Can someone answer this?

The area of the shape is the amount of space on the shape

Using the assumed parameters, the area of the shape is 25 square units

The question is incomplete, as the shape is not given.

Assume the shape is a trapezoid, the area of the shape would be:

A = 0.5 * (sum of parallels sides) * height

Using the assumed values, we have:

Area = 0.5 * (12 + 13) * 2

Evaluate the product

Area = 25

Using the assumed values, the area of the shape is 25 square units

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Answer:

54

Step-by-step explanation:

Answer:

16s^2 -9

Step-by-step explanation:

(4s+3)(4s–3)

FOIL

first : 4x*4x = 16s^2

outer -3 *4s = -12s

inner 3*4s = 12s

last = 3* -3 = -9

Add them together

16s^2 -12s+12s -9

Combine like terms

16s^2 -9

En total, durante los últimos meses la familia de Manuel ha consumido 792 kilos de productos de primera necesidad.

Arroz: 17+13+18= 48 kg

Fideos: 12+27+30 = 69 kg

Harina: 26+56+50= 132 kg

Aceite: 6+24+30= 60 kg

Avena: 8+16+20= 44 kg

Papa: 32+48+48= 128 kg

Frejol: 12+20+27= 59 kg

Alverja: 16+24+26= 66 kg

Pollo: 12+12+12= 36 kg

Carne de res: 8+10+10= 28 kg

Mazamorra: 8+25+28= 61 kg

Leche: 13+24+24=61 kg

48+69+132+60+44+128+59+66+36+28+61+61= 792 kilos

Nota: Esta pregunta está incompleta, a continuación se adjunta la parte faltante.

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Answer:

The train will travel 493.817 meters until it stops completely.

Step-by-step explanation:

In this case, we know that train applies the brakes and decelerates at constant rate until rest is reached after travelling an unknown distance. Travelled distance ([tex]\Delta s[/tex]), measured in meters, can be found by using this kinematic formula:

[tex]v^{2} = v_{o}^{2}+2\cdot a \cdot \Delta s[/tex] (Eq. 1)

Where:

[tex]v_{o}[/tex] - Initial speed, measured in meters per second.

[tex]v[/tex] - Final speed, measured in meters per second.

[tex]a[/tex] - Acceleration, measured in meters per square second.

Now travelled distance is cleared within the formula:

[tex]\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex]

If we know that [tex]v_{o} = 22.222\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]a = -0.5\,\frac{m}{s^{2}}[/tex], then the distance travelled by the train is:

[tex]\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(22.222\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.5\,\frac{m}{s^{2}}\right) }[/tex]

[tex]\Delta s = 493.817\,m[/tex]

The train will travel 493.817 meters until it stops completely.

Answer:

v² = v²0 + 2aΔx

Step-by-step explanation:

Answer:

13 tables

Step-by-step explanation:

Just do 78÷6 to get your answer

Answer:

[tex]36.25[/tex]

Step-by-step explanation:

Let [tex]x[/tex] be the cost of 5 bags of bulk cereal.

3 is to $21.75 as 5 is to [tex]x[/tex], this translates to the following

[tex]\frac{3}{21.75}=\frac{5}{x}[/tex]

Solving for [tex]x[/tex], we get [tex]x=36.25[/tex]

Answer:

5 bags of bulk cereal cost $36.24

Step-by-step explanation:

Answer:

the answer is b

Step-by-step explanation:

bc i just this it is

Answer:

D) 45 ounces for $4.50

Step-by-step explanation:

You have to find the price of one unit (ounce) for each. You can do this by dividing the price by quantity. The one with the lowest price is the best deal.

A) 32 ounces for $4.00

$0.13 for 1 ounce

B) 60 ounces for $6.75

$0.11 for 1 ounce

C) 48 ounces for $5.00

$0.11 for 1 ounce

D) 45 ounces for $4.50

$0.10 for 1 ounce

The best choice will be option D. That is 45 ounces for $4.50.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

You have to find the price of one unit (ounce) for each. You can do this by dividing the price by quantity. The one with the lowest price is the best deal.

A) 32 ounces for $4.00

$0.13 for 1 ounce

B) 60 ounces for $6.75

$0.11 for 1 ounce

C) 48 ounces for $5.00

$0.11 for 1 ounce

D) 45 ounces for $4.50

$0.10 for 1 ounce

The complete question is given below.

A company is trying to decide which container of coffee to buy for a staff meeting. Which of the following would be the best deal? Hint: find the best unit cost

Group of answer choices

32 ounces for $4.00

60 ounces for $6.75

48 ounces for $5.00

45 ounces for $4.50

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#SPJ2

The best price is $6.50, and the maximum revenue that the school can get is $2,112.50.

Given that the starting price for a ticket for a high school play is $5, and the auditorium capacity is 400 people, and the organizer estimates that for every 10 cent increase in the ticket price 5 fewer people will attend the play, to determine what is the best price and what is the maximum revenue that the school can get, the following calculation must be made:

Therefore, the best price is $6.50, and the maximum revenue that the school can get is $2,112.50.

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Answer:

D

Step-by-step explanation:

The measure of center best represents the data set is Mean or Median.

Given

Data Set Best Measure of Center {27, 29, 26, 28, 25}.

The mean is the average of a set of data.

The mean is found by finding the sum of the data and then dividing the sum by the number of data.

The mean of the given data set is;

[tex]\rm Mean = \dfrac{27+29+26+28+25}{5}\\\\Mean =\dfrac{135}{5}\\\\Mean =27[/tex]

Arranging the data set in the ascending order

{25, 26, 27, 28, 29}

The median is defined as the middle value of the given data set.

The median of the data set is 27.

Hence, the measure of center best represents the data set is Mean or Median.

