a. There are 362,880 different ways to arrange the bands.
b. If band 8 is performing first and band 2 last, there are 40,320 different ways to schedule their appearances.
To find the number of different ways to arrange the bands, we use the concept of permutations. Since there are 9 bands, we have 9 options for the first slot, 8 options for the second slot, 7 options for the third slot, and so on. Therefore, the total number of arrangements is 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 362,880.
b. Given that band 8 is performing first and band 2 last, we fix these two positions. Now we have 7 bands left to fill the remaining 7 slots. We can arrange these 7 bands in 7! (7 factorial) ways, which is equal to 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5,040.
However, since we have already fixed the positions for bands 8 and 2, we need to multiply this by the number of ways to arrange the remaining bands, which is 7!. Therefore, the total number of ways to schedule their appearances is 5,040 × 7! = 40,320.
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can someone please explain to me how to solve this?
Which set of ordered pairs represents y as a function of x?
A (0, 0.5), (2, 1.5), (−5.5, 5), (−5.5, −6)
B (5, −7), (3, −7), (−9.2, −7), (9.2, −7)
C (9.3, −1), (7.3, −2), (7.3, 2), (9.3, 1)
D (8.1, 9), (9.1, 10), (10.1, 9), (9.1, 8)
Answer:
B.
Step-by-step explanation:
A C and D are not functions as they are one - to - many whereas B is many-to-one.
A linear function on a coordinate plane. A line passing through (1, 4), (minus 2, minus 2), intersects the y- axis at 2 units and intersects the x-axis at (minus 1, 0) to form shaded portions on the left side of the line. Which of the following inequalities is graphed on the coordinate plane?
The inequality passing through (1, 4), (-2, -2), intersecting the y-axis at 2 units and intersects the x-axis at (-1, 0) to form shaded portions on the left side is y > 2x+2
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
An inequality shows the non equal comparison of two or more numbers and variables.
The inequality passing through (1, 4), (-2, -2), intersecting the y-axis at 2 units and intersects the x-axis at (-1, 0) to form shaded portions on the left side is y > 2x+2
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Evaluate if m= 14.
m
2 + m =
Answer:
16
Step-by-step explanation:
You replace m with 14. 2 + 14 = 16.
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textsf{Assuming equation:}[/tex]
[tex]\mathsf{\dfrac{m}{2} + m}[/tex]
[tex]\huge\textsf{If so, let's solve for your equation:}[/tex]
[tex]\mathsf{\dfrac{m}{2} + m}[/tex]
[tex]\mathsf{= \dfrac{14}{2} + 14}[/tex]
[tex]\mathsf{= 7 + 14}[/tex]
[tex]\mathsf{= 21}[/tex]
[tex]\huge\textsf{Therefore, your answer should be:}[/tex]
[tex]\huge\boxed{\frak{21}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Which represents the solution set to the inequality 5.1(3 2.2x) > –14.25 – 6(1.7x 4)? x < –2.5 x > 2.5 (–2.5, [infinity]) (–[infinity], 2.5)
The solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4) gives x > -2.5
What is an equation?An equation is an expression that shows the relationship between two numbers and variables.
An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.
Inequality shows the non equal comparison of two or more numbers and variables.
Given the inequality:
5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)
Simplifying:
15.3 + 11.22x > –14.25 – 10.2x - 24
21.42x > -53.55
x > -2.5
The solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4) gives x > -2.5
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HELPP A PERSON OUT PLSS! i dont really understand how to do ittt!!
giving you all my points so help pleaseeee
Can someone help me please?
A.0.36
B.0.55
C.0.18
D.0.45
Answer:
B
Step-by-step explanation:
44/77
=0.55
the vertices of abc are a (-6,-7) b(-3,-10) and c(-5,2) find the vertices of abc given the transition rule (x,y)-->(x,y-3)
The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
How to determine the new vertices?The vertices are given as:
a (-6,-7)
b(-3,-10)
c(-5,2)
The transition rule is given as
(x,y)-->(x,y-3)
So, we have
a' = (-6, -7 - 3)
a' = (-6, -10)
b' = (-3, -10 - 3)
b' = (-3, -13)
c' = (-5, 2 - 3)
c' = (-5, -1)
Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
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in a school of 40 students, 14 liked English language only, 7 students like both English and French language and 12 also like French language only
a. how many students like English but not French?
b. many students did not like any of the two languages?
c. how many students like at least one of the language?
d. if a student is chosen at random what is the probability that he likes only French
Answer:
A. 14, because it says that only 14 liked English language ONLY
B. It’s 7.
14 liked only English, 7 liked both languages, 12 liked only French.
Add those them together.
14 + 7 + 12
21 + 12
33
33 - 40 = 7
( 33 is the number of students that liked a language and 40 is ALL the students in total )
So it would be 7.
C. 26 liked one language.
7 liked both languages and 7 didn’t like neither. You could add them together.
7 + 7 = 14
40 - 14 = 26
OR
14 + 12 = 26
( just English + just French )
D. The probability of a student chosen at random that ONLY likes French would be 12/40.
Since only 12 of the 40 students liked ONLY French, it would be 12/40 or 12 : 40
Step-by-step explanation:
I hope it helps! Have a great day!
Pan~
Answer:
a) 14
b) 7
c) 33
d) P = 12/40 = 3/10 (In decimal P=0.3)
Step-by-step explanation:
Hope this helps
There are 20 teachers and 705 students in cory's school. what is the ratio of teachers and students
We know that ratios can be shown with both fractions and colons.
20:705
or
[tex]\frac{20}{705}[/tex]
It also looks like we can simplify this by dividing by 5.
20/5 = 4
705/5 = 141.
This means that for every 4 teachers, there are 141 students.
The ratio for teachers to students is:
4 : 141
in a survey, 250 adults and children were asked whether they know how to swim. the surgery data are shown in the relative frequency tqable
Answer: D
Step-by-step explanation:
ASAP
must be done today
The box-and-whisker plot for the data can be seen in the attachment.
The data given to us is:
50, 51, 54, 55, 57, 61, 62, 63, 65, 66, 67, 68, 71, 71, 76, 76, 77.
As the data is already ordered from least to greatest, we can apply the formulas.
The sample size, n = 17.
Start point = 50.
First quartile, Q1 = (n + 1)/4 th observation = (17 + 1)/4 th observation = 18/4 th observation = 4.5 th observation = average of the 4th and the 5th observation = (55 + 57)/2 = 112/2 = 56.
Median, Q2 = (n + 1)/2 th observation = (17 + 1)/2 th observation = 18/2 th observation = 9th observation = 65.
Third quartile, Q3 = 3(n + 1)/4 th observation = 3(17 + 1)/4 th observation = 3*18/4 th observation = 54/4 th observation = 13.5 th observation = average of the 13th and the 14th observation = (71 + 71)/2 = 142/2 = 71.
End point = 77.
Thus, the box-and-whisker plot should be designed as follows:
The start of the first whisker is from 50, representing the start point.
The start of the box is from 56, representing the first quartile.
The line inside the box is at 65, representing the median.
The end of the box is at 71, representing the third quartile.
The end of the whisker is at 77, representing the endpoint.
The box-and-whisker plot can be seen in the attachment.
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Help help help help help just need answer
Answer:
25 miles
Step-by-step explanation:
2 inches represents 10 miles ( divide both parts by 2 )
1 inch represents 5 miles , then
5 inches represents 5 × 5 = 25 miles
Rewrite the function by completing the square. x2 + 4x = 0 (x + )2 =
When the completing the square is applied, the rewritten function is (x + 2)^2 = 4
How to complete the square?The equation is given as:
x^2 + 4x = 0
The above equation is a quadratic equation and the coefficient of x in the above equation is 4.
So, we have:
k = 4
Divide the variable k by 2
k/2 = 4/2
k/2 = 2
Square the above result
(k/2)^2 = 4
Next, we add 4 to both sides of x^2 + 4x = 0
x^2 + 4x + 4 = 4
Expand the equation by expressing 4x as 2x + 2x
This gives
x^2 + 2x + 2x + 4 = 4
Factorize the above equation
x(x + 2) + 2(x + 2) = 4
Factor out x + 2 from the above equation
(x + 2)(x + 2) = 4
Rewrite the equation as a perfect square of (x + 2)
(x + 2)^2 = 4
Hence, the rewritten function after completing the square is (x + 2)^2 = 4
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The difference in measure of two complemenatary angles is 12 find the measure of the angles
The measure of the angle is 51 degrees.
If the sum of two angles is ninety levels, then we say that they may be complementary. thus, the supplement of an attitude is received by means of subtracting it from 90. as an example, the supplement of 40° is ninety° - forty° = 50°.
If two attitudes are complementary, the sum in their measure is ninety tiers. So, the measures of the 2 complementary angles are 51 degrees and 39 degrees.
While the sum of angles is equal to ninety ranges, they are known as complementary angles. For example, 30 stages and 60 stages are complementary angles.
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Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
Write formal proofs using LL Theorem.
Question 6
1) [tex]\overline{AB} \cong \overline{BD}[/tex], [tex]\overline{CD} \perp \overline{BD}[/tex], O is the midpoint of [tex]\overline{BD}[/tex], [tex]\overline{AB} \cong \overline{CD}[/tex] (given)
2) [tex]\angle ABO, \angle ODC[/tex] are right angles (perpendicular lines form right angles)
3) [tex]\triangle ABO, \triangle CDO[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\overline{BO} \cong \overline{OD}[/tex] (a midpoint splits a segment into two congruent parts)
5) [tex]\triangle ABO \cong \triangle CDO[/tex] (LL)
Question 7
1) [tex]\angle ADC, \angle BDC[/tex] are right angles), [tex]\overline{AD} \cong \overline{BD}[/tex]
2) [tex]\overline{CD} \cong \overline{CD}[/tex] (reflexive property)
3) [tex]\triangle CDA, \triangle CDB[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\triangle ADC \cong \triangle BDC[/tex] (LL)
5) [tex]\overline{AC} \cong \overline{BC}[/tex] (CPCTC)
Question 8
1) [tex]\overline{CD} \perp \overline{AB}[/tex], point D bisects [tex]\overline{AB}[/tex] (given)
2) [tex]\angle CDA, \angle CDB[/tex] are right angles (perpendicular lines form right angles)
3) [tex]\triangle CDA, \triangle CDB[/tex] are right triangles (a triangle with a right angle is a right triangle)
4) [tex]\overline{AD} \cong \overline{DB}[/tex] (definition of a bisector)
5) [tex]\overline{CD} \cong \overline{CD}[/tex] (reflexive property)
6) [tex]\triangle ADC \cong \triangle BDC[/tex] (LL)
7) [tex]\angle ACD \cong \angle BCD[/tex] (CPCTC)
PLEASE HELP!!!! A bag contains 1 white (W), 3 blue (B1, B2, B3), and 2 red (R1, R2) marbles. (4 points)
a. Use a tree diagram to list all the possible outcomes for tossing a coin and then drawing a marble from the bag.
b. Are these independent or dependent events?
c. Find the probability of tossing a head and drawing a red marble. Explain your reasoning.
d. Find the probability of drawing two blue marbles if the first marble is not replaced. Explain your reasoning.
The events are independent events and probability of tossing a head and drawing a red marble is 1/7
a) The answer is present in the image attached below
b) Tossing of a coin and drawing of a marble are independent events as these two events do not interfere in the probability of each others events.
c) The probability of tossing a head and drawing a red marble is = [tex]\frac{1}{2}.\frac{2}{7}[/tex]=1/7 as we can see from the tree diagram that probability of tossing a coin and getting head is 1/2 and probability of drawing a red marble is 1/7. As they are independent events, their probability can be multiplied. Hence the probability of tossing a head and drawing a red marble is 1/7.
d) The probability of drawing two blue marbles if the first marble is not replaced and one at a time is 1/7. Probability of drawing first blue marble from the lot is 3/7 as favorable outcomes are 3 and total outcomes are 7. As the ball is not replaced the outcomes are changed. Now the number of blue balls are 2 and total number of balls are 6. So now the probability becomes 2/6. Hence the total probability becomes = 1/7
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Name a postulate or theorem that can be used to prove that the two triangles are similar. Then, write a similarity statement.
Postulate: SAS
Similarity statement: [tex]\triangle CAB \sim \triangle EDF[/tex]
Using numerical integration to estimate the area of the semicircle (r=4 )and c(4,0) with n=4
The area of the semicircle = 8π
A semicircle is formed when the panel passing through the center touches both ends of the circle. Therefore, if you connect two semicircles, you get a circle
If you cut them in half or divide the circumference of the circle by 2, you will get a semi-circle. Area of semicircle The area of the semicircle is half the area of the circle. Because the area of the circle is πr2. Therefore, the area of the semicircle is 1/2 (πr2). Where r is the radius. The value of π is 3.14 or 22/7.
Semi-circular area = 1/2 (πr2)
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You buy a car for $25,000. It depreciates at the rate of 23% per year.
a. Write an exponential equation to model the value of the car.
What will the car be worth in 10 years?
round to nearest cent
The worth of the car in 10 years is $1,831.67 using an exponential equation approach.
