There are twelve shirts in my closet. Five are red, four are blue, and three are green. What is
the probability that I choose a red or blue shirt to wear tomorrow?
O 65%
0 75%
0 80%
60%
58%

Answer:

$2,981.67

Step-by-step explanation:

Answer:

Step-by-step explanation:

48+1=49

Answer:

T = 2.215

df = 7

Critical value = 2.364

Fail to reject the null

Step-by-step explanation:

Swimmer __Spandex __Speedo Fastskin__ d

1 __________31.1 _______29.1 __ 2

2_________ 28.9 ______30.4 __ -1.5

3_________ 31.4 ______ 32.0 __ - 0.6

4_________ 34.9 ______31.7 __ 3.2

5 _________27.7 ______28.2 __ - 0.5

6_________ 36.7 _____ 32.9 ___ 3.8

7 _________ 33.3 _____28.6 ___ 4.7

8_________ 30.8 _____26.2 ___ 4.6

The mean difference = Σd / n

2, - 1.5, - 0.6, 3.2, - 0.5, 3.8, 4.7, 4.6

μd = Σd / n = 15.7 / 8 = 1.9625

Sd = standard deviation of difference = 2.5065 (using calculator)

H0 : μd = 0

H1 : μd ≠ 0

The test statistic:

T = μd / (Sd/√n)

T = 1.9625 / (2.5065/√8)

T = 2.2145574

The degree of freedom, df = n - 1 = 8 - 1 = 7

Using a Pvalue calculator :

α = 0.05

Critical value, Tcritical = 2.364 (T distribution table)

Since Test statistic < Critical value

we fail to reject H0 ;

Answer:

68

Step-by-step explanation:

I did it on my test

The missing value in the table is 68. The correct answer would be option (B).

A linear relationship is a connection that takes the shape of a straight line on a graph between two distinct variables - x and y. When displaying a linear connection using an equation, the value of y is derived from the value of x, indicating their relationship.

The table shows the relationship between the number of faculty members and the number of students at a local school.

Faculty     Students

1                     17

2                   34

3                   51

4                    ?

The relationship between the number of faculty members and the number of students at the local school is that for every faculty member, there are 17 students.

Therefore, if there are 4 faculty members, we can find the number of students by multiplying 4 by 17, which gives us 68.

Thus, the missing value in the table is B. 68.

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Answer:

D. 750(0.75)ˣ

Step-by-step explanation:

Let the new brightness be L'. Since our initial brightness L₀ reduces by 25 %, we have that L' = L₀ - 25% of L₀

L' = L₀ - 0.25L₀

L' = 0.75L₀

Adding the second screen, the new intensity is L" = L' - 25 % of L'  

L" = L' - 0.25 L'

L" = 0.75L'.

Since L' = 0.75L₀,

L" = 0.75L' = 0.75(0.75L₀) = 0.75²L₀

Adding the third screen, the new intensity is L"' = L'' - 25 % of L''  

L'" = L" - 0.25 L"

L"' = 0.75L".

Since L" = 0.75L' = 0.75²L₀

L"' = 0.75L" = 0.75(0.75²L₀) = 0.75³L₀

So, we see a pattern here.

The intensity after x screens is L = (0.75)ˣL₀

Since L₀ = 750 lumens,

L = 750(0.75)ˣ

Answer:

It would take 10 hours for Casey to paint the room by himself.

Step-by-step explanation:

Given that Casey and Malik can paint a room in 6 hours if they work together, and if Malik were to work by himself, it would take him 4 hours longer than it would take Casey working by himself, to determine how long would it take Casey to paint the room by himself if Malik calls in sick the following calculation must be performed:

6 x 2 = 12

12 x 2 = 24

(24 - 4) / 2 = 10

Therefore, it would take 10 hours for Casey to paint the room by himself.

Options :

A.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded below the line

B.The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded above the line.

C. The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded below the line.

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Answer:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Step-by-step explanation:

The equation y > 3x – 8

Interpreting as a linear relation :

y > ax + b

Where, a = slope ; b = intercept

a = 3 ; that is a slope value of 3

b = -8 ; that is an intercept value of - 8

Since the inequality is >, a dashed line is used (dashed like is used for > and <) ; since we a have a greater than sign, the graph will be shaded above the dashed line.

