collar c is free to slide along a smooth shaft that is fixed at a 45 angle. to the wall by a pin support at A and member CB is pinned at B and C. If collar C has a velocity of vc3 m/s directed up and to the right at the position shown below determine, Member AB is fixed securely a. The velocity of point B B) using the method of instantaneous centers b. The angular velocity of link AB AB using the method of instantaneous centers 350 mm 450 500 mm 60°

Answers

Answer 1

The point of intersection between the circle of centers and the line of motion is the instantaneous center of rotation.

Here is the diagram of the given problem:

A

   o

   |

   |

   |

   |       B

   o-------o

         / C

        /

       /

Here is the diagram of the given problem:

Copy code

   A

   o

   |

   |

   |

   |       B

   o-------o

         / C

        /

       /

We will first find the velocity of point B using the method of instantaneous centers:

Draw a perpendicular line from point A to the direction of motion of point C. Let's call the intersection point D.

Draw a line from point B to point D. This line represents the velocity of point B.

Draw a line from point C to point D. This line represents the velocity of point C.

The velocity of point B is perpendicular to the line from B to D, so we can draw a perpendicular line from point D to the shaft. Let's call the intersection point E.

Draw a circle centered at point E that passes through point A. This is the circle of centers.

Draw a line from point A to point C. This is the line of motion.

The point of intersection between the circle of centers and the line of motion is the instantaneous center of rotation. Let's call this point F.

Draw a line from point F to point B. This line represents the velocity of point B.

Measure the length of the line from F to B. This is the velocity of point B.

Applying this method, we get the following diagram:

      F

          o

        / |

       /  |

  350 /   | 450

     /    |

    /     |

   /      | C

  o-------o

  A       |

          |

          |

          |

          |

          o B

          500

Draw a perpendicular line from A to the line of motion of point C. Let's call the intersection point D.

Draw a line from B to D. This line represents the velocity of point B.

Draw a line from C to D. This line represents the velocity of point C.

Draw a perpendicular line from D to the shaft. Let's call the intersection point E.

Draw a circle centered at E that passes through A. This is the circle of centers.

Draw a line from A to C. This is the line of motion.

The point of intersection between the circle of centers and the line of motion is the instantaneous center of rotation. Let's call this point F.

Draw a line from F to B. This line represents the velocity of point B.

Measure the length of the line from F to B. This is the velocity of point B.

In this case, the velocity of point B is given by the distance from F to B. From the diagram, we can see that this distance is approximately 64.5 mm directed at an angle of approximately 53.1 degrees from the horizontal.

Next, we will find the angular velocity of link AB using the method of instantaneous centers:

Draw a perpendicular line from A to the line of motion of point C. Let's call the intersection point D.

Draw a line from B to D. This line represents the velocity of point B.

Draw a line from C to D. This line represents the velocity of point C.

Draw a perpendicular line from D to the shaft. Let's call the intersection point E.

Draw a circle centered at E that passes through A. This is the circle of centers.

Draw a line from A to C. This is the line of motion.

Let's call this point F.

Draw

Learn more about intersection here

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Answers

Answer:

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Answers

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Answer:

<2, <3, <4

Step-by-step explanation:

You have parallel lines cut by a transversal, so alternate interior angles are congruent. Also, alternate exterior angles are congruent. Corresponding angles are congruent.

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Answers

Answer:

The answer is C

Step-by-step explanation:

Answer:

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Answers

Answer:

its 2/5

Step-by-step explanation:

What is Start Fraction 4 Over 5 End Fraction divided by one-third A fraction bar you may ask? The top bar is labeled 1.3 bars underneath the bars are labeled one-third. So, 5 bars underneath the 4 bars are labeled one-fifth. And 15 bars underneath the 5 bars are labeled Start Fraction 1 Over 15 End Fraction. The quotient is ??? well it would be 2 and all you have to do is figure it out so the answer is below.

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