Given that yx is a diameter of V, find mZVX if mYVZ=(15r -1)", mWVX =(8x- 2).mUVW =(7x +15).
and mYVU = 3x + 5).
A 32
B 45°
C 70
D. 134

Answer:

[tex] -\frac{9}{2} [/tex]

Step-by-step explanation:

Rate of change of x and y can be calculated using the following formula and using any two given pair of values from the table:

Rate of change = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Using (-12, 60) and (-6, 33).

Where,

[tex] (-12, 60) = (x_1, y_1) [/tex]

[tex] (-6, 33) = (x_2, y_2) [/tex]

Plug is the values

Rate of change = [tex] \frac{33 - 60}{-6 -(-12)} [/tex]

Rate of change = [tex] \frac{-27}{6} [/tex]

Simplify

Rate of change = [tex] \frac{-9}{2} [/tex]

Rate of change = [tex] -\frac{9}{2} [/tex]

Answer:

8

Step-by-step explanation:

Answer:all of them

Step-by-step explanation:

Hope this helps. Please mark brainliest

Answer: 20

let the number be x

1/4 x = 5

x=5*4

x=20

Answer:

x=20

Step-by-step explanation:

[tex]\frac{1}{4}x=5\\x=20[/tex]

divide [tex]\frac{1}{4}[/tex] on both sides, which gives you 20.

Answer:

Exponential Function

Step-by-step explanation:

y values increase by x4

Answer:

exponential function

the ans is b

Answer:

The answer is

[tex]2 {x}^{2} + 3x - 1 = 0[/tex]

Why? Below I explain

Step-by-step explanation:

That formula has three variables a, b and c.

So, a = 2, b = 3 and c = -1

Because the formula is written like

[tex] \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} [/tex]

Hi there!

We are given two ordered pairs which are:

If you are curious how do I get these ordered pairs, they come from those two big circles or dots. x and y make relation and can be written as (x,y).

1. Find the slope

[tex] \large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]

Since we have two given points, we can substitute them in the formula.

[tex] \large{m = \frac{4 - 0}{5 - 0} } \\ \large \boxed{m = \frac{4}{5} }[/tex]

2. Form an equation.

[tex] \large \boxed{y = mx + b}[/tex]

Where m = slope and b = y-intercept. We substitute m = 4/5.

[tex] \large{y = \frac{4}{5} x + b}[/tex]

Next thing to remember is that when the graph intersects an origin point, b-term or y-intercept would be 0. Therefore b = 0 since the graph intersects (0,0).

[tex] \large \boxed{y = \frac{4}{5} x}[/tex]

3. Answer

Answer:

Step-by-step explanation:

A and B are correct!

For part C, just multiply the dimensions given to you by four.

For part D, the answer would be 4 x 4 x 4 which is 264

Answer:

hope it's helpful for you

Answer:

Ok where only looking for junior so heres the stats for that

Morning:5

Afternoon:8

Evening:16

so if we add that up

5+8+16=29

and 8 like after noon so

8/29 as a percent 27.5862%

Hope This Helps!!!

Answer:

Step-by-step explanation:

equation

area(base1 + base2)

Answer:

X= -2. Y= 4.

Step-by-step explanation:

Answer:

$24.00=$21.50+r*$.50

Step-by-step explanation:

total cost= entrance fee + r (number of rides) * $0.50 (cost of rides)

$24.00=$21.50+r*$.50

2.50=r*.50

2.5/.5=r

r=5

Answer:

[tex]f(12) = 323.02[/tex]

Step-by-step explanation:

Given

[tex]f(-2.5) = 9[/tex]

[tex]f(7) = 91[/tex]

[tex]f(12) = 16.7 * 1.28^{12[/tex]

Required

[tex]f(12)[/tex]

An exponential function is:

[tex]f(x) = ab^x[/tex]

[tex]f(-2.5) = 9[/tex] implies that:

[tex]9 = ab^{-2.5}[/tex]

[tex]f(7) = 91[/tex] implies that:

[tex]91 = ab^7[/tex]

Divide both equations

[tex]91/9 = ab^7/ab^{-2.5}[/tex]

[tex]91/9 = b^7/b^{-2.5}[/tex]

Apply law of indices

[tex]91/9 = b^{7+2.5}[/tex]

[tex]10.11 = b^{9.5}[/tex]

Take 9,5th root of both sides

[tex]b = 1.28[/tex]

So, we have:

[tex]9 = ab^{-2.5}[/tex]

[tex]9 = a * 1.28^{-2.5}[/tex]

[tex]9 = a * 0.54[/tex]

[tex]a = 9/0.54[/tex]

[tex]a = 16.7[/tex]

f(12) is calculated as:

[tex]f(x) = ab^x[/tex]

[tex]f(12) = 16.7 * 1.28^{12[/tex]

[tex]f(12) = 323.02[/tex]

Answer:

[tex]P(x < -778) = 0[/tex]

Step-by-step explanation:

Given

[tex]\bar x = 48673[/tex]

[tex]\sigma^2 = 11282880[/tex]

[tex]n = 143[/tex]

Required

[tex]P(x <- 778)[/tex]

First, we calculate the z score

[tex]z = \frac{x}{\sqrt{\sigma^2}/n}[/tex]

So, we have:

[tex]z = \frac{-778}{\sqrt{11282880}/143}[/tex]

[tex]z = \frac{-778}{3359.0/143}[/tex]

[tex]z = \frac{-778}{23.49}[/tex]

[tex]z = -33.12[/tex]

So:

[tex]P(x < -778) = P(z < -33.12)[/tex]

From z score probability, we have:

[tex]P(x < -778) = 0[/tex]

Answer:

All real number greater than equal to zero.

Step-by-step explanation:

The function is given by

[tex]f(x) = \frac{4}{5}\sqrt x[/tex]

The domain is defined as the input values so that the function is well defined.

here, the values of x should be all real number and zero also.

So, the correct option is  (d).

Answer:

D

Step-by-step explanation:

Answer:

17 + 123 (4 - 1) + (36 / 18) 52 =

17 + 123 x 3 + 2 x 52 =

17 + 369 + 104 =

17 + 473 =

490

Step-by-step explanation:

hope this helps! i made up everything so i hope its okay!

We are given the system of equations:

[tex] \large{ \begin{cases} y = 2x - 3 \\ y = - x + 3 \end{cases}}[/tex]

Since both are y-isolated equation, we can combine them together.

[tex] \large{2x - 3 = - x + 3}[/tex]

Isolate and solve for x-term.

[tex] \large{2x - 3 + 3 + x = - x + 3 + x + 3} \\ \large{2x + x = 6 \longrightarrow 3x = 6} \\ \large{ \frac{3x}{3} = \frac{6}{3} \longrightarrow \boxed{ \red{x = 2}}}[/tex]

Next, we find the value of y. Simply substitute x = 2 in one of these equations. The less coefficient values, the faster and better. I will substitute x = 2 in y = -x+3. You can substitute x = 2 in y = 2x-3 if you want but the result would be the same.

[tex] \large{y = - x + 3}[/tex]

Substitute x = 2 in the equation.

[tex] \large{y = - 2 + 3} \\ \large \boxed{ \blue{y = 1}}[/tex]

Therefore - when x = 2, y = 1. We can write in coordinate point or ordered pair as (2,1) from (x,y).

Answer

Answer:

Here the answer is given as follows,

Step-by-step explanation:  

The last three parts are coming with a question mark, so can't answer those parts. post the image or write it properly  

a) Every student is taking at least one course.  

[tex]\forall x \exists y T(x,y)[/tex]  

So for all x, there is a y such that T(x,y) is a true will be given by the above statement  

b) There is a part-time student who is not taking any math courses.  

[tex]\exists x \forall y [A(x) \Lambda (M(y) \rightarrow ~T(x,y))][/tex]

Answer:

z ( max)  =  2000 $

x₁  =  500       x₂ = 0     x₃  = 0

Step-by-step explanation:

                         cutting       sewing    finishing  Profit $

Jean1   (x₁ )           8                 12              4             4

Jean2  (x₂ )          12                18              8              4.5

Jean3  (x₃ )          18                24            12              6

Time available  5200          6000        2200

b) Formulation of a linear programming problem:

Objective Function  z

z  =  4*x₁   +  4.5*x₂  + 6*x₃        to maximize

Constrains:

Constrain 1

Available cutting time  5200 minutes

8*x₁  +  12*x₂  +  18*x₃   ≤  5200

Constrain 2:

Available sewing  time  6000 minutes

12*x₁  +   18*x₂   +  24*x₃    ≤  6000

Constrain 3:

Available finishing time  2200 minutes

4*x₁   +   8*x₂   +  12*x₃    ≤ 2200

General constraints:

x₁    ≥ 0            x₂   ≥ 0             x₃  ≥  0     all integers

After 6 iterations the optimal solution is:

z ( max)  =  2000 $

x₁  =  500       x₂ = 0     x₃  = 0

We can see in the model that times required to make jean 2  and jean 3

are much bigger than jean 1 and but the price of jean 2 is only 0.5 $ above the price of jean 1 and jean 3 is only 2 $.

Step-by-step explanation:

[tex] {x}^{2} + 12x - 3 = 16[/tex]

[tex] {x}^{2} + 12x = 19[/tex]

[tex] {x}^{2} + 12x + 36 = 19 + 36[/tex]

[tex](x + 6) {}^{2} = 55[/tex]

Answer:

[tex]y = -4x + 2[/tex]

Step-by-step explanation:

Required

Determine the equation

From the question, we understand that, it is parallel to:

[tex]4x + y -10 = 0[/tex]

This means that they have the same slope.

Make y the subject to calculate the slope of: [tex]4x + y -10 = 0[/tex]

[tex]y = -4x + 10[/tex]

The slope of a line with equation [tex]y =mx + c[/tex] is m

By comparison:

[tex]m = -4[/tex]

So, the slope of the required equation is -4.

The equation is then calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

Where:

[tex](x_1.y_1) = (2,-6)[/tex]

So, we have:

[tex]y = -4(x - 2) -6[/tex]

Open bracket

[tex]y = -4x + 8 -6[/tex]

[tex]y = -4x + 2[/tex]

Answer:

Therefore each suit cost $600 and each jean cost $199

Step-by-step explanation:

Let x represent the price of each suit and let y represent the price of each jeans.

Since 3 suits and 3 pairs of jeans cost $2397, this can be represented by the equation:

3x + 3y = 2397

Dividing through by 3:

3x/3 + 3y.3 = 2397/3

x + y = 799    (1)

Also, 8 suits and 11 pairs of jeans cost $6989, this can be represented by the equation:

8x + 11y = 6989      (2)

To find x and y, solve equation 1 and 2 simultaneously. Multiply equation 1 by 8 and subtract from equation 2 to get y:

3y = 597

y = $199

Put y = $199 in equation 1:

x + 199 = 799

x = $600

Therefore each suit cost $600 and each jean cost $199.

Step-by-step explanation:

the answer is in the above image

Answer:

3+x/10+x>8/10

Pat bought 5 pounds of apples.

(1) 1 pound of pears cost $0.5 more that 1 pound of apples.

If 1 pound of pears cost $1 and 1 pound of apples cost $0.5, then the cost of 5 pounds of apples is 5*0.5=$2.5. For $2.5 we can buy 2.5/1=2.5 pounds of pears.

If 1 pound of pears cost $1.5 and 1 pound of apples cost $1, then the cost of 5 pounds of apples is 5*1=$5. For $5 we can buy 5/1.5=10/3 pounds of pears.

(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples.

The cost of 5 pounds of apples is $5a (where a is the cost of 1 pound of apples). For $5a we can buy 5a/(1.5a)=5/1.5 pounds of pears. Sufficient.

Learn more about  total cost at:

https://brainly.com/question/25109150

#SPJ1

Given question is incomplete , the complete question is given below ,

Pat bought 5 pounds of apples. How many pounds of pears could he have bought for same amount of money?

(1) 1 pound of pears cost $0.5 more that 1 pound of apples

(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples