The product from your reaction has a sharp melting point, indicating that it is either meso-hydrobenzoin or a racemic mixture of the (1R, 2R) and (1S, 2S) enantiomers. Why is it not possible that your product is either the (1R, 2R) or the (1S, 2S) pure enantiomer?
A sharp melting point is an indication of high molecular homogeneity, meaning the molecules in the sample have a high degree of similarity in their shape and structure.
The product of the reaction has a sharp melting point, indicating that it is either meso-hydrobenzoin or a racemic mixture of the (1R, 2R) and (1S, 2S) enantiomers.
However, it is not possible for the product to be either the (1R, 2R) or the (1S, 2S) pure enantiomer. This is because enantiomers have opposite stereochemistry and cannot be distinguished from each other based on physical properties such as melting point, boiling point, or solubility. Therefore, if the product has a sharp melting point, it must be either meso-hydrobenzoin or a racemic mixture of enantiomers, but it cannot be a pure enantiomer.
In conclusion, a sharp melting point alone is not enough to determine the stereochemistry of the product. Further analysis, such as chiral chromatography or circular dichroism spectroscopy, would be required to determine the absolute configuration of the enantiomers.
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Choose the words that correctly complete the paragraph. Susan ran the 400-m sprint at the track meet, and her final time was 65 s. She reported that her velocity in the race was 6.15 m/s. Susan’s statement was an inaccurate report of velocity because she mentioned only Choose... . She did not include Choose... , which is also a part of velocity.
Susan ran the 400-m sprint at the track meet, and her final time was 65 s. She reported that her velocity in the race was 6.15 m/s. Susan’s statement was an inaccurate because she mentioned only speed.
What is velocity?Velocity is a vector measure of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.
For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below. Susan’s statement was inaccurate because she mentioned only speed.
Therefore, susan’s statement was inaccurate because she mentioned only speed.
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the energy lost when of water cools from 86.4 ∘C to 4.8 ∘C
The amount of energy needed to raise a material's heat content by precisely 1 degree per gram is known as specific heat. If we assume the mass of water 1gm the energy lost is -341.088.
What is specific heat capacity?
Heat always transfers from the warmer to the cooler material until both materials reach the same temperature when two materials, each at an initial different temperature, are placed in contact with one another.
Q = mC(T(final) - T(initial)
Q = 1 X 4.8 (4.8 - 86.4) = -341.088
The heat obtained by the initially colder substance must equal the heat lost by the initially warmer material, according to the law of conservation of energy.
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Which of the following locations is the most likely source of young sand with little quartz, that is dark in color, and that does not bubble when acid is added to it? (a) Great Salt Lake in Utah (b) a North American beach with pounding waves (c) a volcanic island (d) a beach near a coral reef
The location that is the most likely source of young sand with little quartz, that is dark in color, and that does not bubble when acid is added to it is a volcanic island (C)
The presence of either black basalt or green olivine gives volcanic sand its characteristically dark appearance. Volcanic sand is relatively young and, with the exception of obsidian particles, contains very little or any quartz at all. The majority of volcanic oceanic sands can be found on volcanic islands. Sand grains are created when dissolved mineral matter, primarily calcium carbonate, undergoes the process of precipitation in water, this results in the formation of precipitate sand.
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Which of the following measurements are not equivalent?
a. 84 cm=8.4 mm
b. 24 dL= 2.4 L
c. 183 L= 0.183 kL
d. 25 mg= 0.025 g
e. 150 msec= 0.150 sec
The non-equivalent measurements are:
B. 24 dL ≠ 2.4 L
C. 183 L ≠ 0.183 kL
E. 150 msec ≠ 0.150 sec
What is non-equivalent measurements?
Non-equivalent measurements are measurements that have different values despite being expressed in the same units. For example, 23 dL and 2.3 L are both expressed in liters, but they are not equivalent because 23 dL is a larger unit and 23 L is a smaller unit.
