Can please someone help me out and explain it step by step. Thank you

5,0 is not a solution to the system of linear inequalities.

Answer:

f(x) = a(x - 1) + 20

Step-by-step explanation:

Vertex form is written in this format: f(x) = a(x - h) + k. The vertex point is written in the form (h,k). To write the vertex in the equation, fill in the digits where they belong.

Hope it helps!

The ball's parabolic route is represented by the quadratic function's graph. The quadratic function is x²-2x+4=0.

Given that,

A thrown ball's height is a quadratic function of the amount of time it has been in the air. The ball's parabolic route is represented by the quadratic function's graph. The ball's route includes the location (1, 20), which is the graph's vertex (0,4).

We have to find what does the expression for this function look like? In vertex form, write the quadratic function.

Use y= a(x-h)² + k as the vertex form of a parabola.

(The parabola opens upward if "a" is positive and downward if "a" is negative.) Additionally, the vertex of the (h,k) is a parabola.

The vertex of the parabola (h,k) is (1,20)

The a value is 4 and y as 0.

y=a(x-h)²+k

0=4(x-1)²+20

0=4(x²-2x+1)+20

0=4x²-8x-4+20

0=4x²-8x+16

4x²-8x+16=0

x²-2x+4=0

Therefore, the quadratic function is x²-2x+4=0.

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Answer:

Let me know if there is anything you don't get

∠3 = 102 because ∠1 and ∠3 are supplementary and 102 + 78 = 180

∠4 = 102 because ∠1 and ∠4 are consecutive interior angles

∠5 = 78 because ∠1 and ∠5 are corresponding angles

∠6 = 133 because ∠2 and ∠6 are supplementary angles

∠7 = 47 because ∠2 and ∠7 are vertical angles

∠8 = 47 because ∠2 and ∠8 are opposite interior angles

∠9 = 133 because ∠8 and ∠9 are supplementary, and we just saw ∠2=∠8

∠10 = 102 because ∠1 and ∠10 are supplementary

You could have used a whole bunch of different relations, but I wanted to focus on ∠1 and ∠2 since those were told to us

Step-by-step explanation:

For this question you need to know several parts of geometry.  Let me know if anything doesn't make sense.

First, parallel lines are two or more lines which are angles in such a way that no matter how long they are they will not cross.  In other words they are slanted at the same angle.  you can see this with lines a and b in this picture.

Second, a transversal is a line that crosses through two or more parallel lines.  A transversal creates a number of angles that have special properties.  I would like you to look specifically at line c as I describe these angles.  line c is a transversal to Ines a and b.  Also line d is also a transversal.

There are seven special angles to know.

The easiest is supplementary angles.  This you don't need parallel lines, but if any two lines ever cross this creates 4 angles.  you can actually look at where lines c and b intersect in your problem.  Angles 2. 6 and 7 are labeled but there is one more unlabeled one.  Now, 180 degrees is a straight line.  With angles you can see angles 6 and 7 add together to be a straight line.  Similarly 2 and 6 do as well.  These are two sets of supplementary angles.  

To list off the supplementary angles here 9 and 8 are supplementary, as are  2 and 6, 6 and 7, 1 and 3, 1 and 10, and finally 4 and 5.

From supplementary angles comes vertical angles.  Again, if you look at angles 2, 6 and 7 we already know ∠2 + ∠6 = 180 and ∠6 + ∠7 = 180.  Well lets say ∠6 = 133.  Well then, we could use algebra to see that both ∠2 AND ∠7 are 47 degrees.  This is the property of vertical angles.  if you have two lines intersecting, any two angles that have a third in between the are called vertical angles, and are equal.

some examples of vertical angles are ∠2 and ∠7as well as ∠3 and ∠10,  

Finally we go into parallel line specific angles.  If you have two or more parallel lines with a transversal, so in particular look at a and b as the parallel lines and c as the transversal.  The transversal creates some special angles.  in particular, the transversal crosses a and b at the same angle, so angles 8 and 7 have the same value.  These are known as corresponding angles, since they correspond tot he same position with a transversal crossing through parallel lines.  

the corresponding angles in the picture are ∠8 and ∠7, ∠3 and ∠4 and finally ∠1 and ∠5.  the last two using line d as a transversal.