Answer: The answer is D on edu 2021

Step-by-step explanation:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Answer:

[tex]P(\frac{A}{B'})[/tex]=0.111

Step-by-step explanation:

Given:

The probability of winning the first game is 10.1

The first game is won

The probability of winning the second game is 15

If the first is lost, the probability of winning the second game is 25

Solution:

[tex]P(B)=P(A)P(\frac{B}{A})+P(A')P(\frac{B}{A'})\\ =0.1(0.15)+(0.3)*0.25)\\P(B)=0.24 ------(1)\\P(\frac{A}{B})=\frac{P(\frac{B}{A})P(A) }{P(B)}\\ =\frac{0.15(0.1)}{0.24}\\ =0.0625 ------(2)\\P(B')=1-P(B)=0.76 ------(3)\\P(A)=P(B)P(\frac{A}{B})+P(B')P(\frac{A}{B'})\\0.1=0.24(0.0625)+0.76(p(\frac{A}{B'} ))\\P(\frac{A}{B'})=0.111[/tex]

Answer:

[tex]P(W_1/W_2')=0.1110[/tex]

Step-by-step explanation:

Probability of winning the first game be considering the given factors be, [tex]W_1=0.1[/tex]

Probability of winning the second game be considering the given factors be, [tex]W_2[/tex]= probability of winning the second game when the first game is won + probability of winning the second game when the first game is lost:

[tex]P(W_2)=P(W_1).P(W_2/W_1)+P(W_1').P(W_2/W_1')[/tex]

[tex]P(W_2)=0.1\times 0.15+0.9\times 0.25[/tex]

[tex]P(W_2)=0.24[/tex]

Hence the probability of losing the second game:

[tex]P(W_2')=1-P(W_2)[/tex]

[tex]P(W_2')=0.76[/tex]

Probability of winning the first game when the second game is won:

[tex]P(W_1/W_2)=\frac{P(W_2/W_1).P(W_1)}{P(W_2)}[/tex]

[tex]P(W_1/W_2)=\frac{0.15\times 0.1}{0.24}[/tex]

[tex]P(W_1/W_2)=0.0625[/tex]

Probability of winning the first game be considering the given factors, [tex]W_1[/tex]= probability of winning the first game when the second game is won + probability of winning the first game when the second game is lost:

[tex]P(W_1)=P(W_2).P(W_1/W_2)+P(W_2').P(W_1/W_2')[/tex]

[tex]0.1=0.24\times0.0625+0.76\times P(W_1/W_2')[/tex]

[tex]P(W_1/W_2')=0.1110[/tex]

[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]

[tex]\small\color{blak}{{\underline{\bold{ Find \:a X } } } }[/tex]

[tex]\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}[/tex]

[tex]\small\color{blak}{{\underline{\bold{ Find\:a\:m<QSR } } } }[/tex]

[tex]\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m<QSR=68°\:\:\:\: }}}}[/tex]

[tex]\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}[/tex]

The measure of angle QSR is 68 degrees.

Substitution means putting numbers in place of letters to calculate the value of an expression.

According to the given question.

m ∠TSQ = 15x

m ∠TSR = 173 degrees

m ∠QSR = 10x -2

Since,

m ∠TSR = m ∠TSQ + ∠QSR

Substitute the value of m ∠TSR, m ∠TSQ and m ∠QSR in the above expression.

⇒ [tex]173 = 15x + 10x - 2[/tex]

⇒ [tex]173 = 25x - 2[/tex]

⇒ [tex]175 = 25x[/tex]

⇒ [tex]x = \frac{175}{25}[/tex]

⇒ [tex]x = 7[/tex]

Again, for finding the value of angle QSR substitute the value of x in 10x - 2.

Therefore,

m ∠QSR = 10(7) - 2

⇒ m ∠QSR = 70 - 2

⇒ m ∠QSR = 68 degrees

Hence, the measure of angle QSR is 68 degrees.

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Answer:

No.

Step-by-step explanation:

y/x has to be the same number no matter what except at point (0 0) which it must also include for it to be a direct variation.

*y=2x+3 is not a direct variation because you can not write it as y/x=k where k is some constant number. If we were y=2x, then yes since y/x=2.

