Carolyn has 20 biscuits in a tin.
She has
12 plain biscuits
5 chocolate biscuits
3 ginger biscuits
Carolyn takes at random two biscuits from the tin.
Work out the probability that the two biscuits were not the same type.

4 Marks​

Answers

Answer 1

Answer:

Approximately 58.4%

Step-by-step explanation:

The probability that they are different is the opposite of the probability that they are the same.

The probability that they are the same is:

P(plain, plain) = (12/20) (11/19) = 132 / 380

P(chocolate, chocolate) = (5/20) (4/19) = 20 / 380

P(currant, currant) = (3/20) (2/19) = 6 / 380

P(same) = 132/380 + 20/380 + 6/380

P(same) = 158/380

P(same) = 79/190

Therefore, the probability that they are different is:

P(different) = 1 − 79/

Answer 2

[tex]\frac{111}{190}[/tex]  is the  probability that the two biscuits were of not the same type.

What is Probability?

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates certainty.

According to question, Carolyn has 20 biscuits in a tin.

She has 12 plain biscuits, 5 chocolate biscuits and 3 ginger biscuits

Carolyn takes at random two biscuits from the tin.

We have to find out  the probability that the two biscuits were of  not the same type.

             P(plain biscuit, plain biscuit)  [tex]=(\frac{12}{20} )(\frac{11}{19} )=\frac{132}{380}[/tex]

P(chocolate biscuit, chocolate biscuit)[tex]=(\frac{5}{20})(\frac{4}{19} )=\frac{20}{380}[/tex]

          P(ginger biscuit, ginger biscuit)[tex]=(\frac{3}{20}) (\frac{2}{19})=\frac{6}{380}[/tex]

Probability of same type of biscuits

[tex]=\frac{132}{380} +\frac{20}{380}+\frac{6}{380}[/tex]

[tex]=\frac{79}{190}[/tex]

The probability that the two biscuits were not of the same type.

[tex]=1-\frac{79}{190}[/tex]

[tex]=\frac{111}{190}[/tex]

Hence, we can conclude that [tex]\frac{111}{190}[/tex]  is the  probability that the two biscuits were not of the same type.

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(

x

)

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