Which of these ordered pairs is a solution to the linear inequality y > 3x + 2?
(–1, –5)
(–2, –7)
(2, 8)
(2, 9)
The ordered pairs that is a solution to the linear inequality y > 3x + 2 is
(2, 9)
How to find solution of inequality?The inequality is as follows;
y > 3x + 2
Therefore, let's try option 1
(-1, -5)
-5 > 3(-1) + 2
-5 > -3 + 2
-5 > - 1 (This is false)
(–2, –7)
-7 > 3(-2) + 2
-7 > -6 + 2
-7 > -4 (This is false)
(2, 8)
8 > 3(2) + 2
8 > 6 + 2
8 > 8 (false)
(2, 9)
9 > 3(2) + 2
9 > 8 (This true)
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Select the correct answer. In right triangle ABC, b^2+c^2=34 and bc=15. What is the approximate length of side a? Note: Use the law of cosines.
(the triangle is a right triangle with an angle of 53)
Using the law of cosines, it is found that the approximate length of side a is 3.99 units.
What is the law of cosines?The law of cosines states that we can find the side c of a triangle as follows:
[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]
in which:
C is the angle opposite to side c.a and b are the lengths of the other sides.In the context of this problem, we have that side a is opposite to the angle of 53º, hence:
[tex]a^2 = b^2 + c^2 - 2bc\cos{53^\circ}[/tex]
We are given that:
b² + c² = 34.bc = 15.Then:
[tex]a^2 = 34 - 30\cos{53^\circ}[/tex]
a² = 15.95
[tex]a = \sqrt{15.95}[/tex]
a = 3.99.
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there was 506 tickets sold for the school play they were either student tickets or adult tickets there was 56 more student tickets sold than adult tickets sold how many adult tickets were sold
Answer:
A = 228 tickets
Step-by-step explanation:
We need to set up a system of equation to find the number of adult tickets sold, where A represents the adult tickets and S represents the student tickets.
Because the number of adult and student tickets together equals 506, we have A + S = 506.
Because there are 56 more student tickets than adult tickets we have A + 56 = S
And the way the system is already set up allows us to use substitution.
Thus, we have:
[tex]A + S=506\\A+56 = S\\\\A+A+56 =506\\2A+56=506\\2A=456\\\\A=228\\228+56=S\\278=S[/tex]
The number of student tickets was not necessary to find in this problem, but I found anyway just in case you wanted check the work or wanted to prove the validity of the values.
a car's velocity is modeled by
[tex] v(t) = 0.5t {}^{2} - 10.5t + 45 \: for\leqslant t \leqslant 10.5[/tex]
Where velocity is in feet per second and time is in seconds. When does the car come to a complete stop?
In accordance with the function velocity, the car will have a complete stop after 6 seconds.
When does the car stop?
Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:
0.5 · t² - 10.5 · t + 45 = 0
t² - 21 · t + 90 = 0
By the quadratic formula we get the following two roots: t₁ = 15, t₂ = 6. The stopping time is the least root of the quadratic equation, that is, the car will have a complete stop after 6 seconds.
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questions 5 and 6 please!
formula: y = ax + q
Answer:
5) y = 1x + 2
6) y = -0.5x + 6
Explanation:
5)
Given points are (-3, -1), (2, 4)
[tex]\sf slope \:formula: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]
Here, find slope:
[tex]\rightarrow \sf slope \ (a) = \dfrac{4-(-1)}{2-(-3)} = \dfrac{5}{5} = 1[/tex]
Find Equation:
y = ax + q
Here found that a = 1, take (x, y) = (-3, -1)
[tex]\sf -1 = 1(-3) + q[/tex]
[tex]\sf q - 3 = -1[/tex]
[tex]\sf q = -1 + 3[/tex]
[tex]\sf q = 2[/tex]
So, in total equation:
y = 1x + 2
-------------------------------------------------------------------------------------
6)
Given points are (-2, 7), (2, 5)
[tex]\sf slope \:formula: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]
Here, find slope:
[tex]\rightarrow \sf slope \ (a) = \dfrac{5-7}{2-(-2)} = -0.5[/tex]
Find Equation:
y = ax + q
Here found that a = -0.5, (x, y) = (-2, 7)
[tex]\sf 7 = -0.5(-2) + q[/tex]
[tex]\sf 7 = 1 + q[/tex]
[tex]\sf q = 7-1[/tex]
[tex]\sf q = 6[/tex]
So, in total equation:
y = -0.5x + 6
Answer:
Since √3√3 is equal to 1 , you simply rearranged the way it was written. The value of the simplified fraction stays the sameexplain why x squared = 16 has two solutions. What are the solutions.
cual es la mitad de 980
Al aplicar operaciones de aritmética básica, tenemos que la mitad de 980 es igual a 490.
¿Cuál es la mitad de un número par?
En esta pregunta tenemos un número par de tres dígitos que termina en cero. De acuerdo con la teoría numérica, un número de base 10 de más de un dígito que tenga un número par relacionado con números impares como último dígito, tendrá un número impar si es dividido por 2.
Ahora bien, si tenemos un número par con más de un dígito que termina en cero, entonces tendrá un número par que termina en 0 si es dividido por 2.
Si dividimos 980 por 2, entonces tenemos 490 como resultado:
980/2 = 98/2 × 10 = 49 × 10 = 490
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match the expressions with their resultant terms in exponential form.
137
1319
131
13-22
13-14
1315
13-7
Resultant Terms in Exponential Form
Expressions
13-11 × 1316 × 13-3 × 134 × 13-5
arrowBoth
13-21 × 13-4 × 13-5 × 1314 × 13-6
arrowBoth
1333 × 13-2 × 135 × 13-13 × 13-8
arrowBoth
130 × 1310 × 13-12 × 135 × 134
arrowBoth
The correct matching of the exponential form is given.
How to illustrate the information?1: 13^-11 × 13^16 × 13^-3 × 13^-4 × 13^-5
= 13
2. 13^-21 × 13^-4 × 13^-5 × 13^14 × 13^-6
= 13^-22
3. 13^0 × 13^10 × 13^-12 × 13^5 × 13^4
= 13^7
This illustrates the exponential form.
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Which inequality can be used to explain why these three segments cannot be used to construct a triangle?
AC + AB > CB
AC + CB < AB
AC + CB > AB
AC + AB < CB
The answer choice which explains that the three segments cannot be used to construct a triangle is; AC + CB < AB.
Which inequality explains why the three segments cannot be used to construct a triangle?Since, It follows from the triangle inequalities theorem that sum of the side lengths of any two sides of a triangle is greater than the length of the third side.
Hence, since the sum of sides AC + CB is less than AB, it follows that the required inequality is; AC + CB < AB.
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Answer: Option 2 or B. AC + CB < AB
Step-by-step explanation: Trust Me! It is correct on Edge!
Q: Which inequality can be used to explain why these three segments cannot be used to construct a triangle?
A: AC + CB < AB
Find the measure of side b.
b = _ yd
a In a concert band, the probability that a member is in the brass section is
0.50. The probability that a member plays trombone, given that he or she is in
the brass section, is 0.24.
What is the probability that a randomly selected band member is in the brass
section and plays trombone?
A. 0.26
B. 0.74
C. 0.12
D. 0.48
Answer:
C. 0.12
Step-by-step explanation:
Let's use a sample number of 100
Out of 100 members, 50 are in the brass section
Out of those 50, 24% play the trombone. This means that 12 people total play the trombone.
12/100 is .12.. That is the final answer
Need help with this one
Answer: [tex]\frac{9g}{4y}[/tex]
Step-by-step explanation:
[tex]\frac{6g}{2} \times \frac{3}{4y}=\frac{18g}{8y}=\frac{9g}{4y}[/tex]
The data represent the age of world leaders on their day of inauguration. Find the five-number summary, and construct a boxplot for the data. Comment on the shape of the distribution.
The five-number summary is: 41, 56, 65, 67, 69.
The box plot that represents the data is: option B.
Correct statement for the shape of the distribution is: B. the distribution is skewed to the left.
What is the Five-number Summary?The five-number summary is a five data value that describes the distribution of a data set, which include: lower and upper quartiles, minimum and maximum values, and the median of the data.
The five-number summary is used to construct a box plot.
Given the data, 65, 56, 67, 68, 66, 66, 67, 69, 48, 57, 59, 68, 59, 41, 44, the five-number summary for the data is:
Minimum: 41Quartile Q1: 56Median: 65Quartile Q3: 67Maximum: 69This means that the box plot that will represent this data will have a box that ranges between 56 and 67, and the data at both whiskers will be 41 and 69, while the data at the point where the vertical line divides the box would be 65.
Thus, the box plot that represents the data is: option B.
The median is closer to the right of the third quartile/upper quartile, therefore: B. the distribution is skewed to the left.
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What is S10 of the geometric sequence? Round to the nearest whole number.
8, 20, 50, 125, …
15,263
50,857
317,886
The sum of the ten terms to the nearest whole number is 50857.
How to find the sum of a geometric sequence?Using geometric sequence formula,
nth term = arⁿ⁻¹
where
a = first termr = common ration = number of termsr = 20 / 8 = 5 / 2
a = 8
Hence,
s₁₀ = a(rⁿ - 1) / r - 1
s₁₀ = 8((5 / 2)¹⁰ - 1) / 5 / 2 - 1
s₁₀ = 8(9535.74316406) / 1.5
s₁₀ = 50857.296875
s₁₀ = 50857
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quick question for 40 points
A gallon of stain is enough to cover 200 square feet of decking. Bradley has two areas of decking he would like to cover with stain. One rectangular area is 23 feet by 10.4 feet, and the other is 10.5 feet by 7.2 feet. Which expression gives the number of gallons of stain Bradley will need?
Left-bracket (23) (10.5) + (10.4) (7.2) right-bracket divided by 200
Left-bracket (23) (10.4) + (10.5) (7.2) right-bracket divided by 200
Left-bracket (23) (10.5) + (10.4) (7.2) right-bracket times 200
Left-bracket (23) (10.4) + (10.5) (7.2) right-bracket times 200
The expression that we need to get is:
[tex]N = \frac{(23)*(10.4) + (10.5)*(7.2)}{200}[/tex]
So the correct option is the second one.
Which expression gives the number of gallons of stain Bradley will need?
We know that 1 gallon is enough to cover 200 ft².
We have two rectangular areas, one of:
23 feet by 10.4 feet, and other of 10.5 feet by 7.2 feet.
Then the total area is:
A = (23 ft)*(10.4 ft) + (10.5ft)*(7.2 ft)
The number of gallons needed is given by the quotient between the area that we want to cover, and the area that covers one gallon, so the expression is:
[tex]N = \frac{(23ft)*(10.4ft) + (10.5ft)*(7.2ft)}{200ft^2} \\\\N = \frac{(23)*(10.4) + (10.5)*(7.2)}{200}[/tex]
So the corerect option is the second one.
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If the greatest value the variable m can be is less than 9, which of the following inequalities best shows all the possible values of m?
m < 9
m > 9
m ≤ 9
m ≥ 9
The inequality which shows all possible values of m is; m < 9.
Which inequality best shows all possible values of m?It follows from the task content that the variable in discuss, m is described as less than 9.
On this note, the most appropriate inequality to represent the set of all possible values of m is; m < 9.
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1. Is the average change in population is the same now as it was 50 years ago? Explain your answer.
HURRY PLEASE NEED IT URGENTLY!!!!!!!!!!!!
No, the average change in population is not the same as it was 50 years ago.
Reason in Support of the Answer:
In many important ways, the demographic future of the United States and the rest of the world is substantially different from the recent past. The world's average population approximately tripled between 1950 and 2010, and the U.S. population nearly doubled.
However, it is anticipated that between 2010 and 2050, both globally and in the United States, average population growth will be substantially slower and will disproportionately favor the oldest age groups. Hence it is seen that the average change in population is never constant. It depends on the demographic trends and conditions, whether the average change in population will be larger or comparatively trivial in the future. And, similarly, it can be said that the average change in population is not the same as it was 50 years ago.
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Find the reminder when 3x² + 2x -7 is divided by x - 1
Answer:
-2
Step-by-step explanation:
When x = 1, 3x² + 2x - 7 = -2.
HELP ME PLEASE
LOOK AT IMAGE
Answer:
the answer is congruent making d midpoint
[tex] \sqrt{7} [/tex]
multiplicative inverse (reciprocal)
Answer: [tex]\frac{\sqrt{7}}{7}[/tex]
========================================================
Explanation:
The reciprocal of x is 1/x where x is nonzero. Multiplying x with 1/x leads to 1. For example, the numbers 9 and 1/9 are multiplicative inverses of each other.
We'll stick 1 over the given square root expression. Then follow these steps to rationalize the denominator.
[tex]\frac{1}{\sqrt{7}}\\\\\\\frac{1*\sqrt{7}}{\sqrt{7}*\sqrt{7}}\\\\\\\frac{\sqrt{7}}{(\sqrt{7})^2}\\\\\\\frac{\sqrt{7}}{7}\\\\[/tex]
In short, [tex]\frac{1}{\sqrt{7}}=\frac{\sqrt{7}}{7}[/tex]
I need help with the slope
Answer:
Line A
Step-by-step explanation:
Hello!
Given that the x-values is the time in minutes, and the y-axis is the number of dishes stacked, for every minute, the line should go up by 7.
This means, that the value of y when x is 1 should be 7. The line that follows this rule is Line A. For every minute, 7 dishes are stacked.
The answer is Line A.
Find the zeros of the function. Enter the solutions from least to greatest. f(x) = (x - 2)(3x + 3)
The zeros of the given function are x = 2 and x = -1
Zeros of a functionFrom the question, we are to determine the zeros of the given function
The given function is
f(x) = (x - 2)(3x + 3)
To determine the zeros of a function, we will set the function equal to zero
That is,
(x - 2)(3x + 3) = 0
Then,
x - 2 = 0 OR 3x + 3 = 0
x = 2 OR 3x = -3
x = 2 OR x = -3/3
x = 2 OR x = -1
Hence, the zeros of the given function are x = 2 and x = -1
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A six sided die, a 20 sided die, and a 12 sided die are rolled, what’s the probability of all three happening. Showing 3 on the first die, showing either 19 or 20 on the second die, and showing an odd number on the third die
The probability of all three events happening when the dies are rolled is; 0.0083
What is the Probability of Rolling a Die?A) On the first die, it has 6 sides and 3 must come out, that is, 1 event out of 6 possible, therefore the probability is: 1/6
B) On the second die, it has 20 sides and if 19 or 20 can come out, that is 2 events out of 20 possible, so the probability is: 2/20 = 1/10
C) On the third die, which is 12 sides, an odd number can come out. The odd numbers would be 1, 3, 5, 7, 9, 11; i.e, 6 events out of 12 possible numbers.
Thus, the probability would be: 6/12 = 1/2
The final probability would be;
(1/6) * (1/10) * (1/2) = 0.0083
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A pension fund manager is considering three mutual funds. The first is a stock fund, the second is a long-term government and corporate bond fund, and the third is a T-bill money market fund that yields a sure rate of 5.5%. The probability distributions of the risky funds are:
Suppose now that your portfolio must yield an expected return of 12% and be efficient, that is, on the best feasible CAL.
This problem is about pension fund management. It is to be noted that the best Feasible Capital Allocation Line (CAL) is: 0.3162.
What is Capital Allocation Line (CAL)?
A graph's capital allocation line depicts all conceivable combinations of risky and risk-free assets, allowing investors to estimate future returns depending on risk.
What is the calculation for the above solution?
It is to be noted that the optimal risky portfolio's stock percentage is determined by:
Weight of Stock = ((Return on Stock - Risk Free Rate) * Variance of bond) - ((Return on Bond - Risk Free Rate) * Co-Variance of bond & Stock)/ ((Return on Stock - Risk Free Rate) * Variance of bond + (Return on Bond - Risk Free Rate) * Variance of Stock - ((Return on Bond - Risk Free Rate + Return on Stock - Risk Free Rate + ) * Co-Variance of bond & Stock)
→ The weight of stock
= ((15% - 5.5%) * 529) - ((9% - 5.5%) * 110.40)/ ((15% - 5.5%) * 529) + (9% - 5.5%) * 1,024 - ((15% - 5.5% + 9% - 5.5%) * 110.40)
= [(50.255) * (3.864) /(50.255) + (46.08) - (14.352)]
Weight of Stock = 0.646628
Weight of Bonds = 1 - 0.646628
Weight of Bonds= 0.353372
Expected return of portfolio = 0.646628 * 15% + 0.353372 * 9%
= 12.88%
Standard Deviation of Portfolio (SDP)= (0.6466282² * 1,024 + 0.3533722² * 529 + 2 * 0.646628* 0.353372* 110.40)⁰·⁵
SDP = (544.67)⁰·⁵
SDP = 23.34%
Hence,
Best feasible CAL = (12.88% - 5.5%)/ 23.34%
Best feasible CAL = 0.3162
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Full Question
See the attached spread sheet for additional information related to the questions.
On Monday the change in the value of one share of a companies stock can’t be represented as -$2.85 Tuesday the value of one share of the companies that changes again which of these describes a situation that would bring the total change for the two days to zero dollars
Step-by-step explanation:
If a stock's price falls all the way to zero, shareholders end up with worthless holdings. Once a stock falls below a certain threshold, stock exchanges will delist those shares.strong earning result in the stock price moving up and vice versa.
in the question you asked,the situation that will make stock price move from -$2.85 to zero means the stock, bond, or commodity market, or an index representing them, currently trades higher than it did at some specific point in the past.
Evaluate ( 75 − 3/17 + 1 ) 2
Answer:
2=1289/17
Step-by-step explanation:
use the given functions to set up and simplify 2
On Monday, Cinthia studied for 3 1/2 hours. On Tuesday, she studies 2/3 of her study time on Monday. How many hours did Cinthia study on Tuesday?
Answer:
Cinthia studied 2/3 of her time on Tuesday
Which equation represents the line that is perpendicular to and passes through (-8,-2)?
x = -2
x = -8
y = -6
y = -8
The equation of the line that is perpendicular to y = 1/6 is: B. x = -8.
How to Find the Equation of Perpendicular Lines?Perpendicular lines have slope values that equals -1 when multiplied together, that is, they are negative reciprocals.
Given the equation, y = 1/6, the slope is 0. This means it is a vertical line, therefore, the line that is perpendicular to it would automatically be a vertical line with an undefined slope which passes through (,8, -2).
The line therefore, would intercept the x-axis at -8. The equation would be: x = -8.
Equation of the perpendicular line is therefore: B. x = -8.
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which linear inequality is represented by the graph
Answer:
The correct awnser is A : )
Step-by-step explanation: