Can anyone help me? Please

Answer:

D kinetic energy

Step-by-step explanation:

When a vehicle is in motion, it has kinetic energy. Option C is correct.

The statement is given, When a vehicle is in motion, it has _____.
Blank statement to be filled from the options A. no weight B. no inertia C. potential energy D. kinetic energy.

When an object is subjected to perform a motion by the action of force induced by external means the object's potential energy transforms into kinetic energy. Or kinetic energy is half the product of mass and square of the velocity.

When a vehicle is in motion. it has both kinetic energy and inertia because a vehicle has velocity and weight respectively. Since kinetic energy is directly proportional to the square of velocity, inertia is directly proportional to weight. In option, we have only kinetic energy options.  

Thus, When a vehicle is in motion, it has kinetic energy. Option C is correct.

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Answer: X + X= 2x or X squared.

Step-by-step explanation:

Answer:

$42

Step-by-step explanation:

Original price: $56

Discount: 25%

A discount of 25% means that the discount is 25% of the price of the item, so you need to subtract 25% of the price of the item from the original price of the item.

Let's find an expression for the amount of the discount.

25% of $56 = 25% * $56 = 0.25 * $56

The amount of discount is 0.25 * $56.

Now we subtract that amount form the original price of $56.

$56 - 0.25 * $56 = $56 - $14 = $42

Answer: The boots cost $42 on sale.

Answer :

[tex] {ab}^{3} [/tex]

Answer:

11.

Step-by-step explanation:

1011 is a number in binary.

To convert 1011 from base 2 to base 10...

1(2^3) + 0(2^2) + 1(2^1) + 1(2^0)

= 1(8) + 0 + 1(2) + 1(1)

= 8 + 2 + 1

= 11

Hope this helps!

Answer:

18 seconds

Step-by-step explanation:

Given the equation for height as a function of time expressed as

h(t) = -16t² - initial height, if initial height is 5,184ft, the expression will become;

h(t) = -16t² - 5,184

t is  time in seconds

h(t) is height in feet

The height of the rope on the ground is zero. In order to calculate the amount of seconds it will take the  piece of rope to hit the ground, we will substitute h(t) = 0 into the modeled equation as shown:

Since the body falls downwards (negative direction), initial height = -5184 ft

h(t) = -16t² - -(5,184)

0 = -16t² + 5,184

0+16t² = 5184

16t² = 5184

16t²/16 = 5184/16

t² = 324

t = √324

t = 18 seconds

Hence, it will take the rope 18seconds to hit the ground.

Answer:18 seconds

Step-by-step explanation:just did the assignment

Answer:

A option is correct

Step-by-step explanation:

We know that one foot contain 12inches so 12 inches is equal to one foot

There are 36 inches is equivalent to 3 feet which scales is the correct answer would be option (E).

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

The operator that performs the arithmetic operation is called the arithmetic operator.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

/ Division operation: Divides left-hand operand by right-hand operand

For example 4/2 = 2

We know that one foot contains 12 inches.

Therefore 12 inches equal one foot

According to option (E),

36 inches is equivalent to 3 feet.

Therefore, the correct answer would be an option (E).

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Answer:

D. 9 forks and 6 spoons

Step-by-step explanation:

Let's calculate how many forks and spoons were made.  We need to guess a pair of variable values that will add up to $24.60.  We'll do this by substituting all the possible pairs in:

Here's the pair for A:

[($1.80 * a) + ($1.40 * b)]

= [($1.80 * 8) + ($1.40 * 10)]

= [$14.40 + $14]

= $28.40

Is $28.40 equal to $24.60? No, this is not correct.

Here's the pair for B:

[($1.80 * a) + ($1.40 * b)]

= [($1.80 * 8) + ($1.40 * 8)]

= [$14.40 + $10.80]

= $25.20

Is $25.20 equal to $24.60? No, this is not correct.

Here's the pair for C:

[($1.80 * a) + ($1.40 * b)]

= [($1.80 * 9) + ($1.40 * 9)]

= [$16.20 + $12.60]

= $28.80

Is $28.80 equal to $24.60? No, this is not correct.

Here's the pair for D:

[($1.80 * a) + ($1.40 * b)]

= [($1.80 * 9) + ($1.40 * 6)]

= [$16.20 + $8.40]

= $24.60

Is $24.60 equal to $24.60? Yes, this is correct.

Therefore, we know the answer is (D) 9 forks and 6 spoons

We can also check by substituting these values to find the amount Trevon's Custom Kitchen Supplies earned last April:

[($4.60 * a) + ($5.40 * b)]

= [($4.60 * 9) + ($5.40 * 6)]

= [$41.40 + $32.40]

= $73.80

This is equal to the amount of money earned last April.

I hope this helps! Tell me if I'm wrong, please!

Answer:

The local maximum and minimum values are:

Local maximum

[tex]g(0) = 0[/tex]

Local minima

[tex]g(5.118) = -350.90[/tex]

[tex]g(-1.368) = -9.90[/tex]

Step-by-step explanation:

Let be [tex]g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}[/tex]. The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

[tex]g(x) = x^{2}\cdot (x^{2}-5\cdot x -14)[/tex]

Then, first and second derivatives of the function are, respectively:

First derivative

[tex]g'(x) = 2\cdot x \cdot (x^{2}-5\cdot x -14) + x^{2}\cdot (2\cdot x -5)[/tex]

[tex]g'(x) = 2\cdot x^{3}-10\cdot x^{2}-28\cdot x +2\cdot x^{3}-5\cdot x^{2}[/tex]

[tex]g'(x) = 4\cdot x^{3}-15\cdot x^{2}-28\cdot x[/tex]

[tex]g'(x) = x\cdot (4\cdot x^{2}-15\cdot x -28)[/tex]

Second derivative

[tex]g''(x) = 12\cdot x^{2}-30\cdot x -28[/tex]

Now, let equalize the first derivative to solve and solve the resulting equation:

[tex]x\cdot (4\cdot x^{2}-15\cdot x -28) = 0[/tex]

The second-order polynomial is now transform into a product of binomials with the help of factorization methods or by General Quadratic Formula. That is:

[tex]x\cdot (x-5.118)\cdot (x+1.368) = 0[/tex]

The critical points are 0, 5.118 and -1.368.

Each critical point is evaluated at the second derivative expression:

x = 0

[tex]g''(0) = 12\cdot (0)^{2}-30\cdot (0) -28[/tex]

[tex]g''(0) = -28[/tex]

This value leads to a local maximum.

x = 5.118

[tex]g''(5.118) = 12\cdot (5.118)^{2}-30\cdot (5.118) -28[/tex]

[tex]g''(5.118) = 132.787[/tex]

This value leads to a local minimum.

x = -1.368

[tex]g''(-1.368) = 12\cdot (-1.368)^{2}-30\cdot (-1.368) -28[/tex]

[tex]g''(-1.368) = 35.497[/tex]

This value leads to a local minimum.

Therefore, the local maximum and minimum values are:

Local maximum

[tex]g(0) = (0)^{4}-5\cdot (0)^{3}-14\cdot (0)^{2}[/tex]

[tex]g(0) = 0[/tex]

Local minima

[tex]g(5.118) = (5.118)^{4}-5\cdot (5.118)^{3}-14\cdot (5.118)^{2}[/tex]

[tex]g(5.118) = -350.90[/tex]

[tex]g(-1.368) = (-1.368)^{4}-5\cdot (-1.368)^{3}-14\cdot (-1.368)^{2}[/tex]

[tex]g(-1.368) = -9.90[/tex]

Answer:

( -1, 15/2) or ( -1, 7 1/2)

Step-by-step explanation:

Formula: ( (x1 + x2)/2, (y1 + y2)/2 )

1. ( (-4 +6)/2, (8 + 7)/2 ) Plug in

2. ( -2/2, 15/2) Add/Subtract

3. ( -1, 15/2) or ( -1, 7 1/2) Divide

Answer:

Coordinates of the midpoint are: (1, 7.5)

Step-by-step explanation:

Find the distance between the x-values of the given points,and the distance between the y-values of them:

distance between 7 and 8 (y-values of N and A respectively) is: 8-7 = 1

then half of that is 0.5, therefore, the midpoint should have for y value the value of the minimum between 7 and 8 (7)  plus 0.5, that is, the y-value of the midpoint is: 7.5

Now for the x-value of the midpoint we do something similar:

The distance between 6 and -4 (x-values of B and A respectively) is: 10 units, half of this is 5, and therefore, the x-value of the midpoint should be at the minimum of those two values (-4) plus 5 units, that is: -4 + 5 = 1

Coordinates of the midpoint are: (1, 7.5)

Answer:

- 5.5 + ( 5/3 ) x( 100-5.5)     ( as per statement given)

-5.5 + (5/3)x(94.5) = -5.5 + 5x31.5 =  -5.5 + 157.5

=152

Step-by-step explanation:

The correct answer is C. $ 9.38

Explanation:

The first step to solve this mathematical problem is to know the price of the shoes. About this, we know the price is 1/4 of $88 plus taxes. You can find how much is 1/4 of $88 by following this process:

1. Write the amounts given

[tex]\frac{1}{4}[/tex]  of [tex]88[/tex]

2. Divide the number by the denominator (bottom number) and then multiply by the numerator

[tex]88[/tex] ÷ [tex]4 = 22[/tex]

[tex]22 x 1 = 22[/tex]

This means the discount was  $22 and $88- $22 = $66, which is the price with the discount. Now, it is necessary to add the sales tax, which can be done by finding the 7% of $66 and adding this number to $66 (the price of the shoes including the 1/4 discount)

1.  Write the values

66 = 100 (66 represents the total or 100%)

x   =  7 (7% is the value you want to know and the x represents the value is not known)

2. Cross multiply

x 100 = 462

3. Find x

x = 462 ÷ 100

x = 4. 62 ( value of taxes)

Now, add the taxes to the price $66 + $ 4.62 = $70.62 (price with taxes). Finally, we know Devon paid using four $20 bills. This means he gave the clerk $80 ($20 x 4 = $80). Finally, to know how much is the change subtract the price of the shoes from the money Devon gave the clerk $80 - $70.62 = $9.38

Answer:

(1, -6)

Step-by-step explanation:

the layout of your question is kind of confusing, but i'm guessing this is the system of equations

x = -y - 5

-3x + 7y = -45

plug in x to the second equation

-3(-y - 5) + 7y = -45

distribute

3y + 15 + 7y = -45

combine like terms

10y = - 60

divide by 10

y = -6

plug y into first equation

x = -(-6) - 5

x = 6 - 5

x = 1

Answer: 5/33

Step-by-step explanation: There are 12 fruits and 5 are oranges.

If you draw an orange, then there are 11 fruits and 4 oranges. (5/12)x(4/11)=20/132 or 5/33 in simplest form.

Answer:

22 is the avrage rate of elavation change in feet per second if a sumbarine dives 440 feet in 20 seconds

-22 is the avrage temature change in degrees

440 is the avrage distance in miles

2.20 is the boys height if that makes sense

Step-by-step explanation:

if it dosent make sent om sorry

Answer:

5.1 cm² approximately

Step-by-step explanation:

A lighter= Area inscribed -1/2r² sin80°

A lighter=π r² (80°/360°) -1/2(5 cm)² sin 80°

A lighter=π(5cm)² (80°/360°) -1/2(5 cm)² sin 80°

A lighter=3.14*25cm²(80°/360°) - 12.5cm² sin 80°

A lighter=17.444…cm² - 12.31009... cm²

A lighter=5.13cm² approximately

Answer:    =approx 5.13  cm²

Step-by-step explanation:

Lets find the area of the region that is blue ( dark blue+light blue)

S= pi*r^2/360*80=pi*25*2/9=pi*50/9

The lighter region' s area is the S- S(triangle marked with dark blue)

The area of this triangle is r^2*sin(80°)/2= 25*sin(80°)/2=

=12.5*sin(80°)

So the required area  Sreg= pi*50/9-12.5*sin(80°)=

= approx 3.14*50/9-12.5*0.985=approx 5.13  cm²

The answer : (x-5)^2 .....................................(x-5)square

For example, for f(x)= x square . For x=1 ,then, y=1 .

But consider the g function. the minimum value that g function has is x is 5. When x is 5, y is 0 . So (x-5)square is the equation of this function.

The complete equation of the blue graph is (x-5)^2.

Function is a type of relation, or rule, that maps one input to specific single output.

In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable). In mathematics and the physical sciences, functions are indispensable for formulating physical relationships.

Linear function is a function whose graph is a straight line

We are given that;

Red graph equation= X^2

Now,

In blue graph it shifted by 5 units to the right

For blue graph

x=5

Putting the value of x in red graph equation

=(x-5)^2

=x^2 + 25 - 10x

Therefore, by the given graph function will be (x-5)^2.

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Answer:

outliers

Step-by-step explanation:

An outlier is a data point that is significantly different from other observations. An outlier might be due to inconsistency in measurements, or due to an error introduced into the experiment. Outliers cans lie extremely high or low of other observation in statistics, and they usually create a big problem for  proper analysis.

Answer:

With 99 %  confidence, it can be said that the population mean driving distance to work ​ (in miles) is between the​ interval's endpoints [19.91 miles, 31.49 miles] .

Step-by-step explanation:

The complete question is: In a random sample of  six  ​people, the mean driving distance to work was  25.7 miles and the standard deviation was  6.7  miles. Assuming the population is normally distributed and using the​ t-distribution, a  99​%  confidence interval for the population mean  mu  is  left parenthesis 14.7 comma 36.7 right parenthesis  ​(and the margin of error is  11.0​).

Through​ research, it has been found that the population standard deviation of driving distances to work is  5.5 .  Using the standard normal distribution with the appropriate calculations for a standard deviation that is​ known, find the margin of error and construct a  99 ​%  confidence interval for the population mean  mu .

Interpret the results. Select the correct choice below and fill in the answer box to complete your choice.  ​(Type an integer or a decimal. Do not​ round.)  

A.  nothing ​%  of all random samples of  six  people from the population will have a mean driving distance to work​ (in miles) that is between the​ interval's endpoints.

B.  With  nothing ​%  ​confidence, it can be said that most driving distances to work​ (in miles) in the population are between the​ interval's endpoints.

C.  It can be said that  nothing ​%  of the population has a driving distance to work​ (in miles) that is between the​ interval's endpoints.  

D.  With  nothing %  confidence, it can be said that the population mean driving distance to work ​ (in miles) is between the​ interval's endpoints.

We are given that in a random sample of  six  ​people, the mean driving distance to work was  25.7 miles and the standard deviation was  6.7  miles.

Through​ research, it has been found that the population standard deviation of driving distances to work is  5.5 .

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~  N(0,1)  

where, [tex]\bar X[/tex] = sample mean driving distance to work = 25.7 miles

             [tex]\sigma[/tex] = population standard deviation = 5.5 miles

            n = sample of people = 6

             [tex]\mu[/tex] = population mean driving distance to work

Here for constructing a 99% confidence interval we have used a One-sample z-test statistics because we know about the population standard deviation.

So, 99% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5% level

                                                      of significance are -2.58 & 2.58}  

P(-2.58 < [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < 2.58) = 0.99

P( [tex]-2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.99

P( [tex]\bar X-2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.99

99% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex] , [tex]\bar X+2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ]

                                            = [ [tex]25.7-2.58 \times {\frac{5.5}{\sqrt{6} } }[/tex] , [tex]25.7+2.58 \times {\frac{5.5}{\sqrt{6} } }[/tex] ]

                                            = [19.91, 31.49]

Therefore, a 99% confidence for the population mean is [19.91, 31.49] .

The margin of error here is = [tex]2.58 \times {\frac{\sigma}{\sqrt{n} } }[/tex]

                                             = [tex]2.58 \times {\frac{5.5}{\sqrt{6} } }[/tex]  = 5.793

With 99 %  confidence, it can be said that the population mean driving distance to work ​ (in miles) is between the​ interval's endpoints [19.91, 31.49] .

Answer:

We reject H₀

we don´t have evidence to claim  the strength of composite B is smaller than the strength of composite B by at least 2 [N]

Step-by-step explanation:

From data, we calculate μ₁, s₁   and, μ₂, s₂ mean and standard deviation of samples A and B respectively

μ₁  =  464,7         s₁  = 13,42       Composite  A

μ₂  = 479,49       s₂ = 13,38        Composite  B

n₁ ; n₂ < 30 then we should use t -student table

Test Hypothesis:

Null Hypothesis                           H₀         μ₂  -    μ₁  >= 2

Alternative Hypothesis               Hₐ         μ₂  -    μ₁  <  2

Assuming CI  95 %    α  = 5 %    α = 0,05   and degree of freedom is

df  =  n₁ + n₂ - 2      df = 9 + 9 - 2        df = 16

Then for a one tail test   t(c) = 1,746     and to compte t(s)

t(s) = ( μ₂  -    μ₁ - 2 ) / sp * √ 1/n₁ + 1/n₂

sp² = ( n₁ - 1 )*s₁²  +   ( n₂ - 1 )*s₂² / n₁  + n₂  - 2

sp² =  8 * (13,42)² +  8 * (13,38)² / 16

sp² = (8 * 180,1  +  8 * 179) / 16

sp² = 179,55

sp = 13,40

then  

t(s) = ( 479,49 - 464,7 - 2 ) / 13,40*√1/9 +1/9

t(s) = 12,79 / 13,40*0,4714

t(s) = 12,79/6,32

t(s) = 2,02

t(s) > t(c)

2,02 > 1,746

t(s) is in the rejection region, therefore we reject H₀  we don´t have evidence to claim  the strength of composite B s smaller than the strength of composite B by at least 2 [N]

Answer:

V(x) = l*w*x  - 2*l*x² - 2*w*x² + 4*x³

Step-by-step explanation:

The volume of any box is:

a * b * h       where a is the length, b is the wide and h is the height

Assuming we have cardboard of dimensions: l * w

l - 2*x  will be length  of the box and  

w - 2*x will be wide of the box

h  =  x the height, then:

V(x) = ( l  -  2*x  ) *  (  w  -  2*x ) * x

V(x) = [ ( l*w - 2*l*x - 2*w*x + 4*x² ] * x

V(x) = l*w*x  - 2*l*x² - 2*w*x² + 4*x³

Answer:

0.83

Step-by-step explanation:

.9 which is .90 minus the weight of the blue block which is.07 is equal to .83 thus making it your answer.

The blue block weighs 0.2 pounds more than the green block.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

The difference between the weights of the colored blocks is how more the blue block weighs than the green block which is,

= (0.9 - 0.7).

= 0.2 pounds.

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Answer:

10 times more

Step-by-step explanation:

Step 1: Find the 2 '4' values

Value 1 is 400

Value 2 is 4,000

Step 2: Divide the lager number with the smaller number

4,000 / 400 = 10

Therefore the first digit is 10 times more than the second digit(Looking from left to right)

Answer:

Option A is the correct option.

Step-by-step explanation:

[tex] \sf{3r - 6}[/tex]

▪️If there is a common factor in each term of an expression, the common factor can be taken as the factor with the remaining terms.

Here, taking 3 common

[tex] \sf{3(r - 2)}[/tex]

Hope I helped!

Best regards!!

Answer: 3(r - 2)

Step-by-step explanation: First, determine the Greatest Common Factor between the different terms in the polynomial.

The Greatest Common Factor between 3r and 6 is 3.

So a 3 factors out.

Inside the parenthses, we are left with each term divided by 3.

So we have 3(r - 2) as our final answer.

Answer:

multiply by 2

Step-by-step explanation:

5x2=10

10x2=20

Answer:

multiplying by 2 ........

Answer:

On average the size of the area of the forest burnt down every minute is 10117.14 m²

Step-by-step explanation:

The given parameters are;

The rate consumption of forest land by the fire = 25200 acres/week

Therefore, we have;

The number of minutes in one week = 60 × 24 × 7 = 10080 minutes

Therefore;

The rate consumption of forest land by the fire per minute = 25200/10080 acres/minute = 2.5 acres/minute

The number of square meters in one acre is given as follows;

1 acre = 4,046.856 m²

Therefore;

2.5 acres/minute = (2.5 × 4,046.856 m²/(1 acre)) acres/minute = 10117.14 m²/minute

Which give;

The rate consumption of forest land by the fire= 10117.14 m²/minute.

The rate of the fire consumption of the forest is 10117.14 m²/minute.

Answer:

63%

Step-by-step explanation:

Given the following :

Average cholesterol level or mean (m) = 194

Standard deviation (sd) = 15

what percentage of children have a cholesterol level lower than 199?

P(X < 199)

Assume a normal distribution :

Find the z-score :

Z = (score - mean) / standard deviation

Score = 199

Z = (199 - 194) / 15

Z = 5 / 15

Z - score = 0.3333

P(Z < 0.33) :

Using the z - table ; 0.33 = 0.6293

P(Z < 0.33) = 0.6293

0.6293 * 100% = 62.93%

= 63% (nearest whole percent)

Answer:

Explained below.

Step-by-step explanation:

Qualitative variables are categorized or labelled to belong to a certain category or group.

There are two types of qualitative variables, Categorical and ordinal.

Categorical variable are those variables that are labelled in non-numeric or numeric form, where the numbers have no value. The order also does not matters. For example, the number on the jerseys of football players. It is not necessary that the player number 1 is actually the best player.

Ordinal variables are those variables where the label or category has to be in order. For example, the rank of students in the statistics class.

Quantitative variables are in numerical form and can be measured.

There are two types of quantitative variables, discrete and continuous.

Discrete variables are those variables that assume finite and specific value. For example, the number of girls in each section of a school.

Continuous variables are those variables that can assume any number of values between a specific interval. For example, the time it takes to reach point B from A.

Variable              Category               Sub-Category

Height              Quantitative              Continuous

 Grade               Qualitative                   Ordinal

Weight              Quantitative              Continuous

  Color                Qualitative               Categorical

Answer:

          2

a =  -  ------

         15

Step-by-step explanation:

15 a = -2  (divide 15 on each side)

15a           2

-----  =  - ------

15            15

          2

a =  -  ------

         15