Consider a 25-mm-diameter and 15-m-long smooth tube that is maintained at a constant surface temperature. Fluids enter the tube at 50°C with a mass flow rate of 0.01 kg/s. Determine the tube surface temperatures necessary to heat water, engine oil, and liquid mercury to the desired outlet temperature of 150°C

Answers

Answer 1

Answer: ⚠this is not my answer it from hamzaahmeds

Water: h = 35.53 W/m².k

Engine oil: h = 18.84 W/m².k

Mercury: h = 1.19 W/m².k

Explanation:

Assuming the steady state, one-dimensional heat flow, it is clear that the added to the fluid by tube heat will be equal to the heat transfer through convection outside the tube.

Therefore,

mCΔT = hAΔT

mC = hA

h = mC/A

where,

h = convection coefficient

m = mass flow rate =  0.01 kg/s

C = specific heat capacity of fluid

A = surface area of tube = 2πrL = 2π(0.0125 m)(15 m) = 1.178 m²

FOR WATER:

C = 4186 J/Kg.k

Therefore,

h = (0.01 kg/s)(4186 J/Kg.k)/(1.178 m²)

h = 35.53 W/m².k

FOR ENGINE OIL:

C = 2220 J/Kg.k

Therefore,

h = (0.01 kg/s)(2220 J/Kg.k)/(1.178 m²)

h = 18.84 W/m².k

FOR LIQUID MERCURY:

C = 140 J/Kg.k

Therefore,

h = (0.01 kg/s)(140 J/Kg.k)/(1.178 m²)

h = 1.19 W/m².k


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The Web and Digital Communications pathway is broken down into four main categories of technology. Which category BEST describes Aaden's use of digital communication technology in the following example?

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D marketing because he’s advertising ski equipment to buy

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Answer:

i dob't know

Explanation:

People act like they care.

So, I act like I believe them.

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Answer:

Elasticity

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Cloud computing comprises of three (3) service models and these are;

1. Platform as a Service (PaaS).

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Answer:

Mark me please as brainliest

Explanation:

A length of pipe will weigh the most when O A. part dimensions are such that the pipe is in the MMC. O B. the OD and ID are at the minimum allowable limit. OC. the OD and ID are at the maximum allowable limit. OD.part dimensions are such that the pipe is in the LMC

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Part dimensions are such that the pipe is in the MMC.

Explanation:

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Dilute countercurrent immiscible extraction
A feed of 100.0 kg/min of a 1.2 wt % mixture of acetic acid in water is to be extracted with 1-butanol at 1 atm pressure and 26.7°C, we desire an outlet concentration of 0.1 wt % acetic acid in the exiting water. We have available solvent stream 1 that is 44.0 kg/min of pure 1-butanol and solvent stream 2 that is 30.0 kg/min of 1-butanol that contains 0.4 wt % acetic acid. Devise a scheme to do this separation, find the outlet flow rate and concentration of the exiting 1-butanol phase, and find the number of equilibrium contacts needed.
In Example we assumed that we were going to use all of the solvent available. There are other alternatives. Determine if the following alternatives are capable of producing outlet water of the desired acetic acid concentration.
a. Use only the pure solvent at the bottom of the extractor.
b. Mix all of the pure and all of the impure solvent together and use them at the bottom of the column.
c. Mix all of the pure and part of the impure solvent together and use them at the bottom of the column.

Answers

Sorry I don’t know the answer I just need to answer some questions before I am allowed to get my work done

what is the relationship between the voltages of the output and adjust pins of LM1117 when in normal operation

Answers

Based on the engineering analysis, the relationship between the voltages of the output and adjust pins of LM1117 when in normal operation is "the LM1117 adjustable version establishes a 1.25V reference voltage, (VREF) between the output and the adjust terminal."

The LM1117 generally has a 1.2V at 800mA of load current.

The LM1117 is known to be a progression of low dropout linear voltage regulators. It is adjustable and be assigned between the output voltage of 1.25 to 13.8 V using just two external resistors.

Hence, in this case, it is concluded that the correct answer is "the LM1117 adjustable version establishes a 1.25V reference voltage, (VREF), between the output and the adjust terminal.

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Tech A says that the stoichiometric ratio is 14.7 gallons of air to 1 gallon of fuel. Tech B says it is 14.7 lb of air to 1 lb of fuel. Who is correct

Answers

The person that is correct as regards statement made about stoichiometric ratio is; Tech B

In air-fuel mixture, when there is a mix air and fuel in the ideal amounts to make an engine to run efficiently,the ideal ratio of air to fuel is known Stoichiometric ratio.

This stoichiometric ratio is the comparison between the weight of the air relative to the weight of the fuel that it has been mixed with.

Now, weight is in lb and as such, tech B is correct because his ratio is 14.7lb to 1 lb.

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Answer:

Tech B

Explanation:

I took the test and got it right

How much work, in Newtons, is required to lift a 20.4-kg (45lb) plate from the ground to a stand that is 1.50 meters up?

ASAP PLS

Answers

Answer:

Explanation:

Work, U, is equal to the force times the distance:

U = F · r

Force needed to lift the weight, is equal to the weight: F = W = m · g

so:

U = m · g · r

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locate the centroid of the shaded area between the two curves​

Answers

9514 1404 393

Answer:

  (x, y) = (5.76, 1 5/7)

Explanation:

The location of the centroid in the x-direction is the ratio of the first moment of area about the y-axis to the total area. Similarly, the y-coordinate of the centroid is the first moment of area about the x-axis, divided by the area.

For the moment about the y-axis, we can define a differential of area as ...

  dA = (y2 -y1)dx

where y2 = √(x/k2) and y1 = k1·x^3

The distance of that area from the y-axis is simply x.

So, the x-coordinate of the centroid is ...

  [tex]\displaystyle c_x=\frac{a_x}{a}=\frac{\int{x\cdot dA}}{\int{dA}}\\\\a_x=\int_0^{12}{x(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{5k_2^{1/2}}\cdot12^{5/2}-\frac{k_1}{5}12^5\\\\a=\int_0^{12}{(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{3k_2^{1/2}}\cdot12^{3/2}-\frac{k_1}{4}12^4\\[/tex]

For k1 = 4/12^3 and k2=12/4^2, these evaluate to ...

  [tex]a_x=115.2\\a=20\\c_x=5.76[/tex]

The y-coordinate of the centroid requires we find the distance of the differential of area from the x-axis. We can use (y2 +y1)/2 for that purpose. Then the y-coordinate is ...

  [tex]\displaystyle c_y=\frac{a_y}{a}\\\\a_y=\int_0^{12}{(\frac{y_2+y_1}{2}(y_2-y_1))}\,dx=\frac{1}{2}\int_0^{12}{(\frac{x}{k_2}-(k_1x^3)^2)}\,dx\\\\a_y=\frac{12^2}{4k_2}-\frac{k_1^212^7}{14}=\frac{240}{7}\\\\c_y=\frac{12}{7}\approx1.7143[/tex]

The centroid of the shaded area is ...

  (x, y) = (5.76, 1 5/7)

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Answers

Answer:

Liquids have less force of attraction between molecules than solids and more than gases; gases have a very weak force of attraction between the molecules which is the least amongst the three states of matter.

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To find the quotient of 8 divided by 1/3, multiply 8 by?
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DONT GIVE ME LINKS ITS STUIPID JUST SAY A B C OR D

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Because of the skin depth effect, the current at high frequency tends to flow at very low depth from radius. Then at high frequency the effective cross section of the wire is narrower than at DC.

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ai lm dc bài tập môn cơ học vật liệu ko ạ

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Answer:

What's that

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Please brainlest me

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Answer:

In  case whereby you  work for rev and check your work email on your mobile phone and You have decided to resign your job and take a position with a different company. Regarding rdm on your mobile phone, you should B. Take your phone to IT Services, and they will wipe it clean.

What is expected to do when leaving the company?

It is expected from you to return anything that belong to the company before leaving the company, but in the case whereby there is still a rdm on your mobile phone, then you can work to the IT services so they can wipe it away.

Find out more on IT Services

at brainly.com/question/21210308

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Missing options:

A. Turn your phone to IT Services

B. Take your phone to IT Services, and they will wipe it clean

C. Download RDM to your personal computer

D. Call IT Services for support, and they will assist

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The most common use for encoders is to measure angular or linear distance, but encoders can also be used to perform speed or velocity measurements. In other words, as the encoder rotates faster, the pulse frequency increases at the same rate

true/False
1.
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Answers

Answer:true

Explanation:

It is true that around 50 percent of all sales of farm commodities are from dairy products.

What are dairy products?

Dairy products or milk products, also known as lacticinia, are milk-based foods.

Cows, water buffalo, nanny goats, and ewes are the most common dairy animals. Dairy products include common grocery store foods such as yogurt, cheese, and butter in the Western world.

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Dairy products account for roughly half of all farm commodity sales.

Thus, the given statement is true.

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Answer:

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Answers

Answer:

Presents the relevant parameters to be kept in mind when using the following types of motors: 1. AC induction motor 2. BLDC motor 3. Synchronous motorn

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