Answer: 60 m/s
Explanation: If the bus is traveling at 50 m/s, and it accelerates uniformly at 5m/s for 2 seconds, that means it gained 5 m/s for every second it accelerated. We know both the rate the bus accelerated at and how long it accelerated for. All you have to do to solve this problem is figure out how much speed the bus gained and then add that to the original speed. 5*2=10, so the bus gained 10 m/s during 2 seconds of acceleration. 50+10=60, so the bus is now traveling at 60 m/s.
how many weeks will the thrusters have to operate to increase the velocity of the probe to 420 miles per minute?
The thrusters must operate for 50 seconds to increase the velocity of the probe to 420 miles per minute.
What is velocity?
Velocity is a vector quantity that measures the rate of change in an object’s position. It is defined as the rate of change of displacement, or the rate of change of an object’s position over time. It has both magnitude, which is the speed of the object, and direction, which is the direction the object is traveling.
To answer this question, we must first calculate the change in velocity that is needed to bring the probe up to its desired speed of 420 miles per minute. We can do this by subtracting the current velocity of the probe from 420 miles per minute. For example, if the current velocity of the probe is 350 miles per minute, the change in velocity needed is 70 miles per minute (420 - 350 = 70).
Next, we need to calculate the thrust force that the thrusters must generate to achieve the desired change in velocity. This can be calculated using the equation Force = Mass x Acceleration, where Mass is the mass of the probe and Acceleration is the desired change in velocity divided by the time period in which it is achieved. For example, if the mass of the probe is 500 kg and the desired change in velocity is 70 miles per minute, the acceleration needed is 0.14 m/s2 (70 miles per minute / 500 kg = 0.14 m/s2).
Finally, we can calculate the amount of time that the thrusters must operate to achieve the desired change in velocity. This can be calculated using the equation Time = Force / Acceleration, where Force is the force generated by the thrusters and Acceleration is the desired change in velocity divided by the time period in which it is achieved. For example, if the thrusters generate a force of 1000 Newtons and the desired change in velocity is 70 miles per minute, the time required to achieve this is 50 seconds (1000 Newtons / 0.14 m/s2 = 50 seconds).
Therefore, in this example, the thrusters must operate for 50 seconds to increase the velocity of the probe to 420 miles per minute.
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which of the following statements about the size of temperature units is not true? group of answer choices 1 kelvin is bigger than 1 fahrenheit degree. 1 celsius degree is bigger than 1 kelvin. 1 celsius degree is bigger than 1 fahrenheit degree. 1 celsius degree is equal to 1 kelvin.
The wrong statement about size of temperature unit is 1 Celsius degree is bigger than 1 Kelvin (b)
The answer choices should have as follow :
A. 1 kelvin is bigger than 1 fahrenheit degree
B. 1 celsius degree is bigger than 1 kelvin
C. 1 celsius degree is bigger than 1 fahrenheit degree
D. 1 celsius degree is equal to 1 kelvin.
The temperature is measured using three different scales, Fahrenheit, Celsius, and Kelvin.
Celsius or °C is a part of the Metric System, that used in most countries. Celsius temperature scale is based on two points: the boiling point of water as 100° C and the freezing point of water as 0° C.Fahrenheit or °F, used in the US. Fahrenheit temperature scale is 32° for the freezing point of water and 212° for the boiling point of water. 100 degrees separate freezing and boiling on the Celsius scale, but for Fahrenheit the difference is 180 degrees. This means Celsius is 1.8 times larger than Fahrenheit.Kelvin scale. Temperatures measured on the Kelvin scale are written simply as K, not °K. Kelvin degree is the same size as the Celsius degree. The freezing point of water (0°C), and the boiling point of water (100°C), correspond to 273.15°K and 373.15°K. So, 1 celsius degree is equal to 1 Kelvin.Learn more about temperature scale at :
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a hiker walks with an average speed of 1.5 m/s. what distance in kilometers does the hiker travel in a time of 1.7 hours?
A hiker walking with an average speed of 1.5 m/s would travel a distance of 2.55 kilometers in 1.7 hours.
This can be calculated using the equation Distance = Speed x Time, or D = S x T. Substituting the given values, we get D = 1.5 m/s x 1.7 hours = 2.55 kilometers.
Speed is a scalar quantity that refers to how quickly an object is moving. It is typically measured in meters per second (m/s). Speed is related to how much distance an object covers over a given amount of time. The faster an object moves, the greater the distance it covers in a given amount of time, and thus the greater its speed. Speed can also be measured in other units, such as miles per hour (mph).
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What is the benefit of cooling down after exercise?
It allows the body to increase blood flow.
It keeps blood from pooling in the limbs.
It prepares the body for exercise.
It keeps the muscles flexed.
Answer:
It allows the body to increase blood flow.
what would you expect when low pressure forms on earth's surface? group of answer choices convergence and sinking air convergence and rising air divergence and sinking air divergence and rising air
Whenever low pressure builds up upon that earth's surface, we might expect divergence and rising air.
What does physics' SI unit for pressure mean?
Pressure is defined as the force acting on a body's surface area divided by its volume. Mathematically, it can be expressed as follows: The SI pressure unit is the Pascal (Pa). Every Newton of force exerts one Pascal of pressure on a square centimeter of ground.
What factors determine pressure?
P = F / A, meaning force per unit of surface area, is the formula for computing pressure. The sign representing pressure in scientific theory is p, and the Standard unit for maintaining pressure is the pascal (symbol: Pa). One pascal is equivalent to one Newton per square meter of force applied perpendicularly to a surface.
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Full question-
a force of 10 lb is required to hold a spring stretched 8 in. beyond its natural length. how much work w is done in stretching it from its natural length to 13 in. beyond its natural length?
The required work done in stretching the spring from its natural length to the specified length is calculated to be 105.63 lb.in.
The spring is stretched for 8 in.
The force the spring holds is 10 lb.
The spring is being stretched from its natural length to 13 in.
Work done is calculated to be = ?
The relation between force, spring constant and extension is,
F = k x
Making k as subject, we have,
k = F/x = 10/8 = 1.25 lb/in
The work done in stretching from natural length to 13 in is,
W = 1/2 k x² = 1/2 (1.25) 13² = 105.63 lb.in
Thus, the required work done is calculated to be 105.63 lb.in.
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human nerve cells have a net negative charge and the material in the interior of the cell is a good conductor. for related problem-solving tips and strategies, you may want to view a video tutor solution of
The cell boundary's net flux measures -0.887 [tex]Wb.m^{2}[/tex] in both magnitude and direction (inward or outward).
Any impact that seems to flow through or move through a surface or substance is referred to as a magnetic flux. The following formulas are used to determine the size and direction (inward or outward) of the net flux through the cell boundary:
Ф = Q/ε, where:
Q is the net charge
ε is the permittivity of free space.
As per the question,
Φ = (-7.85 x 10⁻¹²)/ (8.85 x 10⁻¹²)
Φ = - 0.887 Wb.m²
The negative sign here indicates the outward flow of the flux. Magnetic flux is a measure of the strength of a magnetic field over a specific area, to put it simply. It has [[tex]ML^{2} T^{-2} A^{-1}[/tex]], as the dimension of mass length squared per square of time and electric current.
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Complete question is:
The human nerve cells have a net negative charge and the material in the interior of the cell is a good conductor. if the cell has a net charge of - 7.85 pc, what are the magnitude and direction (inward or outward) of the net flux through the cell boundary.
Please help with the Task question
When the angle of incident light moves away from 90 degrees, the average intensity of the light incident on a flat surface area diminishes. This how the incident light affect the power output of solar cell.
How does solar cell output depend on light intensity?With an increase in light intensity, solar cells' open loop voltage, short-circuit current, and maximum output power increases. Therefore, it is clear that the solar cell outperforms at producing energy the more concentrated the light is.
How does the solar cell's power output change depending on how far the light source is from it?The amount of energy produced will diminish as the distance between the light source and the solar cell grows. This is caused by the fact as light spreads out immediately after it departs the source, but the amount of light remains unchanged.
How does a solar cell's surface area influence how much power it tends to produce?In order to be able to to point towards the Sun when the spaceship moves, solar panels must have a large surface area. Greater sunlight can be extracted from solar light by presenting more surface area.
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what is the real reason we have different moon phases?
Recall that the moon orbits the Earth, which affects how the moon appears to be in different phases. Half of the moon always receives sunlight as it orbits the Earth.
Darkness is always present on the moon's other side. It depends on the situation whether we can see the illuminated components.
What is the reason for the different phases of Moon?
Due to the Moon's orbit around Earth and Earth's orbit around the Sun, we experience varying amounts of Moonlight throughout the course of a month. Moving is everywhere. A lunar eclipse prevents the Moon from receiving sunlight because Earth is positioned between the Sun and the Moon. All or a portion of the lunar surface is obscured by Earth.
What are the 4 main phases of the Moon?
We generally pay attention to the new moon, first quarter, full moon, and third quarter of the moon. The lunar cycle has a week-long interval between each of these moon phases.
What causes the Moon to look different every 3/4 days?
As a result of its orbit around the Earth, the moon experiences phases. From Earth, we can observe that the sun illuminates the moon to a varying extent depending on its position in relation to the Earth. The moon can be completely dark or completely illuminated.
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8 kw of shaft work is done on a system while 3 kw of heat is lost from the system. what is the rate of energy change of the system?
8 kw of shaft work is done on a system while 3 kw of heat is lost from the system. 5 kW is the rate of energy change of the system.
The rate of energy change of the system can be calculated by subtracting the amount of heat lost from the system from the amount of shaft work done on the system. while 3 kw of heat is lost from the system. 5 kW is the rate of energy change of the system.
So, the rate of energy change of the system can be calculated as follows:
Energy change = Shaft work - Heat loss
Energy change = 8 kW - 3 kW
Energy change = 5 kW
So, the rate of energy change of the system is 5 kW.
8 kw of shaft work is done on a system while 3 kw of heat is lost from the system. 5 kW is the rate of energy change of the system.
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earth's main energy outputs are question 31 options: ultraviolet radiation and visible radiation. gamma rays, x-rays, and ultraviolet radiation. visible and infrared radiation. reflected light and thermal infrared radiation.
The Earth's main energy outputs are reflected light and thermal infrared radiation. Option D is correct.
The Earth reflects a portion of the incoming solar radiation back into space, mainly in the form of visible light. Additionally, the Earth radiates thermal energy back into space in the form of infrared radiation, which is produced by the warm surface and atmosphere of the planet.
Ultraviolet radiation, gamma rays, and X-rays are not the main energy outputs of the Earth, but they do reach the Earth's surface in small amounts, mainly as a result of the Sun's emission of these types of radiation.
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--The given question is incorrect, the correct question is
"Earth's main energy outputs are : A) ultraviolet radiation and visible radiation. B) gamma rays, x-rays, and ultraviolet radiation. C) visible and infrared radiation. D) reflected light and thermal infrared radiation."--
an airplane is flying faster than the speed of sound at the altitude of the airplane. if the speed of the airplane decreases bu tthe airplane is still supersonic, what happens to the mach cone angle?
If an airplane is flying supersonic, its speed creates a cone-shaped disturbance of compressed air known as a Mach cone. The angle of the Mach cone is dependent on the airplane's speed relative to the speed of sound. If the airplane's speed decreases while it is still supersonic, the Mach cone angle will widen.
When an airplane travels faster than the speed of sound, it generates a Mach cone. The Mach cone is created by the compression of the air in front of the airplane as it moves through the air. The Mach cone's angle depends on the airplane's speed relative to the speed of sound.
If the airplane's speed decreases while it is still supersonic, the Mach cone angle will increase or become wider. This is because the Mach cone angle is inversely proportional to the airplane's speed. The slower the airplane travels, the wider the Mach cone angle becomes.
The Mach cone angle is an important consideration in supersonic flight because it affects the aerodynamics and stability of the airplane. A wider Mach cone angle can lead to increased drag, which can affect the performance of the airplane. This is why monitoring and controlling the Mach cone angle during supersonic flight is important.
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if you weigh 665 n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 17.0 km ? take the mass of the sun to be ms
The weight of an object with a mass of 665 N on the surface of the neutron star significantly higher than on Earth, due to the much stronger gravitational pull of the massive neutron star is [tex](6.67 x 10^-11 m^3 / kg s^2)[/tex].
The weight of an object on the surface of a celestial body depends on its mass and the gravitational force acting on it. The equation for the force of gravity is given by[tex]F = G * (m1 * m2) / r^2,[/tex] where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers.
To calculate the weight of an object on the surface of a neutron star with the same mass as the sun and a diameter of 17.0 km, we need to first find the mass of the neutron star and then the radius. The mass of the neutron star can be taken to be the same as that of the sun, which is approximately [tex]1.989 x 10^30[/tex] kilograms.
Next, we can use the formula for the radius of a sphere to find the radius of the neutron star: [tex]r = (3 * M) / (4 * pi * density)[/tex], where M is the mass of the neutron star and density is the average density of the star. The density of a neutron star is extremely high, on the order of several times that of atomic nuclei. For a neutron star with the same mass as the sun and a diameter of 17.0 km, the radius can be calculated to be about 5.6 km.
Finally, we can use the equation for the force of gravity to find the weight of an object on the surface of the neutron star:
[tex]F = G * (m1 * m2) / r^2[/tex]
where m1 is the mass of the object (665 N), m2 is the mass of the neutron star (1.989 x 10^30 kilograms), r is the radius of the neutron star (5.6 km), and G is the gravitational constant[tex](6.67 x 10^-11 m^3 / kg s^2)[/tex].
The weight of an object with a mass of 665 N on the surface of the neutron star would be significantly higher than on Earth, due to the much stronger gravitational pull of the compact and massive neutron star.
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average mass of adult cat is normally distributed with a mean mass of 10 kg and a standard deviation of 1.8 kg. what percentage of cats would have mass more than 12 kg? what percentage of cats would have mass between 7.2 kg and 9.8 kg? round answers to two decimals, if necessary. make sure to include % sign.
a) More than 13% of cats would weigh more than 12 kg.
b) Between 7.2 kg and 9.8 kg of mass would be found in 39.68% of cats.
What is mass and weight?A measuring of an object's gravitational characteristic, or the quantity of matter it includes, is the object's mass. The gravity forces acting on an object or the force required to carry it is measured by the weight of the thing. An object's downward acceleration due to gravity on earth is roughly 9.8 m/s2.
a) P( x > 12 ) = 1 - P( x < 12 )
= 1 - P[(x - \mu) / \sigma < (12 - 10) / 1.8)
= 1 - P(z < 1.11)
= 1 - 0.8665
= 0.1335
Percentage = 13.35%
b) P(7.2 < x < 9.8) = P[(7.2 - 10) / 1.8) < (x - \mu) /\sigma < (9.8 - 10) / 1.8) ]
= P(-1.56 < z < -0.11)
= P(z < -0.11) - P(z < -1.56)
= 0.4562 - 0.0594
= 0.3968
Percentage = 39.68%
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3. A force of 10 N works on a ball over a distance of 5 m. The force is
parallel to the displacement of the ball. What is the total work done by the
force?
O -50 N
O ΟΝ
O 2N
50 N
help!!!
Answer:
2N
Explanation:
works one=force/weight
10N/5m
2N
a magnetic levitation system is shown below. an applied voltage v(t) creates a circuit current i(t), which causes a magnetic force fem(t) to act on the steel ball. the objective is to levitate the ball by manipulating the voltage. this nonlinear force can be modeled as:
The magnetic force acting on the steel ball can be modeled as [tex]Fem(t) = B0 + B1V(t) + B2V(t)^2[/tex] , where B0, B1, and B2 are constants and V(t) is the applied voltage.
This nonlinear force can be used to manipulate the voltage to levitate the ball. To do this, the voltage must be adjusted to find the equilibrium point where the force is zero, which is the point at which the ball is floating in the air.
To find the equilibrium point where the force is zero, you can use a numerical optimization technique such as gradient descent. This involves continuously adjusting the voltage while monitoring the force, until the force is close enough to zero that the ball is levitating.
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Problem 4
Eliana is changing the tire of her car on a steep hill 20 m high. She trips and drops a 10 kg spare tire.
A. What is the initial PE of the tire?
B. What is the kinetic energy of the tire at the bottom of the hill?
C. What is the speed of the tire at the bottom of the hill?
A. The initial PE of the tire is 200 Joules (PE = mgh = 10 kg x 20 m x 9.8 m/s² = 200 J).
B. The kinetic energy of the tire at the bottom of the hill is 200 Joules (KE = PE = 200 J).
C. The speed of the tire at the bottom of the hill is 14.4 m/s (KE = ½ mv² = 200 J, so v = √(2KE/m) = √(400/10) = 14.4 m/s).
What is K.E.?
Kinetic energy is the energy an object has due to its motion. It is defined as the work needed to accelerate an object of a given mass from rest to its stated velocity. It is calculated by multiplying half the object's mass by the square of its velocity. Kinetic energy is a scalar quantity, having magnitude but no direction.
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Vikram and Shruti are sitting on the back seat of a car, Vikram says that both of us are at rest while Shruti says that both of us are in motion. Then they decide to place their problem before the science teacher. The teacher explained their problem with concerning facts.
Answer:pizza party
Explanation:
a ball is thrown straight up from ground level. it takes 30 seconds for the ball to fall back to ground level. as the ball is going upward, what is its upward speed when it is 10 feet above the ground?
The ball is 10 feet off the ground, it has a climbing velocity of 1.33 feet/second.
How toe calculate the speed of the ball ?Using the equations of motion for motion, we can solve for the upward velocity of the ball when it is 10 feet off the ground.
Let's assume the positive direction is up. We know that it takes 30 seconds for the ball to bounce off the ground, so the total time the ball is in the air is 60 seconds (30 seconds up + 30 seconds down).
Using the equations of motion relating displacement, initial velocity, final velocity, acceleration, and time, we get:
displacement = (final velocity + initial velocity) / 2 * time
When the ball reaches its maximum height, its final velocity is 0. The initial velocity of the ball when it is 10 feet off the ground can be solved for:
10 feet = (0 feet/sec + v0) / 2 * (30 seconds / 2)
where v0 is the initial upward velocity of the ball. Solving for v0 gives:
v0 = 10 feet / (15 seconds / 2) = 1.33 feet/second
So if the ball is 10 feet off the ground, it has a climbing velocity of 1.33 feet/second.
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The diameter of copper wire is 7.360 mm. Find the resistance of a 5 km length of such wire used for power transmission. (Specific resistance of wire = 1.720 x 10^-8 ohm meter)
Answer:
2.05 Ω
Explanation:
We are here given that the
diameter= 7.360 mm = 0.7360 cm length of wire= 5km = 5000m specific resistance= 1.720 * 10-⁸ Ω mWe need to find out the resistance of the given wire . As we know that,
[tex]\implies R = \rho \dfrac{l}{A} \\[/tex]
[tex]\implies R =\rho \dfrac{ l}{\pi r^2} \\[/tex]
[tex]\implies R =\rho \dfrac{l}{\pi \dfrac{d^2}{4}} \\[/tex]
[tex]\implies R =\rho \dfrac{4l}{\pi d^2}\\[/tex]
substitute the respective values,
[tex]\implies R = 1.720 \times 10^{-8}\times \dfrac{4\times 5000m}{3.14\times (0.74\times 10^{-2}} \\[/tex]
[tex]\implies\underline{\underline{ R = 2.05 \Omega }} \\[/tex]
and we are done!
how much tension must a rope withstand if it is used to accelerate a 1110- kg car horizontally along a frictionless surface at 1.20 m/s2 ?
The tension force in the rope must withstand a force of 12,270 N to accelerate the 1110-kg car horizontally at 1.20 m/s^2 along a frictionless surface.
The tension force in the rope must be equal to the gravitational force plus the net force required to accelerate the car horizontally.
The equation for this can be determined using Newton's second law of motion, which states that the net force acting on an object is equal to its mass times acceleration (F = ma).
Given that the car has a mass of 1110 kg and is being accelerated at a rate of 1.20 m/s^2, the net force can be calculated as follows:
F = ma = 1110 kg * 1.20 m/s^2 = 1332 N
Since the surface is frictionless, the only force acting against the car is gravity. The gravitational force acting on the car can be calculated using the equation:
Fg = m * g
where m is the mass of the car (1110 kg) and g is the acceleration due to gravity (9.8 m/s^2).
Fg = 1110 kg * 9.8 m/s^2 = 10,938 N
Therefore, the tension force in the rope must be equal to the sum of the gravitational force and the net force, or:
Tension force = F + Fg = 1332 N + 10,938 N = 12,270 N
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the thermal contact resistance may be viewed as a combination of two resistances: one due to the direct contact locations at the interface, and the other due to the gaps. these two resistances: group of answer choices are in parallel. are in series. can be either in parallel or in series.
The thermal contact resistance can be viewed as being in series. The resistance due to the direct contact locations at the interface and the resistance due to the gaps are both contributing to the overall thermal resistance of the interface.
The thermal resistance of the interface is the sum of the resistances of all the components in the thermal path. If the direct contact resistance and the gap resistance were in parallel, they would have an additive effect on the overall thermal resistance, but that is not the case for thermal contact resistance.
Thermal resistance is a measure of the ability of a material or system to resist the flow of heat. It is defined as the ratio of the temperature difference across the material to the heat flux through it.
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if you whirl a yo-yo about your head in a horizontal circle, in what direction must a force act on the yo-yo? what exerts the force?
On the off chance that you spin the yo-yo head in an even circle, you should apply force toward the circle's middle. This force is known as the centripetal force.
The centripetal force continually pulls the yo-yo towards the center of the circle, keeping it moving in a round movement.
The power that conveys the centripetal force to the yo-yo is the pressure in the string.
The string, which pulls the yo toward the circle's middle, gives the centripetal force important to keep up with movement. The string is focused on because of the heaviness of the yo-yo and the speed at which it turns.
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a box is supported by a 5.2 n vertical force and carried 2.5 m horizontally across a room at constant speed. then, the same box is pushed 2.5 m horizontally across a smooth table (smooth enough to ignore friction) by a 5.2 n horizontal force. in which case was more work done on the box by the 5.2 n force?
In the second scenario, more work done on the box by the 5.2 N force compared to the first scenario where no work was done.
The work done on an object is equal to the force applied to it multiplied by the distance it moves in the direction of the force. In the first scenario, the 5.2 N vertical force applied to the box is perpendicular to the direction of motion, so no work is done by this force.
