Answer:
1.33
Step-by-step explanation:
Given that:
Upper specification limit ( USL ) = 10
Lower specification limit ( LSL ) = 2
the standard deviation σ = 1
What is the Cp"
The Cp is the process capability ratio which can be expressed by the formula:
[tex]C_P = \dfrac{USL -LSL}{6 \times \sigma}[/tex]
[tex]C_P = \dfrac{10 -2}{6 \times 1}[/tex]
[tex]C_P = \dfrac{8}{6}[/tex]
[tex]C_P = \dfrac{4}{3}[/tex]
[tex]C_P =1.33[/tex]
A man walks along a straight path at a speed of 3 ft/s. A searchlight is located on the ground 4 ft from the path and is kept focused on the man. At what rate is the searchlight rotating when the man is 3 ft from the point on the path closest to the searchlight
Answer: 0.48 rad/sec
Step-by-step explanation:
dx/dt = 3ft
to find d∅/dt when x = 3
Using the right angled triangle
ΔABC
Now perpendicular (BC) = X FT
Base ( AC) 4 ft
so Hypotenuse(AB) = √ (BC² + AC²) = √ ( x² + 4²) = √ ( x² + 16)
and x/4 = tan∅ ; x = 4tan∅
now we differentiate each side
dx/dt = d/dt(4tan∅) = d/d∅(4tan∅) d∅/dt
⇒ dx/dt = (4sec²∅) d∅/dt = ( 1/4 cos²∅) dx/dt
⇒ d∅/dt = cos²∅/4 × 3 = 3/4 cos²∅
now when x = 3, the length of the beam is
{from our initial equation (AB) = √ (BC² + AC²)}
AB = √(3² + 4²) = √(9 + 16) = 5ft
therefore cos∅ = 4/5
so we substitute in (d∅/dt = ( 1/4 cos²∅) dx/dt)
d∅/dt = 1/4 ( 4/5)² × 3
d∅/dt = 12/15 = 0.48 rad/sec
Which are solutions of the equation x2 - 16 = 0? Check all that apply.
x= -8
x=-4
x=-2
x= 2
x= 4
x=8
Answer:
B) -4 and E) 4
Step-by-step explanation:
f (x) = √2X-6
What is f(5)?
Answer:
f(5) = 2
Step-by-step explanation:
Given:
Function f(x) = [tex]\sqrt{2x - 6}[/tex]For x=5 :
f(5) = [tex]\sqrt{2*5 - 6}[/tex] = [tex]\sqrt{4}[/tex] = 2(3xy2x2y−3)2(9xy−3x3y2)−1.
Answer:
-18x square y -+36xy square + 54 xy - 1
Step-by-step explanation:
collect the terms, calculate the product, collect the terms, then distribute
A book sold 33,200 copies in its first month. Suppose this represents 7.4% of the number of copies sold to date. How many copies have been sold to date?
Answer:
448,648
Step-by-step explanation:
33,200/.074 = 448,648
Answer: 448648
Step-by-step explanation:
33,200 copies represent 7.4% of the total amount
-----------------------------------------------------
#1 33,200 ÷ 7.4%
- this is because how we get 33,200 by calculation is use the total amount and times 7.4% to get 33,200. So we are just working backwards. Since it was times before, then we divide after.
33,200÷7.4%
=33,200÷0.074
≈448648 (you can't round up when the real amount is less the exact amount)
Find the distance between (-1, 4) and (1,-1).
Answer:
The answer is
[tex] \sqrt{29} \: \: units[/tex]Step-by-step explanation:
To find the distance between two points we use the formula
[tex]d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } [/tex]where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(-1, 4) and (1,-1)
The distance between them is
[tex]d = \sqrt{ ({ - 1 - 1})^{2} + ({4 + 1})^{2} } \\ d = \sqrt{ ({ - 2})^{2} + {5}^{2} } \\ d = \sqrt{4 + 25} [/tex]We have the final answer as
[tex]d = \sqrt{29} \: \: \: units[/tex]Hope this helps you
can someone PLEASE help me with these two ill mark them as brainliest!!!!!
Answer:
20
Step-by-step explanation:
A=1/2bh
A=1/2(8×5)
A=1/2(40)
A=20
Circle O is shown. Line segments A C and B D are diameters. The measure of arc A B is (3 x minus 70) degrees and the measure of arc D C is (x + 10) degrees. What is mArc B C? 50° 80° 100° 130° In circle O, AC and BD are diameters. In circle O, AC and BD are diameters.
Answer:
Option (4)
Step-by-step explanation:
From the given circle O,
AC and BD are the diameters intersecting at point O.
∠AOB ≅ ∠COD [Vertical angles]
Therefore, length of intercepted arcs by these central angles will be same.
[tex]m(\widehat{AB})=m(\widehat{CD})[/tex]
(3x - 70) = (x + 10)
3x - x = 70 + 10
2x = 80
x = 40
Since, [tex]m(\widehat{AB})+m(\widehat{BC})=180[/tex] [Since AC is a diameter]
(3x - 70) + [tex]m(\widehat{BC})[/tex] = 180°
3(40) - 70 + [tex]m(\widehat{BC})[/tex] = 180°
[tex]m(\widehat{BC})[/tex] = 180° - 50°
= 130°
Therefore, Option (4) will be the correct option.
Answer:
130 degrees
Step-by-step explanation:
which expression is equivalent to the given expression 8 square root of 6
Answer:
[tex]\sqrt{384}[/tex]
Step-by-step explanation:
[tex]\sqrt{384}[/tex] is equivalent to [tex]\sqrt[8]{6}[/tex]
An equivalent expression to the given expression [tex]8\sqrt{6}[/tex] is [tex]\sqrt{384}[/tex]
What is expression?"It is a mathematical statement which consists of numbers, variables and some mathematical operations."
What are equivalent expressions?"The expressions that work the same even though they look different."
For given question,
We have been given an expression [tex]8\sqrt{6}[/tex]
We know, for a positive real number a, [tex]\sqrt{a^2}=a[/tex]
So, we can write 8 as [tex]8=\sqrt{8^2}[/tex]
So, given expression becomes [tex]\sqrt{8^2}\sqrt{6}[/tex]
We know, for any positive real numbers m, n, [tex]\sqrt{m} \sqrt{n}=\sqrt{mn}[/tex]
[tex]\sqrt{8^2}\sqrt{6}[/tex]
= [tex]\sqrt{8^2\times 6}[/tex]
= [tex]\sqrt{64\times 6}[/tex]
= [tex]\sqrt{384}[/tex]
So, an expression [tex]8\sqrt{6}[/tex] is equivalent to expression [tex]\sqrt{384}[/tex]
Therefore, an equivalent expression to the given expression [tex]8\sqrt{6}[/tex] is [tex]\sqrt{384}[/tex]
Learn more about equivalent expressions here:
https://brainly.com/question/24242989
#SPJ3
. In a study about the relationship between the age of a person and the preference for digital vs analog watches, which of the following could be valid data sets? (Choose all that apply) A.height of a person B.watch preference for those who are less than 30 years C.the quality of the strap of the watch D.type of watch, digital or analog D.age of a person
Answer:
B and the first d and second one.
Step-by-step explanation:
The age is a big factor and b can showing the preference per age
Density is a unit rate measured in units of mass per unit of volume the mass of the Garnett is 5.7 grams the volume is 1.5 cubic centimeters what is the density of the Garnet
Answer:
The density is 3.8 g
Step-by-step explanation:
D=M/V (Density= Mass divided by Volume)
5.7 divided by 1.5 is 3.8
Alex buys a car for $19500 and later sells it at a profit of 5%. At what price did he sell the car?