Non-equivalent measurements can occur when different units or prefixes are used, such as milli, kilo, deci, etc. It is important to ensure that the correct units and prefixes are used to avoid incorrect results in calculations and measurements.
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Glycolysis takes place in the ________ and produces________, which in the presence of O2 then enters the ________.
cytosol; pyruvate; mitochondrion to complete cellular respiration
Glycolysis takes place in the cytosol and produces pyruvate. In the presence of oxygen, pyruvate then enters the mitochondrion to complete cellular respiration.
Glycolysis is the first step of cellular respiration, a process by which cells convert glucose (a simple sugar) into energy. It takes place in the cytosol, which is the liquid portion of the cytoplasm found inside a cell. During glycolysis, glucose is broken down into two molecules of pyruvate, producing a small amount of ATP (adenosine triphosphate) in the process.
Pyruvate, the end product of glycolysis, is then transported into the mitochondria, where it can undergo further processing in the presence of oxygen. The process that takes place in the mitochondria is called the citric acid cycle, which produces a large amount of ATP through oxidative phosphorylation. This ATP is then used by cells for energy to carry out various cellular functions.
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For the compounds H2Te, H2Se, H2S, H2O the general trend is that boiling point increases as the _______ increases. This trend is observed because electrons are held more _____ in H2Te when compared to the other molecules resulting in a stronger induced ________.
For the compounds H2Te, H2Se, H2S, H2O the general trend is that boiling point increases as the molecular weight increases. This trend is observed because electrons are held more tightly in H2Te when compared to the other molecules resulting in a stronger induced dipole interaction.
The boiling point of a substance is related to its molecular weight, as well as its molecular structure. In the case of H2Te, H2Se, H2S, and H2O, the boiling point increases as the molecular weight increases.
This trend is because the electrons in H2Te are held more tightly compared to the other molecules, leading to a stronger induced dipole-dipole interaction between the molecules. This stronger interaction requires more energy to overcome, resulting in a higher boiling point.
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how many moles are in 75g of Al2(Co3)3? please show your work.
The number of moles in 75 g of [tex]Al_2(CO_3)_3[/tex] would be 0.32 moles.
Number of moles in a mass of a substanceThe number of moles present in a mass of a substance is the ratio of the mass and the molar mass of the substance.
Mathematically, mole = mass/molar mass
Molar mass of [tex]Al_2(CO_3)_3[/tex] = 233.99 g/mol
Mass of [tex]Al_2(CO_3)_3[/tex] = 75 grams
Number of moles in 75 g of [tex]Al_2(CO_3)_3[/tex] = 75/233.99 = 0.32 mol
In other words, the number of moles in 75 g of [tex]Al_2(CO_3)_3[/tex] is 0.32 moles.
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Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:
2KI (aq) + Cl2 (g) --> 2KCl (aq) + I2 (g)
a. How many moles of I2 are produced? ________ moles I2 (3 sig figs)
b. How many moles of KI were used? _________ moles KI (3 sig figs)
c. How many grams of KI were used? _________ grams KI (3 sig figs)
20 points
As per the balanced reaction two mole of KI gives one mole of I2. 8.5 L at STP equal to 0.37 moles. 0.74 moles of KI or 122.8 grams are required to produce 0.37 moles of I₂.
What is STP condition ?The standard condition of temperature (298 K ) and pressure (1 atm) is called STP. At STP, one mole of every substance contains 22.4 L volume.
Hence, number of moles of 8.5 L of iodine gas at STP is = 8.5 L/22.4 L/mol = 0.37 moles.
As per the balanced reaction, 2 moles of KI is used to produce one mole of I2. Then, number of moles of KI used to give 0.37 moles of iodine is:
0.37 × 2 = 0.74 moles of KI.
Molar mass of KI = 166 g/mol
mass of 0.74 moles = 166 × 0.74 = 122.8 g.
Therefore, 122.8 grams of KI were used for 8.5 L of iodine gas.
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which of the following is not a safety concern associated with the lab to determine the molar volume of a gas?