In the second scenario, the 5.2 N horizontal force is in the same direction as the movement, so work is done by this force. The work done by the force can be calculated as follows:
W = F × d = 5.2 N × 2.5 m = 13 Nm
So, in the second scenario, more work was done on the box by the 5.2 N force compared to the first scenario where no work was done.
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Iron-cutting scissors have short edges, whereas cloth-cutting scissors have long edges. Why
Answer:
It depends on the amount of pressure needed to cut the material.
Iron is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the iron.
Cloth on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.
Explanation:
When no air resistance acts on a projectile, what will happen to its horizontal acceleration?
Answer:
Explanation:
If air resistance is ignored , then there is no acceleration in horizontal direction in projectile motion.
why can you charge the aluminum plate again and again and the charge on the styrofoam plate never seem to run ou
The charge on the styrofoam plate never seems to run out, as the charge cannot move away from the surface due to its insulating properties.
The aluminum plate and the styrofoam plate have different electrical properties that affect their ability to hold charge. Aluminum is a conductor, meaning it allows the flow of electrical charge, whereas styrofoam is an insulator, which does not allow the flow of charge. When an aluminum plate is charged, the charge can easily move through the conductor, and any excess charge can flow away to ground.
Therefore, the aluminum plate can be charged again and again, as long as there is a source of charge to transfer. In contrast, the styrofoam plate, being an insulator, cannot conduct charge, and any charge that is deposited on it stays trapped on the surface.
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How to find the magnitude of the velocity of the canoe relative to the river?
Our simple expression for the canoe's relative velocity to the river is vc/r=( x, y). When compared to the earth, the river is moving at a vr/e= angle (0.54,0). vc/e=(0.55cos(45),0.55sin(45)) is the canoe's angle to the earth.
How does physics define a magnitude?Magnitude is simply "distance or quantity," according to the definition given in physics. It shows how an object moves when it is in motion, whether that movement is absolute, relative, or of a certain size. It serves as a way to describe something's size or scope.
What exactly are magnitude and unit?Scalar values serve as measurement units, and scalar multiplication provides the definition of magnitude. The original quantity is equal to the magnitude of a quantity multiplied by the supplied unit. This is true for all types of tensors, including.
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Wilbur the pig is on the run from farmer Zuckerman. He climbed a hill and found a sled. The snow
that day was perfectly frictionless. The smooth downhill slope he was about to take was elevated 55
meters above a horizontal landing (also frictionless). If his sled started moving from rest (V₁ = 0,
initial velocity is zero) what would Wilbur's velocity be once he reached the horizontal landing?
Assume all friction of any kind is negligible (ETH = 0).
Wilbur's velocity when he reaches the horizontal landing will be approximately 55.6 m/s.
What do you mean by velocity?
Velocity is a vector quantity, meaning it has both a magnitude and a direction. It is a measure of the rate of change of an object's position in a given direction. The velocity of an object is the rate of change of its position in a given direction and is usually expressed as a vector quantity, with speed and direction.
First, we need to calculate the acceleration due to gravity (g):
g = 9.8 m/s²
We can then use the equation for constant acceleration:
V₂ = V₁ + (a * t)
Where V₂ is the final velocity, V₁ is the initial velocity, a is the acceleration and t is the time.
Since Wilbur's initial velocity is 0 (V₁ = 0) and the acceleration is 9.8 m/s², we can solve for the time (t):
t = (V₂ - V₁) / a
Since the final velocity is unknown, we can rearrange the equation to solve for it:
V₂ = (a * t) + V₁
We can now substitute in the values for a and t:
V₂ = (9.8 m/s² * (55 m / 9.8 m/s²)) + 0
V₂ = 55.6 m/s
Wilbur's velocity once he reached the horizontal landing would be 55.6 m/s.
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How many electrons does a gallium-(2+) ion have?
2nd question
How many electronics does a Titanium-(2-) ion have?
Answer:
gallium ion has 31 electrons
titanium ion has 20 electrons