Answer:
$20,475
Step-by-step explanation:
you multiply 19,500 by 0.05 (19500*0.05) to get $20,475
Hope this helps :)
Find the exact sum or difference. 0.78 – 0.52 = A. 0.16 B. 0.26 C. 0.24 D. 0.14
Given the following probability distribution, what is the expected value of the random variable X? X P(X) 100 .10 150 .20 200 .30 250 .30 300 .10 Sum 1.00
Answer: 1
Step-by-step explanation:
If you were to open an account that will pay you 3.5% interest with a deposit of $150 so find the following ending amount for each period at the end of 2 years
Answer:
FV= $160.68
Step-by-step explanation:
Giving the following information:
Initial investment= $150
Interest rate= 3.5% compounded annually
Number of periods= 2
To calculate the future value, we need to use the following formula:
FV= PV*(1+i)^n
PV= present value
i= interest rate
n= number of periods
FV= 150*(1.035^2)
FV= $160.68
To draw a gragh for y = 2x +5, a person can draw a point at x of 0 and y of _, a second point by going over 1 and ip _, and then draw a line through the points.
Answer: A person can draw a point of x of 0 and y of 5, a second point by going over 1 and up 2, and then draw a line through the points.
Step-by-step explanation:
if x is equal to 0 then y will equal to 5 which in this case will represent the y intercept. And after plotting the point (0,5) you can use the slope and move over or left by 1 and move up by 2 to find the next point.
iven h (t) = t squared + t + 12 andk (t) = StartRoot t minus 1 EndRoot, evaluate (k compose h) (10)
Answer:
11Step-by-step explanation:
Given h(t) = t²+t+ 12 and k(t) = √t-1, we are to find k(k.h)(10)
k{h(t)} = k{ t²+t+ 12}
Since k(t)= √t-1, we will replace the variable t in the function with t²+t+ 12
k(h(t)) = √{(t²+t+ 12)-1}
k(h(t)) = √t²+t+12-1
k(h(t)) = √t²+t+11
Substituting t = 10 into the resulting function;
k(h(10)) = √(10)²+(10)+11
k(h(10)) = √100+10+11
k(h(10)) = √121
k(h(10))= 11
hence the value of (k compose h) (10) is 11
A pool measures 15 feet by 17 feet. A cement walkway is added around the pool, to both the width and the length. The area of the pool and the cement walkway is now 483 square feet. What is the width of the cement walkway?
Answer:
21 feet
Step-by-step explanation:
The pool has dimension 15 feet by 17 feet, which is in the form of a rectangle.
The area of the pool = length × width
= 17 × 15
= 255 square feet
Area of the pool and cement walkway = 483 square feet
Area of walkway = area of pool and walkway - Area of pool
= 483 - 255
= 228 square feet
Let's assume that the cement walkway has equal thickness across its perimeter, so that;
the dimension of the pool and the cement walkway = 23 feet × 21 feet
The width of the cement walkway is 21 feet.
Simplify (2x)/3 + (9-x)/2 FYI. I'm pretty sure that x+27/6 isn't the answer but idk
Answer:
(27+x)/6
Step-by-step explanation:
(2x)/3 + (9-x)/2
Get a common denominator of 6
(2x)/3 *2/2 + (9-x)/2*3/3
4x/6 +3(9-x)/6
Distribute
4x/6 + (27-3x)/6
Combine like terms
(27+4x-3x)/6
(27+x)/6
Evaluate n/6+2when n=12
Points P, Q, and R are shown on the number line. What is the distance between point P and point R?
Answer:
5
Step-by-step explanation:
2.75-(-2.25)=
2.75+2.25=
5
What is the answer ?
Answer:
according to circle theorem the angle in the center is twice of the angle of the angle form by the cords of the circle.
Since, the center circle is 90 theta is 45 degrees
Step-by-step explanation:
*Another approach
Is a − b equal to b − a?
Answer:
a is a 1 and then you subtraction the b is equal 0
Select all the correct answers.
Which expressions are equivalent to the given expression.
y^-8y^3x^0x^-2
Answer:
[tex]x^{-2}y^{-5}[/tex]
Step-by-step explanation:
The options are not given; however, the question can still be solved
Given
[tex]y^{-8}y^3x^0x^-2[/tex]
Required
Simplify
Start by rewriting the expression
[tex]y^{-8} * y^3 * x^0 * x^{-2}[/tex]
Apply the following laws of indices: [tex]a^x * a^y = a^{x+y}[/tex]
This gives:
[tex]y^{-8+3} * x^{0-2}[/tex]
Evaluate the exponents
[tex]y^{-5} * x^{-2}[/tex]
[tex]x^{-2}y^{-5}[/tex]
Hence, [tex]x^{-2}y^{-5}[/tex] is equivalent to [tex]y^{-8}y^3x^0x^-2[/tex]
Answer:
The answer is- (Drumroll)
Step-by-step explanation:
The answers are [tex]x^-2y^-5[/tex], and [tex]1/x^2y^5[/tex]
The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at its head office during the year. A random sample of 30 executive level managers reveals the following: Absenteeism: Sample mean = 7.3 days, Sample standard deviation=6.2 days 18 mid-level managers out of the 30 randomly selected mid-level managers, cite stress as a cause of absence. (a) Construct a 90% confidence intervalestimate for the mean number of absences for mid- level managers during the year.(b) Construct a 98% confidence intervalestimate for the population proportion of mid-level managers who cite stress as a cause of absence. (c) What sample size is needed to have 95% confidence in estimating the population mean absenteeism to within 1.5 days if the population standard deviation is estimated to be 8 days? (d) How many mid-level managers need to be selected to have 99% confidence in estimating population proportion of mid-level managers who cite stress as a cause of absence to within +0.075 if no previous estimate is available?
Answer:
Following are the answer to this question:
Step-by-step explanation:
Given:
n = 30 is the sample size.
The mean [tex]\bar X[/tex] = 7.3 days.
The standard deviation = 6.2 days.
df = n-1
[tex]= 30-1 \\ =29[/tex]
The importance level is [tex]\alpha[/tex] = 0.10
The table value is calculated with a function excel 2010:
[tex]= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127[/tex]
The method for calculating the trust interval of 90 percent for the true population means is:
Formula:
[tex]\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}[/tex]
[tex]=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\[/tex]
It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.
find the unknown angle please help
Answer:
60
Step-by-step explanation:
The exterior angle is the sum of the opposite interior angles.
120 = x + the other angle next to x but not the one next to 120
Since it is an isosceles triangle
120 = x + x
120 = 2x
60 = x
Hope that helped!!! k
Which decimals are less than 2.312? Select all that apply. A. 2.311 B. 2.4 C. 2.32 D. 2.3 E. 2.31 F. 2.313
Answer:
a c d
Step-by-step explanation:
Can someone please help me find the answer for this please. Thank you.
Answer:
3
Step-by-step explanation:
Write down the expression exactly as it is given.
[tex] \dfrac{3y - 9}{x} = [/tex]
Now write the expression again, but replace x with 3, and replace y with 6.
[tex] = \dfrac{3 \times 6 - 9}{3} [/tex]
Now simplify the numerator using the correct order of operations.
[tex] = \dfrac{18 - 9}{3} [/tex]
[tex] = \dfrac{9}{3} [/tex]
Now divide 9 by 3.
[tex] = 3 [/tex]
Answer: 3
Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
x3 sin(x) dx, n = 8
1) The Trapezoidal Rule
2) The Midpoint Rule
3) Simpson's Rule
Answer:
-1392.09-1744.43-1636.41Step-by-step explanation:
using the given integral
calculate: Δx = (12-0) / 8 = 3/2
Xo = 0, f(x) = [tex]x^3sin(x)[/tex]
X1 = 3/2 , X2 = 3, X3 = 9/2, X4 = 6, X5 = 15/2, X6 = 9, X7 = 21/2, X8 = 12
Inputting the given values into the Trapezoid rule, midpoint rule and Simpson's rule to approximate the given integral with the specified value of n = 8
Use the number line below, where RS=7y+2, ST=5y+7, and RT=14y−3. a. What is the value of y? b. Find RS, ST, and RT.
Answer:
j
Step-by-step explanation: