Calculate the volume in milliliters of a 5.11/mol silver nitrate solution that contains 175.g of silver nitrate AgNO3. Round your answer to 3 significant digits.

Answer:

Carbon is stored on our planet in the following major sinks (1) as organic molecules in living and dead organisms found in the biosphere; (2) as the gas carbon dioxide in the atmosphere; (3) as organic matter in soils; (4) in the lithosphere as fossil fuels and sedimentary rock deposits such as limestone, dolomite

Answer:

soil

Explanation:

some organisms aren't plants

The answer is:

A.(soil)

Some organisms need soil but not all, hope this helps!

The volume : V = 45.22 L

Given

Moles = n = 2

Pressure = P = 780 torr = 1,02632 atm

Temperature = T = 10 + 273 = 283 K

Required

Volume

Solution

Ideal gas law : PV = nRT

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

V = (nRT)/P

V = (2 x 0.082 x 283)/1,02632

V = 45.22 L

Answer:

1) Heat

Explanation:

Heat Transfer: The movement of heat from a warmer object to a colder one

Answer:At the molecular level, the pressure of a gas depends on the number of collisions its molecules have with the walls of the container. If the pressure on the piston is doubled, the volume of the gas decreases by one-half. The gas molecules, now confined in a smaller volume, collide with the walls of the container twice as often and their pressure once again equals that of the piston.

Explanation:

Answer:

thanks

Explanation:

Answer:

109.34 g

Explanation:

2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)

Number of moles of NaOH = 105g/40g/mol = 2.6 moles

From the reaction equation;

2 moles of NaOH yields 1 mole of sodium sulphate

2.6 moles of NaOH yields = 2.6 × 1/2 = 1.3 moles of sodium sulphate

Number of moles of H2SO4= 75.5g/98 g/mol = 0.77 moles

From the reaction equation;

1 mole of H2SO4 yields 1 mole of sodium sulphate

Hence, 0.77 moles of H2SO4 yields 0.77 moles of sodium sulphate

So H2SO4 is the limiting reactant.

Theoretical yield = number of moles × molar mass

= 0.77 mol ×142 g/mol

= 109.34 g

Answer:

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

[tex]moles=\frac{510 mL*1.6 moles}{1000 mL}[/tex]

moles= 0.816

Being the molar mass of the elements:

So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

[tex]mass=\frac{0.816 moles*101 grams}{1 mole}[/tex]

mass= 82.416 grams

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Answer:

CHO₂

Explanation:

The following data were obtained from the question:

Carbon (C) = 26.68%

Hydrogen (H) = 2.24%

Oxygen (O) = 71.08%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 26.68%

H = 2.24%

O = 71.08%

Divide by their molar mass.

C = 26.68 /12 = 2.223

H = 2.24 / 1 = 2.24

O = 71.08 / 16 = 4.4425

Divide by the smallest.

C = 2.223 / 2.223 = 1

H = 2.24 / 2.223 = 1

O = 4.4425 /2.223 = 2

Thus the empirical formula of the compound is CHO₂

The correct empirical formula of a compound containing 26.68% carbon, 2.24% hydrogen, and 71.08% oxygen is CHO₂

The empirical formulae shows us how elements in a compound are in their simplest ratio.

From the question, we can see  

Carbon (C) with  26.68%

Hydrogen (H)with  2.24%

Oxygen (O) with 71.08%

Now, the empirical formula of the compound can begotten following these steps:

Carbon  = 26.68 /12 = 2.223

Hydrogen= 2.24 / 1 = 2.24

Oxygen  = 71.08 / 16 = 4.4425

C arbon = 2.223 / 2.223 = 1

H ydrogen= 2.24 / 2.223 = 1

Oxygen  = 4.4425 /2.223 = 2

Giving us the empirical formula of the compound as CHO₂

See related question here:https://brainly.com/question/14044066

Answer:

B) Leah kicked the soccer ball with more force than Seth.

Explanation:

The true statement is that Leah kicked the soccer ball with more force compared to Seth.

We know that both balls have the same mass and that Seth's ball went further compared to Leah's ball.

 So;

       Force  = mass x acceleration

We are sure that Leah's ball has a greater acceleration due to the force applied and it will travel farther due to the energy it contains.

Answer:

B and C

Explanation:

The different types of motor nerves transmit information to and from muscles, and they connect to muscle fibers through the motor endplate.

The actual value is greater than the theoretical value

Given

Reaction

Sb2S3 + 3Fe --> 2Sb + 3FeS

0.022 mol Sb2S3

0.08mol Sb

Required

The percent yield

Solution

Percent yield is the comparison of the amount of product obtained from a reaction(actual) with the amount you calculated (theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

Theoretical yield of Sb : 2/1 x 0.022 mol = 0.044 moles

In the question, there seems to be an error, because the actual yield value(0.08=?) should be smaller than the theoretical yield(0.044)

Answer:

2C2 H6 +7O2=4co2+6h2o+heat

Answer:

0.00246kg

Explanation:

1g = $40.63

$100 = $100/40.63 = 2.46g

2.46/1000 g = 0.00246kg

Answer:

How many grams Acetic Acid in 1 mol? The answer is 60.05196.

We assume you are converting between grams Acetic Acid and mole?

(人◕ω◕)

Explanation:

You can view more details on each measurement unit:

molecular weight of Acetic Acid or mol

The molecular formula for Acetic Acid is CH3COOH.

The SI base unit for amount of substance is the mole.

1 grams Acetic Acid is equal to 0.016652245821785 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams Acetic Acid and mole.

Examples

1 grams Acetic Acid to mol = 0.01665 mol

10 grams Acetic Acid to mol = 0.16652 mol

20 grams Acetic Acid to mol = 0.33304 mol

30 grams Acetic Acid to mol = 0.49957 mol

40 grams Acetic Acid to mol = 0.66609 mol

50 grams Acetic Acid to mol = 0.83261 mol

100 grams Acetic Acid to mol = 1.66522 mol

200 grams Acetic Acid to mol = 3.33045 mol

The given question is incomplete. The complete question is:

Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Answer:   0.0484 g

Explanation:

[tex]Q=I\times t[/tex]

where Q= quantity of electricity in coloumbs

I = current in amperes = 0.920 A

t= time in seconds = 47.0 sec

[tex]Q=0.920A\times 47.0s=43.24C[/tex]

[tex]AgNO_3\rightarrow Ag^++NO_3^-[/tex]

[tex]Ag^++e^-\rightarrow Ag[/tex]

96500 Coloumb of electricity electrolyzes 1 mole of Ag

43.24 C of electricity deposits =[tex]\frac{1}{96500}\times 43.24=0.00045moles[/tex] of Ag

[tex]\text{ mass of Ag}={\text{no of moles}\times {\text{Molar mass}}=0.00045mol\times 108g=0.0484g[/tex]

Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g

Answer:

concentrations of the reactants and products have reached constant values

Explanation:

When a reaction is carried out in a closed system, it attains dynamic equilibrium after sometime. We define dynamic equilibrium as a situation in which the forward and reverse reactions proceed at the same rate.

When this occurs, the concentration of the reactants and products remain fairly constant. Hence the answer.

Explanation:

203.31                brainliest

Answer:

203.31g when rounded to 2 decimal places.

7.51 × 10²² atoms S

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

4.00 g S

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of S - 32.07 g/mol

Step 3: Convert

Step 4: Check

Follow sig figs and round. We are given 3 sig figs.

7.51107 × 10²² atoms S ≈ 7.51 × 10²² atoms S

Answer: [tex]2AgNO_3(aq)+MgSO_4(aq)\rightarrow Ag_2SO_4(s)+Mg(NO_3)_2(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

A double displacement reaction in which on e of the product is formed as a solid is called as precipitation reaction.  

The balanced chemical equation is:

[tex]2AgNO_3(aq)+MgSO_4(aq)\rightarrow Ag_2SO_4(s)+Mg(NO_3)_2(aq)[/tex]

Explanation:

Nitrous oxide

^_^^.^^.^

Answer: The empirical formula for the given compound is [tex]C_3HF_2[/tex]  and molecular formula for the given compound is [tex]C_{24}H_8F_{16}[/tex]

Explanation : Given,

Mass of C = 18.24 g

Mass of H = 0.51 g

Mass of F = 16.91 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =[tex]\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{18.24g}{12g/mole}=1.52moles[/tex]

Moles of Hydrogen = [tex]\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.51g}{1g/mole}=0.51moles[/tex]

Moles of Fluorine = [tex]\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{16.91g}{19g/mole}=0.89moles[/tex]

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.51 moles.

For Carbon = [tex]\frac{1.52}{0.51}=2.98\approx 3[/tex]

For Hydrogen  = [tex]\frac{0.51}{0.51}=1[/tex]

For Fluorine = [tex]\frac{0.89}{0.51}=1.74\approx 2[/tex]

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : F = 3 : 1 : 2

The empirical formula for the given compound is [tex]C_3H_1F_2=C_3HF_2[/tex]

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

[tex]n=\frac{\text{molecular mass}}{\text{empirical mass}}[/tex]

We are given:

Molar mass  = 562.0 g/mol

Mass of empirical formula = 3(12) + 1(1) + 2(19) = 75 g/eq

Putting values in above equation, we get:

[tex]n=\frac{562.0}{75}=7.49\approx 8[/tex]

Multiplying this valency by the subscript of every element of empirical formula, we get:

[tex]C_3HF_2=(C_3HF_2)_n=(C_3HF_2)_8=C_{24}H_8F_{16}[/tex]

Thus, the molecular formula for the given compound is [tex]C_{24}H_8F_{16}[/tex]

The proportionate of the atom found in a given compound is called the empirical formula while the molecular formula represents the actual digits of the atoms found in the given molecule of the compound.

The empirical formula for the given compound is [tex]\rm C_{3}HF_{2}[/tex]  and molecular formula for the given compound is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Given,

Step 1: For determining the empirical formula, convert mass into moles:

For Carbon:

[tex]\begin{aligned}&\rm Moles \;of \;Carbon = \dfrac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}\\\\&= \dfrac{18.24 \rm g}{ 12 \rm g/mol}\\\\&=1.52\text{ moles}\end{aligned}[/tex]

For Hydrogen:

[tex]\begin{aligned}&\rm Moles \;of \;Hydrogen= \dfrac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}\\\\&= \dfrac{0.51\rm g}{ 1\rm g/mol}\\\\&=0.51\text{ moles}\end{aligned}[/tex]

For Fluorine:

[tex]\begin{aligned}&\rm Moles \;of \;Fluorine= \dfrac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}\\\\&= \dfrac{16.91\rm g}{ 19\rm g/mol}\\\\&=0.89\text{ moles}\end{aligned}[/tex]

Step 2: Calculation of mole ratio for the assigned elements:

For this divide the moles of elements with the smallest number of moles calculated above.

[tex]\begin{aligned}\text{For Carbon} & = \dfrac{1.52 }{0.51}\\&= 2.98\end{aligned}[/tex]

Moles of C = 3

[tex]\begin{aligned}\text{For Hydrogen}& = \dfrac{0.51}{ 0.51}\\&= 1\end{aligned}[/tex]

Moles of Hydrogen = 1

[tex]\begin{aligned}\text{For Fluorine}& = \dfrac{0.89}{ 0.51}\\&= 1.74\end{aligned}[/tex]

Moles of Fluorine = 2

Step 3: The calculated mole ratio will be the subscript of the elements.

C : H : F = 3 : 1 : 2

Therefore, the empirical formula will be,

[tex]\rm C_{3}H_{1}F_{2} \;or\; C_{3}HF_{2}[/tex]

Determining the valency (n):

[tex]n = \dfrac {\text{molecular mass} }{\text{empirical mass}}[/tex]

Given,

= 75 g/eq

Substituting values in the above equation, we get:

[tex]\begin{aligned}n &= \dfrac{562 }{ 75}\\\\&= 7.49 \\\\&= 8\end{aligned}[/tex]

Multiply the valency calculated with the empirical formula:

[tex]\begin{aligned}\rm C_{3}HF_{2} &=\rm (C_{3}HF_{2})n\\&= \rm (C_{3}\rm HF_{2})8\\\\\\\\&= \rm (C_{24}H_{8}F_{16})\end{aligned}[/tex]

Therefore, the molecular formula is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Thus, the empirical formula is  [tex]\rm C_{3}HF_{2}[/tex]  and the molecular formula is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Learn more about empirical and molecular formulas here:

https://brainly.com/question/5675358

Answer:

16.06 g

Explanation:

Reaction equation;

S(s) + 3F2(g) ----> SF6(s)

Number of moles of sulphur reacted = 3.5g/32g/mol = 0.11 moles

If 1 mole of sulphur yields 1 mole of SF6

Then 0.11 moles of sulphur yields 0.11 moles of SF6

Also

Number of moles of fluorine = 4.5g/38 g/mol= 0.12 moles

Hence sulphur his the limiting reactant;

Maximum amount of SF6 = 0.11 × 146 = 16.06 g

Answer:

longitudinal

Explanation:

A prime meridian is the meridian (a line of longitude) in a geographic coordinate system at which longitude is defined to be 0°. Together, a prime meridian and its anti-meridian (the 180th meridian in a 360°-system) form a great circle. This great circle divides a spheroid into two hemispheres.

Answer:

4. 12 km.

5. 2 km.

Explanation:

Hello!

In this case, we need to distinguish between two terms:

- Distance traveled: it stands for the total displacement, no matter the initial and final position the body has; it means that the total displacement was:

DT = 3km + 4 km + 3 km + 2 km = 12 km.

- Displacement: it stands for the relationship between the initial position and the final one, it means that the initial position was 0 km and the final one is 2 km away, thus, the displacement is:

D = 2km - 0 km = 2 km.

Best regards!

Answer:

Due to expansion.

Explanation:

The pressure exerted by a sample of gas at constant volume doubles when the absolute temperature is doubled because with the increase of temperature, the molecules of gas start expansion which increases their volume and as a result pressure of a gas increases. Increasing temperature of a gas sample increases the kinetic energy of the particles, and as a result the gas expand.

Answer:

Percent by mass is 69.42% Fe

Explanation:

If the molar mass is 159.69 grams per mol, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first. We will calculate the amu of Iron and divide that by the total molar mass of Fe2O3.. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

Fe2 = 2(55.845) = 111.69

111.69/159.69 = 0.69941762164

0.69941762164 * 100 = 69.42% Fe

The study of chemicals is called chemistry.

The correct answer to the question is Percent by mass is 69.42% Fe

If the molar mass is 159.69 grams per mole, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first.

We will calculate the AMU of Iron and divide that by the total molar mass of Fe2O3. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

[tex]Fe2 = 2(55.845) = 111.69\\\\\\frac{111.69}{159.69} = 0.69941762164\\\\0.69941762164 * 100 = 69.42% Fe[/tex]

Hence, the correct option answer is 69.42.

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1.21 g HBr

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Compounds

Atomic Structure

Step 1: Define

9.03 × 10²¹ molecules HBr

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of Br - 79.90 g/mol

Molar Mass of HBr - 1.01 + 79.90 = 80.91 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21325 g HBr ≈ 1.21 g HBr

Answer:

Metals with larger grains have less grain-boundary area per unit volume, and hence will not be as able to generate as many entanglements at grain boundaries, thus the strength will be lower.