Can someone help me with this question an my other work?

Answer:

All of them are in the domain.

Step-by-step explanation:

The function is f(x)= (x+1)^2. If you simplify this, you get y=x^2+2x+1=0. This is a quadratic that opens upwards. There are no gaps in the x values and no impossible values. The domain is all real numbers and all the answer choices are real numbers.

Answer:

Can not be solved

Step-by-step explanation:

5x+10y = 3............. Equation 1

10x+20y = 8 ............ Equation 2

From the equation above,

both equations can not be solved by elimination method, because both variables will be eliminated

Answer:

c ≈ 21

Step-by-step explanation:

By applying cosine rule in the given triangle ABC,

c² = a² + b² - 2abcos(C)

c² = (17)² + (10)² - 2(17)(10)cos(98.8°)

c² = 289 + 100 - 340(-0.1530)

c² = 441.015

c = 21

c ≈ 21

Answer:

Kevin is correct.

Step-by-step explanation:

3 girls + 5 boys = 8 students.

Answer:

he is incorrect since in a ratio you don't add them together instead what this ratio means is for every 3 girls there is 5 boys

Hope This Help!!!

Answer:

the answae is D THEN C THE. 1

B is the answer for this question hope it helps

Answer:

The answer is true

Step-by-step explanation:

Answer:

tgis moght help

Step-by-step explanation:

https://opentextbc.ca/introbusinessstatopenstax/chapter/full-hypothesis-test-examples/

Answer:

A, C and D are not polynomials

Step-by-step explanation:

A because the variable has a negative power.

C because the variable is in the denominator

D because the variable has a root.

When a variable has a root, it's power is 1/2 which does not count as an ideal polynomial. You might be wondering then that why E is a polynomial?

E is a polynomial because because the root is not on the variable but on the constant.

B and E are polynomials while A,C and D are not.

Please mark me as brainliest.

Answer:

The sample mean weight is 16.235 ounces, and the margin of error is 0.360 ounces

Step-by-step explanation:

To find the sample mean, we can find the mean of the confidence interval.

(15.875 + 16.595)/2 = 16.235

To find the margin of error, that is the difference between the mean and one of the edges of the confidence interval. 16.595 - 16.235 = 0.36

The sample mean weight is 16.235 ounces, and the margin of error is 0.360 ounces

Answer:

C. We are 90% confident that the interval from 15.875 ounces to 16.595 ounces captures the true mean weight of bags of grapes.

Step-by-step explanation:

Answer:

15c + 70b < 64,000

Step-by-step explanation:

15c will represent the amount of ounces in the truck from the 15 ounce cans.

70b will represent the amount of ounces in the truck from the 70 ounce bottles.

These need to be added together in the inequality to represent the total weight in the truck.

Then, a less than inequality sign needs to be used, since the truck has to be carrying less than 64,000 ounces.

Put this all together:

15c + 70b < 64,000

So, the inequality is 15c + 70b < 64,000

Answer:

[tex]-2[/tex]

Step-by-step explanation:

Just substitute -3 for all instances of x.

[tex](-3)^{2} + 4(-3) + 1\\\\[/tex]

[tex]9 - 12 + 1[/tex]

[tex]-2[/tex]

Answer:

D. Unimodal

Step-by-step explanation:

We can immediately tell the data is not symmetrical. That leaves B, C, D. The data of this histogram is also not uniform because the numbers vary- eliminating answer choice B. There are three modes of data distribution; unimodal, multimodal, and bimodal. The one demonstrated here is unimodal because there is one "hump" in the data distribution of the histogram and one mode.

The three modes of data distribution for visual context:

Answer:

7 hundred thousands, 5 ten thousands, 2 thousands, 8 hundreds, 6 tens, 3 ones

Step-by-step explanation:

to write a number in expanded notation all you need to do is write out the number in words.

Answer:

32 = a*2 +b

64 = a*3 + b

Then 32 = a

32 = 32*2 +b

b = - 32

So

Y = 32a - 32

Is the equation

Answer:

[tex]x=2[/tex]

Step-by-step explanation:

When given the following equation;

[tex]\frac{x+3}{3x-2}-\frac{x-3}{3x+2}=\frac{44}{9x^2-4}[/tex]

One has to solve for the variable (x). Remember, when working with fractions, one must have a common denominator in order to perform operations. Since the denominators on the left side of the equation are unlike, one must change them so that they are like denominators. Multiply each fraction by the other fraction's denominator on the respective side. Remember to multiply both the numerator and denominator by the value to ensure that the equation remains true.

[tex]=\frac{x+3}{3x-2}*(\frac{3x+2}{3x+2})-\frac{x-3}{3x+2}*(\frac{3x-2}{3x-2})=\frac{44}{9x^2-4}[/tex]

Simplify,

[tex]=\frac{(x+3)(3x+2)}{(3x-2)(3x+2)}-\frac{(x-3)(3x-2)}{(3x+2)(3x-2)}=\frac{44}{9x^2-4}\\\\=\frac{3x^2+11x+6}{9x^2-4}-\frac{3x^2-11x+6}{9x^2-4}=\frac{44}{9x^2-4}[/tex]

Distribute the negative sign to simplify the left side of the equation;

[tex]=\frac{3x^2+11x+6}{9x^2-4}-\frac{3x^2-11x+6}{9x^2-4}=\frac{44}{9x^2-4}\\\\=\frac{3x^2+11x+6-(3x^2-11x+6)}{9x^2-4}=\frac{44}{9x^2-4}\\\\=\frac{3x^2+11x+6-3x^2+11x-6}{9x^2-4}=\frac{44}{9x^2-4}\\\\=\frac{22x}{9x^2-4}{=\frac{44}{9x^2-4}[/tex]

Since the denominators on opposite sides of the equation are like, one can now ignore the denominators,

[tex]=22x=44[/tex]

Inverse operations,

[tex]=22x=44[/tex]

   ÷[tex]2[/tex]       ÷[tex]2[/tex]

     [tex]x=2[/tex]

Answer:

Range:

UCL = 4.73

LCL = 18.08

MEAN :

UCL = 27.115

LCL = 31.219

Step-by-step explanation:

Given the data:

The mean and range of each sample :

Sample __ Thread wear __ xbar __ R

1 ___31 __ 42 ___ 28 ____ 33.67 _14

2___ 26 _ 18 ____35____ 26.33 _17

3___25 __30 ___ 34____29.67 _ 9

4 __ 17 __ 25 ___ 21 _____ 21 ___ 8

5 __ 38 _ 29 ___ 35 _____ 34 __ 9

6 __ 41 __42 ___36 _____39.67_ 6

7 __ 21 __ 17 ___29 _____22.33 _12

8 __ 32 __26___28 ____ 28.67 _ 6

9 __ 41 __ 34 __ 33 ______ 36 __8

10__29___17___30 _____25.33_ 13

11 __26 __ 31 __ 40 _____32.33_ 14

12__23 __ 19 __ 45 _____12.33 __6

13 __17 __ 24 __ 32_____24.33__15

14 __43__ 35___17_____ 31.67 _ 26

15__18 ___25__ 29_____ 24 ___ 11

16__30___42___31 ____34.33__ 12

17__28___36 __ 32____ 32 ____8

18__40 __ 29 __ 31 ____33.33 __ 11

19__18 ___29__ 28____ 25 ____11

20_ 22 __ 34 __ 26 ___ 27.33 __12

Size per sample, sample size, n = 3

Number of samples, k = 20

We calculate the sample mean and range average :

Sample mean, x-- = Σxbar/n = 29.167

Range average, Rbar = ΣR/n = 11.4

The mean control limit :

x-- ± A2Rbar

From the x chart ;

A2 for n = 20 is A2 = 0.180

29.167 ± 0.180(11.40)

LCL = 29.167 - 0.180(11.40) = 27.115

UCL = 29.167 + 0.180(11.40) = 31.219

The Range control limit :

Rbar(1 ± 3(d3/d2))

From the R-chart :

d2 at n = 20 ; d2 = 3.735

d3 at n = 20 ; d3 = 0.729

LCL = 11.40(1 - 3(0.729/3.735)) = 4.725

UCL = 11.40(1 + 3(0.729/3.735)) = 18.075

Answer:

a. A linear pattern exists in the data.

b. The parameters for the line that minimizes MSE for this time series are as folows:

ß1 = Estimated slope = 1.4567

ß0 = Estimated intercept = 4.7165

Also, we have:

MSE = Mean squared error = 0.4896

c. Forecast for year 10 is 19,280.

Step-by-step explanation:

a. What type of pattern exists in the data?

Note: See Sheet1 of the attached excel file for the line graph.

From the line graph, it can be observed that a linear pattern exists in the data.

b. Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.

Note: See Sheet2 of the attached excel file for all the calculations to obtain the following:

Sample size = 9

Total of X = 45

Total of Y = 108

Mean of X = Total of X / Sample size = 45 / 9 = 5

Mean of Y = Total of X / Sample size = 108 / 9 = 12

SSxx = Total of (X - Mean of X)^2 = 60

SSyy = Total of (Y - Mean of Y)^2 = 130.74

SSxy = Total of (X - Mean of X) * (Y - Mean of Y) = 87.40

Therefore, we have:                

ß1 = Estimated slope = SSxy/SSxx = 87.4 / 60  = 1.4567

ß0 = Estimated intercept = Mean of Y – (ß1 * Mean of X) = 12 - (5 * 1.4567) = 4.7165

Therefore, the parameters for the line that minimizes MSE for this time series are as folows:

ß1 = Estimated slope = 1.4567

ß0 = Estimated intercept = 4.7165

Regression equation which also used in the attached excel is as follows:

Y = ß0 + ß1X =

Y = 4.7165 + 1.4567X …………………. (1)

SSE = Sum of squared error = Total of (Y - Y*)^2 = 3.4273

Therefore, we have:

MSE = Mean squared error = (SSE/(n-2)) = (3.4273 / (9 - 2)) = 0.4896

c. What is the forecast for year 10?

This implies that X = 10

Substitute X = 10 into equation (1), we have:

Y = 4.7165 + (1.4567 * 10) = 19.28

Since it is 1,000s, we have:

Y = 19.28 * 1,000 = 19,280

Therefore, forecast for year 10 is 19,280.

Answer:

79.8

Step-by-step explanation:

math

Answer:

16[tex]\sqrt{5}[/tex]

Step-by-step explanation:

[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]

16[tex]\sqrt{5}[/tex]

The perimeter of the square is 16√5 units.

We have,

The concept used here is straightforward: to find the perimeter of a square, you sum the lengths of all four sides because all sides of a square are equal in length.

In this case, the side length is given as 4√5, so you multiply it by 4 to calculate the total perimeter.

To find the perimeter (P) of a square with a side length of 4√5 units, you simply add up all four sides of the square, as all sides of a square are equal in length.

So,

P = 4 * side length

P = 4 * 4√5

P = 16√5 units

Thus,

The perimeter of the square is 16√5 units.

Learn more about squares here:

https://brainly.com/question/22964077

#SPJ3

Answer:

1 /2

Step-by-step explanation:

Given :

Bag 1 : Red (R) ; Blue (B) ; White (W)

Bag 2 : Red (R) ; Pink (P) ; Yellow (Y) ; Green (G)

Total number of possible outcomes :

3C1 * 4C1 = 3 * 4 = 12 outcomes

Sample space (S) ;

_______ R ______ B _______ W

R_____ RR _____ RB ______ RW

P_____ PR _____ PB ______ PW

Y _____YR_____ YB ______ YW

G _____GR ____ GB ______ GW

To win price of baked goods ; Atleast one red ball must be drawn :

Probability of winning ; P(winning) = required outcome / Total possible outcomes

Required outcome = {RR, RB, RW, PR, YR, GR} = 6

Total possible outcomes = S = 12

P(winning) = 6/12 = 1/2

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

Answer:

[tex]E(x)=\$9.118[/tex]

Step-by-step explanation:

From the question we are told that:

Available bills

 [tex]\$5=N0 9\\\\\$10=N0 5[/tex]

 [tex]\$20=N0 3[/tex]

Therefore

Total Bills

 [tex]n=5+9+3[/tex]

 [tex]n=17[/tex]

Probability of selecting each bill

 [tex]For\$5[/tex]

 [tex]P(\$5)=\frac{9}{17}[/tex]

 [tex]For\$10[/tex]

 [tex]P(\$10)=\frac{5}{17}[/tex]

 [tex]For\$20[/tex]

 [tex]P(\$20)=\frac{3}{17}[/tex]

Generally the equation for Expected winning is mathematically given by

 [tex]E(x)=\sum(X)*P(X)[/tex]

 [tex]E(x)=5*\frac{9}{17}+10*\frac{5}{17}+20*\frac{3}{17}[/tex]

 [tex]E(x)=\$9.118[/tex]

Answer:

width is also "inches"

Step-by-step explanation:

Answer:

x = 16

Step-by-step explanation:

The product of the lengths theorem is a property that can be sued to describe the relationships of the sides between the tangents and secants in a circle. One of these products states the following;

The distance between the point of tangency and its intersection point with the exterior secant squared is equal to the product of the exterior secant times the interior secant.

This essentially means the following equation can be formed;

[tex](AB)^2=(DC)(CB)[/tex]

Substitute,

[tex]12^2=x*9[/tex]

Simplify,

[tex]144=9x[/tex]

Inverse operations,

[tex]\frac{144}{9}=x\\\\16=x[/tex]

Answer:

[tex]\boxed{\sf x=7}[/tex]

Step-by-step explanation:

By Targent-secant theorem...

[tex]\sf 9(x + 9) = {12}^{2} [/tex]

Use the distributive property to multiply 9 by x+9.

[tex]\sf 9x+81= {12}^{2} [/tex]

Now, let calculate 12 to the power of 2 and get 144.

[tex]\sf 9x+81=144[/tex]

Subtract 81 from both sides.

[tex]\sf 9x=63[/tex]

Divide both sides by 9.

[tex] \sf \cfrac{ 9x}{9} = \cfrac{63}{9} [/tex]

[tex]\sf x=7[/tex]

Answer:

Hello friend kya in snap and p to Trisha

Answer:

Answer:Amy used 4 41-cent stamps and 8 6-cent stamps.

Step-by-step explanation:

Let x represent the number of 41-cent stamps that Amy used. Let y represent the number of 6-cent stamps that Amy used.

41 cents = 41/100 = $0.41

6 cents = 6/100 = $0.06

She uses 41-cent stamps and 6-cent stamps to pay $2.12 in postage. It means that

0.41x + 0.06y = 2.12

Multiplying through by 100, it becomes

41x + 6y = 212

6y = 212 -41x

We would test for corresponding values of x and y that satisfies the equation and they must be whole numbers.

If x = 3,

6y = 212 - 41 × 3 = 89

y = 89/6 = 14.8333

If x = 4,

6y = 212 - 41 × 4 = 48

y = 48/6 = 8

Answer:Amy used 4 41-cent stamps and 8 6-cent stamps.

Step-by-step explanation:

Let x represent the number of 41-cent stamps that Amy used. Let y represent the number of 6-cent stamps that Amy used.

41 cents = 41/100 = $0.41

6 cents = 6/100 = $0.06

She uses 41-cent stamps and 6-cent stamps to pay $2.12 in postage. It means that

0.41x + 0.06y = 2.12

Multiplying through by 100, it becomes

41x + 6y = 212

6y = 212 -41x

We would test for corresponding values of x and y that satisfies the equation and they must be whole numbers.

If x = 3,

6y = 212 - 41 × 3 = 89

y = 89/6 = 14.8333

If x = 4,

6y = 212 - 41 × 4 = 48

y = 48/6 = 8

Step-by-step explanation:

[tex]\dfrac{dy}{dx} = \dfrac{2x}{y(x^2 + 1)}[/tex]

Rearranging the terms, we get

[tex]ydy = \dfrac{2xdx}{x^2 + 1}[/tex]

We then integrate the expression above to get

[tex]\displaystyle \int ydy = \int \dfrac{2xdx}{x^2 + 1}[/tex]

[tex]\displaystyle \frac{1}{2}y^2 = \ln |x^2 +1| + k[/tex]

or

[tex]y = \sqrt{2\ln |x^2 + 1|} + k[/tex]

where I is the constant of integration.

Answer:

3.15 seconds is the answer.

Explanation

when the ball touches the ground, h =0

hence,

0=255-21t-16t²

16t²+21t-225=0

here a=16 ,b=21, c= -225

[tex]t= \frac{ - b± \sqrt{ {b }^{2} - 4ac} }{2a} \\ \\ t= \frac{ - 21± \sqrt{ {21}^{2} - 4 \times 16 \times - 225} }{2 \times 16} \\ = \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\ = \frac{ - 21± \sqrt{14841} }{32} \\ = \frac{ - 21±121.82}{32} \\ \\ t = \frac{ - 21 + 121.82}{32} \: or \: \: t = \frac{ - 21 - 121.82}{32} \\ t = 3.15 \: \: or \: \: t = - 4.46[/tex]

time cannot be negative, hence t = -4.46 can be avoided

The ball takes 3.15 seconds to hit the ground.