As 30% of the pizza were made, we will have 500 pizzas that as extra cheese.
How do we calculate the number of pizza that has extra cheese?At Pizza Pi, the number of Pizzas that had extra cheese last week = 150
The percentage of Pizzas that had extra cheese last week = 30%
Now, let us assume that number of Pizzas made last week = X. Then, we will write the equation as:
30X/100 = 150
30X = (150 * 100)
30X = 15000
X = 15000/30
X = 500. Therefore, it can be deducted that 500 pizzas were made last week .
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Jack is in a helicopter and looking down at two friends’ homes. The angle of depression to the first home is 72°. The angle of depression to the second home is 49°. If the homes are 420m apart, what is the distance between the helicopter and the first home?
The distance between the helicopter and the first home is 369. 87 m
How to solve the distance using the angle of depression?The distance between the helicopter and the first home can be found using sine law,
Hence,
180 - 72 - 49 = 59 degrees.
Therefore,
420 / sin 59 = A / sin 49°
where
A = distance form the first home to the helicopter.cross multiply
420 sin 49 = A sin 59°
A = 420 sin 49 / sin 59
A = 316.978023694 / 0.8571673007
A = 369.869339199
A = 369. 87 m
Therefore, the distance between the helicopter and the first home is 369. 87 m
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Find the equation of the line which passes through the point ( 3,-2) and parallel to 2y - x = 3
The equation of the parallel line is 2y-x=-7
A parallel line will have the same slope, but different intercept. Let's assume C in the intercept of this parallel line. Therefore, equation of the parallel would be,
2y-x=C, coefficients of x and y remain the same, since parallel lines.
This line passes through (3, -2). Therefore, substituting those values, we will get value of C.
2.(-2) -3=C
C=(-7)
The equation of the parallel line is therefore 2y-x=-7
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What is the partial fraction decomposition of startfraction 7 x squared minus 6 x + 9 over 3 x (4 x squared + 9) endfraction?
Answer:
A:(1/3x)+(x-2/4x^2+9)
Step-by-step explanation:
Edg2022
Rewrite each multiplication or division expression using a base and an exponent
4^5 divided by 4^2=
Using the laws of indices , 4⁵ ÷ 4² can rewritten as 4³.
What is the result of the division in exponent form?
Given the expression; 4⁵ ÷ 4²
To perform the division operation, we use one of the laws of indices;
[tex]n^a/n^b = n^{a-b}[/tex]
Given that;
n = 4a = 5b = 2Now, we apply the laws of indices ;
4⁵ ÷ 4² = 4⁵⁻² = 4³
Therefore, using the laws of indices, 4⁵ ÷ 4² can rewritten as 4³.
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Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 36 women athletes at the school showed that 23 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%
No this does not indicate that the population proportion of women athletes who graduate from the university is now less than 67%.
Given long term graduation rate of 67%, sample size of 36 and the women athletes graduated is 23.
We have to find whether the given information shows that the population proportion is less than 67%.
First we have to create hypothesis for this :
[tex]H_{0}[/tex]:P=0.67
[tex]H_{1}[/tex]:P<0.67
Under null hypothesis the test statistic is
z=p bar-p/[tex]\sqrt{p(1-p)/n}[/tex]
where p bar=23/36
=0.638
z=(0.638-0.67)/[tex]\sqrt{0.67(1-0.67)/36[/tex]
=-0.032/[tex]\sqrt{0.67*0.33/36}[/tex]
=-0.032/[tex]\sqrt{0.0064}[/tex]
=-0.032/0.078
=-0.41
Now we have to find the left tailed critical at 0.01 significance level using z table.
z=-2.33
Since the z value does not fall in the critical region,therefore we fail to reject the null hypothesis. So we can conclude that there is not sufficient evidence to say that the population proportion of women athletes who graduate from the university is now less than 67%.
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Question is incomplete as it should specify the signficance level of 0.01 to be used.
Factor the greatest common factor: 28a3b4 20a2b2 − 16ab3. 4ab(7a2b 5a − 4b2) 4ab2(7a2b 5a − 4b) 4ab2(7a2b2 5a − 4b) 4ab(7a2b3 5a − 4b)
Answer:
4ab2(7a2b2 5a - 4b)
Step-by-step explanation:
28a3b4 20a2b2 − 16ab3
The GCF of 28, 20 and 16 is 4.
GCF of the variables is ab2
So the answer is
4ab2(7a2b2 5a - 4b)
Answer:
4ab2(7a2b2 5a - 4b)
Step-by-step explanation:
An object has a kinectic energy of 25j and a mass of 34kg,how fast is the object moving
v = 1.21 m/s is the answer
Kinetic energy of object = 25 J
Mass of object = 34 kg
The formula for the kinetic energy of an object is given by
K.E. = 1/2 m v2.
25 = 1/2 *34* v2.
v2= 25/17
v2 = 1.47
v = 1.21 m/s
In physics, the kinetic energy of an object is the energy that the object has due to its motion. This is defined as the work required to accelerate an object of a given mass from a stationary state to a specified velocity. After the body gains this energy during acceleration, it retains this kinetic energy unless the velocity changes
Everything that moves at home is an example of kinetic energy. This could be a cue ball rolling on a pool table, a fan that circulates air on warm days, or a glass that shatters on the floor after falling off the counter. Electrical equipment that is turned on uses kinetic energy, much like people move around the house.
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Figure ABCD is a rhombus. Rhombus A B C D is shown. Angle A is (5 x 25) degrees and angle D is (7 x minus 1) degrees. What is the value of x
Answer: 18
Step-by-step explanation:
Opposite angles of a rhombus are congruent, so
[tex]5 \times 25=7x-1\\\\125=7x-1\\\\126=7x\\\\x=18[/tex]
is P - 1 upon p = 4 find P + 1 upon p whole square
Given that (p - 1/p) = 4, the value of p² + 1/p² is 18. Detail below
Data obtained from the questio(p - 1/p) = 4p² + 1/p² = ?How to determine the value of p² + 1/p²(p - 1/p) = 4
Square both sides
(p - 1/p)² = (4)²
(p - 1/p)² = 16 ....(1)
Recall
(a - b)² = a² + b² - 2ab
Thus,
(p - 1/p)² = p² + 1/p² - (2 × p × 1/p)
(p - 1/p)² = p² + 1/p² - 2
From equation (1) above,
(p - 1/p)² = 16
Therefore,
p² + 1/p² - 2 = 16
Rearrange
p² + 1/p² = 16 + 2
p² + 1/p² = 18
Thus, the value of p² + 1/p² is 18
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ProblemSolving One leg of an isosceles
right triangle has endpoints (1, 1) and (6, 1). The other
leg passes through the point (6, 2). Draw the triangle
5 on the coordinate plane below. Then show how you
can use the Distance Formula to find the length of the
hypotenuse. Round your answer to the nearest tenth.
The length of the hypotenuse of the isosceles triangle is 7.1 units.
We can use the distance formula to find the length of ST (base) and TU(perpendicular). Further, using these lengths, we can find the hypotenuse of the isosceles triangle.
The distance formula is given as follows,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Here, d is the distance between the two points (x₁, y₁) and (x₂, y₂)
As shown in the drawn isosceles triangle STU,
The length of the base ST is given as,
ST = √(x₂ - x₁)² + (y₂ - y₁)²
Here,
x₁ = 1 and y₁ = 1
x₂ = 6 and y₂ = 1
∴ ST = √(6-1)² + (1-1)²
ST = √5²
ST = 5 units
Similarly, for TU as the other leg passes through the point(6,2) and is of length 5 units ( STU being isosceles triangle), we have,
x₁ = 6 and y₁ = 1
x₂ = 6 and y₂ = 6
Also, TU = 5 units
Now, using Pythagoras Theorem,
(hypotenuse)² = (base)² + (perpendicular)²
(SU)² = (ST)² + (TU)²
(SU)² = (5)² + (5)²
(SU)² = 50
SU = √50
SU = 7.071 units
SU ≈ 7.1 units (after rounding of to the nearest tenth)
hence, the hypotenuse of the isosceles triangle is of 7.1 units.
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Assume a student received the following grades for the semester: History, B; Statistics, A; Spanish, C; and English, C. History and English are 6 credit-hour courses, Statistics is a 8 credit-hour course, and Spanish is a 6 credit-hour course. If 4 grade points are assigned for an A, 3 for a B, and 2 for a C, what is the weighted mean grade for the semester
The weighted mean grade for the semester is 8.22
What is mean?It is calculated by dividing the total number of values in a set of data, such as measurements or numbers, by the total number of values.
