Answer:
4 A
Explanation:
Current is found using Ohm's law.
I = V/R
I = (240 volts)/(60 ohms) = 4 A
The heating element current is 4 amperes.
Which of the following answers regarding Mealy and Moore Machines are true?
a. A Mealy will have less or the same amount of states as a Moore and a Mealy machine inputs are not directly connected to the output.
b. A Mealy machine will not have less or the same amount of states as a Moore machine and a Mealy machine inputs are not directly connected to the output.
c. A Mealy machine will not have less or the same amount of states as a Moore machine and a Mealy machine inputs are directly connected to the output.
d. A Mealy will have less or the same amount of states as a Moore and a Mealy machine inputs are directly connected to the output.
Answer:
suck bro ☺️☺️ lol
Consider uniaxial extension of a test specimen. It has gauge length L = 22 cm (the distance between where it is clamped in the testing fixture) with a cross section of diameter D = 1.8 mm. You expect the material to have a Young’s modulus E = 205 GPa and ultimate tensile strength of σu = 420 MPa. You would like to conduct a tensile test such that the test takes 2 minutes to go from initial loading to fracture. In completing the calculations below, assume the material’s stress-strain curve is perfectly linear until fracture.
Required:
a. At what force do you expect the specimen to fracture?
b. At what strain rate should you pull the specimen, in mm/minute? Assume the material undergoes brittle fracture and its stress-strain curve is perfectly linear to fracture.
c. What is the elongation (in inches) of the specimen in the moment just prior to fracture?
Answer:
A) 4800.6 N
B) 0.2255 mm/min
C) 8.6792 inches
Explanation:
Given data :
gauge Length = 22 cm = 220 mm
cross section diameter/thickness = 1.8 mm
young's modulus ( E ) = 205 GPa
Ultimate tensile strength ( σu ) = 420MPa
Time = 2 mins
A) what force would fracture the specimen
σU = Ff /A
where A (area) = thickness * width ( unknown ) hence we assume a width of 6.35 mm
Ff = σU × A = 420 * 1.8 * 6.35 = 4800.6 N
B) calculate the strain rate
Ultimate tensile strength ( σU ) = εE
ε = σU / E = 420/205000 = 0.00205
also ε = ΔL / Li = ( Lf - Li) / Li = (Lf / Li) - 1
therefore ε + 1 = (Lf / Li) = 1 + 0.00205 = 1.00205
Li = gauge length = 220 mm
Hence : Lf = 1.00205 × gauge length = 1.00205 * 220 = 220.451 mm
strain rate
(Lf - Li) / Time = (0.451) / 2 min = 0.2255 mm/min
C) Elongation in inches prior to fracture
ΔL = ε × Li = 0.451 mm
Lf = 220 mm + 0.451 mm = 220.451 mm = 8.6792 inches
7 Water undergoes changes in state because
temperature affects the speed of its particles.
Which of the following statements best
explains why water changes into a gas when
heated? 5.3(A)
A The lower the temperature, the slower the
speed of the particles.
B Particles of liquids can move from place to
place.
C The higher the temperature, the faster the
speed of the particles.
D Water takes the shape of its container.
Answer: B. Particles of liquids can move from place to
Explanation:
Fast-moving particles transfer energy to slower-moving particles ... The motion of water molecules causes them to leave the liquid and become a gas.
calculate the length of the resistor of a circular wire in a heater element connected to a 240V supply and the heater consumes 8 joules of energy in 0,25 seconds.The resistor element is made of aluminium and it has a uniform cross-sectional area with a diameter of 0,00016 inches.
hint: 1 inch=25,4 MN, resistivity of aluminium=2,825×10^-6 cm ohms
Answer:
82.7 cm or 32.5 in
Explanation:
The required resistance is calculated from the relationship of power, voltage, and resistance. The wire length to give that resistance is calculated from ...
L = A·R/ρ
The power is the ratio of energy to time:
P = E/t = (8 J)/(0.25 s) = 32 W
The required resistance is ...
R = V²/P = (240 V)²/(32 W) = 1800 Ω
__
Then the required wire length is ...
L = (π/4)(0.00016 in × 2.54 cm/in)²×(1800 Ω)/(2.825×10^-6 Ω·cm)
L ≈ 82.65 cm
The length of aluminum wire required is about 82.7 cm or 32.5 in.
_____
Additional comment
This wire is roughly 66 AWG, about 1/6 the diameter of a human hair. Its melting current in still air is likely well below the current it carries in this heater. That is, it probably needs to experience significant airflow in order to maintain its integrity.
Show that the dimensions of momentum per unit area per time are the same as those of force per unit area
Answer:
Unit of,
momentum = kg×m/s
momentum per unit area = kg×m/s×m² = kg/m×s
momentum per unit area per unit time= kg/ms²
force = kg×m/s²
force per unit area = kg×m/s²×m² = kg/ms²
Explanation:
Need help solving math problem using integration
A 500mm-long rod has a diameter of 25mm. If an axial tensile load of 50kN is applied to it,please answer the following questions:______.
(a) Will the material undergoyielding? Why or Why not?
(b) Can Hooke’s law be applied to this problem? (Assumethe proportionallimitstress is same with the Yield Strength of the material.)
(c) What is the longitudinalstrain?
(d) What is the lateral strain?
(e) What isthe change in its diameter? (PleaseuseYoung’smodulus E=200GPa, Shear Modulus (or Modulus of Rigidity) G=75.2GPa, and Yield StrengthσY=400????Pa)
Answer:
(a) Since, the stress is less than the yield strength. Therefore, the material does not go yielding.
(b) Yes
(c) Longitudinal Strain = 5.09 x 10⁻⁴
(d) Lateral Strain = 1.67 x 10⁻⁴
(e) Change in Diameter = 4.2 x 10⁻³ mm = 4.2 μm
Explanation:
(a)
First we calculate stress:
Stress = Force/Area = F/πr²
Stress = 50 KN/π(0.0125 m)²
Stress = 101.86 MPa
Since, the stress is less than the yield strength. Therefore, the material does not go yielding.
(b)
Yes, Hooke's law can be applied to this problem because the material is within elastic limits.
(c)
Longitudinal Strain = Stress/E
Longitudinal Strain = 0.10186 GPa/200 GPa
Longitudinal Strain = 5.09 x 10⁻⁴
(d)
Poisson's Ratio = Lateral Strain/Longitudinal Strain = E/2G - 1
Lateral Strain/Longitudinal Strain = E/2G - 1
Lateral Strain/5.09 x 10⁻⁴ = 200 GPa/2*75.2 GPa - 1
Lateral Strain = 0.33*5.09 x 10⁻⁴
Lateral Strain = 1.67 x 10⁻⁴
(e)
Lateral Strain = Change in Diameter/Original Diameter
Change in diameter = (1.67 x 10⁻⁴)(25 mm)
Change in Diameter = 4.2 x 10⁻³ mm = 4.2 μm
Consider a carbon fiber reinforced epoxy composite. The fibers are continuous, unidirectionally aligned and 40% by volume. The tensile strength of carbon fibers is 2998 MPa, and the Young's modulus is 214 GPa. The tensile strength of the epoxy matrix is 100 MPa, and its Young's modulus is 3 GPa.
Required:
a. Compute the Young's modulus and the tensile strength of the composite in the longitudinal direction.
b. What is Young's modulus in the longitudinal direction?
Answer:
- the Young's modulus of the composite in the longitudinal direction = 87.4GPa.
- The tensile strength of the composite in the longitudinal direction = 1.26 × 10⁹.
Explanation:
The following parameters or data were given in this particular question/problem;
1. "The fibers are continuous, unidirectionally aligned and 40% by volume."
2." The tensile strength of carbon fibers is 2998 MPa, and the Young's modulus is 214 GPa."
3. " The tensile strength of the epoxy matrix is 100 MPa, and its Young's modulus is 3 GPa."
So, let us delve right into the solution to this question:
[ kindly note that part b. of this problem is the same as the part a. of the problem
Also, in point 2. above 2998MPa = 2.998 =GPa, approximately 3GPa].
