Radio telescopes must be larger than optical telescopes because of the longer wavelengths of radio waves, which result in a lower diffraction limit.
The diffraction limit of a telescope is determined by its aperture size, or the diameter of its collecting area. For the Hubble Space Telescope, the diffraction limit for visible light is approximately 0.05 arcseconds. This means that the telescope can resolve structures or details that are separated by at least 0.05 arcseconds of an angle.
On the other hand, radio telescopes are much larger than optical telescopes because radio waves have longer wavelengths than visible light. The diffraction limit of a radio telescope is proportional to the wavelength of the radiation it observes. Because radio wavelengths are much longer than those of visible light, radio telescopes must be much larger in order to achieve the same level of resolution as optical telescopes.
In addition, radio telescopes can detect emissions from much larger structures in space, such as galaxies and clusters of galaxies. These emissions are typically very weak and difficult to detect, so radio telescopes must have a large collecting area in order to detect them.
To sum up, radio telescopes must be larger than optical telescopes because of the longer wavelengths of radio waves, which result in a lower diffraction limit, and the need to detect weak radio emissions from large structures in space.
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Radar waves of wavelength 50 mm are emitted from two aerials and create a fringe pattern 1 kilometer from the aerials. Calculate the distance between the aerials if the fringe spacing is 80 cm.
If the fringe spacing is 80 cm, the distance between the aerials is 6.25 meter.
What is interference?In physics, interference refers to the combined result of two or more wave trains travelling along intersecting or converging trajectories. The result is the result of adding the individual wave amplitudes at each place that is influenced by multiple waves.
Given: wavelength = 50 mm = 50 × 10⁻⁴ m
the fringe spacing is = 80 cm = 0.80 m.
x = λD/d
d = λD/x
= 50 × 10⁻⁴ × 1000/0.80 m
= 6.25 meter.
Hence, the distance between the aerials is 6.25 meter.
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the constant potential difference across a 2 ohm resistor is 20 volts. how many watts of power are dissipated by this resistor?
A 2 ohm resistor loses 200 watts of electricity when the steady potential difference across everything is 20 volts, in accordance with the equation Power = V2/R.
What does an electrical volt mean?Volts are units used to express the intensity of either an electric potential difference and or force that propels electrons across a circuit. Electric current is measured in amps. Its quantity of electrons passing across a circuit is measured in terms of current.
What is a volt used to measure?Its difference potential energy that occurs between two points is measured in volts (symbol V). Alessandro Volta, the man who created the battery, is therefore honored by the name of the volt.
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astronomers split up the ancient constellation of argo navis because it was too large to be useful as a celestial landmark. group of answer choices true false
True, astronomers split up the ancient constellation of argo navis because it was too large to be useful as a celestial landmark.
Why was Argo Navis a constellation but is no longer?
The only star design that was abandoned due to strictly practical considerations is Argo Navis; it was simply too large. So Nicolas Louis de Lacaille, a French astronomer, separated it into the constellations Carina, Puppis, and Vela in the year 1750.
Sir John Herschel suggested the complete dissolution and elimination of Argo Navis in 1841 and 1844. Despite this, the constellation and its component pieces continued to be used well into the 20th century. It was given the three-letter abbreviation Arg in 1922, along with the other constellations. In 1930, when the IAU established the 88 contemporary constellations, Carina, Puppis, and Vela were split up and demoted to a previous constellation.
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the staples inside a stapler are kept in place by a spring with a relaxed length of 0.115 m. if the spring constant is 51.0 n/m, how much elastic potential energy is stored in the spring when its length is 0.150 m?
When the spring is 0.150 m long, it will have "0.312 J" of stored potential energy.
What is a spring's Hooke's Law constant?F = -kx. It gauges the stiffness of the spring. When a spring is stretched or compressed to a length that deviates by an amount x from its equilibrium length, it applies a force F = -kx in the direction of its equilibrium position.
According to the question.
Length, L = 0.115 m
Spring constant, k = 51.0 N/m
Now,
P.Eelastic = 1/2 kx²
P.Eelastic = 1/2 × (0.150 - 0,150)²
P.Eelastic = 0.01225 × 51 /2
P.Eelastic = 0,312J.
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a hollow metal sphere of radius r is positively charged. of the following distances from the center of the sphere, which location will have the greatest electric field strength?
The location that will have the greatest electric field strength is the surface of the sphere, which is a distance of r away from the center.
This is because the electric field strength is inversely proportional to the square of the distance from the source, so the closer you get to the source, the stronger the electric field will be.
An electric field is an area of influence created by an electric charge, in which electric force is exerted on other charged objects. This electric force is described mathematically by the electric field vector, which specifies the direction and magnitude of the force. Electric fields can be created by stationary charges, or by time-varying magnetic fields. Electric fields can be used to control the motion of charged objects, and are also responsible for many of the phenomena associated with electricity, such as electric potential, capacitance, and electric current.
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A block with shear modulus is bonded to a fixed based and to a horizontal rigid plate to which a force is applied. Assume , and
The shear force in the block is[tex]F = G*ε = 7.10^3*0.0006855 = 488.75[/tex]kips.
What is shear force?Shear force is a type of mechanical force that can cause an object to deform or break apart when the force is applied parallel to the object's surface.
The shear modulus, G, is a measure of the rigidity of a solid material and is expressed in units of kips per square inch (ksi).
In this case, we are given that G = 7.10^3 ksi.
To calculate the shear force, F,
in the block, we can use the equation F = P(L/2)/(b*t).
Here, P is the applied force (630 kips),
L is the length of the block (15 inches), b is the width of the block (8 inches), and t is the thickness of the block (2 inches).
Plugging in these values, we get[tex]F = 630(15/2)/(8*2) = 488.75[/tex]kips.
Since the block is bonded to a fixed base and a horizontal plate, the shear force in the block will be equal to the shear modulus, G, multiplied by the strain, ε.
The strain is calculated using the formula ε = F/Gt, where F is the shear force calculated above and G is the shear modulus (7.10^3 ksi). Plugging in the values, we get[tex]ε = 488.75/7.10^3*2 = 0.0006855[/tex]
Therefore, the shear force in the block is [tex]F = G*ε = 7.10^3*0.0006855 = 488.75[/tex]kips.
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Complete Question:
Assuming the height of the hill is 50m calculate
(i)The velocity of the car at the bottom of the hill
(ii) The height at which it will have half this speed. Assume the car starts from west from the top of the hill
pls show all workings
(i ) The velocity of the car at the bottom of the hill is 31.3 m/s.
(ii) The height at which it will have half the speed is 12.5 m.
What is the velocity of the car at the bottom?
The velocity of the car at the bottom of the hill is calculated by applying the principle of conservation of energy as follows;
¹/₂mv² = mgh
v = √ (2 gh )
where;
h is the height of the hillg is gravityv = √ (2 x 9.8 x 50 )
v = 31.3 m/s
The height at which it will have half the speed is calculated as;
¹/₂v = ¹/₂ ( 31.3 m/s ) = 15.65 m/s
h = v² / 2g
h = ( 15.65² ) / ( 2 x 9.8 )
h = 12.5 m
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if the rock takes 0.34 s to cross the 2.2- m -high glass door, from what height above the top of the door was it dropped? express your answer to two significant figures and include the appropriate units.
The rock was dropped from a height of 2.2 m above the top of the door.
What is rock?Rock is a natural and solid material made up of minerals and other substances. It is typically found in mountainous areas, deserts, and other areas where the Earth's crust is exposed. It is composed of different minerals which give it its hardness and durability. Rock is used in numerous construction projects and other applications. It provides a strong foundation for structures and is used in construction, landscaping, and even in art.
The equation used to solve this problem is s = vt, where s is the distance, v is the velocity, and t is the time.
The velocity of the rock is found by rearranging the equation to v = s/t, so v = 2.2 m / 0.34 s = 6.47 m/s.
The initial height of the rock is found by rearranging the equation to s = vt to s = 6.47 m/s * 0.34 s = 2.2 m.
Therefore, the rock was dropped from a height of 2.2 m above the top of the door. Expressed to two significant figures, this is 2.2 m.
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a hammer (500 grams), a small parachute (21 grams), and a baseball (145 grams) are all dropped from a height of 25 meters. the hammer and baseball take about the same amount of time to fall. which statement describes the time it takes for the parachute to fall?
The parachute takes longer to fall because of greater air resistance describes the time it takes for the parachute to fall.
How does air resistance slow the fall rate of a parachute?
The drag force resists the downward movement of gravity, pushing the parachute back up. As the parachute falls, the drag increases until it just balances out the pull of gravity. At that point, the parachute stops speeding up and begins to fall at a steady speed.
Why does a parachute increase air resistance?
An open parachute increases the cross-sectional area of the falling skydiver and thus increases the amount of air resistance that he encounters (as observed in the animation below). Once the parachute is opened, the air resistance overwhelms the downward force of gravity.
How does air resistance affect fall time?
With air resistance, acceleration throughout a fall gets less than gravity (g) because air resistance affects the movement of the falling object by slowing it down.
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3-h) a mass m of 4.7 lbm is attached to a light spring of k lbf /ft elongates it by 1.3 in. determine the spring stiffness k (in lbf /ft) and the natural frequency f (in hz) of the system.
The spring constant k (in lbf /ft) is 248.62 lbf/ft and the natural frequency f (in hz) of the system is 10.54 Hz.
Given the mass of object (m) = 4.7lbm
The elongation in spring (L) = 1.3inches
The spring constant of spring = k
We know that the force exerted on the spring is = F
We determine Fs = kL
The force on object (F) = mg
Fs = F then,
mg = kL such that:
k = (4.7 lbm * 32.2 ft/s^2) / (1.3 in) where 1 lbm * 32.2 ft/s2 = 1 lbf
k = 248.62 lbf/ft
The frequency of spring = f
f = 1 / (2π * √(m/k))
f = 1 / (2π * √(4.7 lbm / 248.62 lbf/ft))
f = 10.54 Hz
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If the acceleration of an object is zero, its speed:_________
If the acceleration of an object is zero, its speed is constant.
In mechanics, acceleration is defined as the rate of change of the speed of an object regarding time. Basically,acceleration are considered as vector quantity (in that they have greatness and course). The direction of an object's acceleration is given by the direction of the net power following up on that item.
The magnitude of object's acceleration, as portrayed by Newton's Subsequent Regulation, is the consolidated impact of two causes: the net equilibrium of all outer powers acting onto that item — greatness is straightforwardly corresponding to this net coming about force; that item's mass, contingent upon the materials out of which it is made — extent is contrarily relative to the item's mass.
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a stone is dropped from a height of 4.9 m . find the time taken to cover this distance
Answer:
Explanation:
Initital velocity = 0
s=1/2*g*[tex]t^{2}[/tex]
4/9 = 1/2*9.8 * [tex]t^{2}[/tex]
[tex]t^{2} =1\\t=1 sec[/tex]
ad2 cannot measure the current directly. based on your observation, how does ad2 impedance analyzer produce the values for the current and resistors?
The term "ad2 impedance analyzer" is not totally clear as to what system or procedure is being discussed. To determine the current, the gadget might, for instance, monitor the voltage across a specified resistance and then apply Ohm's Law (V = IR).
The term "ad2 impedance analyzer" is not totally clear as to what system or procedure is being discussed. However, in general, a device may utilise various techniques to inversely calculate the current or the properties associated with it if it is unable to directly measure current. To determine the current, the gadget might, for instance, monitor the voltage across a specified resistance and then apply Ohm's Law (V = IR). Alternately, the device might employ a differential measuring method, in which case it monitors the voltage difference between two places and then determines the current using the resistance between those two points as a reference. In the end, a device's design and intended function will determine the precise mechanism it employs.
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the planet Mars may be considered to be an isolated sphere of diameter of 6.79×10^6m with it's mass of 6.42×10^23 kg concentrated at its center. A rock of mass 1.40kg rests on the surface of Mars.
(assume that the dimensions of the rock are negligible compared to the radius of Mars)
(I) determine the weight of the rock on Mars
(ii) show that the gravitational potential energy of the rock is -1.77×10^7J
The weight of the rock on Mars is 5.18 N.
The gravitational potential energy of the rock is indeed -1.77×10⁷J
How to find weight and potential energy?(I) To determine the weight of the rock on Mars, use the formula for weight, which is given by:
Weight = Mass x Acceleration due to gravity
The acceleration due to gravity on Mars can be calculated using the formula:
Acceleration due to gravity = (Gravitational constant x Mass of Mars) / (Radius of Mars)²
Plugging in the given values:
Acceleration due to gravity = (6.67 x 10⁻¹¹ Nm²/kg²) x (6.42 x 10²³ kg) / (3.395 x 10⁶ m)²
= 3.71 m/s²
The weight of the rock can now be calculated as:
Weight = 1.40 kg x 3.71 m/s²
= 5.18 N
(ii) To find the gravitational potential energy of the rock, use the formula:
Gravitational potential energy = -(Gravitational constant x Mass of Mars x Mass of rock) / Distance between the center of Mars and the rock
The distance between the center of Mars and the rock is equal to the radius of Mars, which is given as:
Radius of Mars = 3.395 x 10⁶ m
Plugging in the values:
Gravitational potential energy = -(6.67 x 10⁻¹¹ Nm²/kg²) x (6.42 x 10²³ kg) x (1.40 kg) / (3.395 x 10⁶ m)
= -1.77 x 10⁷ J
Thus, the gravitational potential energy of the rock on Mars is -1.77 x 10⁷J.
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the weight exerts a moment of 1826 in.lb on his elbow at point e. what is the moment exerted by the same weight on his shoulder at point s?
The moment should exerted by the weight on his shoulder at point s is also 1826 in.lb.
This means that the weight exerts the same amount of torque on the shoulder as it does on the elbow.
The moment of a force is calculated by multiplying the force by the perpendicular distance between the force & the point where the moment is measured. Since the weight remains the same and the perpendicular distance between the weight and the shoulder and elbow are the same: the moment exerted by the weight on both points is equal. This is important information for understanding the mechanics of the body and how forces affect different points.
No picture is provided. However, the answer might still be relevant.
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When a solid goes directly to a gas, which process amongst the following processes best describe the phase change?
(a) Sublimation
(b) Vaporization
(c) Condensation
(d) Deposition
(e) Melting
The correct option is A. Sublimation process amongst the When a solid goes directly to a gas.
Sublimation refers to the process of transforming a substance from its solid state directly into its gaseous state without passing through the intermediate liquid state. This occurs when the pressure of the substance's vapor is higher than the pressure of the surrounding atmosphere.
Sublimation is a physical phenomenon that occurs naturally in a number of substances, such as dry ice (solid carbon dioxide), mothballs (solid naphthalene), and snow (solid water). It is also used in various industrial processes, such as freeze-drying, where substances are dried by freezing them and then removing the ice through sublimation.
In psychology, sublimation refers to the redirection of an individual's impulses or desires into socially acceptable outlets, such as artistic or creative pursuits, instead of expressing them in destructive or harmful ways. Sigmund Freud, the founder of psychoanalysis, believed that sublimation was a healthy and adaptive defense mechanism.
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how do you earn muscle to go on monkey bars
All you need is to be able to pull your weight up and you can use to monkey bars
Explanation:
determine the load indicated by the spring scale and the mass needed to balance the lever scale when the elevator moves upward with an acceleration of 1 m/s2.
The load indicated by the spring scale is equal to the mass times the acceleration, so the load indicated by the spring scale is 1 kg x 1 m/s2 = 1 kg.
What is acceleration?Acceleration is the rate of change of velocity of an object. It is the rate at which something speeds up or slows down, and is usually denoted by the variable 'a'. Acceleration can be positive, negative, or zero. Positive acceleration indicates an increase in velocity while negative acceleration indicates a decrease in velocity. Acceleration can be caused by a variety of external forces, such as gravity, friction, or thrust. It is also related to momentum, as an object with a greater mass will require more force to accelerate. In general, acceleration is measured in meters per second squared (m/s2).
The mass needed to balance the lever scale is equal to the load on the spring scale divided by the acceleration, so the mass needed to balance the lever scale is 1 kg/1 m/s2 = 1 kg.
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Calculate the Tangential Velocity of a ball with mass 0. 50 kg rolling in a circle with a radius of
0. 75m, if it makes a complete circle in 12s
The required tangential velocity of the ball with a mass of 0.50 kg rolling in a circle with a radius of 0.75 m and completing a circle in 12 secs is 0.4 m/s.
Any object moving along a circular path has a linear component to its speed called tangential velocity. When an object moves in a circular path at a distance r from the centre, then the body’s velocity is directed tangentially at any instant. This is termed tangential velocity.
The ball weighs m = 0.50 kg
r = 0.75 m is the radius of the circle
The time is taken by the ball to complete the circle, t = 12 secs
The tangential velocity is given as, v = 2πr/t,
v = 2π × 0.75/12 = 0.4 m/s
Thus, the required tangential velocity of the ball is calculated to be 0.4 m/s.
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A satellite is staged on a rocket and has a height of 110m and a mass of 1,200 kg. What is the GPE (gravitational potential energy) of the satellite before it is launched? ( g=9.8m/s^2)
The formula for gravitational potential energy (GPE) is GPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.
Substituting the values for the satellite, we get:
GPE = 1,200 kg × 9.8 m/[tex]s^{2}[/tex] × 110 m = 132,160 kg[tex]m^{2} /s^{2}[/tex]
So, the GPE of the satellite before it is launched is 132,160 kg[tex]m^{2} /s^{2}[/tex].
What is gravitational potential energy?The energy that an item stores as a result of its position in relation to another enormous object, such as the Earth, is known as gravitational potential energy. The mass, separation between the two items, and the gravitational force between them are all factors that affect an object's potential energy. When an object is lifted higher, its potential energy rises since an object at rest on the ground has zero potential energy. The potential energy of the object is transformed into kinetic energy, or the energy of motion when it is dropped. Gravitational potential energy, in its simplest form, is a measurement of the energy that a body holds as a result of its location inside a gravitational field.
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the temperature of an object is raised by 120° Celsius the resulting increase in its absolute temperature is
The absolute temperature is 393 K
How do you obtain the absolute temperature?Absolute temperature is a temperature scale that starts at absolute zero, which is the temperature at which all matter has zero thermal energy. The most commonly used absolute temperature scale is the Kelvin scale. The conversion from Celsius or Fahrenheit to Kelvin can be done using the following formulas:
Kelvin = Celsius + 273
Here we would have that;
T = 120° Celsius + 273 = 393 K
This is the absolute temperature that we seek.
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a tennis ball bounces on the floor. during each bounce, it loses 31 % of its energy due to heating. how high does the ball reach after the third bounce, if it is initially released 4 m from the floor?
The ball reaches a height of 1.38 m after the third bounce, if it is initially released 4 m from the floor.
What is height?
Height is a measurement of vertical distance or elevation. It is usually defined as the distance from a reference point, such as the ground or sea level, to a point of interest, such as the top of a building, a mountain, or an object. Height can be measured in various units, including meters, feet, and inches.
To find the height of the ball after the third bounce, we can calculate the height of the ball after each bounce and multiply by a factor that takes into account the loss of energy due to heating.
After the first bounce, the ball will lose 31% of its energy, so it will have only 69% of its initial energy. We can calculate the height of the ball after the first bounce by assuming that the ball's potential energy is equal to its initial height multiplied by its weight and subtracting the energy loss due to heating:
PE = mgh
h = PE / (mg)
h = (0.69 * 4 m * 9.8 m/s^2) / (0.06 kg * 9.8 m/s^2) = 2.86 m
After the second bounce, the ball will lose another 31% of its energy, so it will have only 69% of its energy after the first bounce. We can calculate the height of the ball after the second bounce using the same process:
h = (0.69 * 2.86 m * 9.8 m/s^2) / (0.06 kg * 9.8 m/s^2) = 2.01 m
After the third bounce, the ball will lose another 31% of its energy, so it will have only 69% of its energy after the second bounce. We can calculate the height of the ball after the third bounce using the same process:
h = (0.69 * 2.01 m * 9.8 m/s^2) / (0.06 kg * 9.8 m/s^2) = 1.38 m
So, the ball reaches a height of 1.38 m after the third bounce, if it is initially released 4 m from the floor.
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a student's calculation was found to have a 35.5 % error, and his experimental measurement was 15.6 cm. what are the two true/actual measurements?
A student's calculation was found to have a 35.5 % error, and his experimental measurement was 15.6 cm. The two true/actual measurements are 24.19 and 11.53.
Let x and y be the two possible real measurements, with x being less than 15.6 and y being more than 15.6.
x + 35.5% of x = 15.6
y-35.5% of y
35.5% as decimal is 0.355
x + 0.355x = 15.6 , and
y - 0.355y = 15.6
Solving
x + 0.355x = 15.6
1.355x = 15.6
x = [tex]\frac{15.6}{1.355}[/tex] = 11.53
Solving
y - 0.355x = 15.6
0.645y=15.6
0.645y = 15.6
y = 24.19
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two point charges exert a 2.50 n force on each other. what will the force (in n) become if the distance between them is increased by a factor of 4?
If the 2 point charges exert a 2.50 N force on each other , and if distance between them is increased by a factor of 4 , then the Force is 0.15625 N.
The Force between two point charges is calculated by Coulomb's law ; that is represented as ⇒ F = k×(q₁×q₂)/r² ;
where F is = force, k is = Coulomb constant (8.99 × 10⁹ N×m²/C²),
q₁ and q₂ are the magnitudes of the two charges, and r is = distance between them.
If the distance between the charges is increased by a factor of 4, then r will become 4 times larger.
So, force will decrease by a factor of 4² = 16 ;
The new force(F') will be F' = k×(q₁ × q₂)/(4r)²
= k × (q₁ × q₂)/16r²
= F/16
So, if the original force was 2.50 N, the new force will become 2.50/16 = 0.15625 N.
The given question is incomplete , the complete question is
Two point charges exert a 2.50 N force on each other. What will the force (in N) become if the distance between them is increased by a factor of 4 ?
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Two forces of magnitude 10N each . Their resultant is equal to 20N . Then angle between them is
Answer:
0°
Explanation:
refer to the attachment
hope this helps!
A runner dashes 248 m in a direction due North from the starting line (x; = 0 m). She then
turns around and runs due South back toward the starting line 97 m.
If both legs of this run take a total of 130 seconds, to the nearest tenth of a m/s, what is her
average velocity?
K
Her average velocity is 2.65 m/s to the nearest tenth of a m/s.
What is average velocity?The measure of average velocity is a vector. Average velocity is calculated by dividing the change in position or displacement (x) by the time intervals (t) during which the displacement takes place. Depending on the direction of the displacement, the average velocity may be positive or negative. Meters per second (m/s or ms-1) is the SI unit for average speed.
Only the object's displacement is considered when calculating average velocity. However, the displacement's size might differ from the actual path's length. For this reason, we use average speed to describe the rate of motion along a path.
Average speed is calculated by dividing the total distance travelled by the total motion time. The average speed is a scalar quantity, in contrast to the average velocity.
Given distance: 248
and = 345 m
Time for both= 130 s
We know that average velocity = Distance + Distance / time
Therefore,
Average velocity = (248 + 97) / (130)
Average velocity = 69/26
Average velocity = 2.65 m/s
Thus, her average velocity is 2.65 m/s to the nearest tenth of a m/s.
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The original pressure of a gas was 2.5 atmospheres. When the pressure was decreased to 1.7 atmospheres, the volume increased to 850 mL. What was the original volume? Make sure that you show your work and use the proper units.
Taking into account the Boyle's law, the original pressure of a gas was 2.5 atmospheres and the original volume was 578 mL.
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. This is because when the volume decreases, the distance that the particles have to travel is less and therefore more shocks occur in each unit of time, that is, the pressure increases.
Mathematically, if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:
P×V= k
where:
P is the pressure.V is the volume.k is a constant.Being an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁= P₂×V₂
Original volumeIn this case, you know:
P₁= 2.5 atmV₁= ?P₂= 1.7 atmV₂= 850 mLReplacing in Boyle's law:
2.5 atm ×V₁= 1.7 atm ×850 mL
Solving:
V₁= (1.7 atm ×850 mL)÷ 2.5 atm
V₁= 578 mL
The original volume was 578 mL.
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What is a major impact of climate change for fish species? (1 point)
O shifting ocean currents
O too much carbon dioxide in water
O food toxicity
O changes in ocean habitat
Answer:
Changes in ocean habitat.
Explanation:
Climate change has a major impact on fish species by changing the conditions of the oceans where they live.
An object accelerates uniformly from rest to a speed of50 meters per second in 5.0 seconds. The average speed ofthe object during the 5.0-second interval isA 5.0 m/sB 10 m/sC 25 m/sD 50 m/s
The average speed ofthe object during the 5.0-second interval is 25m/s.
The average speed of an object is calculated by taking the total distance traveled in a given time interval, and dividing it by the time interval. Average speed is used to measure the speed of a person, vehicle, or object over a given period of time. Average speed can also be used to compare the performance of different vehicles over the same distance.In this case, the object accelerates uniformly from rest to a speed of 50 m/s in 5.0 seconds.
The total distance traveled in this time interval is 250 meters
[tex]50 m/s * 5.0 s = 250 m[/tex]
The average speed of the object during the 5.0-second interval is then [tex]\frac{250 m }{ 5.0 s }= 25 m/s.[/tex]
Therefore,The average speed ofthe object during the 5.0-second interval is 25m/s.
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the voltage across a membrane forming a cell wall is 76 mv and the membrane is 7.75 nm thick. show answer no attempt what is the electric field strength in the cell wall, in volts per meter?
In terms of volts per metre, the electric field strength in the cell wall is 9.8 105V/m.
What exactly is a "electric field"?When charge is present in any form, a point in space has an electric field that is connected to it. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
voltage v= 76 mV
Membrane thickness d=7.75 nm
To find
Electric field strength E=?
Electric field strength =voltage/Membrane thickness
E = v/d
E = 76×10⁻³/7.75×10⁻⁹
E = 76×10⁷/775
E = 7600ₓ10⁵/775
E = 9.8×10⁵V/m
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