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Answer:

1/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

for every 10c there is 30c. for every 20c there is 125c.

Answer:

[tex]\bold\blue{x {}^{2} + 5x + 4} [/tex]

Here ,

we just need to substitute " x = - 5 " in the equation above.

[tex]\bold{x {}^{2} + 5x + 4} \\\bold{ ( - 5) {}^{2} + 5( - 5) + 4} \\ \bold{ \cancel{25} - \cancel{25} + 4} \\ \fbox\pink{⇢ 4}[/tex]

hope helpful ~

[tex] \huge \qquad \boxed{ \sf Aᥒsᥕᥱr ☂}[/tex]

let's plug in the value of x as -5, in the given expression ~

[tex] \qquad\rightarrowtail \sf {x}^{2} + 5x - 4[/tex]

[tex] \qquad\rightarrowtail \sf { (- 5)}^{2} + 5( - 5) - 4[/tex]

[tex] \qquad\rightarrowtail \sf 25 - 25 + 4[/tex]

[tex] \qquad\rightarrowtail \sf 4[/tex]

Therefore, we got the required value 4

Explanation:

AAS = angle angle side

The arc markings show us which pairs of angles are congruent. The pair of congruent sides are the shared overlapping sides. Notice that the sides are not between the red angles, so we go for AAS instead of ASA. The order is important.

We cannot use SAS because we only know info about one pair of congruent sides (not two).

[tex]\huge\underline\mathtt\colorbox{cyan}{320}[/tex]

Step-by-step explanation:

Answer:

  4√14

Step-by-step explanation:

You simplify a radical by removing squares from under it.

  [tex]\sqrt{224}=\sqrt{16\cdot14}=\sqrt{4^2\cdot 14}=\boxed{4\sqrt{14}}[/tex]

Answer:

192000 J

Step-by-step explanation:

k = 1/2 mv²

48000 = 1/2 x m x (20)²

48000 = 200m

m = 240 kg

new k

k = 1/2 x 240 x 40²

k = 192000 J

Answer:

b

Step-by-step explanation:

Answer:

-4.2 (least) < -2 < -1 < -4/5 < 3.5 (greatest)

| | is called absolute value, but you can ignore it as |-4.2| equals to -4.2

A(1,0)

B(0,-3)

C(-6,5)

D(-3,-5)

E(-1,4)

Answer:

A) equality function will hold

B) equality function doesn't hold

C)  equality function holds )

D) equality function doesn't hold

E) equality function holds

Step-by-step explanation:

a) ⌊⌈x⌉⌋ = ⌈x⌉ for all real numbers x.

The ceiling function will yield an integer, that is greater ≥ x.

Also the floor function when applied to an integer will yield the same integer value. hence the two sides will become the same Therefore the  equality function will hold

b) ⌊x+y⌋=⌊x⌋+⌊y⌋ for all real numbers x and y

The floor function of this statement yields a value that is ≤ inserted value and this makes the right hand side of the statement to be 1 less than the sum produced from the left hand side of the statement, therefore the equality function doesn't hold

c) ⌈⌈x∕2⌉ ∕2⌉ = ⌈x∕4⌉ for all real numbers x.

The ceiling function produces an integer that is ≥ value inserted and the integer gotten is divided by 2 and this serves a s an input to the ceiling function( which means X has been divide by 4 ) making the two sides of the equation the same ( equality function holds )

d)⌊√⌈x⌉⌋ = ⌊√x ⌋ for all positive real numbers x

The ceiling function is applied to the value inserted in x(on the left hand side ), and the result will not be equal to that in the right hand side.

Therefore the equality function doesn't hold

e) ⌊x⌋+⌊y⌋+⌊x+y⌋≤⌊2x⌋+⌊2y⌋forall real numbers x and y.

If the value of the fractional part of x or y is > 0.5, then the right hand side will be greater  than the left hand side by 1.

Otherwise, both left and right hand sides yield equal answers. therefore equality function holds

Answer:

[0,9]

Step-by-step explanation:

The domain is the first set of the ordered pair. When finding the domain you are supposed to find which x value it starts from to where it ends. The x value starts from 0 and ends and the 9th unit on the x-axis which would give us 0,9 now since both points are closed you would use these symbols [ ] to show that it is closed meaning the answer would be [0,9]

Note:

I'm sorry if this is wrong but this is what I believe the answer is.

Answer:

but we need the shape.. to know which is the big and the little basement..

Answer:

[tex]\left(x+2\right)\cdot \left(x-2\right)\cdot \left(x-7\right)[/tex]

Step-by-step explanation:

[tex]\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x^2-4,\:x^2-5x-14[/tex]

[tex]\mathrm{The\:LCM\:of\:}a,\:b\:\mathrm{is\:the\:smallest\:multiplier\:that\:is\:divisible\:by\:both\:}a\mathrm{\:and\:}b[/tex]

[tex]x^2-4[/tex]

[tex]\mathrm{Rewrite\:}4\mathrm{\:as\:}2^2[/tex]

[tex]=x^2-2^2[/tex]

[tex]x^2-2^2=\left(x+2\right)\left(x-2\right)[/tex]

[tex]=\left(x+2\right)\left(x-2\right)[/tex]

[tex]x^2-5x-14[/tex]

[tex]=\left(x^2+2x\right)+\left(-7x-14\right)[/tex]

[tex]=x\left(x+2\right)-7\left(x+2\right)[/tex]

[tex]=\left(x+2\right)\left(x-7\right)[/tex]

[tex]\mathrm{Multiply\:each\:factor\:with\:the\:highest\:power:}[/tex]

[tex]\left(x+2\right)\cdot \left(x-2\right)\cdot \left(x-7\right)[/tex]