Calculate the number of moles in butane C4H10 in 151g of butane (at masses c =12 amu and H=1 )

The ph for each of the cases in the titration of 35.0 ml of 0.190 m Noah(aq) with 0.190 m hbr(aq) is 13.02 and 7.

To calculate the pH for each of the cases in the titration of NaOH with HBr, we need to determine the amount of HBr that has been added to NaOH at each point in the titration. We can use the balanced chemical equation for the reaction to do this:

NaOH(aq) + HBr(aq) → NaBr(aq) + H2O(l)

moles of HBr = moles of NaOH

moles of NaOH = concentration × volume

moles of NaOH = 0.190 M × 0.0350 L = 0.00665 mol

pH = 14.00

pH = 7.00

moles of NaOH remaining = 0.00665 - 0.00300 = 0.00365 mol

concentration = moles / volume

to calculate the concentration of NaOH remaining in the solution:

concentration of NaOH remaining = 0.00365 mol / 0.0350 L = 0.104 M

Kw = [H+][OH-] = 1.0 × [tex]10^-14[/tex]

[H+] = Kw / [OH-] = 1.0 ×[tex]10^-14[/tex] / 0.104 = 9.62 × [tex]10^-14\\[/tex] M

pH = -log[H+] = -log(9.62 × [tex]10^-14[/tex]) = 13.02

Therefore, the pH of the solution 13.02 and 7.

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when 0.982 g of mercury oxide are heated until all oxygen is expelled, 0.909g of mercury remain then the formula of the oxide will be HgO.

The formula of the oxide can be determined by using the mass loss during heating as a clue to the number of moles of oxygen that was present in the original sample.

First, we'll calculate the mass of oxygen that was expelled:

0.982 g - 0.909 g = 0.073 g

Next, we'll convert the mass of oxygen to moles:

0.073 g / (16.00 g/mol) = 0.00456 mol

Next, we'll convert the mass of mercury to moles:

0.909 g / (200.59 g/mol) = 0.00453 mol

The ratio of moles of mercury to moles of oxygen in the original sample is approximately 1:1, which means that the formula of the oxide is HgO.

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Answer:

Avogadro's law is an ideal gas law that states that, at a constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of gas. This law assumes that the gas is an ideal gas, which is a theoretical gas that follows a set of idealized assumptions, such as having no intermolecular forces and occupying no volume.

In reality, gases are not always ideal and can deviate from the ideal gas behavior at high pressures and low temperatures. In these conditions, the volume of a gas is no longer directly proportional to the number of moles of gas due to the intermolecular forces between gas particles. Real gases can also have different molar volumes, which means that the identity of the gas does matter when considering the relationship between volume and number of moles.

Therefore, while Avogadro's law is a useful approximation in many situations, it is not always accurate for real gases.

If the density of the ruby is 4.02 g/cm³, the volume of a 1.00 carat ruby is  0.049 cm³.

The density of the ruby = 4.02 g/cm³

The mass of the ruby = 1 carat

1 carat = 200 mg = 0.200 g

The mass of the ruby 0.200 g

The density is expressed as :

Density = mass / volume

The volume = mass / density

Volume = 0.200 / 4.02

Volume = 0.049 cm³

The volume of the ruby in mL = 0.049 mL.

Thus, the volume of the ruby is 0.049 mL in the 1 carat of the ruby.

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The response is untrue, thus no. Methane (CH4) and oxygen combine to produce water and carbon dioxide. Since there are different numbers of hydrogen atoms on either side.

Methane (CH4) and oxygen combine to generate water and carbon dioxide. Since there are different numbers of hydrogen atoms on either side, we can see that the process is not balanced in this instance. The quantity of oxygen atoms is the same.

Natural gas mostly consists of methane. Methane is released into the atmosphere where it ultimately mixes with oxygen to create additional carbon dioxide (CO2). This straightforward chemical process turns methane into carbon dioxide.

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The kinetic energy of a 100kg cart moving at a speed of 6 m/s is 1800 J.

Kinetic energy is defined as the energy that an object has because of its motion. If you want to accelerate an object, then you must apply a force. Force can be applied when work is done by us. After work has been done, the energy will get transferred to the object, and the object will be moving with a new constant speed.

K.E = 1/2 mv²

m = 100 kg

v = 6 m/s

Substituting the values we get,

K.E = 1/2 × 100 × 6 × 6

⇒ K.E = 1800 J

Hence, The kinetic energy of a 100kg cart moving at a speed of 6 m/s is 1800 J.

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According to the question, 3.26 atm will its pressure be, asumming constant temprature.

What is temprature?

Temperature is a measure of the amount of heat energy present in a system. It is measured in degrees on a variety of scales, including Celsius, Fahrenheit, and Kelvin. Temperature is a fundamental physical property that can be used to characterize the state of a system. It is an important factor in determining the speed of chemical reactions, the rate at which materials expand and contract, and the amount of energy released or absorbed. Temperature affects the behavior of gases, liquids, and solids, and it has a significant impact on the physical and chemical properties of a substance.

Using the ideal gas law, the new pressure of the gas can be calculated as follows: P2 = (1.26 atm × 7.40 L) / 2.93 L

P2 = 3.26 atm

Therefore, the pressure of the gas will be 3.26 atm when its volume is decreased to 2.93 L, assuming constant temperature.

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In the given chemical reaction, 87.4 g of carbon dioxide gas is produced if 29.4 g of ethene and 95.3 g of oxygen is used in a reaction. The correct choice is option e.

Combustion is a chemical process that occurs in the presence of oxygen between a fuel and an oxidizing agent, creating heat and light.

We need to find the limiting reagent by calculating the moles of each reactant and comparing them to the stoichiometric ratio of the balanced equation.

Moles of [tex]\rm C_2H_4[/tex]= 29.4 g / 28.05 g/mol = 1.045 mol

Moles of [tex]\rm O_2[/tex] = 95.3 g / 32 g/mol = 2.978 mol

The stoichiometric ratio of the balanced equation is 1 mol [tex]\rm C_2H_4[/tex]: 3 mol  [tex]\rm O_2[/tex]. Therefore,  [tex]\rm O_2[/tex] is the limiting reagent because we have less moles of  [tex]\rm O_2[/tex] than what is required by the stoichiometric ratio.

Now we can use the moles of  [tex]\rm O_2[/tex] to determine the moles of [tex]\rm CO_2[/tex]produced.

Moles of  [tex]\rm CO_2[/tex]= 2.978 mol  [tex]\rm O_2[/tex] [tex]\times[/tex] (2 mol  [tex]\rm CO_2[/tex]/ 3 mol  [tex]\rm O_2[/tex]) = 1.985 mol  [tex]\rm CO_2[/tex]

Finally, we can use the moles of  [tex]\rm CO_2[/tex] to determine the mass of  [tex]\rm CO_2[/tex]produced.

Mass of  [tex]\rm CO_2[/tex]= 1.985 mol  [tex]\rm CO_2[/tex][tex]\times[/tex] 44.01 g/mol = 87.4 g  [tex]\rm CO_2[/tex]

Therefore, option e. 87.4 g is the correct choice.

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Your question is incomplete but most probably your full question was,

The following balanced equation describes the combustion of ethene

([tex]\rm C_2H_4[/tex]). How many grams of carbon dioxide, [tex]\rm CO_2[/tex], are produced if 29.4 g of ethene and 95.3 g of oxygen, [tex]\rm O_2[/tex], are used for the reaction? [tex]\rm 1C_2H_4+3O_2\rightarrow 2CO_2+2H_2O[/tex]

(a) 133 g

(b) 92.3 g

(c) 46.1 g

(d) 131 g

(e) 87.4 g

The mass of sulfuric acid produced is 2.77 g.

To calculate the mass of sulfuric acid produced, we need to use stoichiometry. Here are the step-by-step calculations:

So the mass of sulfuric acid produced is 2.77 g.

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According to the question, the molar mass of C₆H₆ is 60.5%.

What is molar mass?

Molar mass is the mass of one mole of a substance, measured in grams per mole. It is calculated by summing the atomic masses of the atoms in the molecular formula of the substance. Molar mass can be used to calculate the mass of a given amount of a substance, or to determine the amount of a substance needed to obtain a particular mass. Molar mass is an important concept in chemistry as it is used to calculate the amount of energy released or absorbed in a chemical reaction, as well as the amount of products formed.

Molar mass of C₆H₆ = 78.11 g/mol

Moles of C₆H₆ = 39.0 g / 78.11 g/mol = 0.500 mol

Molar mass of C₆H₅Cl = 92.56 g/mol

Moles of C₆H₅Cl = 28.0 g / 92.56 g/mol = 0.301 mol

Theoretical yield of C₆H₅Cl = 0.500 mol x 92.56 g/mol = 46.28 g

Actual yield of C₆H₅Cl = 28.0 g

Percent yield of C₆H₅Cl = (Actual yield / Theoretical yield) x 100%

= (28.0 g / 46.28 g) x 100%

= 60.5%

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Elements were arranged by atomic number and properties of the elements varied periodically with atomic number.

What is Mendeleev's period Table?

Mendeleev's initial periodic table, which stated that "Element characteristics are a periodic function of their atomic weight," was first published in 1869.

The Periodic table of Mendeleev is a table in which Mendeleev listed elements in the order of their atomic masses.

Mendeleev made an effort to link the atomic masses to their chemical and physical characteristics.

Hence, the properties of the elements varied periodically with atomic number, and the elements were ordered according to their atomic numbers.

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Lead is melted and is poured into a mold to make fishing weights. This is an example of a physical change.

Chemical or physical changes are both possible. Anything that has mass and takes up space is referred to as "matter." It has both physical and chemical qualities and is composed of small particles.

A sort of change known as physical change occurs when the physical characteristics of matter change. Physical changes include those in color, odor, solubility, and the condition of matter, among others.

The chemical makeup or content of matter are not altered after a physical transformation. The internal makeup is unaffected as molecules rearrange themselves during this transformation. The chemical attribute is unaffected by a physical change.

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The complete question is

Lead is melted and is poured into a mold to make fishing weights. This is an example of a________change.

1) physical

2)chemical

when mtbe (shown) is reacted with hbr, carbons a and b will undergo nucleophilic substitution to yield two alkyl halides then by SN2 mechanism each c-o bonds will be cleaved.

When MTBE (methyl tert-butyl ether) is reacted with hydrogen bromide (HBr), the two C-O bonds in the molecule are expected to undergo an S N 2 substitution mechanism. This is because the reaction conditions are favorable for a bimolecular, concerted mechanism, where the nucleophilic (HBr) and substrate (MTBE) interact with each other to produce the products.

In the S N 2 mechanism, the C-O bonds in MTBE are cleaved via backside attack by the nucleophile, HBr. This involves the simultaneous formation of a new C-Br bond and breaking of the existing C-O bond. The attack takes place in a stereospecific manner, so that the orientation of the substrate and nucleophile determines the stereochemistry of the products. The S N 2 mechanism is typically favored under conditions where the substrate is a good leaving group and the nucleophile is a strong base.

In summary, both of the C-O bonds in MTBE are expected to be cleaved via an S N 2 mechanism when reacting with HBr.

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Experiment to determine best solvent for ink stain removal: soak 4 identical cloths with ink stains in nail polish remover, rubbing alcohol, soap+water, and water, observe stain removal, repeat 3 times, analyze results to find best solvent.

Here's a plan for an experiment to identify which solvent is best for removing an ink stain from a white blouse:

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1. Helium has a boiling point of 4 k, and as it does so, the London dispersion force breaks bonds and interactions.

2. Helium has a boiling point of 20 k, and as it does so, the London dispersion force breaks bonds and interactions.

3. Hydrogen is able to break covalent bonds when heated from 30 K to 6000 K.

The least powerful bond-interaction force is the London dispersion force. The atoms of a substance are temporarily attracted to one another. Two atoms' electrons combine in a way that causes them to form dipoles. This force underlies every helium gas reaction.

When two species share electrons, a covalent link is created. Usually, they happen amongst compounds with comparable electronegativities. Bond strength is based on how many bonds there are between the atoms.

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Answer:

Logging is the first step in deforestation in Amazon.

Explanation:

I don't have much to go off of, but usually with any deforestation the first step is logging the area. You must remove all the trees before you can effectively utilize the area.

The molecular formula of the compound with an empirical formula of CH and a molecular molar mass of 78 g/mol is, [tex]C_6H_6[/tex].

An Empirical formula is the chemical formula of a compound that gives the proportions (ratios) of the elements present in the compound but not the actual numbers or arrangement of atoms. This would be the lowest whole number ratio of the elements in the compound.

Given,

Empirical formula = CH

The molar mass of empirical is 12+1 = 13 g

The molar mass of molecular formula = 78 g

To find the number of empirical units divide the molecular mass + empirical mass

No. of units = 78÷13 = 6

So, the molecular formula is 6×(CH)

[tex]C_6H_6[/tex]

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The concentration of the diluted solution be 100 ppm.

Chemistry uses the term PPM, or parts per million, to describe extremely low concentrations of solution. One liter of solution containing milligrams of the chemical is what is meant by this term. Technically speaking, it is a dimensionless quantity that can be used to measure lower concentrations in a solution.There are numerous scientific uses for this conversion.