40% = 40/100 = 0.4. Therefore, 1 - 0.4 = 0.6. Hence, the Young's modulus of the composite in the longitudinal direction = 3 × 0.6 + 214 × 0.4 = 1.8 + 85.6 = 87.4GPa
The tensile strength of the composite in the longitudinal direction = 100 × 10⁶ × 0.6 + 3 × 10⁹ ₓ 0.4 = 1.26 × 10⁹.
A strip footing of width 3 m is founded at a depth of 2 m below the ground surface in a (c – 0) soil having a cohesion c = 30 kN/m2 and angle of shearing resistance 0 = 35°. The water table is at a depth of 5 m below ground level. The moist weight of soil above the water table is 17.25 kN/m3. Determine the find ultimate bearing capacity of the soil.
Using Terzagi's Equation as shown in the attachement;
Qa = 4225 kN/m
As per the given data, the ultimate bearing capacity of the soil is 313 kN/[tex]m^2[/tex]
What is bearing capacity?Bearing capacity is the capacity of soil to support loads applied to the ground in geotechnical engineering.
To determine the ultimate bearing capacity of the soil, we can use the following formula:
q_ult = cN_c + 0.5γ*(BN_q + 0.4N_g*(B - B_f)*N_q)
To find the values of N_c, N_q, and N_g, we can use the following equations:
N_c = [cot(0) + tan(φ)][1 + 0.2(B_f/D)][(N_q/N_c) - 1][(N_q/N_c) - 2]
N_q = [(1 + sin(0))(1 - sin(0))][(N_q/N_c) - 1]
N_g = 0.5*(N_q - 1)*tan^2(φ)
Using the above equations, we can calculate the values of N_c, N_q, and N_g as follows:
N_c = [cot(35°) + tan(35°)][1 + 0.2(3/2)][(2.45/N_c) - 1][(2.45/N_c) - 2] ≈ 11.5
N_q = [(1 + sin(35°))(1 - sin(35°))][(2.45/N_c) - 1] ≈ 10.5
N_g = 0.5*(10.5 - 1)*[tex]tan^2[/tex](35°) ≈ 2.6
Substituting these values into the formula for q_ult, we get:
q_ult = 3011.5 + 0.517.25*(310.5 + 0.42.6*(3 - 3)*10.5) ≈ 313 kN/m^2
Therefore, the ultimate bearing capacity of the soil is approximately 313 kN/m^2.
For more details regarding bearing capacity, visit:
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An entrepreneur buts a computer from a manufacturer for $975. Calculate
the selling price if he makes a profit of 25%.
Answer:
1218.75
Explanation: If he makes a 25% profit, he needs to sell it for 125% of the computer price. 1.25*975 is 1218.75
This figure represents a portable ramp that is being recovered on all sides. How much material is needed to recover the ramp?
A. 1288 m²
B. 1416 m²
C. 1443 m²
D. 1680 m²
the answer is 1288 m2
Explanation:
i took the k12 test
Answer: The answer is 1288
Explanation: I took the test and it was right
20 cusecs of water added to vertical wall reservoir having surface area of 800 Acres. How many hours will it take to raise water level by 1 ft?
Answer:
484 hours
Explanation:
The given quantity of water will be added in a time period equal to the quantity divided by the rate.
(800 ac·ft)(43560 ft²/ac)/(20 ft³/s × 3600 s/h) = 484 h
It will take 484 hours to raise the water level by 1 ft.
__
Additional comment
We have assumed the given rate is a net rate of water influx. Evaporation from 800 acres may amount to about 1.3 ft³/s, or 6.6% of the inflow rate. It could be more than 3 times that amount, depending on the climate conditions at the reservoir's location.
Hi, I need a hand please.
Describe how you would use principles of series circuit to analyze a parallel circuit. What formulas used in a series circuit analysis would not apply?
Answer:
The principles of a series circuit that can be used to analyze a parallel circuit is that of calculating total resistance in the circuits.
The formula used in a series circuit analysis for finding total resistance is different from that used in a parallel circuit for finding overall resistance. i.e.
For a series circuit total resistance Rt={R1+R2+R3+.......Rn}
For a parallel circuit, total resistance 1/Rt ={1/R1+1/R2+1/R3+.....1/Rn]
Explanation:
In a series circuit, the current passing through each component is the same where as in a parallel circuit the voltage through each component is the same.
The principles of series circuit that can be used to analyze a parallel circuit is that of calculating total resistance in the circuits. In a series circuit, total resistance is calculated as the sum of resistance of the components connected to the circuit, where as in a parallel circuit, overall resistance is the summation of the resistance of individual components.
This means you can use principles of series circuit to find total resistance then use that value to confirm the individual resistance values of components in a parallel circuits. This is possible because you will have the expected total resistance [calculated from the series circuit], then the sum of resistance of the same but individual components now in the parallel circuit should be equal to the total resistance calculated from the series circuit.
The formula for calculating resistance in series circuit given as :{Rt= R1+R2+R3+.......Rn} where Rt is the total resistance and R1,R2,R3...Rn are the values of individual components in the series circuit, can not be used in finding overall resistance in a parallel circuits because the formula for total resistance will change to : [1/Rt =1/R1+1/R2+1/R3+.....1/Rn]
What are the two categories of tools? list examples of each. in agriculture
If total surface flow 144 million acre-foot is spread over 881,913 km², Estimate the depth of water?
Answer:
20.1 cm
Explanation:
The depth is the ratio of volume to area.
[tex]\dfrac{1.44\times10^8\text{ ac$\cdot$ft}}{8.81913\times10^5\text{ km}^2}=\dfrac{(1.44\times10^8)(4.356\times10^4\text{ ft}^3)(0.3048\text{ m/ft})^3}{(8.81913\times10^5\text{ km}^2)(10^3\text{ m/km})^2}\\\\=\dfrac{1.44\times4.356\times0.3048^3\times10^{12}}{8.81913\times10^{11}}\text{ m}\approx0.2014\text{ m}[/tex]
The depth of water is about 20.1 cm.
_____
Additional comment
An acre-foot is 43,560 cubic feet.
A foot is 0.3048 meters.
A kilometer is 1000 meters.
A centimeter is 0.01 meters.
PLEASE HELP!!!! 10 POINTS
What battle destroyed German air power?
A The D-Day invasion
B The Battle of Britain
C The Battle for Berlin
D The Battle of the Bulge
An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.
Think about the ineffective leaders (bosses, coaches, etc.) you have experienced. What dark-side traits did these leaders possess that caused them to be ineffective?
The dark-side traits the leaders possessed that caused them to be ineffective are; Narcissism, Psychopathy and Machiavellianism.
What are bad character traits?
According to Paulhus and williams, they discovered in year 2002 that several personality traits could be related to failures of a leader but they narrowed it down to three which they referred to as the Dark Triad.
These dark side traits are;
NarcissismPsychopathyMachiavellianismRead more about character traits at; https://brainly.com/question/24856057
Please help me with this problem i really can't complete it
Answer:
VX = V1·R2/(R2 +R1(1 +AVOL))VX ≈ -99.0001 μVVout = -V1·R2·AVOL/(R2 +R1(1 +AVOL))Vout ≈ 0.990001 VExplanation:
It is useful to consider the voltage at X to be the superposition of two voltages divided by the R1/R2 voltage divider. It is also helpful to remember that OUT = -VX·AVOL.
__
a)[tex]V_X=\dfrac{V_1\cdot R_2+V_{out}\cdot R_1}{R_1+R_2}=\dfrac{V_1\cdot R_2-V_X\cdot A_{VOL}\cdot R_1}{R_1+R_2}\\\\V_X(R_1(1+A_{VOL})+R_2)=V_1\cdot R_2\\\\\boxed{V_X=V_1\dfrac{R_2}{R_2+R_1(1+A_{VOL})}}[/tex]
__
b)Filling in the given numbers, we find VX to be ...
[tex]V_X=-0.01V\cdot\dfrac{400000}{400000+4000(1+10000)}=-0.01V\cdot\dfrac{100}{10101}\\\\\boxed{V_X=\dfrac{-1}{10101}V\approx-99.0001\mu V}[/tex]
__
c)As we said at the beginning, OUT = -VX·AVOL. Multiplying the expression for VX by -AVOL, we get ...
