Comparing the Motion of Two Cars
Position vs Time
for Two Cars
D
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions,
Car Ais moving faster than car B.
Car A and car B started at the same location.
Car A and car B are moving toward each other until
they cross over.
B
Position (m)
Time (s)

Red shirt appears red because:

a. The shirt reflects red light

A red shirt appears red because the shirt reflects red light.

Thus, An important topic for astronomers is "red shift." The phrase can be taken literally; when the light's wavelength is extended, the light is perceived as having "shifted" toward the red portion of the spectrum.

When a source of sound moves in relation to an observer, sound waves experience a similar phenomenon.

The frequency of sound waves varies if the source of the sound and the observer are moving relative to one another, according to Austrian mathematician Christian Andreas Doppler, who made this discovery.

The observer hears a frequency that is higher when the two are moving closer together and lower when they are moving farther apart and red shift.

Thus, A red shirt appears red because the shirt reflects red light.

Learn more about Red shift, refer to the link:

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Answer:

Explanation:

From the question

Weight of painter = 500N

Weight of scaffold = x

Weight of painter + weight of scaffold = 2* 400 (since they are supported by two ropes)

Substitute

500 + x = 2(400)

500+x = 800

x =  800-500

x = 300N

Hence the weight of the  scaffold is 300N

the number is 1 I hope this help

The final velocity of the bus  is 9.83 m/s

The given parameters;

initial velocity of the bus, = 30 km/h

constant increase in speed, = 1.5 m/s

time of motion, t = 6.8 s

The initial velocity of the bus in m/s;

[tex]v = 30 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 8.33 \ m/s[/tex]

The acceleration of the bus;

[tex]a = \frac{\Delta v}{\Delta t} = \frac{1.5 \ m/s}{6.8 \ s } = 0.22 \ m/s^2[/tex]

The final velocity of the bus at the given time of motion;

[tex]v= u + at\\\\v = 8.33 + (0.22 \times 6.8)\\\\v = 9.83 \ m/s[/tex]

Thus, the final velocity of the bus  is 9.83 m/s

Learn more here: https://brainly.com/question/17956487

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

Answer:

A molecule is defined as two or more atom of same element or different element grouped together

Answer:

Gravity

Explanation:

Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all

Answer: The correct statement is D (the sodium azide breaks down into sodium and nitrogen gas).

Explanation:

A chemical change is an irreversible chemical reaction in which new substances are usually formed. It is also defined as chemical decomposition of a substance leading formation of two or more other substances. A typical example is in the break down or decomposition of sodium azide into sodium metal and nitrogen gas. This is seen in the chemical balanced equation below:

2 NaN3 --> 2 Na + 3 N2

Sodium azide ( also called Sodium trinitride) is a chemical compound that is in built into automobile air bags which upon collision is being triggered to decompose. This leads to the generation of sodium and nitrogen gas that fills the air bag. This aid ls in reducing the impact of the collision and absorbs the forward-moving energy of the occupant.

Answer:

The answer is D Im doing the Exam noe

Explanation:

Hope this help :)

Red Riot out

Answer:

2.5 k

Explanation:

Answer:

A force is a push or pull on an object. Forces usually cannot be seen but their effects can.

Nothing moves, changes speed, stops or changes direction without force. Heavier objects need more

force to get them to move or change direction.

Explanation:

Answer:

given..

m= 3.5

t= 3

d=25

f=?

now....a...

25=1/2a×9

a=50/9

f=ma=35/10×50/9=19.4N

Answer:

I believe c and d is the answer because a and b are more material properties.

Answer:

heart

Explanation:

Answer:

The free-body diagram of the cannonball is found in the attachment below

Note The question is incomplete. The complete question is as follows:

A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglected.

Draw the free-body diagram of the cannonball.

Explanation:

Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation.

In order to construct free-body diagrams, it is important to know the various types of forces acting on the object in that situation. Then, the direction in which each of the forces is acting is determined. Finally the given object is drawn using any given representation, usually a box, and the direction of action of the forces are represented using arrows.

In the given situation of a cannonball which has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction., the forces acting on it are:

F = force exerted by the cannon acting in the direction of angle of projection

Fdrag = drag force. The drag force acts in a direction opposite to the force exerted by the cannon

Fw = weight of the cannonball acting in a downward direction

The free body diagram is as shown in the attachment below.

Answer:

20 kg

More force required after placing weight in trunk to accelerate the trunk than before when the trunk is empty.

Explanation:

We are given that

Mass of empty trunk, m=10 kg

Mass of a weight, m'=10 kg

We have to find the total mass after placing weight in trunk and how will this affect the force needed to accelerate the trunk.

Total mass =m+m'

Total mass=10+10=20 kg

We know that

Force, F=ma

Force is directly proportional to mass.

When we placed weight in trunk then the mass of trunk increases .Therefore, now more force required to accelerate the trunk than before when the trunk is empty.

Answer:

B) Synthesis

Explanation:

A combination reaction, also known as a synthesis reaction in chemistry, is when two or more substances, or reactants, combine with each other to form a new product. The product will always be a compound.

Answer:

-140

Explanation:

A gas loses 80joules of heat.

The gas also does 60 joules of work

Therefore the change in internal energy can be calculated as follows

= -80 + (-60)

= -80-60

= -140

Hence the change in internal energy is -140

Answer:

the velocity of the brick when it hits the ground is 39.60 m/s

Explanation:

Given;

height through which the ball is dropped, h = 80.0 m

the initial velocity of the brick, u = 0

The final velocity of the brick when it hits the ground is calculated as;

v² = u² + 2gh

v² = 0 + 2 x 9.8 x 80

v² = 1568

v = √1568

v = 39.60 m/s

Therefore, the velocity of the brick when it hits the ground is 39.60 m/s

Answer:

Explanation

The work done by the lifter is equal to its potential energy since he is covering a height and under the influence of gravity.

potential energy = mass * acceleration due to gravity * height

m is the mass

g is the acceleration due to gravity

h is the height

Hence the required workdone = PE = mgh

Answer:

bhgyg 78 gt78gyug

Explanation:

Answer:77.98

Explanation:

Answer:

Water vapor is steam. An example of water vapor is the floating mist above a pot of boiling water. Water in the form of a gas; steam.

Explanation:

Answer:

A

Explanation:

Answer:

1) q₃ is approximately -7.58 nC

2) The direction of the net force on 'q₃' is the negative '-' direction

3) For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m

Explanation:

1) The force, 'F', between two charged spheres is given as follows;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]

The net force acting on the point charge, 'q₃', is given as follows;

[tex]F_{NET} = \dfrac{k \cdot q_1 \cdot q_3}{x_1^2} + \dfrac{k \cdot q_2 \cdot q_3}{x_2^2}[/tex]

By substituting the given values, we have;

[tex]F_{NET} = 3.10 \ \mu N = \dfrac{k \cdot (-4.10 \ nC) \cdot q_3}{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC \cdot q_3}{(-0.320 \ m)^2}[/tex]

[tex]3.01 \ \mu N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC }{(-0.320 \ m)^2} \right) = -\dfrac{14117 \ nC \cdot K}{320}[/tex]

[tex]\therefore q_3 = 3.01 \ \mu N \times -\dfrac{320 \ m^2}{14117 \ nC \cdot K}[/tex]

K = 9 × 10⁹ N·m²·C⁻²

[tex]\therefore q_3 = 3.01 \ \times 10^{-6} \ N \times -\dfrac{320 \ m^2}{14117 \times 10^{-9} \ C \times 9 \times 10^9 \ N \cdot m^2 \cdot C^{-2}}= -7.58 \ nC[/tex]

q₃ ≈ -7.58 nC

2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin

The net force's direction on q₃ will be in the '-' direction

3) For zero net force, we have;

The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m

Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1

By substitution, we have;

[tex]0 \ N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.57 - r_1 ) ^2} + \dfrac{k \cdot 2.20 \ nC }{(r_1)^2} \right)[/tex]

[tex]\therefore \dfrac{k \cdot 4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{k \cdot 2.20 \ nC }{(r_1)^2}[/tex]

From which we have;

[tex]\dfrac{4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{2.20 \ nC }{(r_1)^2}[/tex]

(r₁)²×4.10 = 2.20 × (0.57 - r₁)²

From the above equation, we have;

95,000·r₁²+ 125,400·r₁-35739 = 0

Solving, using a graphing calculator we get;

r₁ ≈ 0.241 or r₁ ≈ -1.561

Where, 'r₁', is measured from 'q₂', therefore, we have;

r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881

Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero

Answer:

they amplitude modulation

and they ferequency modulation

Explanation:

The difference is in how the carrier wave is modulated, or altered. With AM radio, the amplitude, or overall strength, of the signal is varied to incorporate the sound information. With FM, the frequency (the number of times each second that the current changes direction) of the carrier signal is varied.

hope it helps