Bob and Alice both throw baseballs vertically upwards from the same starting height. Both balls take the same amount of time to go up to their maximum height. Which of the follow is true (select all that apply)A. Both Bob and Alice must have thrown the balls with the same speedB. Bob could have thrown his ball with a larger speed than AliceC. Alice could have thrown her ball with a larger speed than BobD. Both balls must have reached the same maximum heightE. Alice's ball could have reached a large maximum height compared to Bob'sF. Bob's ball could have reached a large maximum height compared to Alice's

The pressure of the gas is 0.970 atm.

The pressure of a gas can be calculated using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

First, we need to find the number of moles of N2, which can be calculated using the molar mass of N2 and the mass of N2 in the container:

n = m/M

n = 0.293g / 28.02 g/mol

n = 0.0104 mol

Next, we need to find the temperature in Kelvin, which can be calculated using the root-mean-square speed of the gas molecules:

T = (2 * k * m / (3 * R))

T = (2 * 1.38 x 10^-23 J/K * 6.63 x 10^-27 kg * (178 m/s)^2 / (3 * 8.31 J/mol/K))

T = 298.15 K

Finally, we can use the ideal gas law to find the pressure:

P = nRT / V

P = (0.0104 mol * 8.31 J/mol/K * 298.15 K) / (1.62 L)

P = 0.970 atm

So the pressure of the gas is 0.970 atm.

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Friction is the force that resists the motion of one object against another. It is a force that acts in the opposite direction of the motion. Friction occurs when two objects rub against each other, resulting in a force that resists their relative motion. This force can be caused by a variety of factors, including the surface roughness of the objects, the material they are made of, the weight of the objects, and the environment they are in.

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To lift the object, you must apply a force of 27 Newtons (9 Newtons divided by 3, the mechanical advantage).

The equation you can use to find the answer is MA = F0/Fi, where MA is the mechanical advantage, F0 is the input force and Fi is the output force.

MA is the mechanical advantage of a machine and is the ratio of output force to input force. For example, if an object needs to be lifted but the force required to lift it is too great, a machine such as a pulley system can be used to reduce the force needed. A pulley system has a mechanical advantage of 3, meaning that the output force is three times greater than the input force.

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The speed of the charged particles or proton or electron will be 2.75 × 10⁵ m/s.

The kinetic energy of an object is the energy which it possesses due to its motion. Kinetic energy is defined as the work needed to accelerate an object of a given mass from the state of rest to its stated velocity.

At the center of the square, all the kinetic energy of the proton is converted to potential energy of the proton. Therefore, far away the kinetic energy of proton must be equal to the potential energy of the person at the center.

Speed of the electron far away from the square, v = 2.75 × 10⁵ m/s

Given, that the charge, q = 15 × 10⁻⁹C

Each side of square, l = 0.02m

Distance of center of square from any charge r = √2l/2 = r= √2 × 0.02/ 2

r = 0.014m

q = 15nC

q = 15nC

I = 0.02m

q = 15nC

q = 15nC

Electric potential at the center of the square is given by:

Vc = 4 × (kq/r)

Electric potential at point far away is V∞ = 0

Potential Energy difference between the two point is

ΔV = Ve - V∞

ΔV = 4×(kq/r)

For the proton to pass through the center of square the proton must have kinetic energy equal to the potential energy at the center of the square.

The kinetic energy of the proton K = mv²

The potential energy of the proton U = eΔV

For the proton to pass through

K(at ∞) = U(Center)

1/2 mv² = 4kqe/ r

v = [tex]\sqrt{(8kq)/(mr)}[/tex]

v = √(8 × 9 × 10⁹ × 15 × 10⁻⁹ × 1.6 × 10⁻¹⁹)/ (1.67 × 10⁻²⁷ × 0.014) m/s

v = 2.75 × 10⁵ m/s

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The device used to vary the current in a circuit is a variable resistor. The symbol of a variable resistor is option d. The symbol with a rectangle and an arrow.

A variable resistor also called a rheostat  is a resistor of which the electric resistance value can be adjusted. A variable resistor is in essence an electro-mechanical transducer and normally works by sliding a contact (wiper) over a resistive element.

When a variable resistor is used as a potential divider by using 3 terminals it is called a potentiometer.

When only two terminals are used, it functions as a variable resistance and is called a rheostat. Electronically controlled variable resistors exist, which can be controlled electronically instead of by mechanical action. These resistors are called digital potentiometers.

Here, the resistance thereby the current through the lamp 2 can be varied by placing a resistor. Hence, option d is correct.

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The symbol used in diagram to represent the device is rheostat's symbol.

Correct option is D.

Electric current is defined as the rate of flow of electrons in a conductor. The SI Unit of electric current is the Ampere.

In given circuit,

A device is added to the electrical circuit to vary the current in Lamp 2 only,

Electrical current is varied by applying variable resistance,

The device used to apply variable resistance is rheostat, which has symbol of box with an arrow through it.

Hence, rheostat's symbol will be used in diagram to represent the device.

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Flared tubing is commonly used in hydraulic systems. Carbon Steel fittings are typically used in hydraulic equipment when attaching tubing to a hose.

Liquid fluid power is used by hydraulic machines to do operations. Heavy-duty construction vehicles are a typical illustration. Hydraulic fluid is pumped to numerous hydraulic motors and hydraulic cylinders located all around the machine in this sort of machine and is pressured in accordance with the resistance present. Control valves direct or automate the distribution of the fluid through hoses, tubes, or pipes.

Pascal's law, which asserts that any pressure applied to a fluid inside a closed system would transmit that pressure equally everywhere and in all directions, is the foundation of hydraulic systems, just like pneumatic systems. An incompressible liquid, as opposed to a compressible gas, serves as the fluid in a hydraulic system.

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The height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

Potential energy is defined as the energy stored in an object or system by virtue of its position or arrangement of parts while kinetic energy is defined as the energy of the moving particles of an object or system.

Potential energy is represented as :

P.E.= mgh

Kinetic energy  is represented as :

[tex]K.E.= 1/2mv^2[/tex]

where, m = mass of the object

h= height

v= velocity

g= acceleration due to gravity which is [tex]9.8m/s^2[/tex]

For above given example,

m= 67kg, v= 6.4m/s

we first find out Kinetic energy,

K.E.=[tex]\frac{1}{2} 67* (6.4)^2[/tex]= 2744.32/2= 1372.16 J

As we know, K.E.= P.E.

So, P.E.= 1372.16J = mgh

1372.16= 67* 9.8* h

height= 2.089 m

Thus, the height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

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The horizontal distance travelled by the golf is 7.75 m.

The time taken for the golf to fall from the given height is calculated by applying the following equation.

t = √ ( 2h / g )

where;

t = √ ( 2 x 46 / 9.8 )

t = 3.1 seconds

The horizontal distance travelled by the golf is calculated as follows;

d = vt

where;

d = 2.5 m/s x 3.1 s

d = 7.75 m

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The complete question is below:

a golf ball is suit from a ship which is at a height 46 m above water surface the horizontal distance covered by Golf is​ if the horizontal velocity is 2.5 m/s.

Answer:

15.33 m/s

Explanation:

We are here given that ,

As we know that,

[tex]\longrightarrow R = \dfrac{u^2\sin2\theta}{g} \dots (1)\\[/tex]

And ,

[tex]\longrightarrow h =\dfrac{u^2\sin^2\theta}{2g} \dots (2)\\[/tex]

Divide equation 1 and 2 ,

[tex]\longrightarrow \dfrac{R}{h}=\dfrac{4 \cos\theta}{\sin\theta} \\[/tex]

[tex]\longrightarrow \dfrac{24m}{6m}=4 \cot\theta \\[/tex]

[tex]\longrightarrow \cot\theta = 1 \\[/tex]

[tex]\longrightarrow \theta = \cot^{-1}(1) \\[/tex]

[tex]\longrightarrow \underline{\underline{\theta = 45^{\circ}}}\\[/tex]

Now we may substitute this value in equation 1 as ,

[tex]\longrightarrow 24 =\dfrac{ u^2\sin(2\times 45^{\circ} )}{g} \\[/tex]

[tex]\longrightarrow 24g = u^2\sin90^\circ \\[/tex]

[tex]\longrightarrow u^2 = 24 \times 9.8 \\[/tex]

[tex]\longrightarrow u =\sqrt{235.2} m/s \\[/tex]

[tex]\longrightarrow \underline{\underline{ u \approx 15.33 \ m/s }}\\[/tex]

and we are done!

Answer:

Their wavelength

Explanation:

Light is a form of energy that travels as waves. Their length — or wavelength — determines many of light's properties. For instance, wavelength accounts for light's colour and how it interacts with matter. The range of wavelengths, from super short to very long, is known as the light spectrum.. Please mark this answer the brainliest. I need it. thanks.