[tex]\boxed{V_{out}=-V_1\cdot\dfrac{A_{VOL}\cdot R_2}{R_2+R_1(1+A_{VOL})}}[/tex]
__
d)As with the expression, the output voltage is found by multiplying VX by -AVOL:
[tex]V_{out}=\dfrac{(-1)(-10000)}{10101}V\\\\\boxed{V_{out}=\dfrac{10000}{10101}V\approx 0.990001V}[/tex]
What are the 2 main sources of data
Following are the two sources of data:
Internal Source. When data are collected from reports and records of the organisation itself, it is known as the internal source. ... External Source. When data are collected from outside the organisation, it is known as the external source.IamSugarBee
Answer:
I hope this helps
Explanation:
.... Internal source
.... External source
Primary mental skills needed for riding a motorcycle
Answer:
You have to know the basic mechanics to help you correctly use the motorcycle, and you also have to have the right mindset - knowing you can ride it, and having determination. All of these factors are the primary mental skills you need for riding a motorcycle.
Answer:
B. Information processing and decision-making
Explanation:
In your own words, describe the differences between en-
tering the workforce right after high school or working in a
skilled trade.
Answer:
if you are entering the workforce right after high school you are likely to get less pay and work maybe a little harder and also have to learn from the people at the job how to do the job compared to someone who is working in a skilled trade where they know what they are doing, are likely to get a higher pay, and dont need to be taught what to do.
Explanation:
The cost to rent a scooter is $15.50 per hour and the cost to rent a watercraft is $22.80 per hour use the expression 15.5 S +22.8 W you The cost to rent a scooter is $15.50 per hour and the cost to rent a water craft is $22.80 per hour use the expression 15.5 S +22.8 W you you
Complete Question:
The cost to rent a scooter is $15.50 per hour and the cost to rent a watercraft
is $22.80 per hour. Use the expression 15.5s + 22.8w to determine how much it would cost to rent a scooter for 3 hours and a watercraft for 1 hours.
Answer:
$69.39
Explanation:
Given
15.5s + 22.8w
Required
Evaluate, when w = 1 and s = 3
To do this, we simply substitute 3 for a and 1 for w in the given expression.
15.5s + 22.8w becomes..
15.5 * 3 + 22.8 * 1
46.5 + 22.8
69.3
Hence, the cost is $69.30
what do engineers do?
Answer:
engineers are people who fix or invent items that will support people’s lives. For fun, engineers may construct unique items that is hard to invent.
Explanation:
If you need more info, pls comment.
Answer:
An engineer uses science, technology and math to solve problems. It designes machinery, build skyscrapers and oversee public works.
Hi,
I'm paying for this monthly and I'm receiving this upgrade message.
I'm here if you need help with a math question
Tru or false A tractor is experiencing a reduction in pressure the amount of force this will result in decreasing the Propulsion of the tractor
Answer:
true
Explanation:
i took the test and got it right
Which decimal is greater than ?
Answer:
What are u asking for?
Explanation:
Please give me the answers
Answer:
the 4th one
Explanation:
no id you can't drive
Create a Reverse application that stores the number corresponding to the element's index in an integer array of 10 elements. For example, the second element, which has index 1, should store 1. The application should then display the title "Countdown" and then list numbers stored in the array in reverse order.
Answer:
Written in Java
public class MyClass {
public static void main(String args[]) {
int [] myarray = new int[10];
for(int i = 0;i<10;i++) {
myarray[i] = i;
}
System.out.println("Countdown");
for(int i = 9;i>=0;i--) {
System.out.println(myarray[i]);
}
}
}
Explanation:
This line declares the array
int [] myarray = new int[10];
The following iteration inserts 0 to 9 into the array
for(int i = 0;i<10;i++) {
myarray[i] = i;
}
This line prints "Countdown"
System.out.println("Countdown");
The following iteration prints the array in reverse order
for(int i = 9;i>=0;i--) {
System.out.println(myarray[i]);
}
Q4. (assessment criteria 3. 1) state newton's law of cooling and define the terms in the equation. 1. 2. Obtain the solution when the initial liquid temperature is 100 c, the ambient temperature is 2 and the thermal time constant is 60 min. 3. Plot the solution. Remember to label the axis. 4. Calculate the fluid temperature after one time constant.