Calculate the de Broglie wavelength of a 300-g object moving at a velocity of 50 m/s (about 100 mph).
O 4x10 -38 m O 4x10-35 m O 4x 10 9 m O 4x10 12 m

Answers

Answer 1

The de Broglie wavelength of a 300-g object moving at a velocity of 50 m/s  is  4×10³⁵ meters. Hence, option (B) is correct.

What is the de Broglie wavelength?

When studying quantum mechanics, the de Broglie wavelength is a key idea. De Broglie wavelength is the wavelength (λ) that is connected to an item in relation to its momentum and mass. Typically, a particle's momentum is inversely proportional to its de Broglie wavelength.

The de Broglie wavelength of a 300-g object moving at a velocity of 50 m/s  is = Planck constant/momentum

= 6.6 ×10⁻³⁴/(0.300×50) meter

= 4×10³⁵ meters.

The de Broglie wavelength of a 300-g object travelling at 50 m/s is 4*10^35 meters. As a result, option (B) is accurate.

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Related Questions

Which of these accurately describes a difference between nuclear energy and
Fossil fuel?
A. In nuclear fuel reactions, heat is released that is used to do work.
B. In fossil fuel reactions, heat is released that is used to do work.
C. Fossil fuels have a higher energy density than nuclear fuel.
D. Nuclear fuel has a higher energy density than fossil fuels.

Answers

Answer:

Nuclear fuel has a higher energy density than fossil fuel

Why does Paul Ehrlich concede that the theory of evolution “cannot be refuted by any possible observations” and thus is “outside of empirical science”?

Answers

Evolution can not be tested by experiment given that it depends largely on observations that fit into a wider scope and point to a common conclusion.

Can evolution be proven empirically?

Science is know to be empirical, In science, the evidence that backs up a claim is what establishes it as true or false. Thus all theories must be tested by experiment.

However, the theory of evolution can not be tested by experiment given that it depends largely on observations that fit into a wider scope and point to a common conclusion. In other words, evolution lies “outside of empirical science”.

The fact that it can not be directly proven empirically does not necessarily make it out to be false. That was the conclusion of Paul Ehrlich in his 1967 article.

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An object weighs 32 newtons. What is its mass if a gravitometer indicates that g = 8.25 m/sec2?

Answers

Answer:

3.88kg

Explanation:

weight=mass_of_body(m) x acceleration_due_to_gravity(g)

The weight is given and acceleration is also give

For mass divide the weight by acceleration.

The heat from the bonfire is transferred to the student's hands through the process of
conduction
convection
radiation
reflection

Answers

Answer:

Radiation

Explanation:

PLEASE ANSWER NEED BY MIDNIGHT TONIGHT!!!!!!
Radium-223 nuclei usually decay by alpha emission. Once in every billion decays, a radium-223 nucleus emits a carbon-14 nucleus.

Write a balanced nuclear equation for carbon-14 emission.

Answers

The equation for carbon-14 emission by Radium-223 nuclei is given below:

[tex]^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C[/tex]

What is radioactivity?

Radioactivity is the spontaneous decay of a substance with emission of radiation.

The equation for carbon-14 emission by Radium-223 nuclei is given below:

[tex]^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C[/tex]

In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.

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Consider the reaction of NaHCO3
with an acid, HA. How many grams of NaHCO3
are required to produce 1.76 g of CO2?

Answers

The mass of NaHCO₃ required to produce 1.76 g of CO₂ is 3.36 g

Balanced equation

NaHCO₃ + HA --> NaA + CO₂ + H₂O

Molar mass of NaHCO₃ = 84 g/mol

Mass of NaHCO₃ from the balanced equation = 1 × 84 = 84 g

Molar mass of CO₂ = 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY

From the balanced equation above,

44 g of CO₂ were produced from 84 g of NaHCO₃

How to determine the mass of NaHCO₃ needed

From the balanced equation above,

44 g of CO₂ were produced from 84 g of NaHCO₃

Therefore,

1.76 g of CO₂ will be produced from = (1.76 × 84) / 44 = 3.36 g of NaHCO₃

Thus, 3.36 g of NaHCO₃ is needed for the reaction

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To answer this question, you may need access to the periodic table of elements.

Which of these would likely be the best conductor of electricity?

a.) H₂
b.) NO₂
c.) CaCl₂
d.) H₂O

Answers

Answer:

A

Explanation:

Beacuse the hydrogen is best

The best conductor of electricity here is calcium chloride because, metals are good conductors by the presence of free electrons. The CaCl₂ solution ionizes to Ca²⁺ ions and Cl- ions make it a good electrolyte.

What is conductivity?

Conductivity is a physical property which describes the ability of a substance to pass electricity through it. The substance which shows good conductivity at normal temperatures are called conductors and those only conducts at higher temperatures are semiconductors.

Substance which does not conduct in any condition are called insulators. Metals are electron rich and the metal crystal lattice is composed of a sea of mobile electrons and a pool of positive ions. The delocalization of electrons make it easy to pass current through it.

When a metallic solution is ionized, it gives free ions and electrons and make the solution conducting. CaCl₂ is a good conductor since it contains the metal ions Ca²⁺ . Hence, option c is correct.

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I need help with my work

Answers

By the mean value theorem, the function y = sin x² on the interval [0, π/4] has this guaranteed number: x ≈ 0.460.

How to find a number that guarantees the mean value theorem

According to the mean value theorem, a function that is differentiable at an interval [a, b] has a number c within the interval such that:

f'(c) = [f(b) - f(a)]/(b - a)     (1)

The first derivative of the function is f'(x) = 2 · x · cos x² and by the mean value theorem we know that:

2 · c · cos c² = [sin (π/4)²- sin 0²]/(π/4 - 0)

2 · c · cos c² = [- √2 / 2]/(π /4)

2 · c · cos c² ≈ 0.900

This equation cannot be solved analytically. By the resource of a graphing tool we found the following solution within the interval: c ≈ 0.460.

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what is the mass of 9.3 x 10^ 24 molecules of glucose, C6H12O6 (C6,H12,O6; 180.18 g/mol

Answers

Molecular mass of  9.3 x 10^ 24 molecules of glucose  = 1675.6 x 10^ 24

It is given that the mass of glucose is 180.18 g/mol
so if we have to calculate the mass of 9.3x 10^ 24 molecules of glucose
we will apply a simple unitary method i.e,

9.3 x 10^ 24 *  180.18 g/mol = 1675.67 x 10^ 24
To calculate the molecular mass of a molecule, multiply the subscript (number of atoms) by the atomic mass of each element in the molecule and add those masses together.
Remember that - To determine the compound's molecular mass in grams per mole, use the molecular formula.
Divide the supplied mass by the molar mass of the chemical to convert it to moles.
By dividing the number of moles by Avogadro's number, you may convert from moles to molecules.

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Calculate the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask

Answers

9.82 mL is the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask.

What is Law of Equivalent ?

N₁V₁ = N₂V₂

where,

N₁ = Normality of solution with known concentration

V₁ = Volume of solution with known concentration

N₂ = Normality of solution with unknown concentration

V₂ = Volume of solution with unknown concentration

Now find the mass of solution

Mass = Density × Volume

         = 1.16 × 0.32 × 1000

         = 371.52 g

How to find the Normality ?

Normality = [tex]\frac{\text{Weight}}{\text{Equivalent weight}}[/tex]

                = [tex]\frac{371.52\ g}{36.5}[/tex]

                = 10.18 equivalents

Now put the values in above formula we get  

N₁V₁ = N₂V₂

1 × 100 = 10.18 × V₂

100 = 10.18 × V₂

[tex]V_{2} = \frac{100}{10.18}[/tex]

    = 9.82 mL

Thus from the above conclusion we can say that 9.82 mL is the volume of 32% HCl required to make about 1 N HCl in 100ml volumetric flask.

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Determine the moles of solute in a 350g solution that is 2.5 molal.

Answers

Answer:

0.875 moles solute

Explanation:

You can find the moles of the solute using the molality ratio:

Molality = moles solute / mass (kg) solution

After converting the mass to kilograms, you can plug the values into the ratio and simplify to find the moles.

1,000 g = 1 kg

  350 g              1 kg
--------------  x  ---------------  =  0.35 kg solution
                        1,000 g

Molality = moles solute / mass solution

2.5 m = moles solute / 0.35 kg

0.875 = moles solute

Carbon monoxide and chlorine gas react to form phosgene:
If a reaction mixture initially contains 215 torr of CO and 245 torr of Cl2, what is the mole fraction of COCl2 when equilibrium is reached?

CO(g) + Cl2(g) ↔COCl2

KP= 310 atm at 700k

Answers

Carbon monoxide and chlorine gas react to form phosgene. If a reaction mixture initially contains 215 torr of CO and 245 torr of Cl₂. 0.76 is the mole fraction of COCl₂ when equilibrium is reached.

How to find Mole fraction ?

CO(g) + Cl₂ (g) → COCl₂ (g)           Kp = 310

With this reaction we can write the Kp expression

[tex]K_{p} = \frac{p_{COCl_2}}{p_{CO} \times p_{Cl_2}}[/tex]

We know that 1 atm = 760 torr

Now

[tex]p_{CO} = \frac{215 \times 1}{760}[/tex]

       = 0.28 atm

[tex]p_{Cl_2} = \frac{245 \times 1}{760}[/tex]

        = 0.32 atm

Now, we can write an ICE chart with pressures, so we can know the pressure of COCl₂.

        CO(g) + Cl₂ (g) → COCl₂ (g)           Kp = 310

I:        0.28     0.32          0

C:         -x         -x             +x
E:    0.28 - x  0.32 - x       x

Now put the value in Kp expression

[tex]K_{p} = \frac{p_{COCl_2}}{p_{CO} \times p_{Cl_2}}[/tex]

[tex]310 = \frac{x}{(0.28 - x) (0.32 - x)}[/tex]

[tex]310 = \frac{x}{0.0896 - 0.28x - 0.32x + x^2}[/tex]

310 (0.0896 - 0.28x - 0.32x + x²) = x

310 (0.0896 - 0.6 x + x²)  = x

27.776 - 186 x + 310 x² = x

310 x² -187 x + 27.776 = 0

By using the quadratic equation find the value of x:

[tex]x = \frac{b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

  [tex]= \frac{187 \pm \sqrt{(187)^2 - 4 \times 310 \times 27.776}}{2 \times 310}[/tex]

  [tex]= \frac{187 \pm \sqrt{34969 - 34,442.24}}{620}[/tex]

  [tex]= \frac{187 \pm \sqrt{526.76}}{620}[/tex]

  [tex]= \frac{187 \pm 22.95}{620}[/tex]

  [tex]= \frac{187 + 22.95}{620}\ \text{or}\ \frac{187 - 22.95}{620}[/tex]

  [tex]= \frac{209.95}{620}\ \text{or}\ \frac{164.05}{620}[/tex]

  [tex]= 0.33\ \text{or}\ 0.26[/tex]

Using the lowest value of x, we have that the partial pressure of COCl₂ would be 0.26 atm.

PpCO = 0.28 - x = 0.28 - 0.26 = 0.02

PpCl₂ = 0.32 - x = 0.32 - 0.26 = 0.06

[tex]X_{COCl_2} = \frac{P_{COCl_2}}{Pt}[/tex]

And Pt is the total pressure of all species in reaction so:

Pt = 0.02 + 0.06 + 0.26 =

    = 0.34 atm

The mole fraction:

[tex]X_{COCl_2} = \frac{0.26}{0.34}[/tex]

             = 0.76

Thus from the above conclusion we can say that Carbon monoxide and chlorine gas react to form phosgene. If a reaction mixture initially contains 215 torr of CO and 245 torr of Cl₂. 0.76 is the mole fraction of COCl₂ when equilibrium is reached.

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Calculate the following using proper units and significant figures: (5.57 m / 0.63 m) - (1.11 m x 0.82 m)


7.93 m


7.931 m


7.9 m²


7.9311 m²

Answers

This will give the value of 7.9311m2

( 5.57m / 0.63m ) - ( 1.11m * 0.82m )

=  8.8413 - ( 1.11m * 0.82m )

= 8.8413 - 0.9102m2

= 7.9311m2

Dividing a value in meter by another value in meter results in the cancellation of both the units and the resulting answer will have no unit.

Multiplying a value in meter by another value in meter it will result in the square meters. It can be written as m2 and can be read a meter square.

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What is the molality of lithium ions in a 0.302 m solution of Li₃PO₄ assuming the compound dissociates completely?

Answers

The molality of the lithium ions is calculated as 0.906 m

What is the molality of lithium ions?

Given that the compound is written as Li₃PO₄, the dissociation of the compound is given by the  equation;

Li₃PO₄ -----> 3Li^+ + PO₄^3-

Since there are three mole of lithium ions in the compound, it the follows that the molality of the lithium ions is;

3 * 0.302 m = 0.906 m

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Calculate the amount of heat deposited on the skin of a person burned by 1.00g of steam at 100.0C. Skin temperature is 37C. ΔHvap= 40.7kJ/mol.

Answers

The amount of heat deposited on the skin is 2.26 kJ.

What is the amount of heat given off by 1.0 g of steam?

The amount of heat given off by steam is determined using the formula below:

Quantity of heat = mass * latent heat of vaporization.

Moles of steam = 1.0/18

Heat = 1.0/18 * 40.7

Heat deposited = 2.26 kJ

In conclusion, the quantity of heat is determined from the latent heat of vaporization and the moles of steam.

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Write an equation for the neutralization of lemon juice with baking soda. Your equation should show a proton transfer to form carbonic acid and a salt.

Answers

The equation of the neutralization reaction is:

HOC(CO₂H)(CH₂CO₂H)₂ + Na₂CO₃ ----> HOC(CO₂Na)(CH₂CO₂Na)₂ + H₂O

What is the acid in lemon juice?

The main acid in lemon juice is citric acid.

Citric acid is a tricarboxylic acid and will react with baking soda to form a salt and water.

The equation of the neutralization reaction is shown below:

HOC(CO₂H)(CH₂CO₂H)₂ + Na₂CO₃ ----> HOC(CO₂Na)(CH₂CO₂Na)₂ + H₂O

In conclusion, the neutralization of citric acid in lemon juice produces a salt and water.

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grams of hydrogen contains the same number of atoms as 9.79 grams of nitrogen?

Answers

Answer:

1.44 g

Explanation:

1. get number of nitrogen atoms in 9.79 grams of nitrogen

1 mole of Nitrogen is 6.022 x 10^23 atoms N which is = 14.01g N

2.

if 6.022 x 10^23 atoms of Nitrogen is 14

then x atoms  of Nitrogen is 9.79

3.

6.022 x 10^23/ x = 14/9.79 ->

x = 8.431 x 10^24 / 9.79 =

8.61799714478 x 10^23

4.