*You could also take two points and see if they are proportional. That is, you can see if y2/x2 gives the same value as y1/x1 where (x1,y1) and (x2,y2) are points on the line y=2x+3. This must work for every pair of points on the linear relation except at x=0 (where you would or should have y=0 if it is directly proportional).

Let's try it out. If x=1, then y=2(1)+3=5.

5/1=5

If x=2, then y=2(2)+3=7

7/2=3.5

As you can see 5 doesn't equal 3.5.

*For it to be a direct variation, it also must contain the point (0,0) and be a diagonal line when graphed. It can also be written in form y=kx where k is a constant number. This fails two of the the things I mentioned. It doesn't contain point (0,0) because y=2(0)+3=3 not 0. It cannot be written in form y=kx because of the plus 3.

If it were y=2x, then the answer would be yes.

Answer:

It could be a solution

Step-by-step explanation:

This depends on what equation you are solving. It could be a solution for a quadratic or even a transformation problem.

Answer:

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

Uniformly distributed between 47.0 and 57.0 minutes.

This means that [tex]a = 47, b = 57[/tex]

Find the probability that a given class period runs between 51.25 and 51.5 minutes.

[tex]P(c \leq X \leq d) = \frac{51.5 - 51.25}{57 - 47} = 0.025[/tex]

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Answer:

Consider points (-1, 0) and (0, 1) :

[tex]{ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ { \tt{slope = \frac{1 - 0}{0 - ( - 1)} }} \\ { \boxed{ \bf{slope = 1}}}[/tex]

Answer:

slope 1

Step-by-step explanation:

above ANS is correct mark it as branliest ANS

Hi

we know that sin(A+B)=Sin(A)Cos(B)-Cos(A) Sin (B)

cos(2x)=1-2sin²(x)

sin(2x)=2sin(x)cos(x)

Exp:- Sin(3x)=Sin(x+2x)

Sin(x)cos(2x)+cos(x)sin(2x)

sin(x){1-2sin²(x)}+2cos²(x)sin(x)

sin(x)-2sin³(x)+2sin(x){1-sin²(x)}

sin(x)-2sin³(x)+2sin(x)-2sin³(x)

3sin(x)-4sin³(x)

Hope it helps....

Answer:

Step-by-step explanation:

because these are similar triangles, that is, one is a bigger of smaller version of the other, then we know, that the bigger triangle is just 2 times bigger than the smaller,  or   2x of any side of the small one

sooo   2(20) =40  

so we know that side n of the bigger triangle is 40

Answer:  Choice D.  (-7, 14)

Work Shown:

[tex](x,y) \to (x-3, y+7)\\\\(-4,7) \to (-4-3, 7+7)\\\\(-4,7) \to (-7, 14)\\\\[/tex]

The point has moved 3 units to the left and 7 units up. See the diagram below.

9514 1404 393

Answer:

  no

Step-by-step explanation:

We assume you are concerned with the cubic

  x³ -9x² -14x +24

Its factors are all irrational, as shown in the attached graph. x-3 is not a factor.

__

x-3 is a factor if the expression evaluates to zero when x=3. Here, it does not.

  ((x -9)x -14)x +24 for x=3 is ...

  ((3 -9)(3) -14)(3) +24 = (-18 -14)(3) +24 = -96 +24 = -72

The remainder from division by x-3 is not zero, so x-3 is not a factor.

Answer:

48.45in

Step-by-step explanation:

To get the height of Dakota, we will use the SOH CAH TOA

Given the following

angle of elevation = 39degrees

distance from the top of Dakotas head to the tip of the shadow = 77in (Hyp)

Required

Height of Dakota (Opp)

Sin 39 = opposite/hyp

Sin39 = H/77

H = 77sin39

H = 77(0.6293)

H = 48.45in

Hence the Dakota is 48.45in

Answer:

13 miles

Step-by-step explanation:

He hikes 4 mph downhill and it takes 30 minutes or 0.5 hours lesser than the trip uphill at 2 mph.

Thus, if the distance upward is x and we are told the distance downhill is 3 miles longer.

Then, since time = distance/speed, we have;

((x + 3)/4) + 0.5 = x/2

Multiply through by 4 to get;

x + 3 + (0.5 × 4) = 2x

x + 5 = 2x

2x - x = 5

x = 5 miles

Now, it means distance uphill = 5 miles and distance downhill = 5 + 3 = 8 miles

Thus, total distance covered = 8 + 5 = 13 miles

Answer:

x=3 y=5

Step-by-step explanation:

it's simultaneous equations so you first try matching the x or the y on both equations

on the first equation the ys are matching so:

4x+y=17

2x+y=11

2x=6

x=3

now that you have x you substitute it back into the equation to get y

6+y=11

-6 -6

y=5

Answer:

(3,5)

(3,2)

(7,0)

(8,1)

Step-by-step explanation:

1.)

Subtract the two equations

(4x+y)-(2x+y)=17-11

2x=6

x=3

plug this into the first equation

4(3)+y=17

y=5

2.) we need one set of the same variable's coefficents to match (so that when we add/subtract the two equations a variable cancels out). To do this multiply the first equation by 1.5

1.5(3x+2y)=13*1.5

4.5x+3y=19.5

Subtract the second equation

(4.5x+3y)-(2x+3y)=19.5-12

2.5x=7.5

x=3

plug this into the first equation

3(3)+2y=13

2y=4

y=2

3.)

Mulitply the first equation by 3

3(x-2y)=7*3

3x-6y=21

subtract this and the second equation

(3x-6y)-(3x+y)=21-21

-7y=0

y=0

plug this into the first equation

x-2(0)=7

x=7

3.)

add the two equations

(x+5y)+(x-5y)=13+3

2x=16

x=8

plug this into the first equation

8+5y=13

5y=5

y=1

Step-by-step explanation:

red=4/19

green2/1

i didnt get the qn prperly..was a marbke taken out second time？ and not replaced？

Answer:

Lf(x) = Lg(x) = Lh(x) =  1 - 2x

value of the functions and their derivative are the same at x = 0

Step-by-step explanation:

Given :

f(x) = (x − 1)^2,  

g(x) = e^−2x ,  

h(x) = 1 + ln(1 − 2x).

a) Determine Linearization of  f, g and h  at a = 0

L(x) = f (a) + f'(a) (x-a)  ( linearization of f at a )

for f(x) = (x − 1)^2  

f'(x ) = 2( x - 1 )

at x = 0

f' = -2  

hence the Linearization at a = 0

Lf (x) = f(0) + f'(0) ( x - 0 )

Lf (x) = 1 -2 ( x - 0 ) = 1 - 2x

For g(x) = e^−2x

g'(x) = -2e^-2x

at x = 0

g(0) = 1

g'(0) = -2e^0 = -2

hence linearization at a = 0

Lg(x) = g ( 0 ) + g' (0) (x - 0 )

Lg(x) = 1 - 2x

For h(x) = 1 + ln(1 − 2x).

h'(x) =  -2 / ( 1 - 2x )

at x = 0

h(0) = 1

h'(0) = -2

hence linearization at a = 0

Lh(x) = h(0) + h'(0) (x-0)

        = 1 - 2x

Observation and reason

The Linearization is the same in every function i.e. Lf(x) = Lg(x) = Lh(x) this is because the value of the functions and their derivative are the same at x = 0

Answer:

1. (x,y) → (y,x)

Step-by-step explanation:

Coordinate of point E:

Before the transformation, the coordinate of point E was given by (3,-6).

After the transformation, we have E'(-6,3), which eliminates options 2 and 3.

For the other points, we will also get, (x,y) -> (y,x), which is the rule given when the original figure is reflected over the line y = x, and thus, the correct answer is given by option 1.

Answer:

hiiiiiii....!!! how r u

9514 1404 393

Answer:

  (a)  21

Step-by-step explanation:

The product of the lengths to the near and far circle intercepts are the same for the two lines. For the tangent, the near and far intercepts are the same point, so we have ...

  (36)(36) = (27)(27+x)

  48 = 27+x . . . . . . . . . . divide by 27

  x = 21 . . . . . . . . subtract 27

9514 1404 393

Answer:

  10

Step-by-step explanation:

Put the values where the arguments are and do the arithmetic.

  g(h(-2)) = g(-2+4) = g(2) = 5(2)

  g(h(-2)) = 10

Answer:

if x=0 then they have same value

1 and 2 options are out

for x=-1

g(-1)=1

h(-1)=-1

3 is true

4th

FALSE

for all values except 0, g(x)>h(x)

correct ones are

g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).

For negative values of x, g(x) > h(x).

Step-by-step explanation: