Bibek went to the swimming pool. he saw the pool to be shallower and is redy to jump into the swimmingpool . is it proper for him to jump? if not why ?

here's the first part but for the 2nd one all I know is that the word "compression" goes on the spirals that are closer together.

hope this helps!

Answer:

[tex]3.125\times 10^{5}watt[/tex]

Explanation:

We are given that

Mass of car, m=1500 kg

Acceleration,[tex]a=10m/s^2[/tex]

Distance, s=1250 m

Time, t=60s

We have to find the power of car during this time.

We know that

Force, F=ma

Using the formula

[tex]F=1500\times 10=15000N[/tex]

Work done, W=Fs

Work done, W=[tex]15000\times 1250[/tex]

Power, P=[tex]\frac{work\;done}{time}[/tex]

Using the formula

Power, P=[tex]\frac{15000\times 1250}{60}[/tex]

Power, P=312500watt

Power, P=[tex]3.125\times 10^{5}watt[/tex]

Answer:

0.33 hz

Explanation:

the formula for the frequency in this situation is f=v/wavelength

Answer:

  v₂ = 2,665 m / s

Explanation:

This is an exercise of conservation of the momentum, we define a system formed by the two cars, so that the forces during the collision are internal and the moment is conserved.

Initial instant. Before the crash

           p₀ = m v_o

Final moment. Right after the crash

           p_f = m v₁ + M v₂

where the first car uses subscript 1 and has a mass m = 1 kg and the second car uses the subscript 2 with a mass M = 2kg

how the moment is preserved

        p₀ = p_f

         m v_o = m v₁ + M v₂

They indicate that the collision is elastic, therefore the kinetic energy is conserved, the velocity of the first car is v1 = -1.33 me / S

         v₂ = [tex]\frac{ m ( v_o - v_1)}{M}[/tex]

we calculate

        v₂ = [tex]\frac{ 1 ( 4 + 1.33)}{2}[/tex]

        v₂ = 2,665 m / s

Answer:

The most correct option for the magnitude of the velocity of the ship relative to the port is;

33 km/h

Explanation:

The given parameters of the cargo ship are;

The speed of the cargo ship = 25 km/h

The direction of the cargo ship, θ₁ = 20° North of East

The speed of the current = 10 km/h

The direction of the current, θ₂ = 15° North of East relative to the port

Therefore the direction of the ship relative to the port, 'θ', is given as the sum of θ₁ and θ₂ as follows;

θ = θ₁ + θ₂ = 20° + 15° = 35°

The component of the velocities relative to the port are given as follows;

The velocity of the ship, v₁ = 25·cos(35°)·i + 25·sin(35°)·j

The velocity of the current , v₂ = 10·cos(15°)·i + 10·sin(15°)·j

The velocity of the ship relative to the port, v = (25·cos(35°) + 10·cos(15°))·i + (25·sin(35°) + 10·sin(15°))·j

∴ v ≈ 30.14·i + 16.93·j

The magnitude of 'v' is [tex]\left | v \right |[/tex] = √(30.14² + 16.93²) ≈ 34.6

Therefore, the magnitude of the velocity of the ship relative to the port, [tex]\left | v \right |[/tex] ≈ 34.6 km/h.

Therefore, the closest correct option for the velocity of the ship relative to the port is 33 km/h

Answer:

The correct option for the magnitude of the velocity of the ship relative to the port is...

(33 km/h)

Answer: The answer is Skill

Explanation:

Answer: I think its 120

Explanation: thx for the free points :)

The total amount of energy remains the same.

Answer:

Specific heat capacity, = 2.1J/g°C

Explanation:

Given the following data;

Mass = 250g

Quantity of heat = 34.125kJ = 34.125 * 1000 = 34125 Joules.

Change in temperature = 65.0∘C

To find the specific heat capacity;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making c the subject of formula, we have;

[tex] c = \frac {Q}{mdt} [/tex]

Substituting into the equation, we have;

[tex] c = \frac {34125}{250*65} [/tex]

[tex] c = \frac {34125}{16250} [/tex]

Specific heat capacity, = 2.1J/g°C

Answer:

soil

Explanation:

CORRECT

Answer:

soil

Explanation:

Hope this will help

Complete Question:

A coin is dropped off of a building landing on its side. It hits with a pressure of 400 N/m². It hits with a force of 0.1N. Calculate the area of the coin?

Answer:

Area = 0.00025 m²

Explanation:

Given the following data;

Pressure = 400N/m²

Force = 0.1N

To find the area of the coin;

Pressure = Force/area

Area = Force/pressure

Substituting into the equation, we have;

Area = 0.1/400

Area = 0.00025 m²

Answer:

Why sex cells only need half the number of chromosomes compared to other cells in the body?  As gametes are produced, the number of chromosomes must be reduced by half. Why? The zygote must contain genetic information from the mother and from the father, so the gametes must contain half of the chromosomes found in normal body cells.

Explanation:

Brainliest Plzz

Answer:

During Mitosis, the chromosomes split at G2 Phase.

Answer:

mass× weight

85×9.5=807.5 kg

An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.

Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.

Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.

Therefore, the correct option is C.

Learn more about Physical Weathering here:

https://brainly.com/question/29616084

#SPJ2

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = [tex]k' \frac{q_1 q_2 }{r^2}[/tex]

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = [tex]k \frac{q_1 q_2 }{r^2}[/tex]

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Answer:

more

Explanation:

The velocity does not change greatly between Mars and Venus —explained Dong— but Venus's closer proximity to the sun boosts the density by almost a factor of 4.5. This would mean that atmosphere on Mars would be lost even more rapidly than at its current position.

Answer:

atoms

Explanation:

they are the smallest

Answer:

Pro athletes are professional athletes, they are professional in their field. They are not paid too much in my thoughts.

