Complete the following statement: (In Boyle's law), the volume of a gas ________ when the ________ decreases.

Answer:

a) NO,   YES that cable 3 should be placed to the left of cable 1

b)  a = 8cm   the current is UP

Explanation:

The force between two cables that carries a current is given through the magnetic field created between them, it has the expression

        F₁ = μ₀ I₁ I₂ / 2π a l

where I₁ and I₂ are the current in each wire, at the separation between them and l the length of wire 1 on which the force is applied.

The direction of the force this given is given by the vector product between the current in wire 1 and the field created by 2, but we can summarize it:

* if the two currents are in the same direction the force is attractive

* if the two currents are contrary, the force is repulsive

With these relationships we can examine the different situations presented

a) Between cable 1 and 3 the force is zero. If cable 1 the current is upward in cable 3 it must be downward, so that the force is repulsive

Between wire 2 and 3. If wire 2 the current is downward, in wire 3 the current must be upward, for a repulsive force.

We see that in the two conditions the current in cable 3 has different directions, which is impossible, therefore this situation cannot occur

the answer is NO

The only way this is possible is that cable 3 should be placed to the left of cable 1

Answer YES

b) and c) Your question is unclear, I interpret that you want the position of cable 3 so that the force is zero on cable 3

we will assume that the current in cables 1 and 2 is ascending and that in cable 3 is descending

We write Newton's second law at the point of cable 3, the acceleration is zero

                    F13 - F23 = 0

                    F13 = F23

Let's calculate the forces

                  F₁₃ = μ₀ I₁ I₃ /2π a    l

                  F₂₃ = μ₀ I₂ I₃ /2π (d + a)    l

we substitute and simplify

                 I₁ / a = I₂ / (d + a)

where we have assumed that the length of all cables is the same

We solve to find

                I₁ (d + a) = I₂ a

                a (I₂ - I₁) = I₁ d₁

                a = I₁ / (I₂ - I₁) d

let's calculate

                a = 1.20 / (4.2 -1.2) 20

                a = 8cm

to the left of wire 1 and the direction is the current is UP

so that it is an attractive force between 1 and 3 and a repulsive force between 2 and 3

Answer:

    E  = 0.2276 10⁻¹⁹ J ,  λ = 8.73374 10⁻⁴ cm

Explanation:

Bohr's atomic model can be used for hydrogen-type atoms, that is, they have a single electron in their last orbit, this is the case of doubly ionized Titanium.

It is much easier to work in EV units.

          r = a₀ / Z n²

          E = - 13.606 (Z² / n²)

where ao is the Bohr radius, which is the ground state orbital of hydrogen a₀ = 0.0529 nm, Z is the atomic number of titanium, and n is an integer that represents the different states of the system.

a) Let's look for the energy, for this we look for the integer numbers of these orbits

r = 13.25 A = 1.325 nm

          r = a₀ / Z   n²

         n = √(Z r / a₀)

the atomic number of titanium is Z = 22

         n = √ (22  1.325 / 0.0529)

         n = 23

r = 2.12 A = 0.212 nm

         n = √ (22  0.212 / 0.0529)

         n = 9

now we can calculate the energy of the transition

         E = 13.606 (1 / [tex]n_{f}^2[/tex] - 1 / [tex]x_{o}^2[/tex])

         E = 13.606 (1/9² - 1/23²)

         E = 13.6060 (0.010455)

         E = 0.1423 eV

Let's reduce to J

         E = 0.1423 eV (1.6 10⁻¹⁹ J / 1eV) = 0.2276 10⁻¹⁹ J

To find the wavelength of the transition, use the Planck relation

         E = h f

the relationship of frequency and speed of light

         c = λ f

  we substitute

         E = h c /λ

         λ = hc / E

        λ = 6.626 10⁻³⁴ 3 10⁸ / 0.2276 10⁻¹⁹

        λ = 8.73374 10⁻⁶ m

       λ = 8.73374 10⁻⁴ cm

Answer:

liter is the SI unit

idk how to explain it

The answer is:

The formula  to calculate average velocity is a) V (average ) = x(f) - x(i) /t(f) - t(i)

Average velocity is a vector quantity . It is defied as the change in displacement  over a time interval .

