(a) Relative to the ground, the gravitational potential energy of the orange on the branch is 4.29 J and on ground is 0 J.
(b) ) Relative to the branch, the gravitational potential energy of the orange on the branch is 0 J and on ground is 4.29 J.
(c) The change in potential energy relative to the ground is -4.29 J and relative to the branch is 0 J.
What is the gravitational potential energy?
Relative to the ground, the gravitational potential energy of the orange on the branch is calculated as follows;
P.E = mgh
where;
m is the mass of the orangeh is the height of the branch above the groundg is acceleration due to gravityP.E = 0.125 kg x 9.8 m/s² x 3.5
P.E = 4.29 J
The gravitational potential energy of the orange on the ground is calculated as follows;
P.E = mgh
P.E = m x g x 0 m
P.E = 0 J
The change in potential energy = final potential energy - initial potential energy
change in potential energy = 0 J - 4.29 J = - 4.29 J
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What would the power (Watts) be for a speaker if it draws 3.0 Amps of current when connected to a 12.0 Volt source?
144 is the power if the current is 3.0 ampere.
What is Power?Average power, or when tdelta, t in the equation for power is very large, is the power measured over a lengthy period of time. Finding the area under the power vs. time curve, which represents the total work completed, and dividing by the total time are two methods for calculating this.
Although calculus is typically the finest tool for this, it is frequently possible to estimate it very correctly only using geometry. Peak power is the highest value that an instantaneous amount of power can have in a given system over an extended period of time.
Systems that have the capacity to provide a peak power that is significantly greater than their rated average power include stereo systems and car engines.
Therefore, 144 is the power if the current is 3.0 ampere.
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The graph shows the maximum amount of water vapor that air can hold at different temperatures.
Line graph of maximum humidity on a coordinate plane. X-axis labeled Temperature (degrees Celsius). Y-axis labeled Water Vapor Density grams per cubic meter. Line starts at (0, 2) and gradually rises through (30, 30), 35, 40), (40, 50), (45, 62).
Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is
grams/cubic meter.
Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is 19.5 grams/cubic meter.
What is the humidity?The actual vapor density or humidity can be determined from the relative humidity value and the saturation vapor density.
The formula that relates the actual vapor density or humidity, the relative humidity, and the saturation vapor density is given below:
relative humidity = (actual vapor density / saturation vapor density) x 100%Hence, the actual vapor density can be calculated as follows:
Actual vapor density or humidity = relative density * saturation vapor density / 100
From the graph;
saturation vapor density at 30°C = 30 g/cm³
relative humidity = 65%
Humidity = 65 * 30 / 100
Humidity = 19.5 g/cm³
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A bike rider accelerates constantly to a velocity of 7.5m/s during 4.5s. The bike's displacement is 19m. What was the initial velocity of the bike?
The initial velocity of the bike was 3.75 m/s.
What was the initial velocity of the bike?The initial velocity of the bike is determined by examining the displacement and the time elapsed. The equation for displacement is displacement = initial velocity (m/s) x time (s). Thus, the initial velocity can be calculated by rearranging the equation, initial velocity = displacement (m) / time (s).In this case, the displacement is 19m and the time is 4.5s. Thus, the initial velocity can be calculated by plugging in the values to the equation, initial velocity = 19m / 4.5s. This evaluates to 4.22m/s. This means that the bike rider's initial velocity was 4.22m/s before accelerating to the velocity of 7.5m/s in 4.5s.To break it down, the bike rider was initially travelling at 4.22m/s and then accelerated constantly to a velocity of 7.5m/s in a period of 4.5s. The resulting displacement was 19m. This can all be determined using the equation displacement = initial velocity x time. By rearranging the equation and plugging in the values, we can determine the initial velocity of the bike as 4.22m/s.To learn more about The initial velocity refer to:
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At a sports car rally, a car starting from rest accelerates uniformly at a rate of 9.0m/s² over a straight-line distance of 100m. The time to beat is 4.5s.
a Does the driver do it?
b. If not, what must the acceleration be to do so?
Answer:
The driver does not do it. The acceleration must be greater than 9.0m/s² in order to beat the time of 4.5s. The acceleration must be calculated using the equation a = (d/t)², where a is the acceleration, d is the distance, and t is the time. In this case, a = (100/4.5)², which is equal to approximately 27.78m/s². Therefore, the acceleration must be greater than 27.78m/s² in order to beat the time of 4.5s.
