Calculate the [OH-] in a solution that has a pH of 3.08.
a. 1.2x10-9
b. 8.3x10-3
C. 1.2x10-11
d. 8.3x10-4

Answer:

This is thought to aid in the extraction, as this dissolved phenol helps denature proteins while they are still in the aqueous solution. ... Phenol/Chloroform – This is a mixture of buffer-saturated phenol and chloroform, usually close to 1:1 for DNA purification with other ratios sometimes used for RNA purification

Explanation:

Hope it helps!

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Answer:

This is thought to aid in the extraction, as this dissolved phenol helps denature proteins while they are still in the aqueous solution. ... Phenol/Chloroform – This is a mixture of buffer-saturated phenol and chloroform, usually close to 1:1 for DNA purification with other ratios sometimes used for RNA purification

Answer:

it is A tide (A,C)

Explanation:

i just took the test and tried c and it was a plzzzzz put a btw it was my test lol

Answer:

9.15

Explanation:

To solve this problem we'll use Henderson-Hasselbach's equation:

For this problem:

Now we calculate [NH₄Cl], first by converting 50.0 g of NH₄Cl into moles using its molar mass:

Meaning that [NH₄Cl] = 0.935 mol / 1.00 L = 0.935 M

Finally we calculate the pH:

The pH can be defined as the hydrogen ion concentration in the solution. The pH of ammonium chloride solution in ammonia is 9.16.

The molarity is the moles of a compound in the liter of solution. The molarity of 50 grams ammonium chloride in a liter of solution is given as:

[tex]\rm Molaity=\dfrac{mass}{molar\;mass\;\times\;volume(L)} \\\\NH_4Cl\;Molarity=\dfrac{50\;g}{53.491\;g/mol\;\times\;1\;L} \\\\NH_4Cl\;Molarity=0.935\;M[/tex]

The ammonia in the solution contributes to the pH from the ammonium chloride salt. The pH can be given as:

[tex]\rm pH=pKa+log\dfrac{acid}{salt}[/tex]

The pKa of ammonia is 9.25. The concentration of ammonia is given as 0.75 M.

The pH of the solution can be given as:

[tex]\rm pH=9.25+log\dfrac{0.75\;M}{0.935}\\ pH=9.25+(-0.09)\\pH=9.16[/tex]

The pH of the solution is 9.16.

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Answer:

change in energy of the system = - 21 J

Explanation:

Δu = q + w

q = 364 J

w = - 385

Temperature of system drops from 25°c to 20°c

hence

Δu ( change in energy ) = q - w

                                       = 364 - 385

                                       = -21  J

Answer:

pH = 3.513

Explanation:

Hello there!

In this case, since this titration is carried out via the following neutralization reaction:

[tex]HONH_2+HCl\rightarrow HONH_3^+Cl^-[/tex]

We can see the 1:1 mole ratio of the acid to the base and also to the resulting acidic salt as it comes from the strong HCl and the weak hydroxylamine. Thus, we first compute the required volume of HCl as shown below:

[tex]V_{HCl}=\frac{22.0mL*0.200M}{0.15M}=29.3mL[/tex]

Now, we can see that the moles of acid, base and acidic salt are all:

[tex]0.0220L*0.200mol/L=0.0044mol[/tex]

And therefore the concentration of the salt at the equivalence point is:

[tex][HONH_3^+Cl^-]=\frac{0.0044mol}{0.022L+0.0293L} =0.0858M[/tex]

Next, for the calculation of the pH, we need to write the ionization of the weak part of the salt as it is able to form some hydroxylamine as it is the weak base:

[tex]HONH_3^++H_2O\rightleftharpoons H_3O^++HONH_2[/tex]

Whereas the equilibrium expression is:

[tex]Ka=\frac{[H_3O^+][HONH_2]}{[HONH_3^+]}[/tex]

Whereas Ka is computed by considering Kw and Kb of hydroxylamine:

[tex]Ka=\frac{Kw}{Kb}=\frac{1x10^{-14}}{9.10x10^{-9}} \\\\Ka=1.10x10^{-6}[/tex]

So we can write:

[tex]1.10x10^{-6}=\frac{x^2}{0.0858-x}[/tex]

And neglect the x on bottom to obtain:

[tex]1.10x10^{-6}=\frac{x^2}{0.0858}\\\\x=\sqrt{1.10x10^{-6}*0.0858}=3.07x10^{-4}M[/tex]

And since x=[H3O+] we obtain the following pH:

[tex]pH=-log(3.07x10^{-4})\\\\pH=3.513[/tex]

Regards!

The volume 15.0 g of O₂ has at a certain temperature and pressure is 2.16 L.

Volume is the space occupied by a three-dimensional object.

By the law of dilution

M₁/V₁ = M₂/V₂

Mass 1 is 5.00

Volume 1 is 7.20 L

Mass 2 15.0 g

Volume 2 is to find

Putting the value in the equation

5.00/ 7.20 = 15.0 / V₂

V₂ = 7.20 × 15.00/ 5.00 = 21.6

Thus, the volume will be 21.6 L.

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Answer:

C. The solubility decreases.

Explanation:

Took the plato test!

Answer:

d

Explanation:

increasing the temperature the fraction of molecules which collide with energy greater than Ea increase and hence the rate constant

Hey love! <3

Answer:

C. Resource use by humans has gone up and down over the years is a false statement

Explanation:

In the graph you can make an observation on how the increase of human population is directly positive.

The resource use either has a positive or negative correlation, making it impossible for the usage to fluctuate over the years.

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Answer:

C. Hydrogen bonds​

Explanation:

Strongest intermolecular force

Hydrogen Bonding (H-Bonding)

Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen, and are the strongest intermolecular force.

Answer: C hydrogen bonds

Explanation:

Answer:

We assume you are converting between moles CaCl2 and gram. You can view more details on each measurement unit: molecular weight of CaCl2 or grams This compound is also known as Calcium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CaCl2, or 110.984 grams.

The mass of calcium chloride is 53.27 grams.

Given:

Moles of CaCl₂ = 0.48 moles

Molar mass of CaCl₂ = 110.98 g/mol

To find:

Mass of CaCl₂ = ?

It is defined as given mass over molar mass.

Number of moles  =  Mass / Molar mass

Mass = Number of moles * Molar mass

Mass = 0.48 moles  * 110.98 g/mol

Mass = 53.27 grams

Thus, the mass of calcium chloride is 53.27 grams.

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Answer:

16.51%

Explanation:

The reaction that takes place is

Meaning that the white precipitate that formed is AgCl. Now we convert 0.535 g of AgCl into moles, using its molar mass:

Then we convert 0.00373 moles of AgCl into moles of CaCl₂, using the stoichiometric coefficients:

We convert moles of CaCl₂ into grams, using its molar mass:

Finally we calculate the percent of CaCl₂ by mass in the original mixture:

The percent calcium chloride by mass in the original mixture is 16.4%

The equation of the reaction between calcium nitrate and silver chloride is:

[tex]\mathbf{CaCl_2 + 2AgNO_3 \to 2 AgCl+Ca(NO_3)_2}[/tex]

Given that;

the number of moles of the precipitated AgCl is:

= 0.535 g / 143.32 g/mol

= 0.0037 moles

From the above reaction, If 2 moles of AgCl are formed  by 1 mole of CaCl2

Then, 0.0037 moles of AgCl will form (0.0037 × 1)/2 moles of CaCl2.

0.0037 moles of AgCl will form 0.00185 moles of CaCl2.

Now, we can say that the number of moles of CaCl2 present in the mixture is =  0.00185 moles

Mass amount of CaCl2 present = 0.00185 moles × 110.98 g/mol

Mass amount of CaCl2 present = 0.205 grams

Finally, the mass percentage   [tex]\mathbf{=\dfrac{0.205}{1.25}\times 100\%}[/tex]

= 16.4%

Therefore, we can conclude that the percent calcium chloride by mass in the original mixture is 16.4%

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Answer:

heterogeneous mixture is a mixture that is non-uniform and contains smaller component parts.

Answer:

heterogenous mixture is type of mixture

Explanation:

it is one type of mixture involve in the mixture of different or hetro substance and can also easely separated or seen by naked eye  example mixture of water  and sand

Answer:

b

Explanation:

Answer:

D. Dry

Explanation:

Colorado's combination of high elevation, midlatitude, and continental interior geography results in a cool, dry climate.

