Be sure to show your work and solve for e:

(264 + 3 x 6) divided by 3 = e

Answer:

2/5√2

Step-by-step explanation:

2/√ 25 * 2

further:

ans (1/5)(√2)

Hi,

[tex]2\sqrt{50}\\\\=2\sqrt25*2}\\\\=2*5\sqrt{2}\\\\=10\sqrt{2}[/tex]

Answer:

In a product like:

a*b = 0

says that one of the two terms (or both) must be zero.

Here we have our equation:

x^2 + 12 = 7x

x^2 + 12 - 7x = 0

Let's try to find an equation like:

(x - a)*(x - b) such that:

(x - a)*(x - b)  = x^2 + 12 - 7x

we get:

x^2 - a*x - b*x  -a*-b = x^2 - 7x + 12

subtracting x^2 in both sides we get:

-(a + b)*x + a*b = -7x + 12

from this, we must have:

-(a + b) = -7

a*b = 12

from the first one, we can see that both a and b must be positive.

Then we only care for the option with positive values, which is x =3 or x = 4

replacing these in both equations, we get:

-(3 + 4) = -7

3*4 = 12

Both of these equations are true, then we can write our quadratic equation as:

(x - 3)*(x - 4) = x^2 + 12 - 7x

The correct option is the last one.

Answer:

d

Step-by-step explanation:

Answer:

Stratified sampling

Step-by-step explanation:

Given

[tex]30 \to 21\ and\ above[/tex]

[tex]15 \to Under\ 21[/tex]

Required

The type of sampling method

From the question, we understand that, the sample are divided into two categories. This means that each person in each person do not have the same probability of being selected.

Such method is a stratified sampling

Answer:

4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

When we divide fractions, we are essentially multiplying by the reciprocal of the fraction.

2/3 ÷ 1/6

= 2/3 × 6

= 12/3

= 4

Answer:Monday, Wednesday and Friday.

Step-by-step explanation:

It’s the other weekdays.

Answer:

x ≈ 39.3°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{KL}{KM}[/tex] = [tex]\frac{6.5}{8.4}[/tex] , then

x = [tex]cos^{-1}[/tex] ([tex]\frac{6.5}{8.4}[/tex] ) ≈ 39.3° ( to the nearest tenth )

Step-by-step explanation:

Cos theta =Base/hypotenuse

Base=KL= 6.5

Hypotenuse=KM=8.4

Cos X=

[tex] \frac{6.5}{8.4} \\ [/tex]

X=

[tex] {cos}^{ - 1} \frac{6.5}{8.4} [/tex]

X=39.30 (2decimal)

Brainliest please~

Answer:

29

Step-by-step explanation:

43.25-7=36.25

36.25/1.25=29

Answer:

4c+10t

Step-by-step explanation:

c= car

t= time/ hour

Hello!

8y + 3 > 15y + 52 <=>

<=> 8y - 15y > 52 - 3 <=>

<=> -7y > 52 - 3 <=>

<=> -7y > 49 <=>

<=> y < -7 => y ∈ { -∞; -7 }

Good luck! :)

Answer:

40/30

Step-by-step explanation:

Since tan∅= o/a, 40 is opposite, and 30 is adjacent to angle A, 40/30 is the ratio for tanA.

Answer:40/30

Step-by-step explanation:

....

Answer:

True

Step-by-step explanation:

This is the case when the result is True. The substituted variables in the argument must equal a conclusion that is also True. For example, if the premises are True, then the conclusion of the valid argument form needs to output a True conclusion as well. This makes the argument valid. Otherwise, the argument would be invalid if two True premises output a conclusion that is equal to False.

