Benjamin has 16 coins in his wallet consisting of quarters and dimes. The total worth of
the coins is $3.10. Benjamin created two linear equations to model this scenario, where
q represents the number of quarters in his wallet, and d represents the number of
dimes.

Volume of a cylinder: PI x radius^2 x height

= 3.14 x 5^2 x 10 = 785 m^3

Volume of a cone: pi x radius^2 x height/3

= 3.14 x 5^2 x 4/3 = 104.67 m^3

Total volume  = 785 + 104.67 = 889.67 M63

Answer: C. 889.67 M^3

Answer:

[tex]\textsf{C)}\quad \sf 889.67\: m^3[/tex]

Step-by-step explanation:

The given composite solid is made up of a cylinder and a cone.

To find the volume of the composite solid, find the volume of the cylinder and the volume of the cone, then add them together.

Volume of a cylinder:

[tex]\sf V=\pi r^2 h[/tex]

(where r is the radius and h is the height)

Given:

Substitute the given values into the formula and solve for V:

[tex]\begin{aligned}\implies \sf Volume\:of\:the\:cylinder & = \sf \pi (5)^2(10)\\ & = \sf 250 \pi \:\:m^3 \end{aligned}[/tex]

Volume of a cone:

[tex]\sf V=\dfrac{1}{3} \pi r^2 h[/tex]

(where r is the radius and h is the height)

Given:

Substitute the given values into the formula and solve for V:

[tex]\begin{aligned}\implies \sf Volume\:of\:the\:cone & = \sf \dfrac{1}{3} \pi (5)^2(4)\\ & = \sf \dfrac{100}{3}\pi \:\:m^3 \end{aligned}[/tex]

Therefore, the volume of the composite solid is:

[tex]\begin{aligned}\implies \sf Volume\:of\:composite\:solid & = \sf Cylinder\:volume+Cone\:volume\\ & = \sf 250\pi + \dfrac{100}{3}\pi \\ & = \sf \dfrac{850}{3} \pi \\ & = \sf \dfrac{850}{3} \times 3.14 \\ & = \sf 889.67\:m^3\:(2\:d.p.)\end{aligned}[/tex]

The area of the large rectangle by using the strategy is; 168cm².

The area of the rectangle can be determined by multiplying the length and width of the rectangle as follows;

Area = Length × width

Area = (10cm + 4cm) × (10cm × 2cm)

Area = (100+20+40+8)cm²

Area = 168 cm².

The strategy used above entails that the two binomials used to represent the length and width of the rectangle are multiplied according to binomial multiplication.

The strategy is that each term of the first binomials is used to multiply the terms in the second polynomial and the aggregate result of the multiplications is determined.

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El dinero que le falta a Maritza y su esposo para viajar es 330.

Para calcular el dinero que les falta debemos identificar la cifra total que les va a costar el viaje:

El valor total del viaje es s/3,130, entonces les faltarían s/330.

3,130 - 2,800 = 330

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Answer:

D

Step-by-step explanation:

I assume that for C and D, you meant e^x.

Since the function is defined at 0, eliminate A and B (since ln 0 is undefined)

Between C and D, we know that when x=0, e^x = 1. Since the y intercept of the graph is -3, this means the equation is y = e^x - 4.

Answer:

g(11) = 101

Step-by-step explanation:

g(r) = -20 + 11r

So in g(11), we just need to replace 'r' with '11'

g(11) = -20 + 11 (11)

--> g(11) = -20 + 121 = 101

--> g(11) = 101

Please comment down below if 8(11) wasn't a typo. I thought it was, so I replaced 8 with g. If that was intentional, I'll edit my answer as soon as possible.

Answer:

89.4 - 13.621 = 75.779

Explanation:

Subtract 13.621 from 89.4 to get 75.779.

519 children chose apple slices.

Given that Daisy's Diner offers a side dish of broccoli, apple slices, or pretzels with their kids' meals, and last weekend, they sold 1,038 kids' meals, and twice as many kids chose pretzels as chose broccoli and 3 times as many chose apple slices as chose broccoli, to determine how many kids chose apple slices, the following calculation must be performed:

Therefore, 519 children chose apple slices.