The following which is not a safety concern associated with the lab to determine the molar volume of a gas include the following below:
Keep valves closed when not in use.Do not store flammable gases near oxidizers or combustible materials.What are Flammable gases?Flammable gases are explosive when they are mixed with air or oxygen in the right proportions.
This is therefore the reason why it is best to store them in a safe environment so that a fire incident doesn't occur. The valves should also be tightly closed so nas to prevent the escape of gases intyo the atmposphere.
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A flask containing 6.50 mL of a liquid weighs 159.9 g with the liquid in the flask and 152 g when empty. Calculate the density of the liquid in g/mL to the correct number of significant digits
The density of the liquid in g/mL to the correct number of significant digits is 1.21g/ml.
Mass of flask in the liquid= 159.9 g
Mass of empty flask = 152 g
Mass of liquid= 159.9 g- 152 g = 7.9g
Density = Mass/volume = 7.9g/6.50ml= 1.21g/ml
Density (volumetric mass density or particular mass) is the substance's mass in line with a unit of extent. The symbol most usually used for density is ρ (the decreased case Greek letter rho), despite the fact that the Latin letter D also can be used. Mathematically, density is defined as mass divided by extent.
The density of fabric varies with temperature and stress. this variation is usually small for solids and drinks but a whole lot greater for gases. increasing the strain on an object decreases the quantity of the object and therefore will increase its density. increasing the temperature of a substance (with some exceptions) decreases its density via increasing its quantity. In most materials, heating the bottom of fluid outcomes in convection of the warmth from the bottom to the pinnacle, due to the decrease in the density of the heated fluid, which reasons it to rise relative to denser unheated material.
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Given the information below, determine the crystal structure. Consider only FCC and BCC structures as possibilities.Lattice parameter a = 0.4997 nmPowder x-ray: λ = 0.1542 nm2θ (°) Constructive Interference 31.0, 36.0, 51.8, 61.6, 64.8
The crystal structure of the material is FCC.
The powder x-ray diffraction pattern and the lattice parameter are used to determine the crystal structure of a material.
The presence of constructive interference at 2θ values of 31.0°, 36.0°, 51.8°, 61.6°, and 64.8° suggests that the material has a face-centered cubic (FCC) crystal structure. This is because the FCC crystal structure is characterized by diffraction peaks at 2θ values of roughly 43.5°, 46.6°, 48.3°, 50.0°, and 51.7°.
In an FCC crystal structure, the lattice points are located at the center of the faces of the unit cell. The lattice parameter "a" represents the length of one side of the unit cell.
On the other hand, a body-centered cubic (BCC) crystal structure is characterized by diffraction peaks at 2θ values of roughly 48.7°, 51.4°, and 53.1°.
Given the lattice parameter and the powder x-ray diffraction pattern, it can be concluded that the crystal structure of the material is FCC.
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how many grams are in 1.53 moles of Li2Co3
To find the number of grams in 1.53 moles of Li2Co3, we need to multiply the moles by the molar mass of Li2Co3. The molar mass of Li2Co3 is calculated as follows:
Li2Co3:
Li = 2 × 6.939 g/mol = 13.878 g/mol
Co = 3 × 58.933 g/mol = 176.799 g/mol
Total: 13.878 g/mol + 176.799 g/mol = 190.677 g/mol
So, 1.53 moles × 190.677 g/mol = 294.455 g of Li2Co3.
What is molar mass?The term "molar mass" describes the weight in atomic mass units of one mole of a substance (AMU). It is a way to quantify how much of a substance has exactly as many atoms, molecules, or ions as there are in 12 grams of pure carbon-12. The atomic masses of all the atoms in a substance's molecular formula are added up to determine its molar mass. Conversions between mass, moles, and concentration are possible. For many chemical calculations, such as calculating reaction yields or figuring out the concentration of a solution, the ability to convert a mass to moles and vice versa depends on knowing a substance's molar mass.
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use the data to determine the heat of vaporization of hexane. Express your answer to three significant figures in kilojoules per mole.
Heat of vaporization of hexane is 32.3 KJ/mol.
Clausius-Clapeyron equation allows us to estimate the vapor pressure of A substance at any temperature It also provides an easy way to estimate The heat of phase transition from the vapor pressures measured at two Temperatures.
lnP2/P1=ΔHvapR(1/T1−1/T2)
Where,
P1 = vapor pressures at temperature T1
P2 = vapor pressures at temperature T2
ΔHvap = Heat of Vaporization
R = Gas constant (8.3145 J mol-1 K-1)
Using T1 =293 k and T2=303k
In(120/186) = ΔHvap/8.31 (1/303-1/293)
ΔHvap= In(120/186) x 8.31 x 303x293/(293-303)
(-0.438) x (8.31) x (303x293)/-10
32313.6 J/mol
32.3 KJ/mol
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As they enter chemistry class, students often think about the dangers of chemical exposure in the lab and everyday life. In this assignment, you will search for websites for information on chemical exposure in a scientific way. For the sake of this discussion, purposely smoking or taking illicit drugs is not chemical exposure. The articles linked below will get you started. Read these articles and then find at least two more sources of information. From this, you will make a post two to three paragraphs long. Make sure to cite all sources of information in your post. Answer the following questions in your post: Look at the top ten causes of death in the US as reported by the CDC. Which of the top ten causes of death are behavior related or can be mitigated through changed behavior? Are there good statistics available on the number of deaths in the US caused by inadvertent chemical exposure? Based on the research, how many deaths does chemical exposure cause compared to the top causes of death in the US? Provide an information source to support your answer.
Overall, chemical exposure is a relatively small contributor to the leading causes of death in the US. Compared to the top causes of death in the US, chemical exposure causes far fewer deaths.
What is the chemical exposure?Chemical exposure is the contact of a person or organism to a chemical substance that can cause health effects. It occurs when a person is exposed to a hazardous chemical agent, either through inhalation, skin contact, or ingestion. This can include exposure to chemicals from air pollution, industrial chemicals, or occupational exposures.
According to the Centers for Disease Control and Prevention (CDC), the top ten causes of death in the US are heart disease, cancer, chronic lower respiratory diseases, unintentional injuries, stroke, Alzheimer's disease, diabetes, influenza and pneumonia, kidney disease.
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To isolate a single variable when rearranging equations, move all other variables to the other side of the equation by using the opposite function on them and remembering to perform that operation on both sides of the equation.
Make sure the rearrangement has the target variable in the numerator, not the denominator.
Yes, that is a good way to isolate a single variable in an equation. You can use the opposite operation (addition or subtraction) to move all the other variables to one side of the equation, and then use division or multiplication to get the target variable by itself.
What are variables?Variable is a symbol in algebra that represents an unknown numerical value in an equation. It is typically a letter. The real numbers x and y, the complex numbers z, the time, the radius, and the arc length are all common variables.
Just make sure to perform the same operation on both sides of the equation to maintain the equality. Also, it is helpful to have the target variable in the numerator and not in the denominator as this makes it easier to solve for the variable.
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A chemist ran the reaction and obtained 5.10 g of ethyl butyrate. What was the percent yield?
A chemist ran the reaction and obtained 5.10 g of ethyl butyrate. Therefore, 58.766 % is the percent yield.
What is ethyl butyrate?An ester is ethyl butyrate, known colloquially as ethyl butanoate or butyric ether. Propylene glycol, propanone, as well as kerosene are all soluble in it. It is extensively employed as artificial flavoring mimicking orange juice and is consequently utilized in practically all orange juices produced, even those labelled as "fresh" or "concentrated".
It is also employed in alcoholic drinks, as a solvents in fragrance items, and as a cellulose plasticizer.
C[tex]_4[/tex]H[tex]_8[/tex]O[tex]_2[/tex] + C[tex]_2[/tex]H[tex]_5[/tex]OH [tex]\rightarrow[/tex]C[tex]_6[/tex]H[tex]_{12}[/tex]O[tex]_2[/tex] + H[tex]_2[/tex]O
Molecular mass of butanoic acid=88 g/mole
Molecular mass of ethyl butyrate=116 g/mole
(7.10 g) / (88 g/mole) = 0.0806 moles of butanoic acid
0.0806 moles × 116 g/mole = 9.359 g of ethyl butyrate
% yield = (actual yield /theoretical yield) * 100
% yield = (5.50 g/9.359 g) * 100
% yield = 58.766 %
Therefore, 58.766 % is the percent yield.
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Jones's test, also known as the chromic acid test, will shows the presence of? what is a positive Jones's test will appears? what is a negative Jones's test will appears?
Jones's test, also known as the chromic acid test, is used to determine the presence of aldehydes in a sample.
A positive Jones's test results in the formation of a blue or greenish-blue precipitate, indicating the presence of an aldehyde. On the other hand, a negative Jones's test results in no visible precipitation, indicating the absence of an aldehyde.
The Jones's test works by adding a small amount of chromic acid (CrO3) to a reaction mixture containing the aldehyde. If an aldehyde is present, it reacts with the chromic acid to form a complex that has a characteristic blue or greenish-blue color. This color change indicates a positive Jones's test. If no aldehyde is present, there will be no reaction and no color change, resulting in a negative Jones's test.
Jones's test is a useful tool for the identification of aldehydes in organic chemistry and is widely used in the laboratory as a qualitative test for the presence of aldehydes. However, it is important to note that the test is not quantitative and should not be used to determine the amount of aldehyde in a sample.
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Rotate the molecular structure. This can be done by clicking and dragging with your mouse, track pad, or touchscreen, depending on your device. Locate the adenine nitrogenous base and determine its location within the molecular structure. Which best describes its location? Choose one: A. not as part of a base pair; at the 3' within one polynucleotide strand B. not as part of a base pair; at the 5' end in one polynucleotide strand C. as part of a base pair; at the 3' end in one polynucleotide strand D. as part of a base pair; at the 5' end in one polynucleotide strand
C. As part of a base pair; at the 3' end in one polynucleotide strand describes its location.
Which functional group is found at the 3 ends of a polynucleotide?
The functional group that is at the end of the 3' end of the DNA is a hydroxyl group. The numbers on the carbon atoms in the pentose sugar of the nucleotides corresponding to the 3' end and the 5' end in DNA. At the 3' end, there is a hydroxyl group, made of an oxygen and hydrogen atom.
What is a nitrogenous base in DNA?
Nitrogenous base: A molecule that contains nitrogen and has the chemical properties of a base. The nitrogenous bases in DNA are adenine (A), guanine (G), thymine (T), and cytosine (C). The nitrogenous bases in RNA are the same, with one exception: adenine (A), guanine (G), uracil (U), and cytosine (C).
Why is adenine called a base?
Adenine and guanine have a fused-ring skeletal structure derived of purine, hence they are called purine bases. The purine nitrogenous bases are characterized by their single amino group (−NH 2), at the C6 carbon in adenine and C2 in guanine.
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compare the structures of ethylene, acetylene, and benzene. these compounds produce only one signal in its 1h nmr spectrum. arrange these signals in order of decreasing chemical shift
Ethylene, acetylene, and benzene are all unsaturated hydrocarbons with different molecular structures. In terms of decreasing chemical shift, the order would be: benzene > ethylene > acetylene.
Comparision of the structures of ethylene, acetylene, and benzene:Ethylene (C2H4) has a double bond between the two carbon atoms, with each carbon atom bonded to two hydrogen atoms. The molecule is linear. Acetylene (C2H2) has a triple bond between the two carbon atoms, with each carbon atom bonded to one hydrogen atom. The molecule is linear.Benzene (C6H6) has a cyclic structure, with each carbon atom bonded to two other carbon atoms and one hydrogen atom. The molecule is planar.The signal for benzene appears at the highest chemical shift due to the deshielding effect of the delocalized pi electrons in the aromatic ring. Ethylene comes next because the double bond causes some deshielding of the hydrogens, but not as much as in benzene. Acetylene has the lowest chemical shift because the triple bond causes less deshielding of the hydrogens compared to the double bond in ethylene.
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When a light bulb is rated at 60 W, it means that
A.each second, the bulb converts 60 J of electrical energy to heat and light.
B.the bulb loses 60 W of potential energy each second.
C.current is traveling at 60 m/s through the filament.
D.the bulb uses 60 J of power when it is lit.
The molecules of a gas are much farther apart than molecules in a solid or liquid.
True
False
The first question has an answer of A: the bulb turns 60 J of electrical energy into heat and light every second. It is True that a gas's molecules are significantly more spaced away from one another than those of a solid or liquid.
A heated filament or a gas discharge generate light in a light bulb, an electric device. The light of the bulb is produced by a wire filament that is heated by an electric current. Thomas Edison created the first incandescent light bulb that was commercially viable in 1879, and by creating a useful source of artificial light, it completely changed the way we live today. With the introduction of compact fluorescent bulbs, LED lights, and other technologies, light bulbs have developed over time to become more energy-efficient. Light bulbs today are a necessary part of contemporary life, providing illumination for private residences, commercial buildings, and public areas.
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For a certain ideal gas, the temperature is
increased from 200 K to 602 K allowing pres-
sure, which is initially 1 atm, to vary while
the volume and number of moles of gas are
held constant. What is the new pressure?
Answer in units of atm.
Answer:
3.01 atmospheres
Step by step explanation:
The pressure of an ideal gas is directly proportional to its temperature and directly inversely proportional to its volume. Since the volume and number of moles are held constant, the pressure will be directly proportional to the temperature.
So, using the ideal gas law, P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the new pressure and temperature, respectively.
Substituting the initial values, P1 = 1 atm and T1 = 200 K, and the new temperature T2 = 602 K, we can solve for P2:
P2 = (P1 x T2) / T1 = (1 atm x 602 K) / 200 K = 3.01 atm
Therefore, the new pressure is 3.01 atm.
In atomic theory, new substances are formed when the atoms of other substances are rearranged. In this kind of change, the total number of atoms is conserved.
An example of this is shown in the diagram below. There are six atoms both before and after the arrow.
Which statement below is also true of the rearrangement of atoms?
According to law of conservation of mass, the number of atoms of reactants and products is equal.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.
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a multistep reaction can only occur as fast as its slowest step. therefore, it is the rate law of the slow step that determines the rate law for the overall reaction.
The rate law for the overall reaction is, [tex]k[A][B][/tex].
Rate law, It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
As we are given the mechanism for the reaction :
Step 1 : [tex]A+B \rightarrow AB[/tex] (slow)
Step 2 : [tex]A+AB \rightarrow A_2B[/tex] (fast)
Overall reaction : [tex]2A+B \rightarrow A_2B[/tex]
The rate law expression for overall reaction should be in terms of A and B.
As we know that the slow step is the rate determining step. So,
The slow step reaction is, [tex]A+B \rightarrow AB[/tex].
The expression of rate law for this reaction will be, [tex]k[A][B][/tex]
Hence, the rate law for the overall reaction is [tex]k[A][B][/tex].
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Serious injuries can occur when students attempt to force the pipet bulb onto the top of the pipet. The blue bulbs we use in lab are not meant to attach to the pipet, they simply rest on the top. Which of the following items will help you be more successful when working with a pipet? O Keep the tip of the pipet submerged when filling O The more aggressive you are with the pipet bulb, the quicker you will get out of lab O It is best to fill the pipet to a point just above the calibration line, then adjust the volume by slowly releasing liquid. O Liquid should fully fill the pipet bulb O Gently place the pipet bulb on the pipet
It is best to fill the pipet to a point just above the calibration line, then adjust the volume by slowly releasing liquid, which will help to be more successful when working with a pipet.
