Circle the reactant that is a nucleophile and draw the mechanism using the appropriate arrows for the following reaction.

Answers

Answer 1

It is a tertiary alkyl halide that is being supplied. It will easily go through the SN1 replacement. The following steps will lead to the reaction(Attached).

A reactant known as a nucleophile provides an electron pair in order to create a covalent bond. Typically, a nucleophile has a negative charge or is neutral with one or two donatable electrons. Some examples include H2O, -OMe, or -OtBu. The species with a lot of electrons is a nucleophile overall.

A nucleophile typically has one electron pair and is negatively charged or neutral. Some examples include H2O, -OMe, or -OtBu. The species with a lot of electrons is a nucleophile overall. Generally speaking, electrophiles are positively charged or neutral organisms with vacant orbitals that are drawn to an electron-rich center.

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Circle The Reactant That Is A Nucleophile And Draw The Mechanism Using The Appropriate Arrows For The

Related Questions

Estimate how much heat in joules is released when 25.0 g of water (C = 4.184 J/g°C) is cooled from 80.0°C to 30.0°C?

Answers

Answer:

5230 J

Explanation:

m = 25 g = 0,025 kg

c = 4,184 J /(g * °C) = 4184 J /(kg * °C)

[tex]t_{1}[/tex] = 80 °C

[tex]t_{2}[/tex] = 30 °C

The formula is Q = c *m * ([tex]t_{2} - t_{1}[/tex])

Calculating:

Q = 4184 * 0,025 * (30 - 80) = 5230 J

Note that we get a negative heat (-5230 J). It just means that it is released.

The amount of heat will be 5230 j.

What is heat?

Heat is a type of energy that is transferred between both the system and its surroundings as a result of temperature variations.

Calculation of heat.

Given data:

Mass = 25.0 g = 0.025 kg

C = 4.184 J/g°C

[tex]T_{1}[/tex] = 80.0°C

[tex]T_{2}[/tex] = 30.0°C

Q= ?

By using the formula of heat.

Q = MC ([tex]T_{2} - T_{1}[/tex])

Put the value of given data in heat equation.

Q(heat) = 0.025 × 4.184 ( 30 - 80)

Q(heat) = 5230 J.

Therefore, the amount of heat will be 5230 J.

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A sample of polystyrene, which has a specific heat capacity of 1.880 J.g .Â°C , is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The polystyrene sample starts off at 94.9 Â°C and the temperature of the water starts off at 22.0 When the temperature of the water stops changing it's 27.7 Â°C. The pressure remains constant at 1 atm. Calculate the mass of the polystyrene sample.

Answers

Answer:

56.6g

Explanation:

Given that :

Mass of water, m1= 300.0 g

Temperature of water, T1= 22°C

Specific heat capacity of water, C= 4.184 J/g°C

Mass of polystyrene, m2=?

Temperature of polystyrene = 94.9

Specific heat capacity of polystyrene, c2= 1.88 J/g°C

Final temperature = 27.7 oC

Heat lost by polystyrene = Heat gained by water

mc(dT) = mc(dT)

m2 * 1.88 * (94.9 - 27.7) = 300 * 4.184 * (27.7 - 22)

m2 * 1.88*67.2 = 300*4.184*5.7

126.336 * m2 = 7154.64

m2 = 7154.64 / 126.336

m2 = 56.631838

Hence, mass of polystyrene = 56.6g

i don’t understand this please help!!!

Answers

Answer:

Numbers after atoms are subscripts. Numbers before atoms are coefficients.

Equation: 2Na +Cl2 -> 2NaCl

Given: 6.8 grams of Na

Unknown: moles of NaCl

Set up: [tex]6.8g Na *\frac{1 mole Na}{22.99 g Na}*\frac{2 moles NaCl}{2 moles Na} =.2957 moles NaCl[/tex]

Explanation:

We know that the reactants are Na and Cl and that what is being produced, the products, is NaCl.

Na + Cl -> NaCl

CAREFUL! Cl is a diatomic ion, is it gets a subscript of 2! This means there need to be 2 cl atoms on the right side as well. But now there are 2 Na on the right side. So we multiply Na by 2 on the left so that both sides have two Na atoms.

2Na +Cl2 -> 2NaCl

We know that there are 6.8 grams of Na. This is our given.

What do we want to find out? We want to find how many moles of NaCl there are, so that is our unknown.

C) A mole ratio is exactly what it sounds like. From our balanced equation, we can see that there are 2 moles of Na and 2 moles of NaCl. In other words, there are 2 moles of Na for every 2 moles Nacl. In notation, this is [tex]\frac{2 mole Na}{2 Mole NaCl}[/tex] or 2:2. You can simplify to 1:1 ratio, but as equations get more complex I find it easier to not. It depends on what your teacher wants and what you find easier.

By set up I assume they mean stoichiometry (chemistry conversion) . First I'm going to split up the set up so that it is easier to understand.

We start with the given and convert that into moles Na. We can do this by remembering that there are 22.99 grams for every 1 mole Na:

6.8 g Na* [tex]\frac{1 mole Na}{22.99g Na} = .2957 moles Na[/tex]

Now we can use that mole ration we found in part C to convert moles of Na into moles of NaCl:

[tex].2957 moles Na *\frac{2 moles NaCl}{2 moles Na}= .2957[/tex]

Usually, we will put these together to get

[tex]6.8g Na *\frac{1 mole Na}{22.99 g Na}*\frac{2 moles NaCl}{2 moles Na} =.2957 moles NaCl[/tex]

Tip: in Stoichiometry, it is important to remember that your units should cancel out until you only have the units you want. If there are moles of Na in the numerator, there should be moles of Na in the denominator of the following fraction. If there are grams Na in the numerator, there should be grams Na in the denominator and so and so on until you are only left with the unit you want, which, in this case, is moles of NaCl.

26. Find the volume of 111.6 grams of NH3 gas.

Answers

Answer:

It is 148.82 L

Explanation:

I need more points. And I hope this helps.

Lesson Question: What is the effect of
pressure on the volume of a gas?
To answer this question, you used weight to
change the pressure of the gas and
measured the
resulting changes to the gas's volume.
COMPLETE
The amount of gas (in terms of moles, mass, and
molecules):

Answers

Answer:

pressure

volume

was constant

Boyle's

Explanation:

Answer:

the first one is pressure &volume the second one is was constant the third one is Boyle's

Explanation:

A: A 21.3−g sample of dinitrogen monoxide is confined in a 5.76−L vessel. What is the pressure (in atm) at 111°C?

B: Find the density of Freon−11 (CFCl3) at 157°C and 4.65 atm.
g/L = ?

Answers

Answer:

A. 2.65 atm.

B. 18.11 g/L.

Explanation:

A. Determination of the pressure

Mass of N₂O = 21.3 g

Volume = 5.76 L

Temperature (T) = 111 °C

Pressure (P) =.?

First, we shall determine the number of mole in 21.3 g of dinitrogen monoxide, N₂O. This can be obtained as follow:

Mass of N₂O = 21.3 g

Molar mass of N₂O = (14×2) + 16

= 28 + 16

= 44 g/mol

Mole of N₂O =?

Mole = mass /Molar mass

Mole of N₂O = 21.3/44

Mole of N₂O = 0.484 mole

Next, we shall convert 111°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 111 °C

Temperature (T) = 111 °C + 273

Temperature (T) = 384 K

Finally, we shall determine the pressure. This can be obtained as follow:

Number mole of N₂O = 0.484 mole

Volume = 5.76 L

Temperature (T) = 384 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =.?

PV = nRT

P × 5.76 = 0.484 × 0.0821 × 384

Divide both side by 5.76

P = (0.484 × 0.0821 × 384) / 5.76

P = 2.65 atm

B. Determination of the density of CFCl₃

Temperature (T) = 157°C

Pressure (P) = 4.65 atm.

Density of CFCl₃ =?

First, we shall determine the molar mass of CFCl₃. This can be obtained as follow:

Molar mass of CFCl₃ = 12 + 19 + (35.5×3)

= 12 + 19 + 106.5

= 137.5 g/mol

Next, we shall convert 157°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 157 °C

Temperature (T) = 157 °C + 273

Temperature (T) = 430 K

Finally, we shall determine the density of CFCl₃. This can be obtained as follow:

Temperature (T) = 430 K

Pressure (P) = 4.65 atm.

Molar mass of CFCl₃ (M) = 137.5 g/mol

Gas constant (R) = 0.0821 atm.L/Kmol

Density (D) of CFCl₃ =?

D = PM / RT

D = (4.65 × 137.5) / (0.0821 × 430)

D = 18.11 g/L

Can metals take away electrons from non metals?

Answers

Answer:

Well no because if metals lose electrons, any non-metal sources/items gain electrons from the metal.

Answer:

Metals tend to lose electrons and non-metals tend to gain electrons, so in reactions involving these two groups, there is electron transfer from the metal to the non-metal

Explanation:

Which is the correct Lewis structure for acetylene (C2H2)?

Answers

Answer:

The answer is H-C≡C-H

Explanation:

4 moles of monoatomic ideal gas is compressed adiabatically causing the temperature to increase from 300 K to 400 K. Calculate the work done on the gas in units of Joules (if the answer is negative, be sure to enter a negative sign in your answer).

Answers

Answer:

the work done on the gas is 4,988.7 J.

Explanation:

Given;

number of moles of the monoatomic gas, n = 4 moles

initial temperature of the gas, T₁ = 300 K

final temperature of the gas, T₂ = 400 K

The work done on the gas is calculated as;

[tex]W = \Delta U = nC_v(T_2 -T_1)[/tex]

For monoatomic ideal gas: [tex]C_v = \frac{3}{2} R[/tex]

[tex]W = \frac{3}{2} R \times n(T_2-T_1)[/tex]

Where;

R is ideal gas constant = 8.3145 J/K.mol

[tex]W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W = \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J[/tex]

Therefore, the work done on the gas is 4,988.7 J.

Convert 392 K into Celsius.

Your answer should have three significant figures (round your answer to the nearest whole number).
Use −273∘C for absolute zero.

Answers

Answer:

118.85 degrees celsius (not sure if it is)

Answer:

118 is correct

Explanation:

Am I right????????????????Btw question was “Name four abiotic factors shown in the above prairie ecosystem?

Answers

Rocks soil water and air

The answer would be air,rocks,water,soils because the prefix a on abiotic means non so non-biotic

Hope this helps

Have a great day/night

Feel free to ask any questions

Pleaseee I need help and it is urgent

Answers

Answer:

1)4180j

Answer:

0.093 M

Explanation:

First, we assume that the density of household hydrogen peroxide is 1 g/mL. We also assume that there's no reaction between hydrogen peroxide and sodium carbonate, if there were, in the end all hydrogen peroxide would be consumed.

Now we calculate how many grams of H₂O₂ were added, using the given volume, concentration and density:

15 mL * [tex]\frac{1gSolution}{1mL}*\frac{3gH_2O_2}{100gSolution}[/tex] = 0.45 g H₂O₂

We convert grams to moles:

0.45 g H₂O₂ ÷ 34 g/mol = 0.013 mol H₂O₂

Now we divide the number of moles by the final volume, to calculate the molarity of H₂O₂:

Final Volume = 15 mL + 120 mL + 5 mL = 140 mL140 mL / 1000 = 0.140 LMolarity = 0.013 mol H₂O₂ / 0.140 L = 0.093 M

Based on the given concentration of the original hydrogen peroxide solution, the molarity of the hydrogen peroxide (in mol/L) of the final solution is 0.093 M.

What is the concentration of the hydrogen peroxide solution?

Assuming that the density of household hydrogen peroxide is 1 g/mL and that no reaction occurs between hydrogen peroxide and sodium carbonate.

The mass in grams of H₂O₂ added is first determined using the given volume, concentration and density:

mass = volume * density * concentration

mass = 15 mL * 1 g/mL * 3g/100g = 0.45 g H₂O₂

Moles of H₂O₂ is determined as follows:

moles = mass /molar mass

molar mass of H₂O₂ = 34 g/mol

moles of H₂O₂ = 0.45 g H₂O₂ / 34 g/mol

moles of H₂O₂ = 0.013 mol H₂O₂

molarity of H₂O₂ is then calculated as follows:

molarity = moles/volume in L

final volume = 15 mL + 120 mL + 5 mL = 140 mL

final volume = 140 mL / 1000 = 0.140 L

molarity = 0.013 mol H₂O₂ / 0.140 L

molarity of H₂O₂ = 0.093 M

Therefore, the molarity of the hydrogen peroxide (in mol/L) of the final solution is 0.093 M.

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how to rapidly separate red#40 from ZnO

Answers

Answer:

your question :

how to rapidly separate red#40 from ZnO

answer :

Red #40 is soluble in water while zinc oxide is not. 4- heat the solution of red #40 and water until water evaporates and red#40 remains

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Please help I’m so confused on this it’s stoichiometry

Answers

Answer:

48.27g Na

Explanation:

To start we need to balance the equation. The trick is to make sure both sides have equal amounts of each atom:

2Na + Cl2 --> 2NaCl

Now we can use sociometry

We have 75 g of Cl2, and for every 1 mole of Cl2, there are 70.9 grams:

[tex]75g Cl2 * \frac{1mole Cl2}{70.9g Cl2}= 1.05 mole Cl2[/tex]

Now we have moles of Cl2. To get to grams of Na, we need to first use mole to mole ratio:

[tex]1.05mole Cl2 *\frac{2 mole Na}{1 mole Cl2} =2.1 mole Na[/tex]

From here we convert moles of Na into grams of Na

[tex]2.1mol Na*\frac{22.99g Na}{1 mole Na} = 48.27g Na[/tex]

It's usually easier to just make one singular equation with all of these smaller equations.

[tex]75gNa*\frac{1molCl2}{70.9gCl2} *\frac{2mol Na}{1 mol Cl2} *\frac{22.99g Na}{1 mol Na}=48.27 gNa[/tex]

The trick to sociometry is making sure your units cancel out until you only have the unit you want. If there are moles of Na in the numerator, there needs to be moles of Na in the denominator. If there are grams of Cl2 in the numerator, there needs to be grams of Cl2 in the denominator and so one and so on

(feso4.(Nh4) So4. 6H2o) +Kmno4+H2So4_Fe2(So4)3+K2So4+mnSo4+(Nh4)2So4+H2o

Answers

Answer:

Answer:

Explanation:

Correct on Edge

All of the following are physical changes except
A. ice melting.
B. plaster hardening.
C. paint drying.
D. rocket fuel burning.

Answers

Answer:

rocket fuel burning i think

You have two compounds that you have spotted on a TLC plate. One compound is more polar than the other. You run the TLC plate with neat hexanes and find that only one spot moved a small distance up the plate. Next you made a 50/50 mixture of hexanes and ethyl acetate. What might you expect to see on your TLC plate (what would the spots do)?

Answers

Answer:

The two spots will move up the plate.

Explanation:

We have to first understand the rudiments of chromatography. In chromatography, there is a stationary phase and a mobile phase. The stationary phase does not move. In this case, the stationary phase is the TLC plate.

The mobile phase is the solvent used to perform the chromatography. The movement of the spots depends on the composition of the solvent.

When neat hexane was used, only one spot was moved. This must be due to the interaction of the nonpolar hexane with the less polar compound. However, when a 50/50 mixture of hexanes and ethyl acetate is used, the both compounds are found to move up the plate.

a)
Name the following compounds
CH, -CH-CH
(i)
CH, Br
-

Answers

Answer:

methyl, ethyl,

Explanation:

that should be the case

Explain why anhydrous aluminium chloride is fairly soluble in organic solvent while anhydrous magnesium chloride is insoluble

Answers

Aluminium chloride is covalent hence soluble in organic solvent while magnesium chloride being ionic is insoluble in organic solvent

AlCl3 takes electrons from other atoms very ease in an effort to complete its valence shell, which consists of eight electrons. Because of this, it typically acts like a Lewis acid. The Al atom accepts a single pair of electrons from a Cl atom in the reaction shown below.Aluminium chloride is covalent hence soluble in organic solvent while magnesium chloride being ionic is insoluble in organic solvent.AlCl3 is soluble in organic solvents , freely soluble in many organic solvents, such as benzophenone, nitrobenzene.Is AlCl3 soluble or insoluble?AlCl3 is soluble in water.The reaction between AlCl3 and water is exothermic and aggressive.

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