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Answer:519 children chose apple slices.

Step-by-step explanation:

Answer:

Six years

Step-by-step explanation:

because it will divided the twoo digit and mutiple it self

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: 10x + 30 = 90[/tex]

[ according to given figure ]

[tex]\qquad \sf  \dashrightarrow \: 10x = 90 - 30[/tex]

[tex]\qquad \sf  \dashrightarrow \: 10x = 60[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 60 \div 10[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 6 \degree[/tex]

Correct choice is D

The null hypothesis is that the proportions are 0.30, 0.20, 0.20, 0.20, 0.10 and the alternative hypothesis is that the proportions are not as given above.

It should be noted that the null hypothesis is the theory that states that there is no statistical relationship between the variables.

In this case, the Chi square test can be run to get the desired information. Therefore, X² was gotten as 19.597. The degree of freedom is 4 and the p value is 0.0006 from the distribution table.

In this case, the critical value of 0.006 is less than the 0.05. Therefore, we need to reject the null hypothesis.

This implies that there's evidence that the distribution doesn't correlate with what we've.

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The two kinds of formula are used in the excel . One from the data analysis the t test assuming equal variances as nothing was mentioned. But if the t test for the means is used there might be slight variation in the values.

The other formula was of descriptive statistics.

The data was

No of feedback (sec) Feedback (sec) Difference

45 54 9

33 50 17

59 58 -1

32 38 6

30 42 12

27 35 8

29 38 9

59 66 7

64 65 1

38 55 17

The null hypothesis is accepted because t stat= -1.322 is less than t critical which is  t critical= ±2.119  and lies in the acceptance region.

The p- value is 2.04 which is greater than alpha= 0.05

The t stat for 0.01=  4.561578674 and t Critical two-tail 3.249835541

The t stat is greater than t critical at alpha 0.01 so it is rejected.

The difference t test gives

Count=N   9                  9

Mean       41.2             49.67

Mean Difference  8.4

Standard Deviation  14.967       11.97

Variance        223.944  143.25

Standard Error 2.0824

t       = -1.322

df = 16

t Critical two-tail 2.119905285

Confidence Level(95.0%) 4.802039614

Lower CI (95.0%) =  3.6

Upper CI(95.0%)=  13.2

t stat for 0.01=  4.561578674

t Critical two-tail 3.249835541

Confidence Level(99.0%) 6.055710988

Lower CI (99.0%) =  2.345

Upper CI(99.0%)=  14.457

For values between 3.6 and 13.2 we are 95% confident that there is no difference between the means of two given data values.

The null hypothesis is accepted because t stat= -1.322 is less than t critical which is  t critical= ±2.119  and lies in the acceptance region.

The p- value is 2.04 which is greater than alpha= 0.05

The t stat for 0.01=  4.561578674 and t Critical two-tail 3.249835541

The t stat is greater than t critical at alpha 0.01 so it is rejected.

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Answer:

f(x)⁻¹ = (x - 11)²

Step-by-step explanation:

To find the inverse of the function, you need to (1) swap the places of the "x" and "y" variables and then (2) solve for "y". Remember, f(x) is another way of writing "y".

y = √x + 11                                        <----- Original equation

x = √y + 11                                        <----- Swap variables

x - 11 = √y                                         <----- Subtract 11 from both sides

(x - 11)² = (√y)²                                  <----- Square both sides

(x - 11)² = y                                        <----- Simplify

Another way of writing the output of an inverse function is with f(x)⁻¹.

Answer: About 830 dollars

Step-by-step explanation: find 15% off on 897 then find 7.5 percent of 897, then add them together.

answer:

x = - 9/2

y = -10

Step-by-step explanation:

make both equations look like y =

2x-3y=21 -> -3y= -2x+21 -> y = (-2x+21)/-3 -> y = 2/3x - 7

-6x + 2y = 7 -> 2y = 6x + 7 -> y = 3x + 7/2

now make the equations equal to each other (since they both equal y)

get x

2/3x - 7 = 3x + 7/2

-7 -7/2 = 3x - 2/3x

-14/2 -7/2 = 9/3x - 2/3x

-21/2 = 7/3x

(3/7) -21/2 = x

x = (3/7) -21/2

x = - 63/14

x = - 9/2

put it back in an equation to get y

y = 3x + 7/2

y = 3(-9/2) + 7/2

y = -27/2 + 7/2

y = -20/2

y = - 10

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None of the three points (A, B, C) lies on the circumference of the unit circle.

Unit circles are circles centered at the origin and with a radius of 1. A point is on the circumference if and only if the distance of the point respect to the origin is equal to 1. The distance of each point is determine by Pythagorean theorem:

Point A

[tex]d = \sqrt{4^{2}+3^{2}}[/tex]

d = 5

Point B

[tex]d = \sqrt{\left(\frac{1}{2} \right)^{2}+\left(\frac{1}{5}\right)^{2} }[/tex]

d = √29 /10

d ≈ 0.539

Point C

[tex]d = \sqrt{\left(\frac{3}{4} \right)^{2}+\left(\frac{7}{4} \right)^{2}}[/tex]

d = √58 /4

d ≈ 1.904

None of the three points (A, B, C) lies on the circumference of the unit circle.

The statement presents a typing mistake, correct form is shown below:

A(x, y) = (4, 3), B(x, y) = (1/2, 1/5), C(x, y) = (3/4, 7/4). Which point lies on the circumference of the unit circle?

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Answer:

$4800

Step-by-step explanation:

Let's use the simple interest formula, P(1+rt), to find the final amount of the loan

10000(1+.12*4) = 14800, the final amount

14800 - 10000 = 4800 total in interest

Answer:

40. 398nine

41: 432six

42: 14714eight

Step-by-step explanation:

765-367=398

The 'nine' is probably confusing you

3x144=432

The 'six' is there to confuse you.

2x7357=14714

The 'eight' is again here to confuse you.

Ignore the 'six' and 'eight' and 'nine' they are making it harder for no reason

Notice that

[tex]7^{2014} - 7^{2012} = 7^{2012} \bigg(7^2 - 1\bigg) = 7^{2012} \times 48 = 2^4 \times 3 \times 7^{2012}[/tex]

[tex]12=2^2\times3[/tex], so

[tex]\dfrac{7^{2014}-7^{2012}}{12} = 2^2 \times 7^{2012}[/tex]

Then taking the positive square root gives

[tex]\sqrt{\dfrac{7^{2014}-7^{2012}}{12}} = \sqrt{2^2 \times 7^{2012}} = 2\times7^{1006}[/tex]

so [tex]\boxed{a=2}[/tex] and [tex]\boxed{b=1006}[/tex].

[tex]order \: does \: not \:matter \\ sample \: space = 15 \: letters \\ no \: repetition\\ P(A) = 15C5 = 3003 \: ways[/tex]

The area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

Since the curves are

We find their point of intersection.

So, r² = r²

2sin(2θ) = 1²

2sin(2θ) = 1

sin(2θ) = 1/2

2θ = sin⁻¹(1/2)

2θ = π/6

θ = π/12

So, we integrate the area from θ = 0 to θ = π/12

Now the area A of the region between two curves between θ = α to θ = β is

[tex]A = \int\limits^{\beta }_\alpha ({r^{2} - r^{'2} }) \, d\theta[/tex]

So, the area betwwen the curves r² = 2sin(2θ),  r = 1 between θ = 0 to θ = π/12 is

[tex]A = \int\limits^{\frac{\pi}{12} }_0 ({r^{2} - r^{'2} }) \, d\theta \\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1^{2} }) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1}) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 {2sin2\theta}\, d\theta - \int\limits^{\frac{\pi}{12} }_0 {1} \, d\theta\\= [2(-cos2\theta)/2 - \theta]_{0}^{\frac{\pi}{12} } \\= [-cos2\theta - \theta]_{0}^{\frac{\pi}{12} } \\= -cos2\frac{\pi}{12} - \frac{\pi}{12} - ( -cos2(0) - 0)\\[/tex]

[tex]= -cos2(\frac{\pi}{12}) - \frac{\pi}{12} - ( -cos2(0) - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -cos0 - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -1)\\= -(\frac{\sqrt{3} }{2} ) - \frac{\pi}{12} + 1\\= -0.8660 - 0.2618 + 1\\= -1.1278 + 1\\= -0.1278[/tex]

So, the area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

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Answer:

31

Step-by-step explanation:

Substitute -10 for x in b(x)=|x+41|, obtaining f(-10) = |-10 + 41|.  This result simplifies to f(-10) = |31| = 31

The combined mean of the 14 people's index finger is: 12.75 cm.

Combined mean = [(mean of first group × number of data of the first group) + (mean of second group × number of data of the second group)] ÷ (number of data of the first group + number of data of the second group).

Given the following:

Mean of first group = 7.8

Number of data of the first group = 7

Mean of second group = 17.7

Number of data of the second group = 7

Combined mean = [(7.8 × 7) + (17.7 × 7)] / (7 + 7)

Combined mean = 178.5 / 14

Combined mean = 12.75 cm.

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Answer:

here ya go :)

the black line is y=-2x-3

the lavender line is y=-x+6

Using secant rule, the value of variable x in the diagram is 10.

A secant is a line that intersect a circle in two points.

Therefore, the following rule guides a secant.

(x + 32)32 = (20 + 28)28

Hence,

32x + 1024 = (48)28

32x + 1024 = 1344

32x = 1344 - 1024

32x = 320

divide both sides by 32

32x / 32 = 320 / 32

x = 10

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Answer:

IV 5

Step-by-step explanation:

you have to solve for x:

x-3<2

x-3+3<2+3

x=5

could you put the brainlyest Icon for me? I have 1500 points, but no brainlyest, so I can't move up the ranks.

The area of the rectangular field is 468cm².

Step-by-step explanation:

If, length is 18cm; width is unknown( let x represent width). Then,

Perimeter of a rectangle= Length + Width+ Length + Width

88= 18 + x + 18 + x

88= 36 + 2x

88-36 =2x

52= 2x

52/2=2x/2

26=x

•x=26cm

The width of the rectangle is 26cm.

Area of a rectangle= Length × Width

=18cm×26cm

= 468cm².

The area of the circle with the given circumference is: 42.25π in.².

Area = πr²

Circumference = 2πr.

Given the following:

Circumference of the circle = 13π in.

Find the radius (r):

2πr = 13π

Divide both sides by 2π

2πr/2π = 13π/2π

r = 13/2

r = 6.5

Area = πr² = π(6.5²) = 42.25π in.²

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Answer:

45° rotation clockwise

Step-by-step explanation:

When you plot these on the graph, the non prime ones are on quadrant 2 and when you plot the prime ones, it is on quadrant 1. This means that it is 45° to the right(clockwise)

⬇️red is prime blue is regular ⬇️

Answer:

a = 103°

b = 103°

c = 97°

d = 83°

e = 154°

Take the prime factorization of each factor in the product.

[tex]\dfrac{72 \times 78 \times 85 \times 90 \times98}{68 \times 84 \times 91 \times 108} \\\\ ~~~~~~~~ = \dfrac{(2^3\times3^2)\times(2\times3\times13)\times(5\times17)\times(2\times3^2\times5)\times(2\times7^2)}{(2^2\times17)\times(2^2\times3\times7)\times(7\times13)\times(2^2\times3^3)} \\\\ ~~~~~~~~ = \dfrac{2^6 \times 3^5 \times 5^2 \times 7^2 \times 13 \times 17}{2^6 \times 3^4 \times 7^2 \times 13 \times 17} \\\\ ~~~~~~~~ = 3 \times 5^2 = \boxed{75}[/tex]