Answer:

Trey = 9 text messages

Rachel = 19 text messages

Juan = 57 text messages

Step-by-step explanation:

Let

Number of messages Trey sent = x

Number of messages Rachel sent = x + 10

Number of messages Juan sent = 3(x + 10)

Total messages = 85

Total = Trey + Rachel + Juan

85 = x + (x + 10) + 3(x + 10)

85 = x + x + 10 + 3x + 30

85 = 5x + 40

85 - 40 = 5x

45 = 5x

x = 45/5

x = 9

Number of messages Trey sent = x = 9 text messages

Number of messages Rachel sent = x + 10

= 9 + 10

= 19 text messages

Number of messages Juan sent = 3(x + 10)

= 3(9 + 10)

= 3(19)

= 57 text messages

Answer:

You have to equal the unit first,

as 1 Rupee = 100 paise,

so,

55paise: 100paise,

= 11:20

I hope it hepled : )

Answer:

Bro a normal speed of a human is 3km/hr

And I don't know the speed of jo

Because u haven't written full question

Step-by-step explanation:

Please Mark me brainliest

Answer: B

Step-by-step explanation:

To find the values of x, we first need to write the function into an equation. We can derive 2 equations from the problem.

Equation 1: y=2|x+6|-4

Equation 2: y=6

Now, we can substitute.

2|x+6|-4=6

Let's solve for x.

2|x+6|-4=6        [add both sides by 4]

2|x+6|=10          [divide both sides by 2]

|x+6|=5              [subtract both sides by 6]

x=-1

Now that we know x=-1 is one of the solutions, we can eliminate C and D.

We know that the absolute value makes the number inside positive always. Therefore, let's solve for x with -5 instead.

|x+6|=-5              [subtract both sides by 6]

x=-11

Therefore, we know that B is the correct answer.

Answer:

2

Step-by-step explanation:

Use the form asin(bx−c)+d

a=3

b=2

c=4

d=0

Phase Shift: c/b

Phase Shift: 4/2 = 2

Answer:

180

Step-by-step explanation:

Answer:

[tex]Pr = \frac{1}{6}[/tex]

Step-by-step explanation:

Given

[tex]S = \{1,2,3,4,5\}[/tex]

[tex]n = 5[/tex]

Required

Probability the third term is 3

First, we calculate the possible set.

The first must be prime (i.e. 2, 3 and 5) --- 3 numbers

[tex]2nd \to 4\ numbers[/tex]

[tex]3rd \to 3\ numbers[/tex]

[tex]4th \to 2\ numbers[/tex]

[tex]5th \to 1\ number[/tex]

So, the number of set is:

[tex]S = 3 * 4 * 3 * 2 * 1[/tex]

[tex]S = 72[/tex]

Next, the number of sets if the third term must be 2

[tex]1st \to 2[/tex] i.e. 1 or 5

[tex]2nd \to 3\ numbers[/tex] ---- i.e. remove the already selected first term and the 3rd the compulsory third term

[tex]3rd \to 1\ number[/tex] i.e. the digit 2

[tex]4th \to 2\ numbers[/tex]

[tex]5th \to 1\ number[/tex]

So

[tex]r = 2 * 3 * 1 * 2 * 1[/tex]

[tex]r = 12[/tex]

So, the probability is:

[tex]Pr = \frac{r}{S}[/tex]

[tex]Pr = \frac{12}{72}[/tex]

[tex]Pr = \frac{1}{6}[/tex]

Answer:

= r²−4r+3

Step-by-step explanation:

(r - 3) (r - 1)

(r x r) + (r x -1) + (-3 x r) + (-3 x -1)

r² + - r - 3r + 3

= r²−4r+3

Answer:

x = 14

Step-by-step explanation:

45 = 3(x + 1)

Distribute the 3

3(x) = 3x

3(1) = 3

We now have 45 = 3x + 3

Subtract 3 from both sides

45 - 3 = 42

3 - 3 cancels out

We now have 42 = 3x

Divide both sides by 3

42/3 = 14

3x / 3 = x

We're left with x = 14

Answer:

x = 14

Step-by-step explanation:

45 = 3(x + 1)

Distribute

45 = 3x + 3

-3           -3

----------------

42 = 3x

----    ----

3       3

14   =  x

Answer:

x=13

y= -9

(13, -9)

Step-by-step explanation:

If we are solving using the substitution method, we can take the first equation and set it to y so y=4-x.

Then, we can take that equation and plug it into the bottom one so

3x+4(4-x)=3

Simplify:

3x+16-4x=3

-x=-13

x=13

We can then plug 13 into any of the two given equations (I am just going to plug it into the top one)

So, 13+y=4 which y= -9

Answer:

None of the above

Step-by-step explanation:

Distance is the difference between two positions. That is x1- x2  Since both numbers were negative, you would want the absolute value of one plus the other, because subtracting a negative results in a positive. For this example the distance would look more like this:

| -4.7 - ( -3.9 ) | = .8

Answer:

We can first, determine two points on the line:

For:

x

=

0

y

=

0

−

6

y

=

−

6

or

(

0

,

−

6

)

For:

x

=

6

y

=

6

−

6

y

=

0

or

(

6

,

0

)

Next, we can plot these two points on the grid:

graph{(x^2+(y+6)^2-0.125)((x-6)^2+y^2-0.125)=0 [-20, 20, -10, 10]}

Now, we can draw a line through the two points to graph the line for the equation:

graph{(x^2+(y+6)^2-0.125)((x-6)^2+y^2-0.125)(y-x+6)=0 [-20, 20, -10, 10]}

Answer:

3,750 cars.

Step-by-step explanation:

We are given that the equation:

[tex]y=9000-2.4x[/tex]

Models the relationsip between y, the number of unfilled seats in the stadium, and x, the number of cars in the parking lot.

We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.

When there are no unfilled seats in the stadium, y = 0. Thus:

[tex]0=9000-2.4x[/tex]

Solve for x. Subtract 9000 from both sides:

[tex]-2.4x=-9000[/tex]

Divide both sides by -2.4:

[tex]x=3750[/tex]

So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.

Answer:

The smaller angle will be "156°".

Step-by-step explanation:

According to the question,

Before 12, the minute hand at 48 minutes:

= [tex]60-48[/tex]

= [tex]12[/tex] (minutes to 12)

So,

= [tex]12 \ minutes+14 \ minutes[/tex]

= [tex]26 \ minutes[/tex]

hence,

The smaller angle will be:

= [tex]26\times 6^{\circ} \ each[/tex]

= [tex]156^{\circ}[/tex]

Answer:

The angle is 204 degree.

Step-by-step explanation:

The angle turned by minute hand in 1 minute is 6 degree

The angle turned by the hour hand in 1 hour is

For the hour hand :

The angle turned in 1 hour = 360/12 = 30degree

At 2 : 00 , the angle covered = 30 x 2 = 60 degree

In each minute the hour hand moves  = 30 degrees / hour  x  1 hour/60 min  

                              = 1/2 degree  

So at 2: 48   the hour hand is at    2*30  + 48 * 1/2 = 84 degrees

For the minute hand:

In each minute it turns = 6 degrees  

So, at 48 minutes the minute hand is at   48 x 6 = 288 degrees

So, the angle between them is 288 - 84 = 204 degrees  

Answer:

14 or 10.4

Step-by-step explanation:

I don’t really understand the question but here I go I’ll try;

The height is 4 and the width is 10, so I think it’s 14 or 10.4.

The Constant that relates the height and width is 5/2.

The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other.

Once you know the constant of proportionality you can find an equation representing the directly proportional relationship between x and y, namely y=kx, with your specific k.

Given:

we have the coordinates as (10, 4)

The coordinates shows that when the height of the rectangle is 4 unit then the width of the rectangle is 10.

Using Constant of Proportionality

y= k x

10 = k(4)

k = 10/ 4

k = 5/2

Learn more about Constant of Proportionality here:

https://brainly.com/question/29126727

#SPJ2

Given:

The limit problem is:

[tex]lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}[/tex]

To find:

The value of the given limit problem.

Solution:

We have,

[tex]lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}[/tex]

It can be written as:

[tex]=lim_{x\to -5}\dfrac{\dfrac{x+5}{5x}}{2(5+x)}[/tex]

[tex]=lim_{x\to -5}\dfrac{x+5}{5x}\times \dfrac{1}{2(5+x)}[/tex]

[tex]=lim_{x\to -5}\dfrac{1}{5x\times 2}[/tex]

[tex]=lim_{x\to -5}\dfrac{1}{10x}[/tex]

Applying limit, we get

[tex]lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{10(-5)}[/tex]

[tex]lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{-50}[/tex]

Therefore, the value of given limit problem is [tex]-\dfrac{1}{50}[/tex].