can someone help me please

Answer:

A. The astronaut would way somewhat less

The planet Jupiter has much more mass than Earth, is an astronaut who landed on Jupiter would weigh more on Jupiter than on Earth. Thus, the correct option is D.

Jupiter is a planet of the Solar system of the Milkyway galaxy. It is made up of mostly hydrogen and helium gas. The temperature on this planet is extremely hot and an astronaut landing on this planet will experience free-floating in mid-Jupiter with no way of escaping.

Jupiter has more mass than that of the Earth thus, it exerts greater gravitational force than the Earth, and the weight is equal to the product of the mass and the gravitational acceleration. So, the mass of an astronaut will remain constant when he or she move from earth to jupiter however the weight of the astronaut will increase on jupiter.

Therefore, the correct option is D.

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Explanation:

Hey there!

Given that 4kg ball struck by 12 N force.

So, we need acceleration.

Force = Mass × Acceleration

And, so

Acceleration = Force / Mass.

Acceleration = 12/4

Acceleration is equal to 3m/s² in SI units.

Hope it helps :)

Answer:

[tex]A=0.136\ m^2[/tex]

Explanation:

The air pressure inside a car tire is 3 atm = 303975 Pa

The force of 41,500 N  of force pushing out on the tire.

We need to find the surface area of the inside of the tire. The pressure acting on an object is given by :

[tex]P=\dfrac{F}{A}\\\\A=\dfrac{F}{P}\\\\A=\dfrac{41500}{303975}\\\\A=0.136\ m^2[/tex]

So, the surface area of the inside of the tire is [tex]0.136\ m^2[/tex].

Answer:

55N

Explanation:

Impulse is the product of Force and Time

Impulse = Force * Time

Given

Impulse = 550Ns

Time = 10s

Force = Impulse/Time

Force = 550/10

Force = 55N

Hence the net force on the scooter is 55N

Answer:

I would say false

Explanation:

Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.

Answer:

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Explanation:

The angular acceleration is given by the relation as follows :

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Where

[tex]\omega_i\ and\ \omega_f[/tex] are the initial and final angular velocities

t is time

The SI unit of angular acceleration is rad/s². Hence, this is the required solution.

Answer:

they're negative bc a proton is positive. a proton attracts an electron by the fact that opposite charges attract each other, while two electrons repel each other. Thus it shows that polarity of the charge on an electron and a proton is opposite.

Explanation:

Answer: a

Explanation: :)

Answer:

2.18 m/s.

Explanation:

Answer:

Initial velocity, U = 4.5m/s

Explanation:

Given the following data;

Final velocity, v = 12m/s

Time, t = 5 seconds

Acceleration, a = 1.5m/s²

To find the initial velocity, we would use the first equation of motion.

[tex] V = U + at[/tex]

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

12 = U + 1.5*5

12 = U + 7.5

U = 12 - 7.5

Initial velocity, U = 4.5m/s

Answer:

10 is the speed

Explanation:

this is y

Answer:

up ward force it is balanced by dow ward force

It is a true statement that the idea that all matter consists of elements was first introduced a few hundred years ago.

Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

Individuals have believed that earth, air, water, and fire are the only four elements that make up matter for roughly two thousand years.

For more than two thousand years, Aristotle's theory that all matter is composed of just four elements was accepted, but only around 500 years ago did scientists begin to find all of the elements that are currently recognized.

Beginning around five hundred years ago, scientists started learning about all of the elements that are currently recognized.

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Answer:

Momentum = 7.14 Kgm/s

Explanation:

Given the following data;

Mass = 0.170 kg

Velocity = 42m/s

To find the momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

Substituting into the equation, we have;

Momentum = 0.170 * 42

Momentum = 7.14kgm/s

Therefore, the momentum of the honey puck is 7.14 Kgm/s.

Answer: 80N

Explanation:

The y-component would be the magnitude of the force multiplied by the sine of the angle.

[tex]95.3*\sin(57.1)=80N[/tex]

The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.

Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.

It can be expressed as:

F = m a

Where, F= Force

m= mass of the object

a= acceleration

In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,

so, For x component [tex]F_x[/tex] = Fcosθ

For y component [tex]F_y[/tex] = F sinθ

Given, F= 95.3 N ; θ= 57.1 °

[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]

Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.

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The velocity of hitting the ground is 4.86 m/s and the velocity after hitting the ground is 4.53 m/s.

Velocity can be defined as the direction of movement of the body or object. Velocity is a vector quantity. It is the rate of change of displacement.

Given data,

Initial velocity when dropped(u)=0 m/s

Distance traveled(s)=1.21 m/s

Distance traveled after leave the ground(s1) = 1.05 ms

According to third law of motion,

v² = u² + 2gs

Initial velocity u=0

v² = 2gs or v = [tex]\sqrt{2gs}[/tex]

​by putting the value of s

v (hitting) = √(2 × 9.8 × 1.21) = [tex]\sqrt{23.71}[/tex] = 4.86m/s

After leaving ground at 1.21 m final velocity will be zero

So, velocity just after left the ground will be

2 = √(2 × 9.8 × 1.05) = [tex]\sqrt{20.58}[/tex] = 4.53m/s

So, velocity of hitting the ground is 4.86 m/s and after hitting is 4.53 m/s.

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Answer:

Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration. When organisms face limiting factors, they show logistic growth (S-shaped curve, curve B: Figure below). ... Limiting factors determine the carrying capacity of a population.

Explanation:

Answer:

b. He has to apply less force to lift the box because the mass has decreased.

Explanation: i just took a ck12 test and it was right lol

Answer:

The speed of the F-4 Phantom upon impact is approximately 214.92 m/s

Explanation:

The given parameter of the motion of the F-4 Phantom jet aircraft are;

The mass of the F-4 phantom rocket, m₁ = 19,100 kg

The mass of the retaining wall, m₂ = 469,000 kg

The velocity of the combined mass of the wall and the F-4 after collision, v₃ = 8.41 m/s

The retainment wall was initially at rest, therefore, v₂ = 0 m/s

Let 'v₁', represent the speed of the F-4 Phantom upon impact

By the principle of conservation of linear momentum, we have;

m₁·v₁ + m₁·v₂ = m₁·v₃ + m₂·v₃ = (m₁ + m₂)·v₃

Plugging in the values, we have;

19,100 × v₁ + 469,000 × 0  = (19,100 + 469,000) × 8.41

∴ v₁ = (19,100 + 469,000) × 8.41/(19,100) = 214.917329843

v₁ ≈ 214.92

The speed of the F-4 Phantom upon impact, v₁ ≈ 214.92 m/s.

Answer:

Hand soap: basic

chocolate milk: neutral

apple juice: acidic

shampoo: acidic

mouthwash: acidic

tap water: basic

Explanation:

Check your PH scale

1-6 = acidic

7 = neutral

8-14 = basic

Answer:

1. 3.4 x10^-5

2. 5.4 x10^-3

3. 346574

4. 12.5x10^-4

5. 348954

Hope this helps, please mark me brainliest if it does! :)

Answer:

a.3.51s

b.33.8m

c. 9.64,-22.9

Explanation:

(a) The time taken be "3.5083 sec".

(b) The distance will be "33.82 m".

(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".

According to the question,

Speed, V₀x = 15 Cos (50.0°)

                   = 9.64 m/s

            V₀y = 15 Sin (50.0°)

                   = 11.49 m/s

Vertical displacement = -20.0 m

(a) We know the relation between displacement, time and acceleration

→  y = vt + [tex]\frac{1}{2}[/tex]at²

By substituting the values,

→ -20.0 = 11.49 t - 4.9 t²

  4.9 t² - 11.49 t - 20.0 = 0

                                   t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]

                                     = [tex]\frac{11.49 + 22.89}{9.8}[/tex]

                                     = 3.5083 sec

(b) We know the formula,

Distance = Speed × Time

or,

→ X = 9.64 t

      = 9.64 × 3.5083

      = 33.82 m

(c) Again by using the above relation, we get

    Vx = V₀x

          = 9.64 m/s

    Vy = V₀y - gt

By substituting the values,

          = 11.49 - 9.8 × 3.5083

          = 11.49 - 34.38

          = -22.89 m/s

Thus the response above is correct.

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Answer:

Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Let the mass of this ball be [tex]x\; \rm kg[/tex].

Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].

Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:

[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].

Therefore, right before hitting the ground, the velocity of the ball would be:

[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].

The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:

[tex]\displaystyle m = \frac{p}{v}[/tex].

Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:

[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].

Answer:

i. 15.6 m/s

ii. I = 1.44 KNs

Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

i.e I = F x t

Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

i. mass, m, of the player = 92 kg

initial velocity of the player, u = 9.4 m/s

final velocity of the player, v = 6.2 m/s

Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.

So that,

change in velocity of the player = final velocity - initial velocity

                                          = 6.2 - (-9.4)

                                         = 6.2 + 9.4

                                         = 15.6 m/s

change in velocity of the player is 15.6 m/s

ii. Impulse, I = m(v - u)

                    = 92 x 15.6

                    = 1435.2

Impulse on the player is 1.44 KNs.

[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]

[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]

[tex] \\ [/tex]

[tex] \sf• \: The \: Resistance. [/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution :- }}[/tex]

[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]

[tex] \rightarrow \sf R = \frac{9}{18} [/tex]

[tex] \rightarrow \sf R = \frac{1}{2}[/tex]

[tex] \rightarrow \sf R = 0.5[/tex]

[tex] \\ [/tex]

Answer:

C would be the correct answer.

The speed change : Δv = 0.41 m/s

Given

mass = 5.5 kg

Force = 15 N

time = 0.15 s

Required

the speed change

Solution

Newton 2nd's law

Impulse and momentum

F = m.a

F = m . Δv/t

F.t = m.Δv

Input the value :

15 N x 0.15 s = 5.5 kg x Δv

Δv = 0.41 m/s