Answer:

Explanation: A compound with the empirical formula SO has a molecular weight of 96.13

Answer:

not sure but i think the answer is A

Answer:

Explanation:

The principal reason why these statements are equivalent and identical is that there can be a progressional flow of heat from a hot object item to a cold object because of this entropy is increasing and expanding Δg < 0 but stream flow from cold to hot is nonspontaneous as Δg > 0.

e.g [tex]dS = \dfrac{\delta Q}{T}[/tex]

As found in heat engines and refrigerators.

Answer:

a) Base Peak

b) Base Peak

c) Molecular Ion

d) Base Peak and Radical Cation

e) The Parent Ion, Molecular Ion, the Radical Cation and the Base Peak

Explanation:

a) The Base Peak is assigned a relative intensity of 100.

b) The Base Peak is the most intense peak in the mass spectrum.

c) The Molecular Ion Peak represents the original molecule that has only lost an electron.

d) Base Peak and Radical Cation could be/represent a smaller, charged fragment of the original molecule.

e) The Parent Ion, the Molecular Ion, the Radical Cation/ the Base Peak is/represents a positively charged species.

Answer:

pH = 7.08

Explanation:

We can solve this problem using Henderson-Hasselbach's equation:

With the given concentrations and volumes, we can calculate the new values for [ClO⁻] and [HClO] when the solutions are mixed:

Now we calculate pKa:

Finally we calculate the pH:

Answer:

D. Na+

Explanation:

Na+ is the only ion here that is not related to pH. Adding OH- increases pH, and adding H3O+ or H+ (the two are interchangeable) decreases pH.

Answer: radio wave frequencies have longer wavelengths and smaller

Energies per photon

On CK-12 all of these answers are correct

1.9

1.888

1.89

1.88

The molality of a 10.0 % by mass solution of sodium chloride (NaCl) is 1.7M.

Molarity of any solution will be calculated as number of moles of solutes present in per litre of the solution.

Moles of the substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given that percent mass of NaCl = 10% i.e. 10g of NaCl is present in 100 g of solution.

We know that 1 g = 0.001 L

100 g = 0.1 L

Moles of NaCl = 10g / 58.44g/mol = 0.17 mol

Molarity of NaCl = 0.17 / 0.1 = 1.7M

Hence required molarity is 1.7 M.

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Answer:

Ok, thank you

Explanation:

Answer:

5.5

Explanation:

i think so?????????

The diluted solution of volume 120 ml has the molarity of 0.60 M. Then, the volume of the original solution with a molarity of2.25 M is 32 ml.

The molarity of a solution is the ratio of the number of moles of its solute particles to the volume of solution in liters.

To solve the given problem, we can use the formula for dilution:

C1V1 = C2V2

where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

We are given that the diluted solution has a concentration of 0.60 M and a total volume of 120 mL. We are also given that the original concentration was 2.25 M, and we want to find the original volume.

Using the formula for dilution, we can write:

2.25 M x V1 = 0.60 M x 120 mL

Simplifying, we get:

V1 = (0.60 M x 120 mL) / 2.25 M

V1 = 32 mL

Therefore, the original volume of the KOH stock solution was 32 mL.

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The number of moles of Gas B in the gas mixture is equal to 2.00 mol.

The ideal gas equation can be explained as an equation that describes the state of an ideal gas. This equation gives the product of the volume and pressure of ideal gas equal to the multiplication of the universal gas constant, absolute temperature, and moles of gas.

The mathematical form of the ideal gas equation mentioned below:

PV = nRT

Where P is the pressure, V is the volume, n is the moles, and R is the gas constant.

Given, the volume of the gas mixture, V = 500 ml = 0.5 L

The temperature of the gas mixture, T = 303 K

The pressure of the gas mixture = 5 atm

The value of gas constant, R =0.082 atmL/K mol

Substituting the values R, V, P, and T in the ideal gas law, we get:

The number of moles of the gas mixture, n = PV/RT

n = 5 ×20/(0.082 × 303)

n = 4.00 mol

The total number of moles of gas mixture = 4.00 mol

The moles of Gas A = 2.00 mol

The moles of Gas B = 4 - 2 = 2.00 mol

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Answer:

it's the amount of energy released by an earthquake