Complete each of the statements regarding amino acids. Select the amino acid that fits best in each category. 1. An example of a basic amino acid is 2. An example of an acidic amino acid is 3. An example of a neutral polar amino acid is 4. An example of a hydrophobic amino acid is

Answer:

Question 1 ; 2.15 atm

Question 2; 1.078 atm

Step by step explanation:

Question 1

We can use the Ideal Gas Law to calculate the pressure: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant (8.31 J/mol·K), and T is the temperature in Kelvin.

Given the initial conditions:

V1 = 2.27 L, T1 = 285 K, and P1 = 1.10 atm

And the final conditions:

V2 = 1.36 L, T2 = 306 K

We can rearrange the Ideal Gas Law to solve for P2:

P2 = (nRT2) / V2 = (nRT1) / V1 * (V1 / V2) = (P1 * V1 * T2) / (T1 * V2) = (1.10 atm * 2.27 L * 306 K) / (285 K * 1.36 L) = 2.15 atm

Question 2

The total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases. So, after adding the third gas, the total pressure will become:

0.292 atm + 0.676 atm + 0.110 atm = 1.078 atm.

The exact SQL clause to use with the query "SELECT * FROM package" depends on the desired results.

The SQL clause to use with the query "SELECT * FROM package" depends on the desired results. The WHERE clause can be used to filter data and only return rows that meet a condition. The GROUP BY clause can be used to aggregate data and group rows based on columns. The HAVING clause can be used to filter aggregated data. The ORDER BY clause can be used to sort the data. The combination of these clauses can create complex queries to filter, aggregate, and sort data to meet specific needs.

For example, "SELECT recipient, SUM(weight) FROM package GROUP BY recipient HAVING SUM(weight) > 50 ORDER BY weight DESC" would return recipients with total weight greater than 50, sorted by weight in descending order.

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Mg-24 has a mass of 23.9850 and abundance of 78.99%.

Mg-25 has a mass of 24.9858 and abundance of 10.00%.

Mg-26 has a mass of 25.9826 and abundance of 11.01%.

When a substance is present in large quantities and is essentially unaltered by the reaction, it is said to be a reactant that is present in abundance in a chemical reaction. Abundance differs from excess in that excess refers to any reactant other than the limiting reagent; the amount by which a reactant is in excess is frequently specified, such as with terms like "twofold excess," which denotes that there is twice as much reactant as is required for the limiting reagent to completely react. In this case, if the reaction is successful, the amount of excess reactant will have been cut in half.

Sketch of graph is given below↓↓↓

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If m_c = m_l, then there is equal amounts of copper and lead.

To determine the relative amounts of each type of bull3t (copper and lead), we need to know the mass and volume of each type of bull3t. Assuming that the copper and lead are pure, the mass of each bull3t can be calculated using its density and volume.

Let's say the volume of the copper bull3t is V_c and the volume of the lead bull3t is V_l. Then, the mass of the copper bullet can be calculated as follows:

m_c = ρ_c * V_c

where ρ_c is the density of copper (8.96 g/cm3).

Similarly, the mass of the lead bull3t can be calculated as follows:

m_l = ρ_l * V_l

where ρ_l is the density of lead (11.4 g/cm3).

To determine the relative amounts of each type of bull3t, we need to compare their masses. If m_c > m_l, then there is more copper than lead. If m_c < m_l, then there is more lead than copper. And if m_c = m_l, then there is equal amounts of copper and lead.

Note: The actual masses of the bull3ts will depend on their individual volumes, which are not specified in the question. The above calculation provides only a relative comparison of the masses of the two types of bull3ts.

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The rate of the disappearance of Br- in this reaction is given,  0.113 M/s. Then, the rate of consumption of H+ ion in this reaction is 0.09 M/s.

The rate of a reaction is the rate of disappearance of the reactants or the rate of formation of the products. Hence, the rate of the reaction in terms of reactants is expressed in negative sign and that of products is written in positive sign.

From the reaction we can write the rate of reaction as:

5 - d [Br-]/dt = 6 - d [H+]/dt = d [Br₂]/dt

Given that, - d [Br-]/dt = 0.113 M/s

The rate of consumption of H+ ion at the given moment is calculated as follows:

d [H+]/dt = 5/6   d [Br-]/dt

               = 5/6 × 0.113 M/s

               = 0.09 M/s.

Therefore, 0.09 M/s rate  of H+ being consumed at that moment.

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The acid ionization constant for the acid is 1.40 x 10^-10.

The acid ionization constant (Ka) can be calculated using the equation:

Ka = [H+][A-] / [HA]

where [H+] and [A-] are the concentrations of the hydrogen ion and the conjugate base, respectively, and [HA] is the concentration of the undissociated acid.

Given that the percent dissociation is 0.57%, the concentration of the dissociated species can be calculated as follows:

[A-] = 0.57% * 8.0 x 10^-2 M = 4.56 x 10^-5 M

[H+] = [A-]

Since the dissociation is very small, we can assume that the concentration of the undissociated acid is equal to the initial concentration of the solution:

[HA] = 8.0 x 10^-2 M

So, the value of Ka can be calculated as:

Ka = [H+][A-] / [HA] = (4.56 x 10^-5 M)^2 / (8.0 x 10^-2 M) = 1.40 x 10^-10.

Therefore, the acid ionization constant for the acid is 1.40 x 10^-10.

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The number of atoms of oxygen in the reactants is 5 (3 from NO₂ and 2 from H₂O) and the number of atoms of oxygen in the products is 5 (1 from NO and 8 from HNO₃).

3NO₂(g) + H₂O(l) →→ NO(g) + 2HNO₃(aq)

Atom: Atoms are made up of smaller particles such as electrons, protons, and neutrons. These particles determine the properties of an atom and the elements they form.

Oxygen: Oxygen is the chemical element having symbol O and its atomic number will be 8. It is a member of the chalcogen group in the modern periodic table, a highly reactive nonmetal, and an oxidizing agent that readily forms oxides with most elements as well as with other compounds.

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The correct order for the freezing point of the solution will be [tex]\mathrm{K_3PO_4 < Na_2CO_3 < NaNO_3}[/tex]

Freezing is the process of cooling a substance to a temperature below its freezing point, which is the temperature at which a liquid turns into a solid. This process occurs naturally when the temperature of a liquid decreases to the freezing point or below. When a liquid freezes, its molecules slow down and become arranged in a solid crystal lattice structure. Freezing is often used in food preservation, as freezing temperatures prevent the growth of microorganisms and slow down the breakdown of chemical compounds. Freezing can also be used for other purposes, such as medical applications, where tissue samples are frozen for later analysis.

The number of ions formed by the dissociation of 1 molecule of [tex]\mathrm{Na_2CO_3, NaNO_3 \quad}[/tex] and [tex]\mathrm{ K_3PO_4}[/tex] are 3,2 and 4 respectively.

Hence, the correct order fro the vant Hoff,s factor i and the depression in the freezing point will be [tex]\mathrm{NaNO_3 < Na_2CO_3 < K_3PO_4}[/tex]

Hence, the correct order for the freezing point of the solution will be [tex]\mathrm{K_3PO_4 < Na_2CO_3 < NaNO_3}[/tex]

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Correct question:

Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. Na2Co3, NaNo3, K3PO4.

compared to a metal with an ASTM grain size of 3, a material with a grain size number of 7 would have finer crystals and would be stronger.

The ASTM (American Society for Testing and Materials) grain size number is a measure of the average size of the grains in a metal. A lower number indicates a material with larger grains, while a higher number indicates smaller grains. The size of the grains affects the mechanical properties of the metal, such as strength, toughness, and ductility. In general, metals with finer grain sizes have better mechanical properties, such as increased strength and improved ductility. This is because smaller grains result in a more uniform microstructure and reduced defects, leading to improved mechanical performance. Therefore, a metal with an ASTM grain size of 7 would be expected to have finer crystals and to be stronger compared to a metal with an ASTM grain size of 3.

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The considerations which are applicable in a suitable recrystallization solvent are: should have a boiling point that is ~ 30-50 °C, Should be unreactive, Offers minimal solubility and solubility-temperature relationship. Option A, C, D and E will be correct.

This statement is true. Because the solvent should have a boiling point that is around 30-50 °C higher than the melting point of the compound to be recrystallized in order to achieve efficient dissolution and crystal formation.

This statement is false. Because a good recrystallization solvent should dissolve the compound of interest well at high temperatures but not at all or only slightly at lower temperatures. Ideally, the impurities should dissolve well at all temperatures, so that they can be separated from the compound of interest during the filtration step.

This statement is true. Because the solvent should not react with the compound of interest, which would affect the purity of the final product.

This statement is true. Because the solvent should have minimal solubility for the compound to be purified at room temperature and lower temperatures, but should dissolve the compound well at higher temperatures in order to achieve efficient recrystallization.

