Pakistan scored 270 runs and fell short of India's score by 10%. How much did

India score?

**Answer:**

India score 290 more than pakistan

**Step-by-step explanation:**

India score 20 more

India score is

= 270/90 x 100

= 300 runs

= 270/90 x 100

= 300 runs

Dana believes that she needs to study for at least 14 hours to be prepared for her monthly accounting test. If she can study for 4 hours per day, what is the minimum number of days that she should allow to study for the test?

4 days minimum

This is because 4x4 is 16, but it can’t be 3 since 4x3 is only 12.

This is because 4x4 is 16, but it can’t be 3 since 4x3 is only 12.

The Apollo space program lasted from 1967 until 1972 and included 13 missions.The missions lasted from as little as Z hours to as long as 30ours.The duration of each flight is listed below. 9 195 241 295 142% 142% 147 a.Expain why the flight times b.Find Mean and the Median of flight times c.Find range and the standard deviation of flight times

The **mean** and the **median** based on the information given will be 166.08 and 195.

It should be noted that the **mean** is also the **average**. It's gotten by adding all the numbers and dividing by 13. This will be 166.08.

The **median** is simply the middle number. This will be 195.

The **range** will be:

= 301 - 7

= 294

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What is the discount and sale price of a $300 item that has been discounted at 10%?

Answer:

Discount: $30 off

New Sale Price: $270

Step-by-step explanation:

$300*10% =

30

$300-30=

$270

or

$300*.1=

30

$300-30=

$270

Imogen buys some sandwiches costing £3.50.

She has a 20% off coupon.

How much discount will Imogen receive?

K

4

£0.7

Explanation:

3.50 x 0.2 = 0.7

Explanation:

3.50 x 0.2 = 0.7

As seen in the diagram below, Shandra is building a walkway with a width of feet

to go around a swimming pool that measures 8 feet by 6 feet. If the total area of the

pool and the walkway will be 168 square feet, how wide should the walkway be?

The **walkway** should be about **2.57feet**.

**What is the total surface area?**

The total surface area of the building is the sum of the total faces of an object contains.

The formula is expressed as:

**TSA = 2(lw + wh + lh)**

where,

l is the length ,w is the width , h is the height

**Calculation**

Given the following parameters

TSA = 168 square feet

length = 8 feet and Height = 6 feet

Required

Width of the walkway, Substitute the given values in the formula

168 = 2(lw + wh + lh)

84 = (8(6) + 6w + 8w)

84 = 48 + 14w

4w = 84 - 48

14w = 36

w = 2.57feet

The **walkway** should be about **2.57feet**.

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what is the absolute value of -45/6. I need serious help

**Answer:**

[tex]\frac{15}{2}[/tex]

**Step-by-step explanation:**

The absolute value of a number is just its distance from zero. In other words, if it's negative, the absolute value would make the number positive. This makes the absolute value [tex]\frac{45}{6}[/tex]. Now, reduce to get[tex]\frac{15}{2}[/tex].

The graph of the function f(x) = (x - 3)(x + 1) is shown.

Ty

-10-8-6

10

8

6

-6

8

-10-

6

10

X

Which describes all of the values for which the graph is

positive and decreasing?

O all real values of x where x < -1

O all real values of x where x < 1

O all real values of x where 1
O all real values of x where x > 3

**Answer:**

all real values of x where x < -1

**Step-by-step explanation:**

See attached graph.

The difference of the square of a number and 9 is equal to 8 times that number. Find the positive solution.

[tex]x {}^{2} - 9 = 8x \\ x {}^{2} - 8x - 9 = 0 \\ x = \frac{ - ( - 8) + \sqrt[]{( - 8) {}^{2} - 4(1)( - 9)} }{2( {1}^{}) } [/tex]

[tex]x = \frac{8 + \sqrt{64 + 36} }{2} = \frac{8 + \sqrt{100} }{2} = \frac{8 + 10}{2} = 9[/tex]

**Answer: x = 9**

**Step-by-step explanation:**

The **difference** of the **square** of a number **and 9** is equal to **8 times** that **numbe**r. Find the positive solution.

let x = a number

[tex]x^2-9=8x\\x^2-8x-9\\(x-9)(x+1)\\x-9 = 0\\x=9\\x+1=0\\x=-1[/tex]

taking only the positive solution, we get x = 9

Teacher increases spatial awareness for children as they use position words and provide experience through mapping and manipulating shapes.

a. True

b. False

It is **true** teachers can increase **spatial** **awareness** as they use position words or implement **mapping** and shape **manipulation**.

This refers to the ability to understand the **position** of one's body in relation to **space** and other objects as well as understanding how **location** and **movement** work.

In children **spatial** **awareness** can be increased through:

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Super confused need help

Round off to the nearest 100

Please help me answer this question, 20 POINTS!

Buns,cost 40p each. Cakes cost 55p each. I spend exactly £4.35 on buns and cakes.

How many of each did I buy?

**It's 4 buns & 5 cakes**

Hope my explanation to the other one helps, if not, you can draw them; while following the steps & you may get it better.

E.g draw a box for the bun & a circle for the cake, then, adding them up to get the 95p. Also, you keep taking away from 435p

Please help with this geometry question!

**Answer:**[tex]\sqrt{303.51}[/tex]

**Step-by-step explanation:**

The difference in the radii of the two circles is [tex]4.3-1.8=2.5[/tex] inches.

Since the tangent has a length of 2.5 inches, by the Pythagorean theorem, the required distance is

2. Grade points are assigned as follows: A = 4, B = 3, C = 2, D = 1, and F = 0. Grades are weighted according to credit hours. If a student receives one A in three-credit class, one D in three-credit class, three B in three-credit class and two C in one-credit class, what is the student’s grade point average?

Based on the **student's** **grades**, and the **credit hours,** their **grade point average** is **2.60.**

First, find the **grade points earned:**

= (4 x 3) + (1 x 3) + (3 x 3) + (2 x 1)

= 12 + 3 + 9 + 2

**= 26**

The **GPA **is:

=Grade points earned / total number of credits

= 26 / (3 + 3 + 3 + 1)

= 26 / 10

**= 2.6 **

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A = {1, 2, 6}

B = {x|x is an odd whole number less than 8}.

Find An B.

**Answer:**

A∩B = { 1 }

**Step-by-step explanation:**

**Consider the sets** :

A = {1, 2, 6}

B = {x ;where x is an odd whole number less than 8}

Suppose the numbers of B are natural numbers (not integers).

Then

B = {1 , 3 , 5 , 7}

**We obtain** :

A = {1, 2, 6} and B = {1 , 3 , 5 , 7}

*The intersection of A and B or the set A∩B :*

*is the set of the common numbers of A and B*.

Then

A∩B = { 1 }

The set** A intersection B**(or, A∩B) for the given set A and set B exists** {1}. **

"The set A intersection B(or, A∩B) exists described as the set composed of all elements that belong to** both A and B**".

The intersection of a set A with a B exists the set of elements that exist in both sets A and B. The intersection exists represented as **A∩B.**

The intersection of** two mathematical objects** exists where they **overlap. **For geometric objects, the intersection exists as a point or group of points where the **objects cross.**

For **numerical **or **non-numerical sets**, the intersection exists every number or object the two sets contain in common.

Given: A = {1, 2, 6}

B = {x | x is an odd whole number less than 8}.

From the above information, we get

⇒ B = {1, 3, 5, 7}

If A = {1, 2, 6} and B = {1, 3, 5, 7}

then **A∩B = {1, 2, 6} ∩ {1, 3, 5, 7}**

**A∩B = {1}**

Therefore, the correct answer **A∩B** exists **{1}.**

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PLEASE IF ANYONE CAN HELP I HAVE 35 MINUTES LEFT 1-8 ANSWERS ONLY WILL DO THANK YOU

**Answer:**

1. x=2 2.

y=1

**Step-by-step explanation:**

Im sorry I TRIED :(

What is the domain and range of the quadratic function given by the equation /(x) = 2(x-4)] - 2

The **domain **of the **function **is the set of all real numbers and the **range** of the** function **is the set of all values **greater than **-2

The **function **is given as:

f(x) = 2(x -4)^2 - 2

A **quadratic function** can take any real number as its input.

So, the **domain **of the **function **is the set of all real numbers

The **vertex **of the above function is:

Vertex = (4, -2)

And the **leading coefficient **is:

a = 2

The y value of the **vertex** is;

y = -2

Because the value of a is positive, then the **vertex **is a **minimum**.

This means that the **range** of the** function **is the set of all values **greater than **-2

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WHAT TWO EQAUL NUMBERS ADD TO THE EVEN NUMER 40

**Answer:**

20

**Step-by-step explanation:**

20+20=40

A rectangle has a length of x-8 and a width of x-9. Which equation below describes the perimeter, P, of the rectangle in terms of x?

a. P=x² - 17x+72

b. P=x-17

c. P = 2x-17

d. P = 4x - 34

*show your work*

**Answer:**

d.

**Step-by-step explanation:**

Given a length [tex]l[/tex] and a width [tex]w[/tex], we can express the perimeter of a rectangle as [tex]2(l+w)[/tex].

Therefore the perimeter [tex]P[/tex] can be expressed as

[tex]2\times[(x-8)+(x-9)]\\=2\times(2x-17)\\=4x-34[/tex]

If two points on a line are A(10, −3) and B(12, 9), the rise is __________, and the run is __________, so the slope of the line is __________.

The rise is the **difference in y-coordinates**:

The run is the **difference in x-coordinates**:

The slope is the **quotient of rise over run**:

========================

If two points on a line are A(10, −3) and B(12, 9), the rise is 12, and the run is 2, so the slope of the line is 6.

Is this Network a HAMILTONIAN Circuit? If so write the path.

The path of the given **Hamiltonian** **diagram **is A, E, B, C, D, F. See explanation below.

A **Hamiltonian path**, also known as a traceable path, is one that visits each vertex of the graph **precisely once. **

A traceable graph is one that contains a **Hamiltonian** path.

Hence, the path is given as;

A, E, B, C, D, F

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Select the correct answer.

Which of the nets below will make a closed cube?

Mariatu Yakubu

The **net **that represents a **cube** is (b) net b

A **cube **has 6 faces

This means that the **net** must have 6 faces

For a **net **to represent a **cube**, there must be four **adjacent faces**

And 2 two **adjacent faces**

Where

One of the twoThe **net** that represents the above scenario is net (b)

Hence, the **net **that represents a **cube** is (b) net b

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Sharon is planting tulip

bulbs in her garden. In the

catalog she sees a disclaimer that there is a 1/15 probability that a bulb will not flower. If Sharon plants 90 bulbs, how many tulips can she expect to see in her garden?

**Answer:**

84 flowers.

**Step-by-step explanation:**

We must multiply 90 by 1/15 to get 6 bulbs that will not flower. 90-6 is 84.

Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$

When [tex]n=0[/tex], we have

[tex]5^{3^0} + 1 = 5^1 + 1 = 6[/tex]

[tex]3^{0 + 1} = 3^1 = 3[/tex]

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for [tex]n=k[/tex], that

[tex]3^{k + 1} \mid 5^{3^k} + 1[/tex]

Now for [tex]n=k+1[/tex], we have

[tex]5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)[/tex]

so we know the left side is at least divisible by [tex]3^{k+1}[/tex] by our assumption.

It remains to show that

[tex]3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1[/tex]

which is easily done with Fermat's little theorem. It says

[tex]a^p \equiv a \pmod p[/tex]

where [tex]p[/tex] is prime and [tex]a[/tex] is any integer. Then for any positive integer [tex]x[/tex],

[tex]5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3[/tex]

Furthermore,

[tex]5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3[/tex]

which goes all the way down to

[tex]5^{3^k} \equiv 5 \pmod 3[/tex]

So, we find that

[tex]\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3[/tex]

QED

Company TYK forecasts that it will begin paying dividends seven years from now, at which point dividends are $1 per share. Thereafter, dividends are expected to growth at a constant rate of 6% per year. The discount rate for TYK is 10%. How much would you pay for one share in Company TYK?

14.11 is the price of one share in the company TYK.

How much would you pay for one share in Company TYK?Given:

Company TYK forecasts that it will begin paying dividends seven years from now, at which point dividends are $1 per share.Dividends are expected to grow at a constantFind:

How much would you pay for one share in Company TYK?Solution:

The dividend is the amount paid to the shareholders for their investment in the company.

Dividend at end of 7th year = $1 per share (given)

dividend expected growth** rate** = 6% (given)

the dividend will be paid from the end of seven years.

So find the price of the share at the end of the 6th year.

price at the end of the 6th year

= Dividend at the 7th year/discount **rate ** growth **rate**

= 1/(10%-6%) = 1/4% = 25

price of the share at the end of the 6th year is $25

discount price 10% (given)

current price share = 25/(1+10%)^6

= 25/(1.1)^6

= 25/1.77

= 14.11

The current price of the share is $ 14.11

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The following contingency table gives the results of a sample survey of Sowetan male and female respondents regarding their preferred mobile phone service provider.

What is the probability of selecting a respondent who does not prefer Cell C?

a.

0.2250

b.

0.50

c.

0.3750

d.

0.65

e.

0.7750

The **probability **of selecting a respondent who **does not** **prefer **Cell C is 0.775

The complete question is in the attached image

From the attachment, we have

Prefer cell C = 90

Total = 400

So, the number of **respondents **that **do not **prefer cell C is

Do not = 400 - 90

Do not = 310

The **probability **is then calculated as:

P = 310/400

Evaluate

P = 0.775

Hence, the **probability **of selecting a respondent who **does not** **prefer **Cell C is 0.775

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The coconut milk is in a can but he doesn’t know how much the can holds.

The can is 12 cm high and the diameter is 8 cm.

Using the formula V = π r2 h, work out how much coconut milk is in the can.

Use 3 as a value for π.

Give your answer using the correct units.

Here is the solution for this question.

Given f of x is equal to 1 over the quantity x minus 3 end quantity and g of x is equal to the square root of the quantity x plus 3 end quantity comma what is the domain of f (g(x))?

[–3, ∞)

[–3, 6) ∪ (6, ∞)

(–∞, 3) ∪ (3, ∞)

ℝ

The **domain **of the **composite function** is given as follows:

[–3, 6) ∪ (6, ∞)

What is the composite function of f(x) and g(x)?The composite function of f(x) and g(x) is given as follows:

[tex](f \circ g)(x) = f(g(x))[/tex]

In this problem, the **functions **are:

The** composite function** is of the given functions f(x) and g(x) is:

[tex]f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}[/tex]

The **square root** has to be** non-negative**, hence the **restriction **relative to the square root is found as follows:

[tex]x + 3 \geq 0[/tex]

[tex]x \geq -3[/tex]

The **denominator **cannot be zero, hence the **restriction **relative to the denominator is found as follows:

[tex]\sqrt{x + 3} - 3 \neq 0[/tex]

[tex]\sqrt{x + 3} \neq 3[/tex]

[tex](\sqrt{x + 3})^2 \neq 3^2[/tex]

[tex]x + 3 \neq 9[/tex]

[tex]x \neq 6[/tex]

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the **domain **is:

[–3, 6) ∪ (6, ∞)

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PLEASE HELP EDGE2022 Which inequality is represented by the graph?

y ≥ –2(x + 1)2 + 5

y ≤ –2(x + 1)2 + 5

x ≥ –2(y + 1)2 + 5

x ≤ –2(y + 1)2 + 5

The **inequality graphed **is the one in the first option.

On the **graph **we can see a solid **parabola**, the **parabola **opens downwards, and we can see that the **vertex **of the **parabola **is on the point (-1, 5).

And the shaded region is above the **parabola**.

Then the **inequality **is of the form:

y ≥ parabola.

By knowing where is the **vertex**, we know that:

parabola = -a*(x + 1)^2 + 5

Then the correct option is the **first one.**

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Ross Martin arrived at the following tax information gross salary 56,145 interest earnings 205 dividend income 65 standard deduction 12,000 itemized deductions 11,250 adjustments to income 1200 what amount with Ross report as taxable income income

The amount that Ross report as **taxable** **income** will be $31965.

**Taxable income** refers to the base upon which an income tax system imposes the tax.

In other words, the **taxable income** is the income over which the government imposed tax. It includes some or all items of income and is reduced by expenses and other **deductions****.**

From the information:

Gross salary = $56,145

Interest earnings = $205

Dividend income = $65

**Standard** deduction = $12,000

Itemized deductions = $11,250

Adjustments to **income** = $1,200

The **taxable income** is given by:

= Gross salary + Interest earnings + Dividend income - Standard deduction - Itemized deductions - Adjustment to income

= 56145 + 205 + 65 - 12000 - 11250 - 1200

= $31965

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Simplify:

x² + 3x + 2 /x² - 4x - 5

x² + 7x + 12 / x²-3x - 28

[tex]\\ \rm\Rrightarrow \dfrac{x^2+3x+2}{x^2-4x-5}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x^2+2x+x+2}{x^2-5x+x-5}[/tex]

[tex]\\ \rm\Rrightarrow {(x+2)(x+1)}{(x-5)(x+1)}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x+2}{x-5}[/tex]

And

[tex]\\ \rm\Rrightarrow \dfrac{x^2+7x+12}{x^2-3x-28}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x^2+4x+3x+12}{x^2-7x+4x-28}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{(x+4)(x+3)}{(x-7)(x+4)}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{x+3}{x-7}[/tex]

Find the Slope of the line that passes through (5, -10) and (5, -4)A. - 14/10B. 10/14C. 0D. Undefined
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