Wavelength is defined as the distance between two consecutive points on a wave that are in phase, or have the same phase. Velocity, on the other hand, is defined as the rate at which an object moves in a certain direction.
In this case, we can assume that the ball is moving in a straight line, so we can use the equation v = λf, where v is the velocity of the ball, λ is the wavelength, and f is the frequency of the wave. Since the ball is not producing a wave, we can assume that f is equal to zero, so the equation simplifies to v = λ x 0, or λ = v/0.
Thus, we can simply divide the velocity of the ball by zero to get the wavelength. However, dividing by zero is undefined, so we need to find a different way to approach this problem. One possible solution is to assume that the ball is a particle, not a wave, and use the equation λ = h/mv, where h is Planck's constant, m is the mass of the particle, and v is the velocity of the particle.
Using this equation, we can plug in the values given in the question to get:
λ = (6.626 x 10^-34 J s)/(0.25 kg x 0.20 m/s) = 1.33 x 10^-32 m
Therefore, the wavelength of the 0.25-kg ball traveling at 0.20 m/s is 1.33 x 10^-32 m, expressed to two significant figures. The appropriate units are meters (m).
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The wavelength of the 0.25-kg ball traveling at 0.20 m/s is approximately 1.3 x 10^-32 m.The wavelength of a 0.25-kg ball traveling at 0.20 m/s cannot be calculated directly as wavelength is a property of waves, not objects in motion. However, we can use the de Broglie wavelength formula, which relates the wavelength of a particle to its momentum:
λ = h/p
where λ is the wavelength, h is Planck's constant (6.626 x 10^-34 J s), and p is the momentum of the particle.
To find the momentum of the 0.25-kg ball, we can use the equation:
p = mv
where p is the momentum, m is the mass of the object, and v is its velocity. Substituting the given values:
p = (0.25 kg)(0.20 m/s) = 0.05 kg m/s
Now we can plug this into the de Broglie wavelength formula:
λ = (6.626 x 10^-34 J s) / (0.05 kg m/s)
λ ≈ 1.33 x 10^-32 m
Expressing our answer to two significant figures and including the appropriate units, the wavelength of the 0.25-kg ball traveling at 0.20 m/s is approximately 1.3 x 10^-32 m.
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Several short trips taken from a cold start can use ....... as much fuel as a longer multi-purpose trip covering the same distance when the engine is warm.
Several short trips taken from a cold start can use ...twice... as much fuel as a longer multi-purpose trip covering the same distance when the engine is warm.
In cold weather, properly designed gasoline aids in engine starting, while in hot weather, it helps prevent vapor lock. In order to meet the requirements of a modern engine, the fuel must have the volatility for which the engine's fuel system was built and an antiknock quality strong enough to prevent knock during routine operation.
During the intake phase, the air and fuel are combined before being introduced into the cylinder. The spark ignites the fuel-air mixture after the piston compresses it, resulting in combustion. During the power stroke, the piston is propelled by the expansion of the combustion gases.
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What is the voltage drop across the 10.0 ohm resistor?
The voltage across all the resistors is the same i.e 120V
Each element of the parallel circuit has the same voltage applied to it. The total current flowing from the source is equal to the sum of the currents across each path. The electric potential difference (V) across each resistor in a parallel circuit is the same. Ohm's law states that I = V / R applies to the current in a resistor. The current will be lowest where the resistance is highest since the V is the same for each resistor. The currents passing through each resistor in a parallel combination have the same voltage across them because of their different resistance values and the laws of Ohms i., If two or more components are connected in parallel, they will be having same difference of potential (voltage) across their ends Parallel circuits are then used as current dividers.
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Location C is 0.02 m from a small sphere which has a charge of 3 nanocoulombs uniformly distributed on its surface. Location D is 0.06 m from the sphere. What is the change in potential along a path from C to D?
sorry for the late reply back I have been working on this project for a year now so it will not care if we can get the best of him and also has a full one of the most common misconceptions is that Africa is one large country and its followers are known as Sikhs and is the last survivor from the whole family and the fearful of all that is a metaphor of joy organised by the way I have
The change in potential along a path from C to D due to a small charged sphere is 900 V.
Given:
Charge, Q = 3 nC = 3 × 10⁻⁹ C
Distance between the sphere and point C, r₁ = 0.02 m
Distance between the sphere and point D, r₂ = 0.06 m
Calculation:
We know that the electric potential is given as:
V = k Q/r - (1)
where, V is the electric potential
k is Coulomb's force constant
Qis the charge on the sphere
r is the separation distance
The electric potential at point C due to charged sphere can be given as:
V₁ = k Q/r₁
= (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.02 m)]
= 1350 V
The electric potential at point D due to charged sphere can be given as:
V₂ = k Q/r₂
= (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.06 m)]
= 450 V
Now, the change in potential along the path from C to D can be calculated as:
ΔV = V₂ - V₁
= 450 V - 1350 V
= -900 V
The negative sign indicates that the work is done against the electric field in moving the charge from C to D.
Therefore, the change in potential along a path from C to D is 900 V against the direction of the electric field.
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A 3.5 mH inductor and a 4.5 mH inductor are connected in parallel. When the total emf of the combination is 16 V, the rate of change of the current in the larger inductor is:
The rate of change of the current in the larger inductor is 0.3mA/s.
To find the answer, we need to know about the relation between the emf and inductance.
What's the mathematical expression to find the emf in term of inductance?Mathematically, emf induced across an inductor= L× (dI/dt)L= inductance and dI/dt = rate of change of currentWhat is the rate of change of current in 4.5 mH when when the total emf of the combination is 16 V?As both the inductors are connected in parallel, so emf of the combination remains same across each inductor.Emf induced in 4.5mH = 16 V dI/dt = 4.5mH / 16 = 0.3 mA/sThus, we can conclude that the rate of change of the current in the larger inductor is 0.3mA/s.
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Air that is not saturated will cool or heat at a rate of __________________ as it rises or descends, respectively
Air that is not saturated will cool or heat at a rate of 10 degrees C/1000 meters as it rises or descends, respectively
The rate of the change in temperature which is observed while moving upward in the earth's atmosphere with elevation. It can be positive, negative and zero when the temperature decreases, increases or is constant with the elevation respectively.
For the atmosphere, the drop in temperature of rising air that is unsaturated air is about 10 degrees C/1000 meters (5.5 °F per 1000 feet) altitude.
That means if a there occur a rise of 1000 m , then the temperature of that thing will decrease to 10 degrees. Every 10°C of temperature from the given temperature will decrease at every rise of 1000 m .Air that is not saturated will cool or heat at a rate of 10 degrees C/1000 meters as it rises or descends, respectively
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A block with a mass of 2kg is pushed 20cm and a constant speed up an incline that makes a 40 degree angle with the floor. how much work is done by gravity on the block ? let d be the displacement of the block.
work done will be 2.5872 J
Given :
mass of block = 2kg
distance travelled by block = 20cm
angle of inclination = 40°
To Find :
Work done by gravity
Solution :
Gravity is defined as the force that attracts a body towards the earth or towards any other physical body having mass.
work done by gravity is mgh
If θ is the angle made when the body falls, the work done by gravity is given by,
W = m g h cosθ
W = 2 x 9.8 x 0.2 x cos40°
= 2.5872 J
So work done will be 2.5872 J
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A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 T. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod? A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 T. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod? 7.6 A 2.5 A 9.8 A 4.9 A 1.2 A
The minimum current in the rod needed is 4.9 A for the magnetic force to cancel the weight of the rod.
What is a magnetic field?
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.
A moving charge in a magnetic field experiences a force perpendicular to its velocity and the magnetic field.
Force on a current carrying rod due to the magnetic field is given as:
F = i*L*B
Where,
i is current in the rod.
L is the length of rod = 1 m
B is magnetic field = 0.10 T
Here,
The Magnetic force is balanced by the weight of the rod
i*L*B = m*g
i* ( 1 )* ( 0.10 ) = 0.05 * 9.8
i = 4.9 A
Hence, option d is correct.
The minimum current in the rod needed is 4.9 A for the magnetic force to cancel the weight of the rod.
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A thin stream of water bends toward a negatively charged rod. When a positively charged rod is placed near the stream, it will bend in the same direction, not the opposite direction. Why
Water bends in the same direction irrespective of the charge of the rod placed near it is because water is dipole- that hydrogen is positively charged and oxygen is negatively charged and thus either of the particle is attracted by the charged rod.
The reason behind it:
As a neutral substance, water has an equal number of positive and negative charges. The negatively charged electrons migrate away from the negatively charged rod and the positively charged protons move toward the rod when the negatively charged rod is placed closer to the water. Water then adheres to the rod. Protons migrate away from the positively charged rod, just as they do when it is moved closer to the water, while electrons flow in its direction. As a result, the water and rod form a relationship.
The partial +ve charge on H is drawn to the -ve charged rod when it is installed, which causes the water stream to bend in the direction of the charged rod.
The partial -ve charge on O is drawn to the +ve rod when it is installed, causing the water stream to bend in the direction of the rod.
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Why is the molten metallic outer core and the magnetic field important to life on earth?.
Earth's magnetic field and molten metallic outer core creates barrier to stop Sun's radiation to strip away our atmosphere.
As we know that inside the earth there are several layers of the earth. The outer one is the Earth's crust which is all the ground we have , then we have the mantle that consist upper and lower crust. And then after we have outer and inner crust.
The outer core is made of molten material that consist of mainly iron and other ferrous metals. The core is important for many reasons-
The inner core rotates counter to the outer core which in return creates powerful magnetic field. And this magnetic field creates barrier to stop Sun's radiation to strip away our atmosphere.The outer core is conveniently under the crust which is fragmented into tectonic plates. Because of this, the terrain changes and sometimes holes are formed in the crust allowing volcanoes to form. The volcanoes provide all sorts of natural gases which is essentials to life and also help in creating very fertile land in which animals can thrive.Learn more about earth's magnetic field here:
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Technical skills: knowledge base of sport rearrange our coaching skills from best (at the top) to worst (at the bottom) by dragging each skill to where you think it belongs. this should help you identify your current strengths and limitations as a teacher/coach. after organizing each group of skills, describe steps you think you can take to enhance your strengths and being to address your limitations as a coach.
The steps which enhance strengths and address limitations as a coach include:
Identifying weakness.Setting goals.Consistency.Who is a Coach?This is referred to a professional who gives special training about a particular subject or topic.
It is best to identify weakness and work towards improvement through determination and consistency.
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If we have a sample of silicon (si) atoms that has 14 protons, 14 electrons, and 18 neutrons
Its silicon-32 because if you want to find an isotope, you have to add the number of protons (14) and number of neutrons (18) to get 32 as your total.
There are 23 known isotopes of silicon (14Si), with mass numbers ranging from 22 to 44. Stable isotopes include 28Si (92.23 percent), 29Si (4.67 percent), and 30Si (3.1 percent). The longest-lived radioisotope is Si-32, which is created by argon cosmic ray spallation.
What is the half-life of an ionic compound with a mass of 32?silicon-32 has a half-life of about 150 years (with a decay energy of 0.21 MeV) and decays by beta emission to 32P (which has a half-life of 14.28 days) and then to 32S. Si-32 has the second longest half-life after Si-32, at 157.3 minutes. All others have half-lives of less than 7 seconds.
Which element has the heaviest stable isotope?Bismuth, the 83rd element, was previously thought to have the heaviest stable isotope, bismuth-209, but in 2003, researchers in Orsay, France, measured the half-life of 209 Bismuth to be 1.91019 years. Only isotopes of technetium and promethium, as well as all elements with an atomic number greater than 82, are known to decompose via radioactive decay. Because no undiscovered elements are expected to be stable, lead is regarded as the heaviest stable element.
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A 40.0 N crate is pulled up a 5.0 m inclined plane. The angle of inclination of the plane to horizontal is 37o. If there is a constant force of friction of 10.0 N between the crate and the surface, what is the net gain in potential energy by the crate? Group of answer choices 120 J -120 J 210 J -210 J
The net gain in potential energy by the crate is 120 J.
What is potential energy?Potential energy is the energy that an object has stored in it as a result of its position or condition. Potential energy exists in a stretched spring, a book held above your head, and a bicycle on top of a hill. The joule, which is represented by the letter "J," is the standard unit for calculating potential energy.
Calculation:We use the idea of potential energy, which is given by the equation,
PE = mgh
where,
m = mass of the crate
g = gravitational acceleration
h = height
Given,
mg = 40 N
L = 5 m
angle of inclination, ∅ = 37°
h = L sin∅
h = 5 (sin 37°)
h = 5 (3/5)
h = 3 m
Put the values in the above formula,
PE = mgh
PE = 40 (3)
PE = 120 J
Therefore, the net gain in potential energy by the crate is 120 J.
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A new CFD method for determination of translational added mass coefficients of an underwater vehicle
A new CFD method for determination of translational is RANS simulations
What is CFD?Using numerical analysis and data structures, the field of computational fluid dynamics (CFD) studies and resolves issues involving fluid flows. The computations necessary to model the fluid's free-stream flow and its interactions with surfaces constrained by boundary conditions (both liquids and gases) are done on computers. Better answers can be found using high-speed supercomputers, which are frequently needed to address the most challenging issues.
Five prominent CFD methods -
Finite Difference Method (FDM)Finite Volume Method (FVM)Finite Element Method (FEM)Lattice Boltzmann Method (LBM)Smoothed Particle Hydrodynamics (SPH)to learn more about Fluid dynamics go to - https://brainly.com/question/5144636
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At 30° north latitude, at the northern edge of tropical (hadley) cell convection in the northern hemisphere, ________.
a. cool
b. dry
c. air sinks
d. becoming drier as it heats up
At 30° north latitude, at the northern edge of tropical (Hadley) cell convection in the northern hemisphere d. becoming drier as it heats up
Hadley cells: A cell in the tropics is called Hadley cell. Ferrel cells: In the middle latitudes the circulation is that of sinking cold air that comes from the poles and the rising warm air that blows from the subtropical high. At the surface these winds are called westerlies and the cell is known as the Ferrel cell.
As air is warmed at the equator it becomes less dense and rises, while at the poles the cold air is denser and sinks.
Because of the rotation of the Earth and the Coriolis Effect, rather than a single atmospheric convection cell in each hemisphere, there are three major cells per hemisphere. Warm air rising at the equator cools as it moves through the upper atmosphere, and it descends at around 30° latitude.
The convection cells created by rising air at the equator and sinking air at 30° are referred to as Hadley Cells, of which there is one in each hemisphere. The cold air that descends at the poles moves over the Earth’s surface towards the equator, and by about 60° latitude it begins to rise, creating a Polar Cell between 60° and 90°.
correct option is d. becoming drier as it heats up
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A machine has a mechanical advantage of 0.6. what force should be applied to the machine to make it apply 600 n to an object? 100 n 360 n 1000 n 3600 n
Answer:
frictional force, should be applied to the machine
Answer: C) 1000N is needed to be applied.
Explanation: Have a Good day!!
An 80-N crate is pushed at constant speed for a distance of 5.0 m upward along a smooth inclined plane that makes an angle of 30o with the horizontal. If the force on the crate is parallel to the slope, what is the work done by the pushing force? Group of answer choices 260 J 200 J 61 J 140 J -200 J
The work done by the pushing force is 200 J; option B.
What is work done in an inclined plane?The work done in an inclined plane is given by the formula below:
Work done = Force * distanceForce, F = mgsinθ + ma
where a = 0
Work done = 80 * 5 * sin 30°
Work done = 200 J
In conclusion, work done is the product of force and distance.
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Answer the following regarding Momentum Change and Force:
A) A top-class tennis player can serve the ball, of mass 57 g, at an initial horizontal speed of 50 m/s. The ball remains in contact with the racket for 0.05 s. Calculate the average force exerted on the ball during the serve.
B) A motor car of mass 3000 kg moving with 72 km h-1 made to reduce its speed to 18 km h^-1, in 40 s, by applying brakes. Find the resistive force.
A. The average force exerted on the ball during the serve is 57 N
B. The resistive force, given the data is -1125 N
A. How to determine the average forceMass (m) = 57 g = 57 / 1000 = 0.057 KgInitial velocity (u) = 50 m/sTime (t) = 0.05 sAcceleration (a) = u / t = 50 / 0.05 = 1000 m/s²Force (F) = ?F = ma
F = 0.057 × 1000
F = 57 N
B. How to determine the resistive forceMass (m) = 3000 KgInitial velocity (u) = 72 Km/h = 72 / 3.6 = 20 m/sFinal velocity (v) = 18 Km/h = 18 / 3.6 = 5 m/sTime (t) = 40 sForce (F) = ?F = m(v – u) / t
F = 3000(5 – 20) / 40
F = -1125 N
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A student is given a box containing ten similar plastic drinking straws, a 30 cm ruler and two set-squares. (a) Explain how the student determines an average value for the external diameter of the straws using this apparatus. Draw a diagram to illustrate your answer.
The way to perform the experiment is illustrated below.
How to perform the experiment?Place each straw tightly without deforming the roundness of the straw into the corner of the set square.
Measure the distance from the corner of the set square to where the straw touches the set square using the 30 cm ruler. This will be the radius of each straw.
Multiply this radius by 2 in order to obtain the diameter of each straw.
Sum the diameter of each of the 10 straws.
Divide this sum by 10 to obtain the average value for the diameter of a straw.
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Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial planet's geological destiny?
Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .
According to the question
Terrestrial Planets:
They belongs to a class of planets that are like the earth
Geological destiny :
Geology is biological destiny: Whatever minerals land or are deposited in a place determine what or who can make a living there millions of years later
Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial planet's geological destiny
i.e
The size of terrestrial planet is one of the factors to play the most important role in a terrestrial planet's geological destiny
which determines how long the planet can retain internal heat, which drives geological activity because Smaller worlds cool off faster and harden earlier .
Hence, Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .
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As the volume of a chamber decreases, the pressure inside the chamber ____________ . as the volume increases, the pressure ____________ .
Answer: Increases, decreases
Explanation:
As the volume of a chamber decreases the pressure inside the chamber increases. As the volume increases the pressure decreases
Differences between sublimation and condensation
The difference between sublimation and condensation is that
Sublimation is used to in a separation technique to separate sublime substance from a mixture while condensation is the
is the process where water vapor becomes liquid
What is separation technique?This technique is used in chemistry to separate two or more constituents from a mixture
In conclusion, sublimation differs from condensation because sublimation is used to in a separation technique to separate sublime substance from a mixture while condensation is the
is the process where water vapor becomes liquid
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A marching band is practicing. The band director sees the drum major hit a drum. How far away is the director if he hears the drumbeat in 0.40 seconds
The director is 132 meters away from the marching band when the sound travels to him at 330 m/s.
The speed of sound is 330 m/s.
Time taken by sound to travel = 0.40 seconds
Speed = Distance/Time
The temperature of the air that the sound travels through affects the speed of the sound. Assuming an air temperature of 59 degrees Fahrenheit (15 degrees Celsius), the speed of sound at sea level on Earth is 761.2 mph (1,225 km/h).
The speed of sound is slowed down because gas molecules move more slowly at lower temperatures; sound travels more quickly through warmer air. As a result, higher in the atmosphere, where it is colder, the speed needed to break the sound barrier drops.
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Energy in should always be equal to energy out. select an answer and submit. for keyboard navigation, use the up/down arrow keys to select an answer.
a. true
b. false
Energy in should always be equal to energy out. This is a False statement.
- Energy In: Energy put into the body in form of calories from food like fats, carbohydrates and proteins.
- Energy Out: Energy burn for basic functions of the body like beating of the heart during physical movements.
When we consume more energy but does not consume it upto its potential, the body keeps storing the excess amount of energy as body fat. Maintaining a balance between Energy In and Energy Out is important to live a healthy lifestyle since the disbalance creates problems to the body.
It is easier to accurately measure change in energy than to measure the amount of energy present.
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A stone is thrown horizontally from the top of a tower at the same instant a ball is droppedvertically. Which object is traveling faster when it hits the level ground below?
The ball is travelling faster when the two objects hits the level ground below.
Time of motion of the objectsThe time of motion of the objects depends on height and initial velocity of projection of the objects.
The stone has no initial vertical velocity while the ball has initial vertical velocity.
Thus, the ball is travelling faster when the two objects hits the level ground below.
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The figure in Figure 1 shows two single-slit diffraction patterns. The distance between the slit and the viewing screen is the same in both cases. Which of the following could be true
Answer:
"The wavelengths are the same for both. The width of slit 1 is larger than the width of slit 2."
Explanation:
The full question has not been provided, so I just copied this into the web and found this answer and explanation on quizlet:
"The wavelengths are the same for both. The width of slit 1 is larger than the width of slit 2.
D sin θ = m λ
if the wavelengths are the same, then if the angle is smaller, the slit width must be larger. The top photo shows a pattern that is more closely spaced. That means the angle is smaller. The slit width must be larger."
This answer/explanation should be correct, as we are looking at bright fringes and the formula being used corresponds to the parameters of the question.
Hope this helps!
7. A battery is used to light a 24 W electric lamp. The battery provides a charge of 120 C in
60 s.
TH
24W
What is the potential difference across the lamp?
Answer:
power p =24 watt
charge q=120 C
time t = 60s
let V be the potential difference
we know that
work done =qV = pt
qV = Pxt
120V = 24 * 60
V = (24 * 60) / 120
V = 12 volts
If a star appears to move relative to other stars over a one-year period, this motion is due to the star's: Doppler shift. radial motion. parallax shift. transverse motion. true space motion.
If a star appears to move relative to other stars over a one-year period, this motion is due to the star's true space motion.
What is the proper motion of stars?
Proper motion is the angular change in position of a star across our line of sight, measured in arc seconds per year, and symbolized with the letter μ.
Proper motion is generally measured by measuring the movement of the image of a star with respect to more distant background stars over that time period.
Here we are told that star appears to move relative to other stars over 1 year period.
So we know that,
True space motion is the annual apparent motion of a star across the sky.
True Space Motion is Combination of radial velocity, proper motion, and distance.
Hence,
If a star appears to move relative to other stars over a one-year period, this motion is due to the star's true space motion.
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A rectangle has an area measuring 1350 square centimeters. Its length and width are whole numbers of centimeters. What are the possible combinations of length and width? which possibility gives the smallest perimeter?.
The smallest perimeter of the rectangle is of value 150 cm.
Given:
The area of the rectangle, A = 1350 cm²
Calculation:
Let the length of the rectangle be 'x'
the breadth of the rectangle be 'y'
We know that the area of a rectangle is given as:
A = (x) × (y)
Applying values in the above equation we get:
xy = 1350 cm²
Factorizing the value of 1350, the possible values of length and breadth of the rectangle is as listed below:
x (cm) y (cm)
1350 × 1
675 × 2
450 × 3
270 × 5
225 × 6
150 × 9
135 × 10
90 × 15
75 × 18
54 × 25
50 × 27
45 × 30 (least possible value)
Thus, the smallest perimeter of the rectangle can be calculated as:
P = 2 (x + y)
= 2 (45 + 30)
= 150 cm
Therefore, the smallest perimeter that the rectangle will have is 150 cm.
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A Carnot engine operates between a hot reservoir at 320 degrees Kelvin and a cold reservoir at 260 degrees Kelvin. If it absorbs 500 Joules of heat at the hot reservoir, how much work does it deliver
The work done delivered by the Carnot engine is 93.75 J.
What is Carnot Engine?Leonard Carnot proposed the Carnot engine, a hypothetical thermodynamic cycle. It calculates the highest feasible efficiency that a heat engine can have when converting heat into work and when operating between two reservoirs.Any system working between [tex]T_1[/tex] (hot reservoir) and [tex]T_2[/tex] (cold reservoir) will never have better efficiency than the Carnot engine running between the identical reservoirs.Additionally, the efficiency of this form of engine is only reliant on the temperature of the hot and cold reservoirs and is independent of the composition of the working substance.Solution:
[tex]T_c = 260 K\\ T_h = 320K\\ Q_h = 500J[/tex]
As we know that Carnot engine is ideal, the efficiency depends only on the temperature of the reservoirs(in kelvin scale):
[tex]n = 1 - \frac{T_c}{T_h} \\n = 1 - \frac{260}{320}[/tex]
[tex]n = 1- 0.8125\\n = 0.1875[/tex]
Also, we know that the work done is equal to product of efficiency and heat at hot reservoir:
[tex]W = n\times Q_h\\W = 0.1875 \times 500\\W = 93.75 J[/tex]
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What tidal volume typically maintains normal oxygenation and elimination of carbon dioxide acls?
The tidal volume which typically maintains normal oxygenation and elimination of carbon dioxide is 8 to 10 ml/kg of body mass.
What is tidal volume?Tidal volume refers the amount of air that moves in and out of the lungs in one respiratory cycle.
During a respiratory cycle, oxygen moves into the lungs and the tissues during inhalation, while carbon dioxide moves out of the lungs during exhalation.
The continuous outward movement of carbon dioxide and inward movement of oxygen ensures that the body maintains homeostasis and internal or tissue respiration continues.
The normal tidal volume is about 500 ml per inspiration or 7 ml/kg of body mass.
However, for normal oxygenation and elimination of carbon dioxide, a tidal volume of about 8 to 10 ml/kg of body mass is required.
In conclusion, the tidal volume is a measure of the amount of air flow in the lungs for each respiratory cycle.
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