This statement is true. Because the solubility-temperature relationship for the solvent and the compound should have a low slope in order to achieve efficient recrystallization.

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--The given question is incorrect, the correct question is

"Which of the following considerations are applicable when choosing a suitable recrystallization solvent? (TRUE / FALSE) A) Should have a boiling point that is ~ 30-50 °C above room temperature. B) Does not dissolve impurities at all temperatures or completely dissolves impurities at all temperatures. C) Should be unreactive toward the compound of interest. D) Offers minimal solubility of the compound to be purified at room and lower temperatures. E) Its solubility-temperature relationship to the compound should give a curve with a low slope."--

The equation that shows the formation of cobalt (III) ion from the neutral atom of cobalt is written as below:

[tex]\rm Cu \rightarrow Cu^{3+} + 3 e^{-}[/tex]

Oxidation is the process of reaction with oxygen or donation of electrons to form the higher oxidation state. When a neutral atom donates one electron to other atom, it gains positive charge. Thus oxidizes to one higher oxidation state.

Cobalt is a transition metal exhibiting variable oxidation states as other transition metals. The possible oxidation states of cobalt are  +1, +2 and +3.

When cobalt atom donates 3 electrons from its valence shell. It forms the ion Co³⁺. The reaction can be represented as written above. The number of electrons donated is written in the right of the arrow.

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Answer:

Proton (charge of +e, in the nucleus), Neutron (0 charge, in the nucleus), and Electron (charge of –e, outside the nucleus).

Explanation:

Answer:

Denmark, Finland, New Zealand, Norway, Singapore, and Sweden are perceived as the least corrupt nations in the world, ranking consistently high among international financial transparency, while the most apparently corrupt are Somalia (scoring 12), Syria and South Sudan (both scoring 13).

In a chemical reaction involving the formation of an intermediate activated complex, the step from reactants to the activated complex must always be exothermic. Option A is correct.

This step is called the activation energy, and it represents the energy required to form the activated complex, which is a high-energy transition state between the reactants and the products. The formation of the activated complex is exothermic because the activated complex is higher in energy than the reactants and lower in energy than the products.

The energy difference between the reactants and the activated complex is the activation energy, which is usually overcome by heat, light, or some other form of energy. Once the activation energy has been supplied, the reaction proceeds to form the products, which are lower in energy than the activated complex.

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103ml of borax will be 7 tbsp of borax.

What is the use of borax?

Borax, commonly known as sodium borate, sodium tetraborate, or disodium tetraborate, is a white powdery chemical. It is frequently utilized as a household cleanser and laundry detergent booster. It contains boron, sodium, and oxygen in combination.

Baking soda (sodium bicarbonate) and borax (sodium tetraborate) aren't interchangeable terms. Although both salts and often used as "green" household cleaners, baking soda has a pH of 8, and borax has a pH of 9.5. Borax is a lot more alkaline than baking soda as a result.

Given,

1 tbsp is 14.8ml

So 7 tbsp will be 14.8*7 i.e. 103.6ml

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Eyewash station for chemicals in the eyes, a fire blanket for fire on a person, a fire extinguisher for a large fire on the benchtop, and a first aid kit for cuts or minor burns.

Eyewash station:

For chemicals in the eyes, an eyewash station provides immediate flushing of the affected area to help prevent damage and remove any hazardous material. This should be located close to where the chemicals are being used and easily accessible in the event of an emergency.

Fire blanket:

A fire blanket can be used to smother a small fire on a person, such as clothing that has caught fire. The blanket is placed over the person and the fire is suffocated by cutting off the oxygen supply.

Fire extinguisher:

A fire extinguisher is the primary piece of equipment for fighting a small fire, such as a fire on a benchtop. It is important to choose the correct type of extinguisher for the type of fire that is occurring, as using the wrong type can make the fire worse.

First aid kit:

A first aid kit can be used to treat cuts or minor burns. This kit should contain items such as bandages, antiseptic wipes, and pain relievers. Having a first aid kit on hand can help to prevent minor injuries from becoming more serious and can provide a measure of comfort to the person who is injured.

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Answer:

Explanation:

The pressure of a gas can be calculated using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in kelvin.

Assuming that the number of moles of gas and the temperature remain constant during the compression, the pressure of the gas after compression can be calculated as follows:

P2 = (nRT) / V2 = (nRT) / 1.64 L

where P2 is the pressure after compression and V2 is the volume after compression. To find P2, we need to substitute the known values into the equation:

P2 = (1.43 atm * 7.7 L) / 1.64 L = 6.76 atm

So, the pressure of the gas after compression will be 6.76 atm.

The number of photons that are produced in a laser pulse of 0.436 J

at 619 nm is 1.35 * 10¹⁸ photons.

The energy of a single photon at 619 nm wavelength

E = hc/λ

where:

h is Planck's constant = 6.63 x 10⁻³⁴ J•s.

c is speed of light = 3.0 * 10⁸ m/s

λ is wavelength = 619 nm or 6.19 * 10⁻⁷ m

E = 6.63 x 10⁻³⁴ * 3.0 * 10⁸ / 6.19 * 10⁻⁷

E = 3.21 * 10⁻¹⁹ J

1 photon is equivalent to 3.21 * 10⁻¹⁹ J

The number of photons = 0.436/3.21 * 10⁻¹⁹

The number of photons = 1.35 * 10¹⁸ photons.

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The formula for molarity is:

M = n/V

Where:

M is molarity

n is the number of moles

V is the volume in liters

We know the volume is 100 mL, so we need to convert it to liters:

100 mL = 0.1 L

Now we can calculate the number of moles needed for a 0.75 M solution:

n = M × V

n = 0.75 × 0.1

n = 0.075 moles

Finally, we can use the moles to calculate the number of grams of NaBr:

n = m/M

m = n × M

m = 0.075 moles × 102.9 g/mol

m = 7.72 g

So, we would need 7.72 grams of NaBr to prepare 100 mL of a 0.75 M solution.

The concentration of a solute in a solution is expressed using the unit of measurement known as molarity. It is designated by the symbol "M" and is defined as the number of moles of solute present in one liter of solution. In chemistry, biochemistry, and analytical chemistry, molarity is frequently employed to express the concentration of a solution in a consistent and quantitative way. The number of moles of solute divided by the number of liters of the solution is the definition of molarity, a concentration unit in chemistry.

A chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration. The number of moles per liter, denoted by the unit sign mol/L, is the most often used molarity unit in chemistry.

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Answer:

C) 5 to 3

Hope it helped; please mark brainliest, I put a lot of effort into my answers!

Answer:

1.25 L of C2H4 is equal to:

1.25 L / 22.4 L/mol = 0.0558 moles

From the balanced chemical equation, we see that for every 1 mole of C2H4 that reacts, 2 moles of H2O are formed.

So, for 0.0558 moles of C2H4:

0.0558 moles * 2 moles H2O/mole C2H4 = 0.1116 moles of H2O

0.1116 moles * 22.4 L/mol = 2.51 L H2O (3 sig figs)

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The number of milliliters of lead is: 368.81 mL

To calculate the number of milliliters of lead (density 11.3 g/mL) having a mass of 4.145 kg, you can use the following equation:

Therefore, 4.145 kg ÷ 11.3 g/mL = 368.81 mL

It is also important to remember that while this equation is useful for calculating the volume of a sample of a substance, it is not applicable to calculating the volume of a compound that contains multiple elements.

In such cases, the molar mass of the compound must be used instead. Additionally, the equation only works for substances with a constant density, as the density of a substance can vary depending on its temperature and pressure.

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Answer:

Physicist Ernest Rutherford established the nuclear theory of the atom with his gold-foil experiment. When he shot a beam of alpha particles at a sheet of gold foil, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflection.

According to the concept of Avogadro's number, all of the above choices is equal to 111 moles of the substance.

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

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Approximately 71.1 grams of sucrose would be hydrolyzed when 2.60 L of a 0.160 M sucrose solution is allowed to react for 200 minutes, assuming the reaction follows first-order kinetics.

To calculate the mass of sucrose hydrolyzed, we need to first determine the amount of sucrose (in moles) present in the solution, using the formula:

moles of sucrose = concentration of sucrose x volume of solution

moles of sucrose = 0.160 mol/L x 2.60 L = 0.416 mol

Since sucrose (C12H22O11) is hydrolyzed into glucose (C6H12O6) and fructose (C6H12O6), we know that one mole of sucrose yields two moles of product. Therefore, the number of moles of product formed will be twice the number of moles of sucrose hydrolyzed.

mol of sucrose hydrolyzed = 0.416 mol / 2 = 0.208 mol

Finally, we can use the molar mass of sucrose (342.3 g/mol) to calculate the mass of sucrose hydrolyzed:

mass of sucrose hydrolyzed = 0.208 mol x 342.3 g/mol = 71.1 g

Therefore, approximately 71.1 grams of sucrose would be hydrolyzed when 2.60 L of a 0.160 M sucrose solution is allowed to react for 200 minutes, assuming the reaction follows first-order kinetics.

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The rate of converting intermediates to products will be faster, because this reaction has a lower barrier than the reaction that converts intermediates back to reactants.  

This is because the reaction that converts intermediates to products is an exothermic reaction, meaning it releases energy and is therefore more likely to occur.

An elementary reaction is a chemical reaction in which the reactants directly form the products in a single reaction step and with a single transition state. It is a reaction that cannot be broken down into simpler steps and is considered to be a basic unit of chemical kinetics.

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The number of moles of N atoms in 1.00 x1022 Ny molecules is 1.66 ₓ 10⁻² mol.

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

1 mole is equal to 6.023 × 10 ²³ molecules.

10 gm of Nitrogen gas having number of mol = mass/ molar mass

n =10 / 28

n = 0.3571 mol

number of nitrogen molecule is 0.3571 × 6.0221023 molecules

= 2.151023 molecules

number of nitrogen atoms = 20.3571 × 6.0221023 atoms

= 4.301023 atoms

b. 10 gm of oxygen gas having no of mol = mass / molar mass

n = 10/32

n= 0.3125 mol

number of oxygen atoms = 0.3125 × 6.0221023 molecules

= 1.881023 molecules

number of oxygen atoms = 20.3125 × 6.0221023 atoms

= 3.761023 atoms

c. 10 gm of carbon having no of mol = mass / molar mass

n = 10 / 12

n= 0.83 mol

number of Carbon atoms = 0.83 × 6.0221023 atoms

= 4.9991023 atoms

d. 10 gm of sulfur having no of mol = mass / molar mass

n = 10 / 32

n= 0.3125 mol

number of nitrogen atoms = 0.3125 × 6.0221023 atoms

= 1.881023 atoms

So, the highest number of atom is 10 gm Carbon.

and greatest molar mass has sulfur and oxygen if sulfur is taken as octaatomic as sulfur has greatest molar mass.

here nitrogen has the greatest number of molecule.

Therefore, 6.022× 10²³ molecules of N2 gas contain 1 mol

so, 1 × 10²² molecule of N2 gas having  

= 0.166 ₓ 10-1

= 1.66 ₓ 10⁻² mol.

Thus, the number of moles of N atoms in 1.00 x1022 Ny molecules is 1.66 ₓ 10⁻² mol.

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The ionic equation for the reaction between Na2[Zn(OH)4] and H2S is:

Na2[Zn(OH)4] + 2H+ + 2S2- -> ZnS + 2Na+ + 4OH- + 2H2O

The ionic equation for the reaction between Na2[Zn(OH)4] and H2S is:

Na2[Zn(OH)4] + 2H+ + 2S2- -> ZnS + 2Na+ + 4OH- + 2H2O

The net-ionic equation, which shows only the species that are involved in the reaction, is:

Zn2+ + S2- -> ZnS

In this reaction, the sodium zinc hydroxide (Na2[Zn(OH)4]) reacts with hydrogen sulfide (H2S) to form zinc sulfide (ZnS), sodium hydroxide (NaOH), and water (H2O). The hydrogen ions (H+) and sulfide ions (S2-) are spectator ions, as they do not participate in the reaction and their presence does not affect the reaction outcome.

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The mass of urea (CH4N2O) needed to prepare 52.0g of a solution in water in which the mole fraction of urea is 7.71×10−2 is 13.62 g.

The term mole fraction represents the number of molecules of a particular component in a mixture divided by the total number of moles in the given mixture. It's a way of expressing the concentration of a solution.

The mass of water = 48.5 g

number of moles of water = 52.0 g/18g/mol

= 2.8 moles of water

mole fraction of urea = 7.71×10−2

but mole fraction = mole of substance/ total number of moles

Let the number of moles of urea be x

7.71 × 10−2 = x / 2.8 + x

7.71 × 10 − 2 (2.8 + x) = x

7.71 × 10 - 5.6 + 2x = x

x = 0.227 moles of urea

mass of urea in solution = number of mole × molar mass

= 0.227 moles × 60 g/mol

= 13.62 g of urea

Thus, the mass of urea (CH4N2O) needed to prepare 52.0g of a solution in water in which the mole fraction of urea is 7.71×10−2 is 13.62 g.

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