the two triangles are proportional, so we have ...
AB/ED = AC/EC
AB/(9 mm) = (36 mm)/(72 mm) = 1/2
AB = (9 mm)(1/2) = 4.5 mm . . . . . multiply by 9 mm
The length of segment AB is 4.5 mm.
F and H are sets of real numbers defined as follows.
F ∩ H = [4, 9)
FUH= ∞
What is the interval?Generally, To find the intersection of F and H, denoted as F ∩ H, we need to identify the values that are in both sets F and H.
From the definitions of F and H, we have:
F = {v | v=4 or v>4}
H = {v | v<9}
The values that are in both F and H are those that satisfy both conditions, i.e., v=4 or v>4 and v<9. This is equivalent to just the condition v=4, since any value that satisfies v<−4 will also satisfy v>4 and v<9.
Therefore, F ∩ H = {v | 4}.
In interval notation, we can write this as:
F ∩ H = [4, 9)
To find the union of F and H, denoted as F ∪ H, we need to identify all the values that are in either set F or set H or both.
From the definitions of F and H, we have:
F = {v | v=4 or v>4}
H = {v | v<9}
this denotes
F= {v | v=4> x > ∞}
H = {v |-∞ <v<9}
FUH= ∞
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Please help me with this math problem!
1) The model is R = 1820 - 19t
2) After six years R = 1706 barrels
3) There would be non more oil in 96 years.
How do you model a linear equation?We know that an equation can be used as a model. This implies that we can be able to use an equation to show how a variable is changing over time and that is what the problem that we have here is all about.
If at the current time we have 1820 billion barrels Then they decrease by 19 barrels per year and t is the number of years then the model is;
R = 1820 - 19t
After six years we would have;
R = 1820 - (19 * 6)
R = 1706 barrels
When there are no further barrels;
0 = 1820 - 19t
1820 = 19t
t = 1820/19
t = 96 years.
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Find the slope of the line that passes through each par of points(4,-4)(2-4)
the shop has 1100 ounces of cranberry juice and 680 ounces of passion fruit juice.if the juices are used to make crazy cranberry smoothies, which juice will run out first?how much of the other juice will be left over?
Answer: The passion fruit will run out first and 420 ounces left.
Step-by-step explanation: If you put the same amount of cranberry and passion fruit in each juice than they will be using an equal amount each time. We know that there are more ounces of cranberry than passion fruit which already tells us that there will be more cranberry when the passion fruit runs out. In order to find how much is left we can simply subtract the amount of cranberry and passion fruit.
1100-680=420
Emily parents put $1,500 in her bank account for college tuition. At an interest rate of 8.25% compounded annually. What will be the total balance after 2 years?
(A) $1,314.08
(B) $2,385.72
(C) $3,273.50
(D) $1,757.71
Answer:(A) 1.314.08
Step-by-step explanation:
Inflation
I will give brainliest and ratings if you get this correct
The first derivative of the composite function r(x) = √[x + √(x + √x)] is equal to r' (x) = [1 / [2 · √[x + √(x + √x)]]] · [1 + [1 / [2 · √(x + √x)]] · [1 + 1 / (2 · √x)]].
How to determine the first order derivative of a composite function
In this problem we find the case of a composite function of the form:
f ° g ° h (x) = f [g [h (x)]]
Whose first derivative must be found by means of the following differentiation rules:
Chain rule
d [f [u (x)]] / dx = (df / du) · (du / dx)
Derivative of a square root
d (√x) / dx = 1 / (2√x)
And the first order derivative of the function r(x) = √[x + √(x + √x)] is:
r' (x) = [1 / [2 · √[x + √(x + √x)]]] · [1 + [1 / [2 · √(x + √x)]] · [1 + 1 / (2 · √x)]]
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y=2x-1 (2,3) (5,11)(-1,-3) determine which of the following points work for the given information algebraically
home realty claims that it can sell a detached, residential house faster than any other realty company. with the aim of examining home's claim, you sample customers who sold a detached, residential house through home and record the selling times (in days) of the houses. your data are summarized in the following histogram.
The proportion of selling times in the sample that are greater than or equal to 10 days is 0.85.
As per the data given:
HOME Realty claims that it can sell a detached, residential house faster than any other realty company.
With the aim of examining HOME's claim, you sample 20 customers who sold a detached.
The data has been summarized in the histogram(attached at the end of solution)
Here we have to determine the proportion of selling times in the sample that are greater than or equal to 10 days.
Selling Time Frequency
0 - 10 3
10 - 20 4
20 - 30 7
30 - 40 3
40 - 50 3
Frequencies for which selling times are 10 or greater
= 4 + 7 + 3 + 3
= 17
Total frequencies = 3 + 4 + 7 + 3 + 3
= 20
Proportion for which selling times are 10 or greater
= [tex]$\frac{17}{20}[/tex]
= 0.85
Therefore the proportion is 0.85.
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HOME Realty claims that it can sell a detached, residential house faster than any other realty company. With the aim of examining HOME's claim, you sample 20 customers who sold a detached, residential house through HOME and record the selling times (in days) of the houses. Your data are summarized in the following histogram(attached at the end of solution):
Based on the histogram, find the proportion of selling times in the sample that are greater than or equal to 10 days. Write your answer as a decimal, and do not round your answer.
1.
Solve for x. Round to one
decimal place (nearest
tenth).
X
48°
1
15
The length of the hypotenuse or the value of 'x' is 60.
What are trigonometric ratios in terms of a right-angle triangle?We know a right-angled triangle has three sides they are -: Hypotenuse,
Opposite and Adjacent.
We can remember SOH CAH TOA which is,
sin = opposite/hypotenuse, cos = adjacent/hypotenuse and
tan = opposite/adjacent.
From the given diagram respect to the reference angle of 37°,
Hypotenuse is 'x' and adjacent is 48.
And we know, cos = adjacent/hypotenuse.
Therefore, cos37° = 48/x.
x = 48/0.8.
x = 60.
Q. A right-angle triangle is shown, Find the value of x.
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Rose drew a regression line for this paired data set. Her line passed through (1, 2) and (3, 5). What is the equation of Rose's regression line? Responses yˆ=6.8x+1.6 y hat equals 6.8 x plus 1.6 yˆ=1.5x+0.5 y hat equals 1.5 x plus 0.5 yˆ=0.66x−0.33 y hat equals 0.66 x plus 0.33 yˆ=2x+1 y hat equals 2 x plus 1
Answer: The equation of a line in the form of y = mx + b can be found using the slope-intercept form, where m is the slope of the line and b is the y-intercept. To find the slope, you can use the two points on the line: (1, 2) and (3, 5). The slope is found by the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the two points.
m = (5 - 2) / (3 - 1) = 3 / 2 = 1.5
The y-intercept can be found by plugging in one of the points and the slope into the equation and solving for b. Let's use the point (1, 2).
2 = 1.5 * 1 + b
b = 2 - 1.5 = 0.5
So the equation of the regression line is:
y = 1.5x + 0.5
Therefore, the correct answer is: yˆ = 1.5x + 0.5
Step-by-step explanation:
Find an equation for the surface with all points which are equidistant of (−1,0,0)and the plane x=1. Draw the surface.
The equation for the surface with all points which are equidistant of (−1,0,0)and the plane x=1 is x² - 2x + y² + z² = 2.
In mathematics, an equation is a statement that asserts the equality of two expressions. An equation typically consists of two sides separated by an equal sign (=).
To start with, let's consider the given information. We have been given that all points on the surface are equidistant from (-1,0,0) and the plane x=1. This means that the distance between any point on the surface and (-1,0,0) is the same as the distance between that point and the plane x=1.
We can use the formula for the distance between a point and a plane to derive an equation for the surface. The formula for the distance between a point (x1, y1, z1) and a plane Ax + By + Cz + D = 0 is given by:
distance = |Ax1 + By1 + Cz1 + D| / √(A² + B² + C²)
In our case, the plane is x=1, which can be written as x - 1 = 0. So, A=1, B=0, C=0, and D=-1. The point (-1,0,0) can be substituted as x1=-1, y1=0, and z1=0.
We can simplify the distance formula to:
distance = |x-1|
Now, since all points on the surface are equidistant from (-1,0,0) and x=1, we can set up the following equation:
|x-1| = √( (x+1)² + y² + z² )
Squaring both sides and simplifying, we get:
(x-1)² = x² + 2x + 1 + y² + z²
Rearranging and simplifying, we get the final equation for the surface:
x² - 2x + y² + z² = 2
This is the equation of the surface that contains all points that are equidistant from (-1,0,0) and x=1.
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b) Would this circle work for the pony's path? Why or why not? Explain your
answer by using the equation, the location of the stake, and the length of the
rope to support your reasoning. (2 points)
The equation for the pony's path is -
(x - 8)² + (y - 8)² = 128.
What is the equation of a circle?The general equation for a circle is -
(x - h)² + (y - k)² = r²
where (h, k) is the center and (r) is the radius.
Given is that the pony is staked at the coordinate point (8, 8).
The general equation for a circle is -
(x - h)² + (y - k)² = r²
We can write the equation for the pony's path as -
(x - 8)² + (y - 8)² = 128
Therefore, the equation for the pony's path is -
(x - 8)² + (y - 8)² = 128.
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Gravetter/Wallnau/Forzano, Essentials - Chapter 3 - End-of-chapter question 24 A sample yielded the following scores: 2, 3, 4, 4,5,5,5,6,6,7 n = 10 Assume that the scores are measurements of a discrete variable and find the median Median = ___Assume that the scores are measurements of a continuous variable and find the median by locating the precise midpoint of the distribution (Use two decimal places.) Median = ___
Answer:
Step-by-step explanation:
24. Gravetter/Wallnau/Forzano, Essentials - Chapter 3 - End-of-chapter question 24
A sample yielded the following scores:
2, 3, 4, 4, 5, 5, 5, 6, 6, 7
n= 10
Assume that the scores are measurements of a discrete variable and find the median.
Median =5Correct
Points:
1 / 1
Median = 5
To find the median for a set of numbers with an even quantity the two middle numbers are added together and divided by 2.
n=102+(n = 102+1)2
= 5th score + 6th score2
= 5 + 52
= 102=5
Assume that the scores are measurements of a continuous variable and find the median by locating the precise midpoint of the distribution. (Use two decimal places.)
Median = 4.83Correct
The median for the discrete variable is 5 and for continuous variable is 5.
What is median?Median in statistics is the middle value of a list of data when arranged in order. It is a measure of central tendency that separates the data into two halves: the upper half and the lower half.
Given that: scores = 2, 3, 4, 4, 5, 5, 5, 6, 6, 7
a) The scores are in ascending order; then the median which is the middle number will be:
median = (5th term + 6 term)/2
= (5+5)/2
= 10/2
= 5
b) Use the cumulative percentage table ;
X frequency cumulative frequency cumulative percentage
2 1 1 10%
3 1 2 20%
4 2 4 40%
5 3 7 70%
6 2 9 90%
7 1 10 100%
Fraction = the no. required to reach 50%/ no. in that interval
= 1/3
Since we have a total of 4 boxes when we reach the value of 4.5
The median of the continuous variable = 4.5 + (1/3)
= 4.833
≈ 5
Hence, the median for the discrete variable is 5 and for continuous variable is 5.
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i need with this question
The height of the wall is 14 feet
What are similar triangles?Similar triangles are triangles that have the same shape, but their sizes may vary. All equilateral triangles, squares of any side lengths are examples of similar objects. In other words, if two triangles are similar, then their corresponding angles are congruent and corresponding sides are in equal proportion.
Therefore ;
TH/ JS = TV/VS
4/JS = 6/21
21× 4 = 6 JS
JS = 21× 4/6
JS = 84/6
JS = 14 feet
therefore the height of the wall is 14 feet
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11.9 A cube has edge lengths that are each 100 centimeters. What is the volume of
the cube?
A
B
1 cubic centimeter
1 cubic meter
100 cubic centimeters
100 cubic meters
The volume of the cube is 1 cubic meter.
Option B is the correct answer.
What is a cube?It is a polygon having six faces.
The volume of a cube is side³.
Example:
The volume of a cube of 3 cm in length is 27 cm³.
We have,
Side length = 100 cm
Now,
Volume.
= Side³
= 100³
= 1000000 cm³ _____(1)
Now,
1 m = 100 cm
1 m³ = 1000000 cm³ _____(2)
From (1) and (2),
Volume = 1 cubic meter.
Thus,
The volume of the cube is 1 cubic meter.
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Mr. Phil T. Rich had a boat load of money. He decided to leave it to his family. But wanted to make sure his goldfish, Bubbles was taken care of too. He decided to leave 1/2 of his estate to his wife 30,000$ to his daughter, half of what was left over for his butler, Niles half of what was left to bubbles (his goldfish). He realized 8,000$ remaking, so he donated it to charity. What was the original value of his estate? GO STEP BY STEP. WORK BACKWARDS
If Mr. Phil T. Rich had a boat load of money. The original value of his estate is $152,000.
How to find the original value?Let's call the original value of Mr. Phil T. Rich's estate "x".
After he gave 1/2 of the estate to his wife, he was left with x/2.
After he gave 30,000 to his daughter, he was left with x/2 - 30,000.
After he gave half of what was left to his butler Niles, he was left with (x/2 - 30,000)/2.
After he gave half of what was left to Bubbles, he was left with (x/2 - 30,000)/4.
Finally, after he donated the 8,000 to charity, he was left with (x/2 - 30,000)/4 - 8,000.
We know that the final amount after all these transactions was $0, so we can set up an equation to solve for x:
0 = (x/2 - 30,000$)/4 - 8,000
Multiplying both sides by 4 to isolate x/2:
0 * 4 = (x/2 - 30,000) - 8,000 * 4
Expanding the right side:
0 = (x/2 - 30,000) - 32,000
Adding 30,000 and 32,000 to both sides:
30,000+ 32,000 = (x/2)
Dividing both sides by 1/2:
62,000 * 2 = x
Multiplying both sides by 2:
62,000* 2 * 2 = x * 2
Expanding the left side:
62,000* 4 = x
Dividing both sides by 4:
62,000 * 4 / 4 = x / 4
Expanding the left side:
$62,000 = x
Therefore the original value of Mr. Phil T. Rich's estate was $62,000.
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Question Help Error Analysis On a math test a student, Jake, has to identify all the coefficients and constants of the expression 9m +4+y. Jake says that 9 is a coefficient and 4 is a constant. Identify all the coefficients and constants of the expression. What error might Jake have made? The coefficient(s) of the expression is/are. (Use a comma to separate answers as needed.)
The error which Jake made is likely to be a result of confusion or oversight in identifying the variable y as having a coefficient of 1.
What error might Jake have made?The coefficients of an expression are the numerical factors that multiply the variables, while the constants are the numerical values that do not contain any variables.
In the expression 9m + 4 + y, the coefficients are 9 and 1 (which is the implied coefficient for y since there is no visible numerical factor), and the constant is 4.
So Jake correctly identified 9 as a coefficient and 4 as a constant, but missed the implied coefficient of 1 for the variable y. The error that Jake made is likely to be a result of confusion or oversight in identifying the variable y as having a coefficient of 1, rather than assuming it is a constant or neglecting it entirely.
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pls help I GIVE BRAINIEST.In the graph above, determine where the image for vertices A, B, C, and D will be located after Quadrilateral ABCD is reflected over the y = 0 mirror line and then dilated using a scale factor of 2.5.
Step-by-step explanation:
reflect the shape, will give you:
A = (-1,0)
B= (3, -5)
C= (-6, -7)
D= (-4, -1)
If a point A(x, y) is dilated by a factor P, the new point would be at
A'(Px, Py).
A = -1/2.5 = -0.4 0/2.5= 0
= ( - 0.4, 0)
B = 3/2.5 = 1.2 -5/2.5 = -2
= (1.2, -2)
C = -6/2.5= -2.4 -7/2.5 = -2.8
= ( -2,4, -2.8)
D = -4/2.5 = -1.6. -1/2.5 = -0.4
= ( -1.6, -0.4)
You're Welcome!
Answer:
Step-by-step explanation:
( -1.6, -0.4)
Lesson 4.1: Steps in a Simulation Study.) Which steps are regarded asessential for a successful simulation study? (There may be more than onecorrect answer.)
a. Problem formulation
b. Model validation
c. Model verification
d. Experimental design
e. Output analysis
The steps regarded essential for a successful simulation study are:
a. Problem formulation
b. Model validation
c. Model verification
d. Experimental design
e. Output analysis
To give any solution to the problem the very first step necessary is to understand the problem . Now through the observations of the process the problem is defined and formulated .
Keeping in mind the real life solutions and necessities a model is developed . Now the further process of verification and validation is carried out . In verification we make sure that the model works as we thought through animation whereas validation makes sure that the model reflects reality .
Experimental design multiple similar models are compared with minute changes and the performance are compared to find the best suited model.
Finally the results of the study are discussed in output analysis through written reports , documents or presentation and the best product is chosen .
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Please help I dont understand this thank you
Answer:17x25 i think
Step-by-step explanation: