Answer:
The density is 0.0625 g/cm³
Explanation:
In order to find the density, you have to use its formula, ρ = mass/volume. Then substitute the following values into the formula :
[tex]ρ = \frac{mass}{volume} [/tex]
Let mass = 108g,
Let volume = (12³)cm³ = 1728cm³,
[tex]ρ = \frac{108}{1728} [/tex]
[tex]ρ = \frac{1}{16} [/tex]
[tex]ρ = 0.0625g / {cm}^{3} [/tex]
Would you recommend storing nuclear waste near natural resources? Explain why or why not.
Answer:
No
Explanation
I say no because that could possibly put many species of animals i danger of nuclear reaction. Not only would it put many animals in danger it would put humans plant and most likely make that area a toxic waste for years
Answer:
No
Explanation:
You are given a piece of paper and a match. The paper has a mass of 2.5 g. You then light the match and light the piece of paper on fire. After it burns, the remaining bits of paper weigh 0.5 g. Does this demonstration violate the conservation of mass? Explain why or why not?
Answer:
No
Explanation:
No. The demonstration does not violate the conservation of mass.
The law of conservation of mass states that mass can neither be created nor destroyed in a reaction. However, mass can be converted from one form to another during the reaction.
In this case, even though the remaining bits of paper weigh 0.5 g while the original paper weighed 2.5 g, the ashes and smoke/gas from the burning will all add up to the lost weight of the paper.
The burned part has been converted into other forms. If the smoke/gas and the ashes are properly captured, they will mark up with the weight of the remaining paper to give the weight of the original paper.
The answer to the question on whether the burning violates the law of conservation of mass, we say that;
No, the demonstration does not violate the conservation of mass because the mass formed still adds up to the original mass.
The law of conservation of mass states that mass in an isolated system, matter can neither be created nor destroyed by chemical reactions or physical transformations. However, it could involve change in mass from one form to another.
Now, we are told that the remaining bits of paper has a mass of 0.5 g while the original paper has a mass 2.5 g. The reason why the mass left is 0.5 kg is because the ashes and smoke from the burning will add up to give the original weight of the paper.
Thus, since when the ashes, and smoke add up to still give the original mass of 3.5 g, it means that the mass is neither created nor destroyed
Read more about law of conservation of mass at; https://brainly.com/question/7041730
1. Which type of organic compound is represented by the structural formula shown below?
a) Ether
b) Ester
C) Alcohol
d) Aldehyde
Answer:
c. alcohol
Explanation:
Alcohol is -OH
Ether is -OR
Ester is O=C-OR
Aldehyde is O=C-H
- Only alcohol fits
Alcohol is the type of organic compound is represented by the structural formula.
What is Alcohol?This can be defined as the type of organic compound that carries at least one hydroxyl functional group (−OH) bound to a saturated carbon atom.
The hydroxyl group(OH) is attached to a Carbon atom in the diagram which depicts features of an Alcohol.
Read more about Alcohol here https://brainly.com/question/13621129
Water's unusual properties are primarily due to
a molecular geometry
b small molar mass
c chemical reactivity
d hydrogen bonding
Answer:
D hydrogen bonding
Explanation:
5. 54 J of heat is required to raise the temperature of a 2.47g unknown substance from 17.10C to 46.70C. a) Calculate the specific heat of the substance b) What is the substance
Answer:
C = 0.7385J/g°C
Explanation:
Heat energy (Q) = 54J
Mass (m) = 2.47g
Initial temperature (T1) = 17.10°C
Final temperature (T2) = 46.70°C
Specific heat capacity of substance (c) = ?
Heat energy of a substance (Q) = Mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature of substance = T2 - T1
Q = mc∇T
Q = mc (T2 - T1)
54 = 2.47 * c * (46.70 - 17.10)
54 = 2.47 * 29.6 * c
54 = 73.112c
C = 54 / 73.112
C = 0.7385
Specific heat capacity of the substance is 0.7385J/g°C
B.
The specific heat capacity of the above substance does not match any metal in the periodic table, however the closest to it was potassium with a value of 0.7536J/g°C and silicone with value of 0.711756J/g°C
Answer:
The specific heat of the substance is 0.739 J/g°C
The substance can be glass or SiO2
Explanation:
Step 1: Data given
Heat required = 54 J
Mass of the substance = 2.47 grams
Initial temperature = 17.10 °C
Final temperature = 46.70 °C
Step 2: Calculate the specific heat of the substance
Q = m*c¨*ΔT
⇒with Q = the heat required =54 J
⇒with m = the mass of the substance = 2.47 grams
⇒with c = the specific heat of the substance = TO BE DETERMINED
⇒with ΔT = the change of temperature = T2 - T1 = 46.70 - 17.10 = 29.60 °C
c = Q / (m*ΔT)
c = 54 / (2.47 * 29.60)
c = 0.739 J/g°C
The specific heat of the substance is 0.739 J/g°C
The substance can be glass or SiO2
when two atoms of the same nonmetal react, they often form?
Answer:
a diatomic molecule
Explanation: