Calculus3 - Infinite sequences and series ( URGENT!!)​

Calculus3 - Infinite Sequences And Series ( URGENT!!)

Answers

Answer 1

Answer:

Limit=0

Converges

Absolutely converges

Step-by-step explanation:

If [tex]a_n=\frac{2^n n!}{(3n+4)!}[/tex]

then [tex]a_{n+1}=\frac{2^{n+1} (n+1)!}{(3(n+1)+4)!}[/tex].

Let's rewrite [tex]a__{n+1}[/tex] a little.

I'm going to hone in on (3(n+1)+4)! for a bit.

Distribute: (3n+3+4)!

Combine like terms (3n+7)!

I know when I have to find the limit of that ratio I'm going to have to rewrite this a little more so I'm going to do that here. Notice the factor (3n+4)! in [tex]a_n[/tex]. Some of the factors of this factor will cancel with some if the factors of (3n+7)!

(3n+7)! can be rewritten as (3n+7)×(3n+6)×(3n+5)×(3n+4)!

Let's go ahead and put our ratio together.

[tex]a_{n+1}×\frac{1}{a_n}[/tex]

The second factor in this just means reciprocal of [tex]{a_n}[/tex].

Insert substitutions:

[tex]\frac{2^{n+1} (n+1)!}{(3(n+1)+4)!}×\frac{(3n+4)!}{2^nn!}[/tex]

Use the rewrite for (3(n+1)+4)!:

[tex]\frac{2^{n+1} (n+1)!}{(3n+7)(3n+6)(3n+5)(3n+4)!}×\frac{(3n+4)!}{2^nn!}[/tex]

Let's go ahead and cancel the (3n+4)!:

[tex]\frac{2^{n+1} (n+1)!}{(3n+7)(3n+6)(3n+5)}×\frac{1}{2^nn!}[/tex]

Use 2^(n+1)=2^n × 2 with goal to cancel the 2^n factor on top and bottom:

[tex]\frac{2^{n}2(n+1)!}{(3n+7)(3n+6)(3n+5)}×\frac{1}{2^nn!}[/tex]

[tex]\frac{2(n+1)!}{(3n+7)(3n+6)(3n+5)}×\frac{1}{n!}[/tex]

Use (n+1)!=(n+1)×n! with goal to cancel the n! factor on top and bottom:

[tex]\frac{2(n+1)×n!}{(3n+7)(3n+6)(3n+5)}×\frac{1}{n!}[/tex]

[tex]\frac{2(n+1)}{(3n+7)(3n+6)(3n+5)}×\frac{1}{1}[/tex]

Now since n approaches infinity and the degree of top=1 and the degree of bottom is 3 and 1<3, the limit approaches 0.

This means it absolutely converges and therefore converges.


Related Questions

What is the answer. I need it ASAP u have to choose 3 answers

Answers

x= 5
y=1.25 :))))
If it is true, don't forget to click ”thanks♥️” for me

To solve the equation, Lorie applies the distributive property, combines like terms, then applies the addition and subtraction properties of equality to isolate the variable term on one side of the equation and the constant term on the other side. What are the possible coefficients of x after Lorie has completed these steps?

10 (one-half x + 2) minus 5 = 3 (x minus 6) + 1
–32 and 2
–2 and 32
–2 and 2
–32 and 32

Answers

Answer: -2 and 2

For this problem you really need to use algebraic skills. Coefficients refer to the number by the variable. So if you follow the steps it gives you then you’re fine.

Problem:
10(0.5x+2) - 5 = 3(x-6) + 1

Distribute:
5x +20 - 5 = 3x - 18 + 1

Combine like terms:
5x + 15 = 3x - 17

Addition and subtraction properties:
5x - 3x + 15 = -17
2x = -17 -15
2x = -32

OR:
5x + 15 = 3x - 17
15 + 17 = 3x - 5x
32 = -2x

Therefore your answer is -2 and 2 because coefficient is the number being multiplied by the variable. In this case it can be -2 or 2 depending where you move the variables (aka adding them or subtracting them from both sides)

Answer:

-2 and -2

Step-by-step explanation:

please help its urgent​

Answers

Answer:

Step-by-step explanation:

18x-6=120

18x=120+6

18x=126

    x=126÷18

    x=7

In mixture A of candy ingredients there are 3 parts of milk-chocolate for every Z parts peanut separate mixture B. there are 4 parts of nougat for every 3 parts of caramel equat parts of A and combined in one mixing bow what is the ratio of peanut butter to nougat in the bowl

Answers

3m=Z :A
4n=3c :B

If it’s a1:1 for A:B
z:4n

Feel like you left out something but this is what I got from info provided

Answer:

D. 7:10

Step-by-step explanation:

The Correct Answer

There are 5,000 books in the​ town's library. Of​ these, 4,700 are fiction. To find the percent of the books that are​ fiction, first set up the percent equation. Then find the percent.

Answers

Answer:

94%

Step-by-step explanation:

4,700/5,000 x 100%

0.94 x 100% = 94%

Answer:

94%

Step-by-step explanation:

PLEASE HELP ASAP Determine the period.

Answers

That’s easy_________

find the equation of straight line passing through each of the following pairs of points
a) (2,4) and (7,2)​

Answers

Answer:

The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

[tex]y = mx + b[/tex]

In which m is the slope and b is the y-intercept.

Slope:

Having two points, the slope is given by the change in y divided by the change in x. Points (2,4) and (7,2)​, so:

Change in y: 2 - 4 = -2

Change in x: 7 - 2 = 5

Slope: [tex]m = \frac{-2}{5} = -\frac{2}{5}[/tex]

So

[tex]y = -\frac{2}{5}x + b[/tex]

(2,4)

This means that when [tex]x = 2, y = 4[/tex]. So

[tex]y = -\frac{2}{5}x + b[/tex]

[tex]4 = -\frac{2}{5}(2) + b[/tex]

[tex]b = 4 + \frac{4}{5} = \frac{20}{5} + \frac{4}{5} = \frac{24}{5}[/tex]

The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]

Select all the correct answers.

These examples show the application of the negative exponent property. Which two examples correctly apply this property?

Answers

Answer:

First one and Third one

Step-by-step explanation:

Answer is correct from Plato

The correct expressions are:

[tex]17^{-1/4}[/tex] [tex]= \frac{1}{17^{1/4}}[/tex]

[tex]y^{1/2}[/tex] [tex]= \frac{1}{y^{-1/2}}[/tex]

In the given expression,

Since we know that the rule of exponent,

[tex]a^{-n} = \frac{1}{a^n}[/tex]

Therefore,

For the given expression,

[tex]17^{-1/4}[/tex]

Using the above property of exponent we can write it,

[tex]= \frac{1}{17^{1/4}}[/tex]

Hence this is the correct expression.

For the given expression,

[tex]y^{1/2}[/tex]

Using the above property of exponent we can write it,

[tex]= \frac{1}{y^{-1/2}}[/tex]

Hence this is the correct expression.

To learn more about exponent visit:

https://brainly.com/question/31242910

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A box has three balls, one white and two red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Find the probability of the following events:

a. Let F= the event of getting the white ball twice.
b. Let G= the event of getting two balls of different colors.
c. Let H= the event of getting white on the first pick.
d. Are F and G mutually exclusive?
e. Are G and H mutually exclusive?

Answers

Answer:

See explaation

Step-by-step explanation:

Given

Represent the balls with the first letters

[tex]W =1[/tex]

[tex]R =2[/tex]

Solving (a): P(F) --- White balls twice

The event of F is:

[tex]F = \{(W,W)\}[/tex]

So:

[tex]P(F) = P(W) * P(W)[/tex]

[tex]P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(F) = \frac{1}{3} * \frac{1}{3}[/tex]

[tex]P(F) = \frac{1}{9}[/tex]

Solving (b): P(G) --- two different colors

The event of G is:

[tex]G = \{(W,R),(R,W)\}[/tex]

So:

[tex]P(G) = P(W) * P(R) + P(R) * P(W)[/tex]

[tex]P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(G) = \frac{1}{3} * \frac{2}{3} + \frac{2}{3} * \frac{1}{3}[/tex]

[tex]P(G) = \frac{2}{9} + \frac{2}{9}[/tex]

[tex]P(G) = \frac{4}{9}[/tex]

Solving (c): P(H) --- White picked first

The event of H is:

[tex]H = \{(W,R),(W,W)\}[/tex]

So:

[tex]P(H) = P(W) * P(R) + P(W) * P(W)[/tex]

[tex]P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(H) = \frac{1}{3} * \frac{2}{3} + \frac{1}{3} * \frac{1}{3}[/tex]

[tex]P(H) = \frac{2}{9} + \frac{1}{9}[/tex]

[tex]P(H) = \frac{3}{9}[/tex]

[tex]P(H) = \frac{1}{3}[/tex]

Solving (d): F and G, mutually exclusive?

We have:

[tex]F = \{(W,W)\}[/tex]

[tex]G = \{(W,R),(R,W)\}[/tex]

Check for common elements

[tex]n(F\ n\ G) = 0[/tex]

Hence, F and G are mutually exclusive

Solving (e): G and G, mutually exclusive?

We have:

[tex]G = \{(W,R),(R,W)\}[/tex]

[tex]H = \{(W,R),(W,W)\}[/tex]

Check for common elements

[tex]n(G\ n\ H) = 1[/tex]

Hence, F and G are not mutually exclusive

please help meeeeeeeeeeeeeeeeee

pt 1

Answers

Answer:

Completing the square

Step-by-step explanation:

The proof is lengthy, and I don't think you came here to see that whole proof. Here it is anyway to show you the process of completing the square.

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:more-on-completing-square/a/quadratic-formula-proof-review

If 12 muffins cost $27, how much would 2 muffins cost?​

Answers

2 muffins would be $4.5

Question 1 of 10
The number √3 goes on forever with no repeating pattern; therefore, it is
rational.
A. True
B. False
SUBMIT

Answers

the answer should be true

Answer:

False

Step-by-step explanation:

Rational number :

A rational number is a number which can be represent as p/q of two integers where q is not equal to zero

Example: 2/3

[tex]\sqrt{3}[/tex] = 17320508075........ and it keeps extending. Since it does not terminate or repeated after the decimal point.

Therefore [tex]\sqrt{3}[/tex] is an irritational number,

Hence given statement is FALSE

four times the difference of 15 and 6

Answers

Answer:

36

Step-by-step explanation:

9 is the difference

9 times 4 is 36

Subtraction is a mathematical operation. The statement "Four times the difference of 15 and 6" is equal to 36.

What is subtraction?

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.

The statement "Four times the difference of 15 and 6" can be expressed as,

= 4 × (15 - 6)

= 4 × (9)

= 36

Hence, The statement "Four times the difference of 15 and 6" is equal to 36.

Learn more about Subtraction:

https://brainly.com/question/1927340

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Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. The population is observed once a year. Given that the Leslie matrix is equal to

Answers

Answer: hello your question lacks some information attached below is the complete question

answer :

a) attached below

b) 65 students aged 1-2 years

Step-by-step explanation:

For a Leslie matrix ; there is a relation

Pn = L^n Po  where ; Pn = population vector after n years , Po = initial population vector .

a) Initial population vector

attached below

[tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

b) Number of birds aged 1-2 years are available after 10 years

i.e. P10 = L^10 Po

note : Po = Xo

∴ P10 = [tex]\left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]   [tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

we will apply  MATLAB to resolve the above matrix

P10  = [tex]\left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]

∴ Number of children between 1-2 years left after 10 years  = 65.24 ≈ 65

The total number of birds aged between 1-2 years which are available after 10 years is 65 and this can be determined by using the Leslie matrix relation.

Given :

Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. [tex]\rm L = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]

According to the given data, the initial population vector is given by:

[tex]x_0 = \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

Now, the total number of birds aged between 1-2 years which are available after 10 years is:

[tex]\rm P_{10} = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right] \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

Now, solve the above matrices in order to determine the value of [tex]\rm P_{10}[/tex].

[tex]\rm P_{10} = \left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]

Therefore, the total number of birds aged between 1-2 years which are available after 10 years is 65.

For more information, refer to the link given below:

https://brainly.com/question/16823190

Find the length of side x

Answers

no no no no no no no no no no

Answer:

Step-by-step explanation:

tan(30) = x/1

sqrt(3) / 3 = x/1

x= sqrt(3) / 2

Which expression can be modeled using the number line?

Answers

Answer:

7 x 1/10 = 7/10

Step-by-step explanation:

There are 7 "bumps" on the number line, and each "bump" moves the line 1/10.

This can also be modeled as

1/10 + 1/10 + 1/10 +1/10 +1/10 +1/10 +1/10 = 7/10

subtract

a2-b2 from a2 +b2

Answers

Answer:

2b^2

Step-by-step explanation:

according to the question equation is

(a^2 + b^2 ) - (a^2 - b^2)

a^2 + b^2 - a^2 + b^2

plus a square and minus a square gets cancel

b^2 + b^2

since they are like terms they can be added

2b^2

Answer:

2b^2

Step-by-step explanation:

according to the question equation is

(a^2 + b^2 ) - (a^2 - b^2)

a^2 + b^2 - a^2 + b^2

= b^2 + b^2

like terms can be added

+2b^2

help please show work

Answers

7.) 18.8 square kilometers
1/2 • 4.7 x 8 = 18.8

8.) 40.96 square miles
6.4^2 = 40.96

9.) 7 square meters
1/2 • 4 • 3.5 = 7

10.) 36.4 square centimeters
(2.6 + 7.8) ÷ 2 x 7

11.) 22.8 square yards
6 • 3.8 = 22.8

12.) 30.6 square centimeters
5.1 • 6 = 30.6

Explanation:
FORMULAS FOR AREAS OF:
Triangle: 1/2 • base • height
Square: side^2
Parallelogram: base • height
Rectangle: Length • width
Trapezoid: (a + b) ÷ 2 x height
(a & b are the two bases)

hope this helps!

Which is equivalent to f/125)*? O 125+ 0 1254 125" C. 125/11​

Answers

Answer:

I think choose (1)

[tex]125 ^{ \frac{1x}{3} } [/tex]

Tính (1,5)4; ((-2)/3)3; (√3)5.

Answers

Step-by-step explanation:

câu trả lời là trong bức ảnh trên

Evaluate the expression for the given value of the variable.

3x + 4 when x = 2


5y - 3.6 when y = 4


7z4+ 1.05 when z = 1.2


20 - b3.2when b = 5.2

Answers

Answer:

I NOT 100% SURE BUT I THINK ITS .B)

Step-by-step explanation:

Cos15°°- Sin 15°= 1/√2​

Answers

Refer this attachment

Hope it's help you

Pic added
Solve for x.
L
20x + 10
850
K
J
3
8

Answers

Answer:

Option (3)

Step-by-step explanation:

By applying the property of inscribed angle and intercepted arc in the given circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

[tex]m(\angle LKJ)=\frac{1}{2}m(\text{arc LJ})[/tex]

[tex]85=\frac{1}{2}(20x+10)[/tex]

[tex]170=20x+10[/tex]

[tex]20x=160[/tex]

[tex]x=8[/tex]

Therefore, Option (3) is the correct option.

67 2/3% of the animals at an animal shelter are dogs. About what fraction of the animals at the shelter are dogs?

Answers

Answer:

2/3

Step-by-step explanation:

2/3 is 66 2/3%

06.04 find the area of the image below a.24.6 units b.25.8 units c.26.3 units d.27.5 units​

Answers

Its D. 27.5 units.

Divide the figure into one parallelogram and one triangle.

Count the base and height of the parallelogram:
The base is 5 units, the heigth is 3 units.
AREA- 3 • 5 = 15 units

Count the base and height of the triangle:
The base is 5 units, the height is also 5 units.
AREA- 1/2 • 5 • 5 = 12.5

Add the area of the parallelogram and the area of the triangle:
15 + 12.5 = 27.5

SO, the area of the whole figure is 27.5 square units.

BRAINLIEST WILL BE APPRECIATED!
Have a nice day -SpaceMarsh

A TRIANGLE HAS SIDE LENGTH 3, 8 AND 9. FIND THE ANGLE MEASUREMENTFOR THE ANGLE CROSS FROM THE SIDE WITH LENGTH OF 8.

Answers

Answer:tu culo

Step-by-step explanation:

solve for x 7_3x=2x_3
[tex]7 - 3x = 2x - 3 = [/tex]

Answers

Answer:

x=2

Step-by-step explanation:

[tex]7 - 3x = 2x - 3 \\ 7 - 3x - 2x = - 3 \\ 7 - 5x = - 3 \\ - 5x = - 3 - 7 \\ - 5 = - 10 \\ x = \frac{ - 10}{ - 5} \\ x = 2[/tex]

HOPE IT HELPS!!!

I NEED BRAINLIEST ✌️ PLZ

ANYONE KNOW THE ANSWER TO THIS??

Answers

Answer:

x = 14 is your answer

Step-by-step explanation:

76 = 7x-22, so to figure it out, you first move -22 to the other side and get

76+22 = 7x.

add them together and you get 98 = 7x

7x would be your equation, so divide 98 by 7 and you get your solution

x = 14 is your answer

the answer is B: x=14

Which operation should you perform first in the expression 7x2^3?

Answers

Answer:

Below,

Step-by-step explanation:

The exponent part is done first

7 x 2^3

= 7 * 8

= 56.

You use the acronym PEMDAS:-

( E ( exponential) comes before  M (multiply))

Please can you help me

Answers

Answer:

[tex]x = 24.75[/tex]

Step-by-step explanation:

Required

Find x

To find x, we have:

[tex]\angle PQR + \angle RPQ + \angle QRP = 180[/tex] -- angles in a triangle

Because [tex]\bar {PR}[/tex] is extended to S, then:

[tex]\angle QRS = \angle QRP[/tex]

So, we have:

[tex]2x + 6 + x - 7 + 5x -17 = 180[/tex]

Collect like terms

[tex]2x + x + 5x = 180 + 17 + 7-6[/tex]

[tex]8x = 198[/tex]

Divide by 8

[tex]x = 24.75[/tex]

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