What is an exponential equation?
An exponential equation is the one with exponents such X^3(the 3 is the exponent)
The exponential equation required here is the one where the future value would be lower than current value because the car reduces in value year-in-year-out.
FV=PV*(1-r)^N
FV=future worth of the car
PV=today's value=$25,000
r=depreciation rate=-23%
N=number of years=10
The fact that r is negative means the car is depreciating not appreciating.
FV=$25,000*(1-23%)^10
FV=$1,831.67
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When multiplying or dividing measured quantities, what determines the number of significant figures in the result?.
The quantity with the fewest number of significant figures.
The least number of significant figures is used to calculate the product's or quotient's number of significant figures when multiplying or dividing measurable numbers. While 5.25 has three major figures, 3.5 only has two.What is significant figures?
Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value. We start counting significant figures at the first non-zero digit. Calculate the number of significant figures for an assortment of numbers.When multiplying two measured values the number of significant figures should be equal to the?
For multiplication or division, the rule is to count the number of significant figures in each number being multiplied or divided and then limit the significant figures in the answer to the lowest count. An example is as follows: The final answer, limited to four significant figures, is 4,094.Learn more about significant figures
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Help needed
65. Solve for in the logarithmic equation 3 log x = 2.
O * = 1,000,000
O * = 150
O * = 56.423
O * = 4.642
9x/4y=1 and y= 18, what is the value of x
Answer:
x = 8
Step-by-step explanation:
[tex]\frac{9x}{4y}=1[/tex]
[tex]\frac{9x}{4*18} =1[/tex]
9x = 72
x = 8
Can someone help me with these problems please
Sabrina Uses a hose to fill a 20-gallon fish tank. The hose
puts out water at a rate of 3 gallons per minute. To start
with, the tank has 5 gallons of water in it.
A. How much water is in the tank after 2 minutes
of filling the tank with the hose?
B. Write an equation that represents the volume
In a two-tailed hypothesis test comparing the means of independent samples, the test statistic is 3.06 and the critical values are /-2.086. True or false: the null hypothesis is not rejected.
In a two-tailed hypothesis test the null hypothesis is rejected.
According to the statement
The test statistic is 3.06 and the critical values are /-2.086.
If we find the value of t by using the formula the then it comes with Negative sign and it lies under the critical region.
That's why In a two-tailed hypothesis test the null hypothesis is rejected.
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1. Write the next 3 terms in
patterns.
these
121,11,1,1/11
Answer:
Your simply dividing by 11
Step-by-step explanation:
0.008...
0.0007...
0.00006...
All you have to do is turn these numbers into fractions!
Answer:
1/121, 1/1331, 14641
Step-by-step explanation:
121, 11 ,1 , 1/11
We need to find the next three terms in the pattern
We are taking each term and dividing by 11
121/11 =11
11/11 =1
1/11 = 1/11
1/11 divided by 11
1/(11*11) = 1/121
1/121 * 1/11 = 1/1331
1/1331 * 1/11 = 14641
An auditorium with 30 rows of seats has 10 seats in the first row. Each successive row has one more seat than the previous row. If students taking an exam are permitted to sit in any row, but not next to another student in that row, what is the maximum number of students that can be seated for an exam
Answer:
Step-by-step explanation:
380 rows in total
bcs
use sense
What is the solution of startfraction 1 over c minus 3 endfraction minus startfraction 1 over c endfraction = startfraction 3 over c (c minus 3) endfraction?
The solution of the given equation can be all real numbers, except c = 0 and c = 3.
Lets simplify the given problem,
1/c-3 - 1/c = 3/ (c-3)
As the denominators cannot be equal to zero (0) because a division by zero (0) is undefined.
Next, we would multiply both sides of the given by the lowest common multiple (LCM).
The lowest common multiple (LCM) is c(c - 3).
c-[c-3] = 3
c-c+3 = 3
0 = 3-3
0=0
Therefore, the solution of the given equation can be all real numbers, except c = 0 and c = 3.
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HURRY PLS 15 MINS LEFT!!
Answer:
y is less than or equal to 2/3x + 1/5
Step-by-step explanation:
What are the three coordinates that need to be plotted?
Answer:
Step-by-step explanation:
y=2*|x-3|+2
y=|2*x-2*3|+2
y=|2x-6|+2
1)
y=2x-6
x | 2 | 3 |
y | -2| 0 |
2)
y=|2x-6|
3)
y=|2x-6|+2
y=2*|x-3|+2.