After corresponding angles opposite interior angles I think are the next logically to look at.  Opposite means they are on two different parallel lines and on different sides of the transversal, while interior means they are between the parallel lines.  so if you look at the parallel lines a and b there are angles 8 and 2 that are interior angles.  Since 8 is against line a and 2 is against line b, and ∠8 is above transversal c while ∠2 is below it, they are opposite angles.  so 8 and 2 are opposite interior angles.  Now, if you look at ∠8 and ∠7 you know these are corresponding angles, then ∠7 and ∠2 are vertical angles.  This means opposite interior angles are equal.

A list of opposite interior angles are ∠8 and ∠2, and ∠10 and ∠4.

Alongside opposite interior, there are opposite exterior angles.  opposite means on different parallel Ines and on opposite sides of the transversal, while this time exterior means not between the parallel lines.  Now just like we figured with opposite interior angles

The only labeled pair of opposite exterior angles are ∠9 and ∠6.  Now just like we figured with opposite interior angles, let's start with ∠8 and ∠9, which are supplementary.  then ∠8 and ∠7 are corresponding angles so ∠9 and ∠7 are supplementary.  We can also see ∠7 and ∠6 are supplementary.  well, since ∠9 + ∠7 = 180 = ∠6 + ∠7 then ∠9 = 180 - ∠7 = ∠6 so ∠9 = ∠6.  This shows opposite exterior angles are  equal.

So we did two kinds of opposite angles, it might make sense there are non opposite angles.  And there are.  these are called consecutive angles.  There are consecutive exterior and consecutive interior angles.  An example of each are ∠1 and ∠4 for consecutive interior, consecutive because they are on the same side of the transversal, and interior because they are between the two parallel lines.  ∠3 and ∠5 are consecutive exterior angles.

You can use similar reasoning we have been so far to conclude all consecutive angles are supplementary

Answer:

C, 33 1/3%

Step-by-step explanation:

Because there are only two even number that follow this rule: 2<x≥6, and since there are only 6 possible outcomes, the probabilty is 2/6, which is 1/3. In a percent form, this is 100%*2/3, or 33 1/3%.

Answer:

[tex]2[/tex][tex]z^{3}[/tex][tex]\sqrt{14z}[/tex]

Step-by-step explanation:

The simplified form of  √56z⁷  is 2z³√(14z⁴ ) in the given question.

To simplify √56z⁷, we can break down the number 56 into its prime factors and remove any perfect square factors from inside the square root.

When simplifying a square root expression, removing perfect square factors from inside the square root helps simplify the expression further. This is because the square root of a perfect square is a whole number.

First, let's factorize 56:

56 = 2 * 2 * 2 * 7

Since 2 is a perfect square, we can remove it from inside the square root:

√56z⁷  = √(2 * 2 * 2 * 7 * z⁷ )

Simplifying further:

√56z⁷ = 2z³√(2 * 7 * z)

Therefore, the simplified form of √56z⁷  is 2z³ √(14z⁴ ).

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Answer:

The appropriate solution is "1.7109". A further explanation is provided below.

Step-by-step explanation:

The given values are:

Sample size,

n = 25

Degree of freedom,

[tex]df=n-1[/tex]

   [tex]=25-1[/tex]

   [tex]=24[/tex]

At 90% confidence level,

[tex]\alpha=1-90 \ percent[/tex]

  [tex]=1-0.9[/tex]

  [tex]=0.1[/tex]

and,

[tex]\frac{\alpha}{2}=\frac{0.1}{2}[/tex]

  [tex]=0.05[/tex]

Now,

The correct values of t will be:

=  [tex]t_{\frac{\alpha}{2}, df }[/tex]

=  [tex]t_{0.05,24}[/tex]

=  [tex]1.7109[/tex]

Answer:

...... .................

Answer:

second option.

Step-by-step explanation:

Answer:

11.7947881

depends now how you wanna round it

Step-by-step explanation:

tan(25)=5.5/x

x=5.5/tan(25)

x=11.7947881

this is how we round it in my school

x≈11.8

Answer:

Step-by-step explanation:

i think that the equations might be y = x - 7

Answer: 3

Step-by-step explanation: The number in front of your variable is called your coefficient so we say that 3 is the coeficient.

Make sure to understand that a variable

is just a letter that represents any number.

Answer:

14

Step-by-step explanation:

[tex]x + 2 = 16 \\ x = 16 - 2 \\ x = 14[/tex]

Like this ？？？

Answer:

16 = 2 + 14

Step-by-step explanation:

Sum means to add to numbers, so we are finding x + 2 = 16.

x + 2 - 2 = 16 - 2

x = 14

Answer:

<B=24

Step-by-step explanation:

<B=x

<A=5(x+7.2)

x+5(x+7.2)=180

x+5x+36=180

6x=180-36

6x=144

x=24

Answer and Step-by-step explanation:

When two angles are supplementary, the add up to 180 degrees.

Measure of angle A is 5 times the sum of the measure of angle B + 7.2.

So, we have b, and we have a.

a + b = 180

a = 5(b + 7.2)

b = ?

We input 5(b + 7.2) for a into the equation.

5(b + 7.2) + b = 180

Now we distribute the 5 and combine like terms.

5b + 36 + b = 180

6b + 36 = 180

Subtract 36 from both sides, then divide both sides by 6 to get b.

6b = 144

b = 24

The measure of angle B is 24 degrees.

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Answer:

sorry dude I really want to help but it's pretty hard and I don't

know

Step-by-step explanation:

Answer:

9.364 is the expected number of points.

we can approximate this to 10 points if we want a whole number

Step-by-step explanation:

We have these variables:

[0,5,10,15]

P(x= 0) = p(y>20)+p(y<-20) = 2p(y>20)

P(x=5) = p(-20<=y<=10)+p(10<=y<=20) = 2p(10<=y<=20)

P(x=10) = p(-10<=y<=-3)+p(3<=y<=10) = 2p(3<=y<=10)

P(x=15) = p(-3<=y<=3) = 2p(0<=y<=3)

Z = y/10

Therefore

P(x= 0) = 2(y>20)

= 2p(z>2) = 2(1-p<=2)

= 2(1-0.9772)

= 0.0456

P(x= 5)

= 2p(10<=y<=20)

= 2p(1<=z<=2)

= 2(0.9772-0.8413)

= 0.2718

P(x= 10)

= 2p(3<=y<=10)

= 2p(0.3<=z<=1)

= 2(0.8413-0.6179)

= 0.4468

P(x = 15)

= P(0.6179-0.3821)

= 0.2358

To get expected value of Y

0(0.0456)+5(0.2718)+10(0.4468)+15(0.2358)

= 1.359 + 4.468 + 3.537

= 9.364

E[Y] = 9.364

Answer:

Step-by-step explanation:

[tex]T_j \sim exp ( \lambda j) \ \ \ j = 1 (1) n \\ \\ f_{Tj}(tj) = \lambda j e^{-\lambda j tj } , tj>0 \\ \\ P\Big[ Tj> x\Big] = \int \limits ^{\infty}_{x} \lambda j e^{-\lambda j tj}\ dtj \\ \\ = e^{-\lambda j x}, x > 0 \\ \\ \\ \\ a) F_x (x) \\ \\ = P[X \le x ] \\ \\ = 1 - P[X> x] \\ \\ = 1 - \pi \limits ^{n}_{j =1} \Big\{ P[T_j > x ] \Big \}[/tex]

[tex]\text{This is because the appliance has the capacity to work for more than (x) }[/tex][tex]\text{hours if and only if all the "n" components work more than (x) hours.}[/tex]

[tex]\text{Then:}[/tex]

[tex]= 1 - e \ \pi^{n}_{j=1} \ e^{-\lambda j x} \\ \\ = 1 - e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}[/tex]

∴

[tex]CDF = 1 - e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ x>0[/tex]

[tex]PDF =\Big( \sum \limits ^{n}_{j =1} \lambda j\Big) e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ x>0[/tex]

[tex]f_x(x) = \Big( \sum \limits ^{n}_{j =1} \lambda j\Big) e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ x>0[/tex]

(b)

[tex]E(x) = \int \limits ^{\infty}_{o }x f_x (x) \ dx \\ \\ = \int \limits ^{\infty}_{o }x \ \Big( \sum \limits ^{n}_{j =1} \lambda j\Big) e^{- (\sum \limits ^{n}_{j=1} \lambda j)x}\ , \ dx[/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j=1} \lambda j} \ \ \int \limits ^{\infty}_{o} \Big [(\sum \limits ^n_{j=1} \lambda j )x \Big] e ^{-\Big ( \sum \limits ^{n}_{j=1} \lambda j \Big)x} \ \ d \Big( x \sum \limits ^n_{j=1} \lambda j \Big)[/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j= 1} \lambda j} \int \llimits ^{\infty}_{o} t e^{-t} \ dt[/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j= 1} \lambda j} \int \llimits ^{\infty}_{o} t e^{-t} \ dt \ \ \ \ \text{\Big[By transformation }t =( \sum \limits ^n_{j=1} \lambda j )x \Big][/tex]

[tex]= \dfrac{1}{\sum \limits ^n_{j= 1} \lambda j}[/tex]

(c)

[tex]Let \ \ l_y_{\dfrac{1}{2}} \text{ be the median}[/tex]

∴

[tex]F(l_y_{\dfrac{1}{2}}) = \dfrac{1}{2} \\ \\ 1 - e ^{-\Big (\sum \limits ^{n}_{j=1} \lambda j \Big)} {l_y}_{\frac{1}{2}} = \dfrac{1}{2} \\ \\ \dfrac{1}{2} = e^{-\Big (\sum \limits ^{n}_{j=1} \lambda j \Big) } {l_y}_{\frac{1}{2}} \\ \\ - In 2 = {-\Big (\sum \limits ^{n}_{j=1} \lambda j \Big)} {l_y}_{\frac{1}{2}} \\ \\ \\ \\ \mathbf{ {l_y}_{\frac{1}{2}} = \dfrac{ In \ 2}{\sum \limits ^{n}_{j=1} \lambda j }}[/tex]

Answer:

it is A.2/3

Step-by-step explanation:

Answer:

d≈21.99

Step-by-step explanation:

Answer: Hello the statement related to your question is missing attached below is the statement

answer : The statement is false

Step-by-step explanation:

The statement is false

This is because a confidence interval gives a range of values for an unknown parameter.

A 95% confidence interval is calculated and it gives a lower and upper limit in which the 58% of the voters can fall into i.e. The 58% of voters can fall within the upper and lower limit of the 95% confidence interval and not exactly 95% . Hence the statement is false.

Answer:

4

Step-by-step explanation:

Answer:

1/10 = 4  

Step-by-step explanation:

Answer:

Me encanta el pollo, de todos modos, un día que es hoy, por cierto, fui a la tierra de los pollos y caminé en México, ¿sabías que es mi sueño? ¿Olvidé que mi nombre es jemma y me gusta caminar? párrafo así que nos vemos

Answer:

26 square feet

Step-by-step explanation:

I dont know if this is right

Answer:

x = 16

Step-by-step explanation:

[tex] \frac{2x - 5}{x + 8} = \frac{22.5}{20} [/tex]

Cross multiply

[tex] (2x - 5)*20 = (x + 8)*22.5 [/tex]

[tex] 40x - 100 = 22.5x + 180 [/tex]

Collect like terms

40x - 22.5x = 100 + 180

17.5x = 280

Divide both sides by 17.5

x = 280/17.5

x = 16

Answer:

98%

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

x = -7

Step-by-step explanation:

4x - 2 = 3(x - 3)

use the distributive property

4x - 2 = 3x - 9

    +9         +9

4x + 7 = 3x

-4x        -4x

7 = -1x

x = -7

Hope I helped! Have a nice day! Plz mark as brainliest!!! :D

-XxDeathshotxX

Step-by-step explanation:

13 hours

6 + 4 + 3 = 13

correct if wrong