It refers to how many of the one million parts that make up the entire solution a specific substance or molecule occupies. It is used to describe substance concentrations that are typically dissolved in a solvent. When there are two solutions, and one of them has a known ppm concentration, the ppm concentration can be calculated by:

ppm1 x volume = ppm2 volume

500 ppm x 2 mL = ppm2 x 10 mL

ppm 2 = 500 ppm x 2 mL/ 10 mL

ppm 2 = 100 ppm

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If a molecule has an uneven distribution of electrons then it is polar molecule and it will not be dissolved in water because the distribution of electrons around the molecule is no longer symmetrical.

This is referred to as a separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment, with a negatively charged end and a positively charged end.

A polar covalent bond is a covalent bond in which the atoms have an unequal attraction for electrons and so the sharing is unequal. In a polar covalent bond, sometimes simply called a polar bond, the distribution of electrons around the molecule is no longer symmetrical.

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The relationship between the pressure, volume, and temperature of a gas can be described by the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in kelvins.

We can rearrange the ideal gas law to solve for volume:

V = (nRT) / P

We know the initial volume of the gas at STP (standard temperature and pressure of 0 °C and 1 atm):

V1 = 3.2 m^3

We also know the initial temperature and pressure:

T1 = 273.15 K (0 °C converted to kelvins)

P1 = 1 atm

And we know the final temperature and pressure:

T2 = 38.0 + 273.15 = 311.15 K

P2 = 3.1 atm

Assuming the number of moles of gas stays constant, we can substitute the known values into the equation and solve for the final volume:

V2 = (nRT2) / P2

V2 = (n * R * 311.15) / 3.1

V2 = (n * 8.31 * 311.15) / 3.1

Since the number of moles n cancels out, we can simplify the equation:

V2 = (8.31 * 311.15) / 3.1

V2 = 936.76 / 3.1

V2 = 301.31 m^3

So the final volume of the gas under the specified conditions is 301.31 m^3 to two decimal places.

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A noble gas, other than helium, have 8 electrons in its highest-occupied energy level.

The noble gas are a group of elements in the periodic table that have exceptional chemical stability and low reactivity due to their complete valence shell of electrons. These elements are found in the far right-hand column of the periodic table and include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Unlike other elements in the periodic table, the noble gases do not readily form compounds with other elements, making them highly unreactive. This characteristic makes them useful in a variety of industrial applications, such as filling incandescent lamps, as cooling agents in cryogenics, and in the production of semiconductors. The electron configurations of the noble gases, excluding helium, follow the pattern s^2p^6, meaning that the highest-occupied energy level has 8 electrons. This full valence shell of electrons gives the noble gases their exceptional stability and non-reactivity, making them unique among the elements in the periodic table.

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Sample A was from a gunshot while sample B is from a blow. Option C

In forensics, the blood pattern has to do with the way that the blood is arranged or the way that the blood flows among a particular target. It is common to see that when a person is shot, the blood would splatter on the wall behind the victim.

The pattern of the splatter of the blood can be used to tell if the would from a high velocity impact of if the would was just from a medium velocity impact as are shown by the images.

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Answer:

Light vs electron

Explanation:

Light Microscope vs Electron Microscope. Light microscopes and electron microscopes both use radiation - in the form of either light or electron beams, to form larger and more detailed images of objects (e.g. biological specimens, materials, crystal structures, etc.) than the human eye can produce unaided.

The pH at the equivalence point in the titration of 50.0 ml of 0.300 M CH₃COOH with 0.3 M NaOH is approximately 4.68.

To calculate the pH at the equivalence point, we need to determine the concentration of acetate ion (CH₃COO⁻) and hydronium ion (H³O⁺) at this point.

At the start of the titration, the initial concentration of acetic acid is 0.300 M and the initial concentration of hydronium ion is the same.

Let's say that x moles of NaOH are added to the solution. This will lead to the formation of x moles of acetate ion (CH³COO⁻) and x moles of hydroxide ion (OH⁻).

The final concentration of acetic acid will be (0.300 M - x M) and the final concentration of hydronium ion will be (x M).

The ionization constant (Ka) for acetic acid can be used to determine the concentration of acetate ion and hydronium ion in the solution. The equation for the ionization of acetic acid is:

CH₃COOH + H₂O ↔ CH₃COO⁻ + H₃O⁺

Ka = [CH₃COO⁻][H₃O⁺] / [CH₃COOH]

At the equivalence point, [CH₃COOH] = (0.300 M - x M), [CH₃COO⁻] = x M, and [H₃O⁺] = x M. Substituting these values into the equation for Ka, we get:

1.8 x 10⁻⁵ = (x)(x) / (0.300 - x)

Solving for x, we get:

x = 2.1 x 10⁻⁵ M

The pH at the equivalence point is equal to the negative log of the hydronium ion concentration:

pH = -log[H₃O⁺] = -log(2.1 x 10⁻⁵) = 4.68

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A 0.026 M KOH solution has [tex][OH-] = 0.026 M, [H3O+] = 10^(-13) M[/tex], and a pH of 12.97.

A potassium hydroxide (KOH) solution is a strong base and dissociates completely in water to produce hydroxide ions (OH-). The molar concentration of KOH can be used to calculate the concentration of hydroxide ions.

[OH-] = 0.026 M

The hydroxide ions will react with water to produce hydronium ions (H3O+), according to the equation:

[tex]OH- + H2O - > H3O+ + OH-[/tex]

The concentration of hydronium ions can be calculated using the equation:

[tex][H3O+] = Kw/[OH-] = 10^(-14)/[OH-] = 10^(-14)/0.026 = 10^(-13) M[/tex]

The pH of the solution can be calculated using the equation:

[tex]pH = -log[H3O+] = -log(10^(-13)) = 13.[/tex]

Therefore, the pH of the 0.026 M KOH solution is 12.97.

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During radioactive decay Unstable isotopes can occur by releasing particles.

Isotopes are atoms with the same number of protons but differing numbers of neutrons. They differ in mass, which affects their physical characteristics even if they have nearly identical chemical properties. There are unstable isotopes that emit radiation as well as stable isotopes that do not. These are referred to as radioisotopes.

Unstable isotopes undergo radioactive decay.The unstable isotope can release particles like alpha particles, beta particles, or gamma rays during radioactive decay. By emitting particles, the isotope transforms into a different element or isotope and becomes stable.

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8.  The pressure of the gas in the container is 369.7 mmHg.

9. The new pressure of the gas in atmospheres is 1.47 atm

10. The temperature in Kelvin will 0. 1243 moles of fluorine exert a pressure of 2. 02 atm at a volume of 0. 625 L is 124 K.

The ideal gas equation is expressed as :

P V = n R T

8. The gas law is :

P₁ V₁ = P₂ V₂

P₂ =  P₁ V₁ / V₂

P₂ = ( 256.4 × 362 ) / 251

     = 369.7 mmHg

9. P₁ V₁ / T₁ = P₂ V₂ / T₂

P₂ = P₁ V₁ T₂ V₂T₁

P₂ = ( 1 × 32.4 × 352) / 28.4 × 273

    = 1.47 atm

The pressure is 1.47 atm

10. P V = n R T

T = P V / n R

T = ( 2.02 × 625 ) / 0.1243 × 0.082

T = 124 K

Thus, the temperature is 124 K.

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The molarity is viewed as 0.00109 M if a solution sodium carbonate was prepared by dissolving 3.2990 g of na2co3 in 1.000 l of water. a 25.00-ml aliquot of this solution required 28.39 ml of hydrochloric acid solution.

The molarity of the HCl arrangement can be determined involving the fair substance condition for the response between sodium carbonate (Na2CO3) and hydrochloric corrosive (HCl):

Na2CO3 + 2 HCl - > 2 NaCl + CO2 + H2O

One mole of sodium carbonate responds with two moles of hydrochloric corrosive. We realize how much sodium carbonate utilized in the response (3.2990 g) and its molar mass (106.0 g/mol), so we can work out the quantity of moles of sodium carbonate:

n = m/M = 3.2990 g/106.0 g/mol = 0.03109 mol

We additionally know the volume of the HCl arrangement utilized in the response (28.39 ml), so we can work out its molarity:

M = n/V = 0.03109 mol/(28.39 ml/1000 L/ml) = 0.00109 M

Thus, the molarity of the HCl arrangement is 0.00109 M (adjusted to 5 huge digits).

The molarity of the HCl arrangement can be determined by finding the quantity of moles of sodium carbonate utilized in the response and separating it by the volume of HCl arrangement utilized. The quantity of moles can be found by partitioning the mass of sodium carbonate by its molar mass. The molarity is viewed as 0.00109 M.

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System B is in a liquid phase since it is at the same temperature as System A, but has a lower pressure.

When a substance is heated, the pressure of the vapour increases, and eventually the pressure of the vapour and the liquid become equal at the substance's boiling point. This is known as the saturated vapour point. If the pressure of the vapour is lowered, then the vapour will condense into a liquid, as is the case with System B. As a result, System B is in a liquid phase due to the lower pressure.

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