Explanation:
A baseball is thrown straight upward with an initial speed of 35m/s. compute:
a) The maximum height reached by the ball b) The time taken to reach that height
c) Its velocity 30s after it is thrown,
a) Maximum height reached by ball = 376 m ; b) Time taken to reach that height is 21.5 s and c) Velocity 30s after it is thrown is -13.9 m/s
What is velocity?Velocity is vector expression of displacement that an object or particle undergoes with respect to the time.
Given:
y₀ = 0 m ; v₀ = 35 m/s
a) Find: y when v = 0 m/s.
As, v² = v₀² + 2a (y − y₀)
(0 m/s)² = (35 m/s)² + 2(-1.63 m/s²) (y − 0 m)
So, y = 376 m
Maximum height reached by ball, y = 376 m
b) Find: t when v = 0 m/s.
As, v = at + v₀
0 m/s = (-1.63 m/s²) t + 35 m/s
So, t = 21.5 s
Time taken to reach that height is, t = 21.5 s
c) Find: v when t = 30 s.
As, v = at + v₀
v = (-1.63 m/s²) (30 s) + 35 m/s
So, v = -13.9 m/s
Velocity 30s after it is thrown is, v = -13.9 m/s.
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in a generator as the magnet spins opposite poles of the magnet push the electrons in opposite directions this back and forth movement of electrons is called
Answer: In a generator, the back and forth movement of electrons as the magnet spins and opposite poles of the magnet push the electrons in opposite directions is called Alternating Current (AC).
Explanation:
Answer:
alternating current and direct current
Explanation:
yall some of these questions arent that hard, use common sense
Two balls with masses of 2.0kg and 6.0kg traveling at 12ms and 4.0 m/s, respectively. They have a head-on inelastic collision (not perfectly). The 2.0kg moves in the opposite direction with a speed of 8.0 m/s. a. Find the speed of the 6.0kg ball after the collision. B. Find the KE for each ball before and after the collision C. Find the amount of KE that is lost during the collision.
Answer:
Explanation:
A. To find the speed of the 6.0 kg ball after the collision, we can use the principle of conservation of momentum. The total momentum of the system before the collision is equal to the total momentum after the collision.
Momentum before collision = Momentum after collision
m1v1 + m2v2 = (m1 + m2)vf
where:
m1 = 2.0 kg (mass of first ball)
m2 = 6.0 kg (mass of second ball)
v1 = 12 m/s (velocity of first ball)
v2 = 4.0 m/s (velocity of second ball)
vf = final velocity of the combined balls after collision
Since the 2.0 kg ball moves in the opposite direction with a speed of 8.0 m/s after the collision, and the total mass of the two balls is 8.0 kg, we can write:
vf = (m1v1 + m2v2) / (m1 + m2) = (2.0 kg x (-8.0 m/s) + 6.0 kg x 4.0 m/s) / 8.0 kg = 2.33 m/s
So the speed of the 6.0 kg ball after the collision is 2.33 m/s.
B. To find the KE for each ball before and after the collision, we can use the formula:
KE = 0.5mv^2
where:
m = mass of the ball
v = velocity of the ball
For the 2.0 kg ball, the KE before and after the collision is:
KE before = 0.5 x 2.0 kg x (12 m/s)^2 = 72 J
KE after = 0.5 x 2.0 kg x (8.0 m/s)^2 = 32 J
For the 6.0 kg ball, the KE before and after the collision is:
KE before = 0.5 x 6.0 kg x (4.0 m/s)^2 = 48 J
KE after = 0.5 x 6.0 kg x (2.33 m/s)^2 = 20.44 J
C. To find the amount of KE that is lost during the collision, we can subtract the total KE after the collision from the total KE before the collision:
KE lost = KE before - KE after = (72 J + 48 J) - (32 J + 20.44 J) = 40.56 J
So the amount of KE that is lost during the collision is 40.56 J.
3) You observe a deep water (water depth> wave base) wave with a wavelength of 15 m and period of 3 seconds. What is the frequency and celerity of the wave?
Frequency:
Celerity:
4) what happens to wavelength as celerity increases? (see part 3)
The frequency of the wave is 0.33 Hz.
The celerity of the wave is wave is 4.95 m/s.
As the celerity of the wave increases, the wavelength increases.
What is the frequency of the wave?
The frequency of the wave is calculated by applying the following formula.
v = fλ
where;
f is the frequency of the waveλ is the wavelength of the wavef = 1 / T
f = 1 / 3 s
f = 0.33 Hz
The celerity of the wave is wave is calculated as follows;
v = fλ
v = ( 0.33 Hz ) x ( 15 m )
v = 4.95 m/s
λ = v / f
Thus, from the above equation as the celerity of the wave increases, the wavelength increases.
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The mid-ventral line divides the body into:
right and left.
front and back.
top and bottom.
north and south.
The mid-ventral line divides the body into right and left.
What is mid-ventral line?Mid-ventral line -
The intersection between the ventral skin and the median plane.
Given is that the mid-ventral line divides the body.
Midline refers to the imaginary line that divides the body into symmetrical left and right halves.
Therefore, the mid-ventral line divides the body into right and left.
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A car P was decelerating at 2.0 m/s^2 when it passes a stationary car Q, and speed was 20 m/s. At the same car Q from rest and accelerated at 2.5 m/s² along the same straight road.
(i) Find the time when car Q overtook car P.
(ii) How far was car Q from car P when car P came to a stop?
(i) The time when car Q overtook car P is 8 seconds.
(ii) The car Q was 32 meters away from car P when car P came to a stop.
What is the time when car Q overtook car P?(i) To find the time when car Q overtook car P, we can use the formula for relative velocity:
v = u + at
where;
v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.Let's call the time when car Q overtook car P as t. At that time, the velocity of car Q is equal to the velocity of car P, so:
20 = 0 + 2.5t
Solving for t, we get:
t = 8 seconds
(ii) To find the distance between the two cars when car P came to a stop, we can use the formula for distance traveled:
d = ut + (1/2)at^2
Let's call the distance between the two cars when car P came to a stop as d. Since car P was decelerating, its final velocity is 0 m/s. Substituting the known values into the formula, we get:
d = 20t + (1/2)(-2.0)(t^2)
d = 20 * 8 + (1/2)(-2.0)(8^2)
d = 160 - 128
d = 32 meters
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A spring oscillates with a frequency of 2.09 Hz. What is its period?
(Unit=s)
Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.
What is frequency ?Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.
The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the wavelength.
Given the time period of the wave = 2.09 Hz
then frequency = 1/2.09 Hz = 0.47 s.
Therefore, the time period of the wave is 0.47 seconds.
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why is interpretation an important part of meteorology
Strong interpretation is an important thing in meteorology. Because, analyzing the climate level in each area and the factors affecting it with their visual representation is very important in weather forecast.
What is meteorology ?Meteorology is a branch of science dealing with the weather in different regions. On interpreting data, forecasters are tasked with synthesizing available observations from multiple platforms (including surface observations, weather balloons, radar, and satellite), numerical guidance from computer model forecasts, scientific theory, and experience-based intuition to arrive at a forecast.
The forecast process is often collaborative, with teams of meteorologists routinely integrating new information into the forecast as the event approaches.
Increasingly, forecasters are also responsible for effectively communicating the forecast and its anticipated impacts upon life and property to various stakeholders, including the public.
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does the troposphere absorb more or less ultraviolet radiation than the thermosphere? why?
Aerosols in the troposphere, like dust and smoke, scatter UV-B radiation in addition to absorbing it, unlike clouds.
The effects of radiation on peopleOur cells' DNA may become damaged by radiation. Acute Radiation Syndrome (ARS) or Cutaneous Radiation Injuries are potential side effects of high radiation doses (CRI). The long-term effects of high radiation doses may include cancer.
Is radiation a long-term contaminant in the body?Certain radiation sources only briefly remain in the body. Some substances persist in the body permanently, such as seeds and radioactive medications. Yet as time passes, the radiation deteriorates and exhausts itself. You do temporarily become radioactive due to internal radiation.
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An 112 kg man drops from rest on a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. How fast was he going as he hit the water? (use units of measurement)
A bare helium nucleus has two positive charges and a mass of 6.64×10
−27
kg. What voltage would be needed to obtain the speed of 6.00×10
6
m/s ? 12.5×10
−2
V
0.0134×10
−4
V
120×10
−15
V
37.4×10
4
V 149×10
4
V 0.0803×10
2
V 239×10
−15
V 299×10
4
V
Answer:
Explanation:
The voltage needed to obtain the speed of 6.00 x 10^6 m/s for a bare helium nucleus is 149 x 10^4 V.
what is the formula for time dialation
Answer: γ = √(1 - v²/c²)
Explanation:
The formula for time dilation in Einstein's theory of special relativity is:
γ = √(1 - v²/c²)
The change in velocity divided by the time over which the change occurs is the
a) speed
b) average acceleration
c) velocity
d) displacement
An athlete exerts 3000 W of power when he takes 10.2 s to run the race. How much WORK does the athlete do?
Answer:
30600 J
Explanation:
Work = Power* Time
=30600 J
What is an isolated system
?
Answer:
In physical science, an isolated system is either of the following: a physical system so far removed from other systems that it does not interact with them. a thermodynamic system enclosed by rigid immovable walls through which neither mass nor energy can pass
Which of the following is a vital component to creating an atmosphere?
A. Meter
B. Rhythm
C. Pulse
D. All of these answers
A) The atmosphere shields life on earth from harmful ultraviolet (UV) radiation, insulates the planet to maintain a comfortable temperature, and prevents temperature extremes between day and night.
The convection that results from the sun's heating of the atmosphere's layers is what drives global air currents and weather patterns.
What makes up the environment most importantly?While most life on Earth requires oxygen, oxygen does not make up the bulk of the planet's atmosphere. About 78% of the gases in the Earth's atmosphere are nitrogen, 21% are oxygen, 0.9 % are argon, and 0.1 % are other gases.
What are the early atmosphere's four constituent parts?The initial atmosphere of Earth was deficient in free oxygen but abundant in methane, ammonia, water vapor, and the noble gas neon.
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Rocket powered sleds are used to test the responses of humans to acceleration. Starting from rest, one sled can reach a speed of 444m/s in 1.80s and can be brought to a stop again in 2.15s.
a. What is its acceleration when braking?
b. After braking for 1s what is the velocity?
Answer:
to explain the work on the other one you said its this A) The speed of the truck at the end of the 20.0m distance can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement. The initial velocity of the truck is 100m/s, the acceleration is 6.5m/s^2, and the displacement is 20.0m. Plugging in these values, we get v^2 = 100^2 + 2(6.5)(20.0). Solving for v, we get v = 36.6 km/h. B) The time elapsed can be calculated using the equation t = (v-u)/a, where t is the time elapsed, v is the final velocity, u is the initial velocity, and a is the acceleration. Plugging in the values, we get t = (36.6-100)/6.5, which gives us t = 3.03 seconds.
Explanation:
but for this problem
The acceleration when braking is -202m/s2. b. After braking for 1s, the velocity is 242m/s.
The acceleration when braking can be found by using the equation a = (Vf- Vi)/t, where Vf is the final velocity, Vi is the initial velocity, and t is the time. In this case, the initial velocity is 444m/s and the final velocity is 0m/s. The time is 2.15s. Plugging these values into the equation gives us a = -202m/s2. For the second question, we can use the equation Vf = Vi + at, where Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 444m/s, the acceleration is -202m/s2, and the time is 1s. Plugging these values into the equation gives us Vf = 242m/s.
t = 3.03 seconds.
Explanation:
Which equation would you use to solve the following problem: A train
decreases speed from 30 m/s to 20 m/s while in 20s. What is the
displacement of the train?
O vf = vo+a*t
O x = 1/2* (vf+vo) * t
O x= vo*t + 1/2 *a* t^2
O we don't have an equation for this problem yet
The kind of equation that we can use to solve the problem is; x = 1/2* (vf+vo) * t. Option B
What are the equations of motion?Th equations of motion has to do with the equations that we cam be able to apply so as to solve the equations that are for the uniformly accelerated motion.
In the case of the problem that we have in this question, we have been told that A train decreases speed from 30 m/s to 20 m/s while in 20s. The formula that can be used to get the displacement of the train is x = 1/2* (vf+vo) * t.
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A car slows from 22m/s to 3m/s with a constant acceleration of -2.1m/s². How long does it take?
Answer:
The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.
Explanation:
Answer:
The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time
Explanation:
Test you Two groups of students pull a box in two opposite directions as in the opposite figure. If the friction force between the box and the surface is F/4, then the box will move........
a) to the left with constant velocity
b) to the left with constant acceleration
c) to the right with constant velocity
d) to the right with constant acceleration
The box would move at a constant acceleration in the direction of F.
What direction will the box move?We know that the frictional force is the force that opposes the motion of an object. In this case, we can see that the image is not shown but we can be able to discuss the scenario in a general way.
Now is the force is about F/4 that means that it is less than the applied force and that the object would move in the first place. The direction in which the object would move would now depend on where the force F is directed.
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A land yacht is a low mass three-wheeled wind-powered vehicle with a sail. Suppose you are in the desert, observing a land yacht race. Consider your location to be the origin. When a particular land yacht passes you, it is traveling 8 m/s in the −z direction. If the mass of the vehicle plus driver is 188 kg, and the net force on the vehicle remains constant at ‹ 0, 0, −26 › N, what is the position of the yacht 29 seconds after it passes you?
The position of the yacht 29 seconds after it passes you is 290.87 m.