Hope this helps!

It has been demonstrated that the angle when the body exits the sphere is   θ = cos⁻¹(2/3)

Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor. Every time an object moves or attempts to move, friction always acts in the direction opposing to that movement.

Force acting on a stationary particle

The following formula is used to compute the particle's force while it is stationary;

Rgcos = mgcos = mv2/R v2 —- (1)

power-saving measures

Utilizing the principle of energy conservation, one may calculate the object's ultimate speed once it begins to slide.

v2 = 1/2mR(1 - cos) = 2gR(R - Rcos) ---(2) reconcile (1) and (2)

Rgcos = 2gR (cos - 1);

cos = 2 - cos 2.

Cos1(2/3) = 3cos = 2cos = 2/3

As a result, the body exits the sphere at an angle of θ = cos⁻¹(2/3) , proved.

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The complete question is

A body of mass m and negligible size starts from rest and slides down the surface of a frictionless solid sphere of radius R. Prove that the body leaves the sphere when 0 = cos(2/3).

The diffusion coefficient based on the provided data is 3.651 x 10^(-5) cm^2/s. (Option C)

The diffusion coefficient refers to the ratio of flux density to the negative of the concentration gradient in direction of diffusion. The diffusion coefficient in solids at different temperatures is generally found to be well predicted by the Arrhenius equation:

D=Do exp (-E/RT)

Where D is the diffusion coefficient (in m2/s), Do is the maximal diffusion coefficient (at infinite temperature; in m2/s), E is the activation energy for diffusion (in J/mol), T is the absolute temperature (in K), and R ≈ 8.31446 J/(mol⋅K) is the universal gas constant.

In the given case,

Do = 0.0047 cm/s = 4.7 x 10^-5 m/s

E = 18300 cal/mol = 76567.2 J/mol

T = 700°C = 973.15 K

Hence,

D=(4.7 x 10^(-5)) exp (-76567.2/(8.31446*973.15))

D=(4.7 x 10^(-5)) exp (-9.463)

D=3.651 x 10^(-9) m^2/s or 3.651 x 10^(-5) cm^2/s

Note: The question is incomplete.  The complete question probably is: What is the diffusion coefficient (D) for iron at 700°C, with an activation energy (E) of 18,300 cal/mol, and Do = 0.0047cm/s. A) 2.43E3 cm2/s B) 9.08E-9 cm2/s C) 3.64E-5 cm2/s D) 60.66 cm2/s.

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Answer:

You will observe the transition from the first energy level to the fourth energy level. This is because the energy of the photons is equal to the amount needed to move the electron from the first energy level to the fourth energy level. Any energy higher than 51.0 electron-volts would not be observed because the electron would not be able to transition to a higher energy level.

The force in the cord ab is 37.6 lb when being lifted at a constant speed, and the angle u for balance.

The rotation of the earth is an example of a body that is moving with uniform velocity when its speed is increasing throughout an interval of time.

The sum of the forces in each direction must be zero in order to lift the block at a steady speed.

XFx = 0 : F sin θ − T sin 20° = 0

XFy = 0 : T cos 20° − F cos θ − 20 = 0

The tension in cord CAD stays constant throughout because there is no friction on the pulley: F = 20 lb.

20 sin θ − T sin 20° = 0......... (1)

T cos 20° − 20 cos θ − 20 = 0 ........(2)

Solve equation (1) for T

T = 20 sin θ/sin 20

and substitute it into equation (2).

(20 sin θ/sin 20°)cos 20° − 20 cos θ − 20 = 0

cot 20°sin θ − cos θ − 1 = 0

cot 20°sin θ − 1 = cos θ

cot 20°sin θ − 1 = √1 − sin2θ

cot²20°sin²θ − 2 cot 20°sin θ + 1 = 1 − sin²θ

(cot²20° + 1) sin²θ − 2 cot 20°sin θ = 0

csc²20°sin²θ − 2 cot 20°sin θ = 0

(csc²20°sin θ − 2 cot 20°) sin θ = 0

csc²20°sin θ − 2 cot 20° = 0 or sin θ = 0

sin θ = 2 cot 20°/csc² 20°

= 2 cos 20°sin 20° = sin 40° or sin θ = 0

θ = 40° or θ ≠ 0°.

Substitute this nonzero value for θ into the formula for T.

T =20 sin θ/sin 20°

≈ 37.6 lb

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Answer:

C) 0.83 Ω

Explanation:

Answer:

The gravitational force on the moon is approximately 1/6th of the gravitational force on Earth. This means that the value of gravity on the moon is 1.62 m/s2.

Answer:

on earth the value of gravity on moon is 1.625 m/s2

Explanation:

1.625 m/s2

The magnitude of your total displacement is 745 m.

The total displacement of the your motion is calculated by applying the following formula as shown below;

Δx = x₂ - x₁

where;

The magnitude of your total displacement is calculated as follows;

Δx = ( 23 m/s x 155 s ) - ( 12 m/s x 235 s )

Δx = 745 m

Thus, the magnitude of your total displacement is based on the change of your position.

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A stopped roller coaster cart (velocity = 0 m/s) with a mass of 12,000 kg starts from the top of

the track at a height of 35 meters. It begins to roll down to the bottom (where height will be 0 meters).

KE = PE = mgh

KE = (12,000)(9.8)(35)

= 4,116,000

What is height?

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From a towering building, 2 tennis balls fall into the air. Lead pellets are contained within one of them. The lead-filled ball becomes the first to touch the ground.

The invisible atmospheric mixture that envelops Earth is called air. Most organisms depend on vital elements like oxygen and nitrogen to thrive, which are found in air. Of course, a member of this species is human people (Homo sapiens). In some cases, "atmosphere" is substituted in place of "air."

Respiration is a procedure that includes breathing. A living organism breathes by taking intake oxygen from the environment and exhaling carbon dioxide. This process provides the energy necessary for plants and animals to absorb, grow, and sustain life.

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Answer:

3.92 m/s²

Explanation:

It's hard to read your sketch, but it looks like m2 = 30 kg?  If so, here's the answer:

m1 = 20 kg

m2 = 30 kg

a = (m2·g) - (m1·g·sin∅) / (m1 + m2)   you can see how this equation is derived from Newton's 2nd Law in any physics textbook or website

a = ((30 kg)(9.8 m/s²) - (20 kg)(9.8 m/s²)(sin30)) / (20 kg + 30 kg)

a = (294 kg·m/s² - 98 kg·m/s²) / (50 kg) = 3.92 m/s²

A and D are correct. A home run is the only type of successful hit, so the probabilities of each must be equal.

Additionally, a home run by definition is a successful hit, so the probability that he gets a successful hit must be greater than, or at least equal to, the probability that he hits a home run. B, C and E are incorrect since these probabilities can be calculated and it is possible to say which one is greater.

The probability is a measure of how likely an event is to occur. It is a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain. The probability of an event can be calculated by dividing the number of favorable outcomes by the total number of potential outcomes. For example, if the probability of flipping a coin and getting heads is 0.5, it means that there is a 50% chance of getting heads when flipping the coin.

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The following factors change as one moves to higher magnifications with a microscope:

What is magnification?

Magnification is a measure of how much an image is enlarged or increased in size compared to the original object. It is commonly used in optics, such as microscopes and telescopes, to describe the level of enlargement achieved by the instrument. The magnification is usually expressed as a ratio or a multiple of the original size.

a. Resolution: Resolution refers to the ability of a microscope to distinguish two separate points as separate entities. As one moves to higher magnifications, the resolution of the microscope increases, meaning that smaller and finer details can be seen.

b. Amount of light needed: As magnification increases, the amount of light needed to illuminate the specimen also increases. This is because the increased magnification reduces the amount of light that reaches the specimen and the observer.

c. Working distance: Working distance refers to the space between the lens and the specimen. As one moves to higher magnifications, the working distance decreases, meaning that the lens must be positioned closer to the specimen.

d. Depth of field: Depth of field refers to the range of distances from the lens that are in focus at any given time. As one moves to higher magnifications, the depth of field decreases, meaning that only a very small portion of the specimen will be in focus at any given time.

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Answer:

see below

Explanation:

We are here given that ,

As we know that,

[tex]\implies h =\dfrac{u^2\sin^2\theta}{2g} \\[/tex]

substitute the respective values,

[tex]\implies 2.4 m =\dfrac{u^2\sin^245^\circ}{2\times 10} \\[/tex]

[tex]\implies 2.4m =\dfrac{u^2\times \bigg(\dfrac{1}{\sqrt2}\bigg)^2}{20}\\[/tex]

[tex]\implies u^2 = 40 \times 2.4 = 96 \\[/tex]

[tex]\implies u^2 =\sqrt{96}\\[/tex]

[tex]\implies \underline{\underline{ u \approx 9.79 \ m/s }}\\[/tex]

secondly we know that,

[tex]\implies t = \dfrac{u\sin\theta}{g}\\[/tex]

[tex]\implies t =\dfrac{9.79\times \sin45^\circ}{10} \\[/tex]

[tex]\implies t =\dfrac{9.79\times \dfrac{1}{\sqrt2}}{10} \\[/tex]

[tex]\implies \underline{\underline{ t \approx 0.69 \ s }}\\[/tex]

and we are done!

After applying the gravitational potential energy, the amount work done in lifting a 35 kg sandbag to a height of 4.5 m would be 1,544 Joule

Gravitational potential energy is another name for work done against gravity. Because of this, if a mass (m) object is lifted through a height (h), the work done on it will be [m × g × h], and this energy will be stored as gravitational potential energy in the body.

Thus, the amount work done would be:

Work = m × g × h

         = 35 kg × 9.8 m/s² × 4.5 m

         = 1,543.5 Nm

         = 1,543.5 Joule

         = 1,544 Joule

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Answer:

3Ω

Explanation:

we are here given that,

From Ohm's law , we know that,

[tex]\implies V = iR \\[/tex]

where ,

on substituting the respective values, we have,

[tex]\implies 12V = 4A(R) \\[/tex]

[tex]\implies R =\dfrac{12V}{4A} \\[/tex]

[tex]\implies \underline{\underline{ R = 3\Omega}} \\[/tex]

and we are done!

At a height of 4.48 meters, a rock's kinetic energy is twice its potential energy.

Potential energy is the energy stored in any object or system due to the position or arrangement of its parts. It is, however, unaffected by factors outside of the object or system, such as air or height. Kinetic energy, on the other hand, is the energy of moving particles in an object or system.

Given that a 6.0-kg rock is dropped from a height of 9.0 m.

Calculate the total potential energy at the initial point,

PE = mgh

PE = 6 x 9.81 x 9

PE = 530.74 J

At the zero height, the kinetic energy will be maximum and is equal to the total energy,

KE = 530.75 J

1/2 mv² = 530.75

v² = 175.85

The height at which the kinetic energy is two times the potential energy is calculated as:-

1 /2 x mv² = 2 x mgh

h = ( 4 v²) / ( 4 x 9.81 )

h = 4 ( 175.82 ) / ( 4 x 9.81 )

h = 4.48 meters

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Answer:

Explanation:

Matter is identified based on its physical and chemical properties.

Physical properties, such as color, texture, density, melting point, and boiling point, can be used to identify matter without changing its composition. For example, a solid object with a high density and a high melting point is likely to be a metal, while a lighter, less dense material with a low melting point is likely to be a plastic.

Chemical properties, such as reactivity, flammability, and acidity, are also used to identify matter. For example, the reaction of a substance with a strong acid or base can provide information about its chemical composition.

In addition to physical and chemical properties, matter can also be identified based on its molecular structure and composition. This can be done using techniques such as X-ray diffraction, spectroscopy, and microscopy, which allow scientists to examine the atomic and molecular structure of matter.

Finally, the chemical formula of a substance can also be used to identify it. The chemical formula specifies the types and numbers of atoms present in the substance, which can be used to determine its chemical properties and behavior.

If there is a non-trivial linear combination of the vectors that equals 0, then a set of vectors is said to be linearly dependent.

Physical quantities can be represented using vectors. Vectors are most frequently employed in physics to describe displacement, velocity, and acceleration. Vectors are depicted as arrows and combine magnitude and direction.

Because they may visually depict position, displacement, velocity, and acceleration, vectors are useful. It is crucial to indicate where the scale is being drawn at when drawing.

|v| =(x2 + y2) is the formula to calculate the magnitude of a vector in two dimensions, where v = (x, y). The equation |V| = (x2 + y2 + z2) can be used to calculate the magnitude of a vector in three dimensions, where V = (x, y, z).

Therefore, vectors because you frequently do not have enough room to draw them at the scale they represent.

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The light year is an unit of measure for distance. It is defined as the distance travelled by light in a vacuum over the course of a year.

A vacuum is a space area that is either devoid of matter or has a pressure so minimal that any particles there have no bearing on any processes occurring there. It is a condition that has a pressure that is measured in units of pressure and is much lower than the mean air pressure.

The quantity of force applied to a certain region is referred to as pressure. So either a strong force or a strong force applied over a short area can cause a lot of pressure (or do both).

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