No. of credits for Spanish, History and English = 6
No. of credits for Statistics = 8
Grade points for A = 4
Grade points for B = 3
Grade points for C = 2
Weighted mean = (6 * 2 + 6 * 3 + 8 * 4 + 6 * 2) / 9
Weighted mean = (12 + 18 + 32 + 12) / 9
Weighted mean = 74 / 9 = 8.22
Hence, the weighted mean grade for the semester is 8.22.
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Please help answer now please
Answer:
- 4/7 , -1/9, 7/4
Step-by-step explanation:
You know that 7/4 is the largest number because it is the only positive number. To compare the two negative numbers you need common denominators. The common denominator would be 133 (19 x 7). Now make equivalent fractions.-4/7 = x/133 133 divided by 7 is 19. Multiple the -4 by 19 to get -76/133. Next, make an equivalent fraction for -1/19. The new denominator will be 133. If I divide 133 by 19, I will get 7, so I multiple -1x7 and get -7 and the new fraction -7/133.
I have two fractions to compare -7/133 and -76/133. -76/133 if farthest from 0 so it has the least value.
Circle 1 is centered at (-4,
2) and has a radius of 3 centimeters. Circle 2 is centered at (5, 3) and has a radius of 6 centimeters.
What transformations can be applied to Circle 1 to prove that the circles are similar?
Enter your answers in the boxes.
The circles are similar because you can
translate Circle 1 using the transformation rule C, ) and then
dilate it using a scale factor of
The transformation for circle 1 exists (x+9), (y+5) and the scale factor of circle 1 exists 2.
What is a scale factor?Scale exists described as the ratio of the length of any object on a model to the actual length of the exact object in the entire world.
What is the transformation rule?The function transformation rules: f(x)+b changes the function b units upward. f(x)−b shifts the function b units downward. f(x + b) shifts the function b units to the left.
Circle 1
center: (−4, −2)
Radius: 3 centimeters
Circle 2
center: (5, 3)
Radius: 6 centimeters
Transformations can be used to circle 1 to verify that the circles exist similar.
As circle 2 and circle 1 do not contain the exact coordinates
So, circle 1 has to utilize transformation rules.
The difference between the coordinates of circle 2 and circle 1 exists
[tex]$x_2 - x_1 = 5 - (-4 ) = 9[/tex]
[tex]y_2 - y_1 = 3 - (-2) = 5[/tex]
Therefore, transformation for circle 1: (x+9), (y + 5)
The scale factor between circle 2 and circle 1 exists
The radius of Circle 2 = 2 [tex]*[/tex] radius of circle 1
Therefore, the scale factor of circle 1 = 2
Therefore, the transformation for circle 1 exists (x+9), (y+5), and the scale factor of circle 1 exists 2.
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HELPPPP PLSSSSSSSS
-----
Answer:
Translation of 3 units to the left.
Vertical stretch by a factor of 2.
Translation of 5 units down.
Step-by-step explanation:
Transformations
For a > 0
[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]
[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]
[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]
Parent function:
[tex]y=x^2[/tex]
Translate 3 units left
Add 3 to the variable of the function
[tex]\implies y=(x+3)^2[/tex]
Stretch vertically by a factor of 2
Multiply the whole function by 2:
[tex]\implies y=2(x+3)^2[/tex]
Translate 5 units down
Subtract 5 from the whole function:
[tex]\implies y=2(x+3)^2-5[/tex]
Please see the attached graphs for the final transformed function (as well as the graphed steps).
Answer:
a) vertical expansion by a factor of 2; translation 3 units left and 5 units down
b) see attached
Step-by-step explanation:
a.Describing transformations is all about matching patterns. The elements of the transformed function are matched with the elements of a transformation.
Vertical scalingA function is scaled vertically by multiplying each function value by some scale factor. In generic terms, the function f(x) is scaled vertically by the factor 'c' in this way:
original function: f(x)scaled by a factor of 'c': c·f(x)If we want the function f(x) = x² scaled vertically by a factor of 2, then we have
f(x) = x² . . . . . . . original function
2·f(x) = 2x² . . . . scaled vertically by a factor of 2
On a graph, each point is vertically twice as far vertically from some reference point (the vertex, for example) as it is in the original function graph.
Horizontal translationA function is translated to the right by 'h' units when x is replaced by (x -h).
original function: f(x)translated h units right: f(x -h)If we want the function f(x) = x² translated right by 3 units, we will have ...
f(x) = x² . . . . . . . . . . . original function
f(x -3) = (x -3)² . . . . . .translated right 3 units
Note that translation left by 3 units would give ...
f(x -(-3)) = f(x +3) = (x +3)² . . . . translated left 3 units
On a graph, each point of the left-translated function is 3 units left of where it was on the original function graph.
Vertical translationA function is translated upward by 'k' units when k is added to the function value.
original function: f(x)translated k units up: f(x) +kThe value of k will be negative for a translation downward.
If we want the function f(x) = x² translated down by 5 units, we will have ...
f(x) = x² . . . . . . . . . . . original function
f(x) = x² -5 . . . . . . . . .translated down 5 units
Combined transformationsUsing all of these transformations at once, we have ...
f(x) = x² . . . . . . . . . . . . . . . . . original function
c·f(x -h) +k = c·(x -h)² +k . . . scaled by 'c', translated h right and k up
Compare this to the given function:
y = 2(x +3)² -5
and we can see that ...
c = 2 . . . . . . vertical scaling by a factor of 2h = -3 . . . . . translation 3 units leftk = -5 . . . . . translation 5 units downThis is the pattern matching that is described at the beginning.
__
b.When graphing a transformed function, it is often useful to start with a distinctive feature and work from there. The vertex of a parabola is one such distinctive feature.
TranslationThe transformations move the vertex 3 units left and 5 units down from its original position at (0, 0). The location of the vertex on the transformed function graph will be at (x, y) = (-3, -5).
Vertical scalingThe graph of the parent function parabola (y= x²) goes up from the vertex by the square of the number of units right or left. That is, 1 unit right or left of the vertex, the graph is 1 unit above the vertex. 2 units right or left, the graph is 2² = 4 units above the vertex.
The scaled graph will have these vertical distances multiplied by 2:
±1 unit horizontally ⇒ 2·1² = 2 units vertically; points (-4, -3), (-2, -3)±2 units horizontally ⇒ 2·2² = 8 units vertically; points (-5, 3), (-1, 3)The graph of the transformed function is shown in blue in the attachment.
__
Additional comment
The vertical scale factor 'c' may have any non-zero value, positive or negative, greater than 1 or less than 1. When the magnitude is less than 1, the scaling is a compression, rather than an expansion. When the sign is negative, the graph is also reflected across the x-axis, before everything else.
If the table of the function contains exactly two potential turning points, one with an input value of -1, which statement best describes all possible values of m?
The statement (inequality) which best describes all possible values of m is: -12 < m < 4.
What is an inequality?An inequality is a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following:
Less than (<).Greater than (>).Less than or equal to (≤).Greater than or equal to (≥).The table indicates two local extremes or potential turning points at x = 1 and x = -1. Thus, the value of m can't exceed f(-3) = -12.
In conclusion, the statement (inequality) which best describes all possible values of m is: -12 < m < 4.
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Which best describes how to Sovle the equation below?
26x = 74
A. Multiply both sides by 74.
B. Multiply both sides by 26.
C. Divide both sides by 26.
D. Divide both sides by 74.
Determine the area of the figure.
Answer: (x + 11) cm²
Step-by-step explanation:
The formula for the area of a trapezoid is [tex]\frac{1}{2}(a+b)h[/tex], where
a and b are the lengths of the top and bottom sides, andh is the height of the figure.For this figure, [tex]a = 5[/tex] and [tex]b= x+6[/tex] (the top and bottom sides), while [tex]h=2[/tex] (the height).
If we suppose [tex]A[/tex] is the area, plugging these values in, we get
[tex]A = \frac{1}{2}(5 + x + 6)*2[/tex]
[tex]A = \frac{1}{2} * 2 * (x + 11)[/tex]
[tex]A = x + 11[/tex]
All the lengths are in cm, so the area will be (x + 11) cm².
Find the missing length of the triangle (Side AC)
Answer: 17.3 cm
Step-by-step explanation:
[tex]\tan 68^{\circ}=\frac{AC}{7}\\\\AC=7\tan 68^{\circ}\\\\AC \approx 17.3[/tex]
The graph of is the widest.
By critically observing and comparing the functions for the given graphs, we can logically deduce that the widest graph is: "Function 1: y = 0.25x²."
How to determine the widest graph?In Geometry, a graph which has the smallest positive coefficient of x² in absolute value is generally considered as the widest graph while the graph with the largest positive coefficient of x² in absolute value is the narrowest graph.
By critically observing and comparing the functions for the given graphs, we can logically deduce that "Function 1: y = 0.25x²" is the widest.
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Complete Question:
Compare the graphs of the functions listed below.
Function 1: y = 0.25x²
Function 2: y = 4x²
Function 3: y = -½x²
Function 4: y = -16x²
The graph of ______ is the widest?
The volume of an object that is recorded as 46cubic cm which was 15% from the actual volume
Two possibilities --- see below
Step-by-step explanation:
So it could be GREATER than 46
.85 x = 46 x = 54.11 cm^3
Or it could be smaller than 46
46= (1.15) x x = 40 cm^3
Determine whether side-side-angle (SSA) is a valid means for establishing triangle congruence. In this case, you know the measure of two adjacent sides and the angle opposite to one of them. If it is a valid criterion, explain why. If it is not valid, use GeoGebra to create a counterexample demonstrating that it doesn’t work and give an explanation. (Hint: Try constructing a triangle where the known angle is opposite to the shortest known side.) If you construct a counterexample, take a screenshot of your work, save it, and insert the image in the space below.
The illustration to determine whether side-side-angle (SSA) is a valid means for establishing triangle congruence is given below.
How to illustrate the information?Congruence of triangles means that two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure.
In this case, these triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other.
To illustrate the question, this will be:
Step 1: Draw a line segment AB
Step 2:Draw an acute angle (let's say 45° ) at A as AX
Step 3: From B draw an altitude on AX BY ⊥ AX
Step 4 Using suitable compass width and taking Y as center cut AX on both sides at C and D
Now BC = BD as BY is perpendicular bisector
Now compare ΔABC and ΔABD. Using suitable compass width and taking B as center cut AX at 2 points C & D directly so BC = BD.
This can illustrate that SSA is not a valid means for establishing triangle congruence.
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Answer:
Below is an example to show whether side-side-angle (SSA) is a legitimate method for proving triangle congruence. How should the information be illustrated? Triangle congruence refers to the property that two triangles are congruent if their three corresponding sides and their three corresponding angles are both equal in size. In this instance, the triangles can be moved around, rotated, flipped, and turned to have a same appearance. They are in alignment with one another when moved. This can serve as an example of why SSA cannot be used to prove triangle congruence.
Step-by-step explanation:
Olympia ate lunch at a restaurant the amount of her check was $6.89 she left eight dollars on the table which included the amount she owed plus a tip for the waiter which equation shows t and the amount of her tip in dollars
The equation will be like this,
6.89 + t = 8.00
t = 8 - 6.89
t = 1.11
tips = $1.11
6.89 + t = 8.00
To sum up the total amount of cash and coins you have, first, sort each invoice and coin by denomination. Create a separate stack for each denomination and count how many denominations or coins you have.
For each denomination of banknotes and coins, multiply the number you have by the denomination. For example, if you have 4 out of $ 10, multiply by 4x10 to get $ 40. If you have three $ 5 bills, multiply by 3x5 to get $ 15.
Sum the totals to calculate the total amount.
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Part E
Considering the probability you found in part D, which option makes more sense for Jake to choose?
Explain your reasoning.
The option which makes more sense for Jake to choose is option (1) He can accept the tie, and the game is over.
How to determine the best option to choose?The complete question is added as an attachment
From the complete question, the probability in part D is
Probability = 33.5%
The options to choose one from are:
Option 1: He can accept the tie, and the game is over.Option 2: He can make one more throw. Jake wins if he earns at least 30 points on the throw, but he loses if he earns less than 30 points.The calculated probability is less than 0.5.
This means that Jake is more likely to lose than win
So, the best option for Jake is option (A) walk away
Hence, the option which makes more sense for Jake to choose is option (1) He can accept the tie, and the game is over.
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what is the solution to the equation below? square root 2-3x/square root 4x=2
Answer:
X=4 easy blah blah blah it’s 4. jdjjdjfnfvbdnnfn
How many triangles are there?
Answer:
20
Steps-by-step explanation:
sorry mistake
Answer:
12
Explanation: I just counted them! :) and there was 6 in the middle and on the outside so 6 + 6 = 12! :)
which of the following is equivalent to the logarithmic equation below?
Answer:
A
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex] , then
[tex]log_{2}[/tex] 8 = 3 ⇒ 2³ = 8
Answer:
A
Step-by-step explanation:
loga(b)=x
a^x=b
since the answer to log2(8)=3
a^3=8
b=8
a=2
so 2^3=8
I hope this helped!
1. The midpoint of KL is M(5, -7). One endpoint is K(9,-7). Find the coordinates of the other endpoint L.
O
O
O
(7.-7)
(1.-7)
(1,0)
Answer:
L (1, - 7 )
Step-by-step explanation:
give endpoints (x₁, y₁ ( and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )
use the midpoint formula and equate to corresponding coordinates of M
[tex]\frac{9+x}{2}[/tex] = 5 ( multiply both sides by 2 to clear the fraction )
9 + x = 10 ( subtract 9 from both sides )
x = 1
and
[tex]\frac{-7+y}{2}[/tex] = - 7 ( multiply both sides by 2 )
- 7 + y = - 14 ( add 7 to both sides )
y = - 7
Then L = (1, - 7 )
Help me please with this question
Answer:
[tex]y = \sqrt{ \frac{\pi \: x - A {}^{} }{\pi} } [/tex]
Step-by-step explanation:
To make y subject of formular, we place y in terms of other variables.
[tex] A = \pi \: x {}^{2} - \pi \: y {}^{2} \\ making \: y \: subject \\ A + \pi \: y {}^{2} = \pi \: x {}^{2} \\ \pi \: y {}^{2} = \pi \: x {}^{2} - A \\ Dividing \: bothsides \: by \: \pi \\ y {}^{2} = \frac{\pi \: x { - A}^{} }{\pi} \\ Squarerooting \: bothsides \\ y = \sqrt{ \frac{\pi \: x - A {}^{} }{\pi} } [/tex]
In the figure pq is parallel to Ed the length of to is 4 cm the length of pt is 16 the length of qt is 20 what is the length of sq
By applying the basic proportionality theorem (BPT), the length of side SQ is equal to 5 cm.
How to calculate the length of side SQ?In order to determine the length of side SQ, we would apply basic proportionality theorem (BPT) as follows:
Since PQ ǁ RS, PT = 16
PT/RP = QT/SQ
16/4 = 20/SQ
Cross-multiplying, we have:
16SQ = 20 × 4
SQ = 80/16
SQ = 5 cm.
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Complete Question:
In the figure, PQ is parallel to RS. The length of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the length of SQ?
The following table shows the weights of nine subjects before and after following a particular diet for two months. Test the claim that the diet is effective in helping people lose weight Subject A B DEFGHI Before 168 180 157 132 202 124 190 210 171 After 162 178 145 125 171 126 180 195 163
Using the t-distribution, it is found that there is not enough evidence that the diet is helping people lose weight.
What are the hypothesis tested?At the null hypothesis, it is tested if the mean hasn't decreased, that is:
[tex]H_0: \mu_B \leq \mu_A[/tex]
[tex]H_0: \mu_B - \mu_A \leq 0[qtex]
At the alternative hypothesis, it is tested if the mean has decreased, that is:
[tex]H_1: \mu_B - \mu_A > 0[qtex]
What are the mean and the standard error for the distribution of differences?For each sample, they are given as follows:
[tex]\mu_B = 170.44, s_B = \frac{29.275}{\sqrt{9}} = 9.7583[/tex].[tex]\mu_A = 160.56, s_A = \frac{24.203}{\sqrt{9}} = 8.067[/tex].Hence, for the distribution of differences, they are:
[tex]\overline{x} = \mu_B - \mu_A = 170.44 - 160.56 = 9.88[/tex].[tex]s = \sqrt{s_B^2 + s_A^2} = \sqrt{9.7583^2 + 8.067^2} = 11.66[/tex]What is the test statistic and the decision?
The test statistic is:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.
Hence:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
[tex]t = \frac{9.88 - 0}{11.66}[/tex]
t = 0.85.
Considering a right-tailed test with 9 + 9 - 2 = 16 df, with a standard significance level of 0.05, the critical value is t = 1.7459. Since t = 0.85 < 0.85, there is not enough evidence that the diet is helping people lose weight.
More can be learned about the t-distribution at https://brainly.com/question/13873630
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