What is the acceleration of the yatch?The acceleration of the yatch is calculated by applying Newton's second law of motion as shown below.
F = ma
a = F / m
where;
F is the applied forcem is the mass of the yatcha is the accelerationa = ( 26 N ) / ( 188 kg )
a = 0.14 m/s²
The distance travelled after 29 seconds is calculated as follows;
s = vt + ¹/₂at²
where;
v is the speed of the yatcht is the time of motiona is accelerations = ( 8 m/s x 29 s ) + ¹/₂(0.14)(29)²
s = 290.87 m
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Determine the normal boiling point of chloroform if its heat of vaporization is 31.4 kJ/mol and the vapor pressure is 190 mmHg at 25°C
Vapor pressure (or vapour pressure in English-speaking countries other than the US; see spelling differences) or equilibrium vapor pressure.
What is Vapor pressure?The equilibrium vapor pressure is an indication of a liquid's thermodynamic tendency to evaporate. It relates to the balance of particles escaping from the liquid (or solid) in equilibrium with those in a coexisting vapor phase.
A substance with a high vapor pressure at normal temperatures is often referred to as volatile. The pressure exhibited by vapor present above a liquid surface is known as vapor pressure.
As the temperature of a liquid increases, the attractive interactions between liquid molecules become less significant in comparison to the entropy of those molecules in the gas phase, increasing the vapor pressure.
Therefore, Vapor pressure (or vapour pressure in English-speaking countries other than the US; see spelling differences) or equilibrium vapor pressure.
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how are neutral atoms different than atoms that are positively charged????
Neutral atoms have an equal number of protons and electrons, which means their overall electric charge is zero. On the other hand, atoms that are positively charged, also known as cations, have lost one or more electrons and thus have a net positive charge. The loss of electrons changes the number of positive charges (protons) and negative charges (electrons) within the atom, altering its chemical and physical properties. The difference in charge also affects how these atoms interact with other atoms and molecules, leading to differences in reactivity and behavior.
What velocity must a car with a mass of 1370kg have in order to have the same momentum as a 2280kg pickup truck traveling at 21m/s to the east
The velocity of the car along east direction must be 34.94 m/s.
What is momentum?In physics momentum of any object can be defined as product of velocity and mass. As velocity is a vector quantity, momentum is also a vector quantity. So, to define momentum both magnitude and direction are required. SI unit of momentum is kg-m/s.
Mass of the car = 1370 kg.
Mass of the pickup truck a = 2280 kg
Momentum of the pickup truck along east = 2280 kg × 21 m/s
= 47880 kg-m/s.
Hence, velocity of the car along east direction = (47880/1370) m/s
= 34.94 m/s.
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What is the specific heat capacity of a silver medal if 55.0 grams of the metal absorbs 197.9 joules of heat and the temperature rises 15°C
The specific heat capacity of silver is 0.235 J/g°C.
What is the specific heat capacity of a silver medal?The theory used in this question is the specific heat capacity equation, which states that the amount of energy required to raise the temperature of an object is proportional to the mass, specific heat capacity, and change in temperature.
The equation is Q = mcΔT, where Q is the amount of energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Explanations given below
Calculate the specific heat capacity of silver by dividing the energy absorbed (197.9 J) by the mass of the silver (55.0 g) and the temperature rise (15°C).
Divide 197.9 J by 825 g°C (55.0 g * 15°C).
(197.9 J) / (55.0 g * 15°C) = 0.235 J/g°C
The result is 0.235 J/g°C, which is the specific heat capacity of silver.
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A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head-on collision with a 14.0 kg raft moving to the right at 16.0 m/s. After the collision, the raft moves to the left at 14.4 m/s. What is the velocity of the canoe after the collision?
According to the law of conservation of momentum, the velocity of the canoe after the collision will be 17.79 meters per second.
What is the law of conservation of momentum?The law of conservation of momentum states that the momentum of the system of objects remains constant before and after the collision unless an external force is applied.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where, m₁ is the mass of one object and m₂ is the mass of second object,
u₁ and u₂ are initial velocities of object one and two,
v₁ and v₂ are the final velocities of object one and two.
16 × 12.5 + 14 × 16 = 12.5 × v₁ + 14 × 14.4
200 + 224 = 12.5v₁ + 201.6
424 = 12.5v₁ + 201.6
424 - 201.6 = 12.5v₁
222.4 = 12.5v₁
v₁ = 222.4/ 12.5
v₁ = 17.79 m/s
Therefore, the velocity of the canoe after the collision will be 17.79 meters per second.
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