Physics High School

Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.

Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.



The two blocks collide head-on in a perfectly elastic collision.

Determine the velocity of each mass after the collision.

Answers

Answer 1

Momentum is conserved, so

(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'

where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives

100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'

0 = (2 kg) v₁' + (4 kg) v₂'

v₁' = -2v₂'

Energy is also conserved, so

1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²

Simplifying yields

2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²

3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²

Substitute v₁' = -2v₂' and solve for v₂' :

3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²

3750 J = (6 kg) (v₂')²

(v₂')² = 625 J/kg = 625 m²/s²

v₂' = 25 m/s

Then the first block has final velocity

v₁' = -2 (25 m/s)

v₁' = -50 m/s

Related Questions

what is the velocity of a 50 kg dog with 3000 j of kinetic energy

Answers

Answer:

KE = 225000000 J

Explanation:

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules

Answers

Answer:

this question makes no sense

Explanation:

like how do you get this question

Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.

Explanation:

can someone explain why is the answer 3.1?​

Answers

i dont know  Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you            Explanation:

stella is driving down a steep hill. she should keep her car __________ to help _________.

Answers

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

An object with a mass of 13.2 kg is accelerating at 9.4 m/s? What force is being applied on the object?
Round your answer to the appropriate number of significant figures and use the following formula:
force = mass x acceleration

Answers

Force = mass x acceleration:

Force = 13.2 kg x 9.4 m/s

Force = 124.08

Force = 124 Newtons

The force will be  = 124 N              

What is newton's second law of motion?

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

according to newton's second law of motion

Force = mass * acceleration

given

mass = 13.2 kg

acceleration = 9.4 m/s

force = 13.2 * 9.4

        = 124.08 N

Rounding off answer to  the appropriate number of significant figures

force = 124 N

learn more about newton's second law :

https://brainly.com/question/13447525?referrer=searchResults

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hi my name is coolboy123hillok

Answers

Answer:

you should change that name

please change your name

A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?

Answers

Force = mass x acceleration:

5N = 1kg x acceleration

Acceleration = 5N / 1 kg

Acceleration  = 5 m/s^2

Acceleration is a positive value so it is speeding up

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