To use a pipet successfully, it is important to ensure that the tip of the pipet is kept submerged when filling, as this will help to prevent air from getting into the pipet. Once the pipet is filled, it is best to fill it to a point just above the calibration line, then adjust the volume by slowly releasing liquid. This will help to reduce the chances of overfilling or spilling the liquid.
It is also important to be gentle when placing the pipet bulb on the pipet, as aggressive movements can cause the bulb to come loose or even break, resulting in injury. Additionally, the blue bulbs used in the lab are not meant to be attached to the pipet, but rather simply rest on top of it.
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If you were to expose cells that are undergoing aerobic respiration to a radioactive oxygen isotope in the form of O2, which of the following molecules would you expect to be radiolabeled?
You would expect to see radiolabeling in molecule CO2. Option D is correct.
Radiolabeled compounds: In a radiolabeled compound, atoms or groups of atoms of a molecule were substituted by similar or different radioactive atoms or the groups of atoms, or certain cations are chelated with some carrier molecules. Labeling can be carried out with isotopes of the same element or of different elements.
Aerobic cellular respiration takes place in the mitochondria, where oxygen is used as the final electron acceptor in the electron transport chain. This process results in the production of ATP, carbon dioxide (CO2), and water as the byproducts. The radioactive oxygen isotope in the form of O2 would be incorporated into the CO2 molecules produced during respiration. Therefore, radiolabeling would be seen in the CO2 produced during cellular respiration.
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--The given question is incomplete, the complete question is
"If you were to expose cells that are undergoing aerobic cellular respiration to a radioactive oxygen isotope in the form of O2, which of the following molecules would you expect to be radiolabeled? A) pyruvate B) water C) NADH D) CO2"--
Estimate the atmospheric pressure at the summit of Mount Everest, 8,848m above sea level. Assume an average temperature of 0 degrees celcius.
The atmospheric pressure at the summit of Mount Everest is 253 mmHg.
M(air) = 0.21x2xM(O) + 0.79x2xM(N) = 29x10^(-3)kg/mole
Assuming that air can be treated as an ideal gas (pV=nRT) express the density of air (ρ) as a function of the other state variables and the molar mass M.
p = pressure
V = volume
R = ideal gas constant
T = temperature
n = the amount of gas, measured in moles
ρ = mass(kg)/V, n=m/M where m is mass measured in kilograms and M is molar mass with units kg/mole. A mole is 6.022x10^23 atoms/molecules.
The ideal gas law rewritten: p(m/ρ)=(m/M)T
Rearranging the variables to write the density in terms of all the other variables we have:
ρ = (M/(RT))p
The hydrostatic equation Δp=ρgΔy describes the change in pressure with depth for an incompressible fluid. This assumption is not valid for air in the atmosphere. Air in the lower parts of the atmosphere is “compressed” by the air above it. However, for an infinitesimally thin layer of air the equation holds.
g = gravitational acceleration (on Earth=9.8 m/s^2)
Δy = a difference in vertical distance
Δp = a difference in pressure between the interval in distance
We do not want the change in pressure, we want to write an equation for pressure, p, as a function of the vertical distance y.
For very small/infinitesimal intervals the theory of calculus tells us that we can write Δy and Δp and dy and dp. If we add up all the intervals over the entire height of the atmosphere we can see how the two variables depend on each other at different heights and derive the equation that will tell us how pressure depends on a specific point in the height. We add up the infinitesimal intervals by doing an integral.
dp/dy=-ρg
For large distances air is compressible and therefore density is not constant. Density can be written in terms of pressure as found in part b
dp/dy = -(Mg/RT)p→ ∫dp/p = -(Mg/RT)∫dy
ln(p1/p2) = -(Mg/RT)(y2-y1)
p2 = p1exp (-(Mg/RT)(y2-y1))
We have assumed that temperature and g are constant at all heights, not realistic. However, the answer is a good approximation compared to more accurate values and the equation demonstrates the general trend.
Use the equation you derived where you are trying to find p2 where y2 is 8848 meters, p1 is the pressure at sea level 1 atmosphere, M is 29x10^(-3)kg/mole, T is the average air temperature in 273 Kelvin, and y1 is zero.
p2 = 0.33289 atm or 253 mmHg
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consider the most stable chair conformation for the following compounds. (a) describe the orientation of groups a and b. methyl group a will be axial and methyl group b will be equat
The most stable chair conformation for a cyclohexane molecule has all substituents in an axial position or all substituents in an equatorial position.
cyclohexane are those that extend above or below the plane of the ring, while equatorial substituents are those that are in the plane of the ring. In general, bulky substituents are more stable in an equatorial position as they can minimize interactions with other substituents on the ring. In the case of the molecule described, the methyl group "a" is axial and the methyl group "b" is equatorial. This arrangement is favored because the methyl groups are small and do not cause significant steric hindrance in either axial or equatorial positions.
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is the chemical energy of a unit of graphite is lower than the chemical energy of a unit of diamond.
Yes, the chemical energy of a unit of graphite is lower than the chemical energy of a unit of diamond.
This is because the arrangement of carbon atoms in diamond has a higher cohesive energy per unit volume than that of graphite, making it more energetically stable. Diamonds also have stronger carbon-carbon bonds than graphite, which further contributes to their higher energy.
Graphite is composed of layers of carbon atoms arranged in a hexagonal lattice, while diamond is composed of carbon atoms arranged in a tetrahedral lattice structure. The arrangement of atoms in diamond increases the strength of the carbon-carbon bonds, resulting in a higher cohesive energy per unit volume than graphite.
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Complete combustion of 1 mole of acetone (C3H6O) liberates 1790 kJ of energy as shown in the reaction below: C3HsO (€) + 402 (g) --> 3C02 (g) + 3H20 (€) AHSrxn = -1790 kJlmol Using the information provided (AHSrxn = -1790 kJlmol) together with the data below; Calculate the enthalpy of formation (AH?f) of acetone (C3H6O): AH?f, CO2: -393.5 kJlmol, AH?f, H2O: -285.83 kJlmol -679 kJlmol 2038 kJlmol +1019 kJlmol -248 kJlmol +1790 kJlmol
When burning one mole of acetone, 1790 kJ is released. The enthalpy of formation of acetone, C₃H₆O is equal to -247.9 kJ/mol.
The combustion reaction of a substance means the burning of a substance in the presence of oxygen to form carbon dioxide and water. For example, the combustion of carbon proceeds as follows: C + O₂ --> CO₂. We have the molar enthalpy of combustion of acetone,
C₃H₆O(l) + 4O₂(g)→ 3CO₂(g) + 3H₂O(l)
Where, ∆H꜀= −1790 kJ. We need to calculate the enthalpy of formation of acetone. Now, the standard enthalpy of formation, *ΔHf(O₂)= 0 kJ/mol, *ΔHf(CO₂)
=−393.4 kJ/mol, *ΔHf(H₂O)= -285.8 kJ/mol. We determine the enthalpy of formation of acetone as follows:
∆H꜀ = 3×ΔHf (CO₂) + 3×ΔHf (H₂O) – 1× ∆Hf(C₃H₆O) – 4× ΔHf (O₂)
=> −1790 kJ = 3 mol × −393.4 kJ/mol + 3 mol × -285.8 kJ/mol - 1 mol × ∆Hf(C₃H₆O) - 4 mol × 0
=> −1790 kJ = - 1180.5 kJ - 857.4 kJ - ∆Hf(C₃H₆O)
=> 1 mol×∆Hf(C₃H₆O)= -1180.5 kJ - 857.4 kJ + 1790 kJ
=> ∆Hf(C₃H₆O) = - 247.9 kJ/mol
Therefore, the required enthalpy value for acetone is -247.9 kJ/mol.
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