Can someone help me please :( ASAP. Also I’m sorry if it’s small

Answers

Answer 1

Answer:

Graph #2

Explanation:

Notice, on the position time graph, there is a constant rate of change. This means that there is a constant velocity, meaning it's a straight line. The line is decreasing so the velocity will be negative.

Related Questions

Assessment started: undefined.
Item 1
Select a word from the drop-down menu to correctly complete the statement.
The elements fluorine, chlorine, and iodine are all part of the same on the periodic table.
a.diagonal
b.group
c.piriod
d.row

Answers

Answer:

Option B: Group

Explanation:

The elements fluorine, chlorine, and iodine are commonly known as halogens.

They all have 7 valence electrons in their outermost shell and thus they all belong to group 7A in the periodic table.

Correct Answer is: Group

Answer:

Explanation:

Group hope this helps

Explain the disadvantage
of precision

Answers

Answer:

The disadvantages are listed below for the defined term.

Explanation:

The initial costs of introducing this method are high, so a long-term solution to agriculture should have been in place. To completely develop a functioning system, it often takes many years to gather data and you'll have to be vigilant about gathering and reviewing data to create a level playing field.

A, B, and C are three successive points on a straight line. AB = 6.0 m, and BC = 10.0 m.

A small object moving along this line from rest with uniform acceleration, passes B and C, 2.0 s

and 4.0 s, respectively, after passing A. Calculate the

i)

acceleration of the body,

Answers

Answer:

1 m/s²

Explanation:

Let velocity at A be v,

Use d = v*t + at²2/2

From A to B,

6 = v(2) + a(2²)/2 = 2v + 2a, so

v + a = 3 (1)

From A to C,

6 + 10 = v(4) + a(4²)/2

16 = 4v + 8a

or, v + 2a = 4 (2)

From (1) (2), get

a = 1 m/s²

Light travels fast and in a _______________.

straight line

compression wave

wavy line

blue line

{its for my sis shes stu!pd}

Answers

Answer:

Straight Line

Light travels in straight lines called rays. Light travels "at the speed of light." This speed is about 186,000 miles per second (670 million miles per hour), or about 300,000 kilometers per second.

Have an amazing day!!

Please rate and mark brainliest!!

The density of blood is 2kg/m.convert to g/cm

Answers

Explanation:

if we convert it into g/cm it'll be

2000 grams

Take another look at line 1. Suppose that you use distance and time between any pair of neighboring dots to calculate speed:

speed = distance ÷ time

Will this speed be the same or different from the average speed you calculated in part F? Why?

Answers

Answer:

The time of travel and the distance between neighboring dots is always the same. So, the speed between neighboring dots is constant. This speed will be the same as the average speed in part F. hope it helps!

A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is the speed of the drone with repeat to the ground? A. 14m/s B. 10m/s C. 2m/s D. 20m/s

Answers

Answer:

v=10 m/s

Explanation:

Given that,

Speed of a drone is 8 m/s due East with respects to the wind

Speed of a drone 6 m/s due North with respect to the ground.

We need to find the speed of the drone with respect to the ground. Let v is the speed. It is given by the resultant of two speeds.

[tex]v=\sqrt{8^2+6^2} \\\\v=10\ m/s[/tex]

So, the speed of the drone with respect to the ground is 10 m/s.

A planar insulating sheet with an infinitesimal thickness has charge per unit area σ and is parallel to the x−z plane, as shown. (The arrows indicate that the object extends for a long distance in the horizontal plane.) By the symmetry of the problem, the electric field may be expressed as E⃗ =Ej^. This problem relates the change in the electric field from the lower side to the upper side of the insulating sheet to the surface charge density.

a) Enter a vector expression, in Cartesian unit-vector notation, for the electric field at points just above the planar insulating sheet.
b)Enter a vector expression, in Cartesian unit-vector notation, for the electric field at points just below the planar insulating sheet.

Answers

a. The electric field above the planar insulating sheet is Ej = (σ/ε₀)j

b. The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

a. Electric field above planar insulating sheet

The electric field above the planar insulating sheet is Ej = (σ/ε₀)j

Gauss's law

Using Gauss' law ε₀∫E.dA = q where

ε₀ = permittivity of free space, E = electric field vector normal to the surface above the planar insulating sheet = Ej, dA = normal vector to surface above the planar insulating sheet = dAj, q = charge enclosed by Gaussian surface on planar insulating sheet = σA where σ = surface charge density and A = area of surface

Now, ε₀∫E.dA = q

ε₀∫Ej.dAj = σA

ε₀∫EdA = σA

ε₀E∫dA = σA

ε₀EA = σA

ε₀E = σ

E = σ/ε₀

So, the electric field above the planar insulating sheet is Ej = (σ/ε₀)j

b. Electric field above below insulating sheet

The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

Gauss's law

Using Gauss' law ε₀∫E.dA = q where

ε₀ = permittivity of free space, E = electric field vector normal to the surface below the planar insulating sheet = -Ej, dA = normal vector to surface below the planar insulating sheet = -dAj, q = charge enclosed by Gaussian surface on planar insulating sheet = σA where σ = surface charge density and A = area of surface

Now, ε₀∫E.dA = q

ε₀∫-Ej.-dAj = σA

ε₀∫EdA = σA

ε₀E∫dA = σA

ε₀EA = σA

ε₀E = σ

E = σ/ε₀

So, the electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

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The work done in holding a 60 kg object at a height of 2 m above the floor for 20 s is

Answers

Answer:

zero

Explanation:

The work done is zero because the object has no displacement

a 3000 kg car accelerates uniformly from 15 m/s to 60 m/s in 5 seconds. determine the net force on the car during this time

Answers

Answer:

F = 2700 N

Explanation:

Given that,

Mass of a car, m = 3000 kg

Initial velocity, u = 15 m/s

Final velocity, v = 60 m/s

Time, t = 5 s

We need to find the net force on the car during this time . The net force on an object is given by the product of mass and acceleration. So,

F = ma

a is acceleration, a = (v-u)/t

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{3000\times (60-15)}{5}\\\\F=27000\ N[/tex]

So, 27000 N is the net force on the car during this time .

I’m not sure what you’re asking here

Calculate the displacement in m and velocity in m/s at the following times for a rock thrown straight down with an initial velocity of 11.4 m/s from the Verrazano Narrows bridge in New York City. The roadway of this bridge is 70.0 m above the water. (Enter the magnitudes.)
(a)
0.500 s
displacement

velocity

Answers

Answer:

y = 6.92[m]

Vf = 16.305[m/s]

Explanation:

To solve this problem we must use the following kinematics equations, where we must first find the final velocity.

[tex]v_{f}=v_{i}+(g*t)[/tex]

where:

Vi = initial velocity = 11.4[m/s]

Vf = final velocity [m/s]

t = time = 0.5[s]

g = gravity acceleration = 9.81[m/s^2}

Note: the positive sign in the equation above is because the acceleration of gravity goes in the direction of the motion of the rock.

Vf = 11.4 + (9.81*0.5)

Vf = 16.305 [m/s]

Now we can calculate how far the rock goes, using the following equation:

[tex]v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f} ^{2}- v_{i}^{2} = 2*g*y\\y = \frac{v_{f} ^{2}- v_{i}^{2}}{2*g} \\y = \frac{16.305^{2}-11.4^{2} }{2*9.81}\\ y=6.92[m][/tex]

Therefore the Rock will be (70 - 6.92) = 63.07 [m] above the water level

A gecko crawls vertically up and down a wall. Its motion is shown on the following graph of vertical position yyy vs. time ttt.
Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec
Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec
What is the average velocity of the gecko between the times t=0\text{ s}t=0 st, equals, 0, start text, space, s, end text and t=7\text{ s}t=7 st, equals, 7, start text, space, s, end text?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
0.57\,\dfrac{\text m}{\text s}0.57
s
m

0, point, 57, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction

(Choice B)
B
-0.57\,\dfrac{\text m}{\text s}−0.57
s
m

minus, 0, point, 57, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction

(Choice C, Checked)
C
-1.0\,\dfrac{\text m}{\text s}−1.0
s
m

minus, 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction

(Choice D)
D
1.0\,\dfrac{\text m}{\text s}1.0
s
m

Answers

Answer:

gfdvcfffddfgffffdrddgfddddghtscgvfrggxfhxdg

Answer:

-.57

Explanation:

Slope from the points (0,6) and (7,2)

2-6/7-0=-.57

A block-spring system oscillates on a frictionless horizontal surface. The time needed for the block to complete one cycle is 0.1 sec. Determine the time needed for the block to travel from -A/2 to A/2, where A is the amplitude of motion

Answers

The time needed for the block to travel from -A/2 to A/2 is mathematically given as

t=0.5sec

What is the time needed for the block to travel from -A/2 to A/2?

Generally, when the start point is the mean intial position and it goes from A/2 down through the right goes through and fro back to the mean position, and this is after it must have gone through -A/2. Hence it has finished one cycle (0.1 sec.)

In conclusion, for an -A/2 to A/2 oscillation, then it will finish half-cycle given time period to be

t=1/2

t=0.5sec

Answers

(a) The work done in strecthing the spring is 122.5 N.

(b) The work done in compressing the spring is -122.5 N.

Work done to stretch the spring

The work done in stretching a spring is positive since the applied force acts in the same direction as the displacement.

The work done in strecthing the spring is calculated as follows;

W = ¹/₂kx²

W = ¹/₂ x (5 x 10⁴) x (0.07)²

W = 122.5 N

Work done in compressing the spring

The work done in compressing the spring is negative, since the applied force acts in opposite direction to the displacement of the spring.

The work done in compressing the spring is calculated as follows;

W = -¹/₂kx²

W = -¹/₂ x (5 x 10⁴) x (0.07)²

W = -122.5 N

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weather meaning of physics

Answers

Answer:

1. The day-to-day conditions of the atmosphere at a place with respect to elements like humidity, temperature, wind speed, rainfall, etc. is called the weather of that place.

2. Weather can be cloudy, sunny, rainy, stormy or clear. It is a part of the natural phenomenon which maintains the equilibrium in the atmosphere.

3. But conditions can be worse sometimes. When the atmospheric conditions are extreme or intense enough to cause property loss or life loss, such weather is termed as severe weather.

4. These also vary according to the altitudes, latitudes, and region and pressure differences. Tornadoes, cyclones, heavy rainfall, fog, winter storms come under this category. They are disastrous and hazardous. Proper disaster management and strategies are required to handle these conditions.

Based on the levels of processing memory model, place in order how deeply the following information about dogs will be encoded, from the shallowest to the deepest.

Answers

From the question, the order of information processing from the shallowest to the deepest is;

A person glances at a magazine and sees a picture of a dog.A person can remember all the breeds of dogs because she knows a song that lists them.A person dog-sits and spends the weekend walking and playing with a dog A person who grew up with a dog enjoyed walking in the woods with her pet.

What is information processing?

The term information processing means the way in which we deal with information. It is the process by which information is encoded into our memory.

The following is the order of information processing from the shallowest to the deepest;

For example 2, there is a friction, so the acceleration in example 2 is:

[tex]\sum F=F-f=100-40 = 60 = ma\rightarrow a_{2}=\frac{60}{50}=1.2 ms^{-2}[/tex]

Here we can say that "according to Newton's 2nd Law, the box in example 2 has less acceleration than in the example 1". So, the claim is denied.

is there gravity in water?

Answers

Gravity works the same way in water that it works in air or a vacuum -- but you have to consider the force of gravity on the water as well as on the object you put into it

A buoy is anchored tho the oceanfloor. A large wave approaches the buoy. How will the buoy move as the wave goes by?

Answers

Answer:

The buoy will move upwards and downwards and well as left and right

Explanation:

As the wind is storing so had the capability to move the buoy in all directions as it is a light object despite being anchored down

PLEASE GIVE BRAINLIEST AND THANKS :-)

You want to double the radius of a rotating solid sphere while keeping its kinetic energy constant. (The mass does not change.) To do this, the final angular velocity of the sphere must be Group of answer choices

Answers

The Final angular velocity of the sphere is : Half of its initial value ( W/2 )

Kinetic energy of a rotating body

Given that The kinetic energy of a rotating body ( K ) = 1/2 IW² --- ( 1 )

where : I = moment of inertia, w = angular velocity

I = [tex]\frac{2}{5} MR^{2}[/tex]

Therefore equation ( 1 ) becomes

K = [tex]\frac{1}{5}MR^2W^2[/tex] ----- ( 2 )

After doubling the radius

R' = 2R

K' = K

Mass = unchanged

therefore :

[tex]\frac{1}{5}MR'^2W'^2 = \frac{1}{5}MR^2W^2[/tex]

= ( 2R )² W'² = R²W²

Resolving equation above

Hence : W' ( new angular velocity ) = W / 2

In conclusion The Final angular velocity of the sphere is : Half of its initial value ( W / 2).

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A car travels 100 m in 4 s on a highway going east. What is the velocity of the car?

Answers

Answer:

velocity =25

Explanation:

Average velocity =total displacement /time e taken

so,average velocity =total displacement

total time taken

100m/4 =25

velocity =25

25 is the answer
Have a good and great day !!!!

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