Explanation:

I do not believe that professional athletes are paid too much or over paid. These group of athletes have become professionals in their fields after many years of training, they are highly talented with extra ordinary physical abilities. More so, fans love to watch them play and pay to watch them because they enjoy them. They are get sponsors due to the great crowd they attract.

Explanation:

Microwave sources include artificial devices such as circuits, transmission towers, radar, masers, and microwave ovens, as well as natural sources such as the Sun and the Cosmic Microwave Background. Microwaves can also be produced by atoms and molecules.

Answer:

Stars, including the Sun, are natural microwave sources.

Explanation: Under the right conditions, atoms and molecules can emit microwaves. Man-made sources of microwaves include microwave ovens, masers, circuits, communication transmission towers, and radar. Either solid state devices or special vacuum tubes may be used to produce microwaves.

Answer:

D: All

Explanation:

In cats, noise pollution causes what is known as acoustic stress in them.

In birds, noise pollution delays their nesting because it makes their songs which they use to probe to be at a low frequency.

Noise pollution affects humans because it can lead to loss of hearing, sleep disturbance, stress, high blood pressure e.t.c

Therefore, it affects Cats, birds and humans.

So option D is correct.

Answer:

The needed force is "1.5 Newtons". A further solution is provided below.

Explanation:

The given values are:

mass,

= 0.1 kg

acceleration,

= 15 m/s²

As we know,

⇒ [tex]Force= mass\times acceleration[/tex]

On substituting the given values, we get

⇒            [tex]=0.1\times 15[/tex]

⇒            [tex]=1.5 \ Newtons[/tex]

Answer:

not sure

Explanation:

jahhhhhsjjjjdddddhdhdj hbdbd#dialectical DHL I have no clue W Bush administration and I don't have any jshshhhhdgggddddddd the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

jsbsbd the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

BFF and I don't have any questions please call her and her husband to the hospital for a bit more time with my family grew up in the form of a ring whose inner circumference is it a lot of people who are you doing today beautiful and I don't have any questions please call her and her husband to the

Answer:

My answer will be (D) . A few thousand years

Explanation:

Carbon-14 is a radioactive isotope of carbon, containing 6 protons and 8 neutrons, that is present in the earth's atmosphere in extremely low concentrations.2

It is naturally produced in the atmosphere by cosmic rays (and also artificially by nuclear weapons), and continually decays via nuclear processes into stable nitrogen atoms.

Suppose we have a sample of a substance containing some carbon-14. Let m be the mass of carbon-14 in nanograms after t years. 3

It turns out that, if the sample is isolated, then m and t approximately 4 satisfy the differential equation

dmdt=−0.000121m.

Suppose our sample initially contains 100 nanograms of carbon-14. Let's investigate what happens to the sample over time.

First, we can solve the differential equation. Since m has a continuous decay rate of −0.000121, a general solution to the differential equation is

m(t)=Ce−0.000121t,

where C is a constant. Substituting the initial condition t=0, m=100 gives C=100, so

m(t)=100e−0.000121t.

With this formula, we can calculate the amount m of carbon-14 over the years.

Mass of carbon-14 in sample

t (years) m (ng to 4 decimal places)

0 100.0000

100 98.7973

1000 88.6034

2000 78.5056

5000 54.6074

10 000 29.8197

20 000 8.8922

Every year, the mass m of carbon-14 is multiplied by e−0.000121≈0.999879. After 100 years, 98.7973 nanograms still remain. After 1000 years, we still have 88.6034 nanograms. But after 5000 years, however, almost half of the carbon-14 has decayed.

Graph showing the decay of 100 nanograms of Carbon-14.

Detailed description

half-life of carbon-14  

Example

How long does it take for precisely half of the carbon-14 in the sample to decay; that is, when does m=50? Give the answer to three significant figures.

Solution

The mass of carbon-14 in our sample is given by

m(t)=100e−0.000121t.

So we solve 50=100e−0.000121t, which gives e−0.000121t=12. Hence,

t=loge12−0.000121≈5730 years (to three significant figures).

The time period calculated in this example is called the half-life of carbon-14. In fact over any period of 5730 years, the amount of carbon-14 in an isolated sample will decay by half. This fact is used in radiocarbon dating to determine the age of fossils up to 60 000 years old. Roughly speaking, while an organism is alive, its interactions with its environment maintain a constant ratio of carbon-14 to carbon-12 in the organism; but after it dies, the carbon-14 is no longer replenished, and the ratio of carbon-14 to carbon-12 decays in a predictable way. (See Wikipedia Open new window for more on radiocarbon dating.)

Exercise 1

Explain why the mass of carbon-14 in the sample is given (approximately) by

m(t)=100(12)t5730,

and hence explain why the amount of carbon-14 in the sample decays by half over any period of 5730 years.

Half-life in general

In general, whenever a quantity x(t) obeys an exponential decay equation

x(t)=Cekt,

where the continuous decay rate k is negative, then the quantity x has a half-life T. After any time period of length T, the quantity x decreases by half. Let us see why.

As k is negative, the factor ekt decreases from 1 (at t=0) towards 0 (as t approaches ∞). Therefore there is a time t=T such that

ekT=12.

We now solve for T and obtain

kT=loge12=−loge2,

so

T=−1kloge2.

This T is the half-life. From time t=0 to time t=T, the factor ekt decreases from e0=1 to ekT=12, that is, decreases by half. Similarly, over any time period of length T, the term ekt decreases by half. 5

Note that, when k=−0.000121, we obtain T=5730, in agreement with our calculation for carbon-14.

Hope this work

If I'm wrong I'm sorry

If I'm right thank you (brainliest plz )