What’s the correct answer for this?

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Answer 1

Answer:

Step-by-step explanation:

Lines with equal slopes are parallel since their slopes are equal so they are parallel.

Related Questions

A survey of 270 young professionals found that one dash eighth of them use their cell phones primarily for e-mail. Can you conclude statistically that the population proportion who use cell phones primarily for e-mail is less than 0.17? Use a 95% confidence interval. The 95% confidence interval is [nothing comma nothing ]. As 0.17 is ▼ within the limits below the lower limit above the upper limit of the confidence interval, we ▼ cannot can conclude that the population proportion is less than 0.17.

Answers

Answer:

As 0.17 is below the upper limit of the confidence interval, so we can conclude that the population proportion is less than 0.17.

Step-by-step explanation:

We are given that a survey of 270 young professionals found that one dash eighth of them use their cell phones primarily for e-mail.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of people who use their cell phones primarily for e-mail = [tex]\frac{1}{8}[/tex] = 0.125

n = sample of young professionals = 270

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95

P( [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95

95% confidence interval for p = [[tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]]

= [ [tex]0.125-1.96 \times {\sqrt{\frac{0.125(1-0.125)}{270} } }[/tex] , [tex]0.125+1.96 \times {\sqrt{\frac{0.125(1-0.125)}{270} } }[/tex] ]

= [0.08 , 0.16]

Therefore, 95% confidence interval for the population proportion who use cell phones primarily for e-mail is [0.08 , 0.16].

Since, the above confidence interval have values which is less than 0.17; so we conclude that the population proportion is less than 0.17.

What expression represents all solutions to cos(x)=0.15

Answers

Answer:

it od domedfg

Step-by-step explanation:

hihihi

please help me with this

Answers

Answer:

9x^2 + 12x

Step-by-step explanation:

The area of the blue

3* 3x^2 = 9x^2

The area of the pink is

3* 4x = 12x

Add them together

9x^2 + 12x

the parent function of the function g(x)

Answers

The parent function of the function g(x) = (x - h)2 + k is f(x) = x2. The vertex of the function g(x) is located at (9, -8)

Mia has earned $43.94 in tokens playing games at the amusement center. The store in the amusement center has the following toys for sale. She plans to get toys and donate them to a local charity for needy children. The tokens are only good in this store, so she plans to spend all the tokens. What combinations of toys can she buy in order to spend all the tokens?

Answers

Answer:

she will have in the end 1 dollar and four cent after she buys 12 things with her 43.94 dollars

Step-by-step explanation:

so she had 43.94 dollars she can by with it she can buy with it 12 things she can buy a yoyo a doll a duckie a tractor a airplane a ball a racecar a dog a car a elephant and the last thing she can buy is a whistle

Super Dave Osborne stands at the bottom of a canyon elevation 256 feet below sea level, he throws a piano up at a velocity of 320 feet per second the piano lands on the edge of the cliff at zero elevation . The flight of the piano is modeled by the equation f( x ) = −16t2 2 + 320t − 256. The piano was in the air for exactly how many seconds

Answers

Answer:

The piano was in the air for 18.34 seconds.

Step-by-step explanation:

The height of the piano after t seconds is given by the following equation:

[tex]f(t) = -16t^{2} + 320t - 256[/tex]

Initially, the piano is below the ground level. At the first root of the equation, it will go into the air, and then some time after that it will fall down again, which is at the second root of the equation.

Roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

In this question:

[tex]f(t) = -16t^{2} + 320t - 256[/tex]

[tex]a = -16, b = 320, c = -256[/tex]

[tex]\bigtriangleup = (320)^{2} - 4*(-16)*(-256) = 86016[/tex]

[tex]t_{1} = \frac{-320 + \sqrt{86016}}{2*(-16)} = 0.8348[/tex]

[tex]t_{2} = \frac{-320 - \sqrt{86016}}{2*(-16)} = 19.17[/tex]

Subtracting:

19.17 - 0.8348 = 18.34

The piano was in the air for 18.34 seconds.

complete the recursive formula of the arithmetic sequence 20,26,32,38

Answers

A recursive formula for a sequence expresses the [tex]n[/tex]-th term as a function of the previous one(s).

In this case, you can see that every term is 6 more than the previous one.

So, the recursive formula is "the [tex]n[/tex]-th term is 6 more than the [tex]n-1[/tex]-th term".

In formula, it's written

[tex]a_n=a_{n-1}+6[/tex]

Since the recursion could go back indefinitely, we usually set a starting point, so that the sequence is fully determined:

[tex]\begin{cases}a_0=20\\a_n=a_{n-1}+6\end{cases}[/tex]

The Recursive formula is [tex]a_n[/tex] = 6n - 14

What is Recursive formula?

Any term of a series can be defined by its preceding term in a recursive formula (s). For instance: An arithmetic series has the recursive formula a = [tex]a_n[/tex]-1 + d. [tex]a_n[/tex]= [tex]a_{n-1][/tex] r is the recursive formula for a geometric sequence.

Given:

20,26,32,38

First term, a= 20

Common difference, d= 26 -20 = 6

So, The recursive formula is

[tex]a_n[/tex] = a+ ( n-1)d

[tex]a_n[/tex] = 20 + ( n-1) 6

[tex]a_n[/tex] = 20 + 6n - 6

[tex]a_n[/tex] = 6n - 14

Hence, the Recursive formula is [tex]a_n[/tex] = 6n - 14

Learn more about recursive formula here:

https://brainly.com/question/8972906

#SPJ5

Find the mean, median, mode and range:
5, 2, 7, 4, 6, 9, 7, 5, 6, 7

Answers

So ,

here's your answer:

Mean =5.8

median=6

Mode=7

Range=7

Look at the attached picture

Hope it will help you

Good luck on your assignment

Write the answer and solution ?

Answers

Answer

4. E

use PEMDAS

5. 36+18=54 so C

plug in x

6. 15=5x

x=3 so C

11. B

break the absolute value into pos and neg components

12.D

is not equal to so open circle

2x=14

2x=8

so 4 and 7 with open circles

Step-by-step explanation:

Question 1
1 pts
In you closet, you have 5 T-shirts, 4 pants, and 7 hats. How many different outfits can you make with
these articles of clothing?

Answers

Answer:

140

Step-by-step explanation:

So all you have to do is multiply 5 * 4 * 7 to find out how many outfits you can make.

140

The postal service sorts mail as Priority Mail Express, Priority Mail, First-Class Mail, or Standard Mail. Over a period of 3 weeks, 18 of each type were mailed from the Network Distribution Center in Atlanta, Georgia, to Des Moines, Iowa. The total delivery time in days was recorded. Minitab was used to perform the ANOVA. The results follow: Source DF SS MS F P Factor 3 1.30 0.43 1.79 0.157 Error 68 16.45 0.24 Total 71 17.75 Level N Mean StDev Priority Mail Express 18 2.965 0.345 Priority Mail 18 3.044 0.631 First-Class Mail 18 3.296 0.578 Standard Mail 18 3.231 0.341 Using the ANOVA results, compare the average delivery times of the four different types of mail.

Answers

Answer:

Here, F = 2.911

F > 2.739502 , so reject null hypothesis ( H0)

There is ample evidence to indicate a disparity in the means for the different forms of mails.

Step-by-step explanation:

Null hypothesis - H₀: μ₁ = μ₂ = μ₃ = μ₄

Alternative hypothesis - H₁: At least one mean is different.

df1 is factor degree of freedom and df2 is error degree of freedom.

Decision rule - Reject H₀ if F > F₀.₀₅, (df1, df2)

F0.05, df1,df2 is f critical value at \alpha = 0.05

Here df1 = 3 , and df2 = 68

Using Excel,

F₀.₀₅, ₃, ₆₈ = FINV( 0.05, 3 , 68 ) = 2.739502302

So reject H0 if F > 2.739502

Here, F = 2.911

F > 2.739502 , so reject null hypothesis ( H0)

There is ample evidence to indicate a disparity in the means for the different forms of mails.

In a recent year, the Better Business Bureau settled 75% of complaints they received. (Source: USA Today, March 2, 2009) You have been hired by the Bureau to investigate complaints this year involving computer stores. You plan to select a random sample of complaints to estimate the proportion of complaints the Bureau is able to settle. Assume the population proportion of complaints settled for the computer stores is the 0.75, as mentioned above. Suppose your sample size is 209. What is the probability that th

Answers

Answer:

The probability that the sample proportion will be within 6 percent of the population proportion is 0.9556.

Step-by-step explanation:

The question is:

What is the probability that the sample proportion will be within 6 percent of the population proportion?

Solution:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

[tex]\mu_{\hat p}=p[/tex]

The standard deviation of this sampling distribution of sample proportion is:

[tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]

The information provided is:

n = 209

p = 0.75

As n = 209 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the Normal distribution.

[tex]\hat p\sim N(\mu_{\hat p}=0.75,\ \sigma_{\hat p}=0.0299)[/tex]

Compute the probability that the sample proportion will be within 6 percent of the population proportion as follows:

[tex]P(p-0.06<\hat p<p+0.06)=P(0.69<\hat p<0.81)[/tex]

[tex]=P(\frac{0.69-0.75}{0.0299}<\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}<\frac{0.81-0.75}{0.0299})\\\\=P(-2.01<Z<2.01)\\\\=P(Z<2.01)-P(Z<-2.01)\\\\=0.97778-0.02222\\\\=0.95556\\\\\approx 0.9556[/tex]

Thus, the probability that the sample proportion will be within 6 percent of the population proportion is 0.9556.

Find the ratio for sin(-120)

Answers

Answer:

- [square root (3) / 2]