Average velocity can be calculated as

Average velocity  = change in displacement / change in time travel

correct answer is a) V (average ) = x(f) - x(i) /t(f) - t(i)

where

x(f) = final position

x(i) = initial position

t(f) = final time

t(i) = initial time

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Answer:

Explanation:

Given data

initial speed ,u= o m/s

final speed v= 25 m/s

time t= 3.11 seconds

Applying the first equation of motion we have

[tex]v= u+at\\\\v-u=at\\\\a= \frac{v-u}{t} \\\\a= \frac{25-0}{6.22} \\\\a= 4.02 m/s^2[/tex]

Also applying [tex]v=u+at[/tex] with initial speed set at 0, we can also find speed at 3.11 seconds

[tex]v=0+4.02*3.11\\v= 12.50 m/s[/tex]

Hence the average speed in the first 3.11 seconds is

[tex]\bar v= \frac{v}{2} \\\\\bar v=\frac{ 12.50}{2} \\\\ \bar v= 6.25 m/s[/tex]

Applying the expression [tex]\bar v=\bar u+at[/tex]  we can now fing the average speed in the second 3.11 second

[tex]\bar v=\bar u+at\\\\ \bar v=6.25+4.02*3.11\\\\ \bar v=18.75m/s[/tex]

Explanation:

The distance between them is 200 km − 20 km = 180 km.

The relative velocity is 30 km/h − (-48 km/h) = 78 km/h.

The time it takes is 180 km / (78 km/h) = 2.31 hours, or 2 hrs 18 min.

Therefore, the trains meet at 9:30 AM.

Answer:

7a. CO2 => carbon dioxide

b. H2O => water

8. The mass of carbon dioxide, CO2 plus the mass of water, H2O is equal to the mass of sugar, C6H12O6 plus the mass of oxygen, O2.

Explanation:

7. Selecting the names of the reactant.

6CO2 + 6H2O —> C6H12O6 + 6O2

From the above equation, the reactants are: CO2 and H2O

Thus, the names of the reactants are:

a. CO2 => carbon dioxide

b. H2O => water

8. Determination of masses of the CO2, H2O, C6H12O6 and O2 from the balanced equation. This can be obtained as follow:

6CO2 + 6H2O —> C6H12O6 + 6O2

Molar mass of CO2 = 12 + (2x16) = 44 g/mol

Mass of CO2 from the balanced equation = 6 x 44 = 264 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 6 x 18 = 108 g

Molar mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180 g/mol

Mass of C6H12O6 from the balanced equation = 1 x 180 = 180 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 6 x 32 = 192 g

Summary:

Mass of Reactant:

CO2 = 264 g

H2O = 108 g

Total = 372 g

Mass of Product:

C6H12O6 = 180 g

O2 = 192 g

Total = 372 g

From the above calculations,

The mass of carbon dioxide, CO2 plus the mass of water, H2O is equal to the mass of sugar, C6H12O6 plus the mass of oxygen, O2.

Answer:

1.260

Explanation:

103.5 has 4 significant figures.

102.24 has 5 significant figures.

We will need to round the answer to the least number of significant figures available (in this case, 4).

103.5 − 102.24 = 1.26 = 1.260

The difference between 103.5 and 102.24 is equal to 1.3 in the correct number of significant figures.

Significant figures can be utilized to produce numbers that can be written in the form of figures. We can determine the number of significant figures by simply counting the values starting from the first non-zero digit placed on the left.

We can calculate the number of significant digits by counting from the first non-zero figure placed on the left. The significant digits of a given number are those significant digits, which convey the meaning with respect to its accuracy.

In the case of division or multiplication or subtraction and addition, the number of significant figures must be the same as the value with the fewest significant figures.

We have to find the difference between 103.5 and 102.24:

103.5 - 102.24 = 1.26 = 1.3

The number 103.5 has one significant figure after the decimal. Therefore, the answer will be equal to 1.3.

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Answer:

Explanation:

The change in the trucks kinetic energy is same as the net work done by the truck in covering the said distance

Given data

mass of truck m= 1890 kg

initial velocity of truck u1= 34 km/h

final velocity v1= 62 km/h

applying the kinetic energy formula we have

[tex]K.E= \frac{1}{2}mv^2[/tex]

K.E(initial)

[tex]K.E(initial)= \frac{1}{2}*1890*34^2\\\\ K.E(initial)= \frac{1}{2}*1890*1156\\\\ K.E(initial)= \frac{1}{2}*2184840\\\\ K.E(initial)= 1092420J\\\\\ K.E(initial)= 1092.4kJ[/tex]

K.E(final)

[tex]K.E(initial)= \frac{1}{2}*1890*62^2\\\\ K.E(initial)= \frac{1}{2}*1890*3844\\\\ K.E(initial)= \frac{1}{2}*7265160\\\\ K.E(initial)= 3632580J\\\\\ K.E(initial)= 3632.58kJ[/tex]

The change in K.E= K.E(final)- K.E(initial) = 3632.58-1092.4= 2540.18 kJ

the change in the truck's K.E is 2540.18 kJ

Time = distance/speed

Time = (175 m) / (320 m/s)

Time = 0.547 second

Answer:

4f   E₄ = 0.85 eV,    L₄ = 4.22 10⁻³⁴ ,  

5d          E₅ = 0.544 eV ,    L5 = 5.28 10⁻³⁴

Explanation:

Let's use the Bohr model, stable the energy of the hydrogen atom

              E = -13.606 / n2

where Eo = 13.606 eV is the energy of the ground states.

a) the energy of each atom

level 4f

In this nomenclature enumeration is the number n

               E = -13606 / 42

               E₄ = 0.85 eV

level 5d

                E₅ = -13.606 / 5 2

                E₅ = 0.544 eV

b) The angular momentum is given in Boh's model

                     L = n h / 2pi

let's calculate

level 4f             L₄ = 4 6.63 10⁻³⁴-34 / 2 pi

                        L₄ = 4.22 10⁻³⁴

level 4d

                       L5 = 5 6.63 10-⁻³⁴ / 2pi

                       L5 = 5.28 10⁻³⁴

c) The hydrogen atom in state n = 5 has lower energy than the other state

d) Atom 1 has less angular momentum than atom 2

Explanation:

Given that,

Size of object, h = 0.066 m

Object distance from the lens, u = 0.210 m (negative)

Focal length of the converging lens, f = 0.14 m

If v is the image distance from the lens, we can find it using lens formula as follows :

[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{0.14 }+\dfrac{1}{(-0.21)}\\\\v=0.42\ m[/tex]

(a) Magnification,

[tex]m=\dfrac{v}{u}\\\\m=\dfrac{0.42}{(-0.21)}\\\\m=-2[/tex]

(b) Magnification, [tex]m=\dfrac{h'}{h}[/tex]

h' is image height

[tex]-2=\dfrac{h'}{0.066}\\\\h'=-2\times 0.066\\\\h'=-0.132\ m[/tex]

Hence, this is the required solution.

Answer:

The value is   [tex]t =  14.129 \  minutes[/tex]    

Explanation:

From the question we are told that

  The distance of planet Tatoone is  [tex]d =  1.7 \ AU  =  1.7 *1.496* 10^{11}=2.543*10^{11} \ m[/tex]

   The  speed of light is  [tex]c =  3.0*10^{8} \  m/  s[/tex]

Generally the time taken is mathematically represented as

     [tex]t =  \frac{d}{c}[/tex]

=> [tex]t =  \frac{2.543*10^{11}}{3.0*10^{8} }[/tex]

=>    [tex]t =  847.7 \  s[/tex]

Now converting to minutes

       [tex]t =  \frac{847.7}{60}[/tex]

   =>     [tex]t =  14.129 \  minutes[/tex]    

Answer:

Explanation:

Knowledge of vectors is important because many quantities used in physics are vectors. If you try to add together vector quantities without taking into account their direction you'll get results that are incorrect.

Some of the key vector quantities in physics: force, displacement, velocity, and acceleration.

An example of the importance of vector addition could be the following:

Two cars are involved in a collision. At the time of the collision car A was travelling at 40 mph, car B was travelling at 60 mph. Until I tell you in which directions the cars were travelling you don't know how serious the collision was.

The cars could have been travelling in the same direction, in which case car B crashed into the back of car A, and the relative velocity between them was 20 mph. Or the cars could have been travelling in opposite directions, in which case it was a head on collision with a relative velocity between the cars of 100 mph!

Vector is defined as a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another

Vector is defined as a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another

Knowledge of vectors is important because many quantities used in physics are vectors. If you try to add together vector quantities without taking into account their direction you'll get results that are incorrect.

Some of the key vector quantities in physics: force, displacement, velocity, and acceleration.

An example of the importance of vector addition could be the following:

Two cars are involved in a collision. At the time of the collision car A was travelling at 40 mph, car B was travelling at 60 mph. Until I tell you in which directions the cars were travelling you don't know how serious the collision was.

The cars could have been travelling in the same direction, in which case car B crashed into the back of car A, and the relative velocity between them was 20 mph. Or the cars could have been travelling in opposite directions, in which case it was a head on collision with a relative velocity between the cars of 100 mph!

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Answer:

a)  R = ρ₀ L /π(r_b² - R_a²) , b)  ρ₀ = V / I    π (r_b² - R_a²) / L

Explanation:

a) The resistance of a material is given by

          R = ρ l / A

where ρ is the resistivity, l is the length and A is the area

the length is l = L and the resistivity is ρ = ρ₀

the area is the area of ​​the cylindrical shell

           A = π r_b² - π r_a²

           A = π (r_b² - r_a²)

we substitute

         R = ρ₀ L /π(r_b² - R_a²)

b) The potential difference is related to current and resistance by ohm's law

         V = i R

we subsist the expression of resistance

          V = I ρ₀ L /π (r_b² - R_a²)

           ρ₀ = V / I    π (r_b² - R_a²) / L

Answer:

Sports drink will show increase in specific gravity

While

Water will decrease in SG

Explanation:

This is because the relative density of urine will increase because of presence of ions in the sport drink unlike in water that has very little ions

Answer:

It will be more than deta t

Explanation:

Because

deta t' = န deta t

But န= 1/√ (1 - v²/c²

So the observers in all the initial frames will be more than deta t

Answer:

v = 2.61 m/s

Explanation:

Given that,

Length of a rectangular trough, l = 1.6 m

Breadth of a rectangular trough, b = 0.6 m

Depth of a rectangular trough, h = 0.35 m

We need to find the speed with which water emerge from the hole. It is a concept of efflux. The velocity of efflux is given by :

[tex]v=\sqrt{2gh}\\\\v=\sqrt{2\times 9.8\times 0.35}\\\\v=2.61\ m/s[/tex]

So, water will emerge from the hole with a speed of 2.61 m/s.

Answer:

Far point = is the farthest point where you can see the object

near point= is the nearest distance where you can see the object.

Explanation:

The far point of human eye is upto infinity & the near point is 25cm.

Answer:

a. Goslo

Explanation:

given data

Speedo travels = 40 light year

Speedo travels relative to the Earth = 0.997

solution

Goslo will measure here proper time and this time is expres as

time T =  Speedo travels ÷ Speedo travels relative to the Earth   ..........................1

put here value

time T = [tex]\frac{40}{0.997}[/tex]

time T = 40.1 year

so Goslo will measure the proper time

Answer:

9.91*10^-7 m

4.955*10^-6 m

Explanation:

Given that

v = 0.4 m/s

d = 1 m

L = 10 m

h = 6.62*10^-34 Js

m(neutron) = 1.67*10^-27 kg

To find the debroglie wavelength of the neutron, we use the formula

λ = h/mv

Now, we plug in the values we have listed.

λ = 6.62*10^-34 / (1.67*10^-27 * 0.4)

λ = 6.62*10^-34 / 6.68*10^-28

λ = 9.91*10^-7 m

b)

y1 = L (m + ½) λ/d, where m = 0

y1 = L (0 + ½) λ/d

y1 = L (½) λ/d

y1 = L/2 * λ/d or

y1 = Lλ/2d

now, we substitute the values for each of them, we have

y1 = (10 * 9.91*10^-7) / (2 * 1)

y1 = 9.91*10^-6 / 2

y1 = 4.955*10^-6 m

c) no, we can not say the neuron passed through one slit

Answer:

v = 1.26 m/s

Explanation:

Given that,

Length of the conducting rods = 34 cm = 0.34 m

Magnetic field, B = 1.75 T

Induced emf is 0.75 V

we need to find the speed with which it slides. Due to the motion of the rod an emf is induced in it which is given by :

[tex]\epsilon=Blv[/tex]

v is the speed of rod

[tex]v=\dfrac{\epsilon}{Bl}\\\\v=\dfrac{0.75}{1.75\times 0.34}\\\\v=1.26\ m/s[/tex]

So, the speed of the sliding rod is 1.26 m/s.

Answer:

2.5 m/s^2

Explanation:

Acceleration = (Final Velocity - Initial Velocity) / TIme

Acceleration = 12 - 2 / 4

=> Acceleration = 10 /4

=> Accelration = 5/2

=> Acceleration = 2.5 m/s^2

So, Acceleration is 2.5 m/s^2

The acceleration of the bicycle which is the change in the velocity of the bike with change in time will be 2.5m/s in the Westward direction

We define acceleration thus :

Therefore, the acceleration of the bike will be 2.5m/s² in the West direction

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Answer:

Newlands law of octave was the first logically basis on the atomic weight. Demerits of dobereiner's triads system: - This system fails because it does not hold good for all the elements discovered till date time. It is limited to only few elements.

Explanation:

Answer:

-384.22N

Explanation:

From Coulomb's law;

F= Kq1q2/r^2

Where;

K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2

q1 and q2 = magnitudes of the both charges

r= distance of separation

F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2

F= -495.65 × 10^-3/ 1.29 × 10^-3

F= -384.22N

Answer:

hypothesis

Explanation:

I think this is right I dont remember

Answer:

D. Top is emission; bottom absorption.

Explanation:

Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."

From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.

Answer:

The distance is [tex]z = 0.008 \ m[/tex]

Explanation:

From the question we are told that

   The  focal length is  [tex]f = 50 \ mm = 50*10^{-3} \ m[/tex]

Generally the lens equation is mathematically represented as  

     [tex]\frac{1}{u} + \frac{1}{v} = \frac{1}{f}[/tex]

At  image  distance  u =  1.5 m

       [tex]\frac{1}{1.5} + \frac{1}{v} = \frac{1}{50 *10^{-3}}[/tex]

=>      [tex]\frac{1}{50 *10^{-3}} - \frac{1}{1.5} = \frac{1}{v}[/tex]

=>[tex]v = 0.052 \ m[/tex]

At  image  distance  [tex]u = 30\ cm = 0.30 \ m[/tex]

        [tex]\frac{1}{0.3} + \frac{1}{v_1} = \frac{1}{50 *10^{-3}}[/tex]

=>     [tex]\frac{1}{50 *10^{-3}} - \frac{1}{0.30 } = \frac{1}{v_1}[/tex]

=>    [tex]v_1 = 0.06 \ m[/tex]

The distance the lens need to move is evaluate as

   [tex]z = |v - v_1|[/tex]

   [tex]z = |0.052 - 0.06|[/tex]

   [tex]z = 0.009 \ m[/tex]

Answer:

A)  K = ½ U / r , B)     T² = (4π² / G M) r³

Explanation:

A) It asks us for the kinetic energy of the satellite and they give us the relation of the potential synergy

         U = - G M m / r

the force can be found from this expression

          F = - dU / dr

          F = - G M m / r²

The kinetic energy is given by the formula

          K = ½ m v²

let's use Newton's second law

        F = m a

        G M m / r² = m a

where the acceleration is centripetal

        a = v² / r

         G M r² = v² / r

         v² = G M r³

we substitute the expression for the kinetic energy

         K = ½ m v²

         K = ½ m G M r³

in terms of potential energy is

         K = ½ (G M m r²) 1 / r

         K = ½ U / r

B) The period of the orbit

We write Newton's second law

            G M m / r² = m a

            a = v² / r

in a circular orbit the speed of the velocity is constant

            v = d / t

the longitude of the orbit is

             d = 2π r

            v = 2π r / T

we substitute

            G Mm / r² = m (2πr / T)² / r

            G M / r³ = 4π² / T²

            T² = (4π² / G M) r³

(A) The kinetic energy of satellite in terms of potential energy is,

       K =  1/2 U / R.

(B)  The expression for the square of the orbital period is,

         T² = (4π² / G M) R³

Given data:

The potential energy of object is, U.

The mass of object is, m.

The distance from the other object of mass M is, R.

A.

The kinetic energy of the satellite and they give us the relation of the potential synergy,

U = - G M m / R

And the force can be found from this expression

F = - dU / dR

F = - G M m / R²

The kinetic energy is given by the formula

K = 1/2 m v²

Now use Newton's second law

F = m a

G M m / R² = m a

where the acceleration is centripetal

a = v² / R

G M R² = v² / R

v² = G M R³

we substitute the expression for the kinetic energy

K = 1/2 m v²

K = 1/2 m G M R³

in terms of potential energy is

K = 1/2 (G M m R²) 1 / R

 K =  1/2 U / R

Thus, we can conclude that the kinetic energy of satellite in terms of potential energy is K =  1/2 U / R.

(B)

Now we need to obtain the period of the orbit of satellite. For that we   write Newton's second law as

G M m / r² = m a

Since,

a = v² / r

In a circular orbit the speed is constant,

v = d / t

For the longitude of the orbit is

d = 2π R

v = 2π R / T

here,

T is the orbital period of satellite.

Substituting the values as,

G Mm / R² = m (2πR / T)² / R

G M / R³ = 4π² / T²

T² = (4π² / G M) R³

Thus, we can conclude that the expression for the square of the orbital period is T² = (4π² / G M) R³.

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