8.61799714478 x 10^23 atoms of N

6.022 x 1023 atoms of H have a mass of 1.008g, so

8.61799714478 x 10^23 atoms of H have a mass of (1.008/6.022 x 1023) x 8.61799714478 x 10^23) = 1.44250051072175g

1.44 g

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How many grams of calcium are in 2.25 molar of calcium

Answers

Answer:

40 g

Explanation:b

What is indicated by the methyl-prefix?
OA. The molecule is an alkene.
OB. The molecule is a branched hydrocarbon.
O C. The molecule is saturated with hydrogen atoms.
OD. The molecule is a stereoisomer.

Answers

Answer:

B.) The molecule is a branched hydrocarbon.

Explanation:

A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.


Balance the equation below and identify the type.
NH4NO₂(s)---> N₂(g) + H₂O(l)

Answers

NH4NO2 (s) —> N2 (g) + 2H2O(l)

What are the molecular polarity and the intermolecular forces present in the sun

Answers

The molecular polarity of the sun is the dipoole separation of electric charge leading to a molecule in the sun.

What is molecular polarity?

Molecular polarity simply refers to those regions of molecules containing or possessing positive and negative charge

So therefore, the molecular polarity of the sun is the separation of electric charge leading to a molecule in the sun.

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What mass of water was produced if 350.0 L of carbon dioxide were made at STP? C3H8 (g) + 5O2(g) → 2CO2 (g) + 4H2O (g)

Answers

700 L of water was produced if 350.0 L of carbon dioxide were made at STP.

The quantitative relationship (ratio) between reactants and products in a chemical reaction that produces gases is known as gas stoichiometry. When the created gases are presumed to be ideal and their temperature, pressure, and volume are all known, gas stoichiometry is applicable.

The ideal gas equation is PV=nRT, where n is the number of moles and R is the gas constant, P is the pressure measured in atmospheres (atm), V is the volume measured in liters (L), and

Calculations based on stoichiometry assist scientists and engineers who work in the business world in estimating the number of items they will make using a particular process. They can also assist in determining if a product will be economical to produce.

Reduced growth, reproduction, and survivability for the consumer are typically the results of a significant stoichiometric imbalance between the primary producer and consumer.

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A piece of string is found to be 35.9 meters long. How long is the string in inches?

Answers

Answer: 1413.39 inches

Explanation:

Formula for converting meters to inches

Meters x 39.37 (roughly) = Value in inches

Applying formula

35.9 meters x 39.37 = 1413.39 inches (roughly)

C3H8O dissolved in water

Answers

If C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

What is a strong electrolyte?

A strong electrolyte is a solute or solution (already an electrolyte) that can completely dissociates in solution.

C3H8O is one of those compounds expected to be a strong electrolyte.

Thus, if C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

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An acid-base indicatior is a compound who's color is pH dependent. That is, it changes color depending upon whether it is in acid or base. This is because indicators are weak acids and undergo the following equilibrium. H-Ind ↔ H+1 + Ind-1 H-Ind = the indicator molecule that is protonated and predominates under acidic conditions. Ind-1 = the deprotonated indicator molecule (the conjugate base of the acid) and predominates under basic conditions. We are using the Acid-Base indicator, phenopthalein for this experiment. What is the color of this indicator in Acid? . What is the color of this indicator in Base

Answers

Phenolphthalein is pink in acid and colorles in base.

Substances called indicators are those whose solutions change colour as the pH changes. We refer to these as acid-base indicators. The conjugate base or acid versions of these typically weak acids or bases have various hues because of variations in their absorption spectra. When it comes into contact with an object that has a pH of 8.2, it turns pink. At a pH higher than that, it turns purple.

Additionally, ionisation, which modifies the charge and structure of the phenolphthalein molecule, is the cause of this shift in colour. If it comes into contact with an acid like vinegar or a neutral substance like water, it retains its colorlessness.

Therefore, Phenolphthalein is pink in acid and colorles in base.

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Which of the following aqueous solutions are good buffer systems?

(Select all that apply.)

a. 0.28 M hydrobromic acid + 0.24 M sodium bromide
b. 0.29 M ammonia + 0.38 M ammonium bromide
c. 0.22 M hypochlorous acid + 0.18 M hydroiodic acid
d. 0.37 M sodium chloride + 0.25 M barium chloride
e. 0.13 M sodium hydroxide + 0.28 M sodium bromide

Answers

0.29 M ammonia + 0.38 M ammonium bromide and 0.22 M hypochlorous acid + 0.18 M hydroiodic acids of aqueous solutions are good buffer systems.

Buffer Systems:

A solution that resists pH change when acids or bases are added to it is referred to as a buffer system. Either a weak acid and its salt, or a weak base and its salt, make up buffer systems. The ratio of HX/X- does not considerably alter when an acid or a base is introduced to a buffer.

Solutions known as buffers withstand pH changes when an acid or base is added. A weak base (A) and its conjugate weak acid (HA) are both present in buffers. When a reactive system is in equilibrium, adding a strong electrolyte with one common ion will cause the equilibrium to shift, lowering the concentration of the common ion. Buffers differ from one another in terms of pH range and buffer capacity.

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Suppose certain sample takes 100 min for 750 mL water to percolate into the
soil. Calculate the rate of percolation of water.

Answers

The rate of percolation of water into the soil will be 0.125 mL per second

Percolation rate

The rate of percolation of water into the soil is determined by the volume of water that enters the soil per unit of time under specific conditions.

In this case, 750 mL of water percolated in 100 minutes.

100 minutes = 100 x 60 = 6,000 seconds

Percolation rate = 750/6000 = 0.125 mL per second

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A gas that has a volume of 13 liters, a temperature of 25 0C, and an unknown pressure has its volume increased to 27 liters and its temperature decreased to 15 0C. If I measure the pressure after the change to be 1.3 atm, what was the original pressure of the gas?

Answers

This is an exercise in the general or combined gas law.

To start solving this exercise, we obtain the data:

Data:V₁ = 13 LtT₁ = 25 °C + 273 = 298 kV₂ = 27 LtT₂ = 15 °C + 273 = 288 kP₁ = 1.3 atmP₂ = ¿?

We use the following formula:

P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula

Where

P₁ = Initial pressureV₁ = Initial volumeT₂ = Initial temperatureP₂ = Final pressureV₂ = Final volumeT₁ = Initial temperature

We clear the general formula for the final pressure.

[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2} }{V_{2}T_{1}} \ \to \ Clear \ formula \end{gathered}$}[/tex]

We substitute our data into the formula to solve:

[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(1.3 \ atm)(13\not{l})(288\not{k} )}{(27 \not{l})(298 \not{K})} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{4867.2}{8046} \ atm \end{gathered}$}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=0.604 \ atm \end{gathered}$}}[/tex]

If I measure the pressure after the change by 1.3 atm, the original pressure of the gas will be 0.604 atm.

7. Which of the following compound is the most soluble in CC14? C. NH3 A. HF B. NaCl D. C10H22​

Answers

C10H22 is a compound which is the most soluble in CC14 because both are non-polar in nature.

Why polar solute soluble in polar solvent?

We know that like dissolve like which means that polar solutes only  dissolve in polar solvent while on the other hand, non-polar solutes only dissolve in non-polar solvent.

So we can conclude that C10H22 is a compound which is the most soluble in CC14 because both are non-polar in nature.

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How many MOLES of sulfur hexafluoride are present in 2.33x1022 molecules of this compound

Answers

Answer:

0.0387 moles SF₆

Explanation:

To find the moles of sulfur hexafluoride (SF₆), you need to multiply the number of molecules by Avogadro's number. Avogadro's number is a ratio between molecules and moles. It is important to arrange the conversion in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to match the sig figs of the given value (2.33 x 10²²).

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

2.33 x 10²² molecules SF₆                    1 mole
---------------------------------------  x  ------------------------------------  =  0.0387 moles SF
                                                